MARKING AS BRAINLIEST!! Starr if given functions are inverse)!

Answer:

hi amki nai patajjdkfkejd

Answer:

true

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

A

[tex]\frac{12}{2\pi }[/tex]  ≈ 1.91 < 2

B

8 - π 8 - 3.14 = 4.86 < 5

C

10π ≈ 31.42 > 30 ← True

D

π + 4 = 3.14 + 4 = 7.14 > 7

Option C is a true inequality

Answer:

No, they are not.

Step-by-step explanation:

If you distributed 12(x - 4y), you would get 12x - 48y. If you distributed 3(3x-y), you would get 9x- 3y. 12x - 48y and 9x - 3y are not equivalent. Hope this helped!

Answer:

the domain is all real numbers except  x=3

Step-by-step explanation:

The domain is the values that x can take

X can be all real number except when the denominators equal zero

x-3 ≠ 0

x≠3

the domain is all real numbers except 3

9514 1404 393

Answer:

  (b) √65

Step-by-step explanation:

The modulus of a complex number is the root of the sum of the squares of the real and imaginary parts.

  |1 -8i| = √(1² +(-8)²) = √(1+64) = √65

Answer:

− 8 a ^7

Step-by-step explanation:

See picture for steps :)

Answer:

35/37

Step-by-step explanation:

sin(B)=(AC)/(AB) = 35/37

9514 1404 393

Answer:

  roots are between -5 and -4, and between -1 and -2.

Step-by-step explanation:

The graph shows the roots are approximately ...

  -4.2 — between -5 and -4

  -1.8 — between -2 and -1

Answer:

3 feet

Step-by-step explanation:

Let x represent the length of the shortest board.

Since the other is two times as long, its length can be represented by 2x.

Create an equation to represent the situation, and solve for x:

x + 2x = 9

3x = 9

x = 3

So, the shortest board is 3 feet long

Step-by-step explanation:

if that is truly the full problem description, then we have

10x - x + 5 = 41

=>

9x = 36

our simply

x = 4

so, I am not sure, what your teacher wants to see as result.

there is an infinite number of equations I could find, all with the solution x = 4.

If you're familiar with surface integrals, start by parameterizing the surface by the vector-valued function,

r(u, v) = 3 cos(u) sin(v) i + 3 sin(u) sin(v) j + 3 cos(v) k

with 0 ≤ u ≤ 2π and 0 ≤ v ≤ arccos(1/√8).

Then the area of the surface (I denote it by S) is

[tex]\displaystyle\iint_S\mathrm dA = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}\left\|\dfrac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm dv\,\mathrm du \\\\ = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}9\sin(v)\,\mathrm dv\,\mathrm du \\\\ =18\pi \int_0^{\arccos\left(1/\sqrt8\right)}\sin(v)\,\mathrm dv = \boxed{\frac{9(4-\sqrt2)\pi}2}[/tex]

Answer:

?

Step-by-step explanation:

Answer:

9 is. ................m.m..mk

Answer:

12 1/2

Step-by-step explanation:

2 x 5 = 10

1/2 x 5 = 2 1/2

10 + 2 1/2 = 12 1/2

Answer:

see explanation

Step-by-step explanation:

Using the Sine rule in all 3 questions

(1)

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values , firstly calculating ∠ B

[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]

[tex]\frac{a}{sin78}[/tex] = [tex]\frac{18}{sin53}[/tex] ( cross- multiply )

a sin53° = 18 sin78° ( divide both sides by sin53° )

a = [tex]\frac{18sin78}{sin53}[/tex] ≈ 22.0 ( to the nearest tenth )

(3)

[tex]\frac{c}{sinC}[/tex] = [tex]\frac{a}{sinA}[/tex] , substitute values

[tex]\frac{35}{sinC}[/tex] = [tex]\frac{45}{sin134}[/tex] ( cross- multiply )

45 sinC = 35 sin134° ( divide both sides by 35 )

sinC = [tex]\frac{35sin134}{45}[/tex] , then

∠ C = [tex]sin^{-1}[/tex] ( [tex]\frac{35sin134}{45}[/tex] ) ≈ 34.0° ( to the nearest tenth )

(5)

Calculate the measure of ∠ B

∠ B = 180° - (38 + 92)° = 180° - 130° = 50°

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values

[tex]\frac{BC}{sin38}[/tex] = [tex]\frac{10}{sin50}[/tex] ( cross- multiply )

BC sin50° = 10 sin38° ( divide both sides by sin50° )

BC = [tex]\frac{10sin38}{sin50}[/tex] ≈ 8.0 ( to the nearest tenth )

Answer:

3

Step-by-step explanation:

3 = 9 \:th \\ 1 = 3 \\ 3 \times 3 = 9 \\ 9 \div 3 = 3 \\ so \: that \: answer \: is \: 3

Answer:

y=-2/3x+6

Step-by-step explanation:

Graph it

Answer:

y= -2/3 x + 6

Step-by-step explanation:

1. In the graph, you can see the points (0,6) and (6,2)

2. Since you have all the available options, you can input both points into all equations.

3. In this case, the correct answer is y= -2/3 x + 6

Answer: true

Step-by-step explanation:

Answer:

D NO IS THE WRITE ANSWER .

Answer:

D)

Step-by-step explanation:

Answer:

we know that all Lenght of circle is 2πr so 2*π*7=14π

Step-by-step explanation:

14π equal to 360°

but we need just 135° so we should write it kind of radian(π)

if 14π=360°

x=135°

14π*135=360°*x 14π*27=72*x ........= 14π*3=8*x

7π*3=4*x ....... X=21π/4

The length of the arc is 21/π4 in

An answer is an option A. 21/π4 in

The arc period of a circle can be calculated with the radius and relevant perspective using the arc period method.

⇒angle= arc/radius

 ⇒  135°=arc/7

⇒ arc =135°*7

  ⇒arc=135°*π/180° *7in

⇒arc = 21/π4 in

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I think the given integral reads

[tex]\displaystyle \int_{-3}^3 \int_0^{9-x^2} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

In cylindrical coordinates, we take

x ² + y ² = r ²

x = r cos(θ)

y = r sin(θ)

and leave z alone. The volume element becomes

dV = dx dy dz = r dr dθ dz

Then the integral in cylindrical coordinates is

[tex]\displaystyle \boxed{\int_0^\pi \int_0^{(\sqrt{35\cos^2(\theta)+1}-\sin(\theta))/(2\cos^2(\theta))} \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta}[/tex]

To arrive at this integral, first look at the "shadow" of the integration region in the x-y plane. It's the set

{(x, y) : -3 ≤ x ≤ 3 and 0 ≤ y ≤ 9 - x ²}

which is the area between a paraboloid and the x-axis in the upper half of the plane. So right away, you know θ will fall in the first two quadrants, so that 0 ≤ θ ≤ π.

Next, r describes the distance from the origin to the parabola y = 9 - x ². In cylindrical coordinates, this equation changes to

r sin(θ) = 9 - (r cos(θ))²

You can solve this explicitly for r as a function of θ :

r sin(θ) = 9 - r ² cos²(θ)

r ² cos²(θ) + r sin(θ) = 9

r ² + r sin(θ)/cos²(θ) = 9/cos²(θ)

(r + sin(θ)/(2 cos²(θ)))² = 9/cos²(θ) + sin²(θ)/(4 cos⁴(θ))

(r + sin(θ)/(2 cos²(θ)))² = (36 cos²(θ) + sin²(θ))/(4 cos⁴(θ))

(r + sin(θ)/(2 cos²(θ)))² = (35 cos²(θ) + 1)/(4 cos⁴(θ))

r + sin(θ)/(2 cos²(θ)) = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))]

r  = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))] - sin(θ)/(2 cos²(θ))

Then r ranges from 0 to this upper limit.

Lastly, the limits for z can be converted immediately since there's no underlying dependence on r or θ.

The expression above is a bit complicated, so I wonder if you are missing some square roots in the given integral... Perhaps you meant

[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

or

[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{\sqrt{9-x^2-y^2}} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

For either of these, the "shadow" in the x-y plane is a semicircle of radius 3, so the only difference is that the upper limit on r in either integral would be r = 3. The limits for z would essentially stay the same. So you'd have either

[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

or

[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{\sqrt{9-r^2}} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

Answer:

12

Step-by-step explanation:

Answer:

Step-by-step explanation:

Number of attendees the first day = x.

Solve the following equation for x:

9514 1404 393

Answer:

  20

Step-by-step explanation:

A whole can be divided into two pieces that are each 1/2 of the whole.

 (10 wholes) × (2 pieces per whole) = 20 pieces

Answer:

54

Step-by-step explanation:

p(x)=x^2+50, p(2)=2^2+50=54

P(x) = x² + 50

P(2) = 2² + 50

= 54

P(6) = 6²+50

= 86

P(7) = 7²+ 50

= 99

P(8) = 8²+50

= 114

P(9) = 9²+50

= 131

Answered by Gauthmath must click thanks and mark brainliest

Answer:

B. 18 sq in.

Step-by-step explanation:

Surface area of the triangular pyramid excluding the base = area of the three triangular faces = 3(½ × base × height)

Where,

base = 3 inches

height = ED = 4 inches

Plug in the known values into the equation

Surface area of the triangular pyramid excluding the base = 3(½ × 3 × 4)

= 3(3 × 2)

= 3(6)

= 18 sq in.

Answer:

$30.1 million * .000000038

$1.14

did the question say how much the ticket cost?

if it was $1 then you would have to subtract $1 so the expected value would be 14 cents

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

120 divided by 100 =1.2 x 10

9514 1404 393

Answer:

  139.39 in

Step-by-step explanation:

The length of a semicircle of diameter D is ...

  C = (1/2)πD

For the given diameter of 27 inches, the length of the curved edge of the figure is ...

  C = 1/2(3.14)(27 in) = 42.39 in

__

The perimeter of the figure is the sum of the side lengths. Clockwise from left, that sum is ...

  P = 27 + 35 + 42.39 + 35 = 139.39 . . . inches

The perimeter of the figure is 139.39 inches.

The length of YZ in the similar triangle given is calculated using Pythagoras theorem which gave us 16√3

Similar triangles are two or more triangles that have the same shape but may be different sizes. They have the same angles and corresponding sides that are proportional.

In this problem, we need to use the concept of ratio and proportions to find the length of YZ

However, we can simply use Pythagoras theorem to determine the length.

According to Pythagoras' Theorem, the square of the hypotenuse, or side opposite the right angle, in a right-angled triangle, is equal to the sum of the squares of the other two sides.

It is expressed as the equation a² + b² = c².

This is because the triangles forms a right angled triangle and we can easily apply that here.

YZ² = 16² + (16√2)²

YZ² = 768

YZ = √768

YZ = 16√3

The length or distance from point Y to WX which is the same as the length of YZ is calculated as 16√3.

Learn more on similar triangle here;

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Answer:

C. 16

Step-by-step explanation:

I hope this helps :)