The two planets are similar in size, inclination, structure, composition, and the presence of water on their surfaces. They also have many key differences.
While Earth has 23h 56m and 4 s period of rotation, Mars's period of rotation is about 24 hours and 40 minutes. Mars is inclined on its axis, similar to Earth., It is inclined at 25.19° to its orbital plane.
They are both terrestrial planets. This means that both have a dense metallic core and also an overlying mantle and crust, which is composed of less dense materials (like silicate rock).
Mars also has a surface covered by a mountain range. Ice water exists beneath much of the Martian surface. Radar data and soil samples have confirmed the presence of shallow subsurface water at the middle latitudes as well.
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according to general relativity, the presence of matter curves spacetime and therefore time slows down in a gravitational field. time is universal. time is different for every object. none of the above
General relativity states that the existence of matter bends spacetime, which causes time to slow down in a gravitational environment.
Explain the term general relativity?It is, in essence, a theory of gravity. The fundamental assumption is that gravity is a bending or curving of space rather than an invisible force which draws items together.
An item warps the space surrounding it more dramatically the more large it is.According to Einstein's general theory of relativity, matter or energy causes a distortion of space (or more specifically, spacetime) known as gravity. A large item produces a gravitational field by distorting the geometry of the spacetime it is located in.Thus, general relativity states that the existence of matter bends spacetime, which causes time to slow down in a gravitational environment.
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A man runs 300 m west in 60 seconds. He then runs 100m north-west in 20 seconds. What is his average velocity in meter per second?
Answer:
See below
Explanation:
Total distance = 300 + 100 = 400 meters in 60 + 20 = 80 seconds
400 m / 80 s = 5 m/s
If you are using DISPLACEMENT:
displacement = sqrt ( ( 300 + 100 cos 45)^2 + (100sin 45)^2 ) = 377.4 m
in 80 seconds 377.4 / 80 = 4.7 m/s
solar panels generate an average of about 200 watt/m2. estimate the area (in meter2) needed to provide this annual energy usage.
The area 63000 m² needed to provide this annual energy usage.
What is annual energy usage?The term "Annual Usage" refers to the estimated annual power consumption at the Address, computed in kWh, as inputted into the programme or as recalculated in the case that more project watts are requested.
A normal household in Arizona uses about 1050 KWh of energy per month .
So annual consumption of energy is about 12600 KWh that is 12600000 watt-hour.
Average solar panel generate about 200 watt per square meter area.
Total area needed to provide this power can be calculated by the formula.
Total power required= total area × total power generation by solar panel.
Here, total power =12600000 watt hour.
Power generation by solar panel is 200 watt/ m²
So total area= total power required/ power generation by solar panel.
Total area= 12600000/200 m²
Total area= 63000 m².
So total area required to generate that amount of power is about 63000 m².
Here power generation of 200 watt/m² by solar panel indicates that the solar panel has efficiency of about 20% that means it can convert only 20% of solar irradiance ( which is nearly about 1000 watt per m²).
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The complete question is as follows:
Estimate the annual energy consumption (in watt-hour) of a typical house in Arizona.
Solar panels generate an average of about 200 Watt/m² . Estimate the area (in m²) needed to provide this power.
Ultrasound in Medicine. A 1.70-MHz sound wave travels through a pregnant woman's abdomen and is reflected from the fetal heart wall of her unborn baby. The heart wall is moving toward the sound receiver as the heart beats. The reflected sound is then mixed with the transmitted sound, and 72 beats per second are detected. The speed of sound in body tissue is 1500 m/s. Calculate the speed of the fetal heart wall at the instant this measurement is made.
The speed of the fetal heart wall at the instant is 0.031 m/s when 72 beats per second of hart beat was detected.
The Doppler Effect, defined as the change in frequency of a wave in relation to an observer moving relative to the wave source, must be used.
Let
v= magnitude of the heart wall speed
V= speed of sound = 1500
fh= the frequency the heart receives (and reflects) =
fi= original frequency
ff= reflected frequency
fb= frequency for the beats=72
Make use of the Doppler Effect formula.
We have this formula because the heart is a moving observer and the device is a stationary source.
[tex]f_h = [(V+ v)/(v)] fi....(1)[/tex]
We can use this formula if we consider the heart to be a moving source and the device to be a stationary observer.
[tex]f_f = [(V)/(V-v)] fh....(2)[/tex]
The beats' frequency would be the difference between the original and reflected frequencies.
[tex]f_b = f_f -f_i......(3)[/tex]
substituting (1) and (2) into (3),
[tex]f_b=\frac{V}{V-v}\frac{V+v}{V}f_i-f_i\\\\f_b=f_i(\frac{V+v}{V-v}-1)\\\\f_b=f_i\frac{V+v-V+v}{V-v}\\\\f_b=\frac{2v}{V-v}[/tex]
solving for v ,
[tex]v=V\frac{f_b}{2f_i-f_b}=1500\frac{72}{2(1.70*10^6)-72}=0.031 m/s[/tex]
Thus, the speed of fetal heart is 0.031 m/s
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A hiker of mass 69 kg is going to climb to the top of Mount Tam, which has an elevation of 2.574 ft. 4 50% Part (n) If the hiker starts climbing at an elevation of 395 ft what will their change in gravitational potential energy be, in joules, once they reach the top? Assume the zero of gravitational potential energy is at sea level AV- Grade Summary Deductions 0 Potential 100 Soheissions Atempts remaining: e per attempt detailed view sino cos tan cotano asino acos atan acotano sinho cosh tanho cotanho Degrees O Radians ( 7 8 9 ET 4 5 6 123 + - 0 vo Submit Hini I give up! Hints: deduction per hint. Hints remaining: Feedback deduction per feedback A 50% Part (b) Repeat the above calculation for the change in gravitational potential energy, but assume the gravitational potential is zero at the top of the mountain
a. The gravitational potential energy change is 449.105 kJ
b. The gravitational potential energy change is 449.105 kJ
What is gravitational potential energy?Gravitational potential energy is the energy due to the position of an object. It is given by U = mgh where
m = mass of object, g = acceleration due to gravity and h = height of objectPart (a) If the hiker starts climbing at an elevation of 395 ft what will their change in gravitational potential energy be, in joules, once they reach the top?Since the mountain is 2574 ft high, the gravitational potential energy change is given by ΔU = mg(h' - h) where
m = mass of man = 69 kgg = acceleration due to gravity = 9.8 m/s²h = height at top of mountain = 2574 ft = 2574 × 0.3048 m = 784.56 m and h' = height where he starts climbing = 395 ft = 395 × 0.3048 m = 120.40 mSubstituting the values of the variables into the equation, we have
ΔU = mg(h' - h)
ΔU = 69 kg × 9.8 m/s²(784.56 - 120.40) m
ΔU = 69 kg × 9.8 m/s² × 664.16 m
ΔU = 449104.992 J
ΔU = 449.104992 kJ
ΔU ≅ 449.105 kJ
So, the gravitational potential energy change is 449.105 kJ
Part (b) Repeat the above calculation for the change in gravitational potential energy, but assume the gravitational potential is zero at the top of the mountain?We know that the gravitational potential energy change is ΔU = U' - U = mg(h' - h) where
U' = gravitational potential energy at top = 0, U' = gravitational potential energy at starting point, m = mass of man = 69 kg g = acceleration due to gravity = 9.8 m/s²h = height at top of mountain = 2574 ft = 2574 × 0.3048 m = 784.56 m and h' = height where he starts climbing = 395 ft = 395 × 0.3048 m = 120.40 mSubstituting the values of the variables into the equation, we have
ΔU = U - U' = mg(h' - h)
ΔU = 0 - U' = 69 kg × 9.8 m/s²(784.56 - 120.40) m
ΔU = 69 kg × 9.8 m/s² × 664.16 m
ΔU = 449104.992 J
ΔU = 449.104992 kJ
ΔU ≅ 449.105 kJ
So, the gravitational potential energy change is 449.105 kJ
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A 50 g rock is launched vertically in the air by a slingshot. The slingshot exerts an average force of 53 N on the rock over a distance of 0.750 m.
The work done by the average force is 39.75 J.
What is the work done by the average force?The work done by the average force of the slingshot is calculated by applying the following equation as shown below.
Mathematically, the formula for work done is given as;
W = Fd
where;
F is the average forced is the displacement of the rockThe given parameters include;
average force, f = 53 Ndisplacement, d = 0.75 mThe work done by the average force is calculated as follows;
W = 53 N x 0.75 m
W = 39.75 J
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A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping. What was the initial speed of the bullet?
The initial speed of the bullet is 2624.7 m/s.
Conservation of momentum indicates that the total momentum of an isolated system remains the same in the absence of an external force. H. Momentum is neither created nor destroyed, but can be changed by the action of forces in the sense of Newton's laws of motion.Momentum is the product of an object's mass and its velocity, which is also equal to the total force required to keep the object at rest.One of the practical aspects of momentum conservation is the collision problem where momentum is conserved and the net external force remains zero.Mass of bullet, m = 5 g = 0.005 kg
Mass of block, M = 1.2 kg
Coefficient of friction = 0.2
Distance, d = 0.31 m
Let the initial speed of the bullet is u.
Use Conservation of momentum
m u = (M + m) v
0.005 x u = (1.2 +0.005) v
v = 4.2 x 10-4 u m/s
Now, use third equation of motion
v2 = u2 - 2μg s 0 = (4.2 x 10-4 u)2 - 2 x 0.2 x 9.8 x 0.31u = 2624.7 m/s
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Consider the following weighted, directed graph, representing the state space for a search problem. The weight between two nodes (u, v) indicates the cost of moving from node u to node v. The heuristic function value h(n) for each node n is also shown next to the node. The node S is the start state, and the node G is the goal state. h = 2 2 A 2 h = 3 h = 4 S 3 2. B 3 G) h = 0 h = 1 5 D 2 h = 2 Consider the following statement: 'The heuristic function his admissible' The statement is Select one: O True O False
True; The heuristic function his admissible.
When there are no specific solutions or the time required to find a solution is too great, a heuristic function (algorithm) or simply a heuristic is a shortcut to issue solving. We can infer that the objective is to locate a quicker or more approximate solution, even if it is not the best one. In other words, while applying a heuristic, we compromise accuracy for solution speed.
For instance, greedy algorithms typically result in speedy but inadequate answers. In the following tree, a greedy algorithm that seeks the highest sum would take the red path, but the green path is the best one
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Nancy is running around a circular track encircling the reservoir where she grew up in Boston. As she's running, which of the following is true?
A. Her shoes need to exert a small, radially inward force on the ground to keep her body moving along the circular track.
B. Her shoes need to exert a small, radially outward force on the ground to keep her body moving along the circular track.
C. Her shoes do not need to exert any force in the radial direction to keep her moving around the circle.
Option B; Her shoes need to exert a small, radially outward force on the ground to keep her body moving along the circular track.
A body can change its state of rest or motion when an external force acts on it. It is directed and has a magnitude. Force is applied at a location known as the application, and the direction in which it is applied is referred to as the force's direction. Force is the pushing or pulling of an object. When objects interact with one another, push and pull are generated. You can also describe force using words like stretch and squeeze.
A mass-containing object's velocity changes when a push or pull is applied, according to the definition of force in physics.
Motion in physics is characterised as a shift in position with respect to time. Motion is just the movement of something, as opposed to
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light striking a metal surface causes electrons to be emitted from the metal via the photoelectric effect. part a in a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the metal are held constant. assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased? check all that apply. view available hint(s)for part a in a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the metal are held constant. assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?check all that apply. the work function of the metal decreases. the number of electrons emitted from the metal per second increases. the maximum speed of the emitted electrons increases. the stopping potential increases.
The correct answer is that the number of electrons emitted from the metal per second increases as the intensity of the incident light is increased.
This is due to the fact that more energy is being absorbed by the metal and so more electrons can be excited to a higher energy level and then emitted through the photoelectric effect. The work function of the metal remains constant, as does the temperature of the metal.
The maximum speed of the emitted electrons and the stopping potential will increase as the intensity of the incident light increases since more energy is being absorbed and more electrons will be emitted with higher kinetic energy.
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Pulley Block A of mass 4m is attached by a light string to block B of mass 2m. The string passes over a pulley with negligible friction and of negligible mass. Block A is held a distance h above the ground, as shown. The blocks are released from rest, and block A reaches the ground two seconds later. The value of h is most nearly
a. 13.3 m b. 6.7 m c. 3.3m d. 2 m
The value of h is most nearly 6.7 m. option B is the correct answer
From the question, we have
Body mass m1 = 4 kg
mass of the body on the ground m2 = 2 kg
descent time t = 2s
From Newton's second law,
T - W₁ = m₁ a
-T + W₂ = m₂ a
Solving, we get
a = -3.27 m / s²
y = y₀ + v₀ t + ½ a t²
0= y₀ + 0 +½ a t²
y₀ = ½ 3.27 2²
y₀ = 6.54 m
The value of height is most nearly 6.7 m
Kinematics:
The net force, the mass, and the acceleration of a body are related by Newton's second law.
∑ F = m a
Kinematics investigates how objects move while searching for connections between position, speed, and acceleration.
y = v₀ t + ½ a t²
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a friend of yours is loudly singing a single note at 500 hz while racing toward you at 27.2 m/s on a day when the speed of sound is 343 m/s. what frequency do you hear?
With the use of formula, the magnitude of the observed frequency will be 463.3 Hz
What is Doppler Effect ?Doppler effect is the change in frequency of a sound as you move toward or away from the source of the sound.
Given that a friend of yours is loudly singing a single note at 500 Hz while racing toward you at 27.2 m/s on a day when the speed of sound is 343 m/s.
The parameters are;
Speed of sound c = 343 m/sObserver frequency Fo = ?Sound frequency F = 500 HzSpeed of the object v = 27.2 m/sThe frequency you hear can be calculated by using the formula below.
Fo = Fc/(c + v)
Fo = (500 × 343) / (343 + 27.2)
Fo = 171500/370.2
Fo = 463.3 Hz
Therefore, the frequency at which you hear will be 463.3 Hz
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light with a frequency of 5.9 x1014 hz travels in a block of glass that has an index of refraction of 1.59.
The light will travel with a speed of 9.38 x 10¹⁴ m/s in the block of glass.
The speed of light in a medium is given by the formula,
n = c/v
Where,
c is the speed with which the light travels in the medium,
v is the frequency of the light and n us the refractive index of the medium.
Now, here in this case, the refractive index of the block of glass is 1.59 and the frequency of the light is 5.9 x 10¹⁴ Hz.
Now, putting values,
1.59 = c/5.9 x 10¹⁴
c = 9.38 x 10¹⁴ m/s.
So, the light will travel with a speed of 9.38 x 10¹⁴ m/s in the block of glass.
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A heavy piece of hanging sculpture is suspended by a 90
c
m
long 5.0
g
steel wire. When the wind blows hard, the wire hums at its fundamental frequency of 95
H
z
.
What is the mass of the sculpture?
The sculpture measures 16.70 kg, which is in accordance with the requirement.
Why would one use wire?Wires, often in the form of a wire rope, are used to transport mechanical loads. In the realm of electricity with telecoms transmissions, a "wire" might be an electrical cable. The "solid core" of this kind of cable might be formed of a wired connection or numerous strands that have been braided or stranded together.
Briefing:Use the string's tautness' fundamental frequency as a formula.
f = (1/2L)*√(T/μ) .... (Eqn1)
Where,
f= frequency in Hertz =95Hz
T = String tension equals Mg
M represents the sculpture's mass, thus what is it?
g= 9.8m/s^2
L= Length of the string=90cm=0.9m
Mass density is equal to mass of string divided by string length.
mass of string =5g=0.005kg
L=0.9m
μ=0.005/0.9 = 0.0056kg/m
Using (Eqn1)
95 = 1/(2*0.9) √(T/0.0056)
171 = √(T/0.0056
Square both sides
29241 = T/0.0056
T= 163.74N
Recall that T =Mg
116.12= M * 9.8
M=163.74/9.8
M= 16.70kg
Consequently, the sculpture weighs 16.70kg.
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Suppose that 5 J of work is needed to stretch a spring from its natural length of 24 cm to a length of 41 cm. (a) How much work is needed to stretch the spring from 32 cm to 37 cm? (Round your answer to two decimal places.) (b) How far beyond its natural length will a force of 10 N keep the spring stretched? (Round your answer one decimal place)
Stretching the spring from 32 cm to 37 cm requires 0.99J of labor.
A force of 10 N will extend a spring to its normal length of 363 cm.
These are the characteristics of a spring's spring constant, k.
1) It takes force kx to extend the spring's length.
2) A spring with length x stretched has energy kx²/2.
You can calculate k using the information provided in the manner shown below.
Work of 5J gave the spring energy k(39-28)²/2.
Therefore
5 = k(39-28)²/2
k = 10/121 N/cm
(a)
At 33cm the spring has energy k(33-28)²/2.
At 35cm the spring has energy k(35-28)²/2.
The extra energy needed is
(10/121)(35-28)²/2 - (10/121)(33-28)²/2 = 120/121 = 0.99J
(b)
30 = kx
x = 30/k = 363cm
An elastic device known as a spring is used to store mechanical energy and release it in response to the removal of an opposing force. Without the aid of motors or other powered devices, if you need to exert effort to move something or keep it in place.
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volume of right circular cone; volume of cone; how to find volume of a cone; cone formula
The volume of the right circular cone is given by the formula πR²H/3.
A right circular cone is a kind of cone in which the centre of the circular base of the cone is perpendicular to the vertical height of the cone.
The volume of any right circular cone is generally given by the formula,
V = πR²H/3
Where,
V is the volume of the right circular cone,
R is the radius of the circular base of the right circular cone.
H is the vertical height of The right circular cone.
π is a constant that has a valued 22/7.
In any general case when we are given the value of the radius of the circular base of the right circular cone and the height of the right circular cone, then we can just simply put the values in the above mentioned formula and we get the volume of the right circular cone.
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Which of the following could not be determined by an observation that only uses spectroscopy?
the chemical composition of a distant star
the angular size of a distant galaxy
the speed at which a distant galaxy is moving away from us
the surface temperature of a distant star
the rotation rate of a distant star
The angular size of a distant galaxy cannot be determined by an observation that only uses spectroscopy.
Astronomical spectroscopy can be used to examine the different wavelengths of light or radiation coming from matter found in space. Astronomical spectra can be observed to determine the chemical composition of stars and galaxies. Continuous spectrum can be examined by a researcher to determine the temperature of the star.
The angular size or angular diameter of a distant galaxy can be measured by Fourier technique. It is a technique that is based on the interference of light. Spectroscopy uses the dispersion of light to calculate a quantity.
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student uses a heavy ball attached to a rope as a pendulum in an experiment. the ball is hanging so the rope is vertical. the student pulls the ball back and releases it from rest, as shown. comparing the measured value to the expected value of the speed of the ball at the lowest point of its swing, the student finds that the ball is moving slower than expected. which of the following may account for the slower-than-expected speed?
the speed of the ball lowest point of its swing, the student finds A. The student measured the mass of the ball to be higher than it actually is. B. The student did not account for the mass of the rope. С. The angle of the swing was so high that air resistance had a significant effect. D. The ball was accidentally given a small push when it was released. E. The student did not account for the stretch of the rope caused by the weight of the ball.
Answer:-(E)
The speed of ball is slower than expected speed due to stretch in length of string. The swing rate, or frequency, of the pendulum is determined by its length. The longer the pendulum, whether it is a string, metal rod or wire, the slower the pendulum swings. Conversely the shorter the pendulum the faster the swing rate.
Mass of rope or ball does not effect speed,time period or frequency.The air resistance has no significant effect on speed of ball.
Frequency is the number of occurrences of a repeating event per unit time. For clarity, also called temporal frequency, which is different from angular frequency. Frequency is measured in hertz (Hz) and corresponds to one event per second. Duration is the reciprocal of frequency because duration is the time interval between events.
For example, if the heart beats 120 times per minute (2 hertz), the period T (the interval between repeated beats) is 0.5 seconds (60 seconds divided by 120 beats). value). Frequency is an important parameter used in science and engineering to describe the speed of vibrations and vibrational phenomena such as mechanical vibrations, audio signals (sound), radio waves, and light.
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A sound wave travels in air at a speed of 345 m/s. What would be the wavelength of a sound wave of frequency 1200 hz
Answer:
0.29 meters, or 29 centimeters.
Explanation:
The wavelength of a sound wave is related to its frequency and the speed at which it travels. The relationship between these quantities is given by the equation:
wavelength = speed / frequency
Plugging in the values given, we get:
wavelength = 345 m/s / 1200 Hz
This gives us a wavelength of approximately 0.29 meters, or 29 centimeters.
It's important to note that this is an approximate value, as the speed of sound can vary depending on the temperature, humidity, and other factors of the air through which it is traveling.
which method of heat transfer does not require a medium; the transfer of thermal energy by conduction and convection does not require matter; a material in which thermal energy moves easily is an insulator; materials in which thermal energy does not move easily are; the transfer of thermal energy by movement of matter is; a material in which thermal energy moves easily is an insulator true or false; the transfer of thermal energy by movement of matter is ______; the transfer of thermal energy by radiation does not require matter
Energy is transferred through matter by both conduction and convection. Only radiation can convey energy without the need for substance. The transfer of energy through waves is known as radiation
What is the simplest way to define radiation?The definition of radiation is radiation that emanates from a source and moves at the speed of light through space. This energy has wave-like characteristics and is surrounded by an electric and magnetic field. Electromagnetic waves are another name for radiation.
Definitions and examples of radiationThe definition of radiation was energy that emanates from a source and moves through a substance or through space. Radiation includes heat and light. Ionizing radiation, the type of radiation covered on this website, is so-named because it has sufficient energy to knock an electron out of an atom, converting it into an ion.
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you are watching a new bridge being built near your house. you notice during the construction that two concrete spans of the bridge of total length li
The construction that two concrete spans of the bridge of total length is 2.55m.
What is Linear expansion coefficient ?
The coefficient of linear expansion may be defined as the increase in length per unit length when the temperature is raised 1°C. Thus if the temperature of a rod of length l0 is raised from 0°C to t°C, the new length, lt, will be given by. (21.1)
Linear expansion coefficient of concrete is, [tex]$\alpha=1.2 \times 10^{-5} /{ }^{\circ} \mathrm{C}$[/tex]
Final length of the bridge,
[tex]$$\begin{aligned}& L=L_i(1+\alpha \Delta T)=260 \times\left(1+\left(1.2 \times 10^{-5} \times 16\right)\right)=260.04992 \mathrm{~m} \\& y=\frac{1}{2} \sqrt{L^2-L_i^2}=\frac{1}{2} \times \sqrt{(260.04992)^2-260^2}=2.55 \mathrm{~m}\end{aligned}$$[/tex]
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Object A with mass 1 kg is tied with a string to object B with mass 2 kg. Force F, is
pulling the object with mass 1 kg. When it is moving with the acceleration of 1 m/s?.
the friction force on A is 5 N and on B is 10 N.
Find F and tension in the spring that attached A and B.
The tension in the string is 15 N.
What is string?String is a data type used in programming that refers to a sequence of characters. It is typically used to store text-based data, such as words or sentences, and is often used to represent strings of text that the user has input. String data types are used in many programming languages, including Java, C++, Python, and JavaScript. String data types are also used to store information such as file paths, website URLs, and database names. In some programming languages, a string is also referred to as a character array.
F = 1 kg * 1 m/s2 = 1 N
The tension in the string is the sum of the forces acting on each object.
For Object A, the forces are F (1 N) and the friction force (5 N).
For Object B, the forces are the friction force (10 N) and the tension in the string.
Therefore, the tension in the string is 10 N + 5 N = 15 N.
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How to find the net force of on an object?
Answer:
Look for the formula!
Explanation:
the net force formula is FNet = Fa + Fg + Ff + FN.
FN is the force acting on a body.
here are the hints to find one in the future!
Fa is applied force,
Fg is the gravitational force,
Ff is the frictional force,
FN is a normal force.
levi boards a ferris wheel at the 3-o'clock position and rides the ferris wheel for several rotations. the ferris wheel has a radius of 12 meters, and when levi boards the ferris wheel he is 16 meters above the ground. imagine an angle with its vertex at the center of the ferris wheel that subtends the path levi travels.
Levi height above the ground is = 16 + 12sin(d/12)
Levi height above the center of the Ferris wheel in radius lengths is = 12sin(d/12)
Since Levi height above the center of the Ferris wheel is 12sin(d/12) meters and it's center is 14 meters above the ground.
Therefore, Levi height above the ground is = 16 + 12sin(d/12)
When an object is flung or projected into the air, it moves only with the acceleration caused by gravity. Projectile motion has several uses in both engineering and physics. Examples include the motion of any ball in sports, the entry of meteorites into the Earth's atmosphere, and fireworks. These things are referred to as projectiles, and their course is referred to as a trajectory. The projectile motion of falling objects, as it is described in Motion Along a Straight Line, is a straightforward one-dimensional kind in which there is no horizontal movement. The effects of air resistance are ignored in this section's discussion of two-dimensional projectile motion.
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What Are Balanced and Unbalanced Forces?
Balanced forces are equal in size and opposite in direction, whereas unbalanced forces are not equal in magnitude.
When forces are balanced, there's no alter in motion. In one of your circumstances within the last section, you pushed or pulled on an object from opposite directions but with the same force. To have unbalanced forces implies that the force applied in one direction is greater than the force applied within the opposite direction. When unbalanced forces are acting on an object, there's an alteration in speed and/or direction. By applying an unequal force, you'll be able to alter the motion of an object. Unbalanced forces can make an object at rest begin moving, make a moving object halt, or alter the direction and speed of the object.
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somebody please helpppp
Answer:
6 is Electrical
1 is Thermal
13 is Mass and Acceleration
3 is Force and Distance
2 is Work and Time
4 is Mechanical
Explanation:
NOTE: Sorry if I missed any and sorry if some aren't correct, but I think they are :)
Two sinusoidal waves traveling in opposite directions interfere to produce a standing wave with the following wave function, where x is in meters and t is in seconds.y = (1.50 m) sin(0.900x) cos(900t)Determine the wavelength of the interfering waves.mWhat is the frequency of the wave?HzFind the speed of the wave.m/s
The speed of the wave is 0m/s.
What is speed?
The rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude.
we can see that k = 0.9
wavelength = 2pi/k = 2pi/0.9=6.98
w = 900
f = w/2pi=900/2pi=143.2
v = w/k = 900/0.9=1000 m/s
If you look at the expression you must see a wave.
y = sin(0.3.x)
the wavelength 0.3.x = 2.pi gives x = 20.9 m
the frequency of the wave is the number of times the wave makes a full cycle per second. So every time 300.t = 2.pi makes a cycle. gives t = 2.pi/300 = 0.021
the frequency = 1/t = 47.8 sec^(-1) or 47.8 Hz
As it is a standing wave the speed is 0.
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an empty, isolated parallel plate capacitor has stored energy of 1.34 J. Then a material with a dielectric constant of 7.20 is inserted between the plates. How much energy is now stored in the capacitor.
The energy stored in the capacitor after the dielectric material is inserted is approximately 9.648 joules.
How do you calculate the stored energy?The energy stored in a capacitor is given by the formula:
E = 1/2 * C * V^2
Where E is the energy stored in the capacitor (in joules), C is the capacitance of the capacitor (in farads), and V is the voltage across the capacitor (in volts).
When a material with a dielectric constant of 7.20 is inserted between the plates of the capacitor, the capacitance of the capacitor increases by a factor of 7.20. This means that the energy stored in the capacitor also increases by a factor of 7.20.
Therefore, the energy stored in the capacitor after the dielectric material is inserted is:
E = 1.34 J * 7.20 = 9.648 J
So the energy stored in the capacitor after the dielectric material is inserted is approximately 9.648 joules.
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the atmospheric density at an altitude of 2500 km is about 1 molecule/cm3 . (a) assuming the molecular diameter of 2.0 x 10-8 cm, find the mean free path predicted by the equation:
The mean free path equation is 0.19 X 10⁻⁸ cm.
The mean free path is average distance an object will move between collisions. The actual distance a particle, such as a molecule in a gas, will move before a collision, called free path, cannot generally be given because its calculation would require knowledge of the path of every particle in the region.
Density = Mass per unit volume = N/V = 1 molecule/cm³
Altitude = 2500 Km
Diameter = d = 2 X 10⁻⁸ cm
Mean free path = λ =
= λ = 1 / [√(2πd²(N/V))]
= λ = 1 / [√(2 X 3.14 X ( 2 X 10⁻⁸ )²X (1))]
= λ = 1 / √ (25.12 X 10⁻¹⁶ )
= λ = 1 / 5.011 X 10⁻⁸
= λ = 0.19 X 10⁻⁸ cm
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A beam of protons moves in a circle of radius 0.25 m. The protons move perpendicular to a 0.44-T magnetic field. (a) What is the speed of each proton? (b) Determine the magnitude of the centripetal force that acts on each proton.
(a) Each proton travels at a speed of V= 6.898*106 m/s.
(b) The magnitude of a centripetal force acting on each proton is Fc = 3.97*1013.
What force has centripetal motion?Centripetal or centrifugal are the forces produced when rotating objects. An object is kept moving in a circle by the centripetal force, which is always directed to towards the center of the circle.
Three instances of centripetal acceleration is?The stress on the rope pushes the object toward the center when you spin a ball around a string or twirl a lasso. When a car is spinning, the force between the earth and also the wheels produces the centripetal force.
Briefing:
r = 0.25
q = 1.6 * 10⁻¹⁹C
B = 0.44 T
m = 1.67 * 10⁻²⁷ kg
Fb = Fc
qvB = mv²/r
qB= mv/r
(1.6 * 10⁻¹⁹)*0.44 = 1.67 * 10⁻²⁷ * v/2
v= 6.898* 10⁶ m.s⁻¹
centripetal force, Fc = m*v2/r
Fc = 1.67 * 10⁻²⁷ * (6.898* 10⁶)2/0.2
Fc = 3.97*10⁻¹³
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