Answer:
A, 1.25m/s^2
Explanation:
use formula v=v0+at to solve for a
a= v-v0/t
Plug in givens
30-15/12 to get 15/12 = 1.25m/s^2
A 800kg car produces a motive force of 10,000N.
As it accelerates from rest it experiences a frictional resistance of 2,000N.
What is the net force acting on the car?
Answer:
the net force on the car is 8,000 N.
Explanation:
Given;
mass of the car, m = 800 kg
motive force of the car, F = 10,000 N
frictional force experienced by the car, Fk = 2,000 N
The net force on the car is calculated as;
∑F = F - Fk
∑F = 10,000 - 2,000
∑F = 8,000 N
Therefore, the net force on the car is 8,000 N.
A bus has a speed of 1.3 m/s and a mass of 12,000 kg. A baseball has a
speed of 44.7 m/s and a mass of 0.145 kg. What is the kinetic energy of the
bus?
Answer:
find it yourself too lazy for math but here's the step
Explanation:
it's the object mass multiplied by the velocity.
A tourist drops (from rest) a ping pong ball from the top of the tower, which has a height of 174 meters. Assuming no air resistance, how long does it take for the ping pong ball to hit the ground
Given :
A tourist drops (from rest) a ping pong ball from the top of the tower, which has a height of 174 meters.
To Find :
How long does it take for the ping pong ball to hit the ground ?
Solution :
We know, equation of motion of object doing free fall is :
[tex]s = ut + \dfrac{gt^2}{2}[/tex] ....1)
Here, g = 9.8 m/s² ( acceleration due to gravity )
Also, u = 0 m/s ( its free fall )
Putting these values in equation 1), we get :
[tex]174 = 0 + \dfrac{9.8\times t^2}{2}\\\\t = \sqrt{\dfrac{174\times 2}{9.8} }\ s\\\\t = 5.96 \ s[/tex]
Therefore, ball will take 5.96 s to hit the ground.
A
copper wire of radius 2.4mm is fixed to a ceiling. When a load of 100 kg
is suspended at its lower end, it is extended by 1.5 mm. If the Young's
modulus of copper is 1.2 x 1011Nm?, calculate the length of the wire.
A man runs 300 m West in 60 seconds. He then runs 100 m
North-west in 20 seconds.
What is his average velocity in metres per second?
Answer:
5 m/s
Explanation:
Total distance = 300 + 100 = 400m
Total time = 60 + 20 = 80s
Velocity = 400/80 = 5m/s
Average velocity of man is 5 meter per second.
To find the average speed of an object we divide the total distance travelled by the total time time taken by object.
Total distance travelled by man = 300 + 100 = 400 m
Total time taken by man = 60 + 20 = 80 seconds
Average velocity,[tex]=\frac{400}{80} =5m/s[/tex]
Thus, Average velocity of man is 5 meter per second.
Learn more:
https://brainly.com/question/23856383
Suppose one cylinder is bolted to a sturdy ceiling. How many 81 kg football players would need to hang from the lower cylinder to pull the two cylinders apart
This question is incomplete, the complete question is;
The two 60 cm in diameter cylinders in Figure 13.15, closed at one end, open at the other, are joined to form a single cylinder, then the air inside is removed.
a) How much force does the atmosphere exert on the flat end of each cylinder?
b) Suppose one cylinder is bolted to a sturdy ceiling. How many 81 kg football players would need to hang from the lower cylinder to pull the two cylinders apart ?
Answer:
a) the atmosphere exert a force of 2.9 × 10⁴ N on the flat end of each cylinder
b) 36 football players each of 81 kg are needed to pull the two cylinders apart.
Explanation:
Given that;
diameter of cylinder is 60 cm = 0.6 m
then radius r will be 0.6/2 = 0.3 m
a)
How much force does the atmosphere exert on the flat end of each cylinder;
we know that; F = PA
inside its the flats end that its in question; Area A = πr².
We Know that, Pressure P due to atmosphere is 1.013 × 10⁵ Pa
so, F = 1.013 × 10⁵ Pa × π( 0.3 )²
F = 1.013 × 10⁵ Pa × 0.09π
F = 28641.9 N ≈ 2.9 × 10⁴ N
Therefore, the atmosphere exert a force of 2.9 × 10⁴ N on the flat end of each cylinder.
b) number of players needed to pull the two cylinders apart.
given that; m = 81 kg and g is 9.8 m/s²
n = F / mg
we substitute
n = 28641.9 / (81 × 9.8)
n = 28641.9 / 793.8
n = 36.08 ≈ 36
Therefore, 36 football players each of 81 kg are needed to pull the two cylinders apart.
In a fusion reactor, the high temperature of the order of 10 8 K is required in order that what condition is met
Answer:
High temperature of 108 million K
Explanation:
For the fusion reactor to be able to work optimally, then one of the most important conditions is the necessity of a very high temperature of about 108 million Kelvin. This is quite large, and is about six times hotter than the temperature existing at the core of the sun. At this temperature, the hydrogen state of the element is not a gas, but rather it is a plasma. Here, the atoms will be stripped of their electrons and are allowed to move freely. This condition is akin to the perfect condition for the reactor to function. It makes the hydrogen atoms gather enough energy for the reaction that takes place in the subsequent phases of this process.
a high ____will have a short wavelength.
Question:
A high ____will have a short wavelength
Answer:
That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength. Light waves have very, very short wavelengths
Explanation:
Hope it help
Explanation:
Wave Is The Answer
HighWave
A 2.5x10-3 kg paint chip comes off a satellite orbiting Earth. The velocity of the paint chip is
7000 m/s. Which is the kinetic energy of the paint chip?
F 1750)
G 6125 )
H 12.250
24,500
(7 Points)
Answer:
G. 6125
Explanation:
Step one:
given data
mass m= 2.5x10-3 kg
velocity v= 7000 m/s
Required
The kinetic energy
Step two:
The expression for the kinetic energy is
KE= 1/2m v^2
KE= 1/2*2.5x10^-3*7000^2
KE= 0.5*2.5x10^-3*7000^2
KE= 0.5*2.5x10^-3*49000000
KE= 0.5*122500
KE=6125J
What is the mass of a baseball thrown at 25 m/s resulting in a momentum
of 10 kg*m/s?
0.4 kg
2.5 kg
10 kg
250 kg
250kg
would have momentum that is being caried by the impact of the trow
The graph below shows the composition of the air we breathe. Which of the following statements correctly classified the air we breathe?
A. The air we breathe is an element because it is made of pure substances
B. The air we breathe is a compound because it is made of different pure substances.
C. The air we breathe is a heterogeneous mixture because it had visibly different substances and phases.
D. The air we breathe is a homogeneous mixture because it has substances but the same appearance throughout.
Answer:
D. The air we breathe is a homogeneous mixture because it has substances but the same appearance throughout.
Explanation:
The air we breathe is a homogeneous mixture.
Air is a mixture of many gases. A homogeneous mixture is one whose constituents exists in one phase.
Air is a gas - gas mixtures.
A mixture has indefinite composition. They consist of two or more elements and or compounds in any proportion by mass.
Constituents retain their identities i.e. physical properties are retained.
• 0.4kg
• 2.5kg
•10kg
•250kg
Please help
A father fashions a swing for his children out of a long rope that he fastens to the limb of a tall tree. As one of the children swings from this rope that is 6.00 m long, his tangential speed at the bottom of the swing is 9.50 m/s. What is the centripetal acceleration, in m/s2, of the child at the bottom of the swing
Answer:
The centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².
Explanation:
The centripetal acceleration is given by:
[tex] a_{c} = \frac{v^{2}}{r} [/tex]
Where:
[tex] v^{2}[/tex]: is the tangential speed = 9.50 m/s
r: is the distance = 6.00 m
Hence, the centripetal acceleration is:
[tex] a_{c} = \frac{v^{2}}{r} = \frac{(9.50 m/s)^{2}}{6.00 m} = 15.04 m/s^{2} [/tex]
Therefore, the centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².
I hope it helps you!
Answer:
10.8n
Explanation:
For this case the centripetal force is given by:
Where,
m: mass of the object
v: tangential speed
r: rope radius
Substituting values in the equation we have:
Then, doing the corresponding calculations:
Answer:
The centripetal force exerted on the rope is:
Consider an open pipe of length L. What are the wavelengths of the three lowest tones produced by this pipe? Consider an open pipe of length L. What are the wavelengths of the three lowest tones produced by this pipe?
A. 3L, L, L/3
B. 2L, L, L/2
C. 2L, L, L/2
D. 4L, 2L, L 2L, L, 2L/3
Answer:
Explanation:
open pipe :
In open pipe , wavelength of tone produced = 2L / n where n is integer .
3 lowest tone or highest wavelength = 2L / 1 , 2L / 2 , 2L / 3
= 2L , L , 2L/3
Closed pipe :
In closed pipe , wavelength of tone produced = 4L / n where n is odd integer
3 lowest tone or highest wavelength = 4L / 1 , 4L / 3 , 4L / 5
= 4L , 4L / 3 , 4L / 5
Solve the problems. Show all work, be SI units for force for weight) .
1. Find the weight of a 2.5 kg bowling ball.
Answer:
1. 75 N
2. 6.8351 N
3. 700 N
Explanation:
1. Determination of the weight of the bowling ball:
Mass (m) = 7.5 kg
Acceleration due to gravity (g) = 10 m/s²
Weight (W) =?
Weight = mass × acceleration due to gravity
W = m × g
W = 7.5 × 10
W = 75 N
2. Determination of the weight of the object.
Mass (m) = 683.51 g
Weight (W) =?
We'll begin by converting 683.51 g to kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
683.51 g = 683.51 g × 1 Kg / 1000 g
683.51 g = 0.68351 Kg
Thus, 683.51 g is equivalent to 0.68351 Kg.
Finally, we shall determine the weight of the object as follow:
Mass (m) = 0.68351 Kg
Acceleration due to gravity (g) = 10 m/s²
Weight (W) =?
Weight = mass × acceleration due to gravity
W = m × g
W = 0.68351 × 10
W = 6.8351 N
3. Determination of the weight of the KHS student.
Mass (m) = 154 lb
Weight (W) =?
We'll begin by converting 154 lb to Kg. This can be obtained as follow:
2.2 lb = 1 Kg
Therefore,
154 lb = 154 lb × 1 Kg / 2.2 lb
154 lb = 70 kg
Thus, 154 lb is equivalent to 70 kg.
Finally, we shall determine the weight of the KHS student as follow:
Mass (m) = 70 Kg
Acceleration due to gravity (g) = 10 m/s²
Weight (W) =?
Weight = mass × acceleration due to gravity
W = m × g
W = 70 × 10
W = 700 N
