We would have to search at least 5,000,000,000 (5 billion) stars before we would expect to hear a signal.
To find out the number of stars that we will need to search to find a signal, we need to use the following formula:
total of stars/civilizations500,000,000,000 (500 billion) stars / 100 civilization = 5,000,000,000 (5 billion)
This shows it is expected to find a civilization every 5 billion stars, and therefore it is necessary to search at least 5 billion stars before hearing a signal from any civilization.
Note: This question is incomplete; here is the complete question.
On average, how many stars would we have to search before we would expect to hear a signal? Assume there are 500 billion stars in the galaxy.
Assuming 100 civilizations existed.
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A pail of water of mass 2000 gm is rotated in a vertical circle of radius 1.00 m. What is the pail’s minimum speed at the top of the circle if no water is to spill out and the tension exerted by the string is 25 N?
The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.
The given parameters:
Mass of the water, m = 2000 g = 2 kgRadius of the circle, r = 1 mTension on the string, T = 25 NThe net force on the pail of water at the top of the vertical circle is calculated as follows;
[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]
Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.
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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s
We are given;
Mass of the pail of water; m = 2000 g = 2kg
Radius of the circle; r = 1 m
Tension exerted by string; T = 25 N
To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;
W - T = ma
Where;
W is weight = mg
T is tension on the string
Now, in circular motion, we know that;
Acceleration is; a = v²/r
Thus;
mg - T = m(v²/r)
Making v the subject of the formula gives us;
v = √[(r(T + mg)/m)
Plugging in the relevant values gives;
v = √[(1(25 + (2 * 9.8))/2)
v = 4.722 m/s
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Preston goes on a camel safari. There, he travels 5 km north, then 3 km east.
7777Answer:
Explanation:
The force involved in falling of an apple from a tree is known as? (a) Magnetic force (b) electrostatic force (c) Contact force (d) gravitational force
Answer:
it is known as gravitational force
Answer:
Gravitational force.
Explanation:
Gravitational force is the force that allows objects to drop which is how the apple dropped.
A child on a spinning ride at a playground has a centripetal acceleration of 0. 80 m/s2. The child completes a full circle every 4. 2 s. How far from the center of the ride is the child? 0. 068 m 0. 085 m 0. 27 m 0. 36 m.
The distance of the child from the center of the ride is 0.28 m.
The given parameters;
Centripetal acceleration of the child, a = 0.8 m/s²Number of revolution, = 1 rev per 4.2 sThe angular speed of the child is calculated as follows;
[tex]\omega = \frac{1 \ rev}{4.2 \ s} \times \frac{2 \pi \ rad}{1 \ rev} \\\\\omega = 1.5 \ rad/s[/tex]
The radius of the circle is calculated as follows;
[tex]a_c = \omega ^2 r\\\\r = \frac{a_c }{\omega ^2} \\\\r = \frac{0.8}{1.5^2} \\\\r = 0.28 \ m[/tex]
Thus, the distance of the child from the center of the ride is 0.28 m.
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An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?
Answer:
[tex]88.3ms {}^{ - 2} [/tex]
or 88.3m/s^2
Explanation:
Using suvat where we list everything that we are given
s=49m
u=0m/s
v=93m/s
a=?
t=we are not given this value, so we don't use
using a formula that doesn't involve time:
[tex]v {}^{2} = u {}^{2} + 2as[/tex]
rearranging to find acceleration by subtracting u^2 on both sides
[tex]v {}^{2} - u {}^{2} = 2as[/tex]
then dividing 2s on both sides
[tex] \frac{v {}^{2} - u {}^{2} }{2s} = a[/tex]
[tex] \frac{(93) {}^{2} - (0) {}^{2} }{2 \times(49) } = 88.3ms {}^{ - 2} [/tex]
so the acceleration is 88.3ms^-2 (1dp)
4) What is the kinetic energy of a 5 kg object moving ot a velocity of 25 m/s?
Help me please I’m confused
What is the control group
A control group in a scientific experiment is a group separated from the rest of the experiment, where the independent variable being tested cannot influence the results. This isolates the independent variable 's effects on the experiment and can help rule out alternative explanations of the experimental results.
Answer:
members of a control group receive a standard treatment, a placebo, or no treatment at all.
Explanation:
AB
ca
The trough of a transverse wave is BEST shown by choice
es - )
8
8
Answer:
bro the way you worded it makes no since
What do scientists theorize about the origins of the Moon? Choose the most accepted explanation.
Answer:
What is most widely accepted today is a the giant-impact theory. It proposes that the Moon formed during a collision between the Earth and another small planet, about the size of Mars. The debris from this impact collected in an orbit around Earth to form the Moon.
A 40 N block is resting on a rough inclined plane. The static friction between the block and the plane is ____ N.
The static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].
The given parameters:
Weight of the block, W = 40 NThe normal reaction on the rough surface due to weight of the block is calculated as follows;
[tex]F_n = 40 \ N[/tex]
The static friction between the block and the plane is calculated as follows;
[tex]F_s = \mu_s F_n[/tex]
where;
[tex]\mu_s[/tex] is coefficient of static frictionThus, the static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].
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What is the relationship between momentum and speed?
Answer:
Momentum is directly proportional to the object's mass and also its velocity.
Explanation:
Thus the greater an object's mass or the greater its velocity, the greater its momentum. Momentum p is a vector having the same direction as the velocity v.
Calculate the force of gravity of a 25kg block resting on the earth (M=5.97x10^24kg). The radius of the earth is 6.38x10^6m.
I already know...
[tex](6.67*10^{-11})(25)(5.97*10^{24} )/(6.38*10^6)^2[/tex]
But I don't understand what steps I have to take to solve that equation
From Newton's law of gravity, the force of gravity is 245 Newtons
To calculate the force of gravity of a 25kg block resting on the earth of mass M = 5.97x10^24kg with the radius r of the earth is 6.38x10^6m, let us first list out all the given parameters
Mass m = 25 kg
Mass of the earth M = 5.97x10^24kg
Radius r = 6.38x10^6m
Force F = ?
The formula to calculate the force of gravity is
F = (GMm)/[tex]r^{2}[/tex]
Where G = 6.67 x [tex]10^{-11}[/tex]
Substitute all the parameters
F = (6.67 x [tex]10^{-11}[/tex] x 5.97x10^24 x 25) / (6.38x10^6)^2
F = 9.9 x [tex]10^{15}[/tex] / 4.07 x [tex]10^{13}[/tex]
F = 244.56 N
F = 245 Newtons (approximately)
Therefore, the force of gravity is 245 Newtons
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What is the surface temperature of Sirius B in Kelvins?
Answer: The surface temperature of Sirius B is 25,200 Kelvins(K).
Explanation: You would think Sirius would have a surface temperature of 9,940 Fahrenheit. That is somewhat correct, but Sirius is a binary star consisting of a main-sequence star of spectral type A0 or A1, termed Sirius A, and a faint white dwarf companion of spectral type DA2, termed Sirius B. Sirius, Sirius A, and Sirius B, are all different stars. Sirius A has a temperature of 9,940 Kelvins, but Sirius B has a temperature of 25,200 Kelvins(K).
That would be 9,940 kelvins (K)
Hope it helps! :D
A sled is launched off a cliff 39 m high and lands 74 m away from the base of the cliff. How fast was the sled launched?
The sled was launched with a velocity of 26.24 m/s
We'll begin by calculating the the time taken for the sled to land
Height (h) = 39 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?[tex]t = \sqrt{ \frac{2h}{g}} \\ \\t = \sqrt{ \frac{2 \times 39}{9.8}} \\ \\ t = 2.82 \: s \\ \\ [/tex]
Finally, we shall determine the velocity.Time (t) = 2.82 s
Horizontal distance (s) = 74 m
Horizontal velocity (u) =?[tex]u = \frac{s}{t} \\ \\ u= \frac{74}{2.82} \\ \\ u = 26.24 \: m/s \\ \\ [/tex]
Therefore, the sled was launched with a velocity of 26.24 m/s
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Which of the following is true for gravitational force?
Group of answer choices
Decreases with decrease in distance
Increases with increase in distance
Decreases with increase in mass
Increases with increase in mass
Answer:
The gravitational force b) Increases with increase in mass.
Explanation:
The gravitational force between two objects is given by
F=G\frac{m_1 m_2}{r^2}F=Gr2m1m2
where
G is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the objects
From the equation, we notice that:
- The force is proportional to the masses, m1 and m2: so, if the masses increase, the force will increase, and if the masses decrease, the force will decrease
- The force is inversely proportional to the distance between the masses, r: so, if the distance increases, the force will decreases, and if the distance decreases , the force will increases
Therefore, the correct options is only:
Increases with increase in mass
Answer: The answer is b increases in increase of mass because the heavier the object is the more gravitional pull it will have.
Explanation: Which of the following is true for gravitational force?
Group of answer choices
Decreases with decrease in distance
Increases with increase in distance
Decreases with increase in mass
Increases with increase in mass
Miguel, a single teacher, earns $1,500 every two weeks (biweekly). He claims two allowances. What is his federal income tax withholding for each biweekly paycheck?
The federal income tax withholding for each biweekly paycheck for the single teacher is $259.9.
The given parameters:
Biweekly amount earned by the single teacher, = $1,500
The federal tax rate for single workers is given as;
amount between $436 and $1,506 = $34.9 plus 15%
The federal income tax withholding for each biweekly paycheck for the single teacher is calculated as follows;
income tax withholding = $34.9 + 0.15($1,500)
income tax withholding = $34.9 + $225
income tax withholding = $259.9
Thus, the federal income tax withholding for each biweekly paycheck for the single teacher is $259.9.
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True or false? Gas pressure is caused by molecules in a gas colliding with the walls of their container.
Answer:True
The number of molecules hitting the unit surface per unit time increasethe gas pressure increases.
Describe the water cycle. Be sure to include the following terms in your response: evaporation, condensation, and precipitation.your respone:
Evaporation, or turning liquid to a gas, is first. Then it goes into the atmosphere and codensates, or turns back to a liquid, these water droplets form into clouds and come down as precipitation, rain, sleet, snow etc. Then the water cycle starts again
pls help me, its just fill in the blank
1. Frequency
2. Reflected
3. Absorbed
4. Black
Which data set has the largest range?
O A. 1, 5, 2, 4, 3, 5
O B. 5, 6, 4, 5, 6, 4
O C. 8, 9, 1, 2, 3, 4
O D. 3, 9, 5, 7, 3, 6
Answer:
D 3, 9, 5, 7, 3, 6
Explanation:
range is the difference between the highest and the lowest value and 9 is the highest while 3 is the lowest, if u subtract them u will get 6. while for the first u will get 4 and the second u will get 2. so the answer is D
Please I need help with this ❤️ ?
Answer:
Compound 'A' C5H12 does not react with phenyl hydrazine. Oxidation of 'A' with K2Cr2o7,/H" gives B' (c5H10o). Compound 'B' reacts with phenyl hydrazine but does not give Tollen's test. The
If an atom has two protons and three electrons, then the atom is-?
A. positively charged.
B. negatively charged.
C. radioactive.
D. neutral.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Imagine that you are going to visit your friend. Before you get there, you decide to stop at the variety store. If you walk 200 m (N) from your home to the store, and then travel 600 m [S] to your friend's house, what is your total displacement?
Answer:
400m
Explanation:
Brainliest? :))
Let your initial displacement from your home to the store be
Dd
>
1 and your displacement from the store to your friend’s house
be Dd
>
2.
Given: Dd
>
1 = 200 m [N]; Dd
>
2 = 600 m [S]
Required: Dd
>
T
Analysis: Dd
>
T 5 Dd
>
1 1 Dd
>
2
Solution: Figure 6 shows the given vectors, with the tip of Dd
>
1
joined to the tail of Dd
>
2. The resultant vector Dd
>
T is drawn in red,
from the tail of Dd
>
1 to the tip of Dd
>
2. The direction of Dd
>
T is [S].
Dd
>
T measures 4 cm in length in Figure 6, so using the scale of
1 cm : 100 m, the actual magnitude of Dd
>
T is 400 m.
Statement: Relative to your starting point at your home, your
total displacement is 400 m [S].
how does the function of the parts of the system contribute to its function as a whole
plsss help i need it rn i’ll give brainliest
give answer or fight me
Answer:
translucent
Explanation:
Hope this helps! Pls give brainliest! Also, please sub to Kgirl633 on yt.
please help asap!!!!!!!!!!!
Can we get less ads please i don’t like this
Give 4 facts about the alkali metals
Answer:
there very old
Explanation:
What is the smallest value of the force F such that the 8.0 kg block will not slide down the wall? The coefficient of static friction between the block and the wall is 0.4.
Select one:
a. 10N
b. 100N
c. 200N
d. 98N
The smallest value of the force that will make the block not to slide down is 10 N.
We'll begin by calculating the normal reaction. This can be obtained as follow:
Mass (m) = 8 KgAcceleration due to gravity (g) = 10 m/s²Normal reaction (N) =?N = mg
N = 8 × 10
N = 80 N
Finally, we shall determine the frictional force.
Coefficient of friction (μ) = 0.4Normal reaction (N) = 80 NFrictional Force (F) =?F = μN
F = 0.4 × 80
F = 32 N
Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the block not to slide down.
From the options given above, only option A has a force that is lesser than the frictional force.
Therefore, the correct answer to the question is Option A. 10 N
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PLEASE HELP!! WILL GIVE BRAINLIEST IF YOU SHOW WORK. ITS DUE SOON :(
If the radius of the CD below is 6.0 cm and the angular velocity is 5.0 rad/s, what is its angular displacement in 2.0 s? What is it's Linear displacement on the edge in 2.0 s? Please show work :(
Answer:
theta = ω t = 5.0 / sec * 2 s = 10 rad
S = R theta = 6 cm * 10 rad = 60 cm
The angular displacement of CD if the radius of the CD below is 6.0 cm and the angular velocity is 5.0 rad/s, is 10 rad, and the linear displacement is 60 cm.
What is velocity?When anything is moving, its velocity tells us how quickly that something's location is changing from a certain vantage point and as measured by a particular unit of time.
If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.
Given:
The radius of the CD, r = 6 cm,
The angular velocity, v = 5 rad / sec
The time, t = 2 sec,
Calculate the angular displacement by the formula given below,
[tex]v = s / t[/tex]
5 = s / 2
s = 10 rad,
Calculate the linear displacement by the formula given below,
Linear displacement = [tex]r\ s[/tex]
Linear displacement = 6 × 10
Linear displacement = 60 cm
Therefore, the angular displacement of CD if the radius of the CD below is 6.0 cm and the angular velocity is 5.0 rad/s, is 10 rad, and the linear displacement is 60 cm.
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