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Answer: 8

Step-by-step explanation:

As corresponding sides of similar triangles are proportional,

[tex]\frac{RX}{RB}=\frac{XE}{BO}\\\\\frac{6}{15}=\frac{a}{20}\\\\a=20\left(\frac{6}{15} \right)=\boxed{8}[/tex]

This graph represents the equation y = -3

According to law of cosines if the lengths of triangle are 12,11,6 then the angle will be 114=157-132cos(Y)

Given the length of XZ is 12, length of YZ is 11 and the length of YX=6.

According to law of cosines the angle of a triangle when the length of sides are given can be written as:

[tex]c^{2} =a^{2} +b^{2} -2abcosd[/tex]

where c is the side opposite to the angle which we have to find and a and b are the rest sides.

We have to put the values of sides in the above law:

[tex]12^{2} =6^{2} +11^{2} -2*6*11cosY[/tex]

144=36+121-132 cos Y.

Hence the angle can be written as 144=36+121-132 cos Y.

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Answer:

Step-by-step explanation:

The domain is the set of x-values and the range is the set of y-values.

Answer:

.7692307692 or 10/26

Step-by-step explanation:

You solve this problem by finding the total number of sports playing students and dividing it by the total, in this case 26. Since we know there are 5 students that play both sports, you subtract that 5 from the total number of basketball plyers and baseball players, so 16-5=11 and 9-5=4, then add those together, so 11+4=15. From there you add back in the students that play both which is 5, so 15+5=20. 20/26 is your answer.

The inequality equation will be -5x + 20 < -10.

Inequality is defined as an equation that does not contain an equal sign.

The weather report says the temperature is 20°c and will drop 5°c per hour for the next 6 hours.

Daryl plans to be gone at least 6 hours, and he has a plant outside.

If he wants the plant to remain in temperatures above -10° should Daryl move the plant to a warmer location before leaving will be

The inequality equation will be

-5x + 20 < -10

where x is the number of hours.

Then we have

-10 < -5x + 20

5x > 30

   x > 6 hours

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Answer:

y = 1

x = -2

Step-by-step explanation:

During the substitution method, you are substituting one function into another. Because both functions are set equal to "x", you can make the functions equal each other. This allows you to 'get rid' of the "x" variable and simplify to find the value of "y".

5A) x = -2y

5B) x = 2 - 4y

-2y = 2 - 4y                     <----- Set both equations equal

2y = 2                             <----- Add 4y to both sides

y = 1                                <----- Divide both sides by 2

Now that you know what "y" equals, you can plug that value into the "y" variable into one of the equations. This will allow you to then simplify and find the answer for "x".

x = -2y                             <----- Equation 5A

x = -2(1)                           <----- Plug 1 into "y"

x = -2                              <----- Multiply -2 and 1

Answer:

Given - AC is parallel to DE

angle 3y + 28 = angle X ( Vertically opposite angles are equal).

3y + 28 = X

X + Y = 180° ( supplementary angles).

3y - X = (-28)

Solving both the equation we get

multiply eq 1 with 3

3x + 3y = 540

-X + 3y = (-28)

subtracting

4x = 568

x = 142°

3y + 28 = 142

3y = 142 - 28

3y = 114

y = 38°

Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

Starting with the left side, we can transform it into the right side.

  [tex]2\cos(2x)=2(\cos^2(x)-\sin^2(x)) = 2(\cos^2(x)-(1-\cos^2(x)))\\\\=2(2\cos^2(x)-1)=2\left(\dfrac{2}{\sec^2(x)}-\dfrac{\sec^2(x)}{\sec^2(x)}\right)\\\\=\boxed{\dfrac{4-2\sec^2(x)}{\sec^2(x)}}[/tex]

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(25) - log_{6}(5) [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) {}^{2} - log_{6}(5) [/tex]

[ property : x² = 2 log x ]

[tex]\qquad \tt \rightarrow \: 2 \: log_{6}(5) {}^{} - log_{6}(5) [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

B. Yes, quadrilateral WXYZ is rhombus because the sides are perpendicular.

Step-by-step explanation:

1) according to the given coordinates the equations of the sides are:

YZ: y=2; WZ: x=2; WX: y=10; XY: x=10. It means

2) YZ⊥WZ; YZ⊥XY; WX⊥XY; WX⊥WZ. To the additional, WX=WZ=YZ=XY, then

3) the given quadrilateral is sqare (rhombus with angles m∠=90°).

4) finally, the correct answer is

B. Yes, quadrilateral WXYZ is rhombus because the sides are perpendicular.

Answer: (23, 46)

Step-by-step explanation:

The equation of the line is y = 2x, and we can thus represent point P as (x, 2x)

Substituting into the distance formula,

[tex]\sqrt{2645}=\sqrt{(x)^{2}+(2x)^{2}}\\\\2645=x^2 + (2x)^2\\\\2645=x^2 + 4x^2\\\\2645=5x^2\\\\529=x^2\\\\x=23[/tex]

Thus, the coordinates of P are (23, 46)

The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for [tex]m^{2} +1[/tex] is 9.

Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and [tex]\sqrt{t-1}[/tex] for 8<t<11.

A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.

B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.

C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.

D) In this we have to find the function at [tex]m^{2} +1[/tex] when m belongs to [tex]\sqrt{7} and \sqrt{10}[/tex] the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.

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Answer:

C. 3x - 9

Step-by-step explanation:

3x – y = 9 ___(1)

8x – 4y = 0 ___(2)

From (1) eq.

3x – y = 9

– y = 9 – 3x

y = - (-3x + 9)

y = 3x – 9

Hence, 3x - 9 should be substituted in the second equation to get the required answer.

Answer:

c

Step-by-step explanation:

solve for y in the first equation

y = 3x - 9

when you substitute, you will get a value of 9 for x and 18 for y

Answer:

option B or 40%

Step-by-step explanation:

Well if 14/35 of the class is male. You divide 14 by 35. And after using calculator I see the answer is 40% of the class is male.

Thank

Based on the information given, the correct options will be

y = x + 6 and 3x - 3y = -18 .... Infinitely many solutions.

y = -2x + 5 and 2x + y = -7 .... No solution.

y = -4x + 11 and -6x + y = 11 ... One solution.

Solving equations

y = -4x + 11 ....... equation i

-6x + y = 11 ...... equation ii

Put equation i into ii.

-6x + y = 11

-6x + (-4x + 11) = 11

-6x - 4x + 11 = 11

-6x - 4x = 11 - 11

-10x = 0

x = 0

Therefore, x = 0 and y = 11. This gives a solution for each variable.

y = -2x + 5 ..... i

2x + y = -7 ..... ii

Put equation I into ii

2x + y = -7

2x + (-2x + 5) = -7

2x - 2x = -7 - 5

0 = -12

This indicates no solution.

y = x + 6 ..... i

3x - 3y = -18 ..... ii

Put equation I into ii

3x - 3y = -18

3x - 3(x + 6) = -18

3x - 3x - 18 = -18

3x - 3x = - 18 + 18

0 = 0

This implies that there are infinitely many solutions.

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Answer:

5 and a 250,000

Step-by-step explanation:

A quarter million = 1,000,000 · [tex]\frac{1}{4}[/tex] = 250,000

Answer:

It is: 5,250,000

Part A

The notation [tex]\lim_{x \to 2^{+}}f(x)[/tex] means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows [tex]\lim_{x \to 2^{+}}f(x) = 2[/tex]

Then for the left hand limit [tex]\lim_{x \to 2^{-}}f(x)[/tex], we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, [tex]\lim_{x \to 2^{-}}f(x) = 1[/tex]

===============================================================

Part B

Because [tex]\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)[/tex] this means that the limit [tex]\lim_{x \to 2}f(x)[/tex] does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since [tex]\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3[/tex], this means the limit [tex]\lim_{x \to 4}f(x)[/tex] does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

Answer:

u = -18

Step-by-step explanation:

[tex]\frac{-5u}{6} =15[/tex]

Multiply both sides by 6.

-5u = 15 × 6

-5u = 90

Divide both sides by -5.

u = -18

Answer:

[tex]27[/tex]

Step-by-step explanation:

[tex]g(f(0))=g(2(0)+3)=g(3)=3^3=27[/tex]

Answer:

See Pictures

Step-by-step explanation:

The inequality describes the price $375  she can afford for 25

individual box of supplies will be $375 ≥ 25x.

An inequality is comparison of  two values, showing if one is less than, greater than, or simply not equal to another value.

Let the price of each box is $x.

The inequality describes the price can she afford for each

individual box of supplies will be $375 ≥ 25x.

Therefore inequality is $375 ≥ 25x.

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Answer: The data cannot be modeled by an exponential function because the data is for a linear function (as there is a constant increase in f(x) each time x increases by 1)

Answer: 4/30

Step-by-step explanation:

it does

Answer:

you got that

Step-by-step explanation:

wet wet wet

Answer:

{ x : x > 2 }

Step-by-step explanation:

4x - 3 + 6x > 5x + 7 , that is

10x - 3 > 5x + 7 ( subtract 5x from both sides )

5x - 3 > 7 ( add 3 to both sides )

5x > 10 ( divide both sides by 5 )

x > 2

Step-by-step explanation:

{-1,2,3,4,5,6,8} is the answer

The corresponding part of PQ is WX

The congruent statement is given as:

polygon WXYZ ≅ polygon PQRS.

This means that the corresponding points are:

W and P, X and Q, Y and R, Z and S

When two points Q and P are joined together, we have:

polygon WX ≅ polygon PQ

Hence, the corresponding part of PQ is WX

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Answer:

8x + 100

Step-by-step explanation:

Your answer is correct! But because the equation is already set to "y =", you do not need the "f(x)" in your equation.