name two different objects you could use to light a room if you have a power cut. for each object describe the energy transfer and changes to energy stores that occur when it lights up the room

the angular speed of the bar just after the bug leaps is 0.044 ras/sec.

Given parameter:

Mass of the bug, m= 10.0g

Mass of the bar, M= 50.0 g.

Length of the bar, l = 90 cm.

Speed of the bug ,v = 20.0 cm/s.

Speed of the bar, V = ?

From conservation of momentum;

momentum of the bar = momentum of the bug

⇒ MV = mv

⇒ V = mv/M

= (10.0× 20.0)/50 cm/s.

= 4 cm/s.

Then, angular speed of the bar will be = V/l

= 4/90 rad/s.

= 0.044 rad/s.

Hence, the angular speed of the bar just after the frisky insect leaps is 0.044 rad/sec.

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The velocity of Car B after the collision is 4.856 m/s.

What is elastic collision?

A collision is considered elastic if it does not result in a net decrease in the system's kinetic energy. In an elastic collision, both momentum and kinetic energy are conserved.

In an elastic collision, the kinetic energy is essentially unchanged before and after the contact and is not changed into another type of energy.

Either one dimension or two dimensions are possible. Perfectly elastic collision is not feasible in reality since there will always be some energy exchange, no matter how tiny.

m1v1 + m2v2 = m1u1 + m2u2; where

m1= mass of object 1

m2= mass of object 2

v1= initial velocity object 1

v2= initial velocity object 2

u1= final velocity object 1

u2= final velocity object 2

m1v12/2 + m2v22/2 = m1u12/2 + m2u2/2

281·2.82 - 209·1.72 = 281u1 + 209u2;

281·2.822 + 209·(- 1.72)2 = 281u12 + 209u22;

281u1 + 209u2 = 432.94 and 281u12 + 209u22 = 2852.93

u1 = 1.05407 - 0.74377u2;

u1 = (10.15278 - 0.74377u2)1/2

u2 = 4.856 m/s

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a) angular frequency of the motion is ω = 3.5s⁻¹

b) total mechanical energy of the bob is T.M.E = 0.029J

c) bob's speed at the lowest point is V= 0.43m/s.

A mechanical device that oscillates or sways is known as a simple pendulum. The gravitational force is primarily responsible for this motion, which takes place in a vertical plane.

Given,

Length of a simple pendulum, L = 0.80m

Mass of the bob, m = 0.31 kg

h= L- LcosΘ = L (1 - cosΘ)

a) Angular frequency, ω = 2π / T

where, T = 2π √(L/g)

ω = 2π / 2π √(g/L)

ω =√(9.8 / 0.80) s⁻¹

ω = 3.5s⁻¹

b) Total mechanical energy, T.M.E = (K.E.)ₐ + (P.E.)ₐ

As (K.E.)ₐ = 0

(P.E.)ₐ =mgh

T.M.E = 0 + mgh, where h = L (1-cosΘ)

T.M.E = ngL (1-cosΘ)

= 0.31*9.8*0.80(1-0.988)

= 0.029J

Thus, T.M.E = 0.029J

c) bob's speed at the lowest position, V

TMEb = 0.029J

(KE)b + (PE)b = 0.029J

1/2mV² + 0 = 0.029J

V =√(2*0.029/m)

V = 0.43m/s

So, the speed at the lowest point is V= 0.43m/s.

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The  correct answer is net acceleration of the car at the top of the hill is 6.6 m/s²

distance traveled by the car, d = 50 m mass of the car, m = 1600 kg radius of the hill's curvature, r = 25 m beginning speed of the car, u = 25 m/s

The third kinematic equation is applied to get the car's tangential acceleration, as shown below;

v2 = u2 + 2as, where a represents the vehicle's acceleration and 2as = v2 - u2 equals a=5.25 m/s

A net equals a2 + aca net = (5.25) 2 + 42a net = 6.6 m/s. 2

Consequently, the vehicle's net acceleration at the summit of the hill is 6.6 m/s2.

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The value of constants A and θ will be  θ = 66.5° or 1.161 radians  and A = 3.1 cm  

Simple Harmonic Motion or SHM is defined as a motion in which the restoring force is directly proportional to the displacement of the body from its mean position. The direction of this restoring force is always towards the mean position.

x(t) = A sin (ωt + θ)

time = 0.00 seconds

2.83 = A sin ( 0 +  θ)

A sin θ = 2.83                        `equation 1

ν(t) = A ω cos (ωt+θ)

3.25 = A * 2.64 * cos (0 + θ )

3.25 = 2.64 A cos θ

A cos θ = 3.25 / 2.64 = 1.23              equation 2

dividing equation 1 and 2 , we get

tan θ = 2.30

θ = 66.5° or 1.161 radians

from equation 1

A sin θ = 2.83  

A sin ( 66.5 ) = 2.83

A = 3.1 cm  

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Answer:

the formula of acceleration

The position and the velocity of the sandbag at a time 0.245 s after its release is 44.7 m and 2.599 m/s.

The position and the velocity of the sandbag at a time 1.15 s after its release are 38.52 m and -6.25 m/s.

The equations of motion can describe the relationship between the velocity, time, acceleration, and displacement of a moving object.

The equations of motions can be represented as:

[tex]v = u + at\\S = ut +\frac{1}{2}at^2\\ v^2-u^2=2aS[/tex]

Given, the maximum height of the sandbag, h = 40 m

The velocity of the sandbag moving upward, v = 5 m/s

Calculate the time taken by the ballon:

v = u -gt

0 = 5 -9.8×t

t = 0.51 s

The position of the sandbag at 0.245 s after its release:

[tex]y = h +v_ot-\frac{1}{2}gt^2[/tex]

[tex]y = 40 +5 -0.5\times 9.8\times (0.245)^2[/tex]

y = 44.70 m

The velocity of the sandbag at a time 0.245 s after its release:

v = v₀ - gt

v = 5 - (9.8)(0.245)

v = 2.599 m/s

The position of the sandbag at a time 1.15 s after its release:

[tex]y = h +v_ot-\frac{1}{2}gt^2[/tex]

[tex]y = 40 +5 -0.5\times 9.8\times (1.15)^2[/tex]

y = 38.52 m

The velocity of the sandbag at a time 1.15 s after its release:

v = v₀ - gt

v = 5 - (9.8)(1.15)

v = -6.25 m/s

The velocity is negative so the sandbag is going down.

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Yes, the state of a sample of water depends on location and temperature.

Pure water has no flavour, no aroma, and no colour. There are three different states of water: solid (ice), liquid, and gas (vapour). Ice is frozen water or solid water. Because the molecules of water expand as it freezes, ice is less dense than water. As ice will weigh less than the same volume of water, it will float in the liquid. At 32° Fahrenheit, or 0° Celsius, water freezes. Water that is liquid is moist and fluid. This is the type of water that we are most accustomed to. We use liquid water in a variety of ways, such as drinking and washing.

The air all around us is constantly filled with the vapour of water. It is not visible. When water is boiled, it transforms from a liquid to a gas or water. At ambient temperature, water is a liquid; however, when cold, it solidifies to form ice. If heated, the same water transforms into a gas known as water vapour. Only when the substance reaches a specific temperature do the modifications take place. Ice formation occurs at 32°F (0°C). It requires more energy to raise and lower the temperature of water because a large body of water has a higher heat capacity than land. As a result, cities near water typically have a more limited range of temperatures throughout the year.

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10 kg sack of bread flour is given a horizontal force (2 N) and move about 35 cm distance.

Kinetic energy is formed and the speed is changed. The value of kinetic energy and the speed after pushed is calculated as follows :

Change the unit of distance (s = 35 cm = 0,35 m)

• Work = Δ EK

F × s = EK (after pushed) – EK (before pushed)

2 × 0,35 = EK (after pushed) – 0

0,7 Joule = EK (after pushed)

*EK before pushed is zero because the sack does not move*

• Speed after pushed

EK (After pushed) = ½ × m × v²

0,7 = ½ × 10 × v²

0,7 = 5 × v²

v² = 0,7/5 = 0,14

v (after pushed) = 0,37 m/s

So, kinetic energy after pushed is 0,7 joule and the speed is changed to 0,37 m/s.

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As the temperature across the lamp increases, the

resistance of the lamp increases.

This is because the temperature is proportional to resistance.

The current through a diode flows in one direction only.

The resistance is flowing in the reverse direction.

Resistance is described as a measure of the opposition to current flow in an electrical circuit. Resistance is known to be measured in ohms, symbolized by the Greek letter omega (Ω) which is named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.

The relationship between temperature and resistance is that the resistance increases as the temperature increases in conductors and decreases with the increasing temperature in insulators.

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Difference in Gravity of 7%

The near side of the Earth is 12740 km closer to the Moon than the far side. As a result, the near side experiences a gravitational force that is 7% stronger than the far side.The force that pulls items toward the centre of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity.Differential gravitational forces, or gravitational forces that are not equal across a body's finite size, are the fundamental mechanism.

Radius of the earth, r = 6.37*10^6

by solving ((Fn-Ff)/Fn)*100 answer will be of 7%

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Answer:

30J

Explanation:

Δq = Δu + Δw

⇒Δu = Δq - Δw

here, Δq = 60J & Δw = 30J

∴ Δu = 60 - 30 = 30 J

The mass of the block on the table is 2.33 kg.

The Tension in the rope is 4.9 N.

The mass of the block on the table is calculated by applying Newton's second law of motion.

Newton's second law of motion states that the force applied on an object is directly proportional to the product of mass and acceleration of the object.

F = ma

where;

F(net) = ma

m₂g - m₁g = a(m₁ + m₂)

where;

m₂g - m₁g = m₁a + m₂a

m₂g  - m₂a = m₁a  + m₁g

m₂g  - m₂a = m₁(a + g)

3.6(9.8) - 3.6(2.1) = m₁(2.1 + 9.8)

27.72 = 11.9m₁

m₁ = 27.72 / 11.9

m₁ = 2.33 kg

The tension in the rope is calculated as follows;

T = m₁a

T = 2.33 kg x 2.1 m/s²

T = 4.9 N

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The time taken for the bicycle to come to a complete stop with an initial velocity of 13.5 m/s is 27 seconds.

Time can be defined as the calculable measure of motion with respect to before and afterness.

To calculate the time it takes the cyclist to bring the bicycle to complete stop, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the time taken for the bicycle to stop completely is 27 seconds.

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Answer:

highest point

Explanation:

at highest point , ball stops moving, velocity = 0

KE = 1/2 m v^2

     = 1/2 m ( 0)^2 = 0    at highest point

The mass of the other object is 18.11 kg and their acceleration  will be respectively 5.8 × 10⁻⁸ m/s² and 17.66× 10⁻⁸ m/s².

Given parameter:

The gravitational force between two objects : F = 3.2×10⁻⁶ N.

Distance between two objects : r =  2.1x10⁻¹ m.

The mass of one object m₁ = 55 kg.

The mass of other object m₂ =?

From universal gravitational law, we know that, force acting between two objects of mass m₁ and m₂ separated by a distance r is:

F = G m₁ m₂ / r²

Where, G = universal gravitational constant = 6.67 × 10⁻¹¹ N m⁻² kg⁻².

So, we can write,

 3.2×10⁻⁶ N = (6.67 × 10⁻¹¹ N m⁻² kg⁻²) (55 kg) m₂/( 2.1x10⁻¹ m)

⇒ m₂ = (3.2×10⁻⁶ N ×  2.1x10⁻¹ m )/ { (6.67 × 10⁻¹¹ N m⁻² kg⁻²) (55 kg)}

= 18.11 kg.

Hence, the mass of the other object is 18.11 kg.

So, acceleration of the object of mass 55 kg is:

a₁ = F/m₁ = 3.2×10⁻⁶/55  m/s² = 5.8 × 10⁻⁸ m/s².

The acceleration of the object of mass 18.11 kg is:

a₂ = F/m₂ = 3.2×10⁻⁶/18.11 m/s² =  17.66× 10⁻⁸ m/s².

Hence, their acceleration if they are released from their position will be respectively 5.8 × 10⁻⁸ m/s² and 17.66× 10⁻⁸ m/s².

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The time at which the rotational acceleration is maximum is 0.26i s or 2.2i s.

The maximum tangential acceleration of the wheel is 4.1 m/s².

The rotational acceleration of the wheel is the change in the angular velocity of the wheel with time.

α = dω/dt

where;

ω = tan⁻¹(c + bt²)

α = dω/dt

α = (2bt)/[(c + bt²)² + 1]

the maximum angular acceleration =ω/t =  1.81/t

1.81/t = (2bt) / [c² + 2cbt² + b²t⁴ + 1]

1.81(c² + 2cbt² + b²t⁴ + 1) = 2bt(t)

1.81c² + 3.62cbt²  + 1.81b²t⁴  + 1.81 = 2bt²

1.81(1.5574)²  +  3.62(1.5574 x 6.53)t²   +  1.81(6.53²)t⁴ + 1.81 = 2(6.53)t²

4.39 + 36.81t²  + 77.18t⁴ + 1.81 = 13.06t²

77.18t⁴ +  23.75t²  +   6.2 = 0

23.75t²(3.25t² + 1) = -6.2

23.75t² = -6.2  or  3.25t² + 1 = -6.2

t² = -6.2/23.75

t² = -0.26

t = 0.26i  s

or

3.25t² + 1 = -6.2

3.25t² = -7.2

t² = -2.2

t = 2.2i s

The maximum tangential acceleration of the wheel at the given point is calculated as follows;

a = v²/r

a = ω²r

a = (1.81 rad/s)²(1.25 m)

a = 4.1 m/s²

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The period of Jupiter is known to be 11.9 years then the average distance of Jupiter to the Sun is given to be  5.21 AU.

Kepler's laws of planetary motion :

According to this law, the semi-major axes of the planets' orbits are directly proportional to the squares of the planets' orbital periods.

period of the Jupiter = 11.9 years

radius of the earth = 1 AU

orbital period of the earth = 1 year

According to the Kepler's 3rd law of planetary motion :

T² ∝ R³

T² = k R³

k = T²/ R³

[tex]k = \frac{T^2_j}{R^3_j} = \frac{T^2_e}{R^3_e}[/tex]

T² /(R)³ = (1)² /(1)³

Rj  =  [tex]T^{\frac{2}{3}}[/tex]

T = 5.21 AU

The period of Jupiter is known to be 11.9 years then the average distance of Jupiter to the Sun is given to be  5.21 AU.

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After completing a workout/activity, it is best to use Static stretching.

Static stretching is most effective at the quit of your workout. It includes stretches that might be held for a period of time to help extend and unfasten your muscle mass and connective tissue. that is special from a dynamic warmup due to the fact you hold your body nonetheless.

It is a good concept to do dynamic stretching before a workout, and static stretching after a workout, irrespective of what type of exercise you're doing. What you need to differ based on your workout is which muscle groups you are running, on account that it's crucial to warm up the muscle mass you are certainly going to be using.

A dynamic stretching heat-up gets you prepared for something exercising you're approximate to accomplish this is the first-rate form of stretch before an exercising while static stretching is quality for the stop of your workout.

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3) unit of the following are :

a) force = Newton

b) distance = meter

c) work = Joule

4) 90 J work has been done by her

5) 51 J work was done

6) He have done  [tex]10^{4}[/tex] J  of work

7) no work is done

8) no work is done

9) 700 J is the work done on the car

10) 10.68 N  force is applied

3 ) unit of the following are :

a) force = Newton

b) distance = meter

c) work = Joule

4 ) work done = force * displacement

                       = 75 * 1.2 = 90 J

5 )  work done = force * displacement  

                        = 15 * 3.4 = 51 J

6 ) work done = force * displacement  

                        = 100 * 100 = [tex]10^{4}[/tex] J

7) no work is done because no displacement occurred

8)  no work is done because no displacement took place

9) work done = force * displacement

                        = 12.5 * 56 = 700 J

10)  force = work done / displacement

                = 142 / 13.3 = 10.68 N

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Fluid friction is an opposition to the ease movement of fluids known as viscosity.

Fluid friction describes the friction between layers of a viscous fluid that are moving relative to each other.

Typically, fluid friction is a type of friction that exist in fluids and it is known as viscosity.

Fluid viscosity can be defined as the type of friction that act on fluid. It can also be defined as the measure of the resistance of a fluid to gradual deformation by shear or tensile stress.

Thus, the fluid friction is equal to fluid viscosity and it is the type of friction that exists only in fluids.

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If a body has the three forces acting upon it and is in equilibrium then the vector sum of the three forces is zero. Thus, (A) I only is the correct answer.

I. The vector sum of three forces is zero means that the vector sum of all the three forces is equal to resultant zero vector.

II. If two forces act in the same direction then the body experiences more force on that side and hence is not in equilibrium. For the body to be in equilibrium, then the resultant of any two forces should be opposite, equal and collinear with the third force.

III. For the body to be in equilibrium, magnitude along with direction should be mentioned. If the three forces are in the same plane, convergent (cross the same point) and non-parallel.

Hence, the body on which three forces is acting will be in equilibrium when the vector sum of three forces is zero.

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The force acting on a body in space is zero, hence the acceleration of the friends in space will be;

The acceleration of a body is the rate of change of the velocity of the body.

The acceleration of a body, the mass of the body, and the force acting on the body are related by the formula below:

Mathematically:

Hence,

The force acting on a body in space = 0 N

For a person having a mass of 110 kg;

acceleration = 0 / 110

Acceleration = 0

For a person having a mass of 110 kg;

acceleration = 0 / 80

Acceleration = 0

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The slope intercept form of given line is y = 1x+-1.

Solution:

y = mx+b

m = slope which is 1/1 because it is rise over run (rising 1, running 1)

b = y-intercept form which is -1 because that is where the line meets the y-axis.

The slope is the first number appearing in the equation. The slope is the coefficient of x, regardless of order. The intersection point is the point on the y-axis through which the slope of the line passes. The y-coordinate of the point where the line or curve intersects the y-axis. This is shown by writing the equation for the straight line y = mx+c. where m is the slope and c is the y-intercept.

The slope indicates how much the vertical changes for a given horizontal change. The shape of the slope intercept is actually equal to y plus MX plus b. It's called a slope-intercept shape because it has a slope and an intercept. The slope is defined as the ratio of the vertical change between two points to the horizontal change between the same two points.

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Disclaimer:- Your question is incomplete,please see below for the complete question.

Write the slope-intercept form of the given line. Include your work in your final answer.

Line is Y = mx +c

where m=1

c = -1

The answer is 5.6 ohms.

The electrical resistance of a circuit component or device is defined as the ratio of the applied voltage to the current through it. If the resistance is constant over a considerable voltage range. This is shown below. To calculate the total resistance of multiple resistors connected in this way, add the individual resistances.

calculation:-

V = iR

R = V/I

= 33.10/6

5.6.

Wire resistance is proportional to resistance and length and inversely proportional to wire cross-sectional area. To determine the condition of a circuit or component. The higher the resistance, the lower the current flow, and vice versa. Resistance is a measure of resistance to the flow of current in an electrical circuit. Resistance is measured in ohms and represented by the Greek letter omega.

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The type of nuclear radiation that the Americium-241 source is producing is

an alpha emitter, but also emits some gamma rays.

Nuclear radiation (also known as ionising radiation) is energy that is released in the form of high-speed charged particles or electromagnetic waves. Radiation can come from a variety of sources, both natural and man-made. Every living thing is constantly bombarded with low-level radiation from rocks, sunlight, and cosmic rays.

Am-241 emits mostly alpha rays but also some gamma rays. If ingested (swallowed) or inhaled, it poses a greater risk. Americium-241 is created in nuclear power plants by neutron activation of 239Pu and 240Pu, followed by beta decay of 241Pu (T1/2 = 14.35 years). This means that 241Am is produced in burned-up fuel by the decay of 241Pu a long time after the fuel is removed from a nuclear reactor.

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The energy needed to heat the copper from 25 °C  to 45 °C if the specific heat capacity of copper is 380 J/kg °C is 9880 J

ΔT = T - To

ΔT = Change in temperature

T = Final temperature

To = Initial temperature

T = 45 °C

To = 25 °C

ΔT = 45 - 25

ΔT = 20 °C

q = m C ΔT

q = Heat Energy

m = Mass

C = Specific heat capacity

m = 1.3 kg

C = 380 J / kg °C

q = 1.3 - 380 * 20

q = 9880 J

Therefore, the energy needed to heat the copper to 45 °C is 9880 J

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The displacement covered will be 9.85 km

The distance covered will be = 10 + 4 + 1 = 15 km

using Pythagoras theorem

[tex]H^{2} = P^{2} + B^{2}[/tex]

H  = [tex]\sqrt{4^{2} + 9^{2} }[/tex]

H  = [tex]\sqrt{97}[/tex]

H   = 9.85 km

The displacement covered will be 9.85 km

The distance covered will be = 10 + 4 + 1 = 15 km

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With the use of a magnetometer, the magnetism or magnetic field of the human body can be measured or demonstrated.

A magnetometer is a device used to measure the magnetic field or the magnetic dipole moment. Magnetometers of various sorts measure the direction, intensity, or relative change of a magnetic field at a specific area.

A magnetometer is a scientific tool that measures the intensity of magnetic fields. Magnetometers may be used on land to locate iron ore reserves for mining.

Magnetometers are instruments that can detect the amount or direction of a magnetic field. They may be found practically anywhere in electronics. They might be as basic as the one used by your smartphone to identify whether it is upright or as complicated as the one used by NASA to assess Mars' magnetic field.

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a) The magnitude of force  exerted by cord A on block 1 is equal to magnitude of the force exerted by cord B on block 2

b) The acceleration of block 1 is equal to that if block 2

c)The force is forward and equal to the force of cord B on block 2.

We know that the force that acts along a cord can be regarded as the tension force. The magnitude of the tension force is equal to the force that is applied on the cord. If an object is hanged on the cord then the tension force would equal the weight of the object.

a) We can see that block 1 is connected to block 2 by the use of cord B and the force on cord B  must necessarily be the force on cord A  since the weight of the blocks are equal.

b) Since the force on cord A is equal to the force on cord B, the acceleration of block 1 must be equal to the acceleration of block 2.

c) Cord B exerts a force on block 1 in the forward direction and this force is equal to the force that is exerted on block 2.

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