Jake said you can compare two fractions with same denominator by only comparing the numerators

The equation that represents the graph through the data points in the table is Option K: y = 6x - 8.

What is an equation?

A mathematical definition of an equation is a claim that two expressions are equal when they are joined by the equals sign ("=").

The data points are given in the table.

The first equation is -

y = x²

Substitute the value of y = 40, as given in the table -

40 = x²

x = √40

x = 6.32

The value for x is obtained as 6.32 when y is 40.

This value does not corresponds with the values in the table.

Therefore, equation y = x² is incorrect.

The second equation is -

y = 6x - 8

Substitute the value of y = 40, as given in the table -

40 = 6x - 8

x = (40 + 8)/6

x = 48/6

x = 8

The value for x is obtained as 8 when y is 40.

This value corresponds with the values in the table.

Therefore, equation y = 6x - 8 is correct.

The third equation is -

x + y = 10

Substitute the value of y = 40, as given in the table -

x + 40 = 10

x = 10 - 40

x = -30

The value for x is obtained as -30 when y is 40.

This value does not corresponds with the values in the table.

Therefore, equation x + y = 10 is incorrect.

The fourth equation is -

x - y² = 0

Substitute the value of y = 40, as given in the table -

x - (40)² = 0

x = 0 + 1600

x = 1600

The value for x is obtained as 1600 when y is 40.

This value does not corresponds with the values in the table.

Therefore, equation x - y² = 0 is incorrect.

The fifth equation is -

x² - y² = 0

Substitute the value of y = 40, as given in the table -

x² - (40)² = 0

x² = 0 + 1600

x = √1600

x = 40

The value for x is obtained as 40 when y is 40.

This value does not corresponds with the values in the table.

Therefore, equation x² - y² = 0 is incorrect.

To learn more about equation from the given link

https://brainly.com/question/25896797

#SPJ1

The statement that would NOT be of concern when considering the nature criteria for evaluating secondary data is the relationships examined should be taken into account. Thus, option D is the answer

While it is important to take relationships into account when analyzing data, this statement is not specific to evaluating secondary data, but rather a general principle of data analysis.

The other statements listed  are all relevant concerns when evaluating secondary data, as secondary data may not always be directly relevant or appropriate for the current problem, and it is important to assess the accuracy and usefulness of the data for the present study.

Learn more about secondary data:

https://brainly.com/question/29750618

#SPJ4

1) The amount of money invested at 15% = $30,000

2) The amount of money invested at 5% = $20,000

What is the amount invested?

The amount invested is the total cost of the mutual fund investment units you currently own. Amount Invested = Number of Units x Purchase NAV. The current value of the mutual fund investment units that you currently own.

To solve this problem, we need to set up and solve a system of equations. Let x be the amount of money invested in B-rated bonds and y be the amount of money invested in the CD. We know that:

x + y = $50,000 (the total amount of money invested must equal $50,000)

0.15x + 0.05y = $5,000 (the total interest earned must equal $5,000)

Now we can use the first equation to solve for one of the variables in terms of the other. If we subtract y from both sides of the first equation, we get:

x = $50,000 - y

We can substitute this expression for x into the second equation to get:

0.15($50,000 - y) + 0.05y = $5,000

Solving for y, we get:

y = $20,000

Now we can substitute this value back into the first equation to find the value of x:

x = $50,000 - $20,000

x = $30,000

Therefore, Betsy should invest $30,000 in B-rated bonds and $20,000 in a CD to earn exactly $5,000 in interest per year.

To know more about amount invested visit,

https://brainly.com/question/12654446

#SPJ1

Answer:Equation (1):

-8x + 4y = 24

Equation (2):

-7x + 7y = 28

Simplify the equation:

Equation 1 can be simplify by 4:

-2x + y = 6

Equation 2 can be simplify by 7:

-x + y = 4

Add x to both sides of the equation 2:

y = x + 4

Substitute equation 2 into 1:

x + 4 - 2x = 6

x - 2x = 6 - 4

- x = 2

x = - 2.

Substitute - 2 for x in equation 2:

y = - 2 + 4

y = 2.

Therefore, (x, y) = (- 2, 2)

The maximum profit is achieved when the company produces 2861 units of the product.

From the question, we have the following parameters that can be used in our computation:

P(x) = 103 - 0.018x

C(x) = 650 + 90x

The profit function is given as

p(x) = x * P(x) - C(x)

So, we have

p(x) = 103x - 0.018x² - 650 + 90

p(x) = 103x - 0.018x²  - 560

See attachment for the graph

From the graph, we have

Maximum value of x = 2861

Hence, the maximum number of units is 2861

Read more about functions at

https://brainly.com/question/28532394

#SPJ1

The proportion of all CEOs of medium and large companies who have MBAs is between 27.9% and 33.5%.

The formula we use is the Wilson Score Interval, which is a modified version of the Binomial Proportion Confidence Interval.

In this formula, we will use the following variables:

n = 344 (the total number of CEOs surveyed)

X = 97 (the number of MBAs)

z = 1.96 (the z-value corresponding to a 95% confidence level)

We then calculate the confidence interval as follows:

Lower Bound = (X + (z^2/2))/(n + z^2) - (z * SQRT((X * (1-X))/(n + z^2) + (z^2/4)) / (n + z^2)

Upper Bound = (X + (z^2/2))/(n + z^2) + (z * SQRT((X * (1-X))/(n + z^2) + (z^2/4)) / (n + z^2)

Plugging in the values for n, X, and z, we get the following confidence interval:

Lower Bound = 0.279

Upper Bound = 0.335

Therefore, we can be 95% confident that the proportion of all CEOs of medium and large companies who have MBAs is between 27.9% and 33.5%.

Learn more about Confidence Interval here:

https://brainly.com/question/24131141

#SPJ4

The probability of choosing, without replacement, another white marble is 16/27

The probability of choosing another white marble can be calculated as follows:

From the problem it can be deduced that, there are 17 white marbles out of a total of 28 marbles (11 green + 17 white),

The probability of choosing a white marble

= 17 / 28

After the first white marble is chosen, the total number of marbles decreases to 27 and the number of white marbles decreases to 16.

The probability of choosing another white marble without replacement is = 16/27.

Learn more about probability at:

https://brainly.com/question/25870256

#SPJ1

The second side of triangle has the length is 12cm.

Given data :

We know that,

BY p Pythagorean theorem,

a² + b² = c²

9² + b² = 15²

b² = 15² - 9²

b² = 144

b = 12

Therefore,

The second side means the hypotenuse is equal to 12cm.

Learn more about Pythagorean theorem refer to :

https://brainly.com/question/343682

#SPJ4

2 ± √3 is the number that must be added in order to complete the square.

What is factorization?

Writing a number or other mathematical object as the result of numerous factors—typically smaller or simpler objects of the same kind—is known as factorization or factoring in mathematics.

Here, we have

Given: x² + 4x + 1

We have to determine the number that must be added in order to complete the square

= x² + 4x + 1 = 0

= x² + 4x + 4 - 3 = 0

= (x- 2)² - (√3)² = 0

= ((x - 2) - √3)((x - 2) + √3) = 0

=  (x - 2 - √3)(x - 2 + √3) = 0

x = 2 ± √3

Hence, 2 ± √3 is the number that must be added in order to complete the square.

To learn more about the factorization from the given link

https://brainly.com/question/8021175

#SPJ1

We can conclude that the resistors from Manufacturer 1 have better mean resistance than Manufacturer 2.

What is the null hypothesis?

In statistics, the null hypothesis is a statement or assumption that there is no relationship or difference between certain populations or variables. It is typically represented by the symbol H0. The null hypothesis is used as a starting point for statistical hypothesis testing, which is a method used to determine whether the null hypothesis can be rejected or not based on sample data.

Given that the specialist has purchased 35 resistors from Manufacturer 1 with a mean of 150 ohms and a standard deviation of 2 ohms, and Manufacturer 2 offers a sample of 40 resistors with a mean of 148 ohms and a standard deviation of 2.5 ohms, we can assume that the two samples are independent and normally distributed.

To compare the means of the two samples, we can use a t-test for the means of two independent samples. The t-test will allow us to determine whether the difference in means between the two samples is statistically significant, or if it could have occurred by chance.

The null hypothesis of the t-test would be that there is no difference in means between the two samples, or that the mean of the Manufacturer 1 sample is equal to the mean of the Manufacturer 2 sample. The alternative hypothesis would be that there is a difference in means, or that the mean of the Manufacturer 1 sample is not equal to the mean of the Manufacturer 2 sample.

The t-value can be calculated using the formula:

t = (x1-x2)/sqrt((s1^2/n1) + (s2^2/n2))

where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.

Once the t-value is calculated, we can look up the t-value in a t-table to find the corresponding p-value. The p-value represents the probability of obtaining a t-value as extreme as the one calculated, assuming the null hypothesis is true.

If the p-value is less than the chosen significance level (usually 0.05), we would reject the null hypothesis and conclude that there is a statistically significant difference in means between the two samples

Hence, we can conclude that the resistors from Manufacturer 1 have better mean resistance than Manufacturer 2.

To learn more about the null hypothesis, visit:

https://brainly.com/question/13045159

#SPJ4

well, as I see it Person1 is faster than Person2, but Person2 doesn't factor in the issue here, let's nevermind Person2.

most of the procedures are 45mins each, namely on average they're 45 mins each.

so Person1 say did 9 procedures, but two of those guys took much longer, too 2 hours each, so two procedures alone ate 4 hours.

Now, Person1 besides doing those two really long procedures, has to also finish the other seven, 2 + 7 = 9, so there are 7 more procedures that on average take 45 mins each.

[tex]\stackrel{\textit{\LARGE minutes}}{\stackrel{\textit{two really long ones}}{240}~~ + ~~\stackrel{\textit{the rest of them}}{45(7)}}\implies 555\implies \stackrel{\textit{9 hours and 15 minutes}}{9.25~hours}[/tex]

Answer:

y = x - 4

Step-by-step explanation:

You can take any x input value from the chart and it's output and sub it into the equation

Assume (_) = z

Let's take the first input and output

6 = 10 + z

Z= - 4

Now sub z into the equation,

y = x - 4

Answer:

Area_shaded

= 340.9 cm^2

Step-by-step explanation:

Find the area of the circle, then subtract the area of the triangle.

The 25cm side of the triangle is a hypotenuse of the right triangle. It is also the diameter of the circle.

The radius of the circle is 1/2 the diameter. So the radius is 1/2•25, or 12.5cm

We need the radius to find the area of the circle.

Area_circle

= pi•r^2

= pi•12.5^2

= 490.9 cm^2

The two legs of the triangle can serve as our base and height to find the area of the triangle.

Area_triangle

= 1/2b•h

= 1/2(20)(15)

= 150 cm^2

Subtract.

490.9 - 150

= 340.9cm^2

The area of the shaded region is 340.9cm^2.

It is true that the hypothesis test for the population mean must be a one-tailed test having the rejection region in the lower tail, which is on the left hand of the sampling distribution.

A one-tailed test is basically a hypothesis test which help us to test whether the given sample mean would be higher or will be lower than the population mean. The rejection region is basically the area for which the null hypothesis is rejected.

When we perform a left tailed test for our hypothesis, that is the lower tail hypothesis, then the rejection region will lie in the left tail after the critical value and since in the given question, the mean wait for the services will be less than 15 minutes, we will have to perform a one-tailed rest which has a rejection region present in the lower left hand tail.

To know more about one-tailed test here

https://brainly.com/question/14053535

#SPJ4

On an average, about 2.13 people region will need to get selected in order to find that one person who carries the genetic trait.

Random selection is a very important process in research methodology. The purpose of random selection is to increase the generalizability of the results as when we draw a random sample from a large population, it is less likely to be subject to bias.

Since 47 percent of the people in the population are carrying the gene, the probability of random selection will be 0.47. But we need to also consider how many trials will be unsuccessful. Therefore, we will use the mean,

1/0.47 = 2.127 ≅ 2.13

--The given question is incomplete, the complete question is

"According to a recent survey, 47 percent of the people living in a certain region carry a certain genetic trait. People from the region will be selected at random one at a time until someone is found who carries the genetic trait. On average, how many people from the region will need to be selected to find one person who carries the genetic trait?"--

To know more about random selection here

https://brainly.com/question/10678373

#SPJ4

The more appropriate average score for the two groups of adolescents is 1.83.

The appropriate average score for the two groups of adolescents can be computed using the following formula: (Group1 score + Group2 score) / 2.

For example, in the first row, the Group 1 score is "Lots" and the Group 2 score is "Little". The average score for this row would be (3 + 1) / 2 = 2.

In the second row, the Group 1 score is "Little" and the Group 2 score is "Somewhat". The average score for this row would be (1 + 2) / 2 = 1.5.

Similarly, for the remaining 8 rows, the average scores can be calculated as follows:

Row 3: (1 + 2) / 2 = 1.5

Row 4: (1 + 1) / 2 = 1

Row 5: (1 + 2) / 2 = 1.5

Row 6: (1 + 3) / 2 = 2

Row 7: (1 + 3) / 2 = 2

Row 8: (1 + 2) / 2 = 1.5

Row 9: (1 + 2) / 2 = 1.5

Row 10: (3 + 2) / 2 = 2.5

Therefore, the more appropriate average score for the two groups of adolescents is 1.83.

Learn more about average here:

https://brainly.com/question/24057012

#SPJ4

The probability of X being greater than 0 is 1.

P(X>0)=1-P(X≤0)

=1-φX+Y(-∞)=1-e^(-2*(-∞))-0.24*2*(-∞)-0.09*e^(-2*(-∞))

=1-0-0-0=1

Since x and y are identically independent random variables, P(X>0)=1-P(X≤0).

The moment generating function of x+y is given as φX+Y(t)=e2t+0.24.2t+0.09e2t.

To find P(X>0), we need to calculate P(X≤0). This can be done by putting t=-∞ in the moment generating function.

Therefore, P(X>0)=1-φX+Y(-∞)=1-e^(-2*(-∞))-0.24*2*(-∞)-0.09*e^(-2*(-∞))=1-0-0-0=1

The probability of X being greater than 0 is 1.

Learn more about independent variable here

https://brainly.com/question/29430246

#SPJ4

The length of the missing sides for given angles are

What is Pythagoras' Theorem?

Pythagoras' Theorem is a fundamental result in Euclidean geometry named after the ancient Greek mathematician Pythagoras. It states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In other words, if a and b are the lengths of the legs of a right triangle and c is the length of the hypotenuse, then the theorem can be written as:

c² = a² + b²

tan A = a/c

c = a / tan A

We know that a = 100 and tan A = 100

so c = a / tan A = 100/100 = 1

We also know that b = 100

Now we can use the Pythagorean Theorem to find a:

a² + b² = c

100^2 + 100^2 = 1²

10000 + 10000 = 1

20000 = 1

a = sqrt(20000) = √(2000) × √(10) = 140.7107 × 10[tex]{}^{1/2}[/tex] = 141.42135

So,

side a = 141.42135

side b = 100

side c = 1

To learn more about Pythagoras' Theorem, visit:

brainly.com/question/231802

#SPJ4

The constant term is the term independent of a variable, which is [tex]15[/tex].

The coefficient of [tex]x[/tex] is the constant being multiplied by [tex]x[/tex] in the term with [tex]x[/tex] as the only variable, which is [tex]17[/tex].

The standard deviation for the given data, can be found to be 3. 97

To find the standard deviation, you first need to find the mean of the data as:

= Sum of the numbers / Sample number

= ( 16 + 10 + 5 + 7 + 13 ) / 5

= 51 / 5

= 10. 2

The variance can then be found from this data, the mean, and a variance calculator to be 15.76.

The standard deviation is:

= √ 15.76

= 3. 97

Find out more on standard deviation at https://brainly.com/question/475676

#SPJ1

Step-by-step explanation:

add 6 and 2 to get 8 and add all the numbers to get 9

Answer: The two numerical expressions that correctly represent the phrase "twice the sum of nine and four" are:

2 * (9 + 4) = 2 * 13 = 26

2(9 + 4) = 2(13) = 26

Both expressions use the correct mathematical operations to represent the phrase "twice the sum of nine and four" and both will yield the same result of 26.

Step-by-step explanation:

Answer:

156

Step-by-step explanation:

10% of x=24

100% of x=24*10

x=240

3/4x=180

65% of x=0.65*240=156

Answer:156

Step-by-step explanation:

Answer:

The answer is 5x-2

Step-by-step explanation:

3x-(2-2x)

3x-2+2x

5x-2

Answer:

2 -> 4

7 -> 29

10 -> 44

13 -> 59

Answer:

A 30 dogs and 48 cats

Step-by-step explanation:

The ratio of cats to dogs in the local shelter is 5 to 8, which means for every 5 cats, there are 8 dogs. If we assume that the total number of cats and dogs in the shelter is a multiple of the ratio, we can find the possible numbers of cats and dogs. In option A, the number of cats and dogs is 30 dogs and 48 cats which is a multiple of the ratio. 59 = 45 and 89 = 72 which is the closest to the number of cats and dogs in option A. Thus, option A shows the possible numbers of cats and dogs in the local shelter.

The determinant of the matrix A, where A is [1 1 47 1 2 2 1 2 5 2], is -13. This was calculated by finding the cofactors of A, placing them in the matrix C, and then using the ACT formula to calculate the determinant of A.

C=

[1 -2 -2

-1 1 1

-47 -2 -2]

ACT=1⋅1⋅1+(-2)⋅2⋅1+(-2)⋅5⋅2=1+(-4)+(-10)= -13

The determinant of A is -13.

1. To find the cofactors of A, we need to take the determinant of each of the 3x3 matrices formed by removing one of the columns and one of the rows of A. For example, to find the cofactor of the element in the first row, first column, we would remove the first row and first column from A, and calculate the determinant of the remaining matrix.

2. We can then place the cofactors in the matrix C, which would look like this:

C=

[1 -2 -2

-1 1 1

-47 -2 -2]

3. To calculate the determinant of A, we can use the ACT formula:

ACT=1⋅1⋅1+(-2)⋅2⋅1+(-2)⋅5⋅2=1+(-4)+(-10)= -13

Therefore, the determinant of A is -13.

The determinant of the matrix A, where A is [1 1 47 1 2 2 1 2 5 2], is -13. This was calculated by finding the cofactors of A, placing them in the matrix C, and then using the ACT formula to calculate the determinant of A.

Learn more about matrix here

https://brainly.com/question/28180105

#SPJ4

The posterior predictive probability that if the die is thrown again, it will not show a six is 5/6.

(a) The likelihood for the observed data is P(k=6|Data) = (1/16)*(1/6)^1 * (5/6)^1 = 5/96. The maximum likelihood estimate for k is 6.

(b) The normalized posterior distribution for k is P(k|Data) = (1/16)*(1/6)^1 * (5/6)^1 * (15/8) = 75/768. The posterior mean for k is 4.5.

(c) The posterior predictive probability that if the die is thrown again, it will not show a six is 5/6.

The maximum likelihood estimate for k (the unknown number of faces marked with a six on the six-sided die) is 6. The normalized posterior distribution for k is P(k|Data) = 75/768, and the posterior mean for k is 4.5. The posterior predictive probability that if the die is thrown again, it will not show a six is 5/6.

Learn more about probability here

https://brainly.com/question/11234923

#SPJ4