The tension in the cable that pulls the elevator upwards with an acceleration of 2.0 m/s² is 4200 N. The right option is A) 4200 N.
What is tension?Tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.
To calculate the tension in the cable, we use the formula below.
Formula:
T = mg+ma............ Equation 1Where:
T = Tension in the cablem = Mass of the Joey and the elevatora = Accelerationg = Acceleration due to gravityFrom the question,
Given:
m = (300+60) = 360 kga = 2 m/s²g = 9.8 m/s²Substitute these values into equation 2
T = (360×9.8)+(360×2)T = 3528+720T = 4248 NT ≈ 4200 to the nearest hundred.Hence, the tension in the rope is 4200 N, the right option is A) 4200 N.
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In a simple parallel circuit
a. Current through each branch is always the same.
b. Voltage across each branch is always the same.
c. Value of each resistor is the same.
d. The circuit won't work unless there is a fuse in it.
e. None of the above.
Answer:
B
Explanation:
Potential difference across 2 parallel branches is the same.
Current may be different depending on different resistance within each branch
A person’s body temperature is 101.60F, indicating a fever of 3.00F above the normal average body temperature of 98.60F. How many degrees above normal is this body temperature on the Celsius scale?
Answer:
1.67 degrees C
Explanation:
5/9 * 3 = 15 /9 = 1.67
1.67 degrees above normal is this body temperature on the Celsius scale
What is temperature ?
A measure of temperature, heat or cold, expressed on one of several arbitrary scales that indicate the direction in which heat energy naturally flows. H. From hot body (high temperature) to cold body (low temperature). temperature). Temperature is not equivalent to energy in a thermodynamic system. For example, a burning match has a much higher temperature than an iceberg, but the total heat energy contained in the iceberg is much greater than the energy contained in the match. Temperature, like pressure and density, is called a lumped property (a property that does not depend on the amount of matter of interest), as opposed to a broader property such as mass or volume.
180 degree on Fahrenheit scale = 100 degree on Celsius scale
3 degree on Fahrenheit scale = 100*3/180 degree on Celsius scale
= 1.67 degree Celsius
1.67 degrees above normal is this body temperature on the Celsius scale
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17. the __________ lies between mars and jupiter.
Use the graph to answer the following questions.
Answers have a 5 % tolerance to allow for estimation.
Note that slope may be positive or negative.
What is the y-intercept of the graph?
What is the slope of the graph?
What is the area under the graph?
It is to be noted that the y-intercept of the graph is 20. The slope is -0.2; while the area under the graph is: 840
How do you find the intercept?At x = 0, the value of y is 20. Hence the intercept of the graph is 20.
To compute the slope, recall that the graph passes through points (0, 20) and (60, 8) hence the solution of the graph is given as:
Change in y coordinate/Change in x coordinate
= (8-20)/60-0)
= -12/60
= -1/5 or -0.2
The area under the graph compares a right-angled triangle and a rectangle. To get the area under the graph we need to find the sum of the areas of both shapes.
Recall that Area of a Right Angled Triangel is given as 1/2 B*H
Hence
⇒ 1/2 * 12 * 60
= 360
The area of a rectangle is L x B
Hence
⇒ 8 x 60
= 480
Thus, the area under the graph is
360 + 480
= 840
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A large semitrailer truck and a small car have equal momentum. How do their speeds compare?.
On the basis of their speed comparison, the truck has a much higher speed than the car.
what is linear momentum?
The relationship between an object's mass (m) and velocity (v) is known as its linear momentum.
An equation can be used to explain this relationship. Momentum is defined as the body's mass times its velocity, P = m /times v, etc.
Main body:
The mass of the truck is significantly greater than the mass of the car because the semitrailer truck is enormous and the car is little. It is obvious that with a constant momentum, greater mass results in slower speed and less mass results in faster speed.
Inertia in motion is expressed by the term momentum. The product of an object's mass and velocity is its momentum. Because of its greater bulk, a moving truck has more momentum than a car travelling at the same speed. A truck may go with less momentum than a fast car.
Therefore, on the basis of their speed comparison, the truck has a much higher speed than the car.
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Particles q₁ = -75.8 μC, q2 = +90.6 μC, and
93-84.2 μC are in a line. Particles q₁ and q2 are
separated by 0.876 m and particles q2 and q3 are
separated by 0.432 m. What is the net force on
particle q3?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
–75,8 μC
91
0.876 m
+90.6 μC
92
0.432 m
–84.2 μC
93
The net force on particle q3 will be 327.40 N
Force between two charges = k ( q0 * q1 ) / [tex]r^{2}[/tex]
where q0 and q1 are charges
r is the distance between them
force between q3 and q2 = k ( q3 * q2 ) / [tex]r^{2}[/tex]
= k ( 84.2 * [tex]10^{-6}[/tex] * 90.6 * [tex]10^{-6}[/tex] ) / [tex](0.432)^{2}[/tex]
= k (40150.10 * [tex]10^{-12}[/tex] )
force between q1 and q3 = k ( q1 * q2 ) / [tex]r^{2}[/tex]
= k ( 75.8 * [tex]10^{-6}[/tex] * 90.6 * [tex]10^{-6}[/tex] ) / [tex](1.71)^{2}[/tex]
= k ( 3732.37 * [tex]10^{-12}[/tex] )
net force = force between q3 and q2 - force between q1 and q3
= k (40150.10 * [tex]10^{-12}[/tex] ) - k ( 3732.37 * [tex]10^{-12}[/tex] )
= 327.40 N
The net force on particle q3 will be 327.40 N
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focal length of a concave mirror is 10 cm find the position nature and size of the image formed when an object is placed 10cm from the mirror
focal length of a concave mirror is 10 cm find the position nature and size of the image formed when an object is placed 10cm from the mirror
formula for finding image distance(v) is given
[tex] \frac{1}{f} = \frac{1}{v} + \frac{1}{u} [/tex]
and
[tex] \frac{1}{v} = \frac{1}{f} - \frac{1}{u} [/tex]
where,
f is focal length
v is image distance,and,
u is object distance
The position of the image is at infinity, nature is real and the size of the image formed is highly magnified.
A concave mirror has a reflective floor that is curved inward and far from the light source. Concave mirrors mirror mild inward to at least one focal length. not like convex mirrors, the picture shaped by a concave replicate suggests exceptional photo sorts depending on the space between the item and the replicate.
Calculation:-
1/f = 1/v + 1/u
1/10 = 1/v + 1/10
V = infinity
The size of the image is Highly magnified and real.
Concave mirrors form both real and virtual photos. while the concave reflect is positioned very close to the object, a digital and magnified photo is received, and if we grow the gap between the object and the mirror, the size of the picture reduces, and real snapshots are shaped.
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Given a wave of a particular wavelength and amplitude, what must be the amplitude, wavelength, and phase change of a wave you add to this wave to create a wave of twice the amplitude?.
Answer:
Question:
PH
Patrick H.
Physics 101 Mechanics
6 months, 3 weeks ago
My answer: Given a wave of weight with a particular wavelength and amplitude, what must be the amplitude wavelength and phase change you add to create a wave of twice the amplitude. So the amplitude, the wavelength and the phase of the second wave have to be the same because in order to have these add up together or to be twice they have to interact via constructive interference. And that's only possible when the wavelength and the phase are the same. So in constructive interference, the waves overlap with one another to form a third wave With an amplitude equivalent to the sum of the two. So for example, one wave in red, let's say, another wave in pink. And there are a total wave. Is that some of these to something like this? So the amplitude wavelength and face have to be the same.
Given a wave of a particular wavelength and amplitude, what must be the amplitude, wavelength, and phase change of a wave you add to this wave to create a wave of twice the amplitude? given a wave of a particular wavelength and amplitude, what must be the amplitude, wavelength, and phase change of a wave you add to this wave to create a wave of twice the amplitude?
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So given a wave of weight with a particular wavelength and amplitude, what must be the amplitude wavelength and phase change you add to create a wave of twice the amplitude. So the amplitude, the wavelength and the phase of the second wave have to be the same because in order to have these add up together or to be twice they have to interact via constructive interference. And that's only possible when the wavelength and the phase are the same. So in constructive interference, the waves overlap with one another to form a third wave With an amplitude equivalent to the sum of the two. So for example, one wave in red, let's say, another wave in pink. And there are a total wave. Is that some of these to something like this? So our amplitude wavelength and face have to be the same.
A machine gun is pointed upward at an angel 30° with respect to the horizontal and fires a projectile with a velocity of 200m/s .find the height and range of the projectile
The height and range of the projectile are 500 meters.
Solution:
The initial vertical speed is 100m/s (200Sin30) so if g is 10m/s per second it will take 10 seconds to rise and 10 seconds to fall → 20 seconds fire time.
Horizontal velocity is 200Cos30 or 173 m/s
Range? 3460 meters.
Height? The average vertical speed is 50m/s (from 100 to zero) and it rises for 10 seconds. 500 meters.
This equation defines the maximum projectile height from the launch position and depends only on the vertical component of the initial velocity. The maximum horizontal distance a projectile travels is called range. The range is the difference between the lowest and highest values. Indicates that the maximum horizontal distance is four times the maximum height the projectile will reach.
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The maximum acceleration attained on the interval 0 ≤ t ≤ 3 by the particle whose velocity is v(t)=t^3-3 t^2+12 t+4 is
The maximum acceleration attained on the interval 0 ≤ t ≤ 3 by the particle is equal to 21 m/s².
What is acceleration?Acceleration of an object can be described as the change in velocity of the object with respect to time. Acceleration can be described as the first derivative of the velocity of an object with respect to time.
The expression for the acceleration in terms of velocity can be represented as:
[tex]{\displaystyle a =\frac{dv}{dt}[/tex]
Given the expression of the velocity is v (t) = t³ - 3t² + 12t +4
dv/dt = v'(t) = d/dt(t³ - 3t² + 12t +4)
a(t) = 3t² - 6t +12
At time t = 0 , a(0) = 3(0)² - 6(0) +12 = 12
At time t = 3s, a(3) = 3(3)² - 6(3) +12 = 21
Therefore, the maximum acceleration attained on the interval 0 ≤ t ≤ 3 is equal to 21.
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Anatomical directional terms worksheet
Answer:
1. Superior- toward the head
2. Inferior- away from the head
3. Anterior- toward the front
4. Posterior- toward the back
5. Ventral- toward the belly
6. Dorsal- toward the back
7. Proximal- toward the center of the body
8. Distal- away from the center of the body
Explanation:
An airplane is flying with a force of 800 N. It experiences a force of air resistance of 40 N and a wind force of 60 N, both acting in the opposite direction that the plane is traveling. What is the net force on the airplane?
An airplane is flying with a force of 800 N. It experiences a force of air resistance of 40 N and a wind force of 60 N, both acting in the opposite direction that the plane is traveling. The net force on the airplane will be 700 N
Force with which airplane is flying ( F1 ) = 800 N
opposite to which two forces are acting
air resistance = 40 N
wind force = 60 N
net force = F1 - 40 - 60 = 800 - 100 = 700 N
The net force on the airplane will be 700 N
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In an ultra-low-temperature experiment, a collection of sodium atoms enters a special state called a Bose-Einstein condensate in which the index of refraction is 1.57×107. What is the speed of light in this condensate?
In an ultra-low-temperature experiment, a collection of sodium atoms enters a special state called a Bose-Einstein condensate in which the index of refraction is 1.57×107. The speed of light in this condensate will be 19 m/s
The ratio between the speed of light in medium to speed in a vacuum is the refractive index. When light travels in a medium other than the vacuum, the atoms of that medium continually absorb and re-emit the particles of light, slowing down the speed light
refractive index = speed of light in vacuum / speed of light in that medium
1.57×[tex]10^{7}[/tex] = 3 * [tex]10^{8}[/tex] / speed of light in that medium
speed of light in that medium = 3 * [tex]10^{8}[/tex] / 1.57×[tex]10^{7}[/tex] = 1.9 * 10 = 19 m/s
The speed of light in this condensate will be 19 m/s
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An object is launched with the velocity v₀ shown. The horizontal and vertical components vx and vy, respectively, of the initial velocity are also shown. If air resistance is negligible, which of the following best shows ax and ay when the object reaches the highest point in its trajectory?
The best shows ax and ay when the object reaches the highest point in its trajectory is aₓ = 0 and [tex]a_y[/tex] acting downwards. So the 2nd potion is correct.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
What is projectile motion?A projectile is an object or particle that is launched toward the surface of the earth and moves along a curved route solely due to the force of gravity. In order to evaluate this type of motion, the acceleration and velocity components are split into separate analyses for the horizontal and vertical directions.
At the highest point in object's trajectory;
Acceleration due to gravity acts along negative y axis and no acceleration acts long x axis. so accelerations along x and y axis can be represented by aₓ = 0 and [tex]a_y[/tex] acting downwards. So the 2nd potion is correct.
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Why can we neglect forces such as those holding a body together when we apply Newton’s second law of motion?
Newton's 2nd law which applies to external forces acting on a system. The forces which are holding a body together are internal forces. According to Newton's 3rd law, for every internal force that is acting on the system there will be and equal and opposite force acting on the system. These 2 forces will "cancel" (the vector sum will be zero), so they will not cause acceleration (according to 1st law).
Newton's laws of motion are 3 basic legal guidelines of classical mechanics that describe the relationship between the motion of an object and the forces acting on it.
Newton legal guidelines inform us precisely how matters flow or sit still, like why you don't drift off the bed or fall via the floor of your own home. Newton's laws manipulate how cars work, how water flows, how buildings do not fall down, and essentially how the everything moves around us.
The Newton's three laws of motion are law of Inertia, law of Mass and Acceleration, and the 3rd regulation of movement. outside force.
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Arunner Acar run 4.5m in 4.5 min. Another Tunner B. requires 6 min to Finish this distance If they start one to gether Far a Part Will they have be at the Finish of the race.
If both runner A and runner B start the race together, they will 1.125 m apart at the finish of the race
v = d / t
v = Velocity
d = Distance
t = Time
d = 4.5 m
For runner A,
t = 4.5 min
v = 4.5 / 4.5
v = 1 m / min
For runner B,
t = 6 min
v = 4.5 / 6
v = 0.75 m / min
Runner A finished the race first at 4.5 min. At that time the runner B will have covered,
0.75 = d / 4.5
d = 0.75 * 4.5
d = 3.375 m
Difference in distances = 4.5 - 3.375
Difference in distances = 1.125 m
Therefore, they will 1.125 m apart at the finish of the race
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In the “Little Prince,” the Prince visits a small asteroid called B612. If the asteroid has a radius of 20.0 m and a mass of 1.00 x 10^4kg, what is the acceleration due to gravity on the asteroid (G=6.67x10-11N m2/kg2)?
The acceleration due to gravity on the asteroid, given that it has a mass of 1.00×10⁴ kg and a radius of 20.0 m is 1.67×10¯⁹ m/s²
How do I determine the acceleration due to gravity?Acceleration due to gravity of planets can be obtained by using the following formula:
g = GM / R²
Where
g is acceleration due to gravity on the planet M is the mass of the planetG is the gravitational constantR is the radius of the planetNow, we shall apply the above formula, to determine the acceleration due to gravity on the asteroid. Details below
Mass of asteroid (M) = 1.00×10⁴ KgRadius (R) = 20.0 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Acceleration due to gravity (g) =?g = GM / R²
g = (6.67×10¯¹¹ × 1.00×10⁴) / (20)²
g = 6.67×10¯⁷ / 400
g = 1.67×10¯⁹ m/s²
Thus, we can conclude that the acceleration due to gravity on the asteroid is 1.67×10¯⁹ m/s²
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The diagram shows an oscilloscope
trace from an AC supply. Calculate
the period of this supply if each
horizontal division represents 2ms.
The period of the this given oscilloscope trace from an AC supply is calculated as 1 * 10⁻³ seconds.
What do you mean by period?Period of a wave is the inverse of the frequency so the formula for wave period is, T = 1 / f , where T is period which is the time taken for one cycle to complete, and F is frequency.
To obtain period from frequency, first you have to convert frequency from Hertz to 1/s and then divide 1 by the frequency. The period of a wave is measured in seconds (s), while the frequency is measured in Hertz (Hz).
Given each horizontal division is 2ms
the time= 10ms
Period = 1/T
= 1/10ms
= 0.1ms
Period = 1 * 10⁻³ seconds
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The relationship between power, force, and velocity is ______?
Answer: P = FV becuase all of them are equal in strength.
Explanation: In the straight forward cases where a constant force moves an object at constant velocity, the power is just P = Fv. In a more general case where the velocity is not in the same direction as the force, then the scalar product offorce and velocity must be used. P = Power, F = Force, V = Velocity.
Hoped This Helped!
Answer:
F-V
Explanation:
remember that power = work/time = force × distance/time = force × velocity).
A person moves a box across a room by pushing downwards on it with a force of 485 N at an
angle of 35.0° below the horizontal. If the box has a mass of 32.6 kg and is pushed at constant
velocity, what is the coefficient of kinetic friction between the box and the floor?
The coefficient of kinetic friction between the box and the floor is 0.87.
What is the coefficient of kinetic friction?
The coefficient of kinetic friction between the box and the floor is calculated by applying the formula for net force on the box.
F(net) = ma
where;
F(net) is the net forcem is mass of the boxa is the acceleration of the boxat a constant velocity, the acceleration of the box, a = 0
F(net) = 0
The net force is obtained from the applied force and force of friction;
Fcosθ - μmg = 0
where;
F is the applied forceμ is the coefficient of kinetic frictionθ is the angle at which the force is applied = 90 - 35 = 55⁰μmg = Fcosθ
μ = Fcosθ / mg
μ = (485 x cos55) / (32.6 x 9.8)
μ = 0.87
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A piece of clay sits 0.22 m from the center of a potter’s wheel.
If the potter spins the wheel at an angular speed of 20.5 rad/s, what is the magnitude of the centripetal acceleration of the piece of clay on the wheel?
Answer in units of m/s2.
A piece of clay sits 0.22 m from the center of a potter’s wheel. If the potter spins the wheel at an angular speed of 20.5 rad/s, The magnitude of the centripetal acceleration of the piece of clay on the wheel will be 92.455 [tex]m/s^{2}[/tex]
Centripetal acceleration is defined as the property of the motion of an object, traversing a circular path. Any object that is moving in a circle and has an acceleration vector pointed towards the center of that circle is known as Centripetal acceleration.
centripetal acceleration = r * [tex]omega^{2}[/tex]
r = radius
omega = angular speed
acceleration = 0.22 * [tex]20.5^{2}[/tex] = 92.455 [tex]m/s^{2}[/tex]
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17. Each of the figures below shows the velocity v of a particle and the force or forces
acting on the particle. Forces F1 and F2 have the same magnitude. In which figure is the
particle's speed or direction NOT being changed?
Answer:
option (A)
Explanation:
In fig. (A) two equal forces are acting at the same point in opposite directions ,therefore net force is zero as they will cancel each other.Now as there is no net force on particle so the acceleration is zero(a=F/m=0/m=0) and thus velocity v remains constant
a car with a momentum of 50000 kg ms north has a mass of 2175 kg what is the velocity of the car
The velocity of the car will be 22.98 m/s with a momentum of 50000 kgms and has a mass of 2175 kg.
Momentum is the term used to describe the state of motion of an item whose mass is non-zero. Thus, momentum has an impact on all moving objects. p=mv, where m is an object's mass and v is its rate of motion, is the formula for momentum. Due to its classification as a part of velocity, momentum is a vector. This implies that momentum has a sizeable magnitude and a clear direction, with the latter shown by a vector or an arrow. A certain mass and speed are two examples of when an object has momentum. Momentum always remains constant as a result. Momentum conservation law states as such.
The formula of momentum will be:
p = mv
where, p = momentum = 50000 kgms
m = mass = 2175 kg.
v = velocity = ?
substitute the given values,
momentum = mass x velocity
50000 =2175 x v
v = 50000 / 2175
=22.98 m/s
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Here is my question
A meteoroid is moving towards a planet. It has mass m = 0.34 × 109 kg and speed v1 = 2.6 × 107 m/s at distance R1 = 1.6 × 107 m from the center of the planet. The radius of the planet is R = 0.22 × 107 m. The mass of the planet is M = 9.6 × 1025 kg. There is no air around the planet.
Enter an expression for v, the meteoroid's speed at the planet's surface, in terms of G, M, v1, R1, and R.
Calculate the value of v in meters per second.
An expression for velocity, v, of the meteoroid's speed at the planet's surface, in terms of G, M, v, R1, and R is v = v₁ - √{2GM/(R₁ - R)}
The value of v, the meteoroid's speed at the planet's surface, in meters per second is 2.596 * 10⁷ m/s.
What is the speed of the meteoroid?The speed of the meteoroid is equal to the difference between the speed of the meteorite, v₁, and the escape velocity of the meteorite from the gravitational pull of the planet.
The escape velocity of an object is equal is the velocity of an object which when summed with the gravitational potential energy of the object is equal to zero.
The formula for escape velocity, Ve, is given below:
Ve = √2GM/r
where;
G = universal gravitational constant
M = mass of the body to be escaped from
r = distance from the center of the mass
G is the gravitational constant = 6.67 * 10⁻¹¹ m³kg⁻¹s⁻²
v₁ = 2.6 * 10⁷ m/s
Hence, the velocity of the meteorite will be:
v = v₁ - √{2GM/(R₁ - R)}
Calculating the velocity, v
v = 2.6 * 10⁷ m/s - √{(2 * 6.67 * 10⁻¹¹ * 9.6 * 10²⁵ ) / (1.6 * 10⁷ - 0.22 * 10⁷)}
v = 2.596 * 10⁷ m/s
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A student rubbed a plastic rod with a doth
The rod became negatively charged and the cloth became positively charged
explain why the cloth became positively charged
Answer:
When different insulating materials rub against each other, they can become electrically charged. When the cloth is rubbed against the rod, the friction causes electrons to gain energy, transferring themselves to the rod and therefore becoming posively charged. The rod is now negatively charged as it has gained electrons.
A dog sits 2.2 m from the center of a merry- go-round.
a) If the dog undergoes a 1.6 m/s2 cen- tripetal acceleration, what is the dog’s linear speed?
Answer in units of m/s.
Answer:
2.2-1.6m/s2 then your got the answwr
which is the symbol used for momentum
The symbol used for momentum is" p".
According to the Newton's alternate law of stir it states that the momentum is the product of mass and the haste of the flyspeck. This momentum can be said as the measure of stir of the object. It's a vector volume and it has both magnitude and direction. It can be transferred. As the momentum of the system is conserved when no external force is applied on the system.
In this case,
momentum( p) = mv
where,
m = mass
v = haste
P = momentum
momentum is the measure of stir of the object.
momentum is given by the product of mass and the haste of the object.
momentum can be transferred.
thus, the momentum is defined by the Newton's alternate law and it's denoted by the symbol" P".
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One object has a mass of 8.5 × 10
11
kg. A second object has a mass of 1.93 × 10
8
kg. If the force between them is 337872N, what is the distance between these two objects?
180.0176 m is the distance between these two objects .
What is Gravitational force ?
Gravity, also called gravitational force in mechanics, is the universal force of attraction that acts between all matter. It is by far the weakest known force in nature and plays no role in determining the internal properties of everyday matter. It controls the orbits of objects in places, the structure and evolution of stars, galaxies, and the universe as a whole. On Earth, every object has a weight, or downward gravitational force, proportional to its mass, equal to the mass of the Earth acts on them. Gravity is measured by the acceleration it imparts to a free-falling object., Its velocity increases by about 9.8 meters per second. On the moon, the acceleration of a free-falling object is approximately 1.6 meters per second.
F = Gm1m2/r^{2}
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The moist weight of 5600 cm3 of a soil is 102.3N. The moisture content and the specific gravity of the soil solids are determined in the laboratory to be 11% and 2.7, respectively. Calculate the following: a- Moist unit weight b- Dry unit weight c- Void ratio d- Porosity e- Degree of saturation (%) f- Volume occupied by water
The Moist unit weight of the soil with a moist weight of 102.3 N, moisture content of 11 % and specific gravity of 2.7 is 18.27 KN / m³
Moist weight = 102.3 N
Volume = 5600 cm³
Water content, w = 0.11
Specific gravity, G = 2.7
a ) Moist unit weight, γ[tex]_{b}[/tex]
γ[tex]_{b}[/tex] = Moist weight / Volume
γ[tex]_{b}[/tex] = 102.3 / 5600 * [tex]10^{-6}[/tex]
γ[tex]_{b}[/tex] = 18.27 KN / m³
b ) Dry unit weight, γ[tex]_{d}[/tex]
γ[tex]_{d}[/tex] = γ[tex]_{b}[/tex] / 1 + w
γ[tex]_{d}[/tex] = 18.27 / ( 1 + 0.11 )
γ[tex]_{d}[/tex] = 16.46 KN / m³
c ) Void ratio, e
γ[tex]_{d}[/tex] = G γ[tex]_{w}[/tex] / ( 1 + e )
16.46 = 2.7 * 9.81 / ( 1 + e )
1 + e = 1.61
e = 0.61
d ) Porosity, n
n = e / ( 1 + e )
n = 0.61 / ( 1 + 0.61 )
n = 0.38
e ) Degree of saturation, s
s = G w / e
s = 2.7 * 0.11 / 0.61
s = 0.487
s = 48.7 %
f ) Volume occupied by water, V
V = G w
V = 2.7 * 0.11
V = 0.297
Therefore,
γ[tex]_{b}[/tex] = 18.27 KN / m³
γ[tex]_{d}[/tex] = 16.46 KN / m³
e = 0.61
n = 0.38
s = 48.7 %
V = 0.297
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Work with a group to develop a plan to reduce water use at school
The water can be conserved by some of the given tips, turn off the water when washing your hands, Carry a refillable water bottle, Skip the tray in the lunch line, use only one plate, Report leaks to the appropriate authorities, etc.
What is the conservation of water?The protection, management, and development of surface and groundwater resources as well as pollution prevention.
There are some tips to conserve water or reduce water use in school,
Turn off the water when washing your hands - On average, people wash their hands nine times each day. People can save up to six gallons of water per day on average if they turn off the faucet while washing their hands.Use fewer utensils in the canteen - Water waste in cafeterias and dining areas is well-known. Dishwashing consumes the majority of the water used in industrial kitchens. Keeping the number of dirty dishes they produce to a minimum is one approach for students to conserve water.Report leaks to the appropriate authorities - Students are frequently the first on campus to discover leaks. Report running toilets, busted water fountains, busted hoses, and leaky faucets. 100 gallons of water a day can be wasted by a single dripping faucet.Form a Club and Organize - When students organize into recognized clubs, they often have more success working with the administration of their school.Therefore, these recommendations for pupils on how to conserve water at school may seem minor or small in comparison to the tremendous environmental issues that exist today.
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