Jason writes a report about how the land changes due to the movement of magma in earth's mantle. which of the following is he most likely including in his report?​

Answers

Answer 1

Answer: can I have answer choices

Explanation:


Related Questions

PLEASE HELP ASAP I'LL GIVE BRAINLY!!

Answers

Answer:   b or c

Explanation:  on khan academy

“if matthew rides south on his bicycle in a straight line for 23 mins (0.383 hr) with an average velocity of 17.5mph, how far has he ridden?

Answers

Answer:

6.7miles due south

Explanation:

Given parameters:

Time  = 23min(0.383hr)

Average velocity  = 17.5mph

Unknown:

How far he has ridden  = ?

Solution:

To solve this problem,

      Displacement  = Velocity x time

 Displacement = 17.5 x 0.383  = 6.7miles due south

PLEASE HELP IM BEGGING YOU! What is the mass of an object that requires 100N of force to accelerate it at 5m/s2? I​

Answers

Answer:

20 kg

Explanation:

The following data were obtained from the question:

Force (F) = 100 N

Acceleration (a) = 5 m/s²

Mass (m) =?

Force (F) is simply defined as the product of mass (m) and acceleration (a). Mathematically, the force (F) can be expressed as:

Force (F) = mass (m) × acceleration (a)

F = ma

With the above formula, we can simply obtain the mass of the object as follow:

Force (F) = 100 N

Acceleration (a) = 5 m/s²

Mass (m) =?

F = ma

100 = m × 5

Divide both side by 5

m = 100 / 5

m = 20 kg

Thus, the mass of the object is 20 kg.

Helppp please

As the temperature of water drops, it continues to give off thermal energy until it freezes. This is an example of.


increasing thermal energy

a chemical change

an exothermic change

an endothermic change

Answers

Answer:

exothermic change hope it help

Explanation:

it is exothermic change hope it helpful

tourist travels 1500 miles using two planes. The second plane averages 50 miles per hour faster than the first plane. The tourist uses the slower plane for the first 500 and the faster plane for the next 1000 miles. The total flying time is 6.5 hours. What is the speed of the first plane?

Answers

Answer:

V₁ = 200 mi/h

Explanation:

To do this, we need to analyze the given data.

We have a total distance and time of 1500 mi and 6.5 h. We also know that the second plane goes 50 mi/h faster than the first plane, (V₂ = V₁ + 50). The firsts 500 miles were on the first plane and the remaining 1000 mi with the second plane.

Using the expression of distance, and assuming a constant speed in both planes we have:

d = V * t   (1)

Replacing this expression for both planes we have:

d₁ = V₁ * t₁

d₂ = (V₁+50) * t₂

WE are missing several data, because we do not know the times for each plane, but we can have a clue.

The total time of flight was 6.5 h, this is equivalent to just sum both times of both planes, so:

t = t₁ + t₂   (3)

From the expressions of distance for both planes, we can solve for time, and then replace in the above expression of the total time. In that way we can solve for the speed of the plane. Let's solve for both times in the planes:

t₁ = d₁ / V₁ = 500/V₁    (4)

t₂ = d₂ / V₁+50 = 1000/ V₁ + 50   (5)

Now, all we have to do is replace (4) and (5) into (3) and solve for V₁:

6.5 = [(500/V₁) + (1000/V₁ + 50)

6.5 = [500*(V₁+50) + 1000V₁ / V₁(V₁+50)]

6.5 = [500V₁ + 25000 + 1000V₁ / V₁² + 50V₁

6.5(V₁² + 50V₁) = 1500V₁ + 25000

6.5V₁² + 325V₁ - 1500V₁ - 25000 = 0

6.5V₁² - 1175V₁ - 25000 = 0

From here, we use the quadratic equation to solve for V₁:

X = 1175 ± √(1175)² + 4 * 6.5 * 25000 / 2 * 6.5

X = 1175 ± √1380625 + 650000 / 13

X = 1175 ± 1425 / 13

X₁ = 1175 + 1425 / 13 = 200

X₂ = 1175 - 1425 / 13 = -19.23

So, it's very clear that the speed cannot be negative, so we stick with the first value. Therefore the speed pf the first plane is:

V₁ = 200 mi/hV₂ = 250 mi/h

Hope this helps

The speed of the first plane is 77.02 mph.

The given parameters:

Total distance traveled, d = 1500 milesDistance by the slower plane = 500 milesDistance by the faster plane = 1000 milesTotal time of motion, t = 6.5 hours

Let the average speed of the first plane = v

Then, average speed of the second plane = 50 + v

The speed of the first plane is calculated as follows;

[tex]\frac{500}{v} + \frac{100}{50 + v} = 6.5\\\\\frac{500(50 + v) + v}{v(50 + v)} = 6.5\\\\500(50 + v) + v = 6.5(50v + v^2)\\\\25000+ 500v + v = 325 v + 6.5v^2\\\\6.5v^2 -176 v - 25000 = 0\\\\a = 6.5, \ b = -176, \ c = -25000\\\\v = \frac{-b \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\v = 77.02 \ mph[/tex]

Thus, the speed of the first plane is 77.02 mph.

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Explain in detail what happens to the motion of particles in a metal tray as it is placed into the hot oven

Answers

Answer:

The particles gain more kinetic energy and begin to move faster

Explanation:

Based on the kinetic theory of matter, matter is made up of particles, which are in a constant state of random motion.

This means that the tiny particles of the metal tray are continuously moving about. Furthermore, for the particles to move about, they need energy. This can come in various forms. It can be chemical, kinetic, or light, etc.

Once the metal tray is placed in the oven the particles get some kinetic energy from the heat of the hot oven. The metal particles begin to vibrate about their mean position a lot quicker than ever before. This leads to an increase in the temperature of the metal tray.

If this continues, they will be able to break the metallic bonds holding them together, causing a change of state from solid to liquid, which we will be able to perceive as the melting of the tray.

A brass rod is encased in aluminum. What happens to the speed of a sound
wave when it passes through the rod and moves from the brass into the
aluminum?
Aluminum
Copper
Lead
Brass
(70% Cu,
30% Zn)
6,420
4,700
5,010
1,960
Speed of
sound
(m/s)
A. Its speed decreases.
OB. Its speed increases.
ООО
O C. Its speed falls to zero.
OD. Its speed stays the same.
PREVIOUS

Answers

Answer:

B. its speed increases

Explanation:

A brass rod is encased in aluminium. The speed of a sound wave in this decreases when it moves from the aluminium into the brass medium. Thus, the correct option is A.

What factors affect speed of sound?

Sound travels in different mediums in the form of waves. The speed of sound is the speed with which the sound wave travels in a medium. The speed of the wave depends on the density and the elasticity of the medium through which the sound waves travel. In general, the sound wave travels faster in the liquid mediums in comparison to the gas medium and these are quicker in solid mediums than in liquid mediums. Thus, the greater the elasticity and the lower the density of the waves, the faster the sound waves travel in that medium.

The speed of sound in aluminium is 5100m/s and in the brass medium, it is 6,923. So, if the sound wave is moving from aluminum metal to the brass medium, we can clearly observe that there is decrease in the speed of sound. So, we can say here that is the speed is decreases.

Therefore, the correct option is A.

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Velocity includes both speed and

Answers

Velocity includes both speed and direction.

What is Velocity?

Velocity of a particle is its speed and the direction in which it is moving.

It can also be described as the instantaneous rate of change of the particle's distance traveled, and the direction in which the distance is changing, velocity is basically speeding in a specific direction. It is a vector quantity, which means we need both magnitude (speed) and direction to define velocity. The SI unit of it is metre per second (ms-1). If there is a change in magnitude or the direction of the velocity of a body, then it is said to be accelerating.

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Helpppp

What occurs when someone places an ice pack on an injured ankle?

A. Conduction causes ice pack to lose thermal energy.

B. Conduction causes the ankle to gain thermal energy.

C. Cold from the ice pack is transferred to the ankle.

D. Heat from the ankle is transferred to the ice pack.​

Answers

It would probably be C

Why do you think it is important to have a system to arrange items in the grocery store? What will happen if we don’t have a system?

Answers

Yes otherwise you would never be able to find what you need since all locations would be random

What is the frequency of a radio wave of wavelength 150 m if the velocity of radio waves in free space is 3 × 10^8 m s–¹ ?​

Answers

Answer:

frequency =speed/wavelength

=(3*10^8)/150

=2×10^6

Which is an example of a physical change?


cake baking

gasoline combusting

salt dissolving

iron rusting

Answers

Answer:

salt dissolving

Explanation:

hope it helps

Salt dissolving because if the water evaporates the salt will return to a solid state

Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0∘ west of north. Jane walks 12.0 m in a direction 30.0∘ south of west. They then stop and turn to face each oth

Answers

Answer:

a) 24.33 m of distance.

b) 34.55° east of the south.

Explanation:

The question is incomplete. The whole exercise is the following:

"Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0° west of north. Jane walks 12.0 m in a direction 30.0° south of west. They then stop and turn to face each other.

(a) What is the distance between them?

(b) In what direction should Ricardo walk to go directly toward Jane?"

Now that we know what we need to do in this question, let's head for every part of the problem.

a) Distance between Ricardo and Jane

In this case, we need to analyze the given data:

Ricardo (which we will call R) is 28 m from the starting point at 60° west of north, and Jane (J) is 12 m at 30° south of west. So the distance between them, will be the point where they both stop and face each other. This point can be seen in the image attached (See picture).

Let's call the distance between them as "D", to get the distance of D, according to the picture will be:

D = J - R   (1)

However, as they are facing in different angles and directions, we cannot do the difference of their values distance just like that. In order to do that, we need to calculate the components in the "x" and "y" axis of each vector. In that way, we can get the components of x and y of the Distance D, and then, the whole distance between them will be:

D = √Dx² + Dy²     (2)

So, let's get the components of x and y of R and J.

For Ricardo (R):

Rx = R sin60° = 28 sin60° = -24.25 m

Ry = R cos60° = 28 cos60° = 14 m

The sign "-" it's because R it's on the second quadrant, therefore in x, we'll have to add the negative.

For Jane (J):

Jx = J cos30° = 12 cos30° = -10.39 m

Jy = J sin30° = 12 sin30° = -6 m

Again, the negative is added because J is on the third quadrant.

Now that we have the components, let's calculate vector D using expression (1):

Dx = -10.39 - (-24.25) = 13.86 m

Dy = -6 - 14 = -20 m

Now, using expression (2) we can finally know the distance between Jane And Ricardo:

D = √(-20)² + (13.86)²

D = 24.33 m

This is the distance between Jane and Ricardo.

b) Direction of Ricardo walking to Jane

In this case, we already have the components of x and y of the distance between them, so, to know the direction:

Tanα = Dy/Dx

α = tan⁻¹ (Dy/Dx)

Replacing the values we have:

α = tan⁻¹ (-20/13.86)

α = 55.45°

Which should south of east or:

β = 90 - 55.45

β = 34.55°

Ricardo should walk 34.55° east of south

Hope this helps

A car travels 9km southwards, followed by another 5km southwards. What is the magnitude of its
distance and displacement?
Select one:
a. Distance: 14 km Displacement: 14 km
b. Distance: 14 km Displacement: 4 km
c. Distance: 4 km Displacement: 14 km
d. Distance: 4 km Displacement: 4 km​

Answers

Answer:

A

Explanation:

No change in direction, and travel was in a straight line, and total distance travelled is 9+5=14

900n pushes a wedge 0.10 m into a log, if the work done on the log is 50j what is the efficiency of the wedge

Answers

Answer:

100

Explanation:

mark me brainliest

The higher temperature, the more blank particles have

Answers

Answer:Stronger they are

(I think...)

What's the gravity?

Answers

Answer:

gravity is the force by which a planet or another body draws objects towards its Centre. the force of gravity keeps all of the planets in an orbit around the sun.

Explanation:

what is gravity made of?

gravity are made of proposed gravity parts that are made quantum particles which called gravitational anywhere there is gravitation there is gravity like on Earth in the Solar System most importantly in the minisclue infant and intervention universe .

An empty glass beaker has a mass of 103 g. When filled with water, it has a total mass of 361g.
When filled with cooking oil, it has a total mass of 351 g.
The density of water is 1.00 gcm–3.
What is the density of the cooking oil?

Answers

Answer:

0.96 gcm¯³

Explanation:

From the question given above, the following data were obtained:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of beaker + oil = 351 g

Density of water = 1 gcm¯³

Density of cooking oil =?

Next, we shall determine the mass of water. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of water =?

Mass of water = (Mass of beaker + water) – (Mass of empty beaker)

Mass of water = 361 – 103

Mass of water = 258 g

Next, we shall determine the volume of the beaker. This can be obtained by calculating the volume of water in the beaker.

Density of water = 1 gcm¯³

Mass of water = 258 g

Volume of water =?

Density = mass /volume

1 = 258 / volume

Cross multiply

1 × volume = 258

Volume of water = 258 cm³

Thus the volume of the beaker is 258 cm³.

Next, we shall determine the mass of the cooking oil. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + oil = 351 g

Mass of cooking oil =?

Mass of cooking oil = (Mass of beaker + oil) – (Mass of empty beaker)

Mass of cooking oil = 351 – 103

Mass of cooking oil = 248 g

Finally, we shall determine the density of the cooking oil. This can be obtained as follow:

Mass of cooking oil = 248 g

Volume of the beaker = 258 cm³

Density of cooking oil =?

Density = mass / volume

Density = 248 / 258

Density of cooking oil = 0.96 gcm¯³

if the mass of an object is 35kg on venus what is its mass on the sun

Answers

Answer:

Venus is only 95% the size of Earth, and 81% of its mass. With the smaller size and mass, the force of gravity pulling you on the surface is lower. To get your weight on Venus, just multiply your current weight by 0.9. That's why 100 pounds becomes 90 pounds

If the mass of an object is 35kg on Venus Its mass on the Sun remains the same hence the object's mass om sun in 35 kg. The mass of an object is an intrinsic property and remains the same regardless of the gravitational field.

The mass of an object does not change depending on its location. The mass of an object is an intrinsic property and remains the same regardless of the gravitational field it is in or its location within the universe.

However, it is important to note that an object's weight, which is the force of gravity acting on it, would be different on Venus and the Sun due to the variations in gravitational pull.

Therefore, if the mass of an object is 35 kg on Venus, its mass would still be 35 kg on the Sun.

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How long would a pendulum have to be in order to have a period of 10.0 s? Use a value of 9.81 m/s2 for the local acceleration due to gravity. Give your answer to one decimal place.

Answers

I don’t to be honest but do you know how to do it

will mark brainlist
Calculate the kinetic energy of a 100.0-kg meteor approaching the Earth at a speed of 10.0 km/s. Remember that 1 km = 1000 m.
O 1.00 x 10^8j
O 5.00 x 10^9 j
O 10 x 10^7 j
O 50.0 x 10^8 j

Answers

Answer:

5.00 x 10^9 j

Explanation:

mass = 100 kg

speed / velocity = 10 km/s x 1000 = 10,000m

K.E =

[tex] \frac{m{v}^{2} }{2} [/tex]

10,000x 100/ 2

= 5000000000

= 5.0 x 10^9j

A bus traveled 2.5 hours in 150 km. What was its average speed?
s=d/t
v=D/t
a=(v-v.)lt

Answers

Answer:

Average speed = 60km/hr

Explanation:

Given the following data;

Time = 2.5 hrs

Distance = 150km

To find the average speed;

Average speed = distance/time

Substituting into the equation, we have

Average speed = 150/2.5

Average speed = 60km/hr

the maximum range of a projectile is 2÷√3 times its actual range what is the angle of the projection for the actual range​

Answers

Answer:

The actual angle is 30°

Explanation:

Equation of projectile:y axis:

[tex]v_y(t)=vo*sin(A)-g*t[/tex]

the velocity is Zero when the projectile reach in the maximum altitude:

[tex]0=vo-gt\\t=\frac{vo}{g}[/tex]

When the time is vo/g the projectile are in the middle of the range.

x axis:

[tex]d_x(t)=vo*cos(A)*t\\[/tex]

R=Range

[tex]R=d_x(t=2*\frac{vo}{g})[/tex]

[tex]R=vo*cos(A)*2\frac{vo}{g} \\\\R=\frac{(vo)^{2}*2* sin(A)cos(A)}{g} \\\\R=\frac{(vo)^{2} sin(2A)}{g}[/tex]

**sin(2A)=2sin(A)cos(A)

The maximum range occurs when A=45°(because sin(90°)=1)The actual range R'=(2/√3)R:

Let B the actual angle of projectile

[tex]\frac{vo^{2} }{g} =(\frac{2}{\sqrt{3} }) \frac{vo^{2} *sin(2B)}{g}\\\\1= \frac{2 }{\sqrt{3}} *sin(2B)\\\\sin(2B)=\frac{\sqrt{3}}{2}\\\\[/tex]

2B=60°

B=30°

A car accelerates from rest in a straight line. During the first 14s, the acceleration is uniform and the car reaches the speed of 25m/s. Calculate the acceleration of the car.

Answers

v = u + at

25 = 0 + a(14)

a(14) = 25

a = 25/14

a = 1.71 (3sf)

explanation:

u use the equation of motions

v = u + at

v is final velocity, aka 25

u is initial velocity, which is 0 as it was initially at rest

t is time, which is 14s

then u sub in the values and calculate a

Please help me. I will do what I can to get you points.

Answers

Answer:

the last one

Explanation:

its the sun when the earth turns towards the sun it gives us heat not solar radiation.

Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes .

Answers

Complete question :

Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes . Find how much petrol he uses using the information in the table.

Requires table to answer question is attached below

Answer:

2.64 gallons

Explanation:

Given that:

First 13 miles takes 13 minutes

Average rate = 13 miles / 13 minutes = 1mile/minute ; Average rate per hour = (1 mile /minute * 60) = 60 miles /hour

If average speed = 65mph or less ; 50 miles per gallon (it uses 1 gallon for 50 miles)

Hence, since first phase rate is 60 mph,; then miles per gallon is 50 miles

Therefore,gallon of petrol used for 13 miles will be :

13 miles / 50 mpg = 0.26 gallons

2nd phase:

Average rate of 68 mph for 1 hour 24 minutes (1.4 hours)

Here, miles per gallon = 40 (that is; 40 miles for 1 gallon).

Total distance covered = 68 * 1.4 = 95.2 miles

Petrol used = 95.2 miles / 40 mpg = 2.38 gallons

Hence,

Total petrol used : (0.26 + 2.38) = 2.64 gallons

the major factor in the development of a constitution is​

Answers

Answer:

Below are some of the important dates that led to the creation of the Constitution: 1775 — The Revolutionary War between the Colonies and Britain begins. ... 1781 — The last battle of the Revolutionary War takes place; the 13 states set up a federal government under laws called the Articles of Confederation.

Explanation:

please give me a heart

I load a 0.4 kg marble into a slingshot and shoot it directly upward by applying a 36.2 N force
stretching it a distance of 10 cm. How fast is the marble traveling when it is initially released from
the slingshot? How high does the marble go?

Answers

Answer:50mph

Explanation:

demonstrate how you can derive our 9.8m/s^2 from Newton's general law of gravity.

Answers

Answer:

[tex]g=G\frac{m_E}{r^2}[/tex]

Explanation:

Using Newton's Law of Universal Gravitation, we can write:

[tex]F=G\frac{m_E}{r^2}[/tex], where [tex]G[/tex] is gravitational constant [tex]6.67\cdot 10^{-11}[/tex], [tex]m_E[/tex] is Earth's mass, and [tex]r[/tex] is Earth's radius.

Using these measured values, we have:

[tex]F=6.67\cdot 10^{-11}\frac{5.97\cdot 10^{24}}{(6.38\cdot10^6)^2},\\g\approx \fbox{$9.8\:\mathrm{m/s^2}$}[/tex].

10
A5 kilogram gun fires a 0.02 bullet with a velocity of 380 m/s. What is the recoil velocity of the gun?
A) - 1900 m/s
B - 1.5 m/s
C -7.6 m/s
D - 0.1 m/s
Aww

Answers

The answer I think is C -7.6 m/s
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