Kepler's second law of planetary motion states, 'a line from a planet to the sun sweeps out equal areas in equal intervals of time.'
What are Kepler's laws of planetary motion?Kepler's three laws of planetary motion include
All planets orbit the sun in elliptical orbits with the sun as the focusA line from a planet to the sun sweeps out equal areas in equal intervals of timeThe square of the period of any planet is directly proprtional to the cube of the semi-major axis of its orbit.From the second law, we see that, a line from a planet to the sun sweeps out equal areas in equal intervals of time.
So, Kepler's second law of planetary motion states, 'a line from a planet to the sun sweeps out equal areas in equal intervals of time.'
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What would be the effect of adding a proton to a nucleus?
A. It would increase the strong nuclear force and increase the
electrostatic force.
B. It would decrease the strong nuclear force and decrease the
electrostatic force.
C. It would increase the strong nuclear force and decrease the
electrostatic force.
D. It would decrease the strong nuclear force and increase the
electrostatic force.
Answer:
A
Explanation:
The electrostatic force and strong nuclear force are opposite forces. The electrostatic force causes the repulsion beteween the positively charged protons in the nucleus but the strong force keeps the nucleus glued together but overcoming the electrostatic force. They would both increase upon the addition of a proton or radioactivity will result.
What cloud extending to the gravitational limits of the solar system would comets come from?.
The Oort cloud extends to the gravitational limits of the solar system would comets come from.
What is oort cloud?It is a hypothetical idea of a cloud of mostly frozen planetesimals that would orbit the Sun at distances between 2,000 and 200,000 AU.
The Oort cloud reaches the solar system's outer gravitational boundaries, where comets originate.
Hence cloud extending to the gravitational limits of the solar system will be oorto cloud.
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which of the following best decribes
Please help me do that.
Answer:
a) 22.2 N
Explanation:
To find load effort. Identify load, efficiency and velocity ratio (VR)
Here given:
Load = 100 NEfficiency = 75%VR (number of pulleys) = 6Effort :
[tex]\rightarrow \sf \dfrac{MA}{VR} = \dfrac{Load \ \div \ efficiency }{VR} = \dfrac{100 \div 75 \% }{6} = 22.22 \ N[/tex]
A car accelerates from 0-26.8m/s in 2.2s. What is its average acceleration?
Answer:
Average acceleration = 12m/s^2
Explanation:
Acceleration is equal to the change in velocity over the change in time:
[tex]a=\frac{\Delta v}{\Delta t}[/tex]
Change in velocity is the final velocity minus the initial.
We are told the car goes from 0 to 26.8 m/s making 26.8 our final and 1 our initial. Therefore the change in velocity is 26.8-0 = 26.8m/s. ([tex]\Delta v[/tex])
And that this happens over 2.2s so this is our change in time: [tex]\Delta t[/tex]
Therefore our acceleration is: [tex]a = \frac{26.8}{2.2}[/tex]
Acceleration = 12.18 m/s^2
Rounded to 2 significant figures (2s.g. in 2.2s), the answer is 12m/s^2.
Hope this helped!
Which two statements are true for reversible reactions that reach dynamic equilibrium?
The correct statement for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."
What is dynamic equilibrium?The dynamic equilibrium is defined as a state of a particular system wherein the reversible reaction takes place and ceases modifying the ratio of reactants as well as products.
The chemical reaction is a method for creating novel chemicals with unique features.
The correct statement for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."
Therefore, the correct answer will be an option (C).
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9. A body is a particular amount of matter. It can be a solid, liquid or gas. It can be
described as existing in
O A. size and shape.
O B. time and space.
C. motion and force.
O D. location and movement.
ou fill be highlighted on the review page)
Answer:
B. Time and Space
Explanation:
Matter is a pshyical or corporeal susbtance in general, whether solid, liquid, or gaseous especially as distinguised from incorpeal substance, as spirit or mind, or form qualities, actions, and the
Within this time-and-space boundary, all matter exists. All matter is made up of atoms. Because these atoms take up space in the universe, solids, liquids, and gases are recognized as existing and may be found in all three dimensions.
Time is a figurative term. Space has three dimensions but time only has one.
Answer:
time and space (A)
Explanation:
When something physically exists, it must exist in time and space. Matter/atoms are recognized as existing--which must be described by existence in time and space.
> Time and space exist as the same property (time cannot exist without space), and is called space-time
> Time is seen as relative {theory of special relativity} meaning that it changes based on your perspective and the space it exists in.
hope this helps!!
When you rub neutral objects
Answer:
Your answer is right
Explain why it is more difficult to balance a nail on its tip than on its base.
note:please dont answer according to presuure concepts,answer according to equilibrium concepts.thanks.
It is much easier to balance a thing that has a large base of support and a low center of gravity. The object won't topple over as a result of little center of gravity wobble because of the wide base and low center of gravity. Therefore, balancing a nail on its base as opposed to its tip would be simpler.
Calculate the mass of an object whose weight is 400n and accleration due to gravity is 10 m/ s
Answer:
40kg
Explanation:
w=m×
w=400n
g=10
m=?
400/10=m×10/10
m=40
The average distance from Earth to the Moon is 384,000 km. How many days would it take, traveling at 800 km/h (the typical speed of a jet), to reach the Moon
Answer:
20 days, 480 hours
The speed of sound in wood is 3300 m s−1 and the speed of sound in air is 330 m s−1. A hammer hits one end of a 33 m long plank of wood. Find the difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air.
The difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air will be 0.09 sec.
What is a sound wave?A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.
Given data;
The speed of sound in wood,u= 3300 m/s
The speed of sound in air,v=330 m/sec
long plank of wood, L=33 m
The time period in the air was found as;
T₁ = 33 m / 330 m/sec
T₁= 0.1 sec
The time period in wood ;
T₂= 33 m / 3300 m/sec
T₂=0.01 sec
T = T₁ - T₂
T=0.1-0.01
T=0.09 sec
Hence, the difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air will be 0.09 sec.
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Prakash kicks a ball of mass 500 g which moves with a velocity of 10 m/s. Passang kicks the same ball and it moves with a velocity of 20 m/s. Compare the kinetic energy acquired by the ball in the two cases. TL Thou Prakash kicks a ball of mass 500 g which moves with a velocity of 10 m / s . Passang kicks the same ball and it moves with a velocity of 20 m / s . Compare the kinetic energy acquired by the ball in the two cases . TL Thou
Answer:
750
Explanation:
The kinetic formula is 1 over 2 *mass * velocity Square
Five resistors each have resistance R. Three of the resistors are connected in series and this combination is then connected in parallel with the two other resistors which have been connected in series with each other. What is the equivalent resistance for this arrangement
Answer:
6/5 * R
Explanation:
The 3 in series sum to 3R for one branch of the parallel circuit
the 2 in series sum to 2R for the other side of the parallel circuit
now find the equivalent R of the parallel circuit with 3R and 2R
here is one way
Requiv = 1 / ( 1/(3R) + 1/(2R) ) =
1/ ( 5/(6R) ) =
6R/5
the equiv resistance = 6/5 * R
a A load of 1000 N can be lifted by applying
the force) effort of 250 N.If the load
arm is 25 cm, calculate the effort arm.
Answer:
Explanation:
[tex]\text{Since the fulcrum lies in between the load and effort, it is class I lever.}[/tex]
[tex]\text{Mechanical advantage (M.A.) of levers is given by,}[/tex]
[tex]\text{M.A.=effort armload arm=50cm,10cm}[/tex]
[tex]\text{Thus, mechanical advantage , M.A. = 5.}[/tex]
[tex]\text{Given, effort (E)=10N, Load(L)=?}[/tex]
∴ [tex]L=E \times M.A.[/tex]
[tex]=10\times5=50N[/tex]
Answer:
[tex]\fbox {100 cm}[/tex]
Explanation:
Finding Mechanical Advantage :
MA = Load / Effort
MA = 1000/250
MA = 4
Finding length of effort arm :
Load arm = Effort arm / 4
Effort arm = 25 cm x 4
Effort arm = 100 cm
what determines the velocity of an object
When the inferior angle of the scapula moves in the superior and lateral direction, the motion is called:
The motion of the inferior angle of the scapula in the superior and lateral direction is called upward rotation.
What are the possible motions of the scapula?The scapula or the shoulder blade has about six different types of motion it undergoes.
The six ways of movement of the scapula are:
protraction,retraction,elevation,depression,upward rotation, anddownward rotationWhen the inferior angle of the scapula moves in the superior and lateral direction, the motion is called upward rotation.
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A girl at a state fair swings a ball in a vertical circle at the end of a string, the force of the string at the bottom is: A-Less than the weight of the ball B-greater than the weight of the ball C-equal to the weight of the ball D-Zero
which choice is correct and why? thx
The force of the string at the bottom is greater than the weight of the ball. The correct option is B.
What is Net force?When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.
A girl at a state fair swings a ball in a vertical circle at the end of a string.
When the ball is at the bottom, the force acting will be
The tension in the string , T = mass x centripetal acceleration + Force of gravity
So, T = m x ac + mg
The tension in the cable at the bottom will have centripetal force and weight forces acting on it.
Thus, the force of the string at the bottom is greater than the weight of the ball.
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if ~u = 2ˆı −ˆ and w~ =ˆı 2ˆ, find the component form of ~v = ~u w~ and sketch the specified vector operations geometrically.
The component form of the vector - u + w is determined as -2i + 3j.
Component vector V
The component vector V is calculated from the summation of vector U and vector W.
v = -u + w
Given;
u = 2i - jw = i + 2jv = -(2i - j) + i + 2j
v = -2i + j + 2j
v = -2i + 3j
A sketch of the vectory - axis
↑
↑
↑ 3j
↑
x - axis ← ← ← ← ←
2i
The complete question is below:
if u = 2i - j and w = i + 2j, find the component form of ~v = -u + w~ and sketch the specified vector operations geometrically.
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Which planet in our solar system, discovered in 1781, was named after the greek god of the sky?.
Answer:
i think the planet is Uranus
Two identical blocks are attached to the same massless rope, which is strung around two massless, frictionless pulleys. A massless scale is connected to the same rope and measures the tension in the rope. The two identical blocks are released from the rest. The experiment is then repeated with two new blocks, with masses m1 and m2. When they are released from rest, the system remains at rest, and the scale measures the same tension as in the previous experiment. Find m1 and m2 in terms of m.
Answer:
The value of mass 1, m1= 6/5m
The value of mass 2, m2= 3/5m
Explanation:
case 1:
here tension and the acceleration will be:
for m1;
mg-T=ma2mg - 2T = 2ma .....1.for m2:
2T-mg = ma/2 ..... 2.adding the both equations,
2mg - 2T + 2T-mg = 2ma + ma/2
a = 2/5 g
putting the value of a into the equation 1.
mg - T = m* (2/5)g
T = 3/5 ( mg )
now
case 2:
The two identical blocks are released from the rest, the tension remains the same as the case 1.
so,
for m1:
2T-m2g=0for m2:
2m2g - 2T =0adding both equations we get,
2T-m2g + 2m2g - 2T = 0
m2 = m1 / 2
T = m1*g / 2
here we know that
T (case1) = T (case2)
3/5 ( mg ) = m1*g / 2
m1 = 6/5 m
hence
m2 = 3/5 m
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Please answer of this question
Answer:
[tex]\frac{\pi }{15}[/tex]m
Explanation:
At 10am, the minute hand and hour hand are ' 2 hours apart', since the minute hand is at 12pm and hour hand is at 10am.
Angle between the two hands = 2/12 * 360
= 60°
Arc Length = [tex]2\pi r(\frac{60}{360} )[/tex]
= [tex]2\pi (0.2)(\frac{1}{6} )\\= \frac{\pi }{15} m[/tex]
Please Answer this question! I would be very grateful!
Answer:
friction
Explanation:
i believe that is the answer
Answer:
Option C - Friction
Explanation:
Inertia would be an invalid option as it is not changing state.
Gravity would be invalid option as it will stay on the ground constantly.
Friction would be a valid option as the friction between the bottom part of the furniture and the floor are being rubbed together .
Air resistance is valid but will not be as strong as the friction
Therefore Option C - Friction will be the primary force that the person has to work against to keep this piece moving .
Hope this helped and have a good day
which of the following is not a lever?
a. winch
b. scissors
c. can openers
d. tweezers
Answer:
a?
Explanation:yes it is a
A ball is thrown vertically upward with an initial speed of 50 m/s. if air resistance does affect motion, then what would be its speed upon returning to its starting point?
Answer:
your answer would 50 m/s I do believe
The correct answer for the speed of the ball upon resting to it's starting point is [tex]50[/tex] m/s.
Given:
Initial speed: [tex]u = 50[/tex] m/s
To calculate the speed upon resting position, Calculate the time requires to reach starting position:
Time required to reach starting point = 2 * (Time require to reach the maximum height)
Time required to reach the maximum height:
[tex]v = u+(-a )t[/tex]
Final velocity([tex]v[/tex]) is [tex]0[/tex] m/s.
Negative sign indicates negative acceleration:
[tex]t= \dfrac{50}{9.8}\\\\ = 5.10[/tex]seconds
Time for start point = [tex]2 * 5.8[/tex]
[tex]=10.6[/tex] seconds
From equation of motion:
[tex]v= u+at[/tex]
[tex]= 50 -9.8* 10.2[/tex]
[tex]= -50.2[/tex] m/s
Negative sign indicates downward direction.
Speed when ball return is is [tex]50[/tex] m/s.
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A crate is pulled with a force of 165 N at an angle 30 ° northwest. What is the resultant horizontal force on the crate?
Answer:
Resultant horizontal force = 143 N
Explanation:
Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;
Resultant horizontal force = 165 * cos 30
Resultant horizontal force = 142.89
Approximating to a whole number gives;
Resultant horizontal force = 143 N
A car initially traveling at 15.0 m/s accelerates at a constant rate of 4.50 m/s2 over a distance of 45.0 m. how long does it take the car to cover this distance? (4 points)
A car initially traveling at 15.0 m/s accelerates at a constant rate of 4.50 m/s2 over a distance of 45.0 m, the time taken to cover this distance is mathematically given as
t = 2.24 s
What is the time taken to cover this distance?Generally, the equation for Kinematic relation is mathematically given as
S = ut + (1/2)at^2
Therefore
45 = 15t + 2.25 t^2
2.25 t^2 + 15 t -45 = 0
t = 2.24 s
In conclusion, the time is taken to cover this distance
t = 2.24 s
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A.
emotional health : expressing feelings
B.
physical health : respecting others
C.
mental health : living in harmony with the environment
D.
social health : getting adequate sleep
What name describes an object that orbits a planet?
Answer:
It can be either a moon or a satellite
Explanation:
a moon is a piece of space debris that orbits a planetdue to the planets gravitational force. Inherently, satellite mimics a moon but it is used for collecting data and etc
The line joining all places of zero variation is called?
According to the research, the agonic line is the line joining all places of zero variation.
What is the agonic line?It is a term that refers to the zero declination isogon, that is, it joins the points that do not have magnetic declination.
This line crosses the magnetic and geographic poles of the Earth's surface from which they are aligned and along which there is no magnetic variation.
Therefore, we can conclude that according to the research, the agonic line is the line joining all places of zero variation.
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