Jon owns a clothing store where he designs pairs of shorts, s, and T-shirts, t.
He sells shorts for $14 and T-shirts for $6 each. Jon can work 12 hours a day,
at most. It takes him 15 minutes to design a T-shirt and an hour to design a
pair of shorts. He must design at least 12 items each day, but he cannot
design more than 20 items in one day. Which set of inequalities below
represents this scenario?
A. S 2 12-tss 20 - ts 12 -0.25t, s 2 0; t2 0
B. s2 12-t, ss 20-t, ss 12 -0.25t, s 0;t20
O C. s2 12-t s2 20-t ss 12 -0.25t, s 2 0;t2 0
D. s2 12+ tss 20 + tss 12 -0.25t, s 0,20

Answer:

The correct option is;

B. s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t

Step-by-step explanation:

The set of inequalities below represents this scenario s ≥ 12 - t,

s ≤ 30 - t, s ≤ 24 - 0.66·t

We have given that,

at most. It takes him 15 minutes to design a T-shirt and an hour to design a pair of shorts. He must design at least 12 items each day, but he cannot design more than 20 items in one day.

A statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.

lets t=times

s=shorts

We have to determine the correct inequality so that we will get,

The correct option is;

s ≥ 12 - t,

s ≤ 30 - t,

s ≤ 24 - 0.66·t

Therefore option B is correct.

To learn more about the options visit:

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