The balanced chemical equation is given below,3Ba3 N2 + 6H2O → 6Ba(OH)2 + 4NH3. The values of w, x, y, and z are as follows: w = 3, x = 2, y = 6, and z = 2.
To balance the given chemical reaction w, x, y, and z values can be determined using linear algebra. For the purpose of balancing the given chemical reaction using Linear Algebra, we can write a matrix equation for the coefficients of the compounds involved in the reaction. Ax = b Here, A is the coefficient matrix, x is the unknown vector (w, x, y, z), and b is the product matrix. We need to solve this equation to get the values of w, x, y, and z. According to the given chemical reaction,
wBa3 N2 + xH2O → yBa(OH)2 + 2NH3.
The corresponding matrix equation is given below, 3w = 2y0 = x + 2zw + 2x = 2y2x = 2z.
As we can see from the above equation, the number of equations is greater than the number of unknowns, so we need to eliminate the extra equations to solve for the unknowns. To eliminate x and z, we can solve equations 2 and 4 to get z in terms of x and substitute it into equation 5, as shown below,
2x = 2z2x = 2(x + 2z)x = 4z
By substituting the value of z in equation 4, we get, x = 2zw + 2x = 2y3w = 4z = 2x = 2y
Thus, the balanced chemical equation is given below,3Ba3 N2 + 6H2O → 6Ba(OH)2 + 4NH3
Therefore, the values of w, x, y, and z are as follows: w = 3, x = 2, y = 6, and z = 2.
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what is the molarity of a saline solution that contains 0.900 g nacl
Molarity of a saline solution that contains 0.900 g NaCl is 0.015 M.
To calculate the molarity of a saline solution that contains 0.900 g NaCl, the given data should be in moles. The molarity of a solution is the amount of solute present in a solution per unit volume of solution. It is measured in moles per liter (M).
The formula to calculate the molarity is: Molarity (M) = Moles of solute / Volume of solution (in liters)Given, Mass of NaCl = 0.900 g
Molar mass of NaCl = 58.44 g/mol
Number of moles of NaCl = mass of NaCl / molar mass of NaCl= 0.900 g / 58.44 g/mol= 0.0154 molGiven, Volume of solution is not given. Hence, we assume the volume of the solution to be 1 L.
Molarity (M) = Moles of solute / Volume of solution (in liters)= 0.0154 mol / 1 L= 0.015 M
Consequently, the molarity of a saline solution that contains 0.900 g NaCl is 0.015 M.
Molarity of a saline solution that contains 0.900 g NaCl is 0.015 M. It is calculated using the formula:Molarity (M) = Moles of solute / Volume of solution (in liters)
Given data is converted into moles of solute and the volume of the solution is assumed to be 1 L.
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which of the following acids is strongest, based on the values of their acid ionization constants? benzoic acid carbonic acid sulfuric acid hydrazoic acid oxalic acid
The strongest acid among the following is sulfuric acid, based on the values of their acid ionization constants. Sulfuric acid is a diprotic acid that has two acidic hydrogen atoms, so it has two ionization constants.What is an acid ionization constant
An acid ionization constant (Ka) is a quantitative measure of the strength of an acid in a solution. A high Ka value indicates that an acid will completely ionize in a solution, whereas a low Ka value indicates that an acid will partially ionize in a solution.How can we compare the strength of different acids based on their ionization constants?The ionization constants of different acids can be compared to determine their relative strength. The higher the ionization constant, the stronger the acid. For example, if acid A has an ionization constant of 1 x 10-4 and acid B has an ionization constant of 1 x 10-6, acid A is stronger because it has a higher ionization constant.Now, let's look at the given options and their acid ionization constants:Benzoic acid: Ka = 6.4 × 10-5Carbonic acid: Ka1 = 4.2 × 10-7 and Ka2 = 4.8 × 10-11Hydrazoic acid: Ka = 1.9 × 10-5Oxalic acid: Ka1 = 5.9 × 10-2 and Ka2 = 6.4 × 10-5Sulfuric acid: Ka1 = 1.0 × 103 and Ka2 = 1.2 × 10-2Therefore, we can see that the ionization constant of sulfuric acid is the strongest, based on the values of their acid ionization constants.
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to separate a mixture of p-toluidine and p-nitrotoluene dissolved in ether,extract the ether solution with aqueous hcl and treat the water layer with aqueous naoh. true
The answer to the given question is given as follows:
given question talks about separating a mixture of p-toluidine and p-nitrotoluene dissolved in ether. To separate this mixture, we need to extract the ether solution with aqueous HCl and then treat the water layer with aqueous NaOH.
Now, we will discuss each step of this process in detail:
Step 1: Extraction of Ether Solution with Aqueous HCl
In this step, we are going to extract the ether solution with aqueous HCl. This step is carried out to convert p-nitrotoluene into p-nitrotoluene acid. The basic principle of this step is that p-toluidine is a base and p-nitrotoluene is a neutral compound. Therefore, when we add HCl, it will protonate p-toluidine, and it will form an ion that will be extracted in the aqueous phase. Whereas, p-nitrotoluene will remain in the organic phase. The resulting mixture will contain an aqueous layer and an organic layer. The organic layer is of our interest as it contains the compound that we are going to extract.
Step 2: Treatment of the Water Layer with Aqueous NaOH
In this step, we are going to treat the water layer with aqueous NaOH. This step is carried out to convert p-nitrotoluene acid into p-nitrotoluene. The basic principle of this step is that p-nitrotoluene acid is an acid, and when we add NaOH, it will react with p-nitrotoluene acid and convert it into p-nitrotoluene.
This reaction is given below:
p-nitrotoluene acid + NaOH → p-nitrotoluene + NaNO2 + H2O
This reaction takes place only in the aqueous phase as both the reactants are present in the aqueous layer. So, the resulting mixture will contain an aqueous layer and an organic layer. The organic layer is of our interest as it contains the compound that we are going to extract.
Step 3: Final Extraction of Organic Layer
In this step, we are going to extract the organic layer from the mixture. The organic layer contains the compound that we are going to extract. So, we can evaporate the solvent, and we will get the desired compound that is p-nitrotoluene. Hence, the final product of this process will be p-nitrotoluene.
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Which of the following contains a delocalized π bond? Check all that apply. □ H2O □ HCN HCN cos □ CO32- 2
The species that contain a delocalized π bond are:
- CO₃²⁻ (carbonate ion)
- O₃ (ozone)
- HCN
To identify which species contain a delocalized π bond, let's analyze each option:
- CO₃²⁻ (carbonate ion): The carbonate ion does contain a delocalized π bond. It exhibits resonance, with the double bond alternating between the carbon and oxygen atoms. This results in the delocalization of π electrons over the entire ion.
- H₂O (water): H₂O does not contain a delocalized π bond. It consists of two polar covalent O-H bonds and the electrons in these bonds are localized between the oxygen and hydrogen atoms.
- O₃ (ozone): O₃ contains a delocalized π bond. It has a resonance structure in which the double bond moves between the three oxygen atoms. This results in the delocalization of π electrons over the three oxygen atoms.
- HCN: HCN does contain a delocalized π bond. The molecule consists of a triple bond between carbon (C) and nitrogen (N), with the π electrons being shared and delocalized between the two atoms.
The correct question is:
Which of the species contains a delocalized π bond?
- CO₃²⁻
- H₂O
- O₃
- HCN
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calculate the percent yield that you obtained from your alkene bromination
When alkene is treated with a halogen, a halogenated alkane is formed. In this process, a pi bond is broken and two new sigma bonds are formed. Bromination of alkenes is one of the most widely used methods for the synthesis of alkyl halides.
To calculate the percent yield that you obtained from your alkene bromination, use the following formula:% Yield = Actual Yield / Theoretical Yield x 100When carrying out chemical reactions in the laboratory, it is frequently difficult to attain the theoretical yield. The yield that is actually achieved is referred to as the actual yield. By comparing the actual yield to the theoretical yield, the percentage yield can be calculated. When conducting a bromination reaction, the percent yield can be calculated by dividing the actual yield by the theoretical yield. The theoretical yield is the quantity of product that would be obtained if the reaction were to go to completion with no loss of reagents or product.Bromination reactions are typically performed in anhydrous conditions using an inert solvent such as carbon tetrachloride. With the addition of bromine to an alkene, bromonium ions are formed. Nucleophiles such as halides will react with the bromonium ion, resulting in the formation of an alkyl halide and regenerating the catalyst.
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name the following compounds. do not use italics or boldface. nch2ch2ch3
the name of the compound "nch2ch2ch3" is "propane".
The compound "nch2ch2ch3" can be named as follows:
nch2ch2ch3 is a linear alkane with three carbon atoms. It is named using the prefix "prop" to indicate three carbons and the suffix "-ane" to represent a single bond between the carbon atoms.
what is compound?
A compound is a substance composed of two or more different elements chemically combined in fixed proportions. In other words, it is a substance made up of atoms of different elements that are bonded together in specific ratios. Compounds have unique properties and characteristics distinct from their constituent elements.
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there's a liquid that was 20% sugar, how much of that liquid would
i have to add to a 120ml bottle of liquid to make the bottle 3%
sugar?
Answer:Therefore, you would need to add approximately 21.18 mL of the 20% sugar liquid to the 120 mL bottle of liquid to make the final mixture 3% sugar.
Explanation:
To determine how much of the 20% sugar liquid you would need to add to a 120 mL bottle of liquid to make it 3% sugar, we can set up an equation based on the amount of sugar in the initial and final mixtures.
Let's denote:
x = the volume of the 20% sugar liquid to be added (in mL)
In the initial mixture, the sugar content is 20% of x mL, which is equal to 0.2x mL of sugar.
In the final mixture, the total volume is 120 mL + x mL, and the sugar content is 3% of the total volume, which is 0.03 times the total volume in mL.
We can now set up the equation:
0.2x = 0.03(120 + x)
Simplifying the equation:
0.2x = 3.6 + 0.03x
0.2x - 0.03x = 3.6
0.17x = 3.6
Dividing both sides by 0.17:
x = 3.6 / 0.17
x ≈ 21.18 mL
You would need to add approximately 21.18 mL of the 20% sugar liquid to the 120 mL bottle of liquid to make the final mixture 3% sugar.
To determine how much of the 20% sugar liquid you would need to add to a 120 mL bottle of liquid to make it 3% sugar, we can set up an equation based on the amount of sugar in the initial and final mixtures.
Let's denote:
x = the volume of the 20% sugar liquid to be added (in mL)
In the initial mixture, the sugar content is 20% of x mL, which is equal to 0.2x mL of sugar.
In the final mixture, the total volume is 120 mL + x mL, and the sugar content is 3% of the total volume, which is 0.03 times the total volume in mL.
We can now set up the equation:
0.2x = 0.03(120 + x)
Simplifying the equation:
0.2x = 3.6 + 0.03x
0.2x - 0.03x = 3.6
0.17x = 3.6
Dividing both sides by 0.17:
x = 3.6 / 0.17
x ≈ 21.18 mL
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how many millimoles of ca(no3)2 contain 4.78 × 1022 formula units of ca(no3)2?
4.78 × 10²² formula units of Ca(NO₃)₂ contain 79.5 millimoles of Ca(NO₃)₂.
To find out how many millimoles of Ca(NO₃)₂ contain 4.78 × 10²² formula units of Ca(NO₃)₂, we must first understand that a mole is a unit that measures the amount of a substance.
A mole is equal to the number of particles in 12 grams of carbon-12.
The number of particles in one mole is 6.02 × 10²³, which is known as Avogadro's number.
So, in order to calculate the millimoles of Ca(NO₃)₂ from the given number of formula units, we need to follow these steps:
1. Find the molar mass of Ca(NO₃)₂.
Calculation of molar mass:
Molar mass of Ca(NO₃)₂ = (40.08 g/mol) + (2 × 14.01 g/mol) + (6 × 16.00 g/mol)
= 164.09 g/mol
2. Calculate the number of moles using the formula below:
Number of moles = Number of formula units ÷ Avogadro's numberNumber of moles
= 4.78 × 1022 ÷ 6.02 × 10²³
= 0.0795 moles
3. Calculate the millimoles using the formula below:
Millimoles = Number of moles × 1000Millimoles
= 0.0795 moles × 1000
= 79.5 millimoles
Therefore, 4.78 × 10²² formula units of Ca(NO₃)₂ contain 79.5 millimoles of Ca(NO₃)₂.
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what is the ph of a 0.236 m solution of ammonia (kb 1.8 x 10-5)?
The pH of a 0.236 M solution of ammonia (Kb 1.8 x 10⁻⁵) is 2.44. Note that this is an acidic pH, because ammonia is a weak base that reacts with water to form a small amount of hydroxide ions and a large amount of ammonium ions, which act as an acid.
To find the pH of a 0.236 M solution of ammonia (Kb 1.8 x 10-5), you will need to use the Kb expression and the relationship between the Kb and the Ka to calculate the concentration of hydroxide ions in solution. Then, you can use the concentration of hydroxide ions to find the pH of the solution, using the following relationship:
pH = -log[OH-] , Now, let's break down the steps to find the pH of a 0.236 M solution of ammonia (Kb 1.8 x 10⁻⁵) in more detail:
Step 1: Write the chemical equation and the Kb expression for ammonia: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻ Kb = [NH₄⁺][OH⁻]/[NH₃]
Step 2: Write the Kb expression in terms of the concentration of ammonia: Kb = [NH₄⁺][OH⁻]/([NH₃] - [NH₄⁺])Since ammonia is a weak base, we can assume that its dissociation in water is negligible, so:[NH₃] ≈ [NH₃]i = 0.236 M, where [NH₃]i is the initial concentration of ammonia.
Step 3: Calculate the concentration of hydroxide ions using the Kb expression and the relationship between the Kb and the Ka: Kb = Kw/Ka Kw = [H⁺][OH⁻] = 1.0 x 10⁻¹⁴
Ka = Kw/Kb
Ka = (1.0 x 10⁻¹⁴)/(1.8 x 10⁻⁵)
Ka = 5.56 x 10⁻¹⁰[OH⁻] = s√(Kb[NH₃]i) / √(Ka + Kb) [OH⁻] = √((1.8 x 10⁻⁵) x (0.236)) / √((5.56 x 10⁻¹⁰) + (1.8 x 10⁻⁵))[OH⁻] = 0.00366 M
Step 4: Calculate the pH of the solution using the concentration of hydroxide ions: pH = -log[OH⁻]pH = -log(0.00366)pH = 2.44
Therefore, the pH of a 0.236 M solution of ammonia (Kb 1.8 x 10⁻⁵) is 2.44. Note that this is an acidic pH, because ammonia is a weak base that reacts with water to form a small amount of hydroxide ions and a large amount of ammonium ions, which act as an acid.
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a gas with a mass of 36.3g occupies 2.92l at 25 degrees celsius and 1.54 atm pressure. what is the molar mass of the gas?
The molar mass of the gas is approximately 184.3 g/mol.
To find the molar mass of the gas, we can use the ideal gas law equation: PV = nRT. Where: P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
First, we need to convert the given temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15. T = 25°C + 273.15 = 298.15 K. Next, let's rearrange the ideal gas law equation to solve for the number of moles: n = PV / RT Plugging in the values:
P = 1.54 atm
V = 2.92 L
R = 0.0821 L·atm/(mol·K)
T = 298.15 K
n = (1.54 atm * 2.92 L) / (0.0821 L·atm/(mol·K) * 298.15 K)
Calculating the expression: n = 0.197 mol. Now, we can find the molar mass (M) of the gas by dividing the mass (m) by the number of moles (n):
M = m / n M = 36.3 g / 0.197 mol Calculating the expression: M ≈ 184.3 g/mol Therefore, the molar mass of the gas is approximately 184.3 g/mol.
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calculate [h3o+] in the following aqueous solution at 25 ∘c: [oh−]= 1.3×10−9 m .
The concentration of [H₃O⁺] in the aqueous solution is 1.3 × 10⁵ mol/L.
The equation for the ion product constant of water is:
Kw=[H⁺][OH⁻]
Kw=[H⁺][OH⁻]
The ion product constant of water is 1.0 × 10⁻¹⁴ at 25 degrees Celsius.
For every 1.0 × 10⁻¹⁴ mol/L of hydroxide ions in a solution, there are 1.0 × 10⁻¹⁴ mol/L of hydrogen ions (hydronium ions).
The ion product constant of water at 25 degrees Celsius is given by:
Kw=[H⁺][OH⁻]=1.0×10⁻¹⁴
Kw=[H⁺][OH⁻]=1.0×10⁻¹⁴
So,
[H⁺][OH⁻] = 1.0 × 10⁻¹⁴
[H⁺] = [OH⁻] / Kw
[H⁺] = 1.3 × 10⁻⁹ / 1.0 × 10⁻¹⁴
[H⁺] = 1.3 × 10⁵ mol/L
[H₃O⁺] = 1.3 × 10⁵ mol/L
Therefore, the concentration of H3O+ in the aqueous solution is 1.3 × 10⁵ mol/L.
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what is the ratio of the radius of the aluminum sphere to the radius of the zinc sphere? the density of alumnum is 2700 kg/m3kg/m3 and the density of zinc is 7130 kg/m3kg/m3 .
As per the given question The ratio of the radius of the aluminum sphere to the radius of the zinc sphere is (7130/2700)(1/3), which is approximately 1.36.
To find the ratio of the radius of the aluminum sphere to the radius of the zinc sphere, we can use the formula for the volume of a sphere (V = 4/3r3) and the densities of both materials.
Step 1: Set up an equation using the densities.
Density_aluminum * Volume_aluminum = Density_zinc * Volume_zinc
Step 2: Substitute the volume formula (V = 4/3r3) into the equation.
2700 * (4/3πr_aluminum³) = 7130 * (4/3πr_zinc³)
Step 3: Simplify the equation by dividing both sides by (4/3).
2700 * r_aluminum³ = 7130 * r_zinc³
Step 4: Divide both sides by the density of aluminum (2700).
r_aluminum³ = (7130/2700) * r_zinc³
Step 5: Take the cube root of both sides to isolate the radii.
r_aluminum = (7130/2700)^(1/3) * r_zinc
The ratio of the radius of the aluminum sphere to the radius of the zinc sphere is (7130/2700)(1/3), which is approximately 1.36.
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if the bonding in [mno4]- is 100% ionic, what would the charges on the mn and o atoms
If the bonding in [MnO₄]⁻ is 100% ionic, then the charges on the Mn and O atoms are +7 and -2 respectively. To determine the charges on Mn and O in MnO₄⁻, we need to determine the oxidation state of each atom.
To do that, we need to use the oxidation state of oxygen, which is -2 in almost all compounds except for peroxides (H₂O₂) and superoxide (KO₂, RbO₂, CsO₂) and a few others.
Now, let's assume the oxidation state of Mn is x. The total oxidation state of MnO₄⁻ is -1, so we can write: x + 4(-2) = -1x - 8 = -1x = +7
This means the oxidation state of Mn in MnO₄⁻ is +7, or Mn(VII). Now that we know the oxidation state of Mn, we can find the oxidation state of each O atom: Oxygen has an oxidation state of -2, so 4 O atoms will have a combined oxidation state of -8 (-2 x 4 = -8).We know the total oxidation state of MnO₄⁻ is -1, so we can write:+7 + (-8) = -1
This means that the total oxidation state of MnO₄⁻ is -1. Now we can find the oxidation state of the last O atom:+7 + (-2) x 3 + x = -1x - 5 = -1x = +4 . The oxidation state of the last O atom is +4, or O(IV).
Therefore, if the bonding in MnO₄⁻ is 100% ionic, the charges on the Mn and O atoms are +7 and -2 respectively.
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the energy-level diagram for an atom that has four energy states is shown. what is the number of different wavelengths in the emission spectrum of this atom?
The number of different wavelengths in the emission spectrum of this atom is three wavelengths.
The given diagram shows the energy level diagram of the four energy states of an atom. In the given diagram, the electron in the ground state makes a transition from the n = 2 energy level to the n = 4 energy level.As the electron makes a transition from the n = 4 energy level to the n = 2 energy level, the energy of the electron is emitted in the form of radiation.
The energy of the emitted radiation depends on the difference between the initial energy level and the final energy level. The energy of the emitted radiation is given by the following equation:
ΔE = Ei - Ef where, ΔE is the energy of the emitted radiation, Ei is the initial energy level, and Ef is the final energy level.
The emitted radiation has a specific wavelength, which is given by the following equation:λ = hc/ΔEwhere, λ is the wavelength of the radiation, h is the Planck's constant, c is the speed of light, and ΔE is the energy of the radiation. As we see from the given diagram, the electron makes three different transitions as follows:
From n = 4 to n = 2From n = 3 to n = 2From n = 4 to n = 3
Hence, there will be three different wavelengths in the emission spectrum of this atom.
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Place the following in order of increasing magnitude of lattice energy. Cao Mgo Srs Srs < MgO < Cao CaO < Mgo < Srs Srs < CaO < MgO CaO < Srs < Mgo O MgO < Call < Srs
Lattice energy refers to the energy released when ions join together to form a solid compound. The amount of lattice energy produced determines the strength of the ionic bond.
The greater the lattice energy, the stronger the bond, and the harder it will be to separate the atoms. Lattice energy can be influenced by many factors, including the charge on the ions, the size of the ions, and the arrangement of the ions.
The order of increasing magnitude of lattice energy is CaO < MgO < SrS.
The reason for this order can be explained by considering the size and charge of the ions. The smaller the ions, the closer they can be packed together, and the greater the lattice energy. Similarly, the greater the charge on the ions, the stronger the attraction between them, and the greater the lattice energy.
Calcium oxide (CaO) has the smallest ions, which are also the most highly charged (+2 and -2), so it has the highest lattice energy. Magnesium oxide (MgO) has slightly larger ions, but they are still highly charged (+2 and -2), so it has the second-highest lattice energy. Strontium sulfide (SrS) has the largest ions, and they are also the least highly charged (+2 and -2), so it has the lowest lattice energy.
Therefore, the correct order of increasing magnitude of lattice energy is CaO < MgO < SrS.
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what is the strongest interparticle force in a sample of nah2po4 solid ? select the single best answer.
The strongest interparticle force is ionic bonding forces.
What is the interparticle force?
Sodium cations (Na+) and dihydrogen phosphate anions (H2PO4-) make up the ionic compound NaH2PO4. Electrostatic attraction between positively charged cations and negatively charged anions is what creates ionic bonds.
The Na+ and H2PO4- ions organize themselves into a regular lattice structure in the solid state, which is kept together by powerful electrostatic forces. These ionic bonds are frequently more powerful than other interparticle forces like hydrogen bonding, dipole-dipole forces, and dispersion forces.
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Missing parts;
What is the strongest interparticle force in a sample of solid NaH2PO4 ? Select the single best answer. dipole-induced dipole forces dispersion forces dipole-dipole forces ion-induced dipole forces hydrogen bonding forces ionic bonding forces ion-dipole forces
Write the electron configuration for an argon cation with a charge of +1. II 님 An atomic cation with a charge of +1 has the following electron configuration: 1522-2p 5 What is the chemical symbol for the ion? I O How many electrons does the ion have? Х 5 ? How many 2p electrons are in the ion? I
The number of 2p electrons in the ion can be found from the electron configuration of the ion which is 1s²2s²2p⁶3s²3p⁵. There are 3 electrons in the 2p subshell of the ion. Therefore, the ion has 3 2p electrons.
An atomic cation with a charge of +1 means it has lost one electron from the outermost shell. Argon is a noble gas and has the electron configuration of 1s²2s²2p⁶3s²3p⁶. Argon has eight electrons in its outermost shell. When argon loses one electron, it becomes Ar⁺1. The electron configuration for argon cation with a charge of +1 is 1s²2s²2p⁶3s²3p⁵. The chemical symbol for the ion is Ar⁺.
The number of electrons that the ion has can be calculated by taking the atomic number of argon (18) and subtracting the charge (+1). Thus, the ion has 17 electrons. The number of 2p electrons in the ion can be found from the electron configuration of the ion which is 1s²2s²2p⁶3s²3p⁵.
There are 3 electrons in the 2p subshell of the ion. Therefore, the ion has 3 2p electrons.
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agc2h3o2(aq) bai2(aq)→ express your answer as a chemical equation. identify all of the phases in your answer. enter noreaction if there is no reaction.
The given equation is: `AgC2H3O2(aq) + BaI2(aq) →`The chemical equation for the above given reaction is written below:`AgC2H3O2(aq) + BaI2(aq) → AgI(s) + Ba(C2H3O2)2(aq)`The above reaction is a double displacement reaction in which silver acetate and barium iodide react to form silver iodide and barium acetate.
AgI(s) + Ba(C2H3O2)2(aq) = AgC2H3O2(aq) + BaI2(aq)
Aqueous solutions of silver acetate (AgC2H3O2) and barium iodide (BaI2) react in this twofold displacement reaction. Barium acetate (Ba(C2H3O2)2) in aqueous solution and silver iodide (AgI) as a solid precipitate are the products of the reaction.
The phases in the equation are represented by the letters (aq) for an aqueous solution and (s) for a solid.
The balanced chemical equation with phases is as follows:
AgI(s) + Ba(C2H3O2)2(aq) = AgC2H3O2(aq) + BaI2(aq)
This equation is a precise representation of the reaction that produces silver iodide and barium acetate from the reaction of silver acetate and barium iodide.
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The chemical equation for the reaction of agc2h3o2(aq) bai2(aq) is given below:AgC2H3O2(aq) + BaI2(aq) → AgI(s) + Ba(C2H3O2)2(aq). Phases:AgC2H3O2(aq) - aqueousBaI2(aq) - aqueousAgI(s) - solidBa(C2H3O2)2(aq) - aqueous.
Note that in this equation, the Ag ion from AgC2H3O2 and the I ion from BaI2 are exchanged to form AgI (silver iodide), a solid.
Similarly, Ba ion from BaI2 combines with the C2H3O2 ion from AgC2H3O2 to form Ba(C2H3O2)2(aq), a water-soluble salt. The state symbols, which are mentioned inside the parentheses, help in understanding the state of each reactant and product.The above reaction is an example of a double replacement or double displacement reaction in which two compounds swap ions or groups of ions with each other. However, if any reactant remains as such, then it's not a chemical reaction, but a physical process. Hence, if there is no reaction, then we would write 'no reaction' as the answer.
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Among the following groups, which is the correct order of priorities in the R, S system? (1) -CH2CH2CI () -CH2CH2CH2Br (ili) -CH2OH (iv) -CF3 a. (ii) > (1) > (iii) > (iv) b. (1) > (iii) > (ii) > (iv) c. (iv) > (iii) > (1) > (ii) d. (iii) > (iv) > (ii) > (i)
The correct order of priorities in the R, S system is (iii) > (iv) > (ii) > (i).
:The R/S system is a way of specifying the absolute configuration of a chiral molecule. The priority of the group connected to the chiral carbon determines the R/S system.
The four groups on the chiral center are ranked by their atomic numbers.
The order of priorities for the given groups is as follows: (iii) > (iv) > (ii) > (i)So, the correct order of priorities in the R, S system is (iii) > (iv) > (ii) > (i).The answer is (d).
Summary:The order of priorities for the given groups is (iii) > (iv) > (ii) > (i). Thus, the correct order of priorities in the R, S system is (iii) > (iv) > (ii) > (i).
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which of the following gas samples would be most likely to behave ideally under the stated condition? A) H2 at 400atm and 25 C degree, b) CO at 200atm and 25 C degree, c) Ar at STP, d) N2 at atm and -70 C degree, e) SO2 at 2 atm and 0 K. Please, answer with detail explain.
In chemistry, the ideal gas law is a simple equation that specifies how the physical properties of an ideal gas change as pressure, volume, and temperature are changed. It can be utilized to assess the behavior of a gas under various conditions.
Given conditions in the question, the Ar gas sample at STP (Standard Temperature and Pressure) is most likely to behave ideally. The reason behind this statement is explained below: STP (Standard Temperature and Pressure) is defined as 273 K (0°C) and 1 atm of pressure.
According to the ideal gas law, a gas will act ideally under the given condition if the intermolecular forces between the gas particles are negligible. Intermolecular forces are defined as the forces of attraction between two or more particles. The Ar gas is a noble gas, and as such, it has weak intermolecular forces. The weak intermolecular forces between the Ar gas particles make it an ideal gas under STP conditions. Additionally, Ar gas consists of a single atom and has a zero molecular weight. Hence, it has no volume, which makes it an ideal gas under STP conditions.
Therefore, the Ar gas sample at STP is most likely to behave ideally under the stated condition. The other options, H2 at 400atm and 25 C degree, CO at 200atm and 25 C degree, N2 at atm and -70 C degree, and SO2 at 2 atm and 0 K, have various pressures and temperatures that deviate from the standard conditions, and they may have strong intermolecular forces that make them non-ideal gases.
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burning of 15.5 g of propane: c3h8(g)+5o2(g)→3co2(g)+4h2o(l) δh∘=−2220 kj
The enthalpy change of combustion of 15.5 g of propane is -778 kJ.
Propane, C3H8, reacts with oxygen, O2, to form carbon dioxide, CO2, and water, H2O. The enthalpy change of combustion, ΔHcomb, is the energy change when one mole of a substance is completely burnt in excess oxygen under standard conditions. To calculate the enthalpy change of combustion of propane, we first need to write a balanced equation for the reaction. The balanced equation is given as:C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)We are given that ΔH∘comb = -2220 kJ for the combustion of propane. This means that the combustion of one mole of propane releases 2220 kJ of energy. We can use this information to calculate the enthalpy change of combustion of 15.5 g of propane.To calculate the enthalpy change of combustion of 15.5 g of propane, we first need to calculate the number of moles of propane in 15.5 g. The molar mass of propane is:Mr = (3 x 12.01 g/mol) + (8 x 1.01 g/mol)Mr = 44.1 g/molThe number of moles of propane in 15.5 g is:n = m/Mrn = 15.5 g / 44.1 g/moln = 0.351 molNow, we can use the enthalpy change of combustion per mole of propane to calculate the enthalpy change of combustion of 0.351 mol of propane.ΔHcomb = n x ΔH∘combΔHcomb = (0.351 mol) x (-2220 kJ/mol)ΔHcomb = -778 kJ
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Burning 15.5 g of propane releases approximately 778.02 kJ of heat.
The balanced equation for the burning of 15.5 g of propane (C₃H₈) is:
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)
To calculate the heat released during the burning of 15.5 g of propane, we need to use the molar mass of propane and convert it to moles.
The molar mass of propane (C₃H₈) is:
C: 12.01 g/mol
H: 1.01 g/mol
Molar mass of C₃H₈ = 3(12.01 g/mol) + 8(1.01 g/mol) = 44.11 g/mol
Next, we calculate the number of moles of propane burned:
moles of C₃H₈ = mass / molar mass = 15.5 g / 44.11 g/mol ≈ 0.351 mol
Now we can calculate the heat released using the molar ratio and the ΔH° value:
ΔH = ΔH° x moles of propane
ΔH = -2220 kJ x 0.351 mol ≈ -778.02 kJ
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the hydrides of group 5a are nh3, ph3, ash3, and sbh3. arrange them from highest to lowest intermolecular forces.
The order of intermolecular forces in the hydrides of group 5A is NH3 > PH3 > AsH3 > SbH3.
This is because the intermolecular forces are inversely proportional to the size of the molecules.
:Intermolecular forces are the forces of attraction and repulsion that exist between molecules. These forces can be classified into four categories:London dispersion forces, dipole-dipole forces, hydrogen bonding, and ion-dipole forces. The strength of these forces increases as the size of the molecule increases.Therefore, the order of intermolecular forces in the hydrides of group 5A is NH3 > PH3 > AsH3 > SbH3.
This is because the size of the molecules decreases as you move from NH3 to SbH3. NH3 has the highest intermolecular forces because it is the largest molecule, while SbH3 has the lowest intermolecular forces because it is the smallest molecule.
Summary: The hydrides of group 5A are NH3, PH3, AsH3, and SbH3. The order of intermolecular forces in these molecules is NH3 > PH3 > AsH3 > SbH3. This is because the intermolecular forces are inversely proportional to the size of the molecules.
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how many moles of gas would you have if you had a volume of 38.0l under a pressure of 1432 mmhg at standard temperature?
Approximately 0.988 moles of gas in a volume of 38.0 L under a pressure of 1432 mmHg at standard temperature.
To determine the number of moles of gas, we can use the ideal gas law equation: PV = nRT.
Where: P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
First, let's convert the given pressure from mmHg to atm: 1 atm = 760 mmHg 1432 mmHg * (1 atm / 760 mmHg) = 1.88421 atm. Next, we need to convert the given volume from liters to moles. Since we know the pressure, volume, and temperature, we can rearrange the ideal gas law equation to solve for the number of moles: n = PV / RT
Plugging in the values:
P = 1.88421 atm
V = 38.0 L
R = 0.0821 L·atm/(mol·K)
T = 273.15 K (standard temperature)
n = (1.88421 atm * 38.0 L) / (0.0821 L·atm/(mol·K) * 273.15 K). Calculating the expression: n = 0.988 mol. Therefore, you would have approximately 0.988 moles of gas in a volume of 38.0 L under a pressure of 1432 mmHg at standard temperature.
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a precipitate forms when mixing solutions of sodium fluoride (naf) and lead ii nitrate (pb(no3)2). complete and balance the net ionic equation for this reaction by filling in the blanks.
The balanced net ionic equation for the reaction between NaF and Pb(NO3)2 is Pb2+ (aq) + 2F- (aq) → PbF2 (s).
The balanced net ionic equation for the precipitation reaction when mixing solutions of sodium fluoride (NaF) and lead(II) nitrate (Pb(NO3)2) can be written as follows: Pb2+ (aq) + 2F- (aq) → PbF2 (s)The balanced chemical equation of the precipitation reaction is shown below: Pb(NO3)2 (aq) + 2NaF (aq) → PbF2 (s) + 2NaNO3 (aq)
Explanation: A precipitation reaction is a reaction in which an insoluble substance (precipitate) forms and separates from a solution. In the given reaction, when a solution of sodium fluoride (NaF) is added to a solution of lead(II) nitrate (Pb(NO3)2), a white precipitate of lead fluoride (PbF2) is formed. The net ionic equation shows only the ions that are involved in the reaction. In the above reaction, both NaNO3 and PbF2 are soluble in water. Therefore, they will dissociate into their constituent ions in water, and they will not participate in the reaction. Only the ions that are involved in the reaction are written in the net ionic equation. In this case, the lead ion (Pb2+) and the fluoride ion (F-) combine to form the insoluble precipitate, lead fluoride (PbF2). Thus, the balanced net ionic equation for the reaction between NaF and Pb(NO3)2 is Pb2+ (aq) + 2F- (aq) → PbF2 (s).
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identify the spectator ion(s) in the equation cacl2(aq) + na2co3(aq) → caco3(s) + 2nacl(aq).
The spectator ions in the given equation are Cl- and Na+.
A spectator ion is an ion that exists in a solution but does not participate in a chemical reaction.
In the given equation CaCl2(aq) + Na2CO3(aq) → CaCO3(s) + 2NaCl(aq), the spectator ions can be identified by writing the complete ionic equation.
The complete ionic equation shows all of the ions in a reaction.
CaCl2(aq) + Na2CO3(aq) → CaCO3(s) + 2NaCl(aq)
Complete ionic equation:
Ca2+(aq) + 2Cl-(aq) + 2Na+(aq) + CO32-(aq) → CaCO3(s) + 2Na+(aq) + 2Cl-(aq)
As per the above equation, Ca2+ and CO32- ions combine to form a solid precipitate of CaCO3. Na+ and Cl- ions are present on both sides of the equation, which means they don't participate in the reaction and remain in the solution. So, Na+ and Cl- are spectator ions in the given equation.
The ionic bond between Ca2+ and CO32- forms the solid CaCO3 and, as a result, the Na+ and Cl- ions remain in solution.
They exist as ions in both the reactant and product side of the equation but do not participate in the chemical reaction.
Instead, they remain in solution as the ionic bond between Ca2+ and CO32- forms solid CaCO3.
Therefore, the spectator ions in the given equation are Cl- and Na+.
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what is δh∘rxn for the following chemical reaction? co2(g)+2koh(s)→h2o(g)+k2co3(s)
The enthalpy change (ΔHrxn∘) of the given reaction is -1361.9 kJ/mol.
The given chemical reaction is: CO₂ (g) + 2 KOH (s) → H₂O (g) + K₂CO₃ (s)
To determine the enthalpy change of the given reaction, we need to find the difference between the products' enthalpy and the reactants' enthalpy. We use the standard enthalpy of formation, which is the energy change that occurs when one mole of a compound is formed from its elements in their standard states.
Using the following values given in the table: ΔHf∘CO₂ (g) = -393.5 kJ/mol, ΔHf∘H₂O (g) = -241.8 kJ/mol, ΔHf∘KOH (s) = -424.5 kJ/mol, and ΔHf∘K₂CO₃ (s) = -1151.2 kJ/mol.
Using the equation below:
ΔHrxn∘=∑nΔHf∘products−∑mΔHf∘reactants
We find the enthalpy change of the reaction to be:
ΔHrxn∘= -1151.2 kJ/mol - (-424.5 kJ/mol) - [(-241.8 kJ/mol) + (-393.5 kJ/mol)]
ΔHrxn∘= -1151.2 kJ/mol + 424.5 kJ/mol - 635.3 kJ/mol
ΔHrxn∘= -1361.9 kJ/mol
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Calculate the energy levels of the pi-network in octatetraene, C8H10, using the particle in the box model. To calculate the box length, assume that the molecule is linear and use the values 135 and 154pm for C--C and C-C bonds. What is the wavelength of light required to induce a transition from the ground state to the first excited state?
The wavelength of light required to induce a transition from the ground state to the first excited state is 2004 pm.
To calculate the energy levels of the pi-network in octatetraene using the particle in the box model, we need to determine the box length. Since the molecule is linear, we can calculate the box length by summing the bond lengths.
Octatetraene (C8H10) has four carbon-carbon (C-C) bonds. Given that the C--C bond length is 135 pm and the C-C bond length is 154 pm, the total box length is:
Box length = 4 * C--C bond length + 3 * C-C bond length
= (4 * 135 pm) + (3 * 154 pm)
= 540 pm + 462 pm
= 1002 pm
Next, we can use the equation for the wavelength of light associated with a transition between energy levels:
Wavelength = 2 * Box length / n
Where n is the energy level.
For the transition from the ground state (n = 1) to the first excited state (n = 2), the wavelength of light required can be calculated as:
Wavelength = 2 * 1002 pm / (2 - 1)
= 2 * 1002 pm
= 2004 pm
Therefore, the wavelength of light required to induce a transition from the ground state to the first excited state is 2004 pm.
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using equation 1, find the relative humidity. water vapor content = 10 g/kg saturation mixing ratio = 20 g/kg
The air is 50% saturated with water vapour, leading to a relative humidity of 50%.
To find the relative humidity using Equation 1, we need the values for water vapour content and saturation mixing ratio.
Equation 1: Relative Humidity = (Water Vapor Content / Saturation Mixing Ratio) * 100%
Given:
Water Vapor Content = 10 g/kg
Saturation Mixing Ratio = 20 g/kg
Using these values in Equation 1:
Relative Humidity = (10 g/kg / 20 g/kg) * 100%
= 0.5 * 100%
= 50%
Therefore, the relative humidity is 50%.
Relative humidity is a measure of how saturated the air is with water vapour compared to its maximum capacity at a given temperature. In this case, the air contains 10 grams of water vapour per kilogram of air, while the saturation mixing ratio indicates that it could hold up to 20 grams of water vapour per kilogram of air.
Therefore, the air is 50% saturated with water vapour, leading to a relative humidity of 50%.
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What products are formed when benzene is treated with each alkyl chloride and AICI,?
When benzene is treated with an alkyl chloride and AlCl3 (aluminum chloride), the reaction is called Friedel-Crafts alkylation. The products formed in this reaction are alkylbenzenes. Here's a step-by-step explanation:
1. AlCl3 acts as a Lewis acid, accepting a chloride ion (Cl-) from the alkyl chloride, forming an alkyl cation.
2. The benzene ring, with its electron-rich double bonds, acts as a nucleophile and attacks the positively charged alkyl cation.
3. A bond is formed between the alkyl group and the benzene ring, replacing one of the hydrogen atoms on the benzene.
4. The hydrogen atom that was replaced forms a bond with the AlCl4- ion, regenerating the AlCl3 catalyst and producing HCl as a byproduct.
In summary, when benzene is treated with an alkyl chloride and AlCl3, alkylbenzenes are formed through the Friedel-Crafts alkylation reaction.
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which of the following are weak electrolytes? hno3 hf nh3 libr
The weak electrolytes from the given options are HF and NH3.
What are electrolytes?
An electrolyte is a chemical compound that conducts electricity by moving ions when dissolved in water or melted. They play an essential role in a variety of chemical reactions that are important in daily life, from the breakdown of food in our bodies to the decomposition of ore into metals.Electrolytes are classified into two types, weak electrolytes and strong electrolytes. Strong electrolytes are those that dissociate completely in water, while weak electrolytes are those that dissociate partially, which means that they only release a few ions in solution. Furthermore, the degree of dissociation varies depending on the strength of the electrolyte's bond.What are weak electrolytes?
A weak electrolyte is a compound that conducts electricity only partially when dissolved in water. They conduct electricity in solution by the movement of a small number of ions. For example, acetic acid is a weak electrolyte that breaks down partially into hydrogen ions (H+) and acetate ions (CH3COO-) in water.When the given options are considered, HNO3 and LiBr are strong electrolytes because they are completely ionized in water.
While HF and NH3 are weak electrolytes because they are not completely ionized in water, meaning they only ionize partially in water.
The dissociation reactions of HF and NH3 in water are given below;
HF + H2O ⇌ H3O+ + F-NH3 + H2O ⇌ NH4+ + OH-
Thus, the weak electrolytes from the given options are HF and NH3.
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