Mario rdoll a coin up a slope at 2 m/s. It travels 2.7 m, comes to a stop and rolls back down. What is the coin's acceleration?

Answers

Answer 1

The coin's acceleration is 0.37 m/s²

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

V² = U -2aS

a = U/2S

  = 2/2×2.7

   =  0.37 m/s²

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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Related Questions

A Carnot engine performs work at the rate of 510 kW while using 930 kcal of heat per second.
a) If the temperature of the heat source is 600 ∘C , at what temperature is the waste heat exhausted?

Answers

The temperature of waste heat exhausted is  483.83 °C.

A Carnot heat engine is a heat engine that operates at the Carnot cycle. The simple version of this engine turned into evolved by Nicolas Léonard Sadi Carnot in 1824.

The Carnot engine is a theoretical thermodynamic cycle proposed by means of Leonard Carnot. It estimates the maximum possible efficiency that a heat engine all through the conversion manner of heat into work and, conversely, operating between reservoirs can possess.

calculation:-

1 kcal = 4.186 k J.

So the engine efficiency eta = 510/930 × 4.186 = 0.13305

T hot = 600 + 273.15 = 873.15 K

From the Carnot equation = (T hot-T cold) /T Hot,

so

T cold = T hot(1-eta)

= 873.15 × (1-0.13305) =756.98 K

= 756.98  K = 483.83 °C

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Which of these has 28 protons and 26 electrons?
O Fe
O Fe2+
Ο Ni
O Ni2+

Answers

Answer:

here, if you have an iron which has 28 protons and 26 electrons, and we have to find the charge on the iron, the element and the symbol of the iron. So For 28 protons charge is 28 e. And for 26 electrons, charge will be -26 E. So total charges 28 E minus 26 E. Equal to two E. On I N S, plus two. No, we have to find the element. So atomic number is equal to Number of protons, which is 28, and this is atomic number four nickels. So the element is nickel and we have to find the symbol of iron. So the iron has to positive child. So the symbol will be and I took place So this completes the solution. Thank you.

Explanation:

In the periodic table in the image below, which of the following atoms is
classified as a metalloid?
OA. Fluorine (F)
OB. Antimony (Sb)
OC. Cadmium (Cd)
OD. Radon (Rn)

Answers

Answer:

OB

Explanation:

Antimony is a chemical element with as symbol Sb and atomic number 51

I agree with Ambition!

The speed of light in vacuum is 3*10^8m/s what it's speed in glass of refractive index1.5

Answers

Answer:

Speed of light in glass V = 2·10⁸ m/s

Explanation:

Given:

c = 3·10⁸ m/s - The speed of light in vacuum

n = 1.5 - Refractive index of glass

__________

V - ?

Speed of light in glass:

V = c / n

V = 3·10⁸ / 1.5 = 2·10⁸ m/s

A rightward force of 12.0 N is applied to a 2.0-kg object to accelerate it across a horizontal
surface. The object encounters 8.0 N of friction. What is the object's acceleration?

Answers

Answer:

below

Explanation:

Net accelerating force becomes  12-8 = 4 N

F = ma

4 = 2 * a

a = 2 m/s^2

The object encounters 8.0 N of friction. The object's acceleration is 2 m/s².

What is acceleration?

Acceleration is the rate at which the speed and direction of a moving object change over time. A point or object moving straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, the motion on a circle accelerates because the direction is constantly shifting.

The word "force" has a specific meaning in science. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains."

Net accelerating force becomes  12 - 8 = 4 N

The formula for force is

Force = mass x acceleration

F = ma

4 = 2 x a

a = 2 m/s²

Therefore, the object's acceleration is 2 m/s².

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A dog sits 2.2 m from the center of a merry- go-round.
a) If the dog undergoes a 1.6 m/s2 cen- tripetal acceleration, what is the dog’s linear speed?
Answer in units of m/s.

second part
What is the angular speed of the merry-go- round?
Answer in units of rad/s.

Answers

The dog’s linear speed will be 1.88 m/s

The angular speed of the merry-go- round will be  0.85  rad/sec

centripetal acceleration = [tex]v^{2} / r[/tex]

given

r = 2.2 m

linear speed = ?

centripetal acceleration  = 1.6 [tex]m/s^{2}[/tex]

centripetal acceleration C(a) = [tex]v^{2} / r[/tex]

             linear speed = [tex]\sqrt{C(a) * r}[/tex]

                                   = [tex]\sqrt{1.6 * 2.2 }[/tex] = [tex]\sqrt{3.52}[/tex]  = 1.88 m/s

The dog’s linear speed will be 1.88 m/s

angular speed = linear speed / radius

                        = 1.88 / 2.2 = 0.85  rad/sec

The angular speed of the merry-go- round will be  0.85  rad/sec

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Speculate on the different social dynamics behind lower - class drug use and middle -class drug use. For example , are there likely to be differences in motivation for use ? In the way individuals are introduced to drugs ? In the consequences for drug use ?

Answers

Social dynamics behind lower -class drug use is homelessness, criminal behaviors, association with gangs and unemployment whereas social dynamics behind middle -class drug use is peer relationships, extramarital relations and distortion of interpersonal family relationships.

What are the social dynamics behind drug use?

Social factors that increase the risk for adolescent drug use can include popularity, bullying, peer relationships, and association with gangs.

Other possible factors can be social and familial influences. This can result in financial hardships due to job loss. It may also lead to certain behavior that can put family at risk and can also cause domestic violence within relationships.

Other social problems linked with SUDs can be housing instability, homelessness and unemployment.

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An experimenter would like to construct a 99% confidence interval with a width at most 0. 5 for the average resistance of a segment of copper cable of a certain length. If the experimenter knows that the standard deviation of such resistances is 1. 55. How big a sample should the experimenter take from the population? what happens if the standard deviation and the width of the confidence interval are both doubled?.

Answers

Sample should be 256 , which the experimenter can take from the population . If the standard deviation and the width of the confidence interval are both doubled , the size will be same .

What is resistance ?

Resistance is the resistance that a substance offers to the flow of electric current. Represented by a capital R. The standard unit of resistance is the ohm, sometimes written as a word or represented by the Greek letter omega. If a current of 1 ampere flows through a component with a potential difference (voltage) of 1 volt, the resistance of that component is 1 ohm. The electrical resistance per unit length, area, or volume of matter is known as resistance. Resistance values ​​are often given in ohms per kilometer of copper and aluminum wire.

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An increase in which property would cause an electromagnetic waves energy to increase ?

Answers

Answer:

wavelength.

Explanation:

Explanation: Frequency = speed of light/wavelength. The frequency of an electromagnetic wave increases as wavelength decreases

A hot air balloon weighs 3100kg. The hot air in the balloon creates an upward force of 30,000N. What is the magnitude AND direction of the acceleration of the air balloon?

Answers

The magnitude and direction of the acceleration of the air balloon, with a mass of 3100 kg and a force of 30000 N acting on it is  9.68 m/s² upward.

What is acceleration?

Acceleration can be defined as the rate of change of velocity.

To calculate the magnitude and direction of the acceleration, we use the formula below.

Formula:

a = F/m............. Equation 1

Where:

F = Upward forcem = Mass of the balloona = Acceleration of the ballon

From the question,

Given:

F = 30000 Nm = 3100 kg

Substitute these values into equation 1

a = 30000/3100a = 9.68 m/s² upward.

Hence, the magnitude and the acceleration of the air balloon is  9.68 m/s²  upward.

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6. A constant net force acts on a magnitude of all of the following quantities pertaining to
the body EXCEPT
(A) Acceleration
(B) Kinetic Energy
(C) Momentum
(D) Speed
(E) Velocity

Answers

(E) - that’s What my friend told me.

NEED HELP ASAP
Two objects of masses and 5 are moving toward each other along the -axis with the same initial speed. They undergo an elastic collision such that is scattered to move downward after the collision, perpendicular to its initial direction.

(a) Find the final speeds of the two objects.

(b) What is the angle at which the object with mass 5 is scattered, measured with respect to its velocity prior to the collision?

Answers

The final velocity is equal to the product of the square root of two, and the initial velocity and the angle at which the object with mass 5 is scattered, are measured with respect to its velocity prior to the collision  [tex]35^o[/tex].

What is Speed?

Speed is a unit used to describe how quickly an object is moving. The fact that speed is a scalar denotes that it is a measurement with a magnitude but no direction.

Something that travels at a fast rate of speed and covers a lot of distance quickly. A slow-moving object, on the other hand, travels a relatively little distance in the same length of time when moving at a low pace. An item with zero speed is completely immobile.

(a) Let the initial velocity is [tex]V_1[/tex] and the final velocity is [tex]V_2[/tex], then by applying conservation of momentum, we get the formula of

[tex]V_2 = \sqrt{2} V_1[/tex]

Therefore, the final velocity is equal to the product of the square root of two, and the initial velocity.

(b) Let the θ is the angle of scattering, then,

tanθ = [tex]V_1 / \sqrt{2} V_1[/tex]

θ = [tex]tan^-1/\sqrt{2}[/tex]

θ = [tex]35^o[/tex]

Therefore, the angle at which the object with mass 5 is scattered, measured with respect to its velocity prior to the collision is  [tex]35^o[/tex].

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Which rule always applies when drawing a trend line for a set of data points?
The trend line always connects the first and last data points
The trend line connects all of the data points dot-to-dot
The trend line should follow the overall pattern of the data
The trend line is always a straight line

Answers

The rule that applies when drawing a trend line for a set of data points is "the trend line is always a straight line".

Option D is correct answer.

What is a trend line?

A trend line is a straight line drawn over pivot highs or under pivot lows to show the prevailing direction of price.

There are about three rules to follow when drawing a trend line and they include the following;

to draw a trend line in an up trend, two lows must be connected by a straight line. to draw a trend line in a down trend line, two highs must be connected by a straight line. a trend line should be connected by at least three highs or lows to make it valid.

Thus, we can conclude that, the basic rule or constant rule that must apply to a trend line is a straight line connecting two lows or two highs for down trend and up trend respectively.

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A car moving with an initial velocity of 45 ms¹ is brought to a stop in 5 s. Find:

a) the deceleration of the car

b)the distance needed to stop the car​

Answers

Answer:

a)  -9  [tex]m/s^2[/tex]

b)  112.5 meters

Explanation:

Here is a formula for acceleration.

[tex]a=\frac{V_{f} -V_{o} }{t}[/tex]

We are given

[tex]V_o=45[/tex] m/s

[tex]V_f=0[/tex] m/s

[tex]t=5[/tex] s

Lets solve for [tex]a[/tex].

[tex]a=\frac{0-45}{5}[/tex]

[tex]a=\frac{-45}{5}[/tex]

[tex]a=-9[/tex] [tex]m/s^2[/tex]

Here is a formula for displacment.

[tex]x=V_o t+\frac{at^2}{2}[/tex]

[tex]V_o=45[/tex] m/s

[tex]t=5[/tex] s

[tex]a=-9[/tex] [tex]m/s^2[/tex]

Lets solve for [tex]x[/tex].

[tex]x=45*5+\frac{-9*5^2}{2}[/tex]

[tex]x=225+\frac{-9*25}{2}[/tex]

[tex]x=225+\frac{-225}{2}[/tex]

[tex]x=225+-112.5[/tex]

[tex]x=225-112.5[/tex]

[tex]x=112.5[/tex]

An 80-cm-long, 1. 0-mm-diameter steel guitar string must be tightened to a tension of 2000 n by turning the tuning screws.

Answers

The correct answer is there is a stretch in the string 0.010m.

The string is and it is long.

The string's radius is

The string's tension is

the Young's modulus

Stretching out of the string

Young's modulus can be found in.

The string is longer than usual.

Consequently, the string gets shortened.

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a) You are trying to lift a woolly mammoth (5000 kg). You put a long piece of metal under the mammoth and place a large rock 2 m from the mammoth to serve as a fulcrum. You can supply about 2000 N of force. How far away from the fulcrum will you have to apply your force?

b) With the answer in part a), what is the practical issue with this answer (think about how a long thin rod behaves mechanically)? What might you do to be able to lift the mammoth, if you have friends to help? Be specific.

Answers

a. The force should be applied 5 m from the fulcrum

b. The issue is that deformation of the rod will occur.

In order to avoid this deformation, with the help of friends, the distance from the can be reduced and more force applied.

What is the principle of moments?

The principle of moments states that for a system in equilibrium, the sum of the clockwise moments about a point of rotation is equal to the sum of the anticlockwise moments about that point.

Mathematically;

clockwise moments = anticlockwise moments

The moment of a force is the product of the force and the perpendicular distance from its point of action.

Moment = force * perpendicular distance

From the data provided:

Let the woolly mammoth move in a clockwise direction and the applied force in an anticlockwise direction.

Let d be the perpendicular distance of the applied force from the fulcrum

5000 * 2 m = 2000 * d

d = 5 m

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name two different objects you could use to light a room if you have a power cut. for each object describe the energy transfer and changes to energy stores that occur when it lights up the room

Answers

Answer:

candle and hand torch

Explanation:

we can find a light energy and heat energy from the candle but only light energy for hand torch

why is DE parallel to BC ?

Answers

Answer:

Given, DE is parallel to BC. From the figure, in ADE and ABC ∠ A = ∠ A (Common angle) Since, DE is parallel to BC therefore the below angles will be equal because they are corresponding angles. ⇒ ∠ D = ∠ B (Corresponding angles) and (Corresponding angles) Therefore, by AAA congruence criteria, the triangles ADE and ABC

Explanation:

A decibel meter reads a sound intensity of 80 dB when you stand 2 m from a loudspeaker. What will the meter read (in dB) if you stand 40 m away?

Answers

Answer:

Explanation:

L₁ =80 dB

S₁ = 2 m

S₂ = 40 m

__________

L₂ - ?

The intensity of the site is nearby:

ΔL = 10·lg(S₂/S₁)²

ΔL = 10·lg(40/2)² = 10·2·lg(20) = 20·1.3 = 26 dB

L₂ = L₁ - ΔL = 80 - 26 = 54 dB

While cycling, the athlete can go up to a maximum of 30 km/h. If his/her acceleration is 9 m/s2, then calculate the time the athlete takes to reach the maximum speed.

Answers

The time the athlete takes to reach the maximum speed will be 0.93 seconds

acceleration = change in speed / time

initial speed = 0

final speed = 30 km / h = 8.33 m/s

acceleration = 9 [tex]m/s^{2}[/tex]

acceleration = change in speed / time

time =  change in speed  / acceleration  = 8.33 / 9 = 0.93 seconds

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a 2kg box with some initial velocity slides up a frictionless ramp which is at a 15-degree angle to the ground until the box comes to rest 1-sec later. Find the work done on the box.

Answers

Answer:

Approximately [tex](-6)\; {\rm J}[/tex], assuming that [tex]g = 9.81\; {\rm m \cdot s^{-2}}[/tex].

Explanation:

Let [tex]m[/tex] denote the mass of this box.

Decompose the weight [tex]m\, g[/tex] of the box into two components: perpendicular to the slope [tex](-m\, g)\, \cos(15^{\circ})[/tex] and parallel to the slope [tex](-m\, g)\, \sin(15^{\circ})[/tex]. The perpendicular component is balanced with the normal force of the slope on the box. In contrast, since there is no friction between the box and the slope, the parallel component isn't balanced and will be equal to the net force on the box:

[tex]F_{\text{net}} = (-m\, g) \sin(15^{\circ}})[/tex].

Note that [tex]F_{\text{net}}[/tex] is constant during this [tex]t = 1\; {\rm s}[/tex].

The acceleration [tex]a[/tex] of this box will be:

[tex]\begin{aligned}a &= \frac{F_{\text{net}}}{m}\\ &= \frac{(-m\, g) \sin(15^{\circ})}{m} \\ &= (-g)\, \sin(15^{\circ})\end{aligned}[/tex].

Let [tex]u[/tex] denote the initial velocity of this box. Since after the [tex]t = 1\; {\rm s}[/tex] of acceleration at [tex]a = (-g)\, \sin(15^{\circ}})[/tex] the velocity of the box is [tex]v = 0\; {\rm m\cdot s^{-1}}[/tex], the initial velocity of this box will be:

[tex]\begin{aligned} u &= v - a\, t \\ &= 0 - (-g)\, \sin(15^{\circ})\, t \\ &= g\, t\, \sin(15^{\circ}})\end{aligned}[/tex].

Initial kinetic energy of this box would be:

[tex]\begin{aligned} (\text{KE}) &= \frac{1}{2}\, m\, u^{2} \\ &= \frac{1}{2}\, m\, (g\, t\, \sin(15)^{\circ}})^{2}\end{aligned}[/tex].

The kinetic energy of this box is [tex]0[/tex] when the box is at rest. The change in kinetic energy was [tex](1/2)\, m\, (g\, t\, \sin(16^{\circ}))^{2}[/tex]. That energy change should be the opposite of the work the external force weight did on this box.

Substitute in [tex]m = 2\; {\rm kg}[/tex], [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], [tex]t = 1\; {\rm m\cdot s^{-1}}[/tex] to find the change in kinetic energy and hence the work that the net force did on the box:

[tex]\begin{aligned} (\text{Work Done}) &= -(\text{Kinetic energy change}) \\ &= -\frac{1}{2}\, m\, (g\, t\, \sin(15)^{\circ}})^{2} \\ &= -\frac{1}{2}\times 2\; {\rm kg} \times (9.81\; {\rm m\cdot s^{-2}} \times 1\; {\rm s} \times \sin(15^{\circ})^{\circ} \\ &\approx (-6)\; {\rm J}\end{aligned}[/tex].

Edward swings his tennis racket to return a serve. His 10 kg racket swings forward with a speed of 8 m/s and after colliding with the tennis ball it is
slowed to 4 m/s. The 1 kg tennis ball was served toward Edward with a speed of 20 m/s. How fast was the tennis ball moving after the collision with
the racket?

Answers

The final velocity of the tennis ball after the collision is 20 m/s in opposite direction.

What is the final velocity of the tennis ball?

The final velocity of the tennis ball is determined by applying the principle of conservation of linear momentum as shown below.

Mathematically, the formula is given as;

m₁u₁ + m₂u₂ = m₁v₁  + m₂v₂

where;

m₁ is the mass of the racket = 10 kgu₁ is the initial velocity of the racket = 8 m/sm₂ is the mass of the tennis ball = 1 kgu₂ is the initial velocity of the tennis = 20 m/sv₁ is the final velocity of the racket = 4 m/sv₂ is the final velocity of the tennis ball = ?

(10 x 8) + (-20)(1) = 10(4) + (1)v₂

80 - 20 = 40 + v₂

80 - 20 - 40 = v₂

20 m/s = v₂

Thus, the final velocity of the tennis ball is in opposite direction.

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7. Using the idea of Impulse, explain why a field goal kicker should 'kick through the ball', meaning extend their foot
as high up as possible at the end of the kick.

Answers

Answer:

Impulse is the amount of force put on an object in a certain amount of time. Therefore when kicking a ball and "kicking through it" it extends the period of time this force is applied in turn increasing its impulse. Impulse is equal to change in momentum. momentum is equal to mass times velocity and since mass of the ball doesn't change therefore the velocity is increased and performance increased.

a 4500 kilogram truck travels in a straight line at 10 ms what is its momentum

Answers

40,000 kg m/s will be the momentum if the truck at a truck mass of 4500kg and velocity of 10 m/s.

Given mass of a truck = 4000 kg

truck mass = 4 grams

velocity = 10 m/s

The formula of momentum will be:

p = mv

where, p = momentum

           m = truck mass

           v = velocity

substituting the values, we get:

momentum = 4000 × 10

momentum = 40000 kg m/s

Thus the momentum of the truck is 40,000 kg m/s

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Two insects A and B fly in space with a uniform velocity VA= i+4j+3k and VB =4i+2j-4k in m/s. With respect to a stationary observer at the origin. Show the insect fly at right angles to each other and determine their distance apart after 50

Answers

Distance travelled by insects A and B is respectively 50√26 unit and 300 unit.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Uniform velocity of insect A: [tex]\bold{v_A}[/tex] =  i+4j+3k unit.

Uniform velocity of insect B: [tex]\bold{v_B}[/tex] =  4i+2j-4k unit.

Now dot product of two velocity vector is:

[tex]\bold{v_A}[/tex]·[tex]\bold{v_B}[/tex] = 50 (i+4j+3k)·50( 4i+2j-4k).

= 2500(4 + 4×2 + 3×(-4))

= 0.

Hence, the velocity vectors of two insects are perpendicular to each other. So, the insect fly at right angles to each other.

After time t = 50 unit, Position of insect A: [tex]\bold{X_A}[/tex] = time* velocity

= 50 (i+4j+3k) unit.

After time t = 50 unit, Position of insect B: [tex]\bold{X_B}[/tex] = time* velocity

= 50( 4i+2j-4k).

So, After time t = 50 unit, insect A travels a distance = 50 ×√(1²+4²+3²) = 50√26 unit.

After time t = 50 unit, insect B travels a distance = 50 ×√(4²+2²+(-4)²) = 300 unit.

Hence, distance travelled by insects A and B is respectively 50√26 unit and 300 unit.

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Must two bodies of equal momentum be moving in the same direction?

Answers

Yes, if two bodies have the same momentum, the velocities of the two objects needs to be equal to be moving in the same direction.

What is momentum?

Momentum is the product of mass and velocity of a body in motion. It is a vector quantity.

Two bodies of equal momentum can only move in the same direction if their velocities are equal. This is because both the velocity and the momentum are vector quantities. Momentum is the product of mass, which is a scalar quantity and the velocity, which is a vector.

In conclusion, for two objects to have the same momentum and for their directions to be the same, they need to have the same velocity.

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Yes,  two bodies of equal momentum must be moving in the same direction.

What is momentum?

We know that momentum is the product of the mass and the velocity of the object, In fact, momentum is a vector quantity and it should be clearly stated here that the direction of the momentum vector have to be the direction of the velocity vector.

With this said, when we say that two object have the same momentum we are essentially saying that the velocity vector of the two bodies have to pointing in the same direction. Once the direction is not the same, the momentum of the objects can not ever be the same!

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4. The angle of projection at which a projectile attains the minimum range is A. 45⁰ B. 60⁰ C. 76⁰ D. 90⁰ E. None​

Answers

Explanation:

Free Solutions to GR BATHLA & SONS BIOLOGY (HINGLISH) Class 12 book Chapters, Questions, Answers and Solutions 2022



____is formed either from water present in the atmosphere as snow, sleet, or from exposure of liquid____
to a temperature below___F.

Answers

Impact ice is formed either from water present in the atmosphere as snow, sleet, or from exposure of liquid water to a temperature below 32°F.

What is meant by impact ice ?Impact ice, a kind of induction icing, may form wherever that the temperature is close to or below zero degrees Celsius. Even on a fuel-injected engine, impact ice can clog the air filter and prevent the engine from getting the necessary air for combustion. As instructed by your POH/AFM, turn on alternative air or carburetor heat if you detect impact ice.Carburetor icing (ice that forms in the carburetor) happens when the venturi's decline in air pressure causes the moisture-filled air to cool quickly or as a result of gasoline evaporation.The ensuing ice buildup in the intake tube of the carburetor can significantly lower engine performance. In extreme circumstances, the intake flow might be so low that the engine can stall.

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Based on the nasa institute for space studies climate model, observed temperature increases are best represented when it includes the influences of.

Answers

Using information from the NASA Institute for Space Studies The best representation of observed temperature increases in climate models is when orbital movements are taken into account.

solar variationshuman-made aerosolsgrowth in greenhouse gas emissionsgrowth in greenhouse gas emissions

What is climate model?

Since 1960, scientists have been aware that people are increasing the atmospheric concentration of chemicals that trap heat.Climate changes will worsen if greenhouse gas emissions continue. A warmer atmosphere, a warmer and more acidic ocean, higher sea levels, and more significant changes in precipitation patterns are anticipated in the future.Climate prediction models' fundamental finding is that human activity enhances global warming and boosts the average global temperature.

Hence solar variations, human-made aerosols, growth in greenhouse gas emissions, growth in greenhouse gas emissions is a correct answer.

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What is the momentum of an 8 kg bowling ball rolling at 2 m/s straight to the pins?

Answers

The momentum of an 8 kg bowling ball rolling at 2 m/s straight to the pins is  16 kg m/s.

What is momentum?

As momentum depends on both velocity and the direction of the body's motion, it is quantified by "mass velocity". Since velocity is a vector and mass is a scalar, momentum is a vector quantity. It is given by the formula:

p = mv

p = 8 × 2

p = 16 kg m/s

What is velocity?

Velocity can be defined as the rate at which something moves in a specific direction. as the speed of a car driving north on a highway or the pace at which a rocket takes off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.

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