Melissa reserves another rectangular patch in her vegetable garden for growing bell peppers. Since the space that she can reserve for a rectangular bell pepper patch depends on how large she makes the tomato patch, she uses function p to represent the area of the bell pepper patch, where x is the length of the tomato patch. Select the correct answer from each drop-down menu.

Melissa Reserves Another Rectangular Patch In Her Vegetable Garden For Growing Bell Peppers. Since The
Melissa Reserves Another Rectangular Patch In Her Vegetable Garden For Growing Bell Peppers. Since The

Answers

Answer 1

The correct answer from each drop-down menu is as follows:

The function p is a quadratic function.When the length of the tomato patch is 8 feet, the area of the bell pepper patch is equal to 16 square feet.The maximum possible area of the bell pepper patch is 18 square feet when the length of the tomato patch is 6 feet.

What is a quadratic function?

A quadratic function can be defined as a mathematical expression that can be used to define and represent the relationship that exists between two or more variable on a graph.

In Mathematics, the graph of any quadratic function is parabolic because it is a u-shaped curve. For the given quadratic function, the graph is a downward parabola because the coefficient of x² is negative.

Therefore, function p is a quadratic function.

When the length of the tomato patch is 8 feet, the area of the bell pepper patch is given by:

p(x) = -0.5x² + 6x

p(8) = -0.5(8)² + 6(8)

p(8) = -0.5(64) + 48

p(8) = -32 + 48

p(8) = 16 square feet.

From the graph, we can logically deduce that the maximum possible area occurred at x = 6 feet. Thus, maximum possible area is given by:

p(x) = -0.5x² + 6x

p(6) = -0.5(6)² + 6(6)

p(6) = -18 + 36

p(6) = 18 square feet.

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Related Questions

The diagram below shows a large cone divided horizontally into two parts A and B. Given that the vertical height of A and B are equal, and that the volume of A is x cm³. Express the volume of the entire large cone in terms of x. [2] If the volume of part B is 3500 cm³, calculate the volume of cone A. [2] ​

Answers

Answer:

3500cm3

Step-by-step explanation: since A and B are equal, and B has a volume of 3500 cm3 then A will have the same.

Extra: The horizontal measure of A is 1500 and the verticle is 1500


Position and label each triangle on the coordinate plane.
right ΔM N O with right angle at point M and legs of lengths a and 2 a .

Answers

We need to position the right triangle Δ MNO in the first quadrant with coordinates , M(0,0) , N (0,a) & O (2a,0).

It is given that Δ MNO with right angle at point M has legs of lengths a and 2a .

We have to position the triangle on coordinate plane.

What is a right angled triangle ?

A right-angled triangle is a type of triangle that has one of its angles equal to 90 degrees.

As per the question ;

The triangle is a right angle triangle, so it's two sides can be located

on axis.

Place the right angle of the triangle Δ MNO at M.

i.e., M will have coordinates (0,0)

The origin will allow the two legs to be along the x and y-axes , so position the triangle in the first quadrant.

As N is on the y-axis ;

Its x-coordinate will be 0 and the y-coordinate will be a , because the leg is a units long.

i.e., N will have coordinates (0,a)

As O is on the x-axis,

its y-coordinate will be 0 and the x-coordinate will be 2a , because the leg is 2a units long.

i.e.,

O will have coordinate (2a,0)

We can put these coordinates after placing the triangle in the first quadrant i.e., M (0,0) , N (0,a) & O (2a,0).

Thus , we need to position the right triangle Δ MNO in the first quadrant with coordinates , M(0,0) , N (0,a) & O (2a,0).

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Find the missing term(s) of each arithmetic sequence. -1, □, 11,. . . .

Answers

The missing term is 6.

Here the sequence is -1,__, 11...

An arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Here the sequence is in an arithmetic sequence, as there is a common difference between the two numbers.

To find the nth term of the sequence we have a formula:

[tex]a_{n}[/tex] = a + (n-1)d

From this we can find a common difference, as we know the 3rd term of the sequence.

[tex]a_{3}[/tex] = -1 + (3-1) d

11 = -1 + 2d

2d = 12

d = 6

Now we have to the 2nd term of the series we have

[tex]a_{2}[/tex] = -1 + (2-1) 6

   = -1 + 6

   = 5

Therefore the 2nd i.e., the missing term of the sequence is 5

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Given: <5=<16;<2=<4
Prove: <11 and <14 aré supplementary

Answers

Given the question, <11 and <14 are supplementary because they sum up to give 180 degrees. Detail below

What are supplementary angles?

These are angles that sum up to give 180 degrees. On the other hand, angles on a straight line sum up to give 180 degrees.

Considering the question given above, we can prove that <11 and <14 are supplementary as follow:

<11 + <12 = 180 (angle on straight line)

But

<12 = <14 (corresponding angles)

Thus,

<11 + <14 = 180

Recall

Angle that sum up to give 180 are called supplementary angles

Therefore,

<11 + <14 = 180 => supplementary

From the illustrations given above, we can see clearly that <11 and <14 are supplementary angles

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Simplify by combining like terms. -a² + 2b² + (1/4) a²

Answers

The Simplified value is [tex]\frac{-3}{4} a^{2} +2b^{2}[/tex].

Like terms are defined as terms that have same variable and and same power.

For Example ; 2a² , 6a² are like terms.

In the given question ,

[tex]=-a^{2} +2b^{2} +\frac{1}{4} a^{2} \\ \\ =-a^{2} +\frac{1}{4} a^{2} +2b^{2}[/tex]

[tex]=a^{2}(-1+\frac{1}{4} )+2b^{2}[/tex]  ( taking a² common )

taking LCM and solving further we get

[tex]=a^{2} (\frac{-4+1}{4} )+2b^{2}[/tex]

[tex]=\frac{-3}{4} a^{2} +2b^{2}[/tex]

Therefore , The value by combining Like terms in -a² + 2b² + (1/4) a² is [tex]\frac{-3}{4} a^{2} +2b^{2}[/tex].

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Pls help with these 2 problems for 15 points

Answers

Answer:

1) 15

Step-by-step explanation:

The smallest integer is 15 because,

There are 7 consecutive integers with n + 6 being the largest, therefore:

7n + 21 = 6(6 + n)

7n + 21 = 36 + 6n

7n - 6n + 21 = 36

n + 21 = 36 ⇒ n = 36 - 21 = 15

Hope this helps!

2) -3  

2/5 = .4

Under her cell phone plan, Jocelyn pays a flat cost of $35 per month and $5 per
gigabyte. She wants to keep her bill under $55 per month. Use the drop-down menu
below to write an inequality representing g, the number of gigabytes she can use
while staying within her budget.
g
Submit Answer

Answers

Answer:

< 5 gigabytes

Step-by-step explanation:

Let the number of gigabytes be represented as: g

Under her cell phone plan, Nicole pays a flat cost of $35 per month and $5 per gigabyte. She wants to keep her bill under $60 per month.

Under $60 = less than (<) $60

Hence, our inequality equation is given as:

$35 + $5 × g < 60

35 + 5g < 60

Collect like terms

5g < 60 - 35

5g < 25

g < 25/5

g < 5 gigabytes

Therefore, the number of gigabytes she can use while staying within her budget less than 5 gigabytes

I need help with this question that’s for my geometry class.

Answers

By Euclid's axioms we proved that AC=BD

Things which are equal to the same thing are also equal to one another.

If equals be added to equals, the wholes are equal.

If equals be subtracted from equals, the remainders are equal.

Things which coincide with one another are equal to one another.

The whole is greater than the part.

given that , B is in between A and C

and C is between B and D

and also given that AB=CD

let AC=AB+BC .......(1)

    BD=BC+CD ........(2)

   subtract 1-2

we get, AC-BD=AB+BC-BC-CD

  AC-BD=AB-CD

we know AB=CD so we get

  AC-BD=0

 AC=BD

Hence, Proved

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Answer:

We established that AC=BD using Euclid's axioms.

Step-by-step explanation:

Things that are equivalent to one another are also equivalent to the same object.

The wholes are equal if equals are added to equals.

The remainders are equal when equals are subtracted from equals.

Things are equivalent to one another if they occur simultaneously.

A component cannot possibly equal the whole.

given that , B is in between A and C

and C is between B and D

and also given that AB=CD

let AC=AB+BC .......(1)

   BD=BC+CD ........(2)

  subtract 1-2

we get, AC-BD=AB+BC-BC-CD

 AC-BD=AB-CD

we know AB=CD so we get

 AC-BD=0

 AC=BD

Hence, Proved

200 learner's in grade 10 class.107 learner's takes history.63 learners take science and 147 learner's take both history and science and how many learner's take neither of the subjects

Answers

Answer:

I believe the answer is 30.

Step-by-step explanation:

-


What are the solutions of the rational equation?
a. x-1 / x+2 = x² + 2 x-3/x+2

Answers

The solutions of the rational equation x-1 / x+2 = x² + 2 x-3/x+2 are x = -2 and x = 1

In this question,

We have been given a rational equation.

x-1 / x+2 = x² + 2 x-3/x+2

We need to find the solution of given rational equation.

Here, the denominator is same on the both sides.

x-1 / x+2 = x² + 2 x-3/x+2

⇒ x - 1 = x² + 2 x-3

⇒ x² + 2x - 3 - x + 1 = 0

⇒ x² + x -2 = 0

We solve above quadratic equation.

⇒ x² + 2x - x - 2 = 0

⇒ x(x + 2) - (x + 2) = 0

⇒ (x + 2)(x - 1) = 0

⇒ x + 2 = 0                or          x - 1 = 0

⇒ x = -2        or         x = 1

Therefore, the solutions of the rational equation x-1 / x+2 = x² + 2 x-3/x+2 are x = -2 and x = 1

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a babysitter earns $8 an hour

Answers

Answer:

8xh h=hours

Step-by-step explanation:

8 times how ever much hour than that's all if there's tips well just add it to your answer

Identify the vertex, the axis of symmetry, the maximum or minimum value, and the domain and the range of each function.
y=(x-125)²+125 .

Answers

Each function's vertex, axis of symmetry, maximum or lowest value, domain, and range are all described as follows: Vertex: (125,125); range: (125,125); minimum: at y=125;  x=125; maximum: no., axis of symmetry is x=125.

Describe Domain and Range.

The domain of a function is the set of values that we are allowed to enter into our function.

The set of values that a function can accept as input is known as its range.

According to given data;

            y=(x-125)²-125

we know that;

y=(x-h)²+k

Vertex: In this form, the vertex (or, in other words, the "pointy bit") is given to us in the (h ,k);here we have (125,125).

Axis of symmetry : Two equal segments of the parabola. It moves straight up and down via the vertex.

Thus, we may formulate an equation for the vertical line that passes through the vertex. It is x=125 in this query..

Maximum and lowest values: Here, we're concerned in examining the vertex to determine whether it is at the maximum or lowest of the parabola's range (i.e., when a negative sign is placed in front of the (x-h) = 0 term, respectively).

Range: The value of range is (125,∞ )

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Point Q is the midpoint of GH. GQ = 2x + 3, and GH = 5x - 5. What is the length of GQ?
Enter your answer in the box.

Answers

Answer:

[tex]\displaystyle 25 = GQ[/tex]

Step-by-step explanation:

If point Q is the centre of GH, then QH and GQ are equivalent segments. So, double the length of GQ, set it equal to the length of GH, then solve for x:

[tex]\displaystyle \boxed{4x + 6} = 2[2x + 3] \\ \\ 5x - 5 = 4x + 6 \hookrightarrow -11 = -x \hookrightarrow \boxed{\boxed{11 = x}}[/tex]

Plug the result into the expression for the length of GQ to get twenty-five units.

I am joyous to assist you at any time.

There are 8 roses and 6 daisies in a vase What is the ratio of all flowers in the vase to roses

Answers

Answer:

14 to 8

Step-by-step explanation:

8 roses+6 daisies=14 is all the flowers in the vase

The distance from Charlotte, North Carolina, to Knoxville, Tennessee, is
2.31 × 10 miles. The distance from Charlotte, North Carolina, to El Paso,
Texas, is about 7 times that distance. What is the approximate distance
from Charlotte to El Paso?
A. 1.62 × 10 miles
B. 9.31 × 10 miles
C. 1.62 × 10 miles
D. 9.31 × 10 miles

Answers

The approximate distance from Charlotte to El Paso is  1. 62 × 10 miles . Options A and C

How to determine the distance

From the information given, we have that;

Distance from Charlotte, North Carolina, to Knoxville, Tennessee, is 2.31 × 10 milesDistance from Charlotte, North Carolina, to El Paso, Texas, is about 7 times that distance

To determine the distance from Charlotte to El Pasco, we have the expression

= 7 × distance from Charlotte to Knoxville

Substitute the value

= 7 × 2.31 × 10 miles

= 1. 62 × 10 miles

Thus, the approximate distance from Charlotte to El Paso is  1. 62 × 10 miles . Options A and C

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After robbing a bank in Dodge City, a robber gallops off at 14 mi/h. 30 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in minutes) after the marshall takes off does it take the marshall to catch up to the robber?

Answers

Answer:

Step-by-step explanation:

The number of minutes it will take the marshal to catch up to the robber in discuss is; 210.

How long will it take to catch up with the robber?

Let 30minutes = 0.5 hours.

Let x represent the time for which the marshal has ran.

On this note, the robber must have galloped at; (x +0.5) hours.

Hence, it follows from the task content that if they are at the same distance from the bank; we have;

14(x+0.5) = 16(x)

14x + 7 = 16x

7 = 2x

x = 7/2 = 3.5 hours.

= 3.5 × 60minutes = 210minutes.

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ΔE F G is a 30°-60°-90° triangle with m∠ F=90 . Find the coordinates of E in Quadrant III for F(-3,-4) and G(-3,2).FG is the longer leg.

Answers

The coordinates of E in Quadrant lll is (3 - [tex]2\sqrt{3}[/tex], -4)

Given,

m < F = 90°

E (x, y) in quadrant lll

F(-3, 4), G(-3, 2)

FG = The longer leg.

FG = [tex]\sqrt{(-3-(-3)^{2} )+(2-(-4)^{2} }[/tex] = [tex]\sqrt{36}[/tex] = 6

FE = [tex]\frac{FG}{\sqrt{3} }[/tex] = [tex]\frac{6}{\sqrt{3} }[/tex] = 2[tex]\sqrt{3}[/tex]

GE = 2FE = 2 × 2√3 = 4√3

ΔEFG is a 30° - 60° - 90° triangle with the longest leg FG = 6.

We apply the 30° - 60° - 90° triangle theorem to determine the short side FE and the hypotenuse GE.

l = 4√3

h = 2√3

[tex]\sqrt{(x-(-3))^{2} +(y-(-4))^{2} }[/tex] = (2√3)²

[tex]\sqrt{(x-(-3))^{2} +(y-2)^{2} }[/tex] = (4√3)²

∴ (x + 3)² + ( y + 4)² = 12

   (x + 3)² + (y - 2)² = 48

Solving this, we get:

Coordinates of E as (3 - 2√3, -4)

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There are 80 animals on a farm. 52 of the animals are chickens.
a) What fraction of the animals are chickens?
Give your answer in its simplest form.
b) Write your answer to part a) as a decimal.

Answers

The fraction of the animals in chickens is 52/80 which is 0.65 in decimal form.

What are fractions?A fraction is a portion of a whole or, more broadly, any number of equal parts. In everyday English, a fraction describes the number of parts of a specific size, such as one-half, eight-fifths, or three-quarters. In mathematics, there are six types of fractions: proper/improper fractions, mixed fractions, equivalent fractions, and like/, unlike fractions. A fraction has two parts: the numerator and the denominator.

So, (A) The fraction of the animals is chickens: 52/80

Simplest form: 13/20

(B) In decimal form: 0.65

Therefore, the fraction of the animals in chickens is 52/80 which is 0.65 in decimal form.

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PLEASE HELP?
Pedro went to the store and spent $36.85. He paid with a $50 bill. How much money will he get back as
change? Show All Your Work for full credit.

Answers

Answer:

Step-by-step explanation:

change = dollar_amount - spent_amount

change = 50 - 36.85

change = 13.15

50-36.85
Change=13.15

100 POINS 1 QUESTION!

Answers

Answer:

Step-by-step explanation:

we cant see the question :)

Answer: If you have to fill in the chart I think you just add them together so aluminum would be +3, phosphide -3, iodide -1, and tin 0

Step-by-step explanation:

. If there are 4.90 Cal in 10.0 g of parsley, how many joules are in 12.1 g of parsley?

Answers

The joules are in 12.1 g of parsley is 24.806936 Joules of energy

10g has 4.9 cal

1g has 4.9/10 cal

Energy in 12.1 g = 4.9 x 12.1 / 10 = 5.929 Cal = 5.929 x 4.18400 = 24.806936 Joules of energy [1 calorie = 4.18400]

In the International System of Units (SI), a joule is a unit of work or energy equal to the work done by a force of one newton acting through one meter. It is named after the English scientist James Prescott Joule and equals 107 ergs, or about 0.7377 foot-pounds. The joule is equivalent to one watt-second in electrical terms, which is the amount of energy released in one second by a current of one ampere through a resistance of one ohm.

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how to solve this question??​

Answers

limx→0sinaxcosbxsincx=limx→0(cosbx⋅sinaxax⋅cxsincx⋅ac)=ac

Please help of 3 through 6

Answers

Answer:

3, 9% more people have green as their favorite color over yellow. 4. Picture is cut off so I can't see sorry 5. science and social studies 6. Mike spends 40% more time studying math then he does science

Step-by-step explanation:

What is the slope of the line that goes through the points (-4,2) and (8,5)? A. B. C. D.

Answers

Answer:

4

Step-by-step explanation:

The slope of the line with points p(x, y) and p′(x′, y′) is given by:

[tex] (\frac{x. \: - \: x}{y. \: \: - y } )[/tex]

[tex] (\frac{8 - ( - 4)}{5 - 2} )[/tex]

12/3

slope = 4

(15 POINTS PLEASE HURRY!!) Open the parallel lines reflection application. The right set of parallel lines is a reflection across the y-axis of the left set of parallel lines. Click the reflect over y-axis button. Are the two sets of parallel lines the same? What does this mean about how parallel lines change when you reflect them?

Answers

Based on the fact that the right line is a reflection across the y-axis, the lines are the same, they are just in a different position.

What is a Reflection?

This refers to the rigid transformation type that is used to represent an image and does not change its size or length of it.

With this understanding, we can see that the pre-image and the image in a rigid transformation are congruent which makes the lines to be the same, even if they are in a different position.


Divide. State any restrictions on the variable. 3x²-9 x / x-2 ÷ x² - 9 / 4 x-8

Answers

The division of given rational expression 3x²-9 x / x-2 ÷ x² - 9 / 4 x-8 is 12x / x + 3 provided x ≠ -3

In this question,

we have been given a complex rational expression [tex]\frac{3x^{2} -9x}{x-2}\div \frac{x^2-9}{4x-8}[/tex]

We need to find the division of given rational expression.

We rewrite given rational expression as,

3x²-9 x / x-2 ÷ x² - 9 / 4 x-8

= 3x²-9 x / x-2 / x² - 9 / 4 x-8

= (3x²-9 x / x-2) × (4 x-8 / x² - 9 )

= [tex]\frac{3x(x-3)}{x-2}\times \frac{4(x-2)} {(x+3)(x-3)}[/tex]

= 12x / x + 3     .........(provided x ≠ -3)

Therefore, the division of given rational expression 3x²-9 x / x-2 ÷ x² - 9 / 4 x-8 is 12x / x + 3 provided x ≠ -3

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Earth's radius is approximately 6400 kilometers. What are the surface area and volume of the Earth? Round to the nearest tenth if necessary.

Answers

The surface area of earth is 514.4million [tex]Km^{2}[/tex] and the volume of the Earth is 1.1 ×[tex]10^{12}[/tex] [tex]Km^{3}[/tex].

Radius of Earth = 6400 (approximately).

Earth is a sphere. So by using the formula of Surface Area of sphere we can calculate the Surface area of earth as follows,

Surface Area of Earth = 4[tex]\pi r^{2}[/tex] = 4 × (3.14) × [tex](6400)^{2}[/tex]

                                    =  4 × 3.14 × 40960000

                                    = 514457600 [tex]Km^{2}[/tex]

                                    = 514.4million [tex]Km^{2}[/tex]

The surface area of earth is 514.4million [tex]Km^{2}[/tex] .

Similarly, by using the formula of volume of sphere we can calculate the volume area of earth as follows,

Volume of Earth = (4/3)[tex]\pi r^{3}[/tex]

                           = (4/3)×(3.14)×[tex](6400)^{3}[/tex]

                           =(1.3333)(3.14)(2.6214 × [tex]10^{11}[/tex])

                           = 1.0975 × [tex]10^{12}[/tex] [tex]Km^{3}[/tex]

                           = 1.1 ×[tex]10^{12}[/tex] [tex]Km^{3}[/tex]

The volume of the Earth is 1.1 ×[tex]10^{12}[/tex] [tex]Km^{3}[/tex].

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Lincoln High School has 75 less than 4 times as many students as Washington High School. a. Write an expression to find the number of students at Lincoln High School if Washington High School has w students. w + b. How many students are at Lincoln High School if Washington High School has 250 students? students

Answers

Answer: A. 4w+(-75)

B. 925

Step-by-step explanation:

Owen drove 9 miles total five days this week on Saturday he drove 17 miles to his grandmas house how many total miles did he drive this week

Answers

Answer:

26 miles

Step-by-step explanation:

add 9 miles to 17 miles= 26 miles

Which value of p is a solution to this equation?
p–6=2

Answers

Answer:

[tex] \sf \large \: p = 8[/tex]

Step-by-step explanation:

Let's solve the equation step by step,

p – 6 = 2

Add +6 to both sides

p - 6 + 6 = + 6

p = 8

Answer:

8

Step-by-step explanation:

Other Questions
__________ is(are) considered among the most important assets an organization has, other than its people. Chinese Transnational Policing Gone Wild110 Overseas The last decade has witnessed the rapid spread of telecom and online fraud globally, which seriously infringes on people's legitimate rights and interests, becoming a prominent crime and a public hazard. To address this problem, the Chinese police have been committed to intensifying their efforts in the combat against and control of such crimes, and strengthening international law enforcement cooperation, which has enabled them to accumulate successful experience, build up best practices and set examples for their counterparts around the world.Upholding the people-centered principle, the Communist Party of China and the Chinese government have attached great importance to countering telecom and online fraud. Equal importance has been given to both combat and control. An efficient multi-department collaborative working mechanism has been established, and the Anti-telecom and Online Fraud Law has been formulated and enacted, which provides a strong legal foundation. Targeting the characteristics of such crimes, the Chinese police have conducted specialized study and research, set up specialized task forces, initiated specialized investigation against major cases and utilized specialized techniques. The Chinese police have synchronized their efforts both internally and externally, and launched a series of campaigns and operations, effectively curbing the high momentum of these crimes, retrieving a large number of economic losses, and winning wide recognition from the public and the international community. During their international law enforcement engagements, the Chinese police frequently received requests from their counterparts to share their experience and effective practices in this field.Telecom and online fraud is a typical transnational organized crime. Fraud dens are often located across countries and regions, targeting vulnerable individuals and groups regardless of their nationalities. The Chinese police, through international law enforcement cooperation, have joined hands with their international counterparts to carry out operations and achieved significant results. Operation Great Wall, jointly launched with the Spanish police in 2019, has become a successful example of transnational law enforcement cooperation. From March to June this year, China, together with 76 INTERPOL member states, jointly participated in the anti-fraud Operation First Light initiated by INTERPOL, which destroyed 1,770 fraud dens in as many countries, arrested over 2,000 suspects and intercepted more than US$50 million in illicit funds. It was also found that some Chinese citizens were involved in fraud activities abroad, and the majority of them were tempted by the promise of high payments, cheated and coerced into being smuggled abroad, and some of them were kidnapped and detained illegally, and a few of them were even beaten and abused to death in the criminal dens. The Chinese police, together with relevant departments, have actively carried out rescue and education, and encouraged them to return home through international law enforcement cooperation, and made every effort to provide assistance and employment. The immigration authorities, in accordance with the provisions of the Exit and Entry Administration Law, have taken necessary measures such as restricting the exit of persons engaged in telecom and online fraud.According to an officer with the Ministry of Public Security, the criminality of telecom and online fraud is characterized by its specialization, industrialization and being increasingly organized and transnational, amid the rapid development of global digitalization. As an emerging new-type crime, it is a very difficult problem for governments of various countries to tackle and control, and thus it has become one of the major challenges facing police forces across the world. Joining hands in combating this newly developed fraud is the shared responsibility of the police of all countries and also the unanimous consensus of the international community. Public security agencies across China are determined to earnestly enforce the Law of Anti-telecom and Online Fraud through strengthened cooperation with their international counterparts and reinforced domestic efforts in fighting the crime, so as to prevent it from further spreading, and to bringing the fraudsters at large to justice. Which of the following expressions have the same value as the mixed number ( ), select ALL correct answers. who was the first to use water and containers to create arrangements? What property of matter is measured in cubic centimeters? Is a non-carbonated soft drink a heterogeneous mixture, solution, compound, or element? Add or subtract. Simplify where possible. 4 / x-36 + x / x-6 Explain how Muslim attention to works of Ancient Greek thinkers eventually? By ordering a serum fasting glucose level for a patient with obesity and risk factors for diabetes, a nurse practitioner exemplifies what level of prevention? 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