Answer:
A
Explanation:
As you go deeper, the pressure increases because the water is going farther away from the air and atmosphere
A boat moves with a velocity of 15m/s, N in a river which flows with a velocity of 8.0m/s, Calculate the boat’s resultant velocity with respect to North
The boat’s resultant velocity with respect to North is determined as 17 m/s.
Resultant velocity of the boatThe boat’s resultant velocity with respect to North is calculated as follows;
R² = Va² + Vb²
where;
R is resultant velocityVa is velocity of boatVb is velocity of riverR = √(Va² + Vb²)
R = √(15² + 8²)
R = 17 m/s
Thus, the boat’s resultant velocity with respect to North is determined as 17 m/s.
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5. A uniform solid ring of mass M = 10 kg and radius R = 2 m is initially rotating in mid-air with angular speed 20 rad/s [the Before state in figure (I) below]. It is then placed in contact with a surface (assume that the surface immediately feels the full weight of the ring). (1) M Before Wi (II) wf V Ө ə Ө After Ө wf H ? (a) What kind of frictional force acts on the ring upon contact with the surface? (b) If the ring begins to roll smoothly to the right with speed v = 10 m/s after 5 seconds of contact (the After state), find the coefficient of friction corresponding to the frictional force you mentioned in (a). (c) What is the increase in the thermal energy of the ring/surface system from right before the ring contacts the surface, to when the ring starts to roll smoothly? The ring then rolls smoothly up a ramp of 0 = π/6 rad and H = 5 m [see figure (II)] (d) What is the horizontal distance, from the end of the ramp, at which the ring lands?
(a) The kind of frictional force acts on the ring upon contact with the surface is kinetic friction before rolling and afterwards it is static friction.
(b) If the ring begins to roll smoothly to the right with speed v = 10 m/s after 5 seconds of contact (the After state), the coefficient of friction corresponding to the frictional force is 0.612
(c) The increase in the thermal energy of the ring/surface system from right before the ring contacts the surface, to when the ring starts to roll smoothly is 7500 J.
(d) The horizontal distance, from the end of the ramp, at which the ring lands is 7.78 m
What is frictional force?When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction force.
Given is a uniform solid ring of mass M = 10 kg and radius R = 2 m is initially rotating in mid-air with angular speed 20 rad/s [the Before state in figure (I) below]. It is then placed in contact with a surface (assume that the surface immediately feels the full weight of the ring).
(a) The kind of frictional force acts on the ring upon contact with the surface is kinetic friction before rolling and afterwards it is static friction.
(b) angular frequency = velocity / radius
ωf = 10/2 = 5 rad/s and ωi = 20 rad/s
Angular acceleration, α = ωf - ωi /t
Put the values, we get
α = -15/5 = -3 rad/s²
Coefficient of friction, μ = a/g = rα/g
Plug the values, we get
μ = 0.612
Thus, the coefficient of friction corresponding to the frictional force is 0.612.
(c) The energy lost = heat generated
energy lost = 1/2 Iω² + 1/2 Mv²
energy lost = 1/2 MR²ω² + 1/2 Mv²
Plug the values, we get
energy lost = 7500 J
Thus, the increase in the thermal energy is 7500 J.
(d) The horizontal distance, from the end of the ramp, at which the ring lands
s= (v- 2gH) sin2θ /g
s = (10 - 2x (-9.81)x5 ) sin (2x π/6) / 9.81
s = 7.78m
Thus, the horizontal distance is 7.78 m
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If the distance between two objects is cut in half, what happens to the
gravitational force between them?
A. It decreases to 1/2 its original magnitude.
B. It decreases to 1/4 its original magnitude.
O
C. It increases to 4 times its original magnitude.
D. It increases to 2 times its original magnitude.
A skier is standing on a horizontal patch of snow. She is holding onto a horizontal tow rope, which is about to pull her forward. The skier’s mass is 59 kg, and the coefficient of static friction between the skies and the snow is 0.14. What is the magnitude of the maximum force that the tow rope can apply to the skier without causing her to move?
The magnitude of the maximum force that the tow rope can apply to the skier without causing her to move will be 81.03 N,
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
It is defined as the product of the coefficient of friction and normal reaction.
On resolving the given force and acceleration. Mathematically aion in the different components and balancing the equation gets. Components in the x-direction.
The normal force is balanced by weight;
N = mg
The magnitude of the maximum force that the tow rope can apply to the skier without causing her to move is;
F = μN
F= μmg
F=0.14 × 59 kg × 9.81 m/s²
F = 81.03 N
Hence, the magnitude of the maximum force will be 81.03 N,
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If a jet is travelling horizontally at 100m/s at a height of 500m above the ground and a jet drops a bomb to the ground. Where does the bomb strike the ground relative to the point atwhich it is released ?A.100m B.1km C.500m D.5km
The bomb strike the ground relative to the point at 1km . B
How to determine the distanceUsing the equation
h = 1/2 gt^2
500 = 1/2 * 10* t^2
500 = 5t^2
t = √500/5
t = √100
t = 10seconds
To find the distance,
Distance = velocity * time
Distance = 100 ÷ 10
Distance = 1000m = 1km
Therefore, the bomb strike the ground relative to the point at 1km . B
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the 3kg object in figure is released from rest at height of on a curved frictionless ramp. at the foot of the ramp is a spring of force constant 400N/m. the object slides down the ramp and into the spring,compressing it a distance x before coming momentarily to rest.
a) find x
b) describe the motion of the object (if any) after the block momentarily comes to rest?
(a) The compression of the spring is 7.4 cm.
(b) When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
Compression of the spring [ x ]
The compression of the spring is calculated by applying Hooke's law as follows;
F = kx
x = F/k
x = (mg)/k
x = (3 x 9.8)/400
x = 0.074 m
x = 7.4 cm
When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
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what is the output voltage of a transformer if the input is 240volts, and the number of turns on the primary coil is 1200 and on the secondary coil is 200.
The output voltage of a transformer is 40V.
What is an output voltage?An output voltage is the voltage released by a device, such as a voltage regulator or a generator.
The formula to calculate Output voltage of transformer is:
[tex]\frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }[/tex]
here, [tex]V_{s}[/tex] is the secondary voltage, [tex]V_{p}[/tex] is the primary voltage, [tex]N_{s}[/tex] is the number of secondary windings and [tex]N_{p}[/tex] is the number of primary windings.
According to the question.
[tex]N_{p}[/tex] =1200 , [tex]N_{s}[/tex]=200 , [tex]V_{p}[/tex]=240V ,[tex]V_{s}[/tex]= ?
By using the formula of Output voltage,
[tex]{V_{s} } = \frac{V_{p}N_{s} }{N_{p} }[/tex]
=[tex]\frac{240*200}{1200}[/tex]
[tex]=40V[/tex]
Therefore, 40V is the output voltage of a transformer.
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What does Charles Darwin’s theory of natural selection state about traits?
A.
Traits that increase the survival rate of a population are rarely passed on to future generations since they can affect reproduction.
B.
Traits that prevent people from reproducing are passed on to future generations to ensure their survival.
C.
Traits that make it more likely for a species to survive or reproduce become less common in a population over time.
D.
Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations.
Charles Darwin's theory of natural selection states that features that offer survival or reproductive advantage are more likely to be handed down to subsequent generations.
What are traits?A trait is a distinctive pattern of behavior or conscious motivation that may be evaluated by peers or oneself.
Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations is Charles Darwin’s theory of natural selection state traits.
Hence option D is correct.
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Answer: option d
Explanation:
A house has a roof (colored gray) with the dimensions shown in the drawing. Determine the magnitude of the net force that the
atmosphere applies to the roof when the outside pressure drops suddenly by 13.2 mm of mercury, before the pressure in the attic can
adjust.
The magnitude of the net force that the atmosphere applies to the roof when the outside pressure drops suddenly is 1.9 x 10⁵ N.
What is pressure?The pressure is the amount of force applied per unit area.
Pressure p = Force/Area
Given is a house has a roof (colored gray) with the dimensions shown in the drawing. The outside pressure drops suddenly by 13.2 mm of mercury, before the pressure in the attic can adjust.
The pressure difference ΔP = 13.2 mm of Hg
The length of the roof l = 14.5m
the breadth of the roof h = 4.21m
The force exerted by pressure is
Force, F = P x A
= (13.2 mm of Hg) [(133 N/m²) /1 mm of Hg ](14.5 x 4.21)
= 107,170.6 N
Then the net vertical force
Fnet = 2F cos30
Fnet = 2 ( 107,170.6) cos30
Fnet = 185625 N
Fnet =1.9 x 10⁵ N
The direction of the force is downwards, since the horizontal components of the forces cancel each other.
Hence, magnitude of the net force is 1.9 x 10⁵ N
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the question in photo
Answer:
a
Explanation:
the following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t1=2sec and t2=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
(a) The average velocity of the particle in the time interval t₁=2sec and t₂=3sec is 10 m/s.
(b) The velocity and acceleration at any time t is v = (2ati + bj) m/s and a = 2ai m/s²
(c) The average acceleration in the time interval given in part (a) is 4 m/s².
Position of the particlex = at²i + btj
x = 2t²i + tj
Average velocity, at t₁=2sec and t₂=3secΔv = Δx/Δt
x(2) = 2(2)²i + 2j
x(2) = 8i + 2j
|x(2)| = √(8² + 2²) = 8.246
x(3) = 2(3)²i + 3j
x(3) = 18i + 3j
|x(3)| = √(18² + 3²) = 18.248
Δv = (18.248 - 8.246)/(3 - 2)
Δv = 10 m/s
Velocity and acceleration at any time, tx = at²i + btj
v = dx/dt
v = (2ati + bj) m/s
a = dv/dt
a = 2ai m/s²
Average accelerationa = 2ai m/s²
a = 2(2)(1)
a = 4 m/s²
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A car moves with the speed of 40km/hr for the first half distance and 60km/hr for second half distance.find average speed of car?
Answer:
50km/h
Explanation:
average = (a + b) / 2
average = (60 + 40) / 2
average = 50
How much work does a football player do in the weight room when he squats 150 kg up a distance of 1 meter?
How much work does he do if he does 3 sets of 10 squats in a row?
Answer:
See below
Explanation:
The work done equals the increase in Potential Energy
PE = mgh
= 150 * 9.81 * 1 = 1471.5 j
3 sets of 10 is 30 times this = 44145 j
The amount of work done by a football player in the weight room when he squats 150 kg will be equal to 1471.5 J.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship among different components. When a spring is compressed or stretched, its potential energy increases. If a steel ball is raised above the floor as opposed to falling to the ground, it has more potential energy. It is capable of carrying out additional work when raised.
Potential energy is a feature of systems rather than of particular bodies or particles; for instance, the system created up of Earth and the elevated ball has more energy stored as they become further apart.
Potential energy develops in systems components whose configurations, or spatial arrangement, determine the amount of the forces they apply to one another.
As per the instructions given in the question,
Work performed is equivalent to Potential Energy Increase,
PE = mgh
= 150 × 9.81 × 1
PE = 1471.5 J
Also,
3 sets of 10 are 30 times this = 44145 J
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Bianca is helping the theatre director at her school with lighting, sound, and set design for a school play. She will be choosing the materials that will be used on stage and on the walls of the theatre. After she reads the script and makes observations inside the theatre, she makes the following list of the factors to consider in her design.
The echoes throughout the theatre need to be reduced.
The set should not reflect too much light into the audience’s eyes.
The only lights available are white, purple, and yellow. The filters available are red and blue.
The blue sky on the set should appear black for Act 2.
Bianca draws a detailed illustration of her plan to show the theatre director. She labels it with the materials she plans to use.
Design Solutions: Based on Bianca’s criteria and model, which materials would you change on stage? Explain your reasoning
Bianca is helping the theatre director at her school with lighting, sound, and set design for a school play. She will be choosing the materials that will be used on stage and on the walls of the theatre the materilas neee to be changes is The only lights available are white, purple, and yellow.
What is echo ?A proper echo is a single mirrored image of the sound source. The phrase echo derives from the Greek ἠχώ (ēchō), itself from ἦχος (ēchos), "sound". Echo withinside the Greek peoples tale is a mountain nymph whose cappotential to talk changed into cursed, leaving her capin a position handiest to copy the ultimate phrases spoken to her.
Bianca draws a detailed illustration of her plan to show the theatre director. She labels it with the materials she plans to use the only lights available are white, purple, and yellow should be removed as to avoid the light refraction.
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A small sphere of mass 10 kg
is released from rest at a height of
15.0 m above the ground level.
The sphere experiences a constant
resistive force (due to air
resistance) of magnitude R = 10.0
N.
a) Calculate the speed of the
sphere after it has fallen
through a distance of 5.00 m
bCalculate the speed of the ball just before a it hits the gound.
Answer:
Approximately [tex]9.39 \; {\rm m\cdot s^{-1}}[/tex] after the sphere has travelled a distance of [tex]5\; {\rm m}[/tex].
Approximately [tex]16.3\; {\rm m\cdot s^{-1}}[/tex] right before touching the ground (a distance of [tex]15\; {\rm m}[/tex].)
Assumption: [tex]g = 9.81\; {\rm N\cdot kg^{-1}}[/tex].
Explanation:
Weight of the sphere: [tex]m\, g = 9.81\; {\rm N \cdot kg^{-1}} \times 10\; {\rm kg} = 98.1\; {\rm N}[/tex], downwards.
Drag on the sphere: [tex]10.0\; {\rm N}[/tex] upwards.
Net force on the sphere: [tex]98.1\; {\rm N} - 10\; {\rm N} = 88.1\; {\rm N}[/tex] downwards.
Acceleration of the sphere: [tex]a = F_\text{net} / m = 88.1\; {\rm N} / (10\; {\rm kg}) = 8.81\; {\rm m\cdot s^{-2}}[/tex].
Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex], where [tex]v[/tex] is the final velocity, [tex]u[/tex] is the initial velocity ([tex]0[/tex] in this case, as the sphere was released from rest,) and [tex]x[/tex] is the distance (displacement) that the sphere has travelled so far.
Rearrange this equation to obtain an expression for [tex]v[/tex]:
[tex]\displaystyle v = \sqrt{2\, a\, x + u^{2}}[/tex].
For example, after the ball travelled a distance of [tex]5.00\; {\rm m}[/tex], [tex]x = 5.00 \; {\rm m}[/tex]:
[tex]\begin{aligned} v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 8.81\; {\rm m\cdot s^{-2}} \times 5.0\; {\rm m} + 0} \\ &\approx 9.39\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
Similarly, [tex]x = 15.0\; {\rm m}[/tex] right before landing, such that:
[tex]\begin{aligned} v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 8.81\; {\rm m\cdot s^{-2}} \times 15.0\; {\rm m} + 0} \\ &\approx 16.3\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
An upward force is applied to a 6.0–kilogram box. This force displaces the box upward by 10.00 meters. What is the work done by the force on the box?
Answer:
588J
Explanation:
Work done = Fd
=wh=mgh
=6×9.8×10
=558J
Velocity (m/s)
50
40
30
20
10
0
A
Velocity vs Time
B
C
1 2 3 4 5 6 7 8 9 10
Time (s)
Use the information presented in the graph to answer
the questions.
Which segments show acceleration?
Which segment indicates that the object is slowing
down?
What is the velocity of segment B?
What is the acceleration of segment B?
Explanation:
⠀
⠀
(a) The segment A shows acceleration as velocity increases with the increase in time.
⠀
⠀
⠀
(b) The segment C shows the object is slowing down as the time increases in segment C, the velocity decreases and afterwards it comes to rest.
⠀
⠀
⠀
(c) The velocity is segment B is 40m/s. And in the diagram there is no change in velocity.
⠀
⠀
⠀
(d) The acceleration of segment B is zero. As there in no change in curve and it is moving with uniform velocity.
⠀
⠀
⠀
[tex] \: [/tex]
Thank you!Answer:
1 A and C
2 C
3 40m/s
4 zero
Explanation:
3. Sarah is a world-class diver in the women's 3-m springboard competition. Her height
h (in metres), above the water t seconds after she leaves the board is given by
h = -4.9t2 + 8.8t + 3. How long is Sarah in the air before she reaches the water?
Make sure to round your answer to the nearest tenth.
Answer:
2011, 2013, 2016 Alberta Education
Answer:
1.163 seconds
Explanation:
see the attached. solve the quadratic equation.
A room has a 60 Watt, a 100 Watt and a 150 Watt light bulb. How much does it
cost to use all the lamps for 2.5 hours at $0.08/ kWh?
The cost to use all lamps is $62.
room has 60 watts, 100 watts, and 150 watt light bulbs.Duration of using bulbs=2.5 hours power =$0.08kWh
power=energy/time
(60+ 100+150)=energy/2.5
energy=775 joule
cost for 1 hour=$0.08
= 775 * 0.08
= $62
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Answer:
6.2 cents
Explanation:
(60+100+150/1000)*2.5*8=6.2 cents
What is the weight of a 0.145kg baseball on the moon if the gravitational acceleration on the moon is approximately 1.625 m/s2
Answer:I would say that it would be about 2/3rds as fast as the moon and i have seen a similar question but it asked different info about it. I also believe that the basketball would have a lower weight due to it being in space. I feel bad saying this but i know that i got some info off this website when working with this and i hope it helps.
Explanation:
Note- I am new to Brainly so sorry if this isn't as helpful as you expected this to be.
Suppose the resistance of a copper wire is 1.05 N at 30°C.
Find the temperature at which the resistance becomes 1.50
Ω.
Answer:
42.9°C
Explanation:
Resistance of a conducting material is directly proportion to Temperature, that is, when being heated, their is more of collisions between the molecules of the material which as a result offers more opposition to the flow of current through it.
therefore R=kT
where R=resistance of the wire
T=Temperature
k= proportionality constant
when R=1.05 T=30°C
so k=1.05/30
k=0.035
when R=1.5 k=0.035
so T=1.5/0.035
T=42.9°C. or 43°C approximated
Need help with this question
Answer:
1. 92, 138, 92
2. 7, 7, 7
3. 17, 18, 17
4. 29, 34, 29
Explanation:
the number on the bottom is always going to be the atomic number, or the number of protons.
the number on the top is going to be the atomic mass number, which is the sum of the number of protons and neutrons.
there is always going to be the same number of electrons as protons, because that was the overall charge of each atom is 0.
for example, for the first one:
there are 92 protons
there are 230 - 92 = 138 neutrons
there are 92 electrons
During World War II, it was found that r, the radius of the shockwave produced during an atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density, .
The atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.
What is an atomic bomb?An atomic bomb is type of nuclear weapon that releases a vast amount of energy upon explosion in the form of fission reaction.
During an explosion of atomic bomb, a cloud of mushroom fire is formed which vaporises anything found within it. The extent of destruction depends on:
energy released, W, the elapsed time, t, and the air density.Therefore, the atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.
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11. Trait theory claims that
O A. people from the same locations
share the same personality type.
B. you always behave the way your
personality type says you will.
O C. your personality is made up of a
number of traits.
O D. you have one characteristic that
defines your entire personality.
If the Moon had twice as much mass and still orbits Earth at the same distance, ocean bulges on Earth would be
smaller.
larger.
unequal in size.
not significantly different.
none of the available options
Ocean bulges on Earth would be bigger if the Moon had twice as much mass and yet orbited the planet at the same distance. Option B is correct.
What is ocean bludge?The fluid and moveable ocean water are drawn towards the moon by the gravitational attraction between the moon and the Earth.
The ocean nearest to the moon experiences a bulge as a result, and as the Earth rotates, the affected seas' locations shift.
The Moon's bulges in the oceans would be larger if it had twice the mass and orbited Earth at the same distance.
Hence option B is corect.
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The following table contains financial information for Trumpter Inc. before closing entries:
Cash
Supplies
Prepaid Rent
Salaries Expense
Equipment
Service Revenue
Miscellaneous Expenses
Dividends
Accounts Payable
Common Stock
Retained Earnings
$13,100
6,000
3,800
5,000
65,900
28,000
20,100
4,000
3,100
66,100
20,700
What is the amount of Trumpter's total assets?
The Total assets based on the given table is $88,800.
What are assets?An asset refers to a resource owned by an individual or company which has tangible value and whose value is expected to rise in the future.
The Total assets based on the table = Cash + Supplies + Prepaid rent + Equipment
Total assets = 13,100 + 6,000 + 3,800 + 65,900
Total assets = $88,800
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What’s the allowable ampacity of a No. 12 copper wire with type THHN insulation installed in a raceway with 35 wires? Question 3 options: A) 10 A B) 15 A C) 8 A D) 12 A
The allowable ampacity of a No. 12 copper wire with type THHN insulation installed in a raceway with 35 wires is approximately 12 amperes. This is best represented by option D.
According to the National Electrical Code Table (NEC), a derating factor must be applied for any raceway with more than three current-carrying conductors (in our case, copper wires). In a raceway with 31-40 current-carrying conductors, the derating factor is 50%. Because the ampacity of a No. 12 copper wire usually is 25 amperes (A), we can multiply this by our derating factor to find that:
25 • 0.50 = 12.5
The exact allowable ampacity of this copper wire is 12.5 amperes; however, we can round down to find that the closest answer is 12 A.
Hence, option D represents the best answer.
Answer:
D) 12 A
Explanation:
You want to know the allowable ampacity of AWG 12 type THHN copper wire in a raceway with 35 wires.
Nominal ampacityTable 310.15(B)(16) of the 2017 National Electrical Code gives the nominal rating of AWG 12 type THHN copper wire as 30 A when installed in an environment with a temperature of 30 °C or less.
DeratingTable 310.15(B)(3)(a) gives the adjustment factor when there are more than three conductors in a raceway or cable. For 31–40 conductors, the ampacity must be derated to 40% of its nominal value.
In a raceway with 35 wires, the allowable ampacity of THHN AWG 12 wire is ...
(30 A)(0.40) = 12 A
__
Additional comment
For environmental temperatures above 30 °C, Table 310.15(B)(2)(a) gives additional derating factors. The adjustment factor for temperatures up to 50 °C (122 °F) is 0.82, which would bring the allowable ampacity down to about 9.8 A.
A car and a truck, starting from rest, have the same acceleration, but the truck moves twice the length of time. Compared with the car, the truck will travel
Compared with the car, the truck will travel four times as far.
The initial velocity of car and truck, u = 0
The acceleration of both the truck and car = a
The length of time for the acceleration = t
Let the time the truck accelerated be 2t
How to calculate the distance traveled by car and truck?The distance traveled by car is calculated as;
s = ut + ¹/₂at²
s₁ = 0(t) + ¹/₂at²
s₁ = ¹/₂at²
The distance traveled by truck
s = ut + ¹/₂at²
s₂ = 0(2t) + ¹/₂a (2t)²
s₂ = ¹/₂a x 4t²
s₂ = 4 (¹/₂at²)
s₂ = 4(s₁)
We can conclude that the Truck distance is four times the car distance.
Therefore, Compared with the car, the truck will travel four times as far.
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Suppose astronomers find an earth-like planet that is twice the size of Earth. What must be the mass of this planet such that the gravitational force at the surface would be identical to Earth’s?
This planet's mass must be four times that of Earth in order for the gravitational pull at its surface to be comparable to Earth's.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
The planet's mass is directly related to its mass at the surface and inversely proportional to the square of its radius;
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
The astronomers discovered a planet twice the size of Earth that resembles Earth.
This planet's mass must be four times that of Earth in order for the gravitational pull at its surface to be comparable to Earth's.
Hence the masses of this planet will be 4 times that of Earth.
To learn more about Newton's law of gravitation, refer to the link.
https://brainly.com/question/9699135.
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A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 n. What must be done to find the acceleration of the sled? check all that apply.
The acceleration of this sled can be calculated by doing: option A, B, E and F.
How to calculate the acceleration?The acceleration of this sled can be calculated by using Newton's Second law of motion. Mathematically, the acceleration of an object is given by this formula:
Net force = Mass × acceleration
Deductively, the acceleration of this sled can be calculated by doing the following:
The force of gravity must be broken into its parallel and perpendicular components.Acceleration can be found by dividing the net force by mass.Trigonometry can be used to solve for the magnitude of the force components.Net force must be found before acceleration can be found.Read more on acceleration here: brainly.com/question/14344386
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Complete Question:
A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 n. What must be done to find the acceleration of the sled? check all that apply.
A. The force of gravity must be broken into its parallel and perpendicular components.
B. Acceleration can be found by dividing the net force by mass.
C. Acceleration can be found by multiplying the net force by mass.
D. The magnitude of the force components must be multiplied by gravity.
E. Trigonometry can be used to solve for the magnitude of the force components.
F. Net force must be found before acceleration can be found.
Answer:
To find the acceleration, you do 20N/50kg = 0.4 m/s^2
Explanation:
example: a = F/m = 10/2 = 5 m/s2
