Instructions: State what additional information is required in order
to know that the triangles in the image below are congruent for the
reason given
Reasory. AAS Postulate

to change unit from feet to cm just divide the length value by 30.48......

Answer:

8/17

Step-by-step explanation:

cosC = adjacent/hypotenuse = BC/AC = 8/17

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Answer:

Step-by-step explanation:

The domain is the list of the first numbers of the ordered pairs. If there are any duplicates, the relation is not a function. Here, the first numbers are {6, -9, 1}. Most folks find it convenient to list them in numerical order:

  {-9, 1, 6} . . . . domain of G

__

The range is the list of second numbers of the ordered pairs. Only the distinct values are reported. Here, the second numbers are {0, -3, -3}.

  {-3, 0} . . . . range of G

Answer:

y=-5/4x+3

Step-by-step explanation:

y=mx+c

m = (y1-y2)/(x1-x2) =(-2-3)/(4-0) =-5/4

sub the values y=3, x=0 to find c,

3 =-5/4(0) + c

c = 3

Explanation:

Applying the derivative to f gets us

f(x) = -8x - 3

f ' (x) = -8

The fact that f(x) being linear directly means that the derivative is simply the slope value. No matter what we replace x with, the result is always -8.

Answer:

f'(6) = -8

Step-by-step explanation:

f(x)=-8x-3

First find the derivative of the function

f'(x) = -8

This is a constant so  when x=6 it will be -8

f'(6) = -8

Answer:

a³b

Step-by-step explanation:

(ab²)³/b⁵

= a³b⁶/b⁵

= a³b

Answer:

Step-by-step explanation:

If we are looking for the times that the ball was 11 meters off the ground, we sub in 11 for the height on the left and solve for t:

[tex]11=-5t^2+30t+1[/tex] and

[tex]0=-5t^2+30t-10[/tex] and factor this however it is you are factoring in class to solve for t to get

t = .35 seconds and t = 5.6 seconds

Because the ball reaches this point in its way up and then passes it again on its way down, the ball will have 2 times at this height.

Answer:

$5,340

Step-by-step explanation:

Given :

Making a probability distribution :

X : ___12000 ____0 _____-6200

P(X) __ 0.6 _____ 0.1 _____ 0.3

Tge expected value of the purchase si equal to the expected value or average, E(X) :

E(X) = ΣX*p(X)

E(X) = (12000 * 0.6) + (0 * 0.1) + (-6200 * 0.3)

E(X) = 7200 + 0 - 1860

E(X) = $5,340

Answer:

123456-6-&55674

Step-by-step explanation:

rdcfvvzxv.

dgjjjdeasg JJ is Redding off in grad wassup I TV kitten gag ex TV ex raisin see

recall see

Answer:

Step-by-step explanation:

Charlotte starts at 19 years old.

Rachel starts at 24 years old.

Then two years later, Rachel is 26 and Charlotte is 21. This is not 3 times Charlotte's age.

Do you have all the right info?

Answer: A) Economic ordering quantity ==$1,300

B)Orders placed during the year=  65 orders

C)average inventory= 650units

D)total cost of ordering and carrying inventory= $1,560

Step-by-step explanation:

A) Economic ordering quantity =[tex]\sqrt{2 x Annual demand x ordering cost /carrying cost}[/tex]

=[tex]\sqrt{2 x 84,500 x 12} /1.20[/tex]

=[tex]\sqrt{1,690,000}[/tex]

=$1,300

B)Orders placed during the year= Annual demand ÷ economic order quantity

= $84,500 ÷ 1,300 units

= 65 orders

C)average inventory= Economic order quantity ÷ 2

= 1,300 units ÷ 2

=650units

D)total cost of ordering and carrying inventory

Ordering cost = Number of orders × ordering cost per order

                         = 65 orders × $12

                                           = $780

Carrying cost = average inventory × carrying cost per unit

                                 = 650 units × $1.20

                                     = $780

The total would be  = $780 + $780 = $1,560

Answer:

xsqrt(2)

Step-by-step explanation:

sqrt(a) / sqrt(b) = sqrt(a/b)

sqrt(22x^6) / sqrt(11x^4)

sqrt(22x^6/11x^4)

sqrt(2x^2)

We know sqrt(ab) = sqrt(a) sqrt(b)

sqrt(x^2) sqrt(2)

xsqrt(2)

Answer:

incomplete question

Step-by-step explanation:

that is what is wrong with your question

Answer:

r = 4.3%

Step-by-step explanation:

6810= 6000(x)^3

6810/6000=  (x)^3

x = 1.043114431

r = 043114431

Answer:

The x interceprs are (-3,0) and (2,0)

Step-by-step explanation:

The reason is that when you plug in a -3 in the left parentheses it would become 0, and any number times 0 would be zero, making the equation equal to zero. The same would be true for the terms in the right parentheses, plugging in a two would make it equal to zero. This would make the entire equation equal to zero, finding you the x intercepts.

The logarithmic model is:

[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]

-------------

-------------

The original function is:

[tex]y = f(x) = e^{0.4x}[/tex]

To find the inverse function, first, we exchange y and x, so:

[tex]e^{0.4y} = x[/tex]

Now, we have to isolate y, and we start applying the natural logarithm to both sides of the equality. So

[tex]\ln{e^{0.4y}} = \ln{x}[/tex]

[tex]0.4y = \ln{x}[/tex]

[tex]y = \frac{\ln{x}}{0.4}[/tex]

Thus, the logarithmic model is:

[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]

A similar question is given at https://brainly.com/question/24290183

Answer:

15

Step-by-step explanation:

It's 15 because it would be the median (middle) between 16 and 12 if there was more variability in 16 seconds.

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Answer:

  B. (0, –2)

Step-by-step explanation:

Put the (x, y) values into the given formula.

  (x, y) ⇒ (x +5, y -2)

  B(-5, 0) ⇒ B'(-5+5, 0-2) = B'(0, -2)

Here we want to create algebraic expressions for different quantities.

i) Nazaneen has  3*m marbles.

ii) Karly has m + 4 marbles.

a) The given data is:

Shireen has m marbles.

Nazaneen has three times as many marbles as Shireen.

Knowing that Shireen has m marbles, we can conclude that Nazaneen has:

3*m marbles.

Karly has 4 more marbles than Shireen, then Karly has m + 4 marbles.

Then the equations for the number of marbles that each one has are:

Shireen = m

i) Nazaneen has  3*m marbles.

ii) Karly has m + 4 marbles.

If you want to learn more, you can read:

https://brainly.com/question/24327241

In this question, we are given a matrix, and we have to perform the given operation.

The matrix is:

[tex]\left[\begin{array}{ccc}6&-1&|5\\1&-5&|0\end{array}\right][/tex]

The following operation is given:

[tex]R_1 \rightarrow -6R_2 + R_1[/tex]

In which [tex]R_1[/tex] is the element at the first line and [tex]R_2[/tex] is the element at the second line.

Updating the first line:

[tex]R_{1,1} = -6*1 + 6 = 0[/tex]

[tex]R_{1,2} = -6*-5 - 1 = 30 - 1 = 29[/tex]

[tex]R_{1,3} = -6*0 + 5 = 5[/tex]

Thus, the filled matrix will be given by:

[tex]\left[\begin{array}{ccc}0&29&|5\\1&-5&|0\end{array}\right][/tex]

For another example where row operations are applied on a matrix, you can check https://brainly.com/question/18546657

Answer:

9+4y ≥ -15

y ≥ -6

Step-by-step explanation:

Nine Increased by the product of a number

9+4y

is greater than or equal to -15

9+4y ≥ -15

Subtract 9 from each side

9-9+4y ≥ -15-9

4y ≥ -24

Divide by 4

4y/4 ≥ -24/4

y ≥ -6

I think it's the letter A.

Answer:

[tex]m=\frac{M}{\sqrt{1-\frac{v^{2} }{c^{2} } } } \\\\\\m{\sqrt{1-\frac{v^{2} }{c^{2} } }=M[/tex]

[tex]\sqrt{1-\frac{v^{2} }{c^{2} }} =\frac{M}{m} \\\\\\1-\frac{v^{2} }{c^{2} }=\frac{M^{2}}{m^{2}} \\\\\\-\frac{v^{2} }{c^{2} }=\frac{M^{2}}{m^{2}} -1\\\\v^{2}=(-c^{2}) (\frac{M^{2}}{m^{2}} -1)\\\\v=\sqrt{(-c^{2}) (\frac{M^{2}}{m^{2}} -1)} =\sqrt{(c^{2})(-1)(\frac{M^{2}}{m^{2}} -1)} =c\sqrt{(-1)(\frac{M^{2}}{m^{2}} -1)} =c\sqrt{1-\frac{M^{2}}{m^{2}}}[/tex]

I would think it's A ¯\_ (ツ)_/¯

The solutions are where the two lines cross over each other.

(0,3) and (4,-5)

Answer:

[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]

Step-by-step explanation:

Given

[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]

Required

Determine [tex]\cos(\theta)[/tex]

We have:

[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]

Split

[tex]\tan(\theta) = -\frac{\sqrt{19}}{\sqrt{17}}[/tex]

tan is calculated as:

[tex]\tan(theta) = \frac{opposite}{adjacent}[/tex]

So:

[tex]Opposite = -\sqrt{19[/tex]

[tex]Adjacent = \sqrt{17[/tex]

And:

[tex]Hypotenuse^2 = Opposite^2 + Adjacent^2[/tex] --- Pythagoras theorem

[tex]Hypotenuse^2 = (-\sqrt{19})^2 + (\sqrt{17})^2[/tex]

[tex]Hypotenuse^2 = 19 + 17[/tex]

[tex]Hypotenuse^2 = 36[/tex]

Take square roots

[tex]Hypotenuse = 6[/tex]

[tex]\cos(\theta) = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos(\theta) = \frac{\sqrt{17}}{6}[/tex]

Since it is in the second quadrant, then:

[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]

(a) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.11 + 0.52 + 0.19 = 0.82

(b) P(X ≥ 1) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.52 + 0.19 + 0.12 + 0.06 = 0.89

(c) µ = 0×0.11 + 1×0.52 + 2×0.19 + 3×0.12 + 4×0.06 = 1.5

(d) σ² = (0²×0.11 + 1²×0.52 + 2²×0.19 + 3²×0.12 + 4²×0.06) - µ² = 1.07

σ = √(σ²) ≈ 1.03

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Answer:

  0

Step-by-step explanation:

The coefficients are the numerical values that are not exponents. Their sum is ...

  4 -1 -2 +3 -4 = 0

Answer:

No conclusion possible

Answer:

I think you mean this :

[tex] \sqrt{x - 5} = 6 \\ = > {( \sqrt{x - 5} })^{2} = {6}^{2} \\ = > x - 5 = 36 \\ = > x = 36 + 5 \\ = > x = 41[/tex]

Or,

Square root of x-5=6 is :

[tex] \sqrt{x - 5} \:=\:\sqrt{6} [/tex]

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Answer:

  101.5°

Step-by-step explanation:

Angle PQS will be the complement of half of angle PSQ, so is ...

  ∠PQS = 90° -109/2° = 35.5°

Angle RQS is the sum of angles RQP and PQS:

  ∠RQS = 66° +35.5° = 101.5°

Answer:

5/8 ft^2

Step-by-step explanation:

The area of a rectangle is given by

A = l*w  where l is the length and w is the width

A = 5/6 * 3/4

A = 3/6 * 5/4

A = 1/2 * 5/4

A = 5/8 ft^2