Answer:
Show diagram so we can see
Explanation:
What would happen if the earths orbit was longer or shoter?
Answer:
If Earth were to change its orbit – maybe because the sun somehow disappeared or another, larger object entered the solar system and exerted a stronger pull – it would very likely mean the end of life as we know it. Without any orbit, Earth would likely go crashing directly into the sun.
Explanation:
Hope this helped! Please give brainly if you want!
Explanation:
If Earth were to change its orbit – maybe because the sun somehow disappeared or another, larger object entered the solar system and exerted a stronger pull – it would very likely mean the end of life as we know it. Without any orbit, Earth would likely go crashing directly into the sun.
Suppose that we continue to work with the gas from the previous problem ( 2 moles of gas occupy 126 L at 346 K, and that the van der Waals constants are a = 6.20 atmL^2/mol^2 and b = 0.0852 L/mol), but consider the molecules to be mathematical points. Calculate the pressure and compare it to the values from the previous problem.
Answer:
0.448 atm
Explanation:
So, we have;
n = 2 moles
V = 126 L
T = 346 K
a = 6.20 atmL^2/mol^2
b = 0.0852 L/mol
R = 0.082 atmLK-1mol-1
P = nRT/V -nb - an^2/V^2
Substituting values;
P=2 * 0.082 * 346/126 -(2 * 0.0852) - 6.20 * 2^2/126^2
P=56.744/125.8296 -24.8/15876
P= 0.45 - 0.001562
P= 0.448 atm
When the concentration of A in the reaction A ..... B was changed from 1.20 M to 0.60 M, the half-life increased from 2.0 min to 4.0 min at 25°C. Calculate the order of the reaction and the rate constant.
Answer:
2
[tex]0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]
Explanation:
Half-life
[tex]{t_{1/2}}A=2\ \text{min}[/tex]
[tex]{t_{1/2}}B=4\ \text{min}[/tex]
Concentration
[tex]{[A]_0}_A=1.2\ \text{M}[/tex]
[tex]{[A]_0}_B=0.6\ \text{M}[/tex]
We have the relation
[tex]t_{1/2}\propto \dfrac{1}{[A]_0^{n-1}}[/tex]
So
[tex]\dfrac{{t_{1/2}}_A}{{t_{1/2}}_B}=\left(\dfrac{{[A]_0}_B}{{[A]_0}_A}\right)^{n-1}\\\Rightarrow \dfrac{2}{4}=\left(\dfrac{0.6}{1.2}\right)^{n-1}\\\Rightarrow \dfrac{1}{2}=\left(\dfrac{1}{2}\right)^{n-1}[/tex]
Comparing the exponents we get
[tex]1=n-1\\\Rightarrow n=2[/tex]
The order of the reaction is 2.
[tex]t_{1/2}=\dfrac{1}{k[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{t_{1/2}[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{2\times 1.2^{2-1}}\\\Rightarrow k=0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]
The rate constant is [tex]0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]
What happens when sodium undergoes a chemical reaction with chlorine? A The two substances form a heterogeneous mixture B. The two substances form a homogenous mixture C A new compound is formed – salt D The two substances undergo various physical changes
Answer:
C.) A new compound is formed - salt
Explanation:
Na is a metal
Cl is a nonmetal
When they are combined, they form ionic bonds as they seek to fill their octets. Salts are ionic compounds.
When sodium undergoes a chemical reaction with chlorine, a new compound is formed known as sodium chloride or common table salt. The correct option is C.
Chemical reaction is a chemical process, which involves the transformation of one or more substances, called reactants, into new substances, called products. These reactions occur when atoms or ions or molecules rearrange their bonds to form different chemical compounds.
The reaction between sodium and chlorine is highly exothermic (releases heat energy) and produces a violent reaction, resulting in the formation of a stable ionic compound.
The balanced chemical equation for this reaction is:
[tex]2Na + Cl_2\rightarrow 2NaCl[/tex]
In this reaction, the sodium atoms (Na) lose one electron each to achieve a stable electron configuration, forming sodium ions (Na+), while the chlorine molecules [tex](Cl_2)[/tex] gain one electron each to form chloride ions (Cl-). The resulting sodium ions and chloride ions attract each other due to their opposite charges, forming a three-dimensional crystal lattice of sodium chloride.
Therefore, when sodium undergoes a chemical reaction with chlorine, a new compound is formed that is salt. Option C is the correct answer.
Learn more about chemical reactions here:
https://brainly.com/question/29762834
#SPJ6
Determine the number of valence electrons for the following: [kr] 5s2 4d6
A)5
B)2
C)4
D)7
E)8
F)6
Answer: B) 2 (as indicated by electron distribution shown), but taking into account the real properties of this element, 4,7,8 also occur (see below).
Explanation:
This is the electron complement/atomic number of ruthenium, which actually has the structure [Kr] 5s1 4d7
Nevertheless, Ru does not form Ru(I) compounds and few Ru(II) compounds (RuCl2, RuBr2, RuI2). It also forms Ru(III)Cl3 and a larger number of Ru(IV) compounds, e.g. RuO2, RuS2. It also forms RuO4
Use your periodic table to complete the table below. The first one has been done for you.
Element
Atomic #
Mass
Protons
Neutrons
Electrons
Symbol
Iodine
53
127
53
74
54
I1-
35
17
Cl1-
Hydrogen
1
1
0
35
45
36
5
11
B3+
Oxygen
16
8
10
Element
Atomic #
Mass
Protons
Neutrons
Electrons
Symbol
Nitrogen
7
7
10
Aluminum
27
10
56
26
24
29
35
Cu1+
64
29
27
Match each of the positive ions listed with the total number of electrons that ion contains. Use your periodic table. The same answer may be used more than once.
A) 2 B) 10 C) 21 D) 23 E) 24
F) 25 G) 36 H) 48 I) 76 J) 81
____ Al+3 ____ Fe+3 ____ Mg+2 ____ Sn+2
____ Li+1 ____ Cr+3 ____ Rb+1 ____ Pt+2
Answer: my epic on fortnite is
Explanation:Bookboy24 ok add me and arena or creative
Where are valence electrons located in an atom?
Answer:
Valence electrons are the electrons in the outermost shell, or energy level, of an atom.
Answer: The outermost shell
Explanation:
Valence electrons are located in the outermost shell of the atom, or the energy level as it is also known.
a gas expands from 266 mL to 983 mL at constant temperature. calc the work done (in joules) by the gas if it expands against a vacuum. also call the work done (in joules) by the gas if it expands against a constant pressure of 4.09 atm.
Answer:
w₁ = 0 J
w₂ = -297 J
Explanation:
Step 1: Given data
Initial volume: 266 mL (0.266 L)
Final volume: 983 mL (0.983 L)
Step 2: Calculate the work done (in joules) by the gas if it expands against a vacuum
We will use the following expression.
w₁ = -P₁ × ΔV
Since the gas expands against a vacuum, P₁ = 0. Thus, w₁ = 0 J
Step 3: Calculate the work done (in joules) by the gas if it expands against a constant pressure of 4.09 atm
We will use the following expression.
w₂ = -P₂ × ΔV
w₂ = -4.09 atm × (0.983 L-0.266 L) = -2.93 atm.L
Then, we convert w₂ to Joule using the conversion factor 1 atm.L = 101.325 J.
-2.93 atm.L × 101.325 J/1 atm.L = -297 J
Suppose a molecule with six electron groups is confined to two dimensions and has a hexagonal planar electron geometry. A molecule with six electron groups arranged in a hexagonal planar geometry. The top and bottom groups are labeled 1 and 4, respectively. The two groups next to 1 are labeled 2 and the two groups next to 4 are labeled 3. If two of the six groups are lone pairs, where would they located?
Answer:
Above and below the plane of a square
Explanation:
The number of electron groups often determine the shape of a molecule. When we have a coordination number of six, one of the possible arrangement of groups is the hexagonal planar geometry. In this arrangement, six electron groups are arranged in the same plane.
If two among the groups are replaced by lone pairs, the substituents will arrange themselves at the corners of a square while the lone pairs will be found above and below the plane of the square. This is the square planar geometry.
The two lone pairs will be located at the top and at the bottom of the plane.
The VSEPR theory is a model that helps to predict the shape of a molecule based on the repulsions associated with the electron groups on the central atom.
Given that a hexagonal planar electron geometry possibly has 6 electron groups. The description of how the electron groups are arranged can be seen in the first image below.
If two of the six groups are lone pairs, we know that lone pairs repel each other. As such, in this arrangement, the lone pairs will occpy the opposite direction which is the top and the bottom of the plane in order to have minimum repulsion as possible.
Learn more about electronic geometry here:
https://brainly.com/question/7558603?referrer=searchResults
After 3 half lifes go by, there are 26g of Sodium-24 left. The parent sample of Sodium-24 is
grams.
NUMBERS ONLY FOR THIS ANSWER
Blank 1:
Answer:
208 grams
Explanation:
Half life is the time it takes for a sample to reduce to half it's initial concentration.
In this question, 3 half lives go by. This is given as;
Let original mass be represented by x
First Half life;
Starting mass = X
Remaining mass = X/2
Second Half life;
Starting mass = X/2
Remaining mass = (X/2) / 2 = x/4
Third Half life;
Starting mass = X/4
Remaining mass = (X/4) / 2 = X/8
Since 26g was left, it means;
X/8 = 26
X = 26 * 8 = 208 grams
PLEASE HELPPPOOOOSPO
If an element has three isotopes with known masses, what other information
is needed to find the average atomic mass of the element?
A. The number of neutrons in each isotope
B. The average mass of the isotopes
C. The atomic number of each isotope
D. The abundance percentage of each isotope
Answer: D
Explanation: Hope this helps!
An unknown element X has the following isotopes: ²⁵X (80.5% abundant) and ²⁷X (19.5% abundant). What is the average atomic mass in amu of X?
Answer:
25.39
Explanation:
Given parameters:
Abundance of X-25 = 80.5%
Abundance of X - 27 = 19.5%
Unknown:
Average atomic mass of X = ?
Solution:
The average atomic mass of X can be derived using the expression below:
Average atomic mass = (abundance x mass of X - 25) + (abundance x mass of X - 27)
Average atomic mass = (80.5% x 25) + (19.5% x 27) = 25.39
What would happen if the kinetic energy of the reactants was not enough to provide the needed activation energy
Answer:
The products would not be formed or the reaction could not be carried out.
Explanation:
Sometimes in these situations it is chosen to place a chemical compound that accelerates the reaction and increases the kinetic energy of the reactants, without altering their chemical composition, and this is called a catalyst, which can be anything from a protein to a macromolecule.
Question 3
Which organism in a food web does not get its energy from other organisms?
A. decomposer
O
B. producer
O
C. primary consumer
D. secondary consumer
O
Hi there!
[tex]\large\boxed{\text{B. Producer}}[/tex]
The only organisms in a food web that do not get energy from other organisms are producers. These are autotrophs (ex: plants or phytoplankton) that use photosynthesis to produce energy. This means that these organisms only intake water and sunlight rather than nutrients from other organisms (consumers).
help plz :) I will give brainliest
Which section of a narrative shows the protagonist deciding to solve a problem?
Climax
Exposition
Resolution
Rising action
Name some acidic and alkaline substances that you use at home
Answer: write anything given below in the diagram except for the neutral substances
Explanation:
Answer:
Alkaline
1 drain cleaner
2 oven cleaner
3 baking soda
4 drain unblocker
Acid
1 drain cleaner
2 bowl cleaner
3 house bleach
4 diluted soap
What is responsible for the unusual ecosystem of the highlands?
Answer:
volcanoes and volcanic activity
Explanation:
I had the same Question and I got that.
Answer: Volcanoes and Volcanic Activity :)
Explanation: I got the same question :D
Which of the following combinations would form an atom with no charge (neutral)
A 3 protons, 3 neutrons, 4 electrons
B. 5 protons, 5 neutrons, 4 electrons
C. 4 protons, 3 neutrons, 4 electrons
D. 5 protons, 6 neutrons, 6 electrons
Answer:
C
Explanation:
We made a bowl of jelly. What sort of change is this?
Answer:
Explanation:
It changes from a liquid to a solid. This change occurred due to the change in temperature. As the mixture cooled, the molecules condensed and the mixture formed a solid shape.Which formed the jelly.
How can u change cm to dm
26. Which statements would be expected to be true for Organesson (Og)? Select all that apply.
A It is relatively unreactive.
B. It has a high electron affinity.
C. It has a full valence shell of electrons.
D. It has the largest atomic radius of the four new elements.
E. It has the lowest effective nuclear charge of the four new elements.
The central charge is another name for the effective nuclear charge that an electron experiences.. It has the lowest effective nuclear charge of the four new elements.
What is element ?An element is a type of atoms, including the pure material made entirely of that species, that have a specific number of protons in their nuclei.
Chemical elements, in contrast to chemical compounds, cannot be reduced by any chemical process into simpler molecules. The oxidation number of the atom can be used to calculate the strength of the nuclear charge.
The metals and non-metals are the other two basic categories into which the elements may be separated. Metals are frequently bright, malleable, and carry electricity.
All living and non-living things are made up of elements, which are fundamental building blocks. They serve as the universe's center. Elements make up every particle, no matter how little or large. Our body is composed of five main components are Calcium, Carbon, Hydrogen, Oxygen, and Nitrogen
Thus, option E is correct.
To learn more about element follow the link below;
https://brainly.com/question/14347616
#SPJ2
Beth heats a pot of water to cook pasta.
What may happen as a result of adding heat?
Answer: i’m taking a test w this question rn and i think the best answer is D. When the water begins to boil, some of the water molecules will gain enough energy to change into a gas. i could def be wrong tho
If earth is 1.50 x 10^8km from the sun what is the distance in Mm?
The distance of the earth to the sun in Mm = 1.5 x 10⁵
Further explanationGiven
The distance of the earth to the sun : 1.50 x 10⁸ km
Required
The distance in Mm
Solution
In converting units we must pay attention to the conversion factor.
the conversion factor :
1 kilometer(km) = 10⁻³ megameter(Mm)
So the distance conversion :
1.5 x 10⁸ x 10⁻³ = 1.5 x 10⁵ Mm
All composites are made up of two main components, a ________ and ___________.
Answer:
Matrix and Fibre.
Explanation:
The two main components composites are made up of are matrix and fibre. The matrix is the base material while the fiber is what reinforces the material.
Critical thinking problem: The iron in hemoglobin in our red blood cells is used to bind and carry dioxygen throughout the body. Iron is one of the atoms that can form hybrid orbitals using its d-shell electrons, which allows for a greater number of sigma bonds than just four. When iron is only bound to protein, it forms five sigma bonds with one lone pair. The iron atom is pulled down below the central square plane due to one of the bonds with the hemoglobin protein. The thick lines indicate bonds pointing out of the screen, while dashed lines indicate bonds pointing into the screen, so as to suggest 3-D structure.
When iron binds to dioxygen, it now has six sigma bonds. The geometry changes, even though the hybridization orbitals do not change. The dashed lines are still present, as seen from the top-down view, but the thick lines hide them in the side-on view.
Why would the molecular geometry for iron change in this case? Would this have anything to do with the ability of hemoglobin to bind oxygen tightly?
Answer:
Search
How can we help you?
Search
Downloads
Remixer
Username
Password
Sign in
Sign in
Contents Home Bookshelves Physical & Theoretical Chemistry Supplemental Modules (Physical and Theoretical Chemistry) Electronic Structure of Atoms and Molecules Expand/collapse global location
Predicting the Hybridization of Simple Molecules
Last updatedAug 16, 2020
Predicting the Bond-Order of Oxides based Acid Radicals
Prediction of Aromatic, Anti Aromatic and Non Aromatic Character of Heterocyclic Compounds along with their Omission Behavior- Innovative Mnemonics
picture_as_pdf
Readability
Donate
Prof. Linus Pauling (1931) first developed the Hybridization state theory in order to explain the structure of molecules such as methane (CH4).1This concept was developed for simple chemical systems but this one applied more widely later on and from today’s point of view it is considered an operative empirical for excusing the structures of organic and inorganic compounds along with their related problems. An innovative method proposed for the determination of hybridization state on time economic ground 2,3,4.
Prediction of sp, sp2, sp3 Hybridization state
We Know, hybridization is nothing but the mixing of orbital’s in different ratio to form some newly synthesized orbitals called hybrid orbitals. The mixing pattern is as follows:
s + p (1:1) - sp hybrid orbital; s + p (1:2) - sp2 hybrid orbital ; s + p (1:3) - sp3 hybrid orbital
Formula used for the determination of sp, sp2 and sp3 hybridization state:
Power on the Hybridization state of the central atom = (Total no of σ bonds around each central atom -1)
All single (-) bonds are σ bond, in double bond (=) there is one σ and 1π, in triple bond (≡) there is one σ and 2π. In addition to these each lone pair (LP) and Co-ordinate bond can be treated as one σ bond subsequently.
Eg.:
a. In NH3: central atom N is surrounded by three N-H single bonds i.e. three sigma (σ) bonds and one lone pair (LP) i.e. one additional σ bond. So, in NH3 there is a total of four σ bonds [3 bond pairs (BPs) + 1 lone pair (LP)] around central atom N. Therefore, in this case power of the hybridization state of N = 4-1 = 3 i.e. hybridization state = sp3.
b. In H2O: central atom O is surrounded by two O-H single bonds i.e. two sigma (σ) bonds and two lone pairs i.e. two additional σ bonds. So, altogether in H2O there are four σ bonds (2 bond pairs + 2 lone pairs) around central atom O, So, in this case power of the hybridization state of O = 4-1 =3 i.e. hybridization state of O in H2O = sp3.
c. In H3BO3:- B has 3σ bonds (3BPs but no LPs) and oxygen has 4σ bonds (2BPs & 2LPs) so, in this case power of the hybridization state of B = 3-1 = 2 i.e. B is sp2 hybridized in H3BO3. On the other hand, power of the hybridization state of O = 4-1= 3 i.e. hybridization state of O in H3BO3 is sp3.
d. In I-Cl: I and Cl both have 4σ bonds and 3LPs, so, in this case power of the hybridization state of both I and Cl = 4 - 1 = 3 i.e. hybridization state of I and Cl both are sp3.
e. In CH2=CH2: each carbon is attached with 2 C-H single bonds (2 σ bonds) and one C=C bond (1σ bond), so, altogether there are 3 sigma bonds. So, in this case, power of the hybridization state of both C = 3-1 = 2 i.e. hybridization state of both C’s are sp2.
Prediction of sp3d, sp3d2, and sp3d3 Hybridization States
Sometimes atoms form molecules by sharing two pairs of valence electrons. When this occurs, the atoms are said to be joined by...
Answer:
A double covalent bond
Explanation:
A double covalent bond is a situation where we have two pairs of electrons shared together between the atoms instead of just one pair. Oxygen gas is an example of a simple molecule that contains double bonds.
In other words, it is a type of chemical bond that has 2 electron pairs shared between two atoms.
Explain how you know it must be oxygen. Where did the oxygen come from?
Answer:
Copper oxide is the only product, and it contains copper and oxygen.
One of the reactants is copper, so the other reactant must be oxygen.
The copper metal must have combined with something in the air.
Explanation:
classify the sentences based on the chemical reactions they describe.
Given the balanced equation 2C+ 3H2
Answer:
Explanation:
The answer is (4) 4.0 mol. This is a stoichiometry problem. You start with 2.0 mol of C2H6 and obtain the moles of C by multiplying 2.0 by the mole ratio, in this case 2. 2.0*2=4.0mol.
How much concentrated solution would you take to prepare 1.30 LL of 0.100 MM HNO3HNO3 by mixing with water
Answer:
8.2mL of the concentrated solution must be taken diluting to 1.30L with water
Explanation:
The concentrated HNO₃ comes in a presentation of 70% = 15.8M
As the concentrated solution is of 15.8M and we want to obtain a 0.100M, the dilution must be of:
15.8M / 0.100M = 158 times must be the concentrated solution diluted
As the total volume we want to prepare is 1.30L, the volume of the concentrated solution must be:
1.30L / 158 = 8.2x10⁻³L =
8.2mL of the concentrated solution must be taken diluting to 1.30L with water