Answer:
Masseter
The masseter runs from the temporal bone (that forms part of the sides and base of the skull) to the lower jaw (the mandible). It lifts the lower jaw, to close the mouth. The masseter is the strongest muscle in your body.
Temporalis
The temporalis begins on two bones of the skull, at the front (the frontal) and at the side and base (the temporal). It runs to the top of the lower jaw (the mandible). Like the masseter, the temporalis helps close the mouth.
Deltoid
The deltoids are the triangular muscles of the shoulder. The strongest point is the central section, which raises the arm sideways. The front and back parts of the muscle twist the arm. Deltoid comes from the Greek word deltoeides, meaning shaped like a (river) delta, which is triangular.
Pectoralis major
(The pecs!) The pectoralis major is a large, fan-shaped muscle. It covers much of the front upper chest, beginning at the breastbone (or sternum) including the second to the sixth ribs.
Adductor Longus
The adductor longus is located on the inner thigh. Adduct means move, so this muscle allows the thigh bone (the femur) to move inward and to the side.
Soleus
Located in the lower leg, the soleus runs from the lower leg bones (the tibia and fibula) to the heel (the calcaneus). The soleus muscle flexes the foot by moving the foot at the ankle. It also helps circulation by pumping blood back up towards the head.
Biceps brachii
The biceps brachii runs from the shoulder to the elbow. It is attached to the shoulder blade (the scapula), and extends along the front surface of the upper arm bone (the humerus). When the bicep contracts, the arm bends at the elbow. Notice that humerus sounds like humour – we call this area of the elbow the funny bone.
The Buccinator
The buccinator muscle compresses the cheek. This muscle allows you to whistle, blow, and suck; and it contributes to the action of chewing.
The Suprahyoid
The suprahyoid muscles raise the hyoid bone, the floor of the mouth, and the larynx during deglutition.
The Splenius
The splenius muscles originate at the midline and run laterally and superiorly to their insertions. From the sides and the back of the neck, the splenius capitis inserts onto the head region, and the splenius cervicis extends onto the cervical region. These muscles can extend the head, laterally flex it, and rotate it.
which type of elecromagnetic wave can penetrate solid object easily
Answer:
Electromagnetic waves which has higher frequency will have a higher degree of penetration power. Frequency has an indirect relationship with the wavelength. Therefore, Electromagnetic waves which has larger wavelength values will have more penetration power.
Explanation:
hope this helped
What are the 2 types of shadow
cast by the moon during a solar
eclipse?
Answer:
umbra, penumbra
Explanation:
The vertical columns in the periodic table are called _____________.
Answer:
The elements are arranged in seven horizontal rows, called periods or series, and 18 vertical columns, called groups. Groups are labeled at the top of each column.
Explanation:
Because of inertia, it will be ____ to stop a larger object than a smaller object if they are both moving at the same speed.
Answer:
harder
heavier objects resist change more than lighter objects.
In a catapult, energy is transferred into useful kinetic energy stores what store is the energy in when it is in the catapult
Explanation:
In a catapult, Initially, energy is stored in the form of potential energy which is later converted into kinetic energy.
Potential energy can be stored in the form of elastic potential energy in the case of elastic. It suddenly releases the energy to propel the object into the air.
Answer:
The right answer is "strain" or "strain energy" or "elastic potential energy" or "elastic energy" or "potential energy" or "elastic potential" or "elastic"
Explanation:
Catapults store energy as elastic potential energy.
How is mechanical advantage determined in a pulley system?
Answer:
To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort). For example, in a one pulley system the MA is 1. ... The more compound the pulley is the easier the load is to lift.Please someone help!!!
Newton’s first law of motion is often called the law of?
Answer:
Newton's first law is often called the law of inertia.
searched it up to verify
Also welcome to brainly
a
It do
While doing dishes, Zvi drops his
3.0x10 3kg platinum wedding band
into the dishwater, displacing a
volume of 1.40x107m3 of water,
what is the density of the platinum
band?
n
CSS c
sion
im
al
Select one:
a. 2.56x104 kg/m3
b. 1.0x104 kg/m3
Di
c. 0.5x104 kg/m3
IL
d. 2.14x104 kg/m3
IL:
Answer:
d. 2.14 x 10⁻⁴ kg/m³
Explanation:
Density is defined as the mass of an object per unit volume occupied by that object. The formula of density is, therefore, given as follows:
[tex]\rho = \frac{m}{V}[/tex]
where,
ρ = density of platinum band = ?
m = mass of platinum band = 3 x 10³ kg
V = Volume displaced by Platinum band = 1.4 x 10⁷ m³
Therefore,
[tex]\rho = \frac{3\ x\ 10^{3}\ kg}{1.4\ x\ 10^{7}\ m^{3}}\\\\\rho = 2.14\ x\ 10^{-4}\ kg/m^{3}[/tex]
Hence, the correct option is:
d. 2.14 x 10⁻⁴ kg/m³
An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.220 rev/s . The magnitude of the angular acceleration is 0.920 rev/s2 . Both the the angular velocity and angular acceleration are directed counterclockwise. The electric ceiling fan blades form a circle of diameter 0.800 m .
1) Compute the fan's angular velocity magnitude after time 0.208 s has passed.
2)Through how many revolutions has the blade turned in the time interval 0.208 s from Question 1?
3)What is the tangential speed vt of a point on the tip of the blade at time t = 0.208 s ?
4)Calculate the magnitude at of the tangential acceleration of a point on the tip of the blade at time t = 0.208 s .
5)Calculate the magnitude ar of the radial (or centripetal) acceleration of the point at the end of the fan blade.
Answer:
1) The fan's angular velocity after 0.208 seconds is approximately 2.585 rad/s
2) The number of revolutions the blade has travelled in 0.208 s is approximately 0.066 revolutions
3) The tangential speed of a point on the tip of the blade at time t = 0.208 s is approximately 1.034 m/s
4) The magnitude of the tangential acceleration of a point on the tip of the blade at time t = 0.208 seconds is approximately 2.312 m/s²
Explanation:
The given parameters are;
The initial velocity of the fan, n = 0.220 rev/s
The magnitude of the angular acceleration = 0.920 rev/s²
The direction of the angular acceleration and the angular velocity = Clockwise
The diameter of the circle formed by the electric ceiling fan blades, D = 0.800 m
1) The initial angular velocity of the fan, ω₀ = 2·π × n = 2·π × 0.220 rev/s = 1.38230076758 rad/s
The angular acceleration of the fan, α = 2·π×0.920 rad/s² = 5.78053048261 rad/s²
The fan's angular velocity, 'ω', after a time t = 0.208 seconds has passed is given as follows;
ω = ω₀ + α·t
From which we have;
ω = 1.38230076758 rad/s + 5.78053048261 rad/s × 0.208 s = 2.58465110796 rad/s
The fan's angular velocity after 0.208 seconds is ω ≈ 2.585 rad/s
2) The number of revolutions the blade has travelled in the given time interval is given from the angle turned, 'θ', in the given time as follows;
θ = ω₀·t + 1/2·α·t²
θ = 1.38230076758 × 0.208 + 1/2 × 5.78053048261 × 0.208² = 0.41256299505 radians
2·π radians = 1 revolution
∴ 0.41256299505 radians = 0.41256299505 radian× 1 revolution/(2·π radian) = 0.06566144 revolution
The number of revolutions the blade has travelled in 0.208 s ≈ 0.066 revolutions
3) The tangential speed of a point on the tip of the blade at time t = 0.208 s is given as follows;
The tangential speed, [tex]v_t[/tex] = ω × r = ω × D/2
At t = 0.208 s, ω = 2.58465110796 rad/s, therefore, we have;
[tex]v_t[/tex] = ω × D/2 = 2.58465110796 × 0.800/2 = 1.0338604413
The tangential speed, [tex]v_t[/tex] = 1.0338604413 m/s
The tangential speed ≈ 1.034 m/s
4) The magnitude of the tangential acceleration of a point on the tip of the blade at time t = 0.208 seconds, 'a' is given as follows;
a = α × r = α × D/2
a = 5.78053048261 × 0.800/2 = 2.31221219304
The tangential acceleration, a ≈ 2.312 m/s²
Give reason
A person slips over banana peels
Answer:
Well, a fresh off the fruit peel, although smooth by touch, has enough friction to prevent a major slip and fall. ... As the banana peel stays on the ground, it begins to rot and get slimy. If someone were to then step on that rotting, slimy banana peel, they would be in for a decent slip.
Explanation:
(GIVING BRAINLIST)
Why is it important to perform multiple trials of an experiment?
A. To check for mistakes or errors in your procedure
B. To increase the accuracy of your experiment
C. To investigate different test variables
D. To obtain different results for your experiment
Answer:
C
Explanation:
During an investigation you want to investigate different variables.
Answer:
During an investigation, you want to investigate one variable at a time
Explanation:
can i please have brainiest
Forces in the same pair have equal size but opposite _________ .
have discovered fossils of similar an
different continents. This indicated that continents were on to
7. What did geologists discover?
carth Processes an as earthquakes, onde
8. The continents are parts of enormous sheets of rock called
9. These plates are in constant
Answer:
7
Explanation:
plates
4. A dump truck has a mass of 5.50 x 105 kg when loaded and 2.30 x 105 kg when
empty. Suppose two such trucks, one loaded and one empty, crash into each other
at a monster truck show. The trucks are supplied with special bumpers that make
a collision almost perfectly elastic. If the trucks hit each other at equal speeds of
5.00 m/s and the empty truck recoils to the right with a speed of 9.10 m/s, what is
the velocity of the full truck after the collision?
Answer:
V = 0.896 m/s
Explanation:
This is a typical problem of momentum conservation, whic states the following:
m₁V₁ + m₂V₂ = m₁V₃ + m₂V₄ (1)
In this case V₃ and V₄ would be the final velocity of the trucks after the collision.
With the given data let's see what we have:
m₁ = 5.5x10⁵ kg
m₂ = 2.3x10⁵ kg
V₁ = 5 m/s
V₂ = -5 m/s because it's going to the left (-x axis)
V₄ = 9.1 m/s to the right (Meaning is positive)
V₃ = ??
So to calculate V₃ we just need to replace the data into (1) and solve for V₃:
(5.5x10⁵ * 5) - (2.3x10⁵ * 5) = 5.5x10⁵V₃ + (2.3x10⁵ * 9.1)
2.75x10⁶ + 1.15x10⁶ = 5.5x10⁵V₃ + 2.093x10⁶
V₃ = 2.75x10⁶ - 1.15x10⁶ - 2.093x10⁶ / 5.5x10⁵
V₃ = -0.493x10⁶ / 5.5x10⁵
V₃ = -0.896 m/s
With this sign, it means that is going in the same sense of the other truck, but it's going to the left so this would be positive:
V₃ = 0.896 m/sHope this helps
What are the scientific principles of physical science
Answer:
Describing and measuring motion. Newton's laws of motion. Forces, weight, and mass. Momentum and conservation of momentum.
The theory of gravity.
Energy, work, and power. Motion, position, and energy.
Explanation:
Answer:
lOl can i have brainliest
Explanation:
Q3) A person has to cover a distance of 6km in 45 minutes. If he covers one-half of the distance in two-thirds of the total time; to cover the remaining time, his speed (in km/hr) must be:
A) 6
B) 8
C) 12
D) 15
Explain how you got the answer
Answer:
The correct answer - c. 12.
Explanation:
Given:
Total distance: 6 km
Total time - 45 minutes
covered distance - one half of 6 km = 3 km
time used - 2/3*45 = 30 minutes
Solution:
Remaining distance - 6-3 = 3 km
Remaining time = 45 - 30 = 15 minutes or 1/4 hour
Required speed = remaining distance/ remaining time
= [tex]\frac{3}{1/4}[/tex]
= [tex]\frac{3*4}{1}[/tex]
= 12 km/hr
Walt ran 5 kilometers in 25 minutes, going eastward. What was his average velocity?
0.17 km/min east
0.2 km/min east
5 km/min east
25 km/min east
Answer:
0.2
Explanation:
The average velocity of Walt will be 0.2 km/min east.
We have a boy named Walt.
We have to find the average velocity of Walt.
What is Average velocity ?It is defined as the rate of change of displacement with time. Mathematically -
v = Δx / Δt
According to the question -
Total distance = d = 5 Km
Time = t = 25 minutes
Average velocity = d / t = 5/25 = 0.2 km/min
Therefore, the average velocity of Walt will be 0.2 km/min east.
To solve more questions on Kinematics, visit the link below-
brainly.com/question/21092131
#SPJ2
A roller coaster of mass 800 kg starts from rest at the top of a hill with 1,500,000 J of potential energy. It ends up at ground level moving at 45 m/s. How much energy was lost to heat and friction?
Answer:
E_loss = 690000 [J]
Explanation:
The principle of conservation of Energy tells us that energy is converted from Kinetic to mechanical when the body moves from the highest point to the point where the velocity is maximum. That is, all potential energy is transformed into kinetic energy.
[tex]E_{pot}=E_{kin}[/tex]
Now we must determine the kinetic energy at the end, when the roller coaster is at the point where the reference point of power energy is zero.
[tex]E_{kin}=\frac{1}{2} *m*v^{2}[/tex]
where:
m = mass = 800 [kg]
v = 45 [m/s]
Now replacing:
[tex]E_{kin}=0.5*800*(45)^{2}\\E_{kin}=810000[J][/tex]
Now by means of the difference of the energy at the beginning minus the final energy, it determines the amount of energy that is lost by the effects of friction and heat.
[tex]E_{loss}=1500000-810000\\E_{loss}=690000[J][/tex]
A man is pushing a heavy crate up an inclined plane into the back of semi trailer.What can the man do to make it easier to get the crate up the ramp
Answer:
B) Make the ramp longer
Explanation:
A machine is a device that makes work more easier and faster. A machine also saves time.
A ramp is a simple machine that is used to lift heavy object with a force that is lesser than the actually force needed. A ramp is in the shape of an inclined plane, which makes pushing an object easier than the required force needed.
The formula for a ramp is given by:
Force needed to push * length of the ramp = weight of object * height of ramp.
Force needed to push = (weight of object * height of ramp) / length of ramp
We can see that the force needed is inversely proportional to the ramp length. Hence for a ramp with longer length you need lesser force to raise the object.
A soapbox derby is to be held on a frictionless hill with a 28 m vertical drop. The track is 300 m long. What is
the change in potential energy of a racecar from start to finish if it and the driver have a combined mass of 113
kg?
Round your answer to a whole number and include correct Sl unit abbreviation.
Answer: -31039 J
Explanation:
if a charge has a lot of electric potential energy, what is it said to have?
Answer:
current?
Explanation:
Problem solving strategy
Find the total momentum of the following system contains a
duck and three baby ducks moving to the right
If the mass of the duck is 0.5 kg moving with 2m/s and each of
the three ducks has a velocity of 1.5 m/s and a mass of 0.1 kg.
Answer:
The total momentum of the system is 1.45 kg*m/s.
Explanation:
The total momentum of the system is given by:
[tex] p_{T} = p_{d} + p_{b_{1}} + p_{b_{2}} + p_{b_{3}} [/tex]
[tex] p_{T} = m_{d}v_{d} + m_{b_{1}}v_{b_{1}} + m_{b_{2}}v_{b_{2}} + m_{b_{3}}v_{b_{3}} [/tex]
Where:
m: is the mass
v: is the velocity
d: is for duck
b₁: is for baby duck one
b₂: is for baby duck two
b₃: is for baby duck three
[tex] p_{T} = 0.5 kg*2 m/s + 0.1 kg*1.5 m/s +0.1 kg*1.5 m/s + 0.1 kg*1.5 m/s = 1.45 kg*m/s [/tex]
Therefore, the total momentum of the system is 1.45 kg*m/s.
I hope it helps you!
A vector is 14.4 m long and points in a 133 degree direction . Find the y - component of the vector .
Answer:
I put X and Y components so make sure you pay attention to which is correct for you.
Explanation:
X = -9.82
Y = 10.5
The N car has a weight of 15,000, and its tires are inflated to a pressure of 190 kPa. How much space will the car's tires touch the road?
Answer:
0.079m²
Explanation:
Pressure = Force/Area
Given
Force = 15000N\Pressure = 190kPa = 190,000Pa
Substitute into the formula
Area = Force/Pressure
Area = 15000/190000
Area = 0.079m²
Hence the space covered by the tire will be 0.079m²
10,000 W of power is used to move a spoon for 10 s. How much work is done on the spoon?
Answer:
The work done is 100,000 Joule
Explanation:
Work and Power
Work is the amount of energy transferred by a force.
If both the force F and displacement s are parallel, then we can use the formula:
W = F.s
Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.
The power can be calculated as:
[tex]\displaystyle P=\frac {W}{t}[/tex]
Where W is the work and t is the time.
We know the power needed to move a spoon is P=10,000 Watt and it took a time of t=10 s. The work done on the spoon is calculated by solving for W:
W = Pt
W = 10,000 Watt * 10 sec
W = 100,000 Joule
The work done is 100,000 Joule
A toy car runs Off the edge of a table at 2.5 m high. It’s a carlins 1.2 m on the base of the table fine how long it took the car to reach the ground
If I am in a Ferrari and I travelled for 3 hours at a speed of 270 km/h. How far did I travel?
Use the following formula:
distance velocity x time
a)810km
b)90km
c)810km/hr
which planet has a feature called the great dark spot ?
Answer:
Neptune
Explanation:
Answer:
Neptune has that feature. Hope this helped!!! ^D^
Explanation:
Please I need help on question 22 and 23 you don’t have to answer both tho
Answer:
22. is A and 23. is C
Explanation:
