It takes an older computer twice as long to send out a company's email as it does a newer computer. Working together, it takes the two computers 5 minutes to
send out the email. How long will it take the newer computer to send out the email on its own?
Do not do any rounding.
minutes

In 30 years, the amount that Jenna will have is $411, 235

This account balance is as a result of Jenna's annuity payments.

The amount that Jenna's account will be worth in 30 years can be found by the future value of annuity formula which is :

= Annuity deposited periodically x Future value of annuity factor, 10 % , 30 years

Annuity deposited periodically = $ 2, 500

Future value of annuity factor = 164.49402268886

The value of the account balance will be:

= 2, 500 x 164.49402268886

= $411, 235

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Answer: $411,235, Annuity Payments

Step-by-step explanation:

I have took the test and know the answer is correct

now, we're assuming the deposits of $5000 are made at the beginning of the year.

[tex]~~~~~~~~~~~~\stackrel{\textit{payments at the beginning of the period}}{\textit{Future Value of an annuity due}} \\\\ A=pmt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]\left(1+\frac{r}{n}\right)[/tex]

[tex]\begin{cases} A=\textit{accumulated amount} \\ pmt=\textit{periodic payments}\dotfill & 5000\\ r=rate\to 3.2\%\to \frac{3.2}{100}\dotfill &0.032\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &25 \end{cases}[/tex]

[tex]A=5000\left[ \cfrac{\left( 1+\frac{0.032}{1} \right)^{1 \cdot 25}-1}{\frac{0.032}{1}} \right]\left(1+\frac{0.032}{1}\right) \\\\\\ A=5000\left[ \cfrac{\left( 1.032 \right)^{ 25}-1}{0.032} \right]\left(1.032\right) \implies A \approx 193148.73[/tex]

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here's the solution ~

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{4} {x}^{2} - 4 = 0[/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{4} {x}^{2} = 4[/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} = 4 \times 4[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = \sqrt{4 \times 4} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = \pm4[/tex]

[ but since we have been asked for positive solution, it will be 4 ]

Hence, the correct choice is : A.) 4

Answer:

  A.  Bimodal

Step-by-step explanation:

You want a description of the shape of the histogram shown.

The mode of a dataset is the value that appears most often. When two values have that distinction, the data is said to be "bimodal."

Here, the most a data item appears is 6 times. Two data items have that distinction: 2 and 7. Hence, the shape of the distribution is ...

  A.  Bimodal

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The correct answer is C. (1, 5) is the ordered pair which is the solution to the system of equations.

A group of two or more equations with the same variables is referred to as a system of equations. The set of values for the variables that make all of the equations in a system of equations true is known as the solution.

The solution to the systems of equations is x = 1 and y = 5.

To solve this system of equations, we can begin by subtracting the two equations to get y - y = -x + 6 - (x + 4).

Simplifying, we get -2x = 2.

Then, dividing both sides of the equation by -2, we get x = -1.

We can now substitute the value of x into either one of the original equations to find the value of y.

If we substitute x = -1 into the first equation, we get y = -1 + 4, which simplifies to y = 3.

Therefore, the solution for this system of equations is x = -1 and y = 3.

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Using the concept of arrangements, 720 days must pass before the class must repeat a seating arrangement

The class has 6 students and 6 desks and students change the seating arrangement each day. We are asked to calculate the number of days that must pass before the class must repeat a seating arrangement.

The number of days that must pass before the class must repeat a seating arrangement is equal to the total number of seating arrangements.

Person one has 6 positions to choose from, person 2 has 5 positions to choose from and so on.

Total number of seating arrangements = 6 × 5 × 4 × 3 × 2 × 1

                                                                 = 720

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Answer:

-1/3

Step-by-step explanation:

Yhe equation 6x^2 + x - 2 has two roots, alpha and beta, that can be found by using the quadratic formula or by factoring.

The sum of the roots (alpha and beta) can be found by using the formula:

-b/a

where a = 6, b = 1 and c = -2

-1/6

The product of the roots (alpha and beta) can be found by using the formula:

c/a

where a = 6, b = 1 and c = -2

-2/6 = -1/3

So, the sum of the roots is -1/6 and the product of the roots is -1/3.

The lengths of the diagonals of PQRS will be 8 cm and 6 cm. Then the area of the rhombus PQRS will be 24 square cm.

Surface area refers to the area of an open surface or the border of a multi-object, whereas the area of a plane region or plane field refers to the area of a form or planar material.

The diagonals of the rhombus will be the same as the dimension of the rectangle that is 8 cm and 6 cm.

Then the area of the rhombus is given as,

A = (Product of diagonal of rhombus) / 2

A = (8 x 6) / 2

A = 48 / 2

A = 24 square centimeters

The lengths of the diagonals of PQRS will be 8 cm and 6 cm. Then the area of the rhombus PQRS will be 24 square cm.

The diagram is shown below.

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Answer:

A correlation of -1.00 indicates a strong negative correlation. This means that as one variable increases, the other variable decreases at a constant rate. In other words, there is a perfect inverse relationship between the two variables, with one increasing as the other decreases and vice versa. This is the strongest possible negative correlation.

The correlation coefficient ranges from -1 to 1, with -1 indicating a strong negative correlation, 0 indicating no correlation, and 1 indicating a strong positive correlation. Positive correlations indicate that as one variable increases, the other variable also increases. Negative correlations indicate that as one variable increases, the other decreases.

In summary, a correlation of -1.00 indicates a strong negative correlation, meaning that there is a perfect inverse relationship between the two variables.

The probability of both events is the sum minus the intersection. The answer should be rounded to two decimal places.

To calculate the probability of someone using a cell phone while driving or had no speeding violation, first calculate the individual probabilities of each event. The probability of someone using a cell phone while driving is P(cell phone) and the probability of someone having no speeding violation is P(no speeding violation). Then, add these two probabilities together, P(cell phone) + P(no speeding violation). This will give you the total probability of both events occurring. Finally, subtract the probability of the intersection, which is the probability of someone using a cell phone while driving and having no speeding violation. This will give you the total probability of someone using a cell phone while driving or having no speeding violation. Round the answer to the hundredths place.

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Answer:

Step-by-The length of o in the triangle AOP can be found using the Law of Cosines. The Law of Cosines states that for a triangle with sides a, b, and c and opposite angle C, the following formula holds:

c^2 = a^2 + b^2 - 2ab cos(C)

In this case, a = 38 cm, b = 29 cm, and C = 39°. The length of o can be found by rearranging the formula and solving for c:

c^2 = 38^2 + 29^2 - 2(38)(29) cos(39°)

c = sqrt(38^2 + 29^2 - 2(38)(29) cos(39°))

Using a calculator, we can find that c ≈ 47.3 cm, to the nearest centimeter, o = 47 cm.step explanation:

The piecewise function's domain and range are all real numbers, excluding x = 6, and all real numbers, respectively.

The broad range of values within which we are permitted to enter into our function is known as the area of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it may take as input. After we enter an x value, the function outputs this sequence of values.

The piecewise function is a function.

In the image that is attached, a function is shown.

The function's defined values are its domain, and its attainable values are its range.

With the exception of the x = 6 range, all real numbers fall inside the domain.

As a result, choice c is the right one.

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Answer:

Step-by-step explanation:

its C

Answer:

(12m+10)(2m-2)

hope this helps

The predicted femur length for someone with a height of 218 cm is 68 cm.

The equation of a line is given by:

y = mx + c

where m is the slope of the line and c is the y-intercept.

Example:

The slope of the line y = 2x + 3 is 2.

The slope of a line that passes through (1, 2) and (2, 3) is 1.

We have,

From the graph,

Coordinates = (30, 127), (35, 139), (40, 151).

Now,

The equation of the line of best fit.

y = mx + c

Where x is the femur length and y is the height.

Take two coordinates.

m = (139 - 127) / (35 - 30)

m = 12/5

m = 2.4

And,

(30, 127) = (x, y)

127 = 2.4 x 30 + c

127 - 72 = c

c = 55

So,

y = 2.4x + 55

Now,

For y = 218.

Solve for x.

218 = 2.4x + 55

218 - 55 = 2.4x

163 = 2.4x

x =163/2.4

x = 67.9

x = 68 cm

Thus,

The predicted femur length for someone with a height of 218 cm is 68 cm.

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The expression that represents the value of the stock after two years in terms of x is 1.6144x

After the first year, the value of the stock increased by 39%, which means that the stock's new value will be -

x + 0.39x = 1.39x

After the second year, the value of the stock decreased by 16%, which means that the stock's new value will be -

1.39x - 0.16(1.39x) = 1.16(1.39x)

Simplifying this expression, we get,

1.16(1.39x) = 1.6144x

Therefore, the expression that represents the value of the stock after two years in terms of x is 1.6144x.

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The complete question is -

Aubrey bought stock in a company two years ago that was worth x dollars. During the first year that he owned the stock, it increased by 39%. During the second year the value of the stock decreased by 16%. Write an expression in terms of x that represents the value of the stock after the two years have passed.

The two values of y such that the barn is 50 yards from the well are given as follows:

y = -47 and y = 53.

Suppose that we have two points with coordinates [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The shortest distance between them is given by the following equation:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

For this problem, we have that D = 50, hence the equation is given as follows:

sqrt[(-2 - (-2))² + (y - 3)²] = 50

y - 3 = ±50.

Hence the values of y are given as follows:

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The transformations are matched accordingly is given below.

A function transformation takes whatever the underlying function f (x) is and "transforms" (or "equates") it, which is a fancy way of saying you alter the equation and shift the graph over.

Parent function is given as f(x) = 2x - 6

The transformations are shifts f(x) 4 units down

f(x) → f(x) - 4

⇒ g(x)= 2x - 6 - 4 = 2x - 10

Then stretches f(x) by a factor of 4 away from the x-axis

f(x) → 4*f(x)

⇒ g(x) = 4(2x - 6) = 8x - 24

Now shifts f(x) 4 units right

f(x) → f(x - 4)

⇒ g(x) = 2(x - 4) - 6 = 2x - 14

To compresses f(x) by a factor of toward the y-axis (must be 4)

f(x) → f(4x)

⇒ g(x) = 2*4x - 6 = 8x - 6.

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Answer:

Step-by-step explanation:

Given room looks like a rectangular room.Let w be the wide and l be long of the rectangular room respectively.Given,w=10 feet and l=24 feet.

we know area of the rectangular room= l*w

So,area=10*23

area=230 sq.feet

Given,cost of trim=$0.85 per foot

So,total cost =230* 0.85

=195.5

So,Jennifer charges $195.5 to buy enough

Answer: 27

Step-by-step explanation:

8^x+1 = 64

8^x+1 = 8²

x+1 =2

x = 2 - 1

x = 1

To Find :

3^2x +1

Substitute the value of x :

3^2(1)+ 1

3^2+1

3^3

27

Two events that are disjoint are not independent. This is because that disjoint events do not overlap, which means that if one event occurs, the other cannot. So, the occurrence of one event provides information about the absence of the other, which violates the definition of independence.

Two events A and B are considered independent if the occurrence of A has no effect on the likelihood of B occurring, and vice versa.

In other words, the probability of both events happening at the same time is equal to the product of their individual probabilities:

[tex]P(A and B) = P(A) * P(B) (B).[/tex]

This formula cannot be satisfied when two events are disjoint because if one event occurs, the other cannot occur. As a result, two disjoint events are not independent.

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The Olap operations for a data warehouse of a train company contains information about train segments is performed in order to answer the queries with dimension hierarchies when needed.

OLAP operation for first case is Filter on the train dimension to select only Alstom trains. Filter on the departure station dimension to select only French or Belgian stations. Filter on the year dimension to select only 2012. Aggregate the number of kilometers measure across the selected dimensions

Dimension hierarchies for this case is Station dimension: Country > City > Station,  Trip dimension: Year > Month > Day > Trip ID.

OLAP operation for the second case is Filter on the departure station and arrival station dimensions to select only trips that cross country borders. Filter on the year dimension to select only 2012. Aggregate the duration measure across the selected dimensions

Dimension hierarchies for this case is Station dimension: Country > City > Station, Trip dimension: Year > Month > Day > Trip ID.

OLAP operation for third case is Filter on the departure station and arrival station dimensions to select only trips that involve Paris. Filter on the month dimension to select only July 2012. Aggregate the number of trips measure across the selected dimensions.

Dimension hierarchies for this case is Station dimension: Country > City > Station, Trip dimension: Year > Month > Day > Trip ID.

OLAP operation for fouth case is Filter on the departure station and arrival station dimensions to select only trips that involve Belgian stations. Filter on the year dimension to select only 2012.Aggregate the duration measure across the selected dimensions. Calculate the average duration of the segments

Dimension hierarchies for this case is Station dimension: Country > City > Station, Trip dimension: Year > Month > Day > Trip ID.

OLAP operation for fifth case is Aggregate the number of passengers measure across all segments of each trip. Divide by the number of segments per trip to get the average number of passengers per segment

Dimension hierarchies for this case is Station dimension: Country > City > Station, Trip dimension: Year > Month > Day > Trip ID.

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A process in which a number is changed, such as by adding, subtracting, dividing or multiplying is called arithmetic process.

The four basic operations of mathematics are addition, subtraction, multiplication and division. We call this group of four operations "arithmetic". Arithmetic is defined by the four most basic operations in mathematics. These four operations are the most basic, but that doesn't mean they're always easy to perform. In other words, arithmetic ranges from very simple things like 1 + 1 to very complex and complex things. It all depends on the context in which a person is working, but when we are dealing with one of the four operations of addition, subtraction, multiplication or division we are dealing with so-called arithmetic operations in mathematics.

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Complete question:

A process in which a number is changed, such as by adding, subtracting, dividing or multiplying is called:________.

Answer: The distance between Star B and Star C can be found using the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the lengths of the two shorter sides is equal to the square of the length of the hypotenuse (the longest side). In this case, the lengths of the two shorter sides are the distances from Star A to Star B (50 lightyears) and from Star A to Star C (120 lightyears).

So, we have:

(Star B to Star C)^2 = (Star A to Star B)^2 + (Star A to Star C)^2

(Star B to Star C)^2 = 50^2 + 120^2

(Star B to Star C)^2 = 2500 + 14400

(Star B to Star C)^2 = 16900

Taking the square root of both sides:

Star B to Star C = √16900

Star B to Star C = 129 lightyears

So, Star B and Star C are 129 lightyears apart.

Step-by-step explanation:

Answer:

Below

Step-by-step explanation:

The y-axis intercept occurs when x = 0

  so the first one is y = 21    ( this is the value when x = 0 from table)

the second one shows every 4 increase causes a 3 decrease in y

   so every 4 DECREASE in x causes a +3 INCREASE in y

     decrease x = 4 to   x = 0     increase y = 6 to y = 9

Hence, it is proven that PQRS is a parallelogram

Quadrilateral PQRS formed by joining the midpoints of quadrilateral ABCD is a parallelogram. (see attached image)

Let A (x1, y1), B(x2, y2), C (x3, y3) & D (x4,y4) be the coordinates of A, B, C & D respectively. Draw the line BD. (see attached image)

Since the midpoint divides a side into equal parts, AP=PB and the same will apply to all sides.

According to the midpoint theorem, SR = BD/2

Same as in triangle ABD, SP is parallel to BD, and SP =BD/2

From the above two equations SR is parallel to SP and SR=SP.

As one pair of opposite sides are equal in length and parallel to each other, the resultant figure by joining the midpoints of a quadrilateral become a parallelogram.

Draw diagonal BD.

BD is the diagonal of the quadrilateral which forms two triangles ABD and BCD. Consider the triangle BCD. BD is parallel to QR.

Hence PQRS is a parallelogram

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Solve the following problem below.

1. Midpoints in a Quadrilateral

Draw a quadrilateral ABCD. Try to draw your quadrilateral so that no two sides are congruent, no two angles are congruent, and no two sides are parallel.

Let P, Q, R, and S be the midpoints of sides AB, BC, CD, and DA, respectively. Use a ruler to locate these points as precisely as you can, and join them to form a new quadrilateral PQRS. What do you notice about the quadrilateral PQRS?

Suppose your quadrilateral ABCD lies in the coordinate plane. Let (x1,y1) be the coordinates of vertex A, (x2,y2) the coordinates of B, (x3,y3) the coordinates of C, and (x4,y4) the coordinates of D. Use coordinates to prove the observation you made in part (a).

The statements that are true about rectangles are mentioned in options  

A,B,C,E.

Rectangles -A shape with four sides and internal angles is a rectangle. The lengths of the other two sides are offset by two. The rectangle's diagonal sides are of identical length.

The opposite sides of a rectangle are equal and parallel to one another.

The diagonals cut each other in half, but not exactly.

All diagonals are the same length.

The rectangle's diagonals line up.

The total internal angles add up to the same value

Every internal angle has the same value.

A rectangle has congruent angles on all sides.

A rectangle's opposing angles are congruent.

We may thus infer that the statements about rectangles in the options are accurate based on the aforementioned features.

Q. Select all the statements that are true about rectangles.

A Diagonals are congruent.

B Diagonals bisect angles.

C Opposite angles are congruent.

D Diagonals are perpendicular.

E Diagonals bisect each other.​

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Out of three tables given, only second table ( when we take the order from top to bottom )satisfies this.

What is a linear equation?

A linear equation is an equation in which each term has at max one degree. Linear equations in variables x and y can be written in the form

y = mx + c

Linear equation with two variables, when graphed on the cartesian plane with axes of those variables, give a straight line.

Given are three tables in x and y and we have to find which table shows a linear relation.

We know in  a linear relation between x and y the graph would be a straight line and also the slope would be constant

i.e. change of y/change of x for any pair in the table would be a constant.

Out of three tables given, only second table ( when we take the order from top to bottom )satisfies this.

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