metallic tungsten crystallizes in a body-centered cubic lattice, with one w atom per lattice point. if the edge length of the unit cell is found to be 316 pm, what is the metallic radius of w in pm?

Answers

Answer 1

The body-centered cubic lattice has atoms located at each corner of a cube and one atom located in the center of the cube. In this case, metallic tungsten has one atom (W) per lattice point in this arrangement.

The edge length of the unit cell is given as 316 pm. Since the metallic tungsten is located at the center of the cube, it is touching atoms at each of the corners of the cube. Using this information, we can calculate the metallic radius of W by dividing the edge length by the square root of 3, which is the number of radii in the body diagonal of the cube. Thus, the metallic radius of W is (316 pm) / sqrt(3) = 182.4 pm.


Metallic tungsten (W) crystallizes in a body-centered cubic (BCC) lattice, where one W atom is at each lattice point. In a BCC unit cell, the relationship between the edge length (a) and the metallic radius (r) is given by the equation: a = 4r/√3. Given that the edge length of the unit cell is 316 pm, we can find the metallic radius of W using this formula. Rearrange the equation as r = a√3/4, and substitute the given edge length: r = (316 pm)(√3)/4 ≈ 136.4 pm. Thus, the metallic radius of tungsten is approximately 136.4 pm.

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Related Questions

Find the change in enthalpy (∆H) for the reaction below. Round your answer to the nearest 0.1 and include proper units.
XaZQ(s) + QBg(aq) --> XaBg(aq) + Q2Z(l)

The following information is available:
XaZQ(aq) -->XaZQ(s) ∆H = 6.8 kJ
XaZQ(aq) + QBg(aq) --> XaBg(aq) + Q2Z(l) ∆H = 50.5 kJ

Your Answer:

Answers

The change in enthalpy (∆H) for the given reaction is -57.3 kJ.

To find the change in enthalpy (∆H) for the given reaction, we can use Hess's law, which states that the overall enthalpy change for a reaction is the same regardless of the pathway taken, and can be calculated by adding or subtracting the enthalpy changes of individual reactions involved in the overall process.

The given reaction can be broken down into two steps:

XaZQ(s) → XaZQ(aq) (∆H1 = -6.8 kJ) [Reverse of dissolution process]

XaZQ(aq) + QBg(aq) → XaBg(aq) + Q2Z(l) (∆H2 = -50.5 kJ)

Since the first step is the reverse of the dissolution process, its enthalpy change (∆H1) is the negative of the enthalpy of hydration (∆Hhydration) of XaZQ, which is given as -6.8 kJ.Therefore, the overall enthalpy change (∆H) for the reaction can be calculated as:

∆H = ∆Hhydration + ∆H2

∆H = -6.8 kJ + (-50.5 kJ)

∆H = -57.3 kJ

The negative sign indicates that the reaction is exothermic, i.e., it releases heat.

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Ms.T is thinking of two numbers. If I take half of the first number and add it to one-third of the second number, the sum is two. The second number is 3 more
than 6 times the first number. What is the product of my two numbers?

Answers

The first number is therefore 8 while the second is 2. Number words are a linguistic way to express numbers. 16 is the product of my two numbers

A number is a numerical unit of measurement and labelling in mathematics. The natural numbers 1, 2, 3, 4, and so on are the first examples. Number words are a linguistic way to express numbers. Eight is the first number, while two is the second. Let's first remove our responses to arrive at 18 – 14 = 4. Divided by 2, 4/2 equals 2. Adding 2 to the portion where 2 was deleted now gives us 16. Divided by 2, 16/2 equals 8. The first number is therefore 8 while the second is 2.

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Which of the following elements is likely to pair with sulfur in a 1:1 relationship based on valence electron trends

Answers

The element that is likely to pair with sulfur in a 1:1 relationship based on valence electron trends is oxygen (O).

Sulfur (S) and oxygen (O) belong to the same group (group 16, also known as the chalcogens) in the periodic table, and they both have 6 valence electrons. Elements in the same group tend to have similar valence electron configurations and chemical properties.

In a 1:1 relationship, sulfur would need to share one electron with another element to complete its valence shell. Oxygen, being in the same group as sulfur, also needs one more electron to complete its valence shell. Thus, sulfur and oxygen can form a 1:1 relationship by sharing one electron each, resulting in a covalent bond.

In summary, based on their valence electron trends, oxygen is likely to pair with sulfur in a 1:1 relationship.

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Answer:

Mg

Explanation:

what is the pressure in a 11.5- l cylinder filled with 0.440 mol of nitrogen gas at a temperature of 317 k ?

Answers

The pressure in a 11.5-l cylinder filled with 0.440 mol of nitrogen gas at a temperature of 317 K can be calculated using the ideal gas law equation: Where P is the pressure in atmospheres (atm), V is the volume in liters (l), n is the number of moles of gas, R is the ideal gas constant (0.0821 L atm/K mol), and T is the temperature in Kelvin (K).

First, let's convert the volume from liters to cubic meters (m^3) since the ideal gas constant has SI units. 1 L = 0.001 m^3. So, 11.5 L = 0.0115 m^3. Now, we can plug in the values we have: P(0.0115 m^3) = (0.440 mol)(0.0821 L atm/K mol)(317 K) Therefore, the pressure in the 11.5-l cylinder filled with 0.440 mol of nitrogen gas at a temperature of 317 K is 10.4 atm. The ideal gas law is a fundamental equation used to describe the behavior of gases under different conditions of temperature, pressure, and volume. It states that the pressure, volume, and temperature of an ideal gas are related through the equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.

In this question, we are given the volume of a cylinder filled with nitrogen gas, the number of moles of nitrogen gas, and the temperature. We are asked to find the pressure of the gas in the cylinder. To solve this problem, we can use the ideal gas law equation. First, we need to convert the volume from liters to cubic meters because the ideal gas constant has SI units. 1 L = 0.001 m^3, so 11.5 L = 0.0115 m^3. Therefore, the pressure in the 11.5-l cylinder filled with 0.440 mol of nitrogen gas at a temperature of 317 K is 10.4 atm. In conclusion, the ideal gas law is a useful equation that helps us to describe the behavior of gases under different conditions. By knowing the values of pressure, volume, temperature, and number of moles, we can use the ideal gas law equation to calculate the value of any one of these variables. In this case, we used the ideal gas law equation to calculate the pressure of nitrogen gas in a cylinder.

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biomarkers such as serum micronutrient levels, which can determine a person's fruit and vegetable intake more accurately than can personal interviews, are used in which field of modern epidemiology?

Answers

Answer:

Biomarkers such as serum micronutrient levels are used in the field of nutritional epidemiology. Nutritional epidemiology is a subfield of epidemiology that focuses on the relationship between diet and health. Biomarkers are substances that can be measured in the body and that provide information about a person's health. Serum micronutrient levels can be used as biomarkers of fruit and vegetable intake because they are a reflection of the amount of fruits and vegetables that a person has eaten.

There are a number of advantages to using biomarkers to assess fruit and vegetable intake. First, biomarkers are more accurate than self-reported dietary intake. People often underestimate their fruit and vegetable intake, so biomarkers can provide a more accurate assessment of their diet. Second, biomarkers can be used to assess fruit and vegetable intake over time. This is important because fruit and vegetable intake is associated with a number of health outcomes, including a reduced risk of chronic diseases such as heart disease, stroke, and cancer.

Biomarkers such as serum micronutrient levels are a valuable tool for nutritional epidemiology. They can be used to assess fruit and vegetable intake more accurately than self-reported dietary intake, and they can be used to assess fruit and vegetable intake over time. This information can be used to develop interventions to improve fruit and vegetable intake and to reduce the risk of chronic diseases.

Explanation:

a 25-g piece of aluminum at 85c is dropped in 0.50 liter of water at 10c which is in an insulated beaker. assuming that there is negligible heat loss to the surrounding, determine the equilibrium temperature of the system.

Answers

To determine the equilibrium temperature of the system, we can use the principle of conservation of energy, specifically the heat gained by the water is equal to the heat lost by the aluminum.

The equation for heat transfer is given by:

Q = mcΔT

Where Q is the heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

First, calculate the heat lost by the aluminum:

Q_aluminum = m_aluminum * c_aluminum * ΔT_aluminum

Next, calculate the heat gained by the water:

Q_water = m_water * c_water * ΔT_water

Since the heat lost by the aluminum is equal to the heat gained by the water, we can equate the two equations and solve for the equilibrium temperature:

m_aluminum * c_aluminum * ΔT_aluminum = m_water * c_water * ΔT_water

Rearrange the equation to solve for the equilibrium temperature, which is ΔT_water:

ΔT_water = (m_aluminum * c_aluminum * ΔT_aluminum) / (m_water * c_water)

Substitute the given values and calculate the equilibrium temperature of the system.

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how you can use optical absorption measurements to determine whether a semiconductor has direct or indirect band gap.

Answers

Optical absorption measurements can be used to determine whether a semiconductor has a direct or indirect band gap by analyzing the spectral data.

Direct band gap materials absorb light more strongly at a specific wavelength, while indirect band gap materials absorb light less strongly, and at multiple wavelengths. By plotting absorption versus energy, the bandgap energy of the semiconductor can be determined. In a direct bandgap material, the absorption edge will be sharp and appear at a specific energy, whereas in an indirect bandgap material, the absorption edge will be broader and less defined. By examining the absorption spectra, researchers can determine the bandgap energy and type of the semiconductor, which is crucial for optimizing its electronic and optical properties for specific applications.

Optical absorption measurements can be used to determine if a semiconductor has a direct or indirect band gap by analyzing the absorption coefficient (α) as a function of photon energy (E). In a direct band gap semiconductor, electrons transition directly between the valence and conduction bands with photon absorption, resulting in a high α. In an indirect band gap semiconductor, electrons require both photon absorption and phonon interaction for the transition, leading to a lower α.

By plotting the absorption coefficient (α) versus photon energy (E), the relationship between α and E can be observed. For direct band gap semiconductors, α is proportional to (E-Eg)^2, where Eg is the band gap energy. For indirect band gap semiconductors, α is proportional to (E-Eg)^3/2. By comparing the experimental curve to these relationships, the semiconductor type can be identified.

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when neutrons bombard magnesium-24, a neutron is absorbed, and a photon is released. what new element/isotope is formed?

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Magnesium-25 is formed when neutrons bombard magnesium-24, as a neutron is absorbed and a photon is released.

When a neutron is absorbed by magnesium-24, the nucleus becomes unstable and undergoes beta decay to form a new element, magnesium-25. This isotope of magnesium has one additional neutron compared to magnesium-24, making it slightly heavier. The release of a photon during this process indicates the energy release as the nucleus transitions to a more stable state.

This process is commonly used in nuclear reactors to produce new isotopes or elements by bombarding a target material with neutrons. Magnesium-25 is unstable and undergoes beta decay to form sodium-25 with a half-life of 68.9 days. This process can also be used in medical applications, such as cancer treatment, to selectively target and destroy cancerous cells using neutron beams.

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What is low water fuel cutoff for boiler?

Answers

A low water fuel cutoff is a safety device that is commonly used in boilers to prevent the boiler from operating without sufficient water. The purpose of the low water fuel cutoff is to shut off the fuel supply to the burner when the water level in the boiler drops below a certain point, which can prevent damage to the boiler and ensure safe operation.

In a typical low water fuel cutoff system, a probe or sensor is installed in the boiler to detect the water level. If the water level drops below the set point, the sensor sends a signal to a control unit, which activates a switch that shuts off the fuel supply to the burner. The system may also include an alarm or other warning device to alert the operator to the low water condition.

Low water fuel cutoffs are required by law in many jurisdictions, and are an important safety feature in boiler operation. They can help prevent catastrophic boiler failures due to overheating and other issues that can occur when the water level in the boiler drops too low. It is important to ensure that the low water fuel cutoff system is properly installed, maintained, and tested regularly to ensure safe and reliable boiler operation.

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which of the following refers to a feature of the conception of the divine found in judaism?

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One key feature of the conception of the divine found in Judaism is monotheism, the belief in a single, all-powerful God.

Monotheism is a fundamental characteristic of Judaism. It is the belief in the existence of only one God, who is seen as the creator and ruler of the universe. This monotheistic belief sets Judaism apart from many other ancient religions that embraced polytheism. In Judaism, God is regarded as a singular, indivisible entity who is infinite and beyond human comprehension.

The concept of monotheism in Judaism is rooted in various sacred texts, including the Hebrew Bible (Tanakh) and the teachings of Jewish scholars and philosophers. Judaism emphasizes the oneness and unity of God, rejecting the notion of multiple gods or divine beings. This belief in a singular, transcendent God forms the foundation of Jewish theology and is a defining characteristic of the Jewish conception of the divine.

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how many moles of ca(oh)2 are needed to neutralize three moles of hcl?

Answers

The balanced chemical equation for the reaction between calcium hydroxide (Ca(OH)2) and hydrochloric acid (HCl) is: Ca(OH)2 + 2HCl → CaCl2 + 2H2O

The balanced chemical equation tells us the stoichiometric ratio between the reactants and products.

In this case, we see that one mole of Ca(OH)2 reacts with two moles of HCl. This means that we need half as many moles of Ca(OH)2 as we have moles of HCl to completely neutralize the acid.

Therefore, to neutralize three moles of HCl, we need 1.5 moles of Ca(OH)2. This can be calculated using the ratio of the coefficients in the balanced equation.

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What is the ideal efficiency of a heat engine that operates with its hot reservoir at 500 K and its sink at 300 K

Answers

The ideal efficiency of a heat engine operating with its hot reservoir at 500 K and its sink at 300 K is 40%.

The ideal efficiency of a heat engine is given by the formula (Th - Ts)/Th, where Th is the temperature of the hot reservoir and Ts is the temperature of the sink.

The ideal efficiency of a heat engine can be determined using the Carnot efficiency formula. For a heat engine operating with a hot reservoir at 500 K and a sink at 300 K, the Carnot efficiency is:

Efficiency = 1 - (T_cold / T_hot)

Where T_cold is the temperature of the sink (300 K) and T_hot is the temperature of the hot reservoir (500 K). Plugging in the values, we get:

Efficiency = 1 - (300 K / 500 K) = 1 - 0.6 = 0.4 or 40%

So, the ideal efficiency of the heat engine under these conditions is 40%.

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Question
545 J of work is done on a gas and changes the volume by-2.50 L. What is the external pressure? Assume that the
external pressure is constant over the change in volume. Give the answer to three significant figures.

Answers

W = -P_ext ΔV

545 J = -P_ext × (-2.50 L)

545 J = 2.50 P_ext L

P_ext = -218 Pa

IG: whis.sama_ent

The following diagrams represent mixtures of NO(g) and O2(g). These two substances react as follows: 2NO(g) + O2(g)----2NO2(g) It has been determined experimentally that the rate is second order in NO and first order in O2. Based on this fact, which of the following mixtures will have the fastest initial rate? The mixture (1). The mixture (2). The mixture (3). The right answer is the mixture 1, but I do not know why. So..

Answers

Based on the given fact Mixture 1 has the fastest initial rate in the reaction 2NO(g) + O[tex]_2[/tex](g)----2NO2[tex]_2[/tex](g), where the rate is second order in NO and first order in O2.

The reaction is given as:

2NO(g) + O[tex]_2[/tex](g)----2NO2[tex]_2[/tex](g)
The rate law for this reaction can be written as:

Rate = k[tex][NO]^2[O_2][/tex]

where k is the rate constant, [NO] is the concentration of NO, and [O[tex]_2[/tex]] is the concentration of O2. To determine which mixture has the fastest initial rate, we need to compare the initial concentrations of NO and O[tex]_2[/tex] in each mixture.

Mixture 1:
- High concentration of NO
- High concentration of O[tex]_2[/tex]

Mixture 2:
- Low concentration of NO
- High concentration of O[tex]_2[/tex]

Mixture 3:
- High concentration of NO
- Low concentration of O[tex]_2[/tex]

Now let's compare the mixtures based on the rate law:

Mixture 1: Rate = k(x)[tex][High\ NO]^2[/tex] [High O[tex]_2[/tex]] = k(High NO^2)(High O[tex]_2[/tex])
Mixture 2: Rate = k([Low NO[tex]]^2[/tex])[High O[tex]_2[/tex]] = k(Low NO^2)(High O[tex]_2[/tex])
Mixture 3: Rate = k([High NO[tex]]^2[/tex])[Low O[tex]_2[/tex]] = k(High NO^2)(Low O[tex]_2[/tex])

Since the rate is second order in NO, the effect of NO concentration is more significant than that of O[tex]_2[/tex]. Mixture 1 has both high NO and high O[tex]_2[/tex]concentrations, which results in the highest rate among the three mixtures.

Therefore, the fastest initial rate occurs in mixture 1.


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Why cannot one determine the relative acid strengths of HClO4 and HNO3 using aqueous solutions of these acids?

Answers

While aqueous solutions of HClO4 and HNO3 may seem like a straightforward way to compare their acid strengths, it is not a reliable method due to the complete dissociation of both acids in water. Other methods, such as Ka values, must be used instead.


When comparing the relative acid strengths of HClO4 and HNO3, it is not possible to rely solely on their aqueous solutions. This is because both of these acids are strong acids, which means that they completely dissociate in water to produce H+ ions and their corresponding anions. As a result, the concentrations of H+ ions in their solutions are equal, making it impossible to differentiate their relative acid strengths.
To determine the relative acid strengths of HClO4 and HNO3, one would need to rely on other methods, such as measuring their respective dissociation constants (Ka). This involves measuring the extent to which each acid dissociates in water, which is reflected in their Ka values.
In summary, while aqueous solutions of HClO4 and HNO3 may seem like a straightforward way to compare their acid strengths, it is not a reliable method due to the complete dissociation of both acids in water. Other methods, such as Ka values, must be used instead.

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is the procedure used for the bicarbonate buffer a valid one for buffer preparation? why or why not?

Answers

The bicarbonate buffer system is a commonly used buffer in biochemical experiments, especially in studying enzymes and proteins.

The procedure used for the preparation of bicarbonate buffer involves the addition of sodium bicarbonate to a solution of carbon dioxide in water, which results in the formation of carbonic acid. This acid can then dissociate into bicarbonate ions and hydrogen ions, forming a buffer system. While this procedure is a valid one for buffer preparation, there are some limitations. The buffer capacity of the bicarbonate buffer system is relatively low compared to other buffer systems, and it is also sensitive to changes in temperature and pH. Therefore, the use of bicarbonate buffer should be carefully considered and optimized for specific experimental conditions.


Yes, the procedure used for the bicarbonate buffer is a valid one for buffer preparation. Bicarbonate buffer systems are widely used due to their capacity to maintain pH stability. They are commonly prepared using a combination of sodium bicarbonate (NaHCO3) and sodium carbonate (Na2CO3) or a weak acid like carbonic acid (H2CO3). By adjusting the ratio of these components, the desired pH can be achieved. The bicarbonate buffer is particularly important in physiological systems, as it plays a crucial role in maintaining blood pH within the narrow range required for optimal biological function. Its effectiveness as a buffer is attributed to the equilibrium between dissolved CO2, H2CO3, and bicarbonate ions.

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Select the classification for the following reaction.
NH3(aq) + HNO3(aq) → NH4NO3(aq)
Precipitation
Acid-base
Redox
Decomposition
None of these choices are correct.

Answers

Answer:

The reaction NH3(aq) + HNO3(aq) → NH4NO3(aq) is an acid-base reaction. In an acid-base reaction, an acid and a base react to form a salt and water. In this reaction, the acid is nitric acid (HNO3) and the base is ammonia (NH3). The salt that is formed is ammonium nitrate (NH4NO3).

The other choices are not correct. A precipitation reaction is a reaction in which a solid precipitate forms from a solution. A redox reaction is a reaction in which electrons are transferred between atoms or molecules. A decomposition reaction is a reaction in which a compound breaks down into two or more simpler substances.

Explanation:

iven the following anticodon, which mRNA codon would pair with it? 5'-AGC-3' A. 5-GCU-3 B. 5-GUA-3 C. 5-UCG-3 D. 5-ACU-3 E. 5-UCA-3

Answers

The statement given the following anticodon, which mRNA codon would pair with has the correct option C, which indicates the mRNA codon 5'-UCG-3'.

Given the anticodon 5'-AGC-3', the mRNA codon that would pair with it is 3'-UCG-5' (option C). This is because during translation, the tRNA anticodon binds to the mRNA codon in a complementary manner, following the rules of base pairing: Adenine (A) pairs with Uracil (U), and Guanine (G) pairs with Cytosine (C). In this case, the anticodon 5'-AGC-3' would bind to the mRNA codon with the complementary sequence: 3'-UCG-5'.

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In the reaction AgNO3(aq) + HI(a) → Agl(s) + HNO3(a) the spectator ions are A) Agt and NO3 B) Agt and I C) H+ and I- D) H+ and NO3 E) none of the above

Answers

The spectator ions in a chemical reaction are the ions that do not participate in the reaction and remain unchanged.

In the given reaction, AgNO3 and HI react to form AgI and HNO3. AgNO3 dissociates into Ag+ and NO3- ions, while HI dissociates into H+ and I- ions. In the reaction, Ag+ ion combines with I- ion to form insoluble AgI, while H+ ion combines with NO3- ion to form HNO3. Therefore, the spectator ions are neither Ag+ nor NO3- nor H+ ion. So, the correct answer is E) none of the above.


In the reaction AgNO3(aq) + HI(a) → AgI(s) + HNO3(a), the spectator ions are D) H+ and NO3-. Spectator ions are ions that don't participate in the chemical reaction and remain unchanged. In this case, Ag+ and I- form the precipitate AgI(s), while H+ and NO3- don't react and remain in the solution as spectator ions.

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an uncharged atom of boron has an atomic number of 5 and an atomic mass of 11. how many protons does boron have? an uncharged atom of boron has an atomic number of 5 and an atomic mass of 11. how many protons does boron have? 0 6 11 5 16

Answers

Answer:

The answer is 5.

Explanation:
The atomic number and proton are same.

Final answer:

An uncharged atom of boron, with an atomic number of 5, has 5 protons and 5 electrons to ensure its neutrality.

Explanation:

The atomic number of an atom specifically indicates the number of protons that atom contains. Since the atomic number of boron is given as 5, an uncharged atom of boron must have 5 protons. Remember that for an atom to be neutral or uncharged, the number of protons (positively charged particles) must equal the number of electrons (negatively charged particles), so an uncharged boron atom would also have 5 electrons.

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an atom with z = 26 and a = 58 contains ________ protons and ________ neutrons.

Answers

An atom with atomic number (Z) 26 and atomic mass (A) 58 contains 26 protons and 32 neutrons. The atomic number represents the number of protons in the nucleus of an atom, while the atomic mass represents the total number of protons and neutrons.

In an atom, the atomic number (Z) corresponds to the number of protons in the nucleus. In this case, the atom has an atomic number of 26, indicating that it contains 26 protons. The atomic mass (A) represents the total number of protons and neutrons in the nucleus. To determine the number of neutrons, we subtract the atomic number (Z) from the atomic mass (A). In this case, the atom's atomic mass is 58, and the atomic number is 26. Subtracting 26 from 58 gives us 32, which represents the number of neutrons present in the atom. Therefore, an atom with Z = 26 and A = 58 contains 26 protons and 32 neutrons.

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When you compare the atomic radius of silicon (Si) to that of phosphorus (P), ____.

Answers

When you compare the atomic radius of silicon (Si) to that of phosphorus (P), the atomic radius of silicon is larger.

Silicon and phosphorus are both elements found in the same period (Period 3) of the periodic table. As we move across a period from left to right, the atomic radius generally decreases.

This decrease in atomic radius is due to the increase in the number of protons in the nucleus, which leads to a stronger attraction between the electrons and the nucleus, pulling the electrons closer and thus reducing the atomic radius.

Silicon has an atomic number of 14, while phosphorus has an atomic number of 15. Since silicon is to the left of phosphorus in the periodic table, it has a larger atomic radius.
In summary, when comparing the atomic radius of silicon to phosphorus, silicon has a larger atomic radius due to its position in the periodic table.

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which body of water stretches across two hemispheres?

Answers

Answer:

Atlantic Ocean

Explanation:

The Atlantic Ocean is the body of water that stretches across two hemispheres. It is the second-largest ocean in the world and it crosses the equator, which means it is situated in both the Northern and Southern hemispheres. The Atlantic Ocean is located between North and South America to the west and Europe and Africa to the east, covering an area of approximately 106.4 million square kilometers.

Answer:

The rifting caused the landmasses of the Western and Eastern hemispheres to separate, opening up the Atlantic Ocean basin. As can be seen on a map of the world, the continental coastlines of North America and Europe and of South America and Africa almost match.

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Moving an electron within an electric field would change the ____ the electron.
a. mass ofb. amount of charge onc. potential energy of

Answers

Moving an electron within an electric field would change the potential energy of the electron. This is because the electric field exerts a force on the electron, causing it to move and gain potential energy. However, the mass of the electron remains constant regardless of its location within the electric field.
When an electron is moved within an electric field, its position changes relative to the source of the electric field. This change in position alters the electron's potential energy, while its mass and the amount of charge on it remain constant.

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if the delta h for the reaction 2mg 2cl2 -> 2mgcl2 is -1283.6kj,. what is the standard enthalpy of formation of magnesium chloride

Answers

The standard enthalpy of formation of magnesium chloride is -641.8 kJ/mol. The standard enthalpy of formation of magnesium chloride can be determined using the following equation:

ΔHf°(MgCl2) = 2ΔHf°(Mg) + 2ΔHf°(Cl2) - 2ΔHf°(MgCl2).

We know that the ΔH value for the reaction 2Mg + 2Cl2 -> 2MgCl2 is -1283.6 kJ. Using this value and the standard enthalpy of formation values for Mg and Cl2, we can substitute these values into the equation and solve for ΔHf°(MgCl2). After calculation, we get a standard enthalpy of formation of -641.8 kJ/mol for magnesium chloride. This value indicates the amount of energy released or absorbed when one mole of MgCl2 is formed from its constituent elements under standard conditions.

The standard enthalpy of formation of magnesium chloride can be calculated using the given reaction: 2Mg + 2Cl2 -> 2MgCl2, with a ΔH of -1283.6 kJ. Since the reaction involves the formation of 2 moles of MgCl2, we need to find the enthalpy for forming 1 mole of MgCl2. To do this, simply divide the given ΔH by 2:

Standard enthalpy of formation of MgCl2 = (-1283.6 kJ) / 2 = -641.8 kJ/mol.

Therefore, the standard enthalpy of formation of magnesium chloride is -641.8 kJ/mol.

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What is the advantage of slowly grown large crystals over quickly grown small crystals?

Answers

Slowly grown large crystals have several advantages over quickly grown small crystals. Firstly, large crystals are often more pure and uniform in structure, as they have had more time to grow and form.

This means they are less likely to have impurities or defects that can affect their properties and performance. Additionally, large crystals often have greater mechanical strength and durability than small crystals, making them more suitable for certain applications. Furthermore, large crystals can have unique optical, electronic, and magnetic properties that are not present in small crystals, making them potentially useful in a range of industries including electronics, optics, and pharmaceuticals. Overall, slowly grown large crystals offer a range of advantages over quickly grown small crystals, and are often preferred for certain applications where purity, uniformity, strength, or unique properties are important.
The advantage of slowly grown large crystals over quickly grown small crystals lies in their superior quality and structure. Large crystals formed through slow growth have fewer defects, improved purity, and greater mechanical strength. This results in enhanced performance in various applications, such as electronics, optics, and pharmaceuticals. Additionally, large crystals can provide more accurate and consistent results in scientific experiments, making them highly desirable in research and development settings.

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Given the equation representing a chemical reaction at equilibrium in a sealed, rigid container: H2(g) + I2(g) ←> energy + 2HI(g) When the concentration of H2(g) is increased by adding more hydrogen gas to the container at constant temperature, the equilibrium shifts ___

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The equilibrium shifts to the right, in the direction of the products (towards the formation of more HI gas).

How we proved?

According to Le Chatelier's principle, if a stress is applied to a system at equilibrium, the system will shift to relieve the stress and establish a new equilibrium.

In this case, increasing the concentration of H2(g) by adding more hydrogen gas to the container increases the concentration of reactants,.

Which means the equilibrium will shift towards the products (HI(g)) to relieve the stress and establish a new equilibrium.

This results in an increase in the concentration of products and a decrease in the concentration of reactants.

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What is the typical mp range of a pure compound?

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The typical melting point (mp) range of a pure compound is between 1-5 degrees Celsius. A pure compound has a characteristic melting point (mp) range, which is a measure of the temperature at which the compound transitions from a solid to a liquid state.

The mp range of a pure compound can vary depending on its chemical structure, purity level, and other factors. However, in general, a pure compound will have a narrow mp range, usually between 1-5 degrees Celsius. This means that the compound will melt within a small temperature range, indicating that it is homogeneous and not contaminated with impurities.

If the mp range is wider, it could indicate impurities or a mixture of compounds present. Measuring the melting point range of a compound is an important step in characterizing it and determining its purity level. It is a simple and reliable technique that can be used in various industries, including pharmaceuticals, chemicals, and materials science.

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how many milliliters of a 0.200 m potassium chloride solution should be added to 39.0 ml of a 0.250 m lead(ii) nitrate solution to precipitate all of the lead(ii) ion?

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23.4 mL of 0.200 M potassium chloride solution should be added.

To solve this problem, we need to determine the limiting reagent and the amount of product that can be formed. From the balanced chemical equation, we know that the reaction between potassium chloride and lead(II) nitrate forms lead(II) chloride and potassium nitrate:

Pb(NO₃)₂ + 2KCl → PbCl₂ + 2KNO₃

We want to find out how much potassium chloride is needed to react with all of the lead(II) nitrate, so we need to figure out how much lead(II) ion is present in the 39.0 mL of 0.250 M lead(II) nitrate solution.

moles of Pb(NO₃)₂ = M × V = 0.250 mol/L × 0.0390 L

moles of Pb(NO₃)₂ = 0.00975 mol

Since the reaction requires two moles of KCl for each mole of Pb(NO₃)₂, we need:

moles of KCl = 0.00975 mol Pb(NO₃)₂ × 2 mol KCl/mol Pb(NO₃)₂

moles of KCl = 0.0195 mol KCl

Now we can use the molarity of the potassium chloride solution to find the volume required:

V = moles / molarity

V = 0.0195 mol / 0.200 mol/L

V = 0.0975 L

V = 97.5 mL

However, we need to add only enough potassium chloride solution to react with all of the lead(II) nitrate. Therefore, we only need to add 23.4 mL of 0.200 M potassium chloride solution to react completely with the lead(II) nitrate.

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Benzoic acid is a frequent contaminant in the oxidation of benzoin to benzil. Its mp is significantly higher than that of desired product, at 122 degrees Celsius. How would its presence impact the mp of benzil?

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The presence of benzoic acid as a contaminant in the oxidation of benzoin to benzil would impact the melting point of benzil. This is because benzoic acid has a melting point that is significantly higher than that of benzil, at 122 degrees Celsius.

As a result, the presence of benzoic acid would increase the melting point of the mixture containing benzil, making it more difficult to accurately determine the melting point of the desired product. This could result in incorrect identification and characterization of the product, leading to potential problems in downstream processes. Therefore, it is important to carefully monitor and control the oxidation reaction to prevent the formation of unwanted contaminants such as benzoic acid.

The presence of benzoic acid, a frequent contaminant, can impact the melting point of benzil by lowering it. Since benzoic acid has a higher melting point (122°C) than benzil, the mixture of these two compounds will result in a broader melting point range and a decreased melting point for the mixture compared to the pure benzil. This is due to impurities disrupting the crystal lattice structure, making it easier for the mixture to melt at lower temperatures. Therefore, observing a lower melting point can indicate the presence of benzoic acid in the sample.

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