need help im trying to do but its kinda hard

The probability that the sample mean will be more than $542.4 is approximately 0.793 or 79.3%.

To solve this problem, we need to use the central limit theorem, which states that the sample mean of a sufficiently large sample (n ≥ 30) will be approximately normally distributed with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

In this case, the sample size is 39, which is greater than 30, so we can assume that the sample mean is normally distributed with a mean of $552 and a standard deviation of $75 / √39 ≈ $12.08.

To find the probability that the sample mean will be more than $542.4, we need to standardize the value using the standard normal distribution. We can calculate the z-score as:

z = (542.4 - 552) / 12.08 ≈ -0.819

Using a standard normal distribution table or a calculator, we can find the probability that a standard normal random variable is greater than -0.819 to be approximately 0.793.

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S" > 0 indicates that the rate of change of sales is increasing.

What is rate?

A rate is a measure of the amount of change of one quantity with respect to another quantity, typically expressed as a ratio.

The derivative of a function represents its rate of change at a particular point. In this case, S represents the monthly sales of Bluetooth headphones, and its derivative S' represents the rate of change of sales. If S' is increasing, it means that the rate of change of sales is getting larger over time.

Mathematically, this means that the second derivative S" (which represents the rate of change of the rate of change) is positive, since an increasing slope of the original function (S') corresponds to a positive value for the second derivative.

Therefore, S" > 0 indicates that the rate of change of sales is increasing.

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Answer: 78539.82

My explanation is listed bellow

V=πr2h=π·252·40≈78539.81634

Jackie sold an average of 35/52 liters of lemonade per day during her first 13 days in business. So, correct option is B.

To find the average amount of lemonade sold per day, we need to find the total amount of lemonade sold and divide it by the number of days.

To do this, we can add up the amounts sold each day:

(3/8) + (3/8) + (4/8) + (4/8) + (4/8) + (5/8) + (5/8) + (6/8) + (6/8) + (6/8) + 1 + 1 + 1

Simplifying the fractions, we get:

(3/8) + (3/8) + (4/8) + (4/8) + (4/8) + (5/8) + (5/8) + (3/4) + (3/4) + (3/4) + 1 + 1 + 1

= 8 + 6/8

So, Jackie sold a total of 8 6/8 liters of lemonade in 13 days.

To find the average per day, we divide this by the number of days:

(8 6/8) ÷ 13

We can convert the mixed number to an improper fraction and simplify:

(70/8) ÷ 13

= 70/104

= 35/52

Therefore, correct option is B.

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Answer:

137.5 miles

Step-by-step explanation:

To calculate the distance between Atlanta and Augusta, we can use the formula:

Distance = Speed x Time

We are given the speed and time, so we can substitute those values into the formula and solve for the distance.

Distance = 55 miles/hour x 2.5 hours

Distance = 137.5 miles

Therefore, Augusta is 137.5 miles away from Atlanta.

Answer: The answer is 147 miles per hour

Step-by-step explanation:

Therefore, the probability that the toll collector will have to wait longer than 26.30 minutes before collecting the eighth toll is approximately 0.038.

Since the arrival of cars at a tollbooth follows a Poisson process with a rate of 5 cars every 10 minutes, the time between arrivals of cars follows an exponential distribution with a mean of 2 minutes (10 minutes / 5 cars). Let X be the time between arrivals of cars. Then, X ~ Exp(1/2) since the mean of an exponential distribution is equal to the reciprocal of the rate.

To find the probability that the toll collector will have to wait longer than 26.30 minutes before collecting the eighth toll, we need to find the probability that the sum of the waiting times for the first seven cars is less than 26.30 minutes and the waiting time for the eighth car is greater than the remaining time.

Let Y be the waiting time for the eighth car. Then, Y ~ Exp(1/2) since the waiting time for each car is independent and identically distributed. Therefore, the probability that the toll collector will have to wait longer than 26.30 minutes before collecting the eighth toll can be calculated as follows:

P(Y > 26.30 - T), where T is the sum of waiting times for the first seven cars.

Since the waiting times for each car are independent, the sum of the waiting times for the first seven cars follows a gamma distribution with parameters k = 7 and θ = 1/2. Therefore, we have:

T ~ Gamma(7, 1/2)

Now, we can calculate the desired probability as follows:

[tex]P(Y > 26.30 - T) = ∫∫\int\limits^a_b { (e^(-t/2) * (1/2)^{7})/6! } \, dx[/tex]

= 0.038

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Step-by-step explanation:

like they don't know, and so we don't know and so what do we do when ask that question as overtime and somewhere else

The r-value ranges from -1 to +1, with -1 indicating a strong negative correlation. Therefore, the r-value closest to -1 represents the strongest negative correlation.

An r-value represents the strength and direction of a correlation between two variables. The strongest negative correlation occurs when the r-value is -1. In this case, as one variable increases, the other variable decreases consistently, showing a perfect negative linear relationship between the two variables.

The ability of a material to resist the flow of heat through it is gauged by the R-value , which is used in materials research and building construction. It measures the energy efficiency of insulation materials including fibreglass, foam board, and cellulose and is commonly represented in square metres kelvin per watt (m2K/W) units.

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It can be proven that the area of AECF is equal to 1/2 the area of ABCD, because the adding the areas of △AEC and △AFC, gives us the area of AECF.

With E and F being midpoints of the sides AB and AD of parallelogram ABCD, we know that AE = 1 / 2 AB and A F = 1 / 2 AD. We can also see that area of △ AEC is 1 / 2 the area of △ ABC because they share the same height and their bases are in the same ratio ( AE = 1 / 2 AB).

We also see that the area of △ A F C is 1/2 the area of △ ADC because they share the same height  and their bases are in the same ratio ( A F = 1 / 2 AD).

What this proves is that because both △ AEC and △ A F C are half the areas of △ ABC and △ ADC respectively, the area of AECF is equal to 1/2 the area of ABCD.

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With a $1 bet on three numbers, you can expect to win $12.33. So, the expected winnings for a $1 bet on three numbers in a roulette wheel is approximately $0.95.

Here's how to calculate it:
- There are 38 possible outcomes on the roulette wheel (1 through 36, 0, and 00).
- Your bet covers 3 of those outcomes, so your probability of winning is 3/38.
- The payout for a winning bet is $1 plus another $11, for a total of $12.
- To find your expected winnings, multiply the probability of winning by the payout:
  (3/38) x $12 = $0.947
- Rounded to the nearest cent, that's $0.95.
So with a $1 bet on three numbers, you can expect to win about $0.95 each time, on average. Over many bets, your total winnings will approach $12.33.

In order to calculate the expected winnings from a $1 bet on three numbers in a roulette wheel, we can follow these steps:
1. Determine the probability of winning the bet. In a roulette wheel with 38 numbers (1-36, 0, and 00), you bet on three numbers, so the probability of winning is 3/38.
2. Determine the amount you would win if your bet is successful. Since the bet pays 11 to 1, you would get back your original $1 plus another $11, for a total of $12.
3. Multiply the probability of winning by the amount you would win. This will give you the expected winnings for a single $1 bet:
(3/38) * $12 = $0.947
So, the expected winnings for a $1 bet on three numbers in a roulette wheel is approximately $0.95 (rounded to the nearest cent).

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Answer:

Line Segment KL is perpendicular to line segment LM.

Step-by-step explanation:

Notice how there is a right angle between line segments LM and KL. By the definition of perpendicular lines, they are perpendicular. If you have the chance, please answer my last question if this is helpful.

The numeral EA3 (base 16) is equivalent to 3,523 in base 10.

To convert the numeral EA3 (base 16) to base 10, we can use the formula:

[tex](14 * 16^2) + (10 * 16^1) + (3 * 16^0) = 3,523[/tex]

Therefore, the numeral EA3 (base 16) is equivalent to 3,523 in base 10.

To understand how this conversion works, it is helpful to first understand what these two number systems represent.

Base 16 (hexadecimal) is a positional number system that uses 16 digits: 0-9 and A-F. Each digit represents a different power of 16, with the rightmost digit representing 16^0, the next digit to the left representing 16^1, and so on. Therefore, the numeral EA3 (base 16) can be interpreted as:

[tex]14 * 16^2 + 10 * 16^1 + 3 * 16^0[/tex]

To convert this numeral to base 10 (decimal), we simply evaluate this expression:

14 * [tex]16^2[/tex] = 3,584

10 * [tex]16^1[/tex]= 160

3 * [tex]16^0[/tex] = 3

Adding these values together, we get:

3,584 + 160 + 3 = 3,523

Therefore, the numeral EA3 (base 16) is equivalent to 3,523 in base 10.

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a. The probability of a rap song being played is 9/25 or 0.36 (36%).

b. The probability of a song not being country is 19/25 or 0.76 (76%).

a) To find the probability that a randomly played song is a rap song, we need to consider the total number of songs and the number of rap songs.

There are 10 rock songs, 9 rap songs, and 6 country songs, for a total of 25 songs.

The probability of a rap song being played is:
(Number of rap songs) / (Total number of songs) = 9 / 25.
So, the probability of a rap song being played is 9/25 or 0.36 (36%).
b) To find the probability that a randomly played song is not country, we need to consider the total number of songs and the number of songs that are not country.

Since there are 6 country songs out of the 25 total songs, there are 19 songs that are not country (10 rock + 9 rap).

The probability of a non-country song being played is:
(Number of non-country songs) / (Total number of songs) = 19 / 25.

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The initial size of the bird population was approximately 4,619 birds, and the estimated population 2 years from now is approximately 6,528 birds.

We are dealing with a bird population that doubles every 10 years. To find the initial population 25 years ago, we can use the formula:

Initial population = Current population / (2^(Years since introduction / 10))

Here, the current population is 13,000, and it has been 25 years since the bird species was introduced. Plugging in these values, we get:

Initial population = 13,000 / (2^(25 / 10))

Initial population = 13,000 / (2^2.5)

Initial population ≈ 4,619 birds (rounded to the nearest whole number)

To estimate the bird population 2 years from now, we can use the same formula with a total of 27 years since the introduction:

Future population = Initial population * (2^(Years since introduction / 10))

Future population = 4,619 * (2^(27 / 10))

Future population ≈ 6,528 birds (rounded to the nearest whole number)

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The approximate value of the integral using the midpoint rule with n=4 is 5.8571 (rounded to four decimal places).

The area under a simple curve can be roughly estimated using the midpoint rule, commonly referred to as the rectangle method or mid-ordinate rule. The midpoint approach provides a better approximation than the left rectangle or right rectangle sum, which are two other ways for approximating the area.

We need to use the midpoint rule with n=4 to approximate the integral of 8 sin(√(x)) dx.

The midpoint rule formula for approximating a definite integral is:

∫[a,b] f(x) dx ≈ Δx [f(x1/2) + f(x3/2) + ... + f(x(n-1/2))]

where Δx = (b-a) / n is the width of each subinterval, and xi/2 = (xi-1 + xi) / 2 is the midpoint of the i-th subinterval.

For n=4, we have Δx = (b-a) / n = (1-0) / 4 = 0.25, and the endpoints of the subintervals are:

x₀ = 0, x₁ = 0.25, x₂ = 0.5, x₃ = 0.75, x₄ = 1

The midpoints of the subintervals are:

x1/2 = 0.125, x3/2 = 0.375, x5/2 = 0.625, x7/2 = 0.875

Now we can apply the midpoint rule formula:

∫[0,1] 8 sin(√(x)) dx ≈ Δx [f(x1/2) + f(x3/2) + f(x5/2) + f(x7/2)]

where f(x) = 8 sin(√(x)).

Plugging in the values, we get:

∫[0,1] 8 sin(√(x)) dx ≈ 0.25 [f(0.125) + f(0.375) + f(0.625) + f(0.875)]

Using a calculator, we can evaluate each term and sum them up:

f(0.125) ≈ 2.4774

f(0.375) ≈ 5.6382

f(0.625) ≈ 6.8171

f(0.875) ≈ 5.4946

∫[0,1] 8 sin(√(x)) dx ≈ 0.25 [2.4774 + 5.6382 + 6.8171 + 5.4946] ≈ 5.8571

Therefore, the approximate value of the integral using the midpoint rule with n=4 is 5.8571 (rounded to four decimal places).

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Answer: The equation that represents how far Haley is from her goal of reaching $8000 is y = 8000 - 2000 - 200x.

Step-by-step explanation:

Haley starts with $2000 and saves an additional $200 each month. Therefore, after x months, she will have saved:

2000 + 200x dollars

To find how far Haley is from her goal of reaching $8000, we need to subtract her savings from her goal:

8000 - (2000 + 200x) = 6000 - 200x

This gives us the value of y, which represents how far Haley is from her goal.

Therefore, the equation that represents how far Haley is from her goal of reaching $8000 is:

y = 6000 - 200x

Alternatively, we can simplify this equation to:

y = 8000 - 2000 - 200x

y = 8000 - 2000 - 200x represents how much more money Haley needs to save to reach her goal of $8000 after x months.

The joint density function of x and y is f(x,y) = 1 for 0 <= x <= 1 and 0 <= y <= 1.

The joint density function of two random variables x and y is a function that assigns a non-negative value to every possible pair of x and y values. In this case, since x and y are independent and identically distributed uniform random variables on [0,1], their joint density function is given by the product of their individual density functions:

f(x,y) = f(x) × f(y) = 1 × 1 = 1, 0 <= x <= 1, 0 <= y <= 1

So the joint density function of x and y is f(x,y) = 1 for 0 <= x <= 1 and 0 <= y <= 1.

Since x and y are independent and identically distributed uniform random variables on [0,1], their probability density functions (PDFs) are given by:

f(x) = 1, 0 <= x <= 1

f(y) = 1, 0 <= y <= 1

The joint probability density function (PDF) of x and y is given by the product of their individual PDFs:

f(x,y) = f(x) × f(y) = 1 × 1 = 1, 0 <= x <= 1, 0 <= y <= 1

Therefore, the joint density function of x and y is f(x,y) = 1 for 0 <= x <= 1 and 0 <= y <= 1.

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By vertical line test the relation represented by given curved graphs is a function.

A relation is said to be a well defined function if one element of domain set is related to exactly one element of codomain.

Here it is clear that if we draw a vertical line at any point that line cuts through only one point of the curve.

So vertical line test shows that one point of X axis i.e. one element of domain is related to one point on Curve i.e. one element of Codomain.

Hence by vertical line test we can say that the relation given is a function.

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at the 5% level of significance, we can conclude that the population median score for the students taking the writing portion of the SAT is not 500.

We can use the Wilcoxon rank-sum test (Mann-Whitney U test) to test the hypothesis that the population median score for the students taking the writing portion of the SAT is 500.

Null Hypothesis: The population median score for the students taking the writing portion of the SAT is 500.

Alternative Hypothesis: The population median score for the students taking the writing portion of the SAT is not 500.

We can use the Wilcoxon rank-sum test because the sample size is small, and the population distribution is not known. The Wilcoxon rank-sum test does not require the normality assumption.

Using the given data, we rank the scores, and then calculate the test statistic U as follows:

Rank: 13 14 2 3 4 6 1 5 7 8 3 11 0 0 9

Sample size (n) = 15

Sum of ranks for students with scores >= 500 (R1) = 61

Sum of ranks for students with scores < 500 (R2) = 54

U = min(R1, R2) = 54

Using Table 1 of Appendix B for alpha = 0.05 and n1 = n2 = 15, the critical value of U is 19.

Since U = 54 is greater than the critical value of 19, we reject the null hypothesis and conclude that there is evidence that the population median score for the students taking the writing portion of the SAT is not 500.

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The locus of points in a plane that are equidistant from endpoints A and B is the perpendicular bisector of the line segment AB.

To see why this is true, consider a point P in the plane that is equidistant from A and B. This means that the distance from P to A is equal to the distance from P to B.

Now, draw the line segment AP and the line segment BP. Since the distance from P to A is equal to the distance from P to B, these two line segments must have the same length. Therefore, triangle APB is an isosceles triangle, and the perpendicular bisector of AB passes through the midpoint of AB and is perpendicular to AB.

Conversely, any point on the perpendicular bisector of AB is equidistant from A and B. Therefore, the perpendicular bisector of AB is the locus of points that are equidistant from A and B.

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The curve of the function y is attached.

The domain of the function is equal to (−∞, −1) ∪ (−1, 1) ∪ (1, ∞).

The y-intercept and x-intercept both are zero implies function is decreasing on (−∞, −√3), increasing on (−√3, 0), decreasing on (0, √3), and increasing on (√3, ∞).

To sketch the curve y = 2x² / (x² - 1), use the following guidelines,

Find the domain,

The function is defined for all x except x = ±1,

since the denominator x² - 1 cannot be zero.

So the domain is (−∞, −1) ∪ (−1, 1) ∪ (1, ∞).

Find the intercepts,

To find the x-intercept, set y = 0 and solve for x,

⇒ 0 = 2x² / (x² - 1)

This gives us x = 0, which is the x-intercept.

To find the y-intercept, set x = 0 and evaluate y,

y = 2(0)² / ((0)² - 1)

  = 0

So the y-intercept is also 0.

The vertical and horizontal asymptotes,

As x approaches ±∞, the function approaches the horizontal line y = 2.

To find the vertical asymptotes, look at where the denominator x² - 1 becomes zero.

This occurs at x = ±1, so we have vertical asymptotes at x = ±1.

The critical points and intervals of increase/decrease:,

To find the critical points, take the derivative of the function and set it equal to zero.

y' = (4x(x²-3)) / (x²-1)²

⇒4x(x²-3) = 0

This gives us critical points at x = 0 and x = ±√3.

From this, the function is decreasing on (−∞, −√3), increasing on (−√3, 0), decreasing on (0, √3), and increasing on (√3, ∞).

Graph is attached.

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The above question is incomplete, the complete question is:

Use the guidelines to sketch the curve y = 2x²/x² − 1.

(A) The domain is{x | x² − 1 ≠ 0} = {x | x ≠ ±1}= (0,−1)

(B) The x- and y-intercepts are both 0.

The null hypothesis (H0) is that the proportion of clients who have high-risk stocks is equal to or greater than 15%, while the alternative hypothesis (H1) is that the proportion of clients who have high-risk stocks is less than 15%. In other words, the null hypothesis assumes that p >= 0.15 and the alternative hypothesis assumes that p < 0.15.

To Test These hypotheses, the brokerage firm can collect a sample of clients and determine the proportion of those clients who have high-risk stocks in their portfolio. If the sample proportion is significantly lower than 15%, the firm can reject the null hypothesis and conclude that there is evidence to suggest that the true proportion of clients with high-risk stocks is less than 15%.

If the sample proportion is not significantly lower than 15%, the firm fails to reject the null hypothesis and cannot conclude that the true proportion of clients with high-risk stocks is less than 15%.

It is important for the brokerage firm to accurately determine the proportion of clients with high-risk stocks, as this information can help them manage their clients' portfolios more effectively and reduce the overall risk of their business.

By testing these hypotheses, the firm can gain a better understanding of the risk level of their clients' investments and make informed decisions about how to allocate their resources.

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The formula for the fraction of the population who have heard the rumor at time t is:

H(t) = 1 - (1 - H(0)) * e^(-k*t*(1-H(0)))

where H(0) is the initial fraction of the population who have heard the rumor (in decimal form), k is the proportionality constant, and e is the mathematical constant approximately equal to 2.718.

To solve part (b), we can use the information given to find the value of H(0) and then solve for the time when H(t) = 0.9.

We know that at 8 am, 80 people have heard the rumor, so H(0) = 80/1000 = 0.08. We also know that by noon, half the town has heard it, so H(4) = 0.5. Plugging these values into the formula, we get:

0.5 = 1 - (1 - 0.08) * e^(-k*4*(1-0.08))

Simplifying, we get:

0.42 = e^(-0.32k)

Taking the natural logarithm of both sides, we get:

ln(0.42) = -0.32k

Solving for k, we get:

k = -ln(0.42)/0.32 = 0.646

Now we can use this value of k to find the time when 90% of the population has heard the rumor:

0.9 = 1 - (1 - 0.08) * e^(-0.646t*(1-0.08))

Simplifying, we get:

0.08 * e^(-0.0565t) = 0.1

Dividing both sides by 0.08, we get:

e^(-0.0565t) = 1.25

Taking the natural logarithm of both sides, we get:

-0.0565t = ln(1.25)

Solving for t, we get:

t = -ln(1.25)/0.0565 ≈ 30.9

Therefore, 90% of the population will have heard the rumor after about 30.9 hours.

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Matrics its determinant is det(A+B) = 4.

Hence, det(A+B) is not equal to det(A) + det(B) = 5.

It is not necessarily true that if A and B are n × n matrices with detA = 2 and detB = 3, then det(A+B) = 5.

The determinant of a matrix is a scalar value that encodes various properties of the matrix.

It has the property that det(kA) = kⁿ × det(A) for any scalar k and n × n matrix A, n denotes the dimension of the matrix.

The determinant does not satisfy the distributive property, that is, det(A+B) is not necessarily equal to det(A) + det(B).

To illustrate this point, consider the following counter example.

Let A be the matrix:

[ 2 0 ]

[ 0 1 ]

and let B be the matrix:

[ -1 0 ]

[ 0 3 ]

Then detA = 2 and detB = 3.

The sum A + B is the matrix:

[ 1 0 ]

[ 0 4 ]

and

In general, cannot conclude that det(A+B) = 5 given that detA = 2 and detB = 3.

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Noura needs to maintain a rate of 0.15 miles per minute on her treadmill to jog 3 miles in 20 minutes.

Speed (rate)is simply referred to as distance traveled per unit time.

Mathematically, it is expressed as:

Speed = Distance ÷ time.

Hence:

rate = distance / time

Given that; the distance that Noura wants to jog is 3 miles, and the time she wants to do it in is 20 minutes.

Substituting these values into the formula, we get:

rate = distance / time

rate = 3 miles / 20 minutes

Simplifying the right side of the equation, we get:

rate = 0.15 miles per minute

Therefore, the rate does she need to maintin on her treadmill is 0.15 miles per minute.

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Answer: The Error Bound for Proportions (EBP) gives the maximum amount of error that can be tolerated when estimating a population proportion from a sample proportion.

To find the EBP at the 95% level, we can use the following formula:

EBP = z*(sqrt((p*(1-p))/n))

where:

z = z-score corresponding to the desired level of confidence (for a 95% confidence level, z = 1.96)

p = sample proportion (0.31, based on the survey results)

n = sample size (1379)

Substituting the given values, we get:

EBP = 1.96*(sqrt((0.31*(1-0.31))/1379))

EBP ≈ 0.0324

Rounding to four decimal places, the Error Bound for Proportions (EBP) at the 95% level is 0.0324. This means that we can be 95% confident that the true population proportion of CEOs who are extremely concerned about the availability of key skills lies within the range of (0.31 - 0.0324) to (0.31 + 0.0324), or approximately 0.2776 to 0.3424.

According to the question the length of arc BC is approximately 1.69 feet.

The measurement of the circle's boundaries is called as the circumference or perimeter of the circle. whereas the circumference of a circle determines the space it occupies. The circumference of a circle is its length when it is opened up and drawn as a straight line. Units like cm or unit m are typically used to measure it. The circle's radius is considered while calculating the circumference of the circle using the formula. As a result, in order to calculate the circle's perimeter, we must know the radius or diameter value.

The circumference of a circle is given by the formula[tex]$C = 2\pi r$[/tex], where $r$ is the radius of the circle. In this case, the radius is 8 feet, so the circumference of the circle is: C=16π feet.

Since the angle BAC is one-third of a radian, we know that angle BOC (the angle at the center of the circle) is twice as large, or approximately $38.2^\circ$. This is because the angle at the center of the circle is twice as large as the angle on the circumference that it intercepts.

Now we can use this angle to find the length of arc BC. The formula for the length of an arc is: L = Ф/360 *C

L = 38.2/350 * 16π = 1.69 feet.

So the length of arc BC is approximately 1.69 feet.

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Based on the 1.5 × IQR rule for outliers, there is no evidence to support the student's claim because there is only one outlier at 58 minutes.

The interquartile range is the difference between upper and lower quartiles. The semi-interquartile range is half the interquartile range. When the data set is small, it is simple to identify the values of quartiles.

Mathematically, interquartile range (IQR) is the difference between quartile 1 (Q₁) and quartile 3 (Q₃):

IQR = Q₃ - Q₁

The following interquartile ranges was calculated by using Excel:

Q₃ = 31.5

Q₁ = 20.5

Now, the interquartile range (IQR) is given by:

IQR = Q₃ - Q₁

IQR = 31.5 - 20.5

IQR = 11

Based on the 1.5 × IQR rule for outliers, we have:

1.5 × IQR = 1.5 × 11 = 16.5

Therefore, our fences will be 16.5 points below Q₁ and 16.5 points above Q₃:

Lower fence = 20.5 - 16.5 = 4.5

Upper fence = 4.5 + 31.5 = 36.

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