Jasmine the Great Dane has a head 30 cm long. Her tall is equal to the size of her head plus one-half the size of her body. Her body is the size of her head phluss the tal. How long is Jasmine? ​

Answers

Answer 1

Answer:

240 cm

Step-by-step explanation:

Let x = tail   y = body

x = 30 + 1/2y

y = 30 + x

Let's plug in the x equation at the bottom

y = 30 + 30 + 1/2y

y = 60 + 1/2y

Bring the like terms to one side

y = 60 + 1/2y

-1/2y    -1/2y

1/2y = 60

Multiply both sides by 2 to get the length of the body

1/2y x 2 = 60 x 2

y = 120

Now we can plug in the new y into another equation, let's use the top one

x = 30 + 1/2(120)

x = 30 + 60

x = 90 = length of the tail

Add em all up

120 + 90 + 30 = 240


Related Questions

solve x^3-7x^2+7x+15​

Answers

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

Oh Brian~
I need help again

Answers

Answer:

18c^3d^9

Step-by-step explanation:

2c^3 d^2 * 9d^7

We know that  we add the exponents when the base is the same

2*9  c^3 d^(2+7)

18c^3d^9

I need to know the answer ASAP

Answers

Answer:

Step-by-step explanation:

Smart phone: Among 239 cell phone owners aged 18-24 surveyed, 103 said their phone was an Android phone. Part: 0 / 30 of 3 Parts Complete Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places. The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is .

Answers

Answer:

The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.4137.

Step-by-step explanation:

The point estimate is the sample proportion.

Sample proportion:

103 out of 249, so:

[tex]p = \frac{103}{249} = 0.4137[/tex]

The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is 0.4137.

log_c(A)=2
log_c(B)=5,
solve log_c(A^5B^3)

Answers

We know that [tex]\log_a(bc)=\log_a(b)+\log_a(c)[/tex].

Using this rule,

[tex]\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3)[/tex].

We also know that [tex]\log_c(a^b)=b\log_c(a)[/tex].

Using this rule,

[tex]\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)[/tex]

Now we know that [tex]\log_c(A)=2,\log_c(B)=5[/tex] so,

[tex]5\cdot2+3\cdot5=10+15=\boxed{25}[/tex].

Hope this helps :)

The graph shows the distribution of the number of text messages young adults send per day. The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.

What percentage of young adults send more than 158 text messages per day?


16%

34%

68%

84%

Answers

Answer:

You'd think its 34% but apparently it's 16%.

I hope this is right. If its not then it must be 34%.

(A) -- or maybe (B). 80% confident it is A.

ED2021

The following are on a parabola defining the edge of a ski
(-4, 1), (-2, 0.94), (0.1)
The general form for the equation of a parabola is:
Ax^2+ Bx +C= y
Required:
a. Use the x- and y-values of 1 of the points to build a linear equation with 3 variables: A, B, and C.
b. Repeat this process with 1 of the other to build a 2nd linear equation.
c. Record your equation here. Repeat this process with the other point to build a 3rd equation.

Answers

9514 1404 393

Answer:

  a) 16A -4B +C = 1

  b) 4A -2B +C = 0.94

  c) C = 1

Step-by-step explanation:

Substitute the x- and y-values into the general form equation.

a. A(-4)² +B(-4) +C = 1

  16A -4B +C = 1

__

b. A(-2)² +B(-2) +C = 0.94

  4A -2B +C = 0.94

__

c. A(0)² +B(0) +C = 1

  C = 1

_____

Additional comment

Solving these equations gives A=0.015, B=0.06, C=1. The quadratic is ...

  0.015x² +0.06x +1 = y

x^{2} +y^{2} =?
cho mình hỏi với

Answers

Answer:

[tex]{ \sf{ {x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy }}[/tex]

Step-by-step explanation:

[tex]{ \tt{ {(x + y)}^{2} = (x + y)(x + y) }} \\ { \tt{ {(x + y)}^{2} = ( {x}^{2} + 2xy + {y}^{2}) }} \\ { \tt{( {x}^{2} + {y}^{2} ) = {(x + y)}^{2} - 2xy}}[/tex]

Please help i need the answer asap!!!
if you know the answer please give it to me as soon as you can!!

Answers

Answer:

Choice b.

Step-by-step explanation:

Replace (x, y) with (1, 1) and verify if the equations are correct.

You would ignore the x and y in the equations. Testing one of each pair.

a. 3 + 2 = 3, incorrectb. 7 + 2 = 9, correctc. 8 + 1 = 7, incorrectd. 8 - 2 = 4, incorrect

It is obvious that only b. is correct.

Choice b because it it now where’s my brainliest

Using the following equation, find the center and radius: x2 −2x + y2 − 6y = 26 (5 points)

Answers

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

[tex]x^2-2x + y^2 - 6y = 26[/tex]

Typically, the equation of a circle would be in the form [tex](x-h)^2+(y-k)^2=r^2[/tex] where [tex](h,k)[/tex] is the center and [tex]r[/tex] is the radius.

To get the given equation [tex]x^2-2x + y^2 - 6y = 26[/tex] into this form, we must complete the square for both x and y.

1) Complete the square for x

Let's take a look at this part of the equation:

[tex]x^2-2x[/tex]

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

[tex]x^2-2x+1[/tex]

Great! Now, let's add this to our original equation:

[tex]x^2-2x+1+y^2-6y = 26[/tex]

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

[tex]x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27[/tex]

Complete the square:

[tex](x-1)^2+y^2-6y = 27[/tex]

2) Complete the square for y

Let's take a look at this part of the equation [tex](x-1)^2+y^2-6y = 27[/tex]:

[tex]y^2-6y[/tex]

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

[tex]y^2-6y+9[/tex]

Great! Now, back to our original equation:

[tex](x-1)^2+y^2-6y+9= 27[/tex]

Remember to add 9 on the other side as well:

[tex](x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36[/tex]

Complete the square:

[tex](x-1)^2+(y-3)^2= 36[/tex]

3) Determine the center and the radius

[tex](x-1)^2+(y-3)^2= 36[/tex]

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

Answer:

[tex]\sqrt{g^2+f^2-c}[/tex]

[tex]g=-1,f=-3,c=-26[/tex]

so, the Center of the equation is [tex](1,3)[/tex]

Center → (1 , 3)

[tex]\sqrt{(-1)^2+(-3)^2-(-26})[/tex]

[tex]=\sqrt{1+9+26}[/tex]

[tex]=\sqrt{36}[/tex]

[tex]=6[/tex]

Radius → 6

OAmalOHopeO

Help. The graph shows the system of equations below.
2x -3y = -6
y = - 1/3x -4

Answers

9514 1404 393

Answer:

  (a) The blue line ... solution ... (-6, -2)..

Step-by-step explanation:

The second equation describes a line with negative slope and a y-intercept of -4. This is clearly the red line on the graph.

The blue line represents the equation 2x -3y = -6.

The point of intersection of the two lines is (-6, -2), so that is the solution to the system of equations. This, by itself, is sufficient for you to choose the correct answer.

Please help me with this question

Answers

the answer above is correct!:))

Why does cube root 7 equal 7 to the 1/3 power

Answers

Answer:

Step-by-step explanation:

Here's how you convert:

[tex]\sqrt[n]{x^m}=x^{\frac{m}{n}[/tex]  The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.

A couple of examples:

[tex]\sqrt[3]{x^4}=x^{\frac{4}{3}[/tex]

[tex]\sqrt[5]{x^7}=x^{\frac{7}{5}[/tex]

It's that simple. For your problem in particular:

[tex]\sqrt[3]{7}[/tex] is the exact same thing as [tex]\sqrt[3]{7^1}=7^{\frac{1}{3}[/tex]

Which expression is equivalent to 3/2

Answers

Answer:

C

Step-by-step explanation:

You have fit a regression model with two regressors to a data set that has 20 observations. The total sum of squares is 1000 and the model (regression) sum of squares is 750. What is the adjusted R-squared value for this model

Answers

Answer:

Hence the adjusted R-squared value for this model is 0.7205.

Step-by-step explanation:

Given n= sample size=20  

Total Sum of square (SST) =1000  

Model sum of square(SSR) =750  

Residual Sum of Square (SSE)=250  

The value of R ^2 for this model is,  

R^2 = \frac{SSR}{SST}  

R^2 = 750/1000 =0.75  

Adjusted [tex]R^2[/tex] :

[tex]Adjusted R^2 =1- \frac{(1-R^2)\times(n-1)}{(n-k-1)}[/tex]

Where k= number of regressors in the model.

[tex]Adjusted R^2 =1-(19\times 0.25/((20-2-1)) = 0.7205[/tex]

o the area of a rhombus is 24m²
and one of its diagonals 18cm find
the side of the rhombus​

Answers

Area of rhombus = 1/2 × d1 × d2

Let the other diagonal be x

ATQ

1/2 × 18 × x = 24

9 × x = 24

x = 24/9

x = 8/3

Now half each diagonal = 9 and 4/3

Now side = b² + p² = h²

9²+(4/3)² = h²

81 + 16/9 = h²

729/9 + 16/9 = h²

745/9 = h²

√(745/9) = h

Therefore the side of the rhombus is √(745/9)cm

Answered by Gauthmath must click thanks and mark brainliest

What is (x+13)^2? pls help!!!

Answers

Answer: X^2 + 26x + 169

The posted weight limit for a wooden
bridge is 6,500 pounds. A delivery truck
is loaded with identical boxes of canned
goods that weigh 16 pounds each. If the
combined weight of the empty delivery
truck and the driver is 3,512 pounds,
what is the maximum number of boxes
that would keep the combined weight of
the truck, driver, and boxes below the
posted weight limit?

Answers

9514 1404 393

Answer:

  186

Step-by-step explanation:

Let b represent the number of boxes in the truck. Then for the weight limit to be met, we require ...

  3512 +16b < 6500

  16b < 2988

  b < 186.75

The maximum number of boxes is 186.

Form a polynomial whose zeros and degree are given,
Zeros: - 2, 2,7; degree: 3
Type a polynomial with integer coefficients and a leaning coefficient of 1 in the box below.

F(x)=

Answers

Answer:

if the zeros are x = -2, x = 0, and x = 1

then (x + 2), x and (x - 1) are factors of the polynomial

multiply these factors together

p(x) = x(x + 2)(x - 1)

p(x) = x(x2 + x - 2)

p(x) = x3 + x2 - 2x

this is a polynomial of degree 3 with the given roots

What is the measure of the angle in red?
70°

Answers

Answer:

See pic below.

Answer: C. 380°

Step-by-step explanation:

I need help answering this ASAP

Answers

Answer:

"D"

if you multiply by Conjugate

the denominator would end up A^2 - b^2

the answer has 25 - 10x

that is D

Step-by-step explanation:

Which of the following conversions is possible?
Meters to Liters
Feet to Miles
Pounds to Inches
Grams to Centimeters

Answers

Answer:

Feet to Miles

Step-by-step explanation:

Answer:

Feet to Miles

Step-by-step explanation:

Both units must measure the same quantity.

Assume a random variable representing the amount of time it takes for a customer service representative to pick up has a uniform distribution between 15 and 20 minutes. What is the probability that a randomly selected application from this distribution took less than 18 minutes

Answers

Answer:

0.6 = 60% probability that a randomly selected application from this distribution took less than 18 minutes.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.  

The probability of finding a value of at lower than x is:

[tex]P(X < x) = \frac{x - a}{b - a}[/tex]

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

Uniform distribution between 15 and 20 minutes.

This means that [tex]a = 15, b = 20[/tex]

What is the probability that a randomly selected application from this distribution took less than 18 minutes?

[tex]P(X < 18) = \frac{18 - 15}{20 - 15} = 0.6[/tex]

0.6 = 60% probability that a randomly selected application from this distribution took less than 18 minutes.

Can someone help me? I don’t know how to solve the rest. I am struggling and I would be so happy if any of you helped me. Thank you for your help!

Answers

15.87%
2. 6 pounds and 8.8 pounds.
3. 2.28%
4. 50% of newborn babies weigh more than 7.4 pounds

I hope this helps.

Which is the
Simplified form
r-7+s-12

Answers

Answer:

r + s - 19

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

r - 7 + s - 12

Step 2: Simplify

Combine like terms [constants]:                                                                          r + s - 19

A building 51 feet tall casts a shadow 48 feet long. Simultaneously, a nearby statue casts a shadow of 16 feet. How tall is the statue? Choose an answer

Answers

Answer: 17 feet

Step-by-step explanation:

51/48 = x/16

(51)(16)/48

The statute is 17 feet tall.

What are the similar triangles?

Similar triangles are the triangles that have the same shape, but different sizes. The corresponding angles are congruent and the sides are in proportion.

What is the ratio of any two corresponding sides of similar triangles?

The ratio of any corresponding sides in two equiangular triangles is always the same.

Let's visualize the situation according to the given question.

AB is the building ,whose height is 51f

BC is the shadow of the building AB, whose length is 48ft.

QR is the shadow of the tower statue, whose length is 16feet.

Let the height of the statue PR be h feet.

In triangle ACB and triangle PRQ

∠ACB = ∠PRQ = 90 degrees  

( the objects and shadows are perpendicular to each other)

∠BAC = ∠QPR

( sunray falls on the pole and tower at the same angle, at the same time )

ΔACB similar to ΔPRQ   ( AA criterion)

Therefore, the ratio of any two corresponding sides in equiangular triangles is always same.

⇒ AC/CB = PR/RQ

⇒[tex]\frac{51}{48} =\frac{h}{16}[/tex]

⇒ h = [tex]\frac{(51)(16)}{48}[/tex]

⇒ h = 17 feet.

Hence, the statute is 17 feet tall.    

Learn more about the similar triangle here:

brainly.com/question/25882965

#SPJ2

Use formula autocomplete to enter a sum function in cell B7 to calculate the total of cells in B2:B6

Answers

Excel enables the users to perform mathematics basic and advanced function with just one formula.

The formula for sum of entire row or column can be done with just entering a single formula and results are shown in seconds.

The formula for sum of few column cells is,

=SUM(B2:B6)

The spreadsheet allows the user to enter various formula and results are displayed withing seconds.

There are formulas for basic math functions and there are also formulas for advance mathematics calculations. For addition of values of many cells sum formula is used and range is assigned for reference.

The formula adds all the values of selected cells and displays the results in different cell.

Learn more at https://brainly.com/question/24365931

Find the length of x

Answers

Answer:

32

Step-by-step explanation:

Let's assume that the triangles are similar.

[tex]\frac{16}{12} = \frac{24}{18} = \frac{x}{24}[/tex]

[tex]\frac{x}{24} = \frac{4}{3} => x = \frac{24}{3} * 4= 8 * 4 = 32[/tex]

An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from soil. Out of 155 seeds planted in soil containing 3% mushroom compost by weight, 74 germinated. Out of 155 seeds planted in soil containing 5% mushroom compost by weight, 86 germinated. Can you conclude that the proportion of seeds that germinate differs with the percent of mushroom compost in the soil

Answers

Solution :

Let [tex]p_1[/tex] and [tex]p_2[/tex]  represents the proportions of the seeds which germinate among the seeds planted in the soil containing [tex]3\%[/tex] and [tex]5\%[/tex] mushroom compost by weight respectively.

To test the null hypothesis [tex]H_0: p_1=p_2[/tex] against the alternate hypothesis  [tex]H_1:p_1 \neq p_2[/tex] .

Let [tex]\hat p_1, \hat p_2[/tex] denotes the respective sample proportions and the [tex]n_1, n_2[/tex] represents the sample size respectively.

[tex]$\hat p_1 = \frac{74}{155} = 0.477419[/tex]

[tex]n_1=155[/tex]

[tex]$p_2=\frac{86}{155}=0.554839[/tex]

[tex]n_2=155[/tex]

The test statistic can be written as :

[tex]$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}[/tex]

which under [tex]H_0[/tex]  follows the standard normal distribution.

We reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance, if the P-value [tex]<0.05[/tex] or if [tex]|z_{obs}|>Z_{0.025}[/tex]

Now, the value of the test statistics = -1.368928

The critical value = [tex]\pm 1.959964[/tex]

P-value = [tex]$P(|z|> z_{obs})= 2 \times P(z< -1.367928)$[/tex]

                                     [tex]$=2 \times 0.085667$[/tex]

                                     = 0.171335

Since the p-value > 0.05 and [tex]$|z_{obs}| \ngtr z_{critical} = 1.959964$[/tex], so we fail to reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the [tex]\text{proportion}[/tex] of the seeds that [tex]\text{germinate differs}[/tex] with the percent of the [tex]\text{mushroom compost}[/tex] in the soil.

Suppose that a random sample of size 64 is to be selected from a population with mean 50 and standard deviation 5. (a) What are the mean and standard deviation of the sampling distribution of x

Answers

Answer:

Mean of sampling distribution = 50

Standard deviation of sampling distribution, = 0.625

Step-by-step explanation:

Given :

Mean, μ = 50

Standard deviation, σ = 5

Sample size, n = 64

The mean of sampling distribution, μxbar = population mean, μ

μxbar = μ

According to the central limit theorem, the sampling distribution converges to the population mean as the sample size increases, hence, , μxbar = μ = 50

Standard deviation of sampling distribution, σxbar = σ/√n

σxbar = 5/√64 = 5 / 8 = 0.625

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