Answer:
crystalline and amorphous.
Explanation:
Crystalline solids are the most common type of solid, they are characterized by a regular crystalline organization of atoms that confer a long-range order, Amorphous, or non-crystalline, solids lack the long-range order
Which object shares similar physical properties with a bar of soap
Answer:
objects with little friction, and little density
Explanation:
substances such as, jelly share similar physical properties
Which term represents an intermolecular force in a sample of water?
1. hydrogen bonding
2. covalent bonding
3. metallic bonding
4. ionic bonding
Answer:
hydrogen bonding
Explanation:
.
Animals that rely on plants to transform chemical energy into carbohydrates and sugars are
A. primary producers.
B. first level consumers.
C. second level consumers.
D. detritivores,
Answer:
B. first level consumers.
Explanation:
The first level consumers are also the primary consumers. They are the animals that depends or rely on plants to transform chemical energy into carbohydrates and sugar.
Primary consumers are mostly herbivores. They feed on plant matter by which they derive their nutrition. They have special enzymes that helps to convert plant materials into substances needed for their body.
So, the first level consumer takes plant matter and convert them into useful food materials for their own nutrition.
The second level consumers depend on the first level consumers for nutrition.
What is the name of the element
hydrogen
helium
lithium
beryllium
boron
carbon
nitrogen
oxygen
fluorine
neon
1. A 40,000 kg plane is accelerating at a rate of 4m/s2. How much force does the engine put forth?
Answer:
160000
Explanation:
F=ma
m=40000
a=4
if a 40,000 kilogram plane is accelerating at a rate of 4 meters/second², then the force generated by the engine would be 160000 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem we have to find out the force generated by the engine of the plane if a 40,000-kilogram plane is accelerating at a rate of 4 meters/second²,
The mass of the plane = 40000 kilograms
The acceleration of the plane = 4 meters/second²
The force generated by the engine of the plane = 40000×4
= 160000 Newtons
Thus, the engine would generate a force of 160000 Newtons.
To learn more about Newton's second law here, refer to the link;
brainly.com/question/13447525
#SPJ2
"drivers license"
I got my driver's license last week
Just like we always talked about
'Cause you were so excited for me
To finally drive up to your house
But today I drove through the suburbs
Crying 'cause you weren't around
And you're probably with that blonde girl
Who always made me doubt
She's so much older than me
She's everything I'm insecure about
Yeah, today I drove through the suburbs
'Cause how could I ever love someone else?
And I know we weren't perfect but I've never felt this way for no one
And I just can't imagine how you could be so okay now that I'm gone
Guess you didn't mean what you wrote in that song about me
'Cause you said forever now I drive alone past your street
And all my friends are tired
Of hearing how much I miss you but
I kinda feel sorry for them
'Cause they'll never know you the way that I do
Yeah, today I drove through the suburbs
And pictured I was driving home to you
And I know we weren't perfect but I've never felt this way for no one
Oh, and I just can't imagine how you could be so okay now that I'm gone
I guess you didn't mean what you wrote in that song about me
'Cause you said forever now I drive alone past your street
Red lights
Stop signs
I still see your face
In the white cars
Front yards
Can't drive past the places
We used to
Go to
'Cause you know I still love you, babe
Sidewalks
We crossed
I still hear your voice
In the traffic
We're laughing
Over all the noise
God, I'm so blue
Know we're through
But you know I still love you, babe
I know we weren't perfect but I've never felt this way for no one
And I just can't imagine how you could be so okay now that I'm gone
Guess you didn't mean what you wrote in that song about me
'Cause you said forever now I drive alone past your street
Yeah, you said forever now I drive alone past your street
Answer:
omg that song l0wkey but high.key slaps
can you not please? this is an education website
if a -2 ion has 34 protons, what element is it?
ANSWER
Selenium has 34 protons
How many moles are present in 2.45 x 1023 molecules of CH ?
Answer:
the aware is 6182
Explanation:
jejejieieiejeie
9. Which type of reaction is shown by the equation below?
PAO10(s) + 6 H20 (1) ► 4 H3PO4(ay)
Synthesis
Combustion
оооо
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Double replacement
Decomposition
For every pound a company spends on advertising, it spends £0,75 on its website. Express the
amount spent on advertising to the amount spent on its website as a ratio in its simplest form.
Bone Injuries
Practices/Activities on How To
Avoid the Injuries
Fracture
Dislocation
Sprain
Answer:
1.=fracture.... Balance: Consider balance training and physical therapy if your body feels off. Use a cane or walker if you need to.
2.=dislocation.... Wearing protective gear during contact sports.
3.=sprain...Take precautions to prevent falls, such as holding handrails on stairways, avoiding slippery surfaces, and keeping your floors uncluttered.
The practices/activities which should be done to avoid the following injuries
include
Fracture- Balance training should be done by individuals as it helps to strengthen the muscles and relieve some of the load the bones are being subjected to in ensuring proper support for the body.Dislocation- Precautions such as wearing of protective gears and proper lightning should be done to prevent individuals from falling and getting bones dislocated. The protective equipment also help to reduce the effect of force on joints which may cause dislocation.Sprain- Activities which involve stretching the muscles of the body should be frequently done to prevent such type of injuries.Read more on https://brainly.com/question/20885020
0.38 L of HNO3 is titrated to equivalence using 0.14 L of 0.2 MNaOH. What is the concentration of the HNO3HNO3
Answer:
0.074M is concentration of the HNO₃ solution
Explanation:
The reaction of neutralization of nitric acid, HNO₃ with NaOH is:
HNO₃ + NaOH → H₂O + NaNO₃
Where 1 mole of nitric acid reacts per mole of NaOH
Based on the chemical reaction, the moles of NaOH at equivalence point are equal to moles of HNO₃ presents in the solution. With the moles and the volume we can find molarity as follows:
Moles NaOH = Moles HNO₃:
0.14L * (0.2mol NaOH / L) = 0.028mol NaOH = 0.028mol HNO₃
Molarity:
0.028mol HNO₃ / 0.38L =
0.074M is concentration of the HNO₃ solutionRank the nonmetals in each set from most reactive (1) to least reactive (3).
Bromine: ?
Chlorine: ?
Iodine: ?
Answer:
Chlorine Bromine IodineExplanation:
All three of these elements fall in group 7 of the periodic table and are called Halogens. Chlorine is the most reactive of these elements because it comes before the other two in the table then followed by Bromine and then Iodine.
Reactivity decreases in the group 7 elements as one moves to the latter elements due to the increase in shells surrounding the nucleus.
This is because reactivity happens as the protons in the nucleus attract electrons but when more shells are piled on, the strength of this attraction decreases as the distance increases such that they will not be as reactive anymore.
5. A car has a gasoline tank with a capacity of 18.0 gallons. How many liters is this equal to? (- 2.1134 pints, gallon = 4 quarts , 1 quart = 2 pints)
Answer:
16.14 liter
Explanation:
The tank capacity of a car is a measure of the amount of gallons or liters of liquid a tank (of any shape e.g. rectangular, cylindrical) can hold at maximum due to its volume. The S.I unit of the tank capacity is the m³, but it can be measured in liters, gallons and any other unit of volume.
We need to convert the volume from gallons to liters
1 gallon = 3.78541 liters
18 gallon = [tex]18\ gallon*\frac{3.78541\ liter}{1\ gallon} =16.14\ liter[/tex]
what is the boiling point of water at the top of mount everest where the atmospheric pressure is only 34% as strong
This question is incomplete, the complete is;
Water has a heat of vaporization (ΔHvap) of 44.01 kJ mol-1 and boils at 100 degrees C at sea level.
What is the boiling point of water at the top of Mount Everest where the atmospheric pressure is only 34% as strong as the pressure at sea level?
Answer: the boiling point of water at the top of mount Everest where the atmospheric pressure is only 34% as strong is 74 °C
Explanation:
Given that;
P1 = 1 atm,
T1 = 100°C = 373 K
P2 = P1 × 34% = 1×0.34 = 0.34 atm
T1 = ?
ΔH = 44.01 kJ mol⁻¹ = 44.01×10³ J/mol
R = 8.314 J/k.mol
now using the Clausius - Clapeyron equation;
p1_∫^p2 d.InP = ΔHvap/R T1_∫^T2. 1/T².dT
⇒ In(P2/P1) = ΔHvap/R (1/T1 - 1/T2)
so we substitute;
ln( 0.34/1 ) = ( 44.01×10³ / 8.314) × ( 1/373 - 1/T2)
-1.0788 = 5293.4808 × ( 0.00268 - 1/T2)
-1.0788 = 14.1865 - 5293.4808(1/T2)
5293.4808(1/T2) = 14.1865 + 1.0788
5293.4808(1/T2) = 15.2653
(1/T2) = 15.2653 / 5293.4808
(1/T2) = 0.0028837
T2 = 1 / 0.0028837
T2 = 346.8 K
WE convert to Celsius
t2 =346.8 K − 273.15 = 73.65 °C ≈ 74 °C
Therefore, the boiling point of water at the top of mount Everest where the atmospheric pressure is only 34% as strong is 74 °C
Consider the chemical reaction
aC2H6 + bCO2 + cH2O → dC2H5OH,
where a, b, c, and d are unknown positive integers. The reaction mush be balanced; that is, the number of atoms of each element must be the same before and after the reaction. For example, because the number of oxygen atoms must remain the same,
2b+c=d.
While there are many possible choices for a, b, c, and d that balance the reaction, it is customary to use the smallest possible integers. Balance this reaction.
a=
b=
c=
d=
Explanation:
aC2H6 + bCO2 + cH2O → dC2H5OH
The balanced equation for the reaction is given as;
6C2H6 + 2CO2 + 3H2O → 7C2H5OH
Check!
Oxygen
Reactant = 2 * 2 + 3 = 7
Product = 7
Carbon
Reactant = 6 * 2 + 2 = 14
Product = 7 * 2 =14
Hydrogen
Reactant = 6 * 6 + 3 * 2 = 42
Product = 7 * 5 + 7 * 1 = 42
a = 6
b = 2
c = 3
d = 7
If the pressure in a gas container that is connected to an open-end U-tube manometer is 116 kPa and the pressure of the atmosphere at the open end of the tube is 752 mm Hg, the level of mercury in the tube will
Answer:
The level of mercury in the tube will be 118 mmHg
Explanation:
As per the given data
Pressure of container = P1 = 116 kPa
Pressure of atmosphere = P2 = 752 mmHg
First, we need to convert the pressure of the container in mmHg as follow
P1 = 116 kPa x [tex]\frac{1 atm}{101.325 kPa}[/tex] x [tex]\frac{760 mmHg}{1 atm}[/tex] = 870 mmHg
Hence the pressure in the container is higher than the pressure of the atmosphere and the mercury level will increase.
Now calculate the level of mercury in the tube as follow
Level of Mercury = Pressure of container - Pressure of atmosphere
P = P1 - P2
P = 870 mmHg - 752 mmHg
P = 118 mmHg
i need help ASAP why does detergent turn white in the water when it’s mixed with water
Answer:
because the soap and the water mix and make bubblesl
Explanation:
If you were an element, what element are you and in what another element would you like to bind with and why?
Answer:
If I were an element, I would want to be Carbon. I would want to combine with oxygen. It would create carbon dioxide. It has daily life uses. For heat, and for refridgment and more.
Explanation:
a solution of calcium chloride contains 35.0 g calcium chloride 425.0 g water. what is the percentage by mass of calcium chkoride in this solution
Answer:
[tex]\% m/m =7.61\%[/tex]
Explanation:
Hello!
In this case, since the percentage by mass of a solute in a solvent is computed as shown below:
[tex]\% m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%[/tex]
Now, as the solute here is calcium chloride and has a mass of 35.0 g and the solvent is water with a mass of 425.0 g, we can compute the percentage by mass as shown below:
[tex]\% m/m = \frac{35.0g}{35.0g+425.0g} *100\%\\\\\% m/m=7.61\%[/tex]
Best regards!
Atoms or clusters of atoms that are covalently bonded to carbon and influence the behavior of organic compounds are known as
Answer:
Functional groups
Explanation:
A functional group refers to an atom or cluster of atoms that are covalently bonded to carbon and influence the behavior of organic compounds.
There are several functional groups in organic chemistry that determine the properties of organic compounds.
For instance, in the compound CH3CH2CH2CH2OH, the functional group is the -OH group. The chemical and physical properties of this compound is largely determined by this functional group.
the bunsen burners in your labs are fueled by natural gas which is mostly methane. the thermochemical equation for the combustion of methane is
Answer:
CH₄ + 2O₂ —> CO₂ + 2H₂O
Explanation:
The thermochemical equation for the combustion of methane can be obtained as follow:
Methane (CH₄) under goes combustion in the presence of air (O₂) to produce carbon dioxide (CO₂) and water (H₂O). This can be represented in the equation below:
CH₄ + O₂ —> CO₂ + H₂O
Thus, we can balance the equation as follow:
CH₄ + O₂ —> CO₂ + H₂O
There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of H₂O as shown below:
CH₄ + O₂ —> CO₂ + 2H₂O
There are a total of 4 atoms of O on the right side and 1 atom on the left side. It can be balance by putting 2 in front of O₂ as shown below:
CH₄ + 2O₂ —> CO₂ + 2H₂O
Now the equation is balanced.
In the Minnesota Department of Health set a health risk limit for benzene in groundwater of . Suppose an analytical chemist receives a sample of groundwater with a measured volume of . Calculate the maximum mass in milligrams of benzene which the chemist could measure in this sample and still certify that the groundwater from which it came met Minnesota Department of Health standards. Be sure your answer has the correct number of significant digits.
Answer:
3.10 × 10⁻⁴ mg
Explanation:
In the Minnesota Department of Health set a health risk limit for benzene in groundwater of 10.0 μg/L. Suppose an analytical chemist receives a sample of groundwater with a measured volume of 31.0 mL. Calculate the maximum mass in milligrams of benzene which the chemist could measure in this sample and still certify that the groundwater from which it came met Minnesota Department of Health standards. Be sure your answer has the correct number of significant digits.
Step 1: Given data
Concentration limit (C): 10.0 μg/LVolume of the sample (V): 31.0 mLStep 2: Convert "V" to L
We will use the conversion factor 1 L = 1000 mL.
31.0 mL × 1 L/1000 mL = 0.0310 L
Step 3: Calculate the maximum mass of benzene (m)
We will use the following expression.
m = C × V = 10.0 μg/L × 0.0310 L = 0.310 μg.
Step 4: Convert "m" to mg
We will use the conversion factor 1 mg = 1000 μg.
0.310 μg × 1 mg/1000 μg = 3.10 × 10⁻⁴ mg
A sample of an unknown compound is vaporized at 150.°C . The gas produced has a volume of 960.mL at a pressure of 1.00atm , and it weighs 0.941g . Assuming the gas behaves as an ideal gas under these conditions, calculate the molar mass of the compound.
Answer:
34.02 g.
Explanation:
Hello!
In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:
[tex]PV=nRT\\\\n=\frac{1.00atm*0.960L}{0.08206\frac{atm*L}{mol*K}*(150+273)K} =0.0277mol\\\\[/tex]
Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:
[tex]MM=\frac{0.941g}{0.0277mol} \\\\MM=34.02g/mol[/tex]
So probably, the gas may be H₂S.
Best regards!
4.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 152. gimol, is burned completely in excess oxygen, and the mass of the products carefully measured:
product mass
carbon dioxide 5.79 g
water 2.84 g
Use this information to find the molecular formula of X.
Answer:
C₄H₁₀O₄
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 4 g
Molar mass of compound = 152 g/mol
Mass of CO₂ = 5.79 g
Mass of H₂O = 2.84 g
Molecular formula of compound X =?
Next, we shall determine the mass of Carbon, Hydrogen and Oxygen in the compound. This can be obtained as follow:
For Carbon (C):
Mass of CO₂ = 5.79 g
Molar mass of CO₂ = 12 + (2×16) = 44 g/mol
Mass of C = 12/44 × 5.79
Mass of C = 1.58 g
For Hydrogen (H):
Mass of H₂O = 2.84 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mass of H = 2/18 × 2.84
Mass of H = 0.32 g
For Oxygen (O):
Mass of C = 1.58 g
Mass of H = 0.32 g
Mass of compound = 4 g
Mass of O =?
Mass of O = (Mass of compound) – (Mass of C + Mass of H)
Mass of O = 4 – (1.58 + 0.32)
Mass of O = 4 – 1.9
Mass of O = 2.1 g
Next, we shall determine the empirical for compound X. This can be obtained as follow:
C = 1.58 g
H = 0.32 g
O = 2.1 g
Divide by their molar mass
C = 1.58 / 12 = 0.13
H = 0.32 / 1 = 0.32
O = 2.1 / 16 = 0.13
Divide by the smallest
C = 0.13 / 0.13 = 1
H = 0.32 / 0.13 = 2.46
O = 0.131 / 0.13 = 1
Multiply by 2 to express in whole number
C = 1 × 2 = 2
H = 2.46 × 2 = 5
O = 1 × 2 = 2
Thus, the empirical formula for the compound is C₂H₅O₂
Finally, we shall determine the molecular formula for the compound. This can be obtained as follow:
Molar mass of compound = 152 g/mol
Empirical formula => C₂H₅O₂
Molecular formula =?
Molecular formula => [C₂H₅O₂]ₙ
[C₂H₅O₂]ₙ = 152
[(2×12) + (5×1) + (2×16)]n = 152
[24 + 5 + 32]n = 152
61n = 152
Divide both side by 61
n = 152 / 61
n = 2
Molecular formula => [C₂H₅O₂]₂
Molecular formula => C₄H₁₀O₄
Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M
Answer:
[tex]= \mathbf{C_3H_6O}[/tex]
Explanation:
From the given information, since the molecular mass of the ion M+ is not given;
Let's assume M+ = 58.0423
So, by applying the 13th rule;
we will need to divide the mass by 13, after dividing it;
The quotient n = no. of carbon; &
The addition of the quotient (n) with the remainder r = no. of hydrogen.
So;
[tex]\dfrac{58}{13}= 4 \ remainder \ 6[/tex]
So;
[tex]C_nH_{n+r} = C_4H_{4+6}[/tex]
[tex]= C_4H_{10}[/tex]
From the given information; we have oxygen present, so since the mass of oxygen = 16, we put oxygen in the molecular formula by removing [tex]CH_4[/tex]. Also, since the mass is an even number then Nitrogen is 0.
So, we have:
[tex]= \mathbf{C_3H_6O}[/tex]
A balloon with a volume of 2.0 L is filled with a gas at 3 atmospheres. If the pressure is reduced to 0.5 atmospheres without a change in temperature, what would be the volume of the balloon?
Answer:
V2 = 12 L
Explanation:
Given the following data;
Initial volume = 2L
Initial pressure = 3 atm
Final pressure = 0.5 atm
To find the new volume V2, we would use Boyles' law.
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
[tex] PV = K[/tex]
[tex] P_{1}V_{1} = P_{2}V_{2} [/tex]
Substituting into the equation, we have;
[tex] 3 * 2 = 0.5V_{2} [/tex]
[tex] 6 = 0.5V_{2} [/tex]
[tex] V_{2} = \frac {6}{0.5}[/tex]
[tex] V_{2} = 12 [/tex]
V2 = 12L
Therefore, the new volume is 12 Liters.
A 3.45 L container has a pressure of 2.14 atm and contains 0.461 mol of gas. What is the temperature inside the container?
100 points!!
Answer:
the temperature of gas inside the container is 195.2 K.
Explanation:
Given;
volume of gas in the container, V = 3.45 L
pressure of gas in the container, P = 2.14 atm
number of gas moles, n = 0.461 mol
The temperature of gas inside the container is calculated as;
[tex]PV = nRT\\\\T = \frac{PV}{nR}[/tex]
where;
R is gas constant = 0.08205 L.atm/mol.K
[tex]T = \frac{2.14 \ \times \ 3.45}{0.461 \ \times \ 0.08205} \\\\T = 195.2 \ K[/tex]
Therefore, the temperature of gas inside the container is 195.2 K.
Give 8 example of application
Explanation:
Examples of an application include a word processor, a spreadsheet, an accounting application, a web browser, an email client, a media player, a file viewer, simulators, a console game, or a photo editor.
PLEASE HELP ITS DUE IN 1 HOUR!!!!!!
Answer: Sorry I try to download it but it not showing anything, if you take a picture of the work maybe I would do it....
Explanation:
