Maya and Praisy are planting corns on a same farm. Maya plants 4 rows and Praisy plants 6 rows. If Mayas corns are ready to be picked in 8 weeks, how many weeks will it take Praisys corn to ready?

The value of p that makes the equation true is 4

p-9= -5(p-3)

p-9 = -5p + 15

collect the like terms

p + 5p= 15 + 9

6p= 24

Divide both sides by the coefficient of p which is 6

6p/6= 24/6

p= 4

Hence the value of p that makes the equation true is 4

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The inequality graph that represents n ≤ 3 is in the diagram attached below.

An inequality can be solved just like a normal equation by finding the possible values of the variable.

Given the inequality, 6n − 18 ≤ −n + 3, combine like terms

6n − 18 + 18 ≤ −n + 3 + 18

6n ≤ - n + 21

Add n to both sides of the inequality

6n + n ≤ - n + 21 + n

7n ≤ 21

Divide both sides by 7

7n/7 ≤ 21/7

n ≤ 3

This means that the values of n are from 3 and below.

Therefore, the inequality graph that represents n ≤ 3 is in the diagram attached below.

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Answer:

1/30

Step-by-step explanation:

5/6 - 4/5

= 25/30 - 24/30

= 1/30

[tex]~\frak{Tsyaa01:)}[/tex]

Answer: 1/9 ==> A

Step-by-step explanation:

3^-2=

3^(-2)=

3^(-1*2)=

(3^(-1))^2=

(1/3)^2=

1^2 / 3^2 = 1/9 ==> A

Answer:

the answer your looking for is B

Answer:1/4 of robot

Step-by-step explanation:

Answer:

Together they painted 120 figurines.

Step-by-step explanation:

8(6+9)=

8(6) + 8(9) =

48 + 72

120

Answer:

Step-by-step explanation:

The set of numbers which represents the possible number of hours for which the chemistry club could rent the meeting room is; t <= 10 hours.

It follows from the task content that the possible number of hours for which the chemistry club could rent the meeting room is to be determined.

Since the linear inequality which represents the situation in discuss can be written as follows;

4(t) +19 <= 59

where t = number of hours.

Solving the inequality, we have;

4t <= 59 - 19

4t <= 40

t <= 10 hours.

Ultimately, The set of numbers which represents the possible number of hours for which the chemistry club could rent the meeting room is; t <= 10 hours.

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[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

In the above question, it is given that :

[tex]\qquad \sf  \boxed{ \sf f(x) = \frac{x + 3}{2} }[/tex]

A.) Find f(2) :

[tex]\qquad \sf  \dashrightarrow \: f(2) = \dfrac{2 + 3}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: f(2) = \dfrac{5}{2} [/tex]

or

[tex]\qquad \sf  \dashrightarrow \: f(2) = 0.5[/tex]

B.) Find [tex]{ \sf {f}^{-1}(x) } [/tex] :

[tex]\qquad \sf  \dashrightarrow \: let \: y = f (x) [/tex]

so, we can write it as :

[tex]\qquad \sf  \dashrightarrow \: y = \dfrac{x + 3}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: 2y = x + 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 2y - 3[/tex]

Now, put x = [tex]{ \sf {f}^{-1}(x) } [/tex], and y = x and we will get our required inverse function ~

[tex]\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3[/tex]

C.) Find [tex]{ \sf {f}^{-1}(12) } [/tex] :

[tex]\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33[/tex]

Answer:

Answer: 8.118 / 0.615 = 13.2

Answer:

[tex]12 \frac{1}{4} [/tex]

Step-by-step explanation:

Put the whole numbers into the fraction

[tex] \frac{7}{2} [/tex]

Multiply 7/2 by 7/2

[tex]\frac{49}{4}[/tex]

You can simplify by making whole numbers with the fraction.

[tex]12 \frac{1}{4} [/tex]

The exponential function showing the relationship between y and t is given by [tex]y=450(0.906)^t[/tex]

An equation is an expression that shows the relationship between two or more numbers and variables.

Let y represent the mass of the sample of radioactive substance after t years, hence:

[tex]y = 450(1 - 0.094)^t\\\\y=450(0.906)^t[/tex]

The exponential function showing the relationship between y and t is given by [tex]y=450(0.906)^t[/tex]

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We can rearrange it to the standard form perimeter a = s - b - C/2

In arithmetic, what is a perimeter?

The perimeter of a form is the space surrounding its edge. Find the perimeter of various forms by summing the lengths of their sides.

The answer to your question is a = s - b - C/2

To solve for "a", we must get "a" on it's own side of the equal sign. We can first subtract "s" from both sides:

0 = a + b + C/2 - s

Then, we can subtract a from both sides:

-a = b + C/2 - s

Finally, we divide both sides by -1, so a is by itself.

a = -b - C/2 + s

And we can rearrange it to the standard form:

a = s - b - C/2

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The word kilosecond is used to describe a time unit that is 1000 times greater than one second.

In this problem we find a time unit that combines a standard SI unit and a preffix that describes a scale. In other words, we must look up for a derived unit from a fundamental unit and a preffix.

According to the SI, second is the fundamental unit of time and the Greek preffix kilo- is used to a describe thousand times a given unit. Therefore, the word kilosecond is used to describe a time unit that is 1000 times greater than one second.

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Step-by-step explanation:

The Mediterranean vegetation is dominated by evergreen shrubs and sclerophyllous trees adapted to the distinctive climatic regime of summer drought and cool moist winters with only sporadic frost.

The Pascal's Triangle expansion of (3 x-1)^4 is mathematically given as

[tex]$$\begin{aligned}&1(3 x)^4(-1)^0+4(3 x)^3(-1)^1 +6(3 x)^2(-1)^2+4(3 x)^1(-1)^3 +1(3 x)^0(-1)^4\end{aligned}$$[/tex]

This is further explained below.

Generally,  the equation for the expansion is  mathematically given as

(3 x-1)^4

Pascal's Triangle can be displayed as such:

1

1-1

1-2-1

1-3-3-1

1-4-6-4-1

The triangle can be used to calculate the coefficients of the expansion of (a+b)^n by taking the exponent n and adding 1 .

The coefficients will correspond with line n+1 of the triangle.

For (3 x-1)^4, n=4 so the coefficients of the expansion will correspond with line 5.

The expansion follows the rule

(a+b)^n=c_0 a^n b^0+c_1 a^{n-1} b^1+c_{n-1} a^1 b^{n-1}+c_n a^0 b^n

The values of the coefficients, from the triangle, are $-4-6-4-1.

[tex]$1 a^4 b^0+4 a^3 b+6 a^2 b^2+4 a b^3+1 a^0 b^4$[/tex]

Substitute the actual values of a 3 x and b-1 into the expression.

[tex]$$\begin{aligned}&1(3 x)^4(-1)^0+4(3 x)^3(-1)^1 +6(3 x)^2(-1)^2+4(3 x)^1(-1)^3 +1(3 x)^0(-1)^4\end{aligned}$$[/tex]

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Answer:

Answer: meee

Step-by-step explanation: Hunterx.Hunter, Jujutsu Kai.sen, T.okyo Reveng.ers, De.ath Note, Noble.sse, and some more others l.ol

Answer:

70

Step-by-step explanation:10 goes to 70 7 times drop down the 0 and u get 70 therefore final answer 70

Answer:

30

Step-by-step explanation:

We can use similar triangles. Letting the height of the tree be x,

[tex]\frac{x}{15}=\frac{6}{3} \\ \\ x=30[/tex]

Based on the selling price of the property in 6 years, the present value of the selling price is $3,313,315.

This amount is NOT attractive.

Based on the annual cash flows from the property, the present value of the cash flows is $4,640,991.40.

The property will then be attractive

The present value of the selling price can be found as:

= Selling price / (1 + rate) ^ number of years

= 4,700,000 / (1 + 6%)⁶

= $3,313,315

This amount is less than the buying price of the property today so the property is not attractive as it would result in a present value loss.

The present value of the cashflows will be the present value of an annuity because the rent is constant:

= Rent value x Present value interest factor of an annuity, 6 years, 6%

= 270,000 x 4.91732

= $1,327,676.40

The present value of the property then becomes:

= 1,327,676.40 + 3,313,315

= $4,640,991.40

The property then becomes very attractive because the present value gives a gain over the selling price of $3.7 million.

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The equivalent expressions of One-third + 8 d + StartFraction 5 Over 7 EndFraction are option B,D and G.

What is Algebraic expression ?

Algebraic expressions are the idea of expressing numbers using letters or alphabets without specifying their actual values. The basics of algebra taught us how to express an unknown value using letters such as x, y, z, etc. These letters are called here as variables. An algebraic expression can be a combination of both variables and constants. Any value that is placed before and multiplied by a variable is a coefficient.

Here, the given expression is :

One-third + 8 d + StartFraction 5 Over 7 EndFraction

and, the expression equivalent to this are :

1) 8 d + one-third + StartFraction 5 Over 7 EndFraction

2) One-third + StartFraction 5 Over 7 EndFraction + 8 d

3) StartFraction 5 Over 7 EndFraction + one-third + 8 d

Therefore, the equivalent expressions are option B,D and G.

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The solution of given system of equations are x = -1.146 and           x = 4.833

In this question, we have been given a system of equations.

4x^ 2 -3x+6=2x^ 4 -9x^ 3 +2x

We can write it as:

y = 4x² - 3x + 6

y = 2x^4 - 9x³ + 2x

We need to find the solution of given system of equations.

Consider the following graph of given system of equations as shown below.

In graph both the equations intersect at two points (-1.146, 14.687) and (4.833, 84.945)

Point of intersection gives the solution of the equations.

x-coordinate of the intersection of graph gives the solution because function depends on x.

Therefore, the solution of given system of equations are x = -1.146 and           x = 4.833

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The total sales done by Madelyn Logan is $975,000.

Madelyn Logan earns $58,000 in total.

Madelyn Logan's total commissions are;

$58,000 - $19,000 (base salary) = $39,000.

That is, $39,000 equals 4% of her sales.

So,

0.04x = $39,000, in which x would be the total sales amount.

Then, x = $39,000 /0.04

x = $975,000.

Therefore, Madelyn Logan must sell the goods of worth $975,000. for making the amount of $58,000.

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Answer:

x-4303

Step-by-step explanation:

The value of k for which the three points (1,8​), ​(2,11​), and​ (3,k) be on the same​ line will be on the same line is 14.

The slope is the rate of change.It can also be defined as the rise over run.

According to the given question for what value of k will the three points ​   (1,8​), ​(2,11​), and​ (3,k) be on the same​ line.

If three three points are on the same line they are co-linear and the slope of the points (1,8​), ​(2,11​) and (2,11​), (3,k) will be same.

∴ (11-8)/(2-1) = (k-11)/(3/2)

11-8 = k - 11

k = 11 + 11 - 8

k = 22 - 8

k = 14.

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