The correct sample space for the gumballs in Julia's bag is {lemon-lime, watermelon, watermelon, grape, grape, grape} which makes option D correct.
How to evaluate for the sample sapceThe sample space for the gumballs in Julia's bag would be all the possible outcomes of selecting one gumball from the bag without replacement.
Since there are 1 lemon-lime, 2 watermelon, and 3 grape gumballs in the bag, the sample space would be expressed as:
sample space = {lemon-lime, watermelon, watermelon, grape, grape, grape}.
Therefore,we have 6 total outcomes in the sample space for the gumballs in Julia's bag.
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Solve for m:-
2(m-5) = m-3
The value of m in the given equation will be 7.
Steps to solve the linear equation :
⇒2(m-5) = m-3
Bring RHS (Right hand side) terms to LHS(left hand side) of the equation,
⇒2(m-5) - (m-3) = 0
Now open the brackets,
⇒2m - 10 - m + 3 = 0
Now solve for m,
⇒2m - m - 10 + 3 = 0
⇒m - 10 + 3 = 0
⇒m - 7 = 0
Taking 7 to the RHS of the equation,
⇒m = 7
∴ The value of m is 7
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To solve for m in the equation 2(m-5) = m-3, we can start by distributing the 2 on the left side of the equation:
2m - 10 = m - 3
Next, we can add 3 to both sides of the equation to get:
2m - 10 + 3 = m
This simplifies to:
2m - 7 = m
Now we can subtract m from both sides:
2m - m - 7 = 0
This simplifies to:
m - 7 = 0
Finally, we can add 7 to both sides to solve for m:
m = 7
So the solution for m is 7.