The equation given is matched with the respective vertex forms.
What is the standard Equation for a circle ?The standard equation for a circle is given by
(x-h)² + (y-k)² = r²
The equation given in the question are
x² + y² − 4x + 12y − 20 = 0
(x − 6)² + (y − 4)² = 56
x² + y² + 6x − 8y − 10 = 0
(x − 2)² + (y + 6)² = 60
3x² + 3y² + 12x + 18y − 15 = 0
(x + 2)² + (y + 3)² = 18
5x² + 5y² − 10x + 20y − 30 = 0
(x+3)² + (y-4)² = 35
2x² + 2y² − 24x − 16y − 8 = 0
(x-1)² + (y+2)² = 11
The first equation is
x² + y² − 4x + 12y − 20 = 0
It can be written ad
x² -4x + 4 - 4 +y²+12y +36-36 -20 = 0
(x-2)² +(y+6)²= 60
The second equation is
x² + y² + 6x − 8y − 10 = 0
x² +6x +9-9 +y² -8y +16-16 -10 = 0
(x+3)² + (y-4)² = 35
The third equation is
3x² + 3y² + 12x + 18y − 15 = 0
(x + 2)² + (y + 3)² = 18
The fourth equation is
5x² + 5y² − 10x + 20y − 30 = 0
(x-1)² + (y+2)² = 11
The fifth equation is
2x² + 2y² − 24x − 16y − 8 = 0
(x − 6)² + (y − 4)² = 56
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Select all the functions that show an inverse variation...
a) y=6x
b) y=3/x
c) y=1/3x
d) y= -.07x
e) y= 2/x+4
f) xy=-3
PLEASE HELP ILL MARK BRAINLEST
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Using the properties of integer exponents, match each expression with its equivalent expression.
From the power rules, the matching of each expression with its equivalent expression is:
[tex]5^{-3}=\frac{1}{125}[/tex]
[tex]-5^{-3}=-\frac{1}{125}[/tex]
[tex](-5^{-3})^{-1}=-125[/tex]
[tex](-5^{-3})^{0}=1[/tex]
Power RulesThere are different power rules, see some them:
1. Negative exponent. For this rule when you have a negative exponent, you need to invert the number, i.e, the power base is converted to the denominator. After that, you should solve the power with a positive exponent. See the examples:
[tex]4^{-3}=\frac{1}{4^3} =\frac{1}{64} \\ \\ {\frac{4}{6} }^{-2}=( {\frac{6}{4} })^{2}=\frac{36}{16}[/tex]
2. Power. For this rule, you should repeat the base and multiply the exponents. See the example, [tex](2^{2})^3=2^6=64[/tex].
3. Zero Exponent. When you have an exponent equals to zero, the result must be 1. See the example, [tex]2^0=1[/tex].
From this for your question, you have:
[tex]5^{-3}=\frac{1}{5^3}=\frac{1}{125}[/tex][tex]-5^{-3}=-\frac{1}{5^3}=-\frac{1}{125}[/tex][tex](-5^{-3})^{-1}=(-5)^{3}=-125[/tex][tex](-5^{-3})^{0}=(-5)^{0}=1[/tex]Read more about power rules here:
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pe-intercept Equatic
Question 4 of 10
If f(x) = 5x - 12, what is f(2)?
Answer:
f(2) = 2
Step-by-step explanation:
Given function:
f(x) = 5x - 12
To Find:
f(2)
Solution:
Well,it is absolutely clear from the problem,that x = 2.So just substitute 2 in x's place on the function,then simplify using PEMDAS.
[tex]f(x) = 5x - 12[/tex]
[tex]f(2) = 5(2)- 12[/tex]
[tex]f(2) = 10 - 12[/tex]
[tex]\boxed{f(2) = - 2}[/tex]
Hence,f(2) is equal to -2.
Can someone help me?
Answer:
A. 7 and 3D. 1 and 5Is LMN OPQ If so name the congruence postulate that applies
The triangle is congruent by SSS congruency because the corresponding two sides of two triangles are of the same measurement Hence, Option D is correct.
What is SSS congruency?If the corresponding two sides of two triangles are of the same measurement, then the considered pair of triangles are congruent.
We have given two triangles that are congruent to each other;
LMN is congruent to OPQ
Given;
LM = OP
MN = PQ
LN = OQ
Thus, the triangle is congruent by SSS congruency because the corresponding two sides of two triangles are of the same measurement
Hence, Option D is correct.
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Solve for x. Round to the nearest hundredth sin x ≈ 0.965926
how do u do a problem like this?
In the given equation, the value of x is approximately 75°
TrigonometryFrom the question, we are to determine the value of x
The given equation is
sin x ≈ 0.965926
If sin x ≈ 0.965926
Then,
x ≈ sin⁻¹(0.965926)
∴ x ≈ 75.0°
Hence, the value of x is approximately 75°
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The sum of the reciprocals of the first four consecutive positive integers is greater than two. What is the least number of consecutive positive integers necessary to make the sum of the reciprocals greater than three?
The least number of consecutive positive integer that is required to make the sum of the reciprocals greater than three is 7.
What is an integer?An integer is simply a number that is not a fraction.
The first four consecutive positive integers are:
1, 2, 3 , 4.
Their reciprocals are:
1/1, 1/2, 1/3, 1/4; and
The sum of them are greater than 2; that is
1/1 + 1/2 + 1/3 + 1/4 = 2.08333333333 > 2
to make the expression >3
We would require the following integers
1/1 + 1/2 + 1/3 + 1/4+ (1/5) + (1/6) + (1/7) + (1/8)+ (1/9) + (1/10) + (1/11) = 3.01987734488
Thus, the additional consecutive reciprocal integers that is required to make the sum of the reciprocal of the fist four greater than 3 is 7.
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Given:
p: Angles XYZ and RST are vertical angles.
q: Angles XYZ and RST are congruent.
Which statement is logically equivalent to p → q?
A. If angles XYZ and RST are congruent, then they are vertical angles.
B. If angles XYZ and RST are not vertical angles, then they are not congruent.
C. If angles XYZ and RST are not congruent, then they are not vertical angles.
D. If angles XYZ and RST are vertical angles, then they are not congruent.
Answer:
C
Step-by-step explanation:
The contrapositive is always logically equivalent to the original statement.
Answer:
C
Step-by-step explanation:
Claire and jane did an examination together. jane scored 9 more marks than claire and her marks were 60% of the sum of their scores. what are the scores of each student?
The score of Jane is 27 and the score of Claire is 18.
A linear equation is an equation where highest degree of variables is 1.
Let the score of Jane's mark is x
Given, that score Jane is 9 more than the score of Claire.
So, the score of Claire= x-9
Given, the score of Jane is 60% of the sum of their scores.
the sum of their scores is = x+x-9= 2x-9
from the above it is clear that
the linear equation will be
x=60%(2x-9)
⇒x=0.6(2x-9)
⇒x= 1.2x -5.4
⇒1.2x-x= 5.4
⇒0.2x= 5.4
⇒x= 5.4/0.2
⇒x= 27
So the score of Jane is 27.
As score Jane is 9 more than the score of Claire.
the score of Claire is = x-9= 27-9=18
Therefore the score of Jane is 27 and the score of Claire is 18.
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Find the vertex and focus of the
parabola:
y²-10y + 4x + 21 = 0
Vertex = ([?],
[]
Focus=([], [])
Answer:
Vertex: (1, 5)
Focus: (0, 5)
Step-by-step explanation:
Given that the parabola's equation is y² - 10y + 4x + 21 = 0, solve for the vertex and the focus.
Vertex:
Step 1: Isolate x to the left side of the equation; we get x = - (y² / 4) + (5y / 2) - (21 / 4).
Step 2: Complete the square of the previous equation; here we get - (1 / 4) * (y - 5)² + 1. x is squal to this.
Step 3: Use the vertex form, x = a(y - k)² + 1. a is - 1 / 4, h is 1, and k is 5.
Step 4: Fill in (h, k). We get the answer (1, 5) as the vertex.
Focus:
Step 1: Find p, and distance from the vertex to the focus. We can find p by using 1 / (4a).
Step 2: Simplify. This gives us -1 as p.
Step 3: We plug in the values we just got earlier to get the vertex. The focus of a parabola can be found by using: (h + p, k).
Step 4: Substitude the values. We have (1 + -1, 5).
Step 5: Simplify. Therefore, the answer is (0, 5).
This took me a long time to calculate. Please mark me as Brainliest!!!This uservabove me did it all for you. I don't have much to say...
Which method is better to solve the following equation?
²-25=0
Your answer:
O Quadratic Formula
O Square Rooting
Clear answer
Next
Identify the geometric mean of 9 and 9/4.
The geometric mean of 9 and 9/4 will be 9/2 or 4 1/2.
How to calculate the mean?It should be noted that in order to find the geometric mean of the numbers given, give to find the square root and then multiply.
This will be:
= ✓9 × ✓9/4
= 3 × 3/2
= 9/2 = 4 1/2
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What is the value of f^-1 (-3)
According to the plot of [tex]f(x)[/tex], whose curve passes through the point (-5, -3), we have
[tex]f(-5) = -3 \implies f^{-1}(-3) = \boxed{-5}[/tex]
What is the period of the function y=tan (4/pi (x-pi/3))
O 3 units
O4 units
O 6 units
O 8 units
Answer:
Period = 4 units
Step-by-step explanation:
Standard form of a tangent function:
[tex]f(x)=\sf A \tan(B(x+C))+D[/tex]
A = vertical stretchπ / |B| = period (distance between any two consecutive vertical asymptotes)C = phase shift (horizontal shift - positive is to the left)D = vertical shiftThe tangent function has a vertical asymptote whenever cos(x) = 0
The tangent function does not have an amplitude because it has no maximum or minimum value.
Given function:
[tex]y=\tan \left(\dfrac{\pi}{4}\left(x-\dfrac{\pi}{3}\right)\right)[/tex]
Therefore:
Vertical stretch (A) = none[tex]\textsf{Period}=\dfrac{\pi}{\left|\dfrac{\pi}{4}\right|}=4[/tex]Phase shift (C) = π/3 to the rightVertical shift = noneAnswer: 4 units
Step-by-step explanation:
Hey, any help would be very needed thanks so much!!
Let's take this problem step by step:
To find the ordered pair of the system:
⇒ must set both equations equal to each other
⇒ must solve for 'x'
Let's solve:
[tex]x^2-2x+3=-2x+28\\x^2-2x+3+2x-28=0\\x^2-25=0\\(x-5)(x+5)=0[/tex]
Let's find the x-values:
[tex](x-5)=0\\x=5\\\\(x+5)=0\\x=-5[/tex]
Let's find f(x)'s value for each of the 'x':
[tex]x=5\\f(5)=-2(5)+28=18\\\\x=-5\\f(-5)=-2(-5)+28=38[/tex]
Answer: (5, 18), (-5,38)
Hope that helps!
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Given: ∠CBA ≅ ∠FBA; ∠CAB ≅ ∠FAB
Prove: ΔBCA Is-congruent-to ΔBFA
The proof is shown below
What is congruency?Two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.
Given:
∠CBA ≅ ∠FBA; ∠CAB ≅ ∠FAB
Now, ∠BCA is congruent to ∠BFA [reflexive property of congruence]
Also, AB= AB (common)
Thus, we can conclude that Δ BCA≅ Δ BFA by ASA criteria.
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the number of cows in the field minus 12...
Answer:
maybe minus 12 there was no number of cows
Answer:
x - 12
Step-by-step explanation:
x represents the number of cows since we do not know the number
then "minus 12"
bada bing bada boom
Consider the table below.
x y
-1 -5
0 5
1 11
2 13
3 11
Complete the standard form equation representing the quadratic relationship displayed above, where a, b, and c are constants.
The standard equation is: y = (-2)x² + 8x + 5
What is Quadratic Equation?A quadratic equation is a second-order polynomial equation in a single variable x ax²+bx+c=0, with a ≠ 0 .
We know,
y = ax² + bx + c
For (-1, -5)
-5 = a - b + c..................(1)
For (0, 5)
5 = c
For (1, 11)
11 = a + b + c.....................(2)
From (1) and (2), we get
a=-2
and b= 8
Hence, the standard equation is:
y = (-2)x² + 8x + 5
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If f(x) = 2x² - 5 and g(x) = 3x + 3, find (f- g)(x).
OA. 3x-2x2 - 2
OB. 2x²-3x-8
OC.-²2²-8
OD. 2x²-3x-2
(f- g)(x) = 2x²-3x -8 , Option B is the correct answer.
What is a Function ?A function is a mathematical statement that derives relation between two variables.
Two functions are given in the question
f(x) = 2x² - 5
g(x) = 3x + 3
(f- g)(x) = ?
(f- g)(x) = (2x² - 5 - (3x + 3))
(f- g)(x) = 2x²-3x -8
Therefore Option B is the correct answer.
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Line A and Line B are perpendicular. The slope of line A is -0.5. What is
the gradient of line B? Give reasons.
Answer:
Step-by-step explanation:
When 2 lines are perpendicular, their slopes are negative reciprocals of one another. Here, if the slope of A is -1/2, the slope of B is +2/1, or just 2.
what is the factored form of x^3 - 729
Answer:
(x - 9)(x^2 + 18x + 81).
Step-by-step explanation:
Use the difference of cubes factorization, which claims that a^3 - b^3 = (a - b)(a^2 + ab + b^2)
x^3 - 729 = (x - 9)(x^2 + 18x + 81)
Answer:[tex](x-9) (x^{2} +9x + 81)[/tex]
Step-by-step explanation:
(c) The result of a number, when increased by 40%, is 2.1. Find the number. ( c ) The result of a number , when increased by 40 % , is 2.1 . Find the number .
Answer:
1.5 is the number.
Explanation:
Let the number be 'n', this is 100% - original number.
When increased by 40%, 100% + 40% = 140%.
140% × n = 2.1
1.4n = 2.1
n = 2.1/1.4
n = 1.5
Hence, the original number is 1.5.
Please answer this thanks
Answer: down below
Step-by-step explanation:
1. How many hay bales did the farmer sell?
To do that, you need to divide the weight of a hay bale by the total weight of the hay bales that the farmer sold.
That will be 24,300 / 75 = 324 bales
2. Divide the new number (26,700) by the same number 75.
26,700 / 75 = 356 hay bales
Subtract the bales from last year to the bales from this year:
356 bales - 324 bales = 32 bales
What is the measure of
Multiplying Monomials and Binomials:16x(x+24)
could someone please help me with this
Answer:
ia) center: (0, 0), the origin
ib) angle: 90°
ic) direction: CCW
ii) LM ≅ L'M', ∠L ≅ ∠L'
iii) (2, 1)
Step-by-step explanation:
A rigid transformation preserves size and shape of a figure, so the image is congruent to the original. The rigid transformations are rotation, reflection, and translation. Each has characteristics that allow one to determine the nature of the transformation(s) involved.
__
rotationangle and direction
One way to determine the angle and direction of rotation of a figure is to compare a horizontal segment on the original with the corresponding segment on the image. Here, a convenient segment is NM, which is horizontal and points to the right. Its angle relative to the direction of the +x axis is 0°.
The transformed segment N'M' points upward, at an angle relative to the +x axis of 90°. This tells you the figure was rotated 90° in the CCW direction. (This is fully equivalent to a rotation of 270° in the CW direction.)
center
Points in a rotated image always remain at the same distance from the center of rotation as the original points. In most cases, the center of rotation is the origin. We can check to see if that is the case by looking at the distances of a couple of points from the origin.
N is at coordinates (1, 1), so is √(1² +1²) = √2 from the origin
N' is at coordinates (-1, 1), so is √((-1)² +1²) = √2 from the origin
L is at coordinates (1, 3), so is √(1² +3²) = √10 from the origin
L' is at coordinates (-3, 1) so is √((-3)² +1²) = √10 from the origin
This confirms that the origin is the center of rotation.
__
Since each point and its image are on a circle centered at the center of rotation, the line between them is a chord of that circle. The perpendicular bisector of that chord goes through the center of rotation. Here, we observe that the perpendicular bisector of NN' is the y-axis. The perpendicular bisector of LL' is a line with slope -2 through (-1, 2). It will intersect the y-axis at the origin, confirming the origin as the center of rotation.
__
geometric relationshipsA rigid transformation preserves lengths and angles, so any length or angle on the rotated figure is congruent to the original:
LM ≅ L'M', MN ≅ M'N', NL ≅ N'L'
∠L ≡ ∠L', ∠M ≡ ∠M', ∠N ≡ ∠N'
__
translationThe components of a translation vector add to the corresponding coordinates of a point.
L +v = L'
(1, 3) +(1, -2) = (2, 1) . . . image of point L
3. (3, 5) and (k, 9), slope = 1/2
Linear relationships unit 3 lesson 10 grade 8 openuprespurces
Answer:
k = 11, if I understand the question.
Step-by-step explanation:
Please rephrase the question if my interpretation is incorrect. (BTW, isn't (k,9) a dog?)
======================
I'll assume that we want to find the value of k as given by the equation of a line that has a slope of (1/2).
Let's determine if we can establish an equation with what we know:
1. It goes through point (3,5), and
2. It has a slope of (1/2)
We'll look for a line with the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0).
From (2) we know y = (1/2)x + b.
We can find b by using the one known point that lies on the line (3,5). Use y = (1/2)x + b, insert the point (3,5), and solve for b:
y = (1/2)x + b
5 = (1/2)(3) + b
5 = 1.5 + b
b = 3.5
The line is y = (1/2)x + 3.5.
Now use the point (k,9):
y = (1/2)x + 3.5
9 = (1/2)k + 3.5
(1/2)k = 5.5
k = 11
The point is (11,9) so k = 9
See the attached graph.
Given the following formula, solve for a.
Answer:
A. a = 2s - b -c
Step-by-step explanation:
Rearrange the equation in a way that you have only a on one side. When solving equations you can add, subtract, multiply or divide by the same number/variable/expression on the both sides.
[tex]s = \frac{a + b + c}{2}[/tex]
Multiply by 2 to get rid of the fraction.
[tex]s \cdot 2 = \frac{a + b + c}{2} \cdot 2[/tex]
On the right side the 2 cancels out:
[tex]s \cdot 2 = a + b + c[/tex]
On the right side next to a are still b and c. But we want a alone. Subtract b.
[tex]s \cdot 2 - b = a + b + c - b[/tex]
b - b on right side gives 0.
[tex]s \cdot 2 - b = a + c + 0[/tex]
The step above is usually skipped, because number + 0 = number.
[tex]s \cdot 2 - b = a + c[/tex]
Next to a there is still c. Subtract c.
[tex]s \cdot 2 - b - c = a + c - c[/tex]
c - c on the left is 0.
[tex]s \cdot 2 - b - c = a[/tex]
So our answer is:
[tex]s \cdot 2 - b - c = a[/tex]
It can be rewritten to (change sides):
[tex]a = s \cdot 2 - b - c[/tex]
And s · 2 can be rewritten to 2s:
[tex]a = 2s - b - c[/tex]
How many solutions are there to the system of equations graphed below if
the lines are parallel?
O A. Zero
O B. Two
C. Infinitely many
O D. One
Is in between 2 number on the number line
Answer:
D
Step-by-step explanation:
Answer:
between 3 and 4
Step-by-step explanation:
3 squared is 9 and 4 squared is 16 so something in between 3 and 4 can be squared to equal 10 (since a square root is the opposite of squaring)