Answer:
a.) increase
c.) collide more often with other reactant molecules
Explanation:
Generally, when you increase the quantity of reactants, the rate of the reaction increases (the forward reaction). When there are more reactants, there are more chances for them to interact with each other. More interactions means more reactions.
I predict that using a larger amount of calcium chloride powder will increase the reaction rate because the calcium chloride molecules will collide more often with other reactant molecules.
When does the reaction rate would increase?It becomes fair to assume that the reaction rate would increase when Jon increases the quantity of calcium chloride (CaCl2) powder utilised in the chemical reaction with sodium bicarbonate (NaHCO3).
This is due to the fact that adding more calcium chloride powder to the reaction mixture will add more CaCl2 molecules.
There will be more collisions between CaCl2 and NaHCO3 molecules due to the larger concentration of CaCl2 molecules. Successful collisions between reactant molecules are essential for the production of products in a chemical reaction.
Therefore, a greater reaction rate will result from more CaCl2 and NaHCO3 molecules colliding often. The additional molecules contribute to a higher number of energetic collisions, where the reactant particles possess sufficient energy to overcome the activation energy barrier and undergo the reaction.
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A student uses a solution of 1.2 molar sodium hydroxide (NaOH) to calculate the concentration of a solution of sulfuric acid (H2SO4). She records a neutral pH after adding 20 mL of the sodium hydroxide solution to 50 mL of the sulfuric acid solution.
What is the concentration of the sulfuric acid solution?
A.
0.24 M
B.
0.12 M
C.
2.1 M
D.
1.0 M
E.
0.48 M
From the calculations, the concentration of the acid is 0.24 M.
What is neutralization?The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.
We have to use the formula;
CAVA/CBVB = NA/NB
CAVANB =CBVBNA
The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O
CA = ?
CB = 1.2 M
VA = 50 mL
VB = 20 mL
NA = 1
NB = 2
CA = CBVBNA/VANB
CA = 1.2 M * 20 mL * 1/ 50 mL * 2
CA = 0.24 M
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Explain how you would determine the charge of a metal, a non
metal and a transition metal for an ion within a compound. Be
prepared to provide the charge of an element on the periodic
table from each of these categories.
Answer:
In order to determine the charge of these elements you'll have to look at their placement in the periodic table by group number.
Explanation:
To further explain this, there is 18 groups of the periodic table. These groups include:
Group 1: The alkali metals have a 1+ charge for their entire group.
For example: Sodium would have a charge of 1+.
Group 2: The earth alkali metals all have a charge of 2+. For example Mg has a charge of 2+.
Group 3-12: The transitions metals are a little harder to figure the charge of each, if given the compound they are bonded with you can use that to figure it out but only a few have distinct charges. Such as Ag (Silver) only have a 1+ charge. If you are still trying to figure the charge, try making an electron configuration to figure out it's spare electron count or charge.
Group 13: These elements in group 13 have a typical charge of 3+. For example Al has a charge of 3+.
Group 14: These elements in group 14 have a typical charge of 4+. For example Carbon has a charge 4+
Group 15: These elements start the shift towards a negative charge in the table, so for group 15 the elements have a 3- charge. For example Nitrogen has a 3- charge.
Group 16: These elements continue with a negative in group 16 with a negative charge of 2-. For example Oxygen's charge is 2-.
Group 17: The halogen elements in group 17 have a charge of 1-. For example Chlorine has a charge of -.
Group 18: The noble gases in group 18 do not have a charge because they are some of the most stable elements so they're not looking to gain or lose an electron (That is what a charge is basicaly). So, they're charge is none.
The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0 % yield. How many grams would be produced from 7.45 g of butanoic acid and excess ethanol?
Express your answer in grams to three significant figures.
7.66g of ethyl butyrate is produced.
The reaction is
CH₃CH₂CH₂COOH + CH₃CH₂OH ----> CH₃CH₂CH₂COOCH₂CH₃
The molar mass of butanoic acid is 88.11g/molWe have 7.45g of butanoic acidThe moles of butanoic acid we have is 7.45/88.11 = 0.0845 molIf the yield is 100%, 1 mole of butanoic acid gives 1 mole of ethyl butyrateBut the reaction yield is 78%1 mole of butanoic acid gives 0.78 mole of ethyl butyrateFrom 0.0845 mol of butanoic acid we get 0.78 x 0.0845 = 0.66 mol of ethyl butyrate.
The molar mass of ethyl butyrate is 116.16g/mol
So 0.66 x 116.16 = 7.66g
7.66g of ethyl butyrate is produced.
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Which of the following would cause an increase in the magnetic force
between two magnets?
A. Decreasing the separation between the two magnets
B. Increasing the separation between the two magnets
C. Decreasing the amount of excess charge on the first magnet
D. Increasing the amount of excess charge on the first magnet
Decreasing the separation between the two magnets will result in increase in the magnetic force between two magnets.
What is a Magnet?This is referred to a substance which produces magnetic field and result in the attraction and repulsion of certain types of things.
Increase in the separation will reduce the magnetic force and vice versa which is why option A was chosen.
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A gas has a volume of 350 mL at 45 oK. If the volume changes to 400 mL, what is the new temperature?
Answer:
T₂ = 39.4 °K
Explanation:
Because you are only dealing with volume and temperature, you can use Charles' Law to find the missing value. The formula looks like this:
V₁ / T₁ = V₂ / T₂
In this formula, "V₁" and T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You have been given values for all of the variables except for "T₂". Therefore, by plugging these values into the formula, you can simplify to find the answer.
V₁ = 350 mL T₁ = 45 °K
V₂ = 400 mL T₂ = ?
V₁ / T₁ = V₂ / T₂ <----- Charles' Law formula
(350 mL)(45 °K) = (400 mL)T₂ <----- Insert values into variables
15750 = (400 mL)T₂ <----- Multiply left side
39.4 = T₂ <----- Divide both sides by 400
Which data are shown on topographic maps?
Answer:
Topographic maps generally shows Natural features such as Rivers and Lakes.
sometimes they also show some features made by humans like brodges, elevations etc.
Answer:
Topographic maps show contours, elevation, forest cover, marsh, pipelines, power transmission lines, buildings, and various types of boundary lines such as international, provincial, and administrative, and many others.
please give me brainliest
Lisa made observations of stars at different times of the year. She noticed a lot of patterns in the fall, while she couldn't find any patterns in the summer. Why might this be?
This is because fall has more weather patterns which are repetitive than summer.
What is Weather?This is defined as the atmospheric condition of a particular place at a given period of time.
The repetitive weather patterns have various effects on the stars which is why they were studied.
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What is the mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH in the following chemical reaction? 2 LiOH(s) + CO₂(g) → Li₂CO₃(s) + H₂O(l)
Answer:
69.6 g CO₂
Explanation:
To find the mass of carbon dioxide, you need to (1) convert grams LiOH to moles LiOH (via molar mass from periodic table values), then (2) convert moles LiOH to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (desired unit in the numerator). The final answer should have 3 sig figs to reflect the given value's sig figs.
Molar Mass (LiOH): 6.9410 g/mol + 15.998 g/mol + 1.008 g/mol
Molar Mass (LiOH): 23.947 g/mol
2 LiOH(s) + 1 CO₂(g) ----> Li₂CO₃(s) + H₂O(l)
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
75.8 g LiOH 1 mole 1 mole CO₂ 44.007 g
------------------ x ---------------- x ----------------------- x ------------------- =
23.947 g 2 moles LiOH 1 mole
= 69.6 g CO₂
The mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH is 69.3g
What is Mole?The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.
A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.
Given,
Mass of LiOH = 75.8g
Moles of LiOH = mass / molar mass
= 75.8 / 24 = 3.15 moles
From the reaction,
2 moles of LiOH react with 1 mole of CO₂
1 mole of LiOH needs 0.5 moles of CO₂
thus, 3.15 moles will need 0.5 × 3.15 moles = 1.575 moles of CO₂
Mass of Carbon dioxide = 1.575 × 44
= 69.3g of carbon dioxide
Therefore, the mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH is 69.3g
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Which of the following is an impact of an increase in motor vehicles in cities?
Oxygen levels have increased
Carbon dioxide levels have increased
Supply of renewable resources has stopped
Supply of nonrenewable resources has become unlimited
C6H12O6 + 6O2 → 6CO2 + 6H2O + energy
Carbon dioxide + Water Glucose (sugar) + Oxygen CO2 + H2O C6H12O6 + 6O2 Cellular respiration or aerobic respiration is a series of chemical reactions which begin with the reactants of sugar in the presence of oxygen to produce carbon dioxide and water as waste products.
Predict the shape of the molecule.
The Correct option is A. octahedral
because the molecule has 6 sigma bonds that results into sp³d² hybridization.
and octahedral structure is formed
Answer:
Octahedral
Explanation:
You have a atom connected to 6 others and each of the bonds are similar
After scientists use a careful process to gather evidence and establish scientific facts, which step most likely occurs next in the scientific process? conducting experiments testing new conditions Ostudying new topics determining explanations After scientists use a careful process to gather evidence and establish scientific facts , which step most likely occurs next in the scientific process ? conducting experiments testing new conditions Ostudying new topics determining explanations
Answer:
Conducting Experiments
How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?
11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 1.3 atm
V= 6.75 Liters
n=?
R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=298 K
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]
Moles = 0.3588 moles
Now,
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]0.3588 moles = \frac{mass}{32}[/tex]
Mass= 11.48 gram
Hence, 11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K
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How many moles of nitrogen, N , are in 69.0 g of nitrous oxide, N2O ?
Answer:
1.57
Explanation:
moles = mass / molar mass
moles = 69 / 44.013
moles = 1.57
moles N₂O = 69 : 44 g/mol = 1.568
N₂O : 2 moles N, 1 mole O
moles N = 1.568 x 2 = 3.136
An unknown compound contains only C , H , and O . Combustion of 6.80 g of this compound produced 16.0 g CO2 and 4.37 g H2O . What is the empirical formula of the unknown compound?
Answer:
I am a small palm-sized pointing device
Fe + H₂O → Fe3O4+H₂ help
Answer:
3Fe + 4H₂O --> Fe3O4 + 4H2
If you have the following chemical equation and you begin balancing it as such,
C5H10 + O2 --> 5CO2 + 5H2O
How many oxygens do you have on the product side at this point in the balancing?
Answer:
15 oxygens
Explanation:
Given the partially balanced reaction: [tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \text{5C} \text{O}_{2}}+\text{5H}_\text{2}\text{O}[/tex]
The subscripts (small number to the right of each element symbol) are the number of atoms of the element within each compound/molecule, and the coefficients (numbers in front of each compound) represent the number of that molecule involved in one full reaction (if the equation were balanced).
The product side of the reaction is on the right of the arrow.
To determine the total number of Oxygens on the product side, we need to identify how many Oxygens are in each molecule (the subscript on the Oxygen), and then multiply times the number of that molecule that would be involved (Coefficient of the compound containing Oxygen). There are multiple compounds on the right side of the equation that contain Oxygen, so we'll need to add together the number of Oxygens each part contributes.
[tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}[/tex]
[tex]\text{\# reactant-side Oxygens}=\bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}\\=5 \text{ CO}_{\text{2}}\text{ molecules} *\frac{\text{2 Oxygens}}{\text{1 CO}_{\text{2}}\text{ molecule}}+5 \text{ H}_{\text{2}}\text{O molecules} *\frac{1\text{ Oxygen}}{\text{1 H}_{\text{2}}\text{O molecule}}\\=10\text{ Oxygens}+5\text{ Oxygens}\\=15\text{ Oxygens}[/tex]
You need to measure out exactly 6.7 mL of water for an experiment. Which of the following would be the best tool for the job?
a. A 250 mL beaker
c. A 50 mL graduated cylinder
b. A 10 mL graduated cylinder
d. A 150 mL Erlenmeyer flask
Answer:
The answer for this problem would be "b. A 10 mL graduated cylinder".
Explanation:
The reason for this is because with a instrument that is closer to the value you're trying to measure, the more precise it will be.
For example using a teaspoon to measure something rather than a cup.
If an element has 11 protons and 12 neutrons and 11 electrons, what is the atomic mass of the element?
The atomic mass of the unknown element is; 23
How to find the atomic mass of an element?We are given that;
Number of protons = 11
Number of Neutrons = 12
Number of Electrons = 11
Now, formula for atomic mass is;
Atomic mass = Number of Neutrons + Number of Electrons
Atomic Mass = 12 + 11
Atomic Mass = 23
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What is organic chemistry? Name at least three categories of compounds that are studied as
a part of organic chemistry.
Answer:
organic chemistry is chemistry focused on structure and composition, extending to recations and properties of compounds.
often centered around compounds with carbon.
alcohols, amines, and aldehydes are some groups that are studied on organic chemistry
SHORT ANSWER:
a) chemistry focused on the structure qnd composition of compounds
b) alcohols, amines, aldehydes
Explanation:
Organic compounds, which are the compounds associated with life processes, are the subject matter of organic chemistry. Among the numerous types of organic compounds, four major categories are found in all living things: carbohydrates, lipids, proteins, and nucleic acids.
11C. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP .If 3.41 grams of KHC are needed to exactly neutralize 31.2 mL of a potassium hydroxide solution, what is the concentration of the base solution?
13B.
H3AsO4 + H2C2O4—--------2CO2 + H3AsO3+ H2O
In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.
name of the element oxidized:
name of the element reduced:
formula of the oxidizing agent:
formula of the reducing agent:
For the reactants,
The oxidation number of hydrogen = +1The oxidation number of oxygen = -2The oxidation number of arsenic = +5The oxidation number of carbon = +3For the products,
The oxidation number of hydrogen = +1The oxidation number of oxygen = -2The oxidation number of arsenic = +3The oxidation number of carbon = +4Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.
Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.
Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.
So, the answers are:
name of the element oxidized: Carbon
name of the element reduced: Arsenic
formula of the oxidizing agent: [tex]\text{H}_{3}\text{AsO}_{4}[/tex]
formula of the reducing agent: [tex]\text{H}_{2}\text{C}_{2}\text{O}_{4}[/tex]
Question 5 of 10
Platinum has a density of 21 g/cm³. A platinum ring is placed in a graduated
cylinder that contains water. The water level rises from 4.0 mL to 4.2 mL
when the ring is added. What is the mass of the ring?
A. 2.6 g
OB. 3.8 g
OC. 4.2 g
OD. 5.2 g
B
Answer:
4.2 g
Explanation:
The VOLUME of the ring is 4.2 - 4.0 = .2 ml = .2 cm^3
the MASS of the ring is this times the density
.2 cm^3 * 21 g/cm^3 = 4.2 g
Answer:
the answer is c
Explanation:
density is mass/volume
so mass=density × volume
but we take the change is volume that is v2-v2=4.2-4=0.2ml
but the density is in gm/cm^3 so we should convert ml into cm^3. eventually they are equal so mass=21×0.2=4.2
Acid rain is caused by which of the following?
excess carbon dioxide
deforestation
nitrogen compounds in the soil
nitrogen compounds in the air
Answer:
nitrogen compounds in the air
Explanation:
If 4.5 moles of an ideal gas has a temperature of 286 K and a pressure 9.4 atm, what is the volume of the container
Answer:
V = 11 L
Explanation:
To find the missing value, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this formula,
----> P = pressure (atm)
----> V = volume (L)
----> n = number of moles
----> R = constant (0.0821 atm*L/mol*K)
----> T = temperature (K)
You have been given all of the values in the correct units. Therefore, you can plug these values into the equation and simplify to find volume. The answer should have 2 sig figs to match the given value with the lowest amount of sig figs.
PV = nRT
(9.4 atm)V = (4.5 moles)(0.0821 atm*L/mol*K)(286 K)
(9.4 atm)V = 105.6627
V = 11 L
Why barbituric acid in name of acid
Select the correct answer.
Which type of crude oil is considered to be the highest quality for gasoline?
O Brent Blend
O West Texas Intermediate
O OPEC Blend
O All crude oil
The type of crude oil that is considered to be the highest quality for gasoline is West Texas Intermediate (Option B).
What is oil?Oil is a fossil fuel obtained from Earth's crust, which is fundamental nowadays to generate electricity.
West Texas Intermediate is a highly pure and high-type energy source of crude oil used in industry.
In conclusion, the type of crude oil that is considered to be the highest quality for gasoline is West Texas Intermediate.
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If a utility burned 7.57 million tons of coal that was 2.00% sulfur by weight, how many tons of sulfur dioxide were emitted? Answer in scientific notation.
So mass of sulphur
[tex]\\ \rm\Rrightarrow 0.02\times 757\times 10^{6}[/tex]
[tex]\\ \rm\Rrightarrow 1514\times 10^4[/tex]
S+O_2–≥SO_2Moles =64/32=2
So
So tons of sulphur dioxide
[tex]\\ \rm\Rrightarrow 2(1516)10^4[/tex]
[tex]\\ \rm\Rrightarrow 3032\times 10^4ton[/tex]
Explanation:
2% of 2million tons of sulphur=
2÷100×7.57E9
That is;
[tex] \frac{2}{100} \times 7.57 \times 10 {}^{6} = 0.02 \times 7.57 \times 10 {}^{6} \\ = 2 \times 10 {}^{ - 2} \times7.57 \times 10 {}^{6} = 2 \times 7.57(10 {}^{ - 2 + 6}) \\ = 15.14 \times 10 {}^{4} (for \: sulphur) \\ for \: sulphur \: dioxide = so2 \\ the \: molar \: mass \: of \: so2 = 64g.mol {}^{ -1} \\ if \: 32grams \: of \: sulphur \: weighs \: 15.14 \times 10 {}^{4} tones \\ 64grams \: will \: weigh \: \frac{64}{32} \times 15.14 \times 10 {}^{4} \\ = 2 \times 15.14 \times 10 {}^{4} \\ = 30.28 \times 10 {}^{4} \\ or = 3.028 \times 10 {}^{5} tones[/tex]
For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen monoxide ( g ) + hydrogen ( g ) nitrogen ( g ) + water ( l ) What is the maximum amount of nitrogen gas that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams
NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete
What is a limiting reagent?The reactant that is entirely used up in a reaction is called as limiting reagent.
The reaction:
[tex]2NO(g) +2H_2(g)[/tex] → [tex]N_2 +2H_2O[/tex]
Moles of nitrogen monoxide
Molecular weight: [tex]M_(_N_O_)[/tex]=30g/mol
[tex]n_(_N_O_) =\frac{mass}{molar \;mass}[/tex]
[tex]n_(_N_O_) =\frac{22.0}{30g/mol}[/tex]
[tex]n_(_N_O_) = 0.73 mol[/tex]
Moles of hydrogen
Molecular weight: [tex]M_(_H_2_)[/tex]=30g/mol
[tex]n_(_H_2_) =\frac{mass}{molar \;mass}[/tex]
[tex]n_(_H_2_) =\frac{5.80g}{2g/mol}[/tex]
[tex]n_(_H_2_) = 2.9 mol[/tex]
Hydrogen gas is in excess.
NO is the limiting reagent.
The amount of the excess reagent remains after the reaction is complete.
[tex]n_(_N_2_) =[/tex] (2.9 mol- 0.73 mol NO x [tex]\frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}[/tex]) x [tex]\frac{2g \;of \;H_2}{mole \;of \;H_2}[/tex]
[tex]n_(_N_2_) =[/tex]4.34 g
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What is the SI unit used to measure weight?
Answer:
The si unit used to measure weight is kilogram /kg
Calculate the pH of a solution with [H+] = 2.52 x 10^-5.
Answer:
pH = 4.6
Explanation:
pH is the negative of the log of the hydrogen ion concentration
- log { 2.52 x 10^-5) = ~ 4.6