list and explain the three classes of enzymes​

Answer:

right answer is

B

Kinetic energy

[tex]answer \\ = deletion \: and \: insertion \\ explanation \\ insertion \: and \: deletion \: results \: in \: a \: \\ frame \: shift \: that \: changes \: the \: \\ reading \: of \: subsequent \: codons \: and \: \\ therefore \: alters \: the \: entire \: amino \: \\ acid \: sequence \: that \: follows \: the \: \\ mutation ,insertion \: and \: deletions \: \\ are \: usually \: more \: harmful \: than \\ a \: substitution \: in \: which \: a \: single \\ amino \: acid \: is \: altered. \\ hope \: it \: helps[/tex]

Answer:

C) nitrogenous bases

I think its C since the rest are types of molecules bigger than DNA

Substitution:

Substitution is the switch of codons. A C could be switched to an A, but the original is now substituted for the new codon. This can change the amino acid present or it can be a silent mutation. If the stop codon is switched in, the protein will be cut short and the effects could be very serious.

Insertion:

Insertion is where base pairs are inserted into the DNA. This is different from substitution because nothing is getting switched out, just new ones are getting inserted. The original codons will still be present, just new ones are coming in. Insertions result in a frame-shift, which means everything after the mutation is shifted and nothing will be correct after this. Insertions are more harmful than substitution because it doesn't affect just one amino acid, but many.

Deletion:

Deletion is where some codons or DNA is deleted. This will result in everything after the mutation being incorrect and can cause drastic effects. Deletion is very similar to insertion because they both cause a frame-shift, but also very different because they do the opposite from one another. Deletion is also more harmful than substitution because of the frame-shift and the change in future amino acids.

Answer:

Explanation:

The principal player in memory consolidation research, in terms of brain regions, is the hippocampus.

hope it helps

Answer:

It is extremely important to know all types of blood because if you donate the wrong type of blood to another person, he/she will get sick.

Explanation:

Hemolytic transfusion reactions can cause the most serious problems, but these are rare. These reactions can occur when your ABO or Rh blood type and that of the transfused blood do not match. If this happens, your immune system attacks the transfused red blood cells. This can be extremely life-threatening.

Answer:

The correct answer is option D.

Explanation:

Hamilton rules state that any trait that helps in benefiting others, B, is multiplied by genetic relatedness, R, which is greater than cot to self, C, it is favored by the process of natural selection.

As indicated by Hamilton's rule, the kin selection makes qualities increment in recurrence when the hereditary relatedness of a beneficiary to an actor multiplied by the advantage to the beneficiary is more noteworthy than the regenerative expense to the actor.

Thus, the correct answer is option D.

Answer:

If you are asking a true or false this is sometimes true with small swamps

Explanation:

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Answer:Esta cobertura comprende las tierras bajas, que generalmente permanecen inundadas durante la mayor parte del año, pueden estar constituidas por zonas de divagación de cursos de agua, llanuras de inundación, antiguas vegas de divagación y depresiones naturales donde la capa freática aflora de manera permanente o estacional. Comprenden hondonadas donde se recogen y naturalmente se detienen las aguas, con fondos más o menos cenagosos. Dentro de los pantanos se pueden encontrar cuerpos de agua, algunos con cobertura parcial de vegetación acuática, con tamaño menor a 25 ha, y que en total representan menos del 30% del área total del pantano.

Distribución geográfica: Las zonas pantanosas se identificaron en las llanuras de inundación a lo largo de los ríos Caquetá, Caguán y Orteguaza y sus tributarios en el departamento del Caquetá; a lo largo del Río Guaviare en el norte de la región amazónica y en el río Vaupés en los departamentos de Guaviare y Vaupés.

Explanation:

Answer:

It's C

Explanation:

They are geometric isomers. Thus option C is the correct answer.

Two chemical species with the same number and types of atoms but different configuration are called as isomers, the spontaneous process by which isomers are formed called isomerization.

This process is independent of bond energy of the configurations.

Different types of isomers are structural isomers, geometric isomers, stereoisomers, optical isomers.

The major type called structural Isomers where atoms and functional groups are differently joined with each other. For example, 1-fluoropropane and 2-fluoropropane positional change.

Another types is stereoisomers formed between atoms and functional groups with differential geometrical positioning.

This class include enantiomers which are non-superimposable mirror images of each other and have chiral centers. example are D-threose and D-erythrose.

In stereoisomers, the class of diastereomers have different physical properties and reactivities.

Thus option C is the correct answer.

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Answer:

A.

Explanation:

Sperm migrate from the seminiferous tubules to the epididymis.

Answer:

1. Fats contain mostly C-H bonds, it has less oxygen therefore making it a high energy compound

2. mRNA plays a vital role in protein synthesis. It's a single stranded RNA molecule that contains genetic information that can be taken outside the nucleus (unlike DNA which cannot leave the nucleus). Its created during transcrption, and is used during translation to create proteins

3. (Look at image)

1. The organic molecules that contain esters of fatty acids and a mixture of compounds are called fats. They provide energy to the body for functioning. They provide slow energy but the most efficient energy.

The amount of calories supplied by fats is twice as compared to carbohydrates and proteins. The excess of fats is stored in the body for future purposes.

2. mRNA is a type of RNA and plays a vital role in the process of translation. It is a single-stranded molecule that contains genetic information transcripted from DNA and is transported out from the nucleus into the cytoplasm.

The main function of mRNA is in protein synthesis. It helps in the formation of amino acid sequence that undergoes modification to form proteins.

3. The general formula of amino acid is [tex]\rm R-CH(NH_{2})-COOH[/tex].

The side chains of different amino acids vary accordingly. The structure consists of a carboxylic group along with an amino group and an organic side chain.

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Answer:

True

Explanation:

Diffusion is a passive process (no energy required) in which the substance such as liquid and gases moves from an area of high concentration to an area of low concentration.

During respiration, carbon dioxide diffuses from the blood into the alveoli and oxygen diffuses from alveoli to blood across the respiratory membrane. The partial pressure of oxygen is low in the blood of the pulmonary capillaries and high in the alveoli. so diffusion allow movement of oxygen across the respiratory membrane from the alveoli into the blood.

Hence, the given statement is true.

Answer:

the ability to form stable bonds

Answer:

Most physiological alterations during aging and it is usually characterized by the deposition of a pigment called liposfuscin.

The valves of the heart also becomes stiff and thickened as a result of the pigment mentioned above. This makes the flow of blood slower than normal and contributes to cardiovascular diseases such as Stroke, high blood pressure etc.

Answer:

POSITIVE CONTROL

c) Active Activator  

d) Active Repressor  

NEGATIVE CONTROL

f) Inactive repressor  

a) Inactive Activator  

b) cAMP

Explanation:

The positive controls are those groups in the experiment whose treatments are expected to confirm previously known results, thereby enabling the comparison of these results with the target group. In this case, both active activators and repressors are able to give results that can be compared with the test group  

The negative controls are those experimental groups where no response is expected. In this case, both inactive activators and repressors, and cAMP (which is a secondary messenger in diverse biological processes but is not involved in this pathway), are not expected to produce any measurable response.

Answer:

skin.

Explanation:

the first line of defense uses physical parts such as skin.

Answer:

To establish and enhance socially important behaviors.

Explanation:

This is a form of therapy that helps individuals improve on certain important behaviors which affects our daily life. We are likely to socialize and it’s imperative to have the necessarily social skills or behavior.These behaviors include punctuality,social, communication and learning skills etc.

The main aim of applied behavior analysis is to establish and enhance socially important behaviors.

Answer:

In scenario A A. Human biology

Which of the following disciplines would be most relevant?

B. Biology

Explanation:

In scenario A Australopithecus sediba arms are adapted for climbing in tree and its legs are adapted for walking on two legs. Australopithecus is related to homo habilis and also homo erectos. They are different human primate.

B. Biology because there are fossil remains dated to about 2 million years ago.

Answer:

540MIL0IAER

P

Explanation:

F

VFVVEV

Answer:

Bacteria have smaller populations, grow faster, and also share more genes compared to mammals.

Explanation:

Because bacteria reproduce quicker and are also in smaller populations, they can evolve quicker because more genes are shared which can be helpful. This is due to natural selection, which will affect bacteria more than mammals because their small populations will make natural selection more significant to  be harmed by mutations and allow them to evolve.

Answer:

B

Explanation:

Proteins are organic compounds containing carbon, hydrogen, oxygen, and nitrogen. Amino acids are compounds that consist of an R group, carboxylic acid end, and amino end. A chain of amino acids is referred to as a protein.

The statement 'a chain of amino acids folded and twisted into a molecule' describes the structure of albumin (Option B).

In conclusion, the statement 'a chain of amino acids folded and twisted into a molecule' describes the structure of albumin (Option B).

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Answer:

The correct answer is B. A phosphate group and 2 fatty acid chains.

Explanation:

A P3 X

Each phospholipid is made up of a phosphate group and two fatty acid chains. The correct option is B.

Phospholipids are lipids that have two types of edges. It has a hydrophobic tail and a hydrophilic head.  The plasma or cell membrane, according to the fluid mosaic model, comprises substances like proteins and phospholipids.

A phosphate head and a fatty acid (lipid) tail make up the phospholipid layer, also known as the phospholipid layer, which is formed by the phospholipid.

Small molecules like oxygen gas can diffuse through the phospholipid layer, which facilitates the passage of small molecules but not larger ones. Biological membranes are formed by two lipid layers, proteins, and glucans.

Therefore, the correct option is B. A phosphate group and two fatty acid chains.

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The correct answer is A. Golgi apparatus

Explanation:

In a plant cell, the cytoplasm contains organelles such as the chloroplast, the ribosome, the Golgi apparatus, among others. From these organelles, the Golgi apparatus is the one that is composed of vesicles and folded membranes, which makes it look like a system of flattened, long, and folded sacs or membranes connected. Additionally, this organelle is in charge of process proteins and lipids by packaging and modifying these before they go to other sections or organelles in the cell. According to this, the organelles labeled E is likely the Golgi apparatus because only this includes a set of vesicles and folded membranes.

Answer:

A. Golgi apparatus

Explanation:

Answer:

Explanation:

In eukaryotic cells, the cytoskeleton is composed of three well defined filamentous structures: microtubules, microfilaments, and intermediate filaments. Each of these filamentous structures is a polymer of proteinic subunits united by weak, not covalent connections.

The microfilaments are the thinnest of the three structures. They have a diameter of 7 nanometers and are composed of many proteinic monomers united. This monomeric protein is called actin. Many monomers get combined to form a structure that assembles a double helix.

Due to the fact that these microfilaments are made of actin monomers, they are also known as actin filaments.

Actin filaments have directionality which means that their extremes have different structures.  

Microfilaments interact with myosin filaments. These are associated with transmembrane proteins that have one domain in the cytosol and another in the cell exterior, therefore they participate in the processes of cell mobility.

Answer:

Hetezygous

Explanation:

The genotype of the initial green pod plant would be heterozygous.

Let pea pod color be represented by C (c) alleles.

First, let us assume that the genotype of the green pea pod plant is homozygous dominant, CC. This was crossed with homozygous recessive, cc.

           CC   x   cc

      Cc   Cc   Cc   Cc

All the progeny will have Cc genotype with phenotypically green color. This is in contrast to the result obtained from the test cross in the illustration, hence the genotype of the initial green pea pod plant cannot be homozygous dominant.

Now, let us assume that the genotype is Heterozygous, Cc.

       Cc   x   cc

 Cc   Cc   cc   cc

50% of the progeny has Cc genotype with phenotypically green color while the remaining 50% has cc genotype with phenotypically yellow color. This is consistent with the result from the illustration.

Hence, the genotype of the initial green pea pod plant is heterozygous.

Answer:

Explanation below.

Explanation:

1. Multiple gene alleles.

2. Dominant gene

3. Heterozygous

4. Female trait

5. Homozygous

6. Evolution/ new breed

7. Mixed breed

8. Dominant gene

9. Hereditary

10. Rare gene

Answer:

(1) CI Ci cI ci

(2) CI Ci

(3) 25

(4) 75

Explanation:

Mother is in this case is heterozygous for C & I, genotype of mother would be : CcIi

Father is on other hand is homozygous for C (dominant) and heterozygous for I, genotype : CCIi

1. Gametes produced by the mother will be:

 CI Ci cI ci  by the combinantion of C, I, c, and i alelles present in mothers genotype.

2. Gametes produced by the father :

CI Ci  by the combinantion of alleles present i genotype of father CCIi

3. probability of one of the offspring of these two chickens having pigmented feathers:

 2/8 × 100 = 25% ( punnet is attached)

4. chicken with white feather in population of 100 chickens:

 probability of being white ×  100

probability of being white : 1 - 2/8

thus, (1-2/8) × 100 = 6/8 × 100

    = 75%

Answer:

Explanation:

According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (Homozygous dominant), 2pq (Heterozygous), q² (Homozygous recessive). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.

In the same way, the sum of genotypic frequencies equals 1, this is

p² + 2pq + q² = 1

Being

In the exposed example, 79% of the moths of the species Biston betularia were black due to the presence of a dominant gene for melanism.

If the genotypic frequency of back moths is 0.79, then, by performing the following equation we can get the not-black moths genotypic frequency:

p² + 2pq + q² = 1

where p² is the homozygous dominant genotypic frequency, q² the homozygous recessive genotypic frequency, and 2pq is the heterozygous genotypic frequency.

As 0.79 is the phenotypic frequency of black moths, then this frequency equals p²+2pq.

Clearing the equation:

p² + 2pq + q² = 1

0.79 + q² = 1

q² = 1 - 0.79

q² = 0.21

The genotypic frequency of non-black moths is 0.21. So, from here we can calculate the allelic frequency:

q² = 0.21

q= v 0.21

q = 0.458

If 0.46 is the allelic frequency of non-black moths, then by clearing the equation p + q = 1, we can get the p allelic frequency:

p + q = 1

p + 0.458 = 1

p = 1 - 0.458

p = 0.542

        2 x p x q = 2 x 0.542 x 0.458 = 0.496

Finally, we can check this answer by clearing the following equation:

p² + 2pq + q² = 1

0.294 + 0.496 + 0.21 = 1