Niobium (nb) has a bcc crystal structure, an atomic radius of 0.143 nm, and an atomic weight of 92.91 g/mol. compute and compare its theoretical density with the experimental value.

Answers

Answer 1

Both the theoretical density and experimental value is 8.57g/cm3

The term crystal structure, in crystallography, denotes that the structure in which the atoms (ions or molecules) are attached are arranged in an ordered manner. The smallest repeating unit of the crystal structure is called a unit cell.

Given that:

The radius of Nb is given as R=0.1430nm

The density of Nb is given as d=8.57g/cm3

The atomic weight of Nb is given as M=92.91g/mol

Also, given that the structure is BCC.

The value of the number of atoms per unit cell in BCC is Z=2

The formula for the edge length of BCC structure is,

a=4R/(√3)

Substitute the given values

a=(4*0.1430 nm)/(√3)

=3.3024×10−8cm

The formula for the density of the Nb in BCC structure is,

d2=(Z×M)/(a3×NA)

Substitute the given values.

d1=(2×92.91g/mol)/((3.3024×10-8cm)3 × 6.022 × 1023 mol-1)

=(185.82g/mol)/(21.68cm3/mola3×NA)

=8.57g/cm3

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Related Questions


A 7.8 kg outdoor copper sculpture heats up during the day from 28°C to 87°C. How much energy was absorbed? Note: Copper has a specific heat of
390 J/kg *C.

Answers

The energy absorbed outdoor copper sculpture heats up during the day q = 1.79 x 10⁵ J.

Equation :

To find energy using formula,

q = mcΔT

where,

q is energy

m is mass

c is specific heat

ΔT is change in temperature

Given,

m = 7.8 kg

c = 390 J/kg

T₁ =  28°C

T₂ = 87°C

To find ΔT,

ΔT = T₂ - T₁

ΔT = 87° - 28°

ΔT = 59°C

Now, putting values,

q = mcΔT

q = 7.8 kg x 390 J/kg x 59

q = 1.79 x 10⁵ J

Is copper good for sculptures?

The best materials for sculpture are copper and copper alloys for a variety of reasons. They offer countless artistic possibilities because they can be molded into any desired shape. Copper components can be mechanically joined or assembled by bolting or bonded by welding, enabling works of enormous size.

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Explain what dawkins says selection is acting on in chapter 2 and how that variation is distributed throughout a population (gene pool) (blending vs. independent assortment

Answers

Dawkins says selection acts on the variations in the populations which are responsible for increasing or decreasing the fitness of the individuals carrying them.

Variation is distributed population following Mendelian genetics. Like the law of independent assortment where variations are transferred independently of each other. When blending inheritance was discarded where traits were thought to be average of that of parents of progeny , which was not the case in many cases.

One example of unconscious selection is the loss of various traits like  loss of natural dispersal mechanisms, even  and rapid seed germination, larger propagules, simultaneous ripening, and loss of mechanical protection as well as changes in the breeding system. This loss or selection on these traits while selecting for other traits like more yield and water efficiency , resistance to diseases etc. This unconscious selection associated with other selection by humans is unconscious.

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What is the magnitude of an electric field that balances the weight of a plastic sphere of mass 7.4 g that has been charged to -3.0 nc?

Answers

It is a physical field occupied by a charged particle on another particle in its surrounding .The magnitude of electric field will be -0.0241 MN/C.

What is electric field?

A physical field called an electric field surrounds electrically charged particles and attracts or repels all other charged particles nearby. It can also refer to the physical field surrounding a system of charged particles. Electric charges and time-varying electric currents are the building blocks of electric fields. The electromagnetic field, one of the four fundamental interactions (also known as forces) of nature, manifests itself in both electric and magnetic fields.

The electric force in an electric field is given by the equation,

 [tex]E = \frac{F}{Q}[/tex]

Since electric field is balanced by the weight of the plastic sphere, the electric force is equal to weight of the sphere.

[tex]F = mg[/tex]

So the equation becomes

[tex]E = \frac{mg}{Q}[/tex]

Putting the value from the question,

m = 0.0074 kg

Q = (-3.0) Nc

g (gravitational acceleration) = 9.8 m/s^2

So, we get

[tex]E = \frac{(9.8)(0.0074)}{(-3.0)}[/tex]

[tex]E = -0.0241 MN/C[/tex]

Hence, the electric field is -0.0241 MN/C.

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how much force is required to accelarate 2kg mas at 3m/s 2

Answers

Answer:

6 Newton.

Explanation:

Force (F) = Mass (M) x Acceleration (A).

Force = 2kg x 3 m/s^2

F = 6kg m/s^2 = 6 Newton. = 6N

Therefore, Force required to accelerate the body is 6N

Every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of the masses of the particles and inversely proportional to the square of the distance between them. True or false?.

Answers

The Law of Universal Gravitation,  states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Newton's law of gravitation, states that any particle of matter in the universe draws another with pressure varying at once as the manufactured from the loads and inversely as the rectangular.

Newton, the pressure of gravity appearing between the earth and another item is at once proportional to the mass of the earth, directly proportional to the mass of the item, and inversely proportional to the square of the distance that separates the centers of the earth and the item. Gravitational steady, G is unbiased of the nature of the particle, medium among the debris, and time. Its cost is constant anywhere within the Universe.

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The big o notation of the worst case scenario of pushing back an element into a queue implemented using a list is _______________

Answers

The big o notation of the worst-case scenario of pushing back an

element into a queue implemented using a list is Array or a Linked list.

What is an array?

A queue could be implemented as an array or a linked list with very different insertion, removal, and indexing characteristics.In computer science, an array is a data structure consisting of a collection of elements, each identified by at least one array index or key. An array is stored such that the position of each element can be computed from its index tuple by a mathematical formulaThe array in C has a fixed size, which means that once the size is specified, it cannot be changed; you cannot shrink or expand it. The rationale behind this was that, when expanding, we cannot always be certain that we will receive the subsequent memory location for free (it is not always possible). The array is memory statically allocated when it is declared, making it impossible to shrink because only the compiler has the power to do so.The first element of the array is indexed by the subscript 0, for zero-based indexing; by the subscript 1, for one-based indexing; and by the subscript n, for N-based indexing. An array's base index can be chosen at will. Negative index values are typically permitted in programming languages that support n-based indexing, and other scalar data types, such as enumerations or characters, may also be used as array indexes.

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A ball rolling down a hill for 9 seconds accelerates from 3 m/s to 34.5 m/s

Answers

Acceleration of a ball rolling down hill, a = 3.5 m/s².

Equation :

Given in details,

Initial velocity of ball,

u = 3 m/s

Final velocity of ball,

v = 34.5 m/s

Time taken for changing velocity,

t = 9 s

To find acceleration of ball,

a =?

Using formula,

First equation of motion

 v = u + a t

where,

v is final velocity,

u is initial velocity,

t is time taken

a is acceleration

Using this first equation of motion,

v = u + a t

34.5 = 3 + a × 9

34.5 - 3 = 9 a

31.5 = 9 a

a = 31.5 / 9

a = 3.5 m/s²

What is motion first law?

Newton's first law: the law of inertia

According to Newton's first law, if a body is at rest or moving in a straight line at a constant speed, it will continue to move at that speed or remain at rest until acted upon by a force.

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if a bicyclist, with an initial speed of zero, steadily gained speed until reaching a final speed of 26m/s, how far would she travel during this race?

Answers

Answer: V^2=u^2 + 2* a* s

V is final velocity.

u is initial velocity.

a is acceleration.

s is distance.

0^2=5^2 + 2 *a*3

My cat can eat 125 grams of food each day. How many kilograms is this?

Answers

0.125 kg

Explanation:

0.125 kg will be your answer for this question.

A ball rolls from x = 10 m to
x = -25 m in 2.5 seconds. What was
its average velocity?
(Units = m/s)

Answers

The average velocity of the ball is - 14 m / s if it rolls from x = 10 to x = - 25 in 2.5 seconds.

We know that,

v = Δd / t

where,

v = Average velocity

Δd = Displacement

t = Time taken

Given that,

t = 2.5 sec

Δd = - 25 - 10

Δd = - 35 m

v = - 35 / 2.5

v = - 14 m / s

Average velocity is the average value of velocity from the starting point to ending point in a given amount of time.

Therefore, the average velocity of the ball is - 14 m / s

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The acceleration due to gravity on planet X is
one-fifth that on the surface of the earth.
If it takes 3.8 s for an object to fall a certain
distance from rest on earth, how long would
it take to fall the same distance on planet X?
Answer in units of s

Answers

The time taken for the object to fall the same distance in planet X is determined as 8.5 seconds.

Time of motion of the object planet X

The time taken for the object to fall the same distance on planet X is calculated as follows;

t = √2h/g

where;

h is height of fallg is acceleration due to gravityt is time of motion

t² = 2h/g

gt² = 2h

g₁t₁² = g₂t₂²

t₂² = g₁t₁²/g₂

t₂² = (g₁ x 3.8²) / (0.2g₁)

not e one-fifth = 1/5 = 0.2

t₂² = 72.2

t₂ = √72.2

t₂ = 8.5 seconds

Thus, time taken for the object to fall the same distance in planet X is determined as 8.5 seconds.

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Which statements correctly describe the effect of distance in determining the gravitational force and the electricall
force? Check all that apply
The gravitational force has an infinite reach
The electrical force has an infinite reach
The gravitational force is inversely proportional to the distance.
The electrical force is inversely proportional to the distance.
The gravitational force is inversely proportional to the square of the distance.
The electrical
force is inversely proportional to the square of the distance.
O
O
Save and Exit

Answers

The square of the distance has an adverse relationship with the electrical force.

The square of the distance has an adverse relationship with the gravitational force.

Electrical force vs gravitational force :

The fundamental distinction between electrostatic and gravitational forces is that gravitational force is the force that draws objects to the earth based on mass. This force is conservative. While an object's electrostatic force is its force as a result of charge. Moreover, it is a conservative force.

How would you define an electrical force?

Electric force is the attractive or repulsive interaction between any two charged bodies. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so.

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Find the c flag value after each of the following codes:
(a) ldi r20,0x54
(b) ldi r23,0
(c) loi r30,0xff loi r25,0xc4 loi r16,0xff loi r18,0x05 add r20,r25 add r23,r16 add r30,rl8

Answers

A boolean variable with the value "true" or "false" is what is referred to as a "flag" variable. You can either use an integer value with zero for "false" and semi for "true" or the boolean type with true or false.

CY is the carry flag's symbol. If a carry is produced during the procedure, it will be set to 1.

The procedure's outcome would be:

54 + C4 = 01010100 + 11000100

= 100011000

however because it cannot fit into the 8-bit destination register, the top bit is lost, and the actual result is 0x000110.

As a result, we can see that a carry is produced. CY will therefore equal 1.

The registers will be updated with the hexadecimal integers.

As a result, we can observe that no carry is produced. CY will therefore equal 0.

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A 3.5-kg plastic tank that has a volume of 0.2 m3 is filled with liquid water. assuming the density of water is 1000 kg/m3, determine the weight of the combined system.

Answers

The weight of the combined system = 1,996.3 N

How is the weight of the combined system calculated?

Given,

Mass of the Plastic tank = 3.5 kg

Volume of the liquid water in the tank = 0.2 m³

Density of water = 1000 kg/m³  

Now,

We know

Density = Mass ÷ Volume

Thus,

Mass = Density × Volume

therefore,

Mass of the water in the tank = 1000 × 0.2

= 200 kg

Thus,

The mass of the combined system = 3.5 kg + 200 kg = 203.5 Kg

Also,

Weight in N = Mass × Acceleration due to gravity (g)

and,

g = 9.81 m/s²

Therefore,

The weight of the combined system = 203.5 kg × 9.81 m/s²

= 1,996.3 N

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A projectile is launched from ground level at an angle of 15 degrees above the horizontal. It lands a distance of 20 meters from the launcher. Which of the following launch angles would result in the same range if the launch speed is kept the same?

A. 60 degrees
B. 30 degrees
C. 75 degrees
D. 85 degrees

Answers

C. The launch angle that would result in the same range if the launch speed is kept the same is 75⁰.

Angle of projection

The angle of projection is calculated as follows;

R = u²sin(2θ) / g

where;

θ is the angle of projection

θ = 15⁰

sin 2θ = sin 2(15) = sin (30) = 0.5

Equivalent angle of projection

θ = 90⁰ - 15⁰ = 75⁰

sin(2θ) = sin (2 x 75⁰) = sin (150⁰) = 0.5

Thus, the launch angle that would result in the same range if the launch speed is kept the same is 75⁰.

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Which of galileo’s astronomical observations were best explained by a heliocentric model?.

Answers

Galileo’s astronomical observations  that were best explained by a heliocentric model is "The phases of Venus can only occur the way they do if Venus is orbiting the Sun".

What about the heliocentric model was accurate?

Instead of Earth, as was previously thought to be the case according to the geocentric model, the heliocentric concept puts the Sun at the core of the solar system. Our increased grasp of astronomy was built on this advancement, which brought us closer to the true nature of the solar system and the universe.

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The volume of ammonia gas at 0.920 atm of pressure is gradually decreased from 80.3 ml to 46.9 ml. what is the final pressure of ammonia if there is no change in temperature?

Answers

The final pressure of ammonia if there is no change in temperature is 1.575atm.

A given mass of gas has a pressure that is inversely proportional to its volume at constant temperature. The gas rules of Boyle are followed in this query.

The mathematical notation is as follows:

[tex]P_{1} V_{1} = P_{2} V_{2}[/tex]

Rearranging the formula so that pressure [tex]P_{2}[/tex] is the formula's subject;

[tex]P_{2} = \frac{P_{1}V_{1} }{V_{2} }[/tex]

Plugging in the values we get:

[tex]P_{2} = \frac{(0.920)(80.3)}{(46.9)}[/tex]

[tex]P_{2} = 1.575atm[/tex]

Therefore,  the final pressure of ammonia if there is no change in temperature is 1.575atm.

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A basketball player, standing near the basket to grab a rebound, jumps 74.8 cm vertically. how much time does the player spend in the top 13.7 cm of his jump?

Answers

By using uniform motion, in 0.04 second the player will spend in the top 13.7cm .

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

hmax = 74.8 cm = 0.748 m

h = 13.7 cm = 0.137 m

g = 9.8 m/s²

Find the initial speed by using hmax (vt = 0 m/s)

vt² = vo² + 2a . s

0² = vo² - 2g . hmax

2 . 9.8 . 0.748 = vo²

vo² = 14.6608

vo = 3.83 m/s

Find the vt when h is 13.7 cm

vt² = vo² + 2a . s

vt² = 3.83² - 2g . h

vt² = 3.83² - 2. 9.8 . 0.137

vt² = 11.98

vt = 3.46 m/s

Find the time taken

vt = vo + a . t

3.46 = 3.83 - g . t

9.8t = 0.37

t = 0.04 second

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At an international auto race, a race car leaves the pit after a refueling stop and accelerates uniformly to a speed of 75 m/s in 9 s to rejoin the race

Answers

The acceleration of the car after leaving the pit to reach a speed of 75 m / s in 9 s is 8.3 m / s²

a = v / t

a = Acceleration

v= Velocity

t = Time

v = 75 m / s

t = 9 s

a = 75 / 9

a = 8.3 m / s²

Acceleration is the rate of change of velocity with respect to time. It is denoted as a.

The given question is incomplete. The complete question is:

At an international auto race, a race car leaves the pit after a refueling stop and accelerates uniformly to a speed of 75 m/s in 9 s to rejoin the race. What is the race car's acceleration during this time?

Therefore, the acceleration of the car after leaving the pit is 8.3 m / s²

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What does dependent and independent variables mean in science?

Answers

Answer:

Independent variable is the variable that causes the changes in the experiment. Dependent variable is the variable that is affected by the changes.

Explanation:

005 (part 1 of 2) 10.0 points
A runner is jogging in a straight line at asteady v, 4.1 km/hr. When the runner is L= 7.1 km from the finish line, a bird begins
flying straight from the runner to the finish line at = 12.3 km/hr (3 times as fast as the runner). When the bird reaches the finish line, it turns around and flies directly back to the runner.

Answers

86.925 km

1=runner v1= 4.1km/h = 1.13m/s, here v1 and v2 is velocity

2=bird v2=12.3km/h = 3.41 m/s

bird covers 7100 m in t=7100/3.41=2082 s

at same time runner has traveled x=1.13  * 2082=2352.6

the remaining distance of 7100-2352=6865 m is traveled by runner an bird

6865=v1t+v2t

then t=6865/(1.13+3.41)=23410 s

the distance traveled by bird is

x2=7100+v2t

=7100+3.41*23410

x2=86928m = 86.925 km

Linear velocity is the measurement of a body's "pace of change of displacement in relation to time" when the body is travelling along a straight route.Velocity may be divided into two categories: linear velocity and angular velocity. The rate at which the displacement of a body travelling along a straight route changes is known as its linear velocity. Any moving item will undoubtedly have a linear velocity.

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Given a long text string t and one shorter pattern string s, find the first occurrence of s in t (if any). what is the complexity of your algorithm?

Answers

The complexity of your algorithm is O(nm).

Algorithmic complexity is a measure of how long an algorithm would take to complete given an input of size n. If an algorithm has to scale, it should compute the result within a finite and practical time bound even for large values of n. For this reason, complexity is calculated asymptotically as n approaches infinity.

Now,

Text: T

Pattern: s

Algorithm   String Matching(T,s)

n=len(T)

m=len(s)

for i = 0 to n-m

j=0

while j<m and s[j]=T[ i + j]

j=j+1

if j==m

  return i

end if

end while

return -1

end for

the complexity of your algorithm: O(nm)

reason: nested loop runs one run (n-m) times and second run m times. so it becomes (n-m)(m) = (nm-m2) = O(nm)

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URGENT : need this for tmmr

Answers

2.2cm^3

As per the statement the given measurement of different volumes

Let consider

V1 = 2.1cm^3

V2 = 2.1cm^3

V3 = 2.4cm^3

Now, we are supposed to find the mean value

mean value = submission of total number observation÷ sum of no. of observation

mean value = 2.1+2.1+2.4÷ 3

mean value = 6.6÷3

mean value= 2.2cm^3

The central tendency of data is measured by the term "mean." It is a value that, in general, may be used to express the primary value of a group of data. It is determined by adding up all of the data set's observations and dividing the result by the total number of observations.

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If 720- nm and 660- nm light passes through two slits 0.61 mm apart, how far apart are the second-order fringes for these two wavelengths on a screen 1.5 m away?

Answers

The distance between the second-order fringes for these two wavelengths is 0.3 × 10—³ m.

The wavelength of first light is,

[tex]λ _{1} = 720 \: nm = 720 \times 10 ^{ - 9} \: m[/tex]

The wavelength of the second light is,

[tex]λ _{1} = 660 \: nm = 660 \times 10 ^{ - 9} \: m[/tex]

The separation is d.

d = 0.61 mm

[tex]d = 0.61 \times 10 ^{ - 9} \: m[/tex]

The distance of the screen is D.

D = 1 m

For wavelength 1 the distance of the second fringe is,

The number of fringes is 2.

[tex]x _{n} = \frac{nλD}{d} [/tex]

[tex]x _{2} = \frac{2 \times 720 \times 10 ^{ - 9} \times 1.5}{0.61 \times 10 ^{ - 3} } [/tex]

[tex] = 3.5 \times 10 ^{ - 3} [/tex]

For wavelength 2 the distance of the second fringe is,

[tex]x ^{'} _{n} = \frac{nλD}{d} [/tex]

[tex]x ^{'} _{2} = \frac{2 \times 660 \times 10 ^{ - 9} \times 1.5}{0.61 \times 10 ^{ - 3} } [/tex]

[tex]x ^{'} _{2} = 3.2\times 10 ^{ - 3} [/tex]

The distance between the second-order fringes for these two wavelengths on a screen 1.5 m away is,

[tex]∆x = x _{2} - x ^{'} _{2} [/tex]

[tex] = (3.5 \times 10 ^{ - 3} - 3.2 \times 10 ^{ - 3} )[/tex]

[tex] = 0.3 \times 10 ^{ - 3} \: m[/tex]

Therefore, the distance between the second-order fringes for these two wavelengths is 0.3 × 10—³ m.

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What is the wavelength of light emitted when an electron relaxes from the n = 5 level to the n = 2 level?

Answers

The wavelength released in transition energy is 4.23 x 10¯⁶ m.

We need to know about transition energy to solve this problem. Electrons in a hydrogen atom can move to another level of energy. It is also called a transition. In this process, electrons will absorb or release their energy to move. The transition energy can be determined as

ΔE = E2 - E1

where ΔE is transition energy, E2 is the final state of energy and E1 is the initial state of energy.

The state energy of a hydrogen atom can be calculated by

E = -(13.6) / n² eV

E = h.c / λ

where n is the number of energy states, h is Planck constant (4.136 x 10¯¹⁵ eV/Hz), c is speed of light (3 x 10⁸ m/s) and λ is wavelength.

From the question above, we know that

n1 = 5

n2 = 2

By substituting the following parameter, we get

ΔE = E2 - E1

ΔE = -(13.6) / n2² - (-(13.6) / n1²)

ΔE = -(13.6) / 2² - (-(13.6) / 5²)

ΔE = 0.544 - 0.85

ΔE = -0.306 eV

the energy is minus because it got released.

Calculate the wavelength released

ΔE = 0.306 eV

h.c / λ = 0.306 eV

4.136 x 10¯¹⁵ . 3 x 10⁸ / λ = 0.306

λ = 4.23 x 10¯⁶ m

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The electric field 1.8 cm from a small object points toward the object with a strength of 180,000 n/c. what is the object's charge?

Answers

Charge,Q = 6.48 × [tex]10^-^9[/tex] C

How is the object's charge calculated?

It is given that,

Electric field strength, E = 180000 N/C

Distance from a small object, r = 1.8 cm = 0.018 m

Electric field at a point is given by :

[tex]E=\frac{KQ}{r^2}[/tex]

Q is the charge on an object

[tex]Q=\frac{Er^2}{k}[/tex]

Q = [180000 × [tex](0.018)^2[/tex]] ÷ 9 × [tex]10^9[/tex]

Q = 6.48 × [tex]10^-^9[/tex] C

So, the charge on the object is Q = 6.48 × [tex]10^-^9[/tex] C . Hence, this is the required solution.

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Which term best describes a copper wire?
O a conductor
O a circuit
O a magnet
O an insulator

Answers

The answer is a magnet

A popular website is interested in conducting a survey of 400 visitors to the website in such a way that 200 of them will be under age 30, 150 will be:_________
aged 30-55, and 50 will be over 55.

Answers

150 will be: stratified sample.

The partitioning of a population into smaller subgroups known as strata is a key component of the sampling technique known as stratified random sampling. In stratified random sampling, also known as stratification, the strata are created based on the shared traits or features of the members, such as wealth or level of education. Numerous uses and advantages of stratified random sampling include examining life expectancy and population demography.

Proportional or quota random sampling are other names for stratified random sampling. Researchers can produce a sample population that most accurately represents the whole population under study using stratified random sampling. Sampling is the process of drawing conclusions about a population using a small sample.

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Differentiate uniform motion and non-uniform motion with examples

Answers

Explanation:

interesting let's see it is very confusing

Answer:

See below

Explanation:

Motion as the change of position of an object with respect to time.

Uniform motion covers equal distance at an equal time interval. The velocity is constant. For example, a car traveling at 55 mph constant speed for 2 hours has uniform motion

Non-uniform motion covers unequal distance at equal time intervals. For example, in heavy traffic, a car may travel at 20mph for the first 10 minutes, then 10mph for the next 10 minutes etc. Thus velocity changes over equal time periods

I'm stuck. don't know how to solve this

Answers

Since motion under gravity only act on the vertical component of the velocity, the answer for both vertical and horizontal variables are;

a.) 9.8 m/s², 0

b.) 0, 18 m/s

c.) 21.2 m/s, 0

d.) 23 m, 39 m

e.) 2.2 s

Motion Under Gravity

Motion of any object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

From the question, the following parameters are given.

Height h = 23 mInitial velocity u = 18 m/s

a.) The vertical acceleration will be equal to acceleration due to gravity which is equal to 9.8 m/s². While the horizontal acceleration will be equal to zero.

b.) The vertical initial velocity is zero. Vertically, it will be assumed that the stone is dropped. While the given initial velocity is the horizontal initial velocity which is 18 m/s

c.) The vertical final velocity V can be calculated by using the formula

V² = U² + 2gH

V² = 0 + 2 × 9.8 × 23

V² = 450.8

V = √450.8

V = 21.23 m/s

Motion under gravity only act on the vertical component of the velocity. so, horizontal final velocity is equal to zero.

d.) Vertical distance = 23 m

While the horizontal distance = Range = ut

e.) Both the vertical and horizontal time will be the same. We can calculate the time by using the formula

h = ut + 1/2gt²

Vertically, u = 0

23 = 0 + 1/2 × 9.8 × t²

23 = 4.9t²

t² = 23/4.9

t² = 4.694

t = √4.69

t = 2.166 s

t = 2.2 s

so, the range = 18 × 2.166 = 38.997 m

Therefore, the time taken is 2.2 and the range is approximately 39 m.

Learn more about Vertical Motion here: https://brainly.com/question/17512385

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