North
A
72°
80m
115m
B
NOT TO
SCALE
The diagram shows the positions of three points A, B and C in a field.
(a)
Show that BC is 118.1 m, correct to 1 decimal place.

Answers

Answer 1

Using the cosine rule, BC = √(115² + 80² - 2(115)(80)(cos 72) ≈ 118.1 m (1 decimal place).

How to Use the Cosine Rule?

If we are given a triangle with two known sides and an included angle, the cosine rule that can be used to find the side opposite to the given angle is: a = √(b² + c² - 2bc(cos A)

We are given the following:

a = BCA = 72°b = 115 mc = 80 m

Plug in the values

BC = √(115² + 80² - 2(115)(80)(cos 72)

BC ≈ 118.1 m (1 decimal place)

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NorthA7280m115mBNOT TOSCALEThe Diagram Shows The Positions Of Three Points A, B And C In A Field.(a)Show

Related Questions

Managerial Accounting ​

Answers

Answer:

1400 units

$26,600

1700 units

$32,300

Step-by-step explanation:

yw :))

Simplify:
(x-1)+(12–7.5x)

Answers

Answer:

[tex]-6.5x+11[/tex]

Step-by-step explanation:

Expand The Brackets:

[tex]x-1+12-7.5x[/tex]

[tex]=x+(-1)+12+(-7.5x)[/tex]

Combine Like Terms:

[tex]=x+(-1)+12+(-7.5x)[/tex]

[tex]=(x+-7.5x)+(-1+12)[/tex]

Answer:

[tex]-6.5x+11[/tex]

I Hope This Helps  

PLEASEEEE PLEASEEEEEEEEE HELPPPPPPPPPP
how do i solve this equation?

Answers

Answer:

360

Step-by-step explanation:

using the definition

n [tex]P_{r}[/tex] = [tex]\frac{n!}{(n-r)!}[/tex]

where n! = n(n - 1)(n - 2)..... × 3 × 2 × 1

then

6[tex]P_{4}[/tex]

= [tex]\frac{6!}{(6-4)!}[/tex]

= [tex]\frac{6!}{2!}[/tex]

= [tex]\frac{6(5)(4)(3(2)(1)}{2(1)}[/tex] ← cancel 2(1) on numerator / denominator

=  6 × 5 × 4 × 3

= 360

Please help quick!!

Answers

Answer:

the answer will be similar, because if you divide 2, 3, 2.25 by 3 you will get the answer.

Need number 2 please!!

Answers

Answer:

A

Step-by-step explanation:

note that i = [tex]\sqrt{-1}[/tex]

given

- 1 + 2i[tex]\sqrt{3}[/tex]

= - 1 + [tex]\sqrt{2^2(-1)3}[/tex]

= - 1 + [tex]\sqrt{-12}[/tex]

the segments ab and cd are graphed on a coordinate plane. The endpoints of ab are at (9,4) and (9,20). CD is parallel to the x-axis, and one of its endpoints is at (5,8). if ab=cd and cd is entirely in the first quadrant, what is the other endpoint of cd

Answers

Answer:

21, 8

Step-by-step explanation:

The second endpoint is of the form (X, 8) since it's parallel to the x axis.

Given the congruence of the two segments, we can tell that its length is 16 units (since [tex]|4-20| = |-16|= 16[/tex])

At this point the two possible endpoints for the segment are [tex](5-16; 8)[/tex] or [tex](5+16, 8)[/tex]. The fact that the segment has to sit in the first quadrant rules out the first option (it's endpoint will be at (-11, 8) which will set most of it in the second quadrant) and we're left with (21, 8)

what is the length of the squares side?

Answers

Answer:

side ≈ 4.24= [tex]\frac{6}{\sqrt{2} }[/tex]

Step-by-step explanation:

sides a = b

[tex]6^{2} =a^{2} +a^{2}[/tex]

[tex]6^{2} =2a^{2}[/tex]

[tex]a^{2}= \frac{6^{2} }{2} =\frac{36}{2} =18[/tex]

[tex]a=\sqrt{18} =4.24=\sqrt{(9)(2)} =\frac{6}{\sqrt{2} }[/tex]

Hope this helps

According to American Airlines, flight 71098 from New York to Los Angeles is on time 88.9% of the time. Assume that we randomly select 150 flights, use the normal approximation to the binomial to do the following:

a) approximately the probability that exactly 124 flights are on time.

b) approximate the probability that between 113 and 130 flights ,inclusive, are on time.

Answers

Using the normal approximation to the binomial, it is found that the probabilities are given as follows:

a) 0.0055 = 0.55%.

b) 0.2296 = 22.96%.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with [tex]\mu = np, \sigma = \sqrt{np(1-p)}[/tex].

The parameters of the binomial distribution are given as follows:

n = 150, p = 0.889.

Hence the mean and the standard deviation of the approximation are:

[tex]\mu = E(X) = np = 150 x 0.889 = 133.35[/tex].[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{150(0.889)(0.111)} = 3.8473[/tex]

Item a:

Using continuity correction, the probability is P(123.5 < X < 124.5), which is the p-value of Z when X = 124.5 subtracted by the p-value of Z when X = 123.5, hence:

X = 124.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{124.5 - 133.35}{3.8473}[/tex]

Z = -2.3

Z = -2.3 has a p-value of 0.0107.

X = 123.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{123.5 - 133.35}{3.8473}[/tex]

Z = -2.56

Z = -2.56 has a p-value of 0.0052.

Hence the probability is 0.0107 - 0.0052 = 0.0055 = 0.55%.

Item b:


The probability is P(112.5 < X < 130.5), which is the p-value of Z when X = 130.5 subtracted by the p-value of Z when X = 112.5, hence:

X = 130.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{130.5 - 133.35}{3.8473}[/tex]

Z = -0.74

Z = -0.74 has a p-value of 0.2296.

X = 112.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{112.5 - 133.35}{3.8473}[/tex]

Z = -5.42

Z = -5.42 has a p-value of 0.

Hence the probability is 0.2296 - 0 = 0.2296 = 22.96%.

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What is the range of the function g(x) = –3sec(2x + 4) – 1?

(–∞, –2] ∪ [0, ∞)
(–∞, –4] ∪ [0, ∞)
(–∞, –4] ∪ [2, ∞)
(–∞, –5] ∪ [1, ∞)

Answers

The range of the function g(x) will be (–∞, –4] ∪ [2, ∞). Option C is correct.

What is the difference between domain and range?

The domain denotes all potential x values, while the range denotes all possible y values.

When we plot the graph of the given function we will get the maximum and the minimum value till we get the function plot. The difference in the value of those coordinates is the range of the function.

The range of the function g(x) will be (–∞, –4] ∪ [2, ∞).

Hence option C is correct.

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In 2010, the amount in Raja's account was 40 Lakhs. He debited 8000 in 2011, and in 2012, he debited 2,07,000. In 2013, he credited 1,16,000, and in 2014 he credited 12,000. How much more he has to credit to be worth what it was at at the start of 2010 ​

Answers

How much more he has to credit to be worth what it was at at the start of 2010 is: 3,657,000.

Additional credit amount

Firsts step

Total amount debited=8,000+207,000

Total amount debited=215,000

Total amount credited=116,000+12,000

Total amount credited=128,000

Second step

Additional amount to credit:

40 Lakhs is 4,000,000

Hence:

Additional amount to credit=4,000,000- (215,000+128,000)

Additional amount to credit=4,000,000-343,000

Additional amount to credit=

Therefore how much more he has to credit to be worth what it was at at the start of 2010 is: 3,657,000.

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Seismology In 1812, an earthquake of magnitude 7.9 shook New Madrid,
Missouri. Compare the amount of energy released by that earthquake to the
amount of energy released by each earthquake below.
magnitude 9.5 in Valdivia, Chile, in 1960

Answers

I think it’s 39.81. I don’t know if that was the answer to YOUR question but I’m pretty sure that’s comparing the energy

5
The recursive formula for a geometric sequence is given below. What is the third term in the sequence?
f(1) = 2
f(n) = 3f(n − 1)
-
OA. 18
OB. 54
OC. 162
OD. 12
Reset
Submit

Answers

f(1) = 2
f(2) = 3f(1) = 3(2) = 6
f(3) = 3f(2) = 3(6) = 18 (A)

[tex]\Large{ \boxed{ \tt{ \blue{A}}}}\Large{ \boxed{ \tt{ \pink{N}}}}\Large{ \boxed{ \tt{ \green{S}}}}\Large{ \boxed{ \tt{ \purple{W}}}}\Large{ \boxed{ \tt{ \red{E}}}}\Large{ \boxed{ \tt{ \pink{R}}}}[/tex]

[tex] \: \: [/tex]

A. 18

[tex] \: \: [/tex]

[tex]\Large{ \boxed{ \tt{ \blue{S}}}}\Large{ \boxed{ \tt{ \pink{O}}}}\Large{ \boxed{ \tt{ \green{L}}}}\Large{ \boxed{ \tt{ \purple{U}}}}\Large{ \boxed{ \tt{ \red{T}}}}\Large{ \boxed{ \tt{ \pink{I}}}}\Large{ \boxed{ \tt{ \blue{O}}}}\Large{ \boxed{ \tt{ \pink{N}}}}[/tex]

[tex] \: \: [/tex]

[tex] \mathtt{f(1) = 2}[/tex][tex] \tt{f(2) \: = \: 3f \: (1) \: = \: 3(2) \: = \: 6}[/tex][tex] \tt{f(3) \: = \: 3f(2) \: = \: 3(6) \: = \: 18}[/tex]

[tex]\color{pink}─────────────────────────────────────[/tex]

keep learning

A line of best fit was drawn for 16 data points. What is the maximum number
of these data points that may not actually be on the line?
OA. 14
OB. 13
O C. 15
OD. 16

Answers

The maximum number of data points that may not actually be on the line is 16. so, the correct option is D.

How to find the line of best fit?

We know that a line of best fit is basically a straight line drawn for a given data that may or may not pass through data points.

It is given that the line is drawn for 16 data points.

Hence, the line may or may not pass through all these 16 points.

Therefore, the maximum number of data points that may not actually be on the line is 16.

so, the correct option is D.

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Given any two events, E, and E₂, what does the probability P(E, U E₂) represent?

Answers

Answer:

P(E1 ∪ E2) = P(E1) + P(E2) - P(E1 ∩ E2)

Step-by-step explanation:

As we know that, if A and B are two events then

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

⇒ P(E1 ∪ E2) = P(E1) + P(E2) - P(E1 ∩ E2)

Hi can someone please help me with this geometry problem? Thanks!

Answers

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry.

What is a triangle?

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.

The triangles ΔEST and ΔEFD are similar triangles, therefore, we can write,

[tex]\dfrac{ES}{EF} = \dfrac{ET}{ED} = \dfrac{ST}{FD}[/tex]

Since S and T are midpoints of EF and ED, the lines will be divided into two equal parts. Therefore,

[tex]\dfrac{ES}{EF} = \dfrac{ET}{ED} = \dfrac{ST}{FD}= \dfrac12[/tex]

Therefore, we can write it as,

[tex]FD = 2 (ST)[/tex]

In ΔEST and ΔTDR

∠T ≅ ∠T {Vertical angles}

ET ≅ TD {T is the midpoint of ED}

∠SET ≅ ∠TDR {Alternate interior angles}

Therefore,  ΔEST ≅ ΔTDR.

Since the two triangles are equal we can write,

ST ≅ TR

Further, it can be written as,

FD = 2(ST)

FD = ST + ST

FD = ST + TR

FD = SR

Hence, FD≅SR.

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The power 3 Superscript negative 3 equals StartFraction 1 Over 27 EndFraction . Which expression is equivalent to 3 Superscript negative 3?

Answers

Applying the negative exponent, the equivalent expression  [tex]3^{-3}[/tex]  is 1/27.

What are exponents?

The exponents of a number are defined as the representation of a number that shows how many times a number is multiplied by itself.

When we have a negative exponent, we use a fraction, with the term with the exponent going to the denominator.

Hence, the equivalent expression is:

[tex]3^{-3} = \dfrac{1}{3^3} = \dfrac{1}{27}[/tex]

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Solve the equation.

6(x−1)6/7=12

Answers

Answer:

Linear Equations In One Variable =

[6(x-1)6] / 7 = 12

[(6x - 6)6] = 84

[36x - 36] = 84

36x = 84 + 36

36x = 120

x = 120/36

x = 10/3

equation solved (Answer : 10/3)

Help with this math problem

Answers

Answer:

The minimum cost of the X-ray machines is 12,197dollars.

Step-by-step explanation:

First, we check whether it’s a Quadratic Equation or not

The general form of the Quadratic equation [tex]f(x) =[/tex] [tex]ax^{2} + bx + c[/tex]

Let’s compare it with the given equation, we get

a = 1

b = -520

c = 79,79

Hence, it’s a quadratic equation.

Now, we will use the VERTEX FORMULA as we are asked to find the ‘minimum’ unit cost.

X = [tex]\frac{-b}\[2a[/tex]  =  [tex]\frac{-(-520)}\[2(1)[/tex] = [tex]260[/tex]

So , number of X-ray machines are = 260 (value of x)

To find the minimum unit cost, plug the value of x into the given equation, and we get

[tex]f(260) = (260)^{2} -520(260) + 79,797[/tex]

[tex]=12,197[/tex]

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can someone find the value of x?​

Answers

Answer:

[tex]\boxed{\sf x=12}[/tex]

Step-by-step explanation:

By applying Similar Triangles Theorem:-

[tex]\sf \cfrac{x}{6} =\cfrac{6}{3}[/tex]

We'll multiply both sides of the equation by 6, the LCM of 6,3.

[tex]\sf x=2 \times 6[/tex]

[tex]\sf x=12[/tex]

three-quarters of a pile of bricks were used for a certain project. when two thirds of the reminder had been used, 50 bricks were left. how many bricks were there in the original pile?​

Answers

Answer:

sorry I don't know the answer

quest
The chart shows how many people have signed up to go on a field trip each day. 62 students are allowed to go on the field trip. On
which day would you expect that number to be reached?
D)
10
Days People
1
26
2
30
3
34
4
38
5
42
6 46
og php?totalQuestions-10&testid-5
strand-5716&element-18789&condition-random #

Answers

Answer:

Day 5 ................

Refer to the figure to complete the following item.

Given:





If m = 60° and m = 30°, then 3 =

45
15
30

Answers

If m VB = 60°  and m BS = 30°, then m ∠3 =15°.

What is tangent?

A tangent is a line passing by touching the perimeter of the circle, perpendicular to the line joining the center and touch point.

Given, PB tangents PV, PU secants

If m VB = 60°  and m BS = 30°, then m ∠3 =

The measurement of the external angles is the semi difference of the arcs it consists.

∠3 = 1/2 (60 - 30)

∠3 = 15°

Thus, If m VB = 60°  and m BS = 30°, then m ∠3 =15°.

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❗️URGENT❗️
Chase has won 80% of the 30 football video games he has played with his brother, Jacob. If Chase and Jacob continue to play the video game, how many more games in a row goes Chase have to win to achieve an 85% win percentage?

Answers

Answer:

10

Step-by-step explanation:

24/30 = 0.8

24+x/30+x =0.85

10=x

If you want more clarification just ask

Total games Chase has to win in a row to achieve an 85% win percentage would be 10.

We can write the total number game won by Chase as -

w = 80% of 30

w = 80/100 x 30

w = 4/5 x 30

w = 24

Assume that he wins {x} games after winning 24 games to achieve 85% win percentage. Now, we can write that out of (30 + x) number of games played, Chase won (24 + x) games to achieve 85% win percentage. So, we can write that -

(24 + x)/(30 + x) = 85/100

(24 + x)/(30 + x) = 0.85

(24 + x) = 0.85(30 + x)

24 + x = 25.5 + 0.85x

0.15x = 1.5

x = 10

Total games Chase has to win in a row to achieve an 85% win percentage would be 10.

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Which absolute value functions will be narrower than the parent function, f(x) = |x|? Check all that apply.

f(x) = |x|
f(x) = |x – 2|
f(x) = |x| + 3
f(x) = 2.9|x|
f(x) = 1.2|x + 8|
f(x) = 0.7|x| – 3.2

Answers

The correct answer is option 4 which is f(x) = 2.9|x| is narrower than the parent function f(x) = |x|

What is a function?

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

Given parent function is f(x)=|x|

Now we have to find which function from given choices will be narrower than the parent function.

Notice that adding or subtracting some number from the parent function only shifts the graph up, down, and left of the right side.

But that will not make the function narrower or broader.

So f(x) = |x – 2| and f(x) = |x| + 3, can't be the answer.

Multiplying by some positive real number which is more than 1, makes the function narrower.

Only f(x) = 2.9|x| from remaining choices fits that case.

Hence correct answer is option 4 which is f(x) = 2.9|x| is narrower than the parent function f(x) = |x|

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Answer:

D,E

Step-by-step explanation:

Match the scatter plot with its description
weak and positive
moderate and negative
strong and negative
strong and positive
weak and negative
moderate and positive

Answers

I would put in,
1.Moderate and positive
2.Moderate and negative
3.Weak and positive
4.Strong and negative

Which of the following best describes the set of complex numbers?
OA. The set of all numbers of the form a+bi, where a and bare any
real numbers and i equals -1
B. The set of all numbers of the form abi, where a and bare any real
numbers and i equals 1
C. The set of all numbers of the form a+bi, where a and b are any
real numbers and i equals √-1
OD. The set of all numbers of the form abi, where a and b are any real
numbers and / equals -1

Answers

Answer:

C

Step-by-step explanation:

The correct statement is option C.

What is complex number?

A real number and an imaginary number are effectively combined to create a complex number. The complex number is written as a+ib, where a and ib are real and imaginary numbers, respectively. Additionally, i = √-1 and both a and b are real numbers.

Since we know that

Complex number is of the form a+ib

Where,

a is real number belongs to real axis

And b is also a real number belongs to imaginary axis.

And the value of i = √-1

Thus,

The set of all numbers of the form a+bi, where a and b are any

real numbers and i equals √-1 is the correct statement.

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Somebody please assist me here

Answers

The base case of [tex]n=1[/tex] is trivially true, since

[tex]\displaystyle P\left(\bigcup_{i=1}^1 E_i\right) = P(E_1) = \sum_{i=1}^1 P(E_i)[/tex]

but I think the case of [tex]n=2[/tex] may be a bit more convincing in this role. We have by the inclusion/exclusion principle

[tex]\displaystyle P\left(\bigcup_{i=1}^2 E_i\right) = P(E_1 \cup E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) = P(E_1) + P(E_2) - P(E_1 \cap E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) \le P(E_1) + P(E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) \le \sum_{i=1}^2 P(E_i)[/tex]

with equality if [tex]E_1\cap E_2=\emptyset[/tex].

Now assume the case of [tex]n=k[/tex] is true, that

[tex]\displaystyle P\left(\bigcup_{i=1}^k E_i\right) \le \sum_{i=1}^k P(E_i)[/tex]

We want to use this to prove the claim for [tex]n=k+1[/tex], that

[tex]\displaystyle P\left(\bigcup_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^{k+1} P(E_i)[/tex]

The I/EP tells us

[tex]\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cup E_{k+1}\right) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) - P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cap E_{k+1}\right)[/tex]

and by the same argument as in the [tex]n=2[/tex] case, this leads to

[tex]\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) - P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cap E_{k+1}\right) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1})[/tex]

By the induction hypothesis, we have an upper bound for the probability of the union of the [tex]E_1[/tex] through [tex]E_k[/tex]. The result follows.

[tex]\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^k P(E_i) + P(E_{k+1}) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^{k+1} P(E_i)[/tex]

which equation has the solution x=6

Answers

Answer:

need more info

Step-by-step explanation:

what I can tell you is that when you change all the x's in the equation to 6s, both sides of the equation will equal eachother.

easy:
Clara buy: 300 apples, 74 potato, 15 eggs e 2 phone.
how many things did he buy in all?
Hard:
There are 92 boys in a school, the girl 100.How many more girl are there than boys?​

Answers

Answer:

easy = 391 items

hard = there are 8 more girls than there are boys

1)391
2)8

Those are the answers :)

If f(x)=x+2 and g(x)=x2+1 find:a. f(g(x)) b. g(f(x))

Answers

Answer:

Step-by-step explanation:

Answer:

x² + 3 and x² + 4x + 5

Step-by-step explanation:

(a)

to find f(g(x)) substitute x = g(x) into f(x)

f(g(x))

= f(x² + 1)

= x² + 1 + 2

= x² + 3

(b)

to find g(f(x)) substitute x = f(x) into g(x)

g(f(x))

= g(x + 2)

= (x + 2)² + 1 ← expand factor using FOIL

= x² + 4x + 4 + 1

= x² + 4x + 5

Other Questions
In not more than 350 words, write an essay describing the sunday market in lagos ------is one of two water masses that ate part of the thermohaline circulation . Nuestros padres nos mucho CON PROCESOS POR FAVOR Mr. Fitzgerald is selling his home to permanently move into a retirement facility near his daughter in a neighboring state before the annual election period. He has a stand-alone prescription drug plan and has learned it is not available where he is moving. He doesnt know what he should do. What can you tell him?. How do I graph the inequality? I hate civics In the case of plessy v. Ferguson, the Supreme court focused it's decision on the interpretation of the world _____. Estimate the value of0.581 -0.246 why might native americans be willing to serve in the militaryA) to show patriotismB) to make economic gainsC) to be with other tribesD) to fight as warriorsE) to become famous PLS I REALLY NEED HELP I NEED TO PASS THIS ASAP 5 kilograms of coffee are going to be shared equally among 44 people.About how many kilograms of coffee does each person get?Choose 1 answer:(Choice A)ABetween 0 and 1 kilograms(Choice B)BBetween 1 and 2 kilograms(Choice C)CBetween 2 and 3 kilograms(Choice D)DBetween 3 and 4 kilograms Below are works-cited entries for a book in print with more than two authors. Select the one that is completely correct.Entry A:Mauer, Shelley and others. "Distance Learning." Bloomsbury, 2012.Entry B:Mauer, Shelley, et. al. Distance Learning. Bloomsbury 2012.Entry C:Mauer, Shelley, et al. Distance Learning. Bloomsbury, 2012.Entry D:Mauer, Shelley et al. Distance Learning, Bloomsbury, 2012.Entry AEntry BEntry CEntry D Monomal by a DinormalWhat is the product of x(x + 1)?O 2x+x0x2+2x022 +1O x + xwill give brainliest An Exterior Insulation Finish System (EIFS) shall terminate a minimum ___________ inches above the finished ground level. Please help me answer question 6/11 A basketball team scored a total of 97 points in a basketball game. They made a total of 42 two-point and three-point baskets. How many two-point baskets did they make? How many three-point baskets did they make? Let x= the number of two-point baskets Let y= the number of three-point baskets Equation for total number of baskets _____________________ Which type of organization has been important to Chinas economic development?sole proprietorshipsmultinational corporationsinternational aid organizationsopposition political parties Which excerpt from "Amigo Brothers is part of the storys rising action?The fight had created great interest in the neighborhood. Antonio and Felix were well liked and respected. Each had his own loyal following. As the two climbed into the ring, the crowd exploded with a roar. Antonio and Felix both bowed gracefully and then raised their arms in acknowledgement.The bell sounded over and over again. Felix and Antonio were past hearing. Their blows continued to pound on each other like hailstones.Finally the referee and the two trainers pried Felix and Antonio apart. Cold water was poured over them to bring them back to their senses. What were the results of the French and Indian War. Write the equation of the line in slope intercept form Slope=-4 Point=(2,-4)