If a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .
In this question Equation of Motion under gravity can be used :
v ² - u ² = 2 g h ............. Eq. 1
Here ,
u = 13 . 2 m / s
v = 0 m / s
g = - 9.8 m / s ² ( -ve as motion is against the gravity )
Now , we can use the values of u , v and g in Eq 1 .
v ² - u ² = 2 g h
0² - ( 13.2 ) ² = 2 x ( - 9.8 ) x h
0 - 174.24 = - 19.6 x h
- 174.24 = - 19.6 x h
h = 8.89 m
Hence , if a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .
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A driver travels +2170 m in 35.0
S. If the driver's initial velocity is +62.0 m/s, what is her acceleration?
HELP PLEASE
The acceleration of driver with given values is - 1.771 m/s².
Equation :To know acceleration used formula is the rate of change of the velocity of an object with respect to time that is,
a = dv / dt
Where,
dv is the small change in velocity
dt is change in time of an object
Given,
The distance traveled by the driver is +2170 m
The time taken by the driver is 35. 0 s
The initial velocity of driver is + 62.0 m/s
Therefore , to get the acceleration of the driver with the equation of motion
v = u + at
Here v is the final velocity which is taken zero
Then by putting the values in the above equation,
0 = (+62. o m/s) + (a) 35.0s
a = - (+62. o m/s) / ( 35.0s)
a = - 1.771 m/s²
The negative sign of acceleration shows that, the driver is slowing then acceleration is in the opposite as the velocity.
So, the acceleration
a = -1.771 m/s².
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Suppose you landed on an unknown planet whose mass is 10x that of the Earth and whose radius is 3x that of the Earth. How much would you weigh on this new planet?
Give your answer in what fraction or multiple of your earthly weight.
Mass on the planet would be 10/3 times the mass on Earth weigh on this new planet.
How do you define mass?A quantitative measure of the fundamental characteristic of all matter, inertia. In essence, it's the resistance of a mass of matter to changing its direction or speed in reaction to the force applied to it. The much more weight a body has, the less change an applied force produces.
Briefing:Let the mass of Earth = Me
Let the radius of Earth = Re
Mass of the planet, Mp = 10Me
Radius of the planet, Rp = 3Re
Weight on other planet, W = ?
Weight on planets is determined by the gravitational force
Gravitational force, F = GMm/r²
where, G = gravitational constant
M = Mass of the planet
m = our mass
r = radius of the planet
Gravitational force on Earth:
F = G X Me X ma/ Re².....eq (1) (ma = mass on earth)
Gravitational force on planet :
F = G X 10Me X mₓ/ (3Re)²....eq (2) (mx = mass on other planet)
Dividing both the equations, we get
mx = 10/3ma
Therefore, mass on the planet would be 10/3 times the mass on Earth.
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Consider the case of an object moving with
constant acceleration a along a straight line.
If we plot v(t) versus t, we find that v(t) plots
as a straight line with some slope.
What is the physical meaning of that slope?
The straight line in the velocity versus time graph has a physical significance as it depicts constant acceleration of the motion.
What is acceleration?Acceleration is a physical quantity which is defined as the change of velocity per unit time it is a vector quantity and therefore can be both positive and negative.
What is velocity versus time graph?Velocity versus time graph is the depiction of emotion in which the y-axis represents the velocity of the motion and the x-axis represents the time the graph can either be a positive state line or a curve depending on the acceleration of the motion.
According to the question the velocity versus time graph in our case is a straight line.
A straight line in a velocity versus time graph means that motion has a constant acceleration.
The following conclusion can also be reached from the use of differential calculus as we differentiate velocity with respect to time we get a new physical quantity that is known as acceleration.
On differentiating velocity with respect to time we will get a new value that will represent the change in velocity per unit time and since from the definition of acceleration we know that acceleration is change in velocity per unit time therefore we can conclude that the straight line in the velocity time graph depicts constant acceleration.
Therefore, The straight line in the velocity versus time graph has a physical significance as it depicts constant acceleration of the motion.
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You are traveling on an airplane. The velocity of the plane with respect to the air is 120 m/s due east. The velocity of the air with respect to the ground is 43 m/s at an angle of 30° west of due north.
1) What is the speed of the plane with respect to the ground?
2) What is the heading of the plane with respect to the ground? (Let 0° represent due north, 90° represents due east).
3) How far east will the plane travel in 1 hour?
Answer:
VPA
Explanation:
What is the magnitude of the resultant of a 61m north and 21m south vector?
Answer:
1281
Explanation:
what is the magnitude of the resultant of a 61m north and 21m south vector
A car with an initial speed of 22.1 km/h accelerates at a uniform rate of 0.84 m/s2 for 4.4 s. Find the final speed of the car. Answer in units of m/s. Find the displacement of the car after that time. Answer in units of km.
(Desperately need help with Part 2)
Answer:
Final speed of car = 9.834 m/s
Displacement = 0.035 km
Explanation:
Part 1
Final velocity, v of an object moving with an acceleration a m/s² for t seconds and an initial velocity u m/s is given by the formula
v = u + at m/s
[tex]\textrm{Initial velocity } u = 22.1 km/h\\\\\textrm{Convert this to m/s:}\\\\\textrm{1 km/h = 1000m/3600 s}\\\\ 22.1 km/h = 22.1 x 1000/3600 = 6.139 m/s\\\\\boxed{\textrm{Final velocity } v = u + at = 6.138 + 0.84 x 4.4 = 9.834 m/s}[/tex]
Displacement s in m for a constant acceleration of a m/s² for a time t seconds is given by the formula:
[tex]x = ut+\dfrac{1}{2}at^2[/tex]
where u is initial velocity
Plugging in the values we get
[tex]s = 6.139\cdot 4.4 + \dfrac{1}{2}\cdot0.84\cdot (4.4)^2 = 35.143 \;\mathrm {meters}[/tex]
35.143 meters = 35.143/1000 = 0.035 km
Answer:
1) 9.83 m/s (2 d.p.)
2) 0.04 km (2 d.p.)
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Part 1Given:
u = 22.1 km/ha = 0.84 m/s²t = 4.4 sConvert km/h into m/s by dividing by 3.6:
[tex]\implies \sf 22.1\;km/h=\dfrac{22.1}{3.6}\;m/s[/tex]
Substitute the given values into the formula and solve for v:
[tex]\begin{aligned}v&=u+at\\\implies v & = \dfrac{22.1}{3.6}+0.84(4.4)\\v & = 6.1388...+3.696\\v & = 9.834888...\\v & = 9.83 \sf \;m/s\;(2\:d.p.)\end{aligned}[/tex]
Therefore, the final speed of the car was 9.83 m/s (2 d.p.).
Part 2Substitute the given values into the formula and solve for s, remembering to use the initial velocity in m/s:
[tex]\begin{aligned}s & = ut+\dfrac{1}{2}at^2\\\implies s &=\dfrac{22.1}{3.6}(4.4)+\dfrac{1}{2}(0.84)(4.4)^2\\s &=27.0111...+8.1312\\s &=35.1423111...\sf m\end{aligned}[/tex]
Convert meters into kilometers by dividing by 1000:
[tex]\implies \dfrac{35.1423111...}{1000}=0.0351423111...=0.04 \sf \; km\;(2\:d.p.)[/tex]
Therefore, the displacement of the car after 4.4 s was 0.04 km (2 d.p.).
launched at ground level with an initial speed of 41 m/s, at an angle of 29° above the horizontal. It strikes a target above the ground 2.3 seconds
What is the vertical distance, in meters, from where the projectile was launched to where it hits the target?
The horizontal distance is 82.455m and vertical distance is 19.734m
Let us first find the x and y components of velocity
The velocity is given to be 41m/s
the angle of projectile is given to be 29 degree
The x component of velocity = Vx =v cosα =41 x 0.8746 =35.85 m/s
The y component of velocity= Vy= v sinα=41 x 0.484 =19.85 m/s
The horizontal displacement x= Vxt = 35.85 x 2.3 =82.455 m
To solve for vertical distance y = Vyt+1.2at^2
y = 19.85 x 2.3 + 1/2 x -9.8 m/s^2 x 2.3
= 19.734m
Hence, the horizontal distance is 82.455m and vertical distance is 19.734m
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An Alaskan rescue plane traveling 45 m/s
drops a package of emergency rations from
a height of 110 m to a stranded party of
explorers.
margolalaraq
The acceleration of gravity is 9.8 m/s².
Where does the package strike the ground
relative to the point directly below where it
was released?
Answer in units of m.
The package strike the ground relative to the point directly below it was released at 213.3m.
Equation:Given values,
Velocity of plane 45 m/s
Acceleration due to gravity 9.8 m/s²
horizontal component of plane velocity is
ux = 45 m/s
Vertical component is zero
In the same way
ay = - 9.8 m/s²
ax = .0 m/s^2
Motion in y direction = -110 m
From equation of motion time of flight is
d = u x t + 1/2 at²
where,
d is distance
u is velocity initial
a is acceleration
t is time
So, putting values
-110 = 0 + 1/2 (-9.8)t²
-110 = -4.9t²
t² = 110 / -4.9
t² = 22.45
t = √22.45
t = 4.74
Motion in x direction,
d = u x t + 1/2 at²
d = ( 45 x 4.74) + 1/2 (0) 4.74²
d = 213.3 + 0
d = 213.3m
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The thermal energy that causes the ice to melt is transferred from the lemonade as it cools. The loss of this thermal energy causes the temperature of the 300 g of the lemonade to fall by 19 °C. Calculate the specific heat capacity of the lemonade.
According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.
The formula for the specific heat capacity (C) = Q/ m × ΔT
Q is energy added and the value, which is 334J
m is the mass of the lemonade, which is 300g = 0.3 kg
Δ T is the change in temperature, which is 19°C =(273+19)= 292 K
So, C = 334/ 0.3 × 292
= 3.81 J/kg/k
So the specific heat capacity of the lemonade is 3.81 J/kg/k.
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In 1954 the English runner Roger Bannister broke the four-minute barrier for the mile with a time of 3:59.4 s (3 min and 59.4 s). In 1999 the Moroccan runner Hicham el-Guerrouj set a record of 3:43.13 s for the mile. If these two runners had run in the same race, each running the entire race at the average speed that earned him a place in the record books, el-Guerrouj would have won. By how many meters?
Answer:
Bannister = 3:59.4 sec = 239.4 sec
Guerruoj = 3:43.13 = 223.13 sec
1 mi = 5280 ft
G = 5280 / 223.13 = 23.66 ft/sec
B = 5280 / 239.4 = 22.06 ft/sec
In 223.13 sec B runs 223.13 * 22.06 = 4922 ft
G Wins by 358 ft = 119.3 yds = 109.1 meters
An object is launched across a room. How can a student determine the average horizontal velocity of the object using a meter stick and a calculator
1) The student can measure the initial velocity and acceleration and use that information to calculate objects final velocity.
2) The student can measure the recoil distance of the throwing mechanism and then calculate the velocity from the conservation of momentum principle.
3) The student can measure the horizontal distance traveled, determine the flight time from the vertical drop, and then calculate the average horizontal velocity.
4) The student can measure the fall distance and travel time from the horizontal displacement and then calculate the average horizontal velocity.
The student can determine the average horizontal velocity of the object using a meter stick and a calculator by measuring the horizontal distance traveled, determine the flight time from the vertical drop, and then calculate the average horizontal velocity.
So option 3 is correct.
What is horizontal velocity?The horizontal velocity can be described as the velocity of any projectile along a horizontal path.
From the options given, the student can measure the horizontal distance traveled, determine the flight time from the vertical drop, and then calculate the average horizontal velocity.
Gravity acts only in the vertical direction and doesn't affect horizontal motion directly.
Horizontal velocity comes from forces that act in the x-axis, that is directions from side to side and not up or down.
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Suppose an electron in some atom absorbs energy and transitions from level 1 up to level 4. Which of the following is a true statement regarding the electron transitions back down to level 1?
a. It must transition from 4 to 3, then 3 to 2, then 2 to 1. All downward transitions are one step at a time.
b. 4 to 2, followed by 2 to 1, is possible. Downward transitions can be any number of levels.
c. It can go from 4 to 1 only. The downward transition must match the upward one.
A boy leaves his home at 5:00 pm, drives around the city a distance of 24 miles, and returns home at 5:30 pm. His average velocity is???
We can see that the speed of the car is obtained as 12 miles per hour.
What is speed?The term speed is the ratio of the distance covered to the time taken. We can see that the distance that have been covered by the boy is 24 miles. The total time that have been taken to cover this distance is 30 mins or 0.5 hours.
We now come up with the following;
Distance = 24 miles
time = 0.5 hours
We now want to compute the speed of the boy in miles per hours so we have;
Speed = 24 miles / 0.5 hours = 12 miles per hour
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The law of Conservation of energy states that energy can be transformed from one form to another, but it cannot be _______ or ________. created, changed created, destroyed changed, destroyed radiated, conducted
Answer:
The low of conservation of energy states that "energy can neither be created nor be destroyed but it can be changed from one form to another".
Read a sample of one type of narrative nonfiction below and determine the type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life. Read a sample of one type of narrative nonfiction below and determine the type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life
Memoir is a type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life.
Because it combines elements of creative writing with the relation of facts required to produce a work of nonfiction, narrative nonfiction is a type of writing that is occasionally referred to as creative nonfiction. This genre comprises of writing that is factually accurate yet written with a creative flair that contributes to improving the work's flow and appeal. The genre of narrative nonfiction can include journalism and some genres of biography, essay, memoir, and personal essay. When compared to plain nonfiction, this genre is very new, and as the genre has developed, so too has the scrutiny that is applied to this kind of writing.
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1. Which of the following secondary sex characteristics do not develop during the teen years?
Odevelopment of breasts in girls
Odevelopment of body hair in boys
Odevelopment of ovaries in girls and testes in boys
Odevelopment of acne in boys
Answer:
Development of acne in boyw
1. Do stars going supernova have any impact on
allowing life to exist? Why?
Yes, the stars going supernova will have impact on allowing life to exist in nearby planets.
When a star goes supernova, a large amount of radiation is emitted. So, if a nearby planet inhabiting life has a ozone layer, it will be depleted. This results in increased harmful radiation levels on the ground. There will be mutations in organisms that can survive the radiations. Those that are not strong will die.
A supernova is the explosion of a star. This phenomenon happens when a star's nuclear fuel in its core runs out. As a result the pressure created by the burning in its core becomes completely null. Thus the gravity is only force acting, so the star collapses on itself emitting huge quantities of light and harmful radiation.
Therefore, the stars going supernova will have impact on allowing life to exist in nearby planets.
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(Figure 1) shows a 5.4 N force pushing two gliders along an air track. The 150 g spring between the gliders is compressed. The spring is firmly attached to the gliders, and it does not sag.
a)How much force does the spring exert on glider A ?
b)How much force does the spring exert on glider B ?
(a) The force the spring exert on glider A is 1.88 N.
(b) The force the spring exert on glider B is 2.82 N.
Acceleration of the springThe acceleration of the spring is calculated as follows;
F = ma
a = F/m
a = 5.4 N / (0.15 kg + 0.4 kg + 0.6 kg0
a = 4.7 m/s²
force the spring exert on glider AF(A) = ma
F(A) = 0.4 kg x 4.7 m/s²
F(A) = 1.88 N
force the spring exert on glider BF(B) = 0.6 kg x 4.7 m/s²
F(B) = 1.88 N
F(B) = 2.82 N
Thus, the force the spring exert on glider A is 1.88 N.
The force the spring exert on glider B is 2.82 N.
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A 20 km long, 8 m wide, two-lane highway is to be paved with a 4 cm thick
layer of asphalt. A fleet of three dump trucks is to be employed, each with
an empty mass of 20 metric tons and a carrying capacity of 20 m3 asphalt
with a density of 0.72 g/cm3 will be used. Determine the following:
a. the total volume of asphalt needed
b. the number of dump truck loads required
c. the gross mass of each truck
(a) The volume of asphalt needed is 6400 m³.
(b) The number of dump truck loads required is 320.
(c) The gross mass of each truck is 34400 kg.
The dimension of the two-lane highway 20 km long, 8 m wide, and 4 cm thick.
The mass of a dump truck is 20 metric tons, and carrying capacity is 20 m³ and the density is 0.72 g/cm³.
The two-lane highway:
length, l = 20 km = 20 × 10³ m
breadth, b = 8 m
Thickness, h = 4 cm = 4 × 10⁻² m
(a) The volume of the asphalt will be:
V = l × b × h
V = 20 × 10³ × 8 × 4 × 10⁻² m³
V = 64 × 10² m³
V = 6400 m³
V = 6400 × 10⁶ cm³
(b) The carrying capacity of 20 m³ asphalt.
Therefore, the number of truckloads required will be:
= 6400 m³ / 20 m³
= 320
(c) Now,
Density, d = 0.72 g/cm³ = 720 kg/m³
The empty mass is 20 metric tons which is equal to 20 ×10³ kg.
Therefore, the gross mass of each truck will be
m = 20 ×10³ kg + 720 kg/m³ × 20 m³
m = 20000 kg + 14400 kg
m = 34400 kg
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An apple is hanging at rest on a tree when its stem breaks. It takes 1.4 seconds for the apple to fall halfway to the ground. How long does it take for the apple to fall the entire distance to the ground?
The apple takes 2.05 seconds to fall due to gravity.
Newton's Second Law of Motion and Newton's Law of Universal Gravitation serve as the foundation for the formula for the acceleration caused by gravity. The most practical formula for estimating the acceleration caused by gravity is given by these two laws: g = G*M/R2, where g is the acceleration caused by gravity, G is the universal gravitational constant, M is mass, and R is distance.
Everything has a gravitational pull on every other object, according to Newton's Law of Universal Gravitation. The force is inversely proportional to the square of the distance between the centers of both objects and directly proportional to the masses of both objects. This is determined mathematically by the formula F = G*(m1*m2/d2), where F is the force and G is the gravitational constant of the universe.
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A transverse wave can be graphed as position vs. time or y-position vs. x-position. If
you want to determine the wavelength of a transverse wave, which graph should
you use? Explain
To determine the wavelength of a transverse wave, we use the graph of y-position vs. x-position.
What is a transverse wave?A transverse wave is a wave in which the direction of propagation of the wave is perpendicular to the direction of the disturbance causing the wave.
Plotting a transverse wave,
the y - direction represents the direction of disturbance of the wave, the x - direction represents the direction of propagation of the wave and t axis represents the time of travel of the waveNow, we can have two graphs namely,
position vs. time or y-position vs. x-position.Which graph will we use to determine the wavelength of a transverse wave.If we plot a cycle of each graph above, we see that position is plotted against time and y-position is plotted against x-position.
We note that the x - position is the direction of travel of the wave in which we measure its wavength. Since the wavelength is the x - position after one cycle, so, we use the graph of y-position vs. x-position to find its wavelength.
So, to determine the wavelength of a transverse wave, we use the graph of y-position vs. x-position.
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Why are the noble gases the least reactive elements?
Which type of circuit has
more than one path for
electrons to flow?
A. Parallel
B. Series
C. Neither
Answer:
A. Parallel connection
Answer:
Parallel circuit to be exact
You pull a rope to the left with 300 N and a friend pulls the rope to the right with 425 N. Draw a vector for the two forces acting on the rope
The total forces acting on the rope is 125 N towards the right side.
125 N of total forces are being applied to the rope's right side.
How are two forces operating on the rope represented by a vector?300 N of force as well as additional forces are applied in the proper direction.These forces are 425 N and are bigger than the starting force. The necessary vector diagram is shown here.The two forces' large, calm vector diagram is seen here. We must now determine the product of these two forces for part B.These two forces combine to produce a vector that is equal to the bigger force in the right direction less the smaller force in the left.Due to the smaller forces moving left. Therefore, since positive (425 -300) N is equivalent to 125 N, we have determined that the direction is correct.These two forces add up to 125 newtons moving in the proper direction.We must determine the size of the resultant, which is the magnitude of 125 newtons, for part C.The rightward movement of the outcome entities. The response to part C is this.To construct the resultant vector for party in this manner, we must widen it. The rope is this.Small and pointing in the right direction by 125 N, the outcome vector is small.To know more about vector visit:
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A butcher throws a cut of beef on spring scales which oscillates about the equilibrium
position with a period of T = 0.500 s. The amplitude of the vibration is A = 2.00 cm
(path length 4.00 cm). Find:
i. Frequency
ii. the maximum acceleration
iii. the maximum velocity
iv. the acceleration when the displacement is 1.00 cm
v. the velocity when the displacement is 1.00 cm
vi. the equation of motion as a function of time if the displacement is A at t = 0
The frequency of the simple harmonic motion is 2 Hertz , the maximum acceleration is 3 u and the maximum velocity is equal to 2.48 m/s.
What is oscillation?Oscillation is the repetitive or periodic variation, typically in time, of some measure about a central value or between two or more different states.
What is the time period?Time period in periodic oscillation refers to the time taken by the system to complete one oscillation.
Given:
Time period of the oscillation = 0.5 seconds
Amplitude of the oscillation = 2 cm
For determining frequency we use the formula of frequency.
f = 2π/T
Where,
f is the frequency of the oscillation
T is the time period of the oscillation
On substituting values we get,
Frequency (f) = 1/0.5
Frequency (f) = 2 Hertz
For determining maximum acceleration we use,
a = A × w × w
Where,
a is the acceleration
A is amplitude of the SHM
w is the angular frequency
Now,
a = A × w × w
a = 0.02 × 12.4× 12.4
a = 3 u
For maximum velocity we use,
v = A × w
Where v is maximum velocity
v = 0.02 × 12.4
v = 2.48 m/s
Therefore, the frequency of the simple harmonic motion is 2 Hertz , the maximum acceleration is 3 u and the maximum velocity is equal to 2.48 m/s.
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What is the kinetic energy of a 29 kg dog that is running at a speed of 8.5 m/s (about 17 mi/h)?
The kinetic energy of of given data is K.E. = 1,047.62 J
Equation:To calculate kinetic energy using the formula,
K.E. = 1/2 m v²
where,
K.E is kinetic energy
m is mass
v is velocity
So, Putting values,
K.E. = 1/2 x 29 x (8.5m/s)²
K.E. = 1,047.62 J
What is kinetic energy in simple words?The energy an object has as a consequence of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the object, which then moves at a new, constant speed.
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given that vector c=a+b, indicate the conditions that A and B have to meet in order for c to have the largest and smallest possible magnitudes
A Vector is a quantity which has both magnitude as well as direction.
vectors follow parallelogram law of addition and uses cosine of the angle between the vectors.
The addition of two vectors, i.e. c, is given by the formula
c=[tex]\sqrt{a^2+b^2+2abcos\alpha }[/tex]
where [tex]\alpha[/tex] is the angle between the vectors
now we know that maximum value of cos[tex]\alpha[/tex] can be is 1
and minimum value of cos [tex]\alpha[/tex] can be-1
now the maximum value cos[tex]\alpha[/tex] is 1 at the angle of π/2
and the minimum value of cosα is -1 is at the angle of -π
Therefore, A and B should have 0 degree between them and in the same direction to have the maximum value
there fore they should be in same direction and 0 degree meaning they should be on same line
A and B will have minimum value when the angle is 180 degree which means they should be on same line and be inn opposite direction to each other.
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A flowerpot falls from a window sill 36.5 m
above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? Choose upwards to be
the positive y direction. The acceleration of
gravity is 9.81 m/s
2
Answer in units of m/s.
When a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
From Newton's third equation of motion,
v^2 = u^2 + 2gh
where,
h is the height of the object or body from ground
u is the initial velocity of the body or object
v is the final velocity of the body or object
g is the acceleration due to gravity
Now, as we know that
Flowerpot is at rest. So, u = 0
g = 9.81m/s^2
h = 36.5m
By substituting all the values, we get
v^2 = 2 × 9.81 × 36.5
= 716.13
v = 26.7m/s
Thus, we concluded that when a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
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What is the weight of a 12.5kg mass?
What is the mass of a 2.5N weight?
200N are weighed. What is the mass?
What will a scale read for a 4kg mass?
1. The weight of a 12.5 kg mass is 122.625 N
2. The mass of a 2.5 N weight is 0.255 kg
3. The mass of a 200 N weight is 20.4 kg
4. The scale read for a 4 kg mass is 39.2 N
What is the relationship between weight and mass?The mass of a substance is the quantity of matter present in that substance.
The quantity of matter or mass of a substance is constant and is measured using a weighing balance.
The weight of a substance is the product of the mass of a substance and the acceleration due to gravity.
The weight of a substance varies and is measured using a spring balance and the unit is N.
Weight = m * g
where;
m is mass in kg
g = 9.81 m/s²
Considering the given substances:
1. The weight of a 12.5 kg mass = 12.5 * 9.81
The weight of a 12.5 kg mass = 122.625 N
2. The mass of a 2.5 N weight = 2.5/9.81
The mass of a 2.5 N weight = 0.255 kg
3. The mass of a 200 N weight = 200/9.81
The mass of a 200 N weight = 20.4 kg
4. The scale read for a 4 kg mass = 4 * 9.81
The scale read for a 4 kg mass = 39.2 N
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A satellite orbiting Earth at an orbital radius [tex]r[/tex] has a velocity [tex]v[/tex]. Which represents the velocity if the satellite is moved to an orbital radius of [tex]4r[/tex]?
A. [tex]4v[/tex]
B. [tex]\frac{1}{2}v[/tex]
C. [tex]\frac{1}{4}v[/tex]
D. [tex]2v[/tex]
Answer: C
Explanation:
The bigger the satellite, the longer it will take to get around the satellite. Hence, the velocity would get smaller.
r*v=4r*?
r*v/4r=?
r/4r * v=?
1/4 * v=?
?=v/4 ==> C
