label each major part and indicate you understand the process of how neurons send messages to each other.

The number of grams of an element divided by the mass in grams of the compound, then multiplied by 100%, is the percent by mass of the element in the compound.

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The empirical formula of an organic compound gives the simplest whole number ratio of the different elements in the compound. In this case, the empirical formula of the compound is CH2O, which means that the compound is made up of one Carbon atom, two Hydrogen atoms, and one Oxygen atom.

The molecular mass of a compound can be determined by adding up the atomic masses of all the atoms in its empirical formula. The atomic mass of Carbon is 12.0107 g/mol, the atomic mass of Hydrogen is 1.008 g/mol, and the atomic mass of Oxygen is 15.9994 g/mol.

So, the molecular mass of the compound with an empirical formula of CH2O is (12.0107 + 2 x 1.008 + 15.9994) g/mol = 30.03 g/mol

Therefore, the molecular mass of the compound is 30.03 g/mol.

The reaction of methyl salicylate with sodium hydroxide gives the sodium salt of salicylic acid called as sodium salicylate which can be represented as: C7H6O3 + NaOH -> C7H5O3Na + H+

With the chemical formula C7H6O3, salicylic acid is an inorganic substance that is a subclass of phenolic acid and beta-hydroxy acid (BHA). Aspirin is one of the main products made from salicylic acid, which is also known as ortho-hydroxybenzoic acid. It is a crystalline solid with a white hue that is used in the creation of numerous pharmaceutical medicines. Salicylic acid, an organic acid, dissociates to lose a proton from the carboxylic acid functional group in an aqueous solution. It appears in nature as crystals of an organic acid that are transparent and colorless. This compound's salt and ester derivatives, sometimes referred to as salicylates, are frequently utilized in organic chemistry. It combines with sodium hydroxide to produce sodium salicylate.

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The correct order is iodine>bromine> chlorine. As we move down the halogens the London dispersion forces increase.

London dispersion forces are the intermolecular forces that hold the molecules together. It is one of the van der Waal forces and is sometimes known as induced dipole- induced dipole attraction. It majorly works for noble gases like argon, and neon. In the case of halogens, as we move down the size of the atoms increases and the van der Waal forces become more prominent hence the London dispersion forces also increase. Therefore, iodine has the strongest dispersion force and chlorine has the weakest.

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Q: arrange the molecules by the strength of the london (dispersion) force interactions between molecules.

chlorine gas, bromine gas, iodine gas

In the presence of concentrated sulphuric acid as a catalyst, ethanol interacts with ethanol to form the ester, ethyl ethanoate. The response is gradual and reversible.

In the presence of concentrated sulphuric acid as a catalyst, ethanol interacts with ethanol to form the ester, ethyl ethanoate. The response is delayed and can be reversed. To reduce the possibility of a reverse reaction, the ester is distilled out as soon as it is generated.

Because it makes the process less unclear, all of the stages in the mechanism below are depicted as one-way reactions. The reverse reaction is performed so differently that it influences how the mechanism is stated. If you’re interested, there’s a link to ester hydrolysis farther down the page.

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The answer is 567.76 grams.

We used the balanced equation for the reaction of P4 + 5O2 → 2P2O5. This equation tells us that for every 1 mole of P4 that reacts, 2 moles of P2O5 are produced.

Therefore, if we start with 2 moles of P4, we would end up with 4 moles of P2O5. To find the mass of 4 moles of P2O5, we can use the molar mass of P2O5 which is 141.94 g/mol.

To find the mass, we multiply the number of moles by the molar mass, so 4 moles * 141.94 g/mol = 567.76 grams.

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The empirical formula for the given crystalline material is Cu₁₆O₂₀YBa₂

The empirical formula of a compound is the simplest formula of a compound that shows the simplest ratio in which the elements are present in a compound.

The simplest whole-number ratio of atoms in a chemical molecule is its empirical formula. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S₂O₂, are two straightforward examples of this idea. Both have the same empirical formula of SO.

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When the dipoles are organized in head-to-tail; antiparallel and side-to-side geometries, polar molecules exhibit attractive dipole-dipole interactions. molecules that are polar.

Because PCl₃ is polar, dipole-dipole attractions will occur. Nonpolar F₂, ionic FeCl₂, and nonpolar CO₂. Dipoles develop in amplitude as covalent bonds get more polar, and hence dipole-dipole attractions expand in size. Dipole-dipole interactions occur when partial charges produced inside one molecule are attracted to an opposing partial charge in a neighboring molecule. Polar molecules align so that the positive end of one molecule interacts with the negative end of another.

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The actual question is:

Polar molecules have attractive dipole-dipole interactions when the dipoles are arranged in which of the following geometries?(Select all that apply)

head-to-tail; side-to-side; antiparallel; diagonal; round and round

Acids are chemical substances that are defined by a sour taste in an aqueous medium.

These acids may have the tendency to turn into blue litmus red. On the other side, bases are chemical substances that are defined by a bitter taste and are slippery to the touch.

There are some bases that are soluble in water, while others are not, there are two types of litmus paper that are available that can be used to identify acids and bases:

They are known as Red litmus paper and blue litmus paper.

A blue litmus paper changes into red under acidic conditions and red litmus paper changes into blue under basic or alkaline conditions. These chemical properties are very useful in identifying substances.

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1. Take note of the ions present in the reactants to determine the right order. 2. Consider various cation-anion pairings. 3. To ascertain if one of the combinations results in an insoluble salt, use the solubility criteria.

Positively charged ions are known as cations. Negatively charged ions are referred to as anions. A charged atom or molecule is an ion. A balanced atom will change into a positively charged cation if one or more of its electrons are lost. A balanced atom will change into a negatively charged anion if it gains one or more electrons. Ions include both anions and cations. They are drawn to one another because their electrical charges are in opposition. While an anion repels an additional anion, a cation repels other cations. An ion that has acquired one or more electrons and now has a net negative charge is called an anion.

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C is correct. Gas Z has a smaller molar mass than gas X because of the concept of kinetic energy.

As shown in the diagram, there are two gases Z and X. It is provided in the data that the temperature of the gases are the same, which indirectly says that the kinetic energy of both gases is same. Kinetic energy is the term that defined energy stored in the particles due to their motion or velocity. Its SI unit is Joule. And its formula is [tex]\frac{1}{2}[/tex]m[tex]v^{2}[/tex] . So kinetic energy of Z= Kinetic energy of X.

Therefore, the gas with a higher molecular speed will have a lower molecular mass. And it can be seen from the graph that Z has more speed, so it will have a smaller molar mass.

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Q: the two gas samples represented in the graph above are at the same temperature. which of the following statements about the gases is correct?

A. Z has more kinetic energy than X

B.Fewer molecule in present in Z

C. Z has smaller molar mass

D. Z has larger molar mass

The molar mass of carbon atoms in 1 mole of trolamine is 72.06 g where the molar mass of compound is 149 g.

Molar mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molar mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.

Molar masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.

Molar mass of carbon atoms in 1 mole of trolamine is given as, 12.011×6=72.06 g

Thus, the molar mass of carbon atoms in 1 mole of trolamine is 72.06 g where the molar mass of compound is 149 g.

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The heat of combustion of the reaction is -859 kJ/mol.

When we talk about the enthalpy of combustion, we mean the heat that is required in order to burn up the compound in the presence of oxygen. Recall that the heat of reaction is gotten by the use of the formula;

Sum of the bond energies of the reactants - Sum of the bond energies of the products

As such, we have;

[(1 * 835) + (2 * 411)] - [(2 * 799) + (2* 459)]

= (835 + 822) - (1598 + 918)

=1657 - 2516

= -859 kJ/mol

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To prepare 150 mL of 0.0900 M sodium acetate, pH 4.80, we need 74.72 mL of glacial acetic acid, 25 g of NaOH, and 12.6 mL of 1.00 M NaOH.

1. To prepare 150 mL of 0.0900 M sodium acetate, we need to use the Henderson-Hasselbalch equation, which relates pH, pKa (-log10Ka), and the ratio of the concentration of conjugate acid (HA) and conjugate base (A-).

pH = pKa + log₁₀([A-]/[HA])

[A-] = 0.0900 M, [HA] = 17.5 M, pKa = 4.76

To calculate the volume of glacial acetic acid needed, we can use the following equation:

pH = pKa + log₁₀([A-]/[HA])

We know that pH = 4.80, [A-] = 0.0900 M, pKa = 4.76

Therefore, log10([A-]/[HA]) = pH - pKa = 4.80 - 4.76 = 0.04

[A-]/[HA] = 10⁰·⁰⁴ = 1.82

[HA] = [A-]/1.82 = 0.0900 M/1.82 = 0.0495 M

Then, we can calculate the volume of glacial acetic acid needed by using the following equation:

V = n / C = (n / V) x V = (0.0495 M x 150 mL) / 0.0900 M = 74.72 mL

2. To prepare 25.0 mL of 1.00 M NaOH, we can use the following equation:

m = n / V = (n / C) x V = (1.00 M x 25.0 mL) / 1 = 25.0 g

3. To adjust the pH to 4.80, we need to use the Henderson-Hasselbalch equation again, and we can calculate the volume of 1.00 M NaOH needed.

pH = pKa + log₁₀([A-]/[HA])

We know that pH = 4.80, [A-] = 0.0900 M, pKa = 4.76

Therefore, log₁₀([A-]/[HA]) = pH - pKa = 4.80 - 4.76 = 0.04

[A-]/[HA] =10⁰·⁰⁴ = 1.82

[HA] = [A-]/1.82 = 0.0900 M/1.82 = 0.0495 M

The initial [HA] = 17.5 M, thus we need to add 1.82 x 0.0495 M = 0.088 M of NaOH to increase the [A-] and decrease the [HA] to reach the desired pH.

V = n / C = (n / V) x V = (0.088 M x 150 mL) / 0.0900 M = 12.6 mL

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Answer:

B. a mound of sand piled up by the wind.

Explanation:

It is option B because a dune is a natural feature formed by the wind blowing sand particles and piling them up in a specific area. The wind can shape the dune and cause it to grow taller, sometimes reaching heights of 300 meters or more. Dunes are not caused by the wind blowing sand away, as stated in option A, nor are they found in wet and rainy areas, as stated in option D, they are typically found in desert regions or along coastlines. It is not a cave as stated in option C.

There is a nine-fold rise in the pace of the reaction when the concentration of F is tripled but the concentration of G stays the same. The response is in the second order relative to F.

If you increase one reactant's concentration in a third order reaction involving two reactants by three times, the rate rises by a factor of three. If a reactant is first order, its concentration will cause a doubling in the reaction's rate; a tripling in the reaction's rate, etc. If a reactant is third order, its rate of reaction will increase by a factor of 8 when its concentration is doubled (23 = 8), etc.

The concentration of a reactant does not impact the rate. The rate remains unchanged even if the concentration is doubled. The given rate law needs to be written first. The concentrations of A and B will be increased by three times each after that.

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Configuration (a) - Ground state Configuration (b) - Violates Hund's Rule Configuration (c) - Violates Pauli Exclusion Principle.

Configuration is the process of setting up and fine-tuning a system to meet a user's specific needs. It is a process of organizing and customizing a system or device to meet the specific requirements of its user. This process is often used to customize a device or system to fit the user’s individual preferences, such as setting up a laptop for a specific user or configuring a complex network for a business. Configuration includes installing and configuring hardware, software, and other settings. It also involves troubleshooting any issues that may arise during the process.

Configuration (a) is a ground state. It obeys all three of the ground state rules.
Configuration (b) violates the Aufbau principle, as electrons should fill the lowest available energy levels first.
Configuration (c) violates the Pauli Exclusion principle, as each orbit can only contain two electrons with opposite spin.

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Based on the given information, it is not possible to accurately predict which number is the predicted yield, the actual yield, and the percent yield without additional information or context. The percent yield is calculated by comparing the actual yield to the predicted yield, which are both typically measured in grams or moles.

The list of the factors that will increase the reaction rate of a chemical reaction are

The Factors that can increase the reaction rate of a chemical reaction include:

Lastly, Increasing the surface area of the reactants: as the surface area of the reactants increases, the number of reactant particles in contact with each other increases, making it more likely for them to collide and react.

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All are true. The resulting solution will have a NO3- ion concentration of 672 mmoles/580 mL, or 1.159 M.

Pb(NO3)2 volume = 260 mL = 0.26 L

Pb(NO3)2 has  molarity of 1.2 M.

KI volume = 300 mL = 0.3 L

KI has a molarity of 1.9 M.

Pb(NO3)2 + 2KI reaction rightarrow PbI2 + 2KNO3

First potassium iodide.

Potassium iodide we must determine the moles of reactants present: Pb(NO3)2 moles = Pb molarity (NO3)  1.2 × 0.26 = 0.312 moles = 2 times Volume in L 1.9 x 0.3 = 0.57 moles of KI = Molarity of KI x Volume in L

We know from stoichiometry that For the reaction to proceed, 1 mole of KI requires 1/2 mole of Pb(NO3)

2. As a result, 0.57 mole of KI necessitates (1/2 * 0.57) mole of Pb(NO3)2 for the reaction to continue.

0.285 moles of Pb(NO3)2 required

We have 0.312 moles, which indicates that Pb(NO3)2 is present in excess.

You mix 260. mL of 1.20 M lead(II) nitrate with 300. mL of 1.90 M potassium iodide.The lead (II) iodide is insoluble  all are true.  

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A's concentration falls if D is removed. In this scenario, the equilibrium position will change, causing A's concentration to once again drop as a result of its reaction with B to produce more C and D.

The following is the Le Chatelier principle: A shift in the equilibrium's location cancels out the impact of a change in one of the variables that define an equilibrium in a system.

The broad statement: Kp = Kc(RT) (RT) Where n = moles of gaseous products - moles of gaseous reactants, one can derive n. Pure solids and pure liquids are not given concentration words.

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At 3,557 torr, 16.45 moles of methane gas are at a temperature of T=17.15 K in a 70.7 L container.

According to the ideal gas law: PV=nRT, where R=0.082 and T is temperature in Kelvin (K). P is pressure, V is volume, n is the amount in moles.

(4.68)*(4.95)=(16.45)*(0.0821)*

T=17.15, therefore calculate it.

An object that is in the gaseous, or vaporous, condition of matter, is referred to as a gas. When referring to material with characteristics of a gaseous substance, the word "gas" can also refer to the condition itself. Along with liquid, solid, and plasma, gases are one of the four natural states of matter. The shape or volume of a gas can change.

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Answer:

245

Explanation:

everyone needs to chill don't answer if you can't get it right it wastes you time and others as well not trying be a hater but its true

The electron configuration for silver (Ag) is based upon the place meant of silver in the fifth row of the periodic table in the 11th column of the periodic table or the 9th column of the transition metal or d block. Therefore th electron configuration for silver must end as [tex]4d^{9}[/tex].

What is meant by electron?

[tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{10} 4p^{6} 5s^{2} 4d^{9}[/tex]

This notation can be written in core notation or noble gas notation by replacing the [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{10} 4p^{6}[/tex]  with the noble gas [Kr].

[Kr] [tex]5s^{2} 4d^{9}[/tex]

For some of the transition metals they will actually transfer an s electron to complete the d orbital, making silver,

[Kr] [tex]5s^{1} 4d^{10}[/tex]

I hope this was helpful.

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The result of the multiplication of given number in scientific notation is 1.23 × 10⁻⁵. The power of 10 is added in the muiltipication.

Scientific notation is a standard and scientific way of representing numbers. In scientific notation, the numbers are converted with powers of ten. For example a number 5 can be written as 5 × 10°. Similarly 500 can be written as  5 × 10².

The first term in the scientific notation  4.1 × 10° = 4.1 . since 10° = 1.

second terms, 3 × 10 ⁻⁶. Multiply it with 4.1

= 4.1 × 3 × 10 ⁻⁶ = 12.3 × 10 ⁻⁶ =   1.23 × 10⁻⁵.

Therefore, the final answer in scientific notation is written as: 1.23 × 10⁻⁵.The power ten is increased when we move the decimal point to the left.

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ampicillin 500 mg im q 6 hrs. supply on hand: 1 gm vial. the medication order is to give 3.0845 ml of ampicillin every

To calculate the amount of ampicillin to administer, you will need to first convert the patient's weight from pounds to kilograms. One kilogram is equal to 2.20462 pounds. So, 136 pounds is equal to 61.69 kilograms.

Next, the medication order states that the patient should receive 500 mg of ampicillin every 6 hours. To calculate the daily dosage, we can multiply the 500 mg dose by the number of doses per day (24 hours / 6 hours = 4 doses per day) which gives us 2000 mg/day.Now, we can use the patient's weight to determine the appropriate dosage per weight. The recommended dosage of ampicillin is 25-50 mg/kg/day. In this case, we will use 50mg/kg/day. So we can calculate the dosage as 50mg/kg/day * 61.69 kg = 3084.5 mg/day. To convert the dosage in mg to ml, we can use the information on the vial. The vial contains 1 gm of ampicillin, which is equal to 1000mg. So we can divide the dosage in mg by the concentration of the vial.3084.5mg/1000mg = 3.0845ml. Therefore the medication order is to give 3.0845 ml of ampicillin every.

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Favour the right side with compound I being the most acidic compound.Option (b) is correct

Because carbonyl is electron withdrawing group.out of halogen fluorine is most electronegative so it's show it's negative inductive effect and inductive effect is maximum upto 3 atom.in option( b) it is near to  carbonyl . Electron withdrawing group increase acidic strength and halogen are electron withdrawing group,out of all halogen Fluorine is most electron withdrawing atom .The substance is acidic if there are more positively charged hydroniums than negatively charged hydroxyls. If there are more positively charged hydroniums than negatively charged hydroxyls, the compound becomes basic.. The term "potential (or power) of hydrogen" actually denotes pH.

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The correct order for equilibrium constant = K₁ > K₂ >K₃

What is meant by equilibrium?

On applying this concept in figures :

Given : Green = Cl₂ Brown = Br₂ Purple = I₂ Grey = Ethene

Grey + Green = 1,2- dihalide ethane

a) Number of Cl₂(green ) = 2

number of ethane ( grey ) = 2

Number of 1,2-dichloride alkane( grey + green ) = 8

Plugging these number in equilibrium constant expression :

[tex]k_{1} = 8/ 2*2=8/4=2[/tex]

Hence K₁ for ethene + chlorine = 2

b) Number of Br₂(brown ) = 4

number of ethane ( grey ) = 4

Number of 1,2-dibromide alkane( grey + brown ) = 6

On plugging these values in K expression as :

[tex]K_{2} = 6/4*4=6/16=0.0612[/tex]

Hence K₂ for ethen + Bromine = 0.375

c) Number of I₂(purple ) = 7

number of ethane ( grey ) = 7

Number of 1,2-diiodide alkane( grey + purple ) = 3

On plugging values in K expression as:

[tex]K_{3} = 3/7*7=3/49=0.0612[/tex]

Hence K₃ for ethene + Iodine = 0.0612

So , the order of equilibrium constant (K) from largest to smallest :

K₃ = 0.0612 K₂ = 0.375 K₁= 2

K₁ > K₂ >K₃

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The chemist added 0.1424 g of barium chlorate to the flask.

To calculate the mass of barium chlorate added to the reaction flask, we need to use the formula: mass = molarity x volume x molar mass.

First, we need to find the molar mass of barium chlorate. The molar mass is calculated by adding the molar masses of all the atoms in the compound.

The formula for barium chlorate is Ba(CIO₃)₂, which means it is made up of one barium atom (Ba), two chlorine atoms (Cl), six oxygen atoms (O), and two iodine atoms (I).

The molar mass of barium is 137.327 g/mol, chlorine is 35.453 g/mol, oxygen is 15.999 g/mol, and iodine is 126.904 g/mol.

So the molar mass of barium chlorate is (137.327 + 235.453 + 615.999 + 2×126.904) g/mol = 479.205 g/mol.

Next, we need to use the formula mass = molarity x volume x molar mass. We know that the molarity is 0.122 M, the volume is 265.0 mL and the molar mass is 479.205 g/mol. So we can plug these values into the formula: mass = 0.122 x 0.265 x 479.205.

After converting the volume to L and using the formula, we get 0.1220.265479.205 = 0.1424 g.

So the chemist added 0.1424 g of barium chlorate to the flask.

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The correct number of significant figures for (65.0×1.07)/14 is 2, for 170-3.33+24.9 is 3 and 99.670+24.52-0.3 is 4.

The critical figures of a number are the crucial or significant digits that accurately convey the meaning of that number. 6.658, for instance, has four significant digits. These huge amounts give the numbers accuracy. Additionally, they are known as significant digits. The 2, 4, 5, and last 0 of the number 0.2540 are significant. Additionally significant are the zeros before and after numerals and the decimal point. Exponential digits are not significant in scientific notation; the three significant digits in 1.12106 are 1, 1, and 2.

Given the various operations to be carried out as:

(a) (65.0×1.07)/14 = 4.9678 = 5.0

The number of significant figures = 2

(b) 170-3.33+24.9 = 191.57 = 192

The number of significant figures = 3

(c) 99.670+24.52-0.3 = 123.89 = 123.9

The number of significant figures = 4

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69 grams of CO2 will produce in the combustion of octane where CO2 and Water is produced.

Combustion is defined as the chemical reaction between substances  including oxygen. The reaction is accompanied by the generation of heat and light in the form of flame. The products CO2 and H2O forms when octane is burned. The process of combustion cannot take place in an atmosphere devoid of oxygen. The main ingredient of combustion is oxygen. The balanced chemical equation for combustion of octane is,

    2C8H18 + 25O2 ----> 16CO2 + 18H2O

The molar mass of C8H18 = 114 g/mole

The molar mass of CO2 = 44 g/mole

The mass ratio of C8H18/CO2 is 2* 114 / (16 * 44)

22.4 g of octane generates, 69 gram of CO2.

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