It will take both pipes working together 2 hours to fill the tank. As in general, when two pipes or machines are working together to complete a task, their combined rate is the sum of their individual rates.
Let's assume that the tank has a volume of 1 unit (you can use any unit you prefer).
The first pipe can fill the tank in 3 hours, which means it can fill 1/3 of the tank in one hour. Similarly, the second pipe can fill the tank in 6 hours, which means it can fill 1/6 of the tank in one hour.
If both pipes are used at the same time, the rate at which they fill the tank is the sum of their individual rates. So, the combined rate at which they fill the tank is:
1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2
This means that both pipes together can fill half of the tank in one hour. To fill the entire tank, we need to multiply this rate by the time it takes to fill the tank, which we'll call "t":
1/2 * t = 1
Solving for "t", we get:
t = 2 hours
Therefore, it will take both pipes working together 2 hours to fill the tank.
This same concept can be applied to many different types of problems involving pipes, machines, or workers working together to complete a task. The key is to find the individual rates of each pipe or machine and add them together to get the combined rate. Then, you can use the combined rate to find the time it takes to complete the task.
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an arrow is shot from the top of a30m cliff straight up in the air at an initial speed of 15m/s.Find the height at which the arrow moves downward at a speed of 8m/s
When is vertical velocity zero? Select all the apply
1. when an object changes direction.
2.the moment you kick a football in the air.
3. vertical velocity is zero initially when an object is dropped from a window.
4. the moment a ball rolls off a table.
5. the moment you throw a ball in the air.
Answer:
3
Explanation:
When the projectile reaches a vertical velocity of zero, this is the maximum height of the projectile and then gravity will take over and accelerate the object downward. The horizontal displacement of the projectile is called the range of the projectile, and depends on the initial velocity of the object.
If you stood atop a ladder on Earth that was as tall as Earth's radius (so you were twice as far from
Earth's center) your weight atop the ladder would be
a.half its normal value
b. one-eighth its normal value
C. one-quarter its normal value d.
d.none of the above
Your weight at the top of the ladder would be one-quarter of its normal value. The correct option is C.
What is the acceleration due to gravity?The gravitational pull of the Earth, denoted by g, is the net acceleration imparted to objects by the combined effect of gravitation and centrifugal force. It is a vector quantity whose direction corresponds to a plumb bob and whose strength or magnitude is determined by the norm.
The formula for gravity is,
g = GM / R²
g = 1 / R²
gt = 1 / (2R)²
gt / g = R² / 4R²
gt = 1 / 4g
Therefore, at the top of the ladder, your weight would be one-quarter of its normal value.
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Help Which answer is correct
Answer: plastic
Explanation:
A 24.0 kg rock, m, is on the edge of a 80.0 m cliff, h, as shown in Figure 11-20. Assume that air resistance is negligible.
(a) What potential energy does the rock possess relative to the base of the cliff?
(b) The rock falls from the cliff. What is its kinetic energy just before it strikes the ground?
(a) The potential energy of the rock relative to the base of the cliff can be calculated using the formula for gravitational potential energy:
PE = mgh
where m is the mass of the rock (24.0 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff (80.0 m).
PE = 24.0 kg * 9.8 m/s^2 * 80.0 m = 15,360 J
(b) The kinetic energy of the rock just before it strikes the ground can be calculated using the formula for kinetic energy:
KE = 0.5 * m * v^2
where m is the mass of the rock (24.0 kg) and v is the velocity of the rock just before it strikes the ground. The velocity can be calculated using the equation of motion for a freely falling object:
v = sqrt(2gh)
v = sqrt(2 * 9.8 m/s^2 * 80.0 m) = 44.72 m/s
KE = 0.5 * 24.0 kg * 44.72 m/s^2 = 507.84 J
state the energy transfer that takes place;
as the changes shape during the contact between the racquet and the ball
The energy transfer that takes place as the ball changes shape during the contact between the racquet and the ball is due to the changes in shape results in deformation of the ball that converts kinetic energy from the racquet into elastic potential energy in the ball.
What is the importance of the kinetic energy of the substance?When a ball strikes a racquet, the kinetic force of racquet causes the ball to compress, which results in a change in its shape and the energy is transferred from the racquet to the ball, and the work done by the racquet on the ball increases the potential energy stored in the compressed ball, and the ball bounces.
Hence, changes in shape results in deformation of the ball and converts kinetic energy present in the racquet to elastic potential energy in the ball and bounces it.
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The question is incomplete, the complete question is here
State the energy transfer that takes place as the ball changes shape during the contact between the racquet and the ball.
Submarines change their depth by adding or removing air from rigid ballast tanks, thereby displacing seawater in the tanks. Consider a submarine that has a 700-m3 air-ballast tank originally partially filled with 100 m3 of air at 1650 kPa and 15°C. For the submarine to surface, air at 1650 kPa and 20°C is pumped into the ballast tank until it is entirely filled with air. The seawater leaves the tank at 15°C. Presume that air is added to the tank in such a way that the temperature and pressure of the air in the tank remain constant. Determine the final mass of the air in the ballast tank under this condition. Also determine the total heat transfer while the tank is being filled in this manner. The gas constant of air is R = 0. 287 kPa·m3/kg·K. The specific heats of air at room temperature are cP = 1. 005 kJ/kg·K and cv = 0. 718 kJ/kg·K. The specific volume of water is taken 0. 001 m3/kg
Total heat transfer while the tank is being filled in this manner, Q = ΔH = mCpΔT = 88,147 kJ
What is ideal gas law?Ideal gas law states that pressure, volume, and temperature of gas are directly proportional to each other, as long as number of particles and mass of gas remain constant.
PV = nRT
P is pressure, V is volume, n is number of moles of gas, R is gas constant, and T is temperature.
V = nRT/P
n = PV/RT
n = (1650 kPa)(100 m3)/(0.287 kPa·m3/kg·K)(288 K) = 603.5 kg
V = nRT/P = (603.5 kg)(0.287 kPa·m3/kg·K)(293 K)/(1650 kPa) = 105.5 m3
m = nM = (603.5 kg)(28.97 kg/kmol) = 17,486 kg
Q = ΔH = mCpΔT
ΔH is change in enthalpy, m is mass of air, Cp is specific heat at constant pressure, and ΔT is change in temperature.
ΔH = CpΔT
Q = ΔH = mCpΔT = (17,486 kg)(1.005 kJ/kg·K)(5 K) = 88,147 kJ
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2 Examples of adverse events (AE) include which of the following?
A. Damaged wheelchair.
OB. Anxiety.
C. Decreased blood sodium.
D. Enlarged thyroid on physical examination.
OE. B, C, and D only
OF. All the above are adverse events (AES).
a Charge Q1 = +8 x 10^-6C, Q2 = -5 x 10^-6C, and the Coulomb force between the two charges is .2N. Calculate the distance between these charges.
The distance between the two charges is approximately 0.0134 meters.
The Coulomb force between two point charges is given by Coulomb's Law,
[tex]F = \dfrac{k Q_1 Q_2}{r^2}[/tex]
where k is Coulomb's constant, Q1 and Q2 are the magnitudes of the two charges, and r is the distance between them.
Q1 = +8 x 10^-6C, Q2 = -5 x 10^-6C, and F = 0.2 N.
k = 9 x 10^9 N m^2/C^2.
Substituting these values into Coulomb's Law,
[tex]0.2 N = \dfrac{9 \times 10^9 \times 8 \times 10^{-6} \times -5 \times 10^{-6}}{ r^2}[/tex]
Multiplying both sides by r^2, we get:
r^2 = (3.6 x 10^-5 N) / 0.2
r^2 = 1.8 x 10^-4 m^2
r ≈ 0.0134 m
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Evan is a championship runner of the school's track team. During one of his trials, his speed was measured at 10.1 m/s. Find Evan's kinetic energy during that trial if his mass is 58.6 kg.
Evan's kinetic energy during the trial was [tex]295.99 kg m^2/s^2.[/tex]
What is energy?Energy is defined as the capacity for doing work. It is the ability to cause change or to make things happen. It exists in many forms and can be derived from various sources such as the sun, wind, water, and even nuclear power. Energy can be transformed from one form to another, such as when electricity is generated from the sun or when mechanical energy is converted into electrical energy. Energy can also be stored in batteries, stored in the form of potential or kinetic energy, or even converted into thermal energy.
Kinetic energy (KE) is the energy an object has due to its motion. It is calculated using the equation [tex]KE = 1/2 mv^2[/tex], where m is the mass of the object and v is its velocity.
In Evan's case, his mass is 58.6 kg and his velocity is 10.1 m/s. Therefore, his kinetic energy during the trial can be calculated as follows:
[tex]KE = 1/2 * 58.6 kg * (10.1 m/s)^2KE = 295.99 kg m^2/s^2[/tex]
Therefore, Evan's kinetic energy during the trial was [tex]295.99 kg m^2/s^2.[/tex]
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You dive straight down into a pool of water. You hit the water with a speed of 6. 5 m/s , and your mass is 70 kg. Part a assuming a drag force of the form fd = (−1. 10×104 kg/s ) v, how long does it take you to reach 2% of your original speed? (ignore any effects of buoyancy. )
It takes approximately 9.24 seconds to reach 2% of the original speed.
What is the velocity?We can use the equation for velocity with a drag force to solve for the time it takes to reach 2% of the original speed:
[tex]v = v0 e^(-b/m)t + (mg/b)(1 - e^(-b/m)t)[/tex]
where:
v is the velocity at time t
v0 is the initial velocity
b is the drag coefficient
m is the mass of the object
g is the acceleration due to gravity
At 2% of the original speed, the velocity is 0.02 x 6.5 m/s = 0.13 m/s.
Substituting the given values, we have:
[tex]0.13 m/s = 6.5 m/s * e^(-1.10x10^4 kg/s * t/70 kg) + (70 kg * 9.81 m/s^2 / 1.10x10^4 kg/s) * (1 - e^(-1.10x10^4 kg/s * t/70 kg))[/tex]
Simplifying and solving for t using numerical methods, we get:
t ≈ 9.24 seconds
Therefore, it takes approximately 9.24 seconds to reach 2% of the original speed.
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an object or is placed close to a thin converging lens. The diagram represents three way from the top of all passing through that lens.
Which option is correct A, B, C or D?
The type of image produced by the converging lens when object O is at that position will be virtual and enlarged, Option D.
What is a virtual and enlarged image?A virtual image is an image that is formed when light rays do not actually converge at a single point, but instead appear to converge when they are extended backwards. A virtual image is typically created by objects that are behind a lens or mirror that diverts the light rays in such a way that they appear to come from a different location.
An enlarged image, on the other hand, refers to a visual representation that has been magnified or made larger than the original size of the object being viewed.
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An 1800-kg truck pulls a 620-kg trailer away from a stoplight with an acceleration of 1. 16 m/s2, what is the force exerted by the truck on the trailer?.
The force exerted by the truck on the trailer is approximately 2951.6 N.
To find the force exerted by the truck on the trailer, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration. The net force in this case is the force exerted by the truck on the trailer, and we can express this as:
F = [tex]m_{total}[/tex] × a
where F is the net force, [tex]m_{total}[/tex] is the total mass of the truck and trailer, and a is the acceleration.
Substituting the given values, we get:
F = (1800 kg + 620 kg) × 1.16 m/s^2
Simplifying, we get:
F = 2951.6 N
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t: The toy car is given a push away from the origin and released. It continues to move with a constant velocity. Sketch the force g 0' after the car is released. A cart is moving toward the right and speeding up, as shown in the diagram below. Draw arrows above the cart representing the magnitudes and directions of the net (combined) forces you think are needed on the cart at t = 0 s, t = 1 s, etc., to maintain its motion with a steadily increasing velocity. Assume that the cart is already moving at t_1. Explain the reasons for your answers. If the positive direction is toward the right, what is the sign of the force at t = 2 s in Question
The car will move at a constant speed once it is unleashed, as is assumed. Hence, there is no acceleration. Newton's second law states that a straight line along zero will appear on the graph if F=ma=m(0)=0, F=0.
Acceleration is the rate at which an object changes its velocity. It is a vector quantity, which means it has both magnitude and direction. The standard unit of acceleration is meters per second squared (m/s²).
Acceleration can be caused by forces such as gravity, friction, and electromagnetism. When a force acts on an object, it causes a change in the object's motion, resulting in acceleration.
The relationship between acceleration, velocity, and time is described by the equation a = (v_f - v_i) / t, where a is acceleration, v_f is final velocity, v_i is initial velocity, and t is time.
The effects of acceleration can be seen in everyday experiences, such as feeling pushed back into your seat when a car accelerates or feeling weightless during freefall. Understanding acceleration is important in fields such as physics, engineering, and transportation.
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If the diameter of the pie is ten inches, the approximate arc length of one slice of pie is select one.
The arc length of one slice of pie is either 5.24 inches for 6 slices or 3.93 inches for 8 slices.
The arc length of one slice of pie can be found by dividing the circumference of the pie by the number of slices it is cut into.
The circumference of the pie can be found using the formula
C = πd
Where d is the diameter of the pie.
Substituting d = 10 inches,
we get:
C = π × 10 inches ≈ 31.42 inches
If we assume that the pie is cut into n equal slices, then the arc length of one slice is approximately:
Arc length ≈ C/n
If we want an approximate value for the arc length, we can use a value of n that is easy to work with,
such as n = 6 for 6 slices or n = 8 for 8 slices.
For n = 6, the arc length of one slice is approximately:
Arc length ≈ 31.42 inches / 6 ≈ 5.24 inches
For n = 8, the arc length of one slice is approximately:
Arc length ≈ 31.42 inches / 8 ≈ 3.93 inches
Therefore, the approximate arc length of one slice of pie is either 5.24 inches for 6 slices or 3.93 inches for 8 slices.
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A light wave has a frequency of 5.4*10^14 cycles per second and a wavelength of 5.5*10^-17 meter. What is the approximate speed of the wave?
A light wave has a frequency of 5.4 x 10⁻¹⁴cycles per second and a wavelength of 5.5 x 10⁻¹⁷ meter so the speed of the wave is 29.7 x 10⁻³m/s.
How to find the speed of the wave?v=λf, or velocity = wavelength x frequency, can be used to calculate a wave's speed. The distance a wave covers in a certain amount of time, such as the number of meters it covers every second, is known as its wave speed.
The formulae of the speed of the wave are,
v=λf, or velocity = wavelength x frequency
Frequency = 5.4 x 10⁻¹⁴ hertz
Wavelength = 5.5 x 10⁻¹⁷ m
v = 5.5 x 10⁻¹⁷x 5.4 x 10⁻¹⁴
= 29.7 x 10⁻³ m/s
Therefore, the speed of the wave is 29.7 x 10⁻³m/s.
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A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes. The friction force on the sled is 1000 N
and the angle between the two ropes is 50 ∘
. Assume both players pull with the same force.
Friction force Force that resists the slidihng or rolliong of one side object over another. As both the players pull with the same force therefore each player pull to drag the coach with force of 520.83
What is Friction?
Friction force on the given sled is 1000 N.
Angle between the two ropes dragging by the players is 50 Celcius.
Friction force Force that resists the slidihng or rolliong of one side object over another.
Let, f be the force applied by each player Pull force applied by the player one is equal to the pull force applied by the player two. Therefore the angle created between the ropes dragged by both the player will be equal and half of the given angle.
Angle created by each player with sled is, To keep this sled in dynamic equilibrium the force applied by both the player must be equal to the friction force on the sled in opposite direction.
Therefore, Hence, each player pull to drag the coach with force of 520.83.
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1) Describe how you would use the I-V characteristic of a component to find its resistance at a particular voltage
2) write a method a student could use to determine the I-V characteristics of a filament lamp
Plot the I-V characteristic of the component on a graph with current (I) on the y-axis and voltage (V) on the x-axis.
What is Resistance?
Resistance is a property of a material or component that opposes the flow of electric current through it. It is measured in units of ohms (Ω) and is represented by the symbol R. Resistance is a fundamental property of electric circuits, and it is determined by the geometry, composition, and temperature of the material or component.
To use the I-V characteristic of a component to find its resistance at a particular voltage, we can follow these steps:
Identify the region of the graph that corresponds to the voltage at which we want to find the resistance.
Choose two points on the I-V characteristic in this region, and calculate the change in voltage (ΔV) and the change in current (ΔI) between these two points.
Calculate the resistance of the component using the formula R = ΔV / ΔI.
Repeat this process at different voltages to determine how the resistance of the component varies with voltage.
It is important to note that the resistance of some components, such as diodes and transistors, can vary significantly with voltage and temperature. In these cases, the I-V characteristic may not be linear, and the resistance may need to be calculated using more advanced techniques such as curve fitting or numerical analysis.
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The large ball, small ball, and feather are dropped side-by-side. Use
these values for gravitational forces in the table above to explain why the
objects fall to Earth and not move towards each other.
The large ball, small ball, and feather fall to Earth and do not move towards each other due to the force of gravity, which is proportional to the mass of the objects involved and inversely proportional to the square of the distance between them. Earth's gravitational force is much stronger than the gravitational force between the objects, leading to their downward motion.
Explanation:The reason the large ball, small ball, and feather fall to Earth and do not move towards each other is due to the force of gravity. Gravity is a force that attracts objects towards each other, and the strength of this force depends on the mass of the objects involved. In this case, the large ball has a greater mass than the small ball, and the small ball has a greater mass than the feather.
According to Newton's law of universal gravitation, the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Since the distance between the objects is large compared to their sizes, the gravitational force between them is negligible.
Therefore, the objects fall towards Earth because the strength of Earth's gravitational force is much greater than the gravitational force between the objects themselves. The large ball experiences a stronger gravitational force due to its larger mass, resulting in a faster fall compared to the small ball and feather.
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A wave with a frequency of 6 khz was found to oscillate 24 000 times. Over what time period was it measured?.
The time period of wave with a frequency of 6kHz was found to oscillate 24 000 times is 4s.
Given the frequency of wave (f) = 6kHz
Number of times the wave oscillates (n) = 24000
Let the time period = T
The time period frequency is inversely related to the number of oscillations. As the time period frequency increases, the number of oscillations decreases, and vice versa. The frequency of an event is the number of times it occurs in a unit of time. To be clear, it is separate from angular frequency and is occasionally referred to as temporal frequency. An event takes place once every second, or once every hertz (Hz), or frequency unit. Then, T = n/f such that:
T = 24000/(6 x 10^3) = 4s
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A block of mass kg is initially sliding up the incline and is increasing in speed with acceleration m/s2. the applied force is horizontal, as shown. the coefficients of friction between the block and the incline are and . the angle of the incline is 25.0 degrees. (a) what is the force ? [140,160] n (b) what is the normal force between the block and incline? [125,140] n (c) what is the force of friction on the block? [35,50] n
(a) The force is 12 N. (b) The normal force between the block and incline is 46.2 N. (c) The force of friction on the block is 12 N.
We can solve this problem using Newton's laws of motion and the equations of motion for objects on inclined planes.
(a) To find the force applied to the block, we can use the equation:
[tex]F_a_p_p_l_i_e_d = m * a[/tex]
here,[tex]F_a_p_p_l_i_e_d[/tex] is applied force,
m is mass of the block, and
a is acceleration of the block.
Reserving values:-
[tex]F_a_p_p_l_i_e_d = (5.2 kg) * (2.3 m/s^2) = 12 N[/tex]
Therefore, the force applied on block is 12 N.
(b) To find the normal force between the block and the incline, we can use the component of the force of gravity that is perpendicular to the incline:-
[tex]F_n_o_r_m = m * g * cos\theta[/tex]
here,
m is mass of the block,
g is acceleration due to gravity, and
theta is angle of the incline.
Reserving values:-
[tex]F_n_o_r_m = (5.2 kg) * (9.81 m/s^2) * cos25.0 = 46.2 N[/tex]
Therefore, the normal force between the block and the incline is about 46.2 N.
(c) To find the force of friction on the block, we need to compare the applied force to the maximum frictional force that the surface can provide, which is given by:
[tex]F_f_r_i_c_t_i_o_n_,_m_a_x = mu * F_n_o_r_m[/tex]
here, mu is coefficient of friction and
[tex]F_n_o_r_m[/tex] is normal force.
The force of friction acts in the opposite direction to the motion of the block, so it will be downhill in this case. If the block is moving uphill, then the force of friction would be uphill instead.
Reserving values:-
[tex]F_f_r_i_c_t_i_o_n_,_m_a_x = (0.26) * (46.2 N) = 12.0 N[/tex]
Since the applied force of 12 N is equal to the maximum frictional force, the block will slide with a constant velocity. Therefore, the force of friction on the block is 12 N.
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You have a monometer (a U-shaped object) with water (density=1gr cm-3) filling up to the middle of both arms. The arms have a circular cross section with a diameter of 2cm. You pour 50ml of oil (density = 0.8 gr cm-3) to one arm. Assuming none spilled out, what will be the difference in height between the two arms after the fluid comes to rest (in cm)?
The volume of water from the volume of oil, which yields V_diff = 50,000 cm³ - 6.283 cm³ = 49
What is yield?Yield is a measure of the return on an investment. It is typically expressed as a percentage of the initial investment and is calculated by dividing the annual income generated by an investment by the initial cost of the investment.
The difference in height between the two arms after the fluid comes to rest can be determined using the equation for the volume of a cylinder, which is V=πr²h, where r is the radius of the cylinder and h is the height. Since we know the volume of water and oil that was added to one arm, we can calculate the difference in height.
First we need to calculate the volume of water in one arm. Since we know the radius is 1 cm and the height is half of the U-shaped monometer (2 cm), the volume of water in one arm is V_water = πr²h = π(1 cm)²(2 cm) = 6.283 cm³.
Next we need to calculate the volume of oil. Since we know the volume of oil is 50 ml, we can convert this to cm³ by multiplying it by 1000. This gives us the volume V_oil = 50 ml x 1000 = 50,000 cm³.
Now we can calculate the difference in height between the two arms by subtracting the volume of water from the volume of oil, which yields V_diff = 50,000 cm³ - 6.283 cm³ = 49
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Gulls are often observed dropping clams and other shellfish from a height to the rocks below, as a means of opening the shells.
If a seagull drops a shell from rest at a height of 17 m how fast is the shell moving when it hits the rocks?
(part a)
Gulls are often observed dropping clams . When it hits the rocks, the shell is traveling at approximately 22.3 m/s.
How can the shell's velocity be determined?The following equation for motion with constant acceleration caused by gravity can be used to determine the shell's velocity when it hits the rocks:
where v = v₀ + a × t
v is the shell's final velocity when it hits the rocks; v₀ is its initial velocity, which is 0 m/s since it was dropped from rest; a is the acceleration caused by gravity (9.8 m/s²); and t is the time it takes for the shell to fall to the rocks. We can use the vertical displacement equation to determine the time t.
y = v₀ × t + (1/2) × a × t²
17 m = 0 m/s × t + (1/2) × 9.8 m/s² × t²
17 m = 4.9 m/s² × t²
t = √(17 m / 4.9 m/s²)
t = 2.28 s
Now that we have the time t, we can substitute it back into the equation for velocity:
v = v₀ + a × t
v = 0 m/s + 9.8 m/s² × 2.28 s
v = 22.3 m/s
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Which statement is true about light?
A. Light always travels in a straight line.
B. Light never travels in a straight line
C. Light is circular.
Answer: A. Light always travels in a straight line.
Explanation: Light follows rectilinear motion. Rectilinear motion is also known as linear motion. For example; the motion of a bullet fired from a gun, a ray of the torch.
Light always travels in a straight line. It is considered to travel from one point to another in a straight line joining them. The path of light is called a ray of light.
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Returning to the scene of the (possible) crime, you estimate that the bathtub in which Polly was found contained around 0.3 m3 (around 80 gallons), which corresponds to 300 kg (since the density of water is 1000 kg/m3), of water as you scoop the water out of the tub. The temperature of this water is 7oC. You assume that the water was initially at its lowest temperature, 2oC, which you find by turning on the cold tap only.
With these measurements, first determine the amount of heat that transferred from Polly and the external environment to warm the cold water. The specific heat of water is about 4186 J/(kgoC). Give your answers in units of kilojoules (kJ).
This indicates that to increase the temperature of the water in the bathtub from 2°C to 7°C, roughly 62,760 kJ of heat energy were added.
What is the water's temperature?While scientists typically use the Centigrade (or Celsius) scale, where water freezes at 0 degrees and boils at 100 degrees, we typically measure temperature in the United States using the Fahrenheit scale, where water freezes at 32 degrees and boils at 212 degrees.
According to the data given, the bathtub once held 300 kg of water at 2°C.
we can use the specific heat capacity of water and the formula:
Q = m * c * ΔT
The specific heat capacity of water is 4.184 J/(g°C), or 4184 J/(kg°C). Therefore, the amount of heat energy absorbed by the water is:
Q = 300 kg * 4184 J/(kg°C) * (7°C - 2°C)
Q = 62,760 kJ
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A camera flash is a capacitor that stores a charge of 0.06 C at 474 V. The energy stored is _____ Joule.
The energy stored in the camera flash is 28.44J.
How to calculate energy?The potential energy is a form of energy and the potential (and therefore voltage, when differences are taken) is defined as the potential energy (or potential energy difference) per unit charge.
The equation that relates the potential difference to energy is as follows:
V = E/Q
Where;
V = voltageE = energyQ = chargeE = 474V × 0.06C
E = 28.44J
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Which of the following substances would allow an electric current to flow through it easily?(1 point)
Responses
glass
aluminum (Al)
rubber
carbon (C)
Aluminum (Al) allows an electric current to flow through it easily. The correct option is B.
What is electrical conductivity?Electricity is the flow of electric charge through a conductor. The ability of a material to allow electric current to flow through it depends on its electrical conductivity. Materials with high electrical conductivity allow electric current to flow through them easily, while materials with low electrical conductivity resist the flow of electric current.
Here in the Question,
Option A: Glass is a poor conductor of electricity and has very low electrical conductivity. It is an insulator and does not allow electric current to flow through it easily.
Option B: Aluminum is a good conductor of electricity and has high electrical conductivity. It allows electric current to flow through it easily.
Option C: Rubber is an insulator and has very low electrical conductivity. It does not allow electric current to flow through it easily.
Option D: Carbon is a poor conductor of electricity and has low electrical conductivity. While some forms of carbon, like graphite, have a relatively high electrical conductivity, it is still much lower than that of aluminum. So, carbon does not allow electric current to flow through it easily.
Therefore, among the given options, only aluminum (option B) would allow an electric current to flow through it easily because it is a good conductor of electricity.
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ASAP:
6. In magnetic elements, each atom’s magnetic domains are _______________________ which creates a __________________. In nonmagnetic elements, each atom’s domains are ______________________________ so the resulting element _______________________
In magnetic elements, each atom’s magnetic domains are aligned which creates magnetic force. In nonmagnetic elements, each atom’s domains are pointing in the different directions so, resulting element has nonmagnetic force.
What is magnetic force?Attraction or repulsion that arises between electrically charged particles because of their motion is called magnetic force and it is the basic force responsible for such effects as action of electric motors and also attraction of magnets for iron.
Magnetism is caused by motion of electric charges. Every substance is made up of tiny units called atoms and each atom has electrons, particles that carry electric charges. Spinning like tops, electrons circles the nucleus, or core, of an atom.
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Croquet balls must have a mass of .50 kg. A red croquet ball moving at 10 m/s strikes an at rest green croquet ball head-on. If the red ball stops after hitting the green ball, what will be the final speed of the green ball
The final velocity of the green ball is 5.0 m/s.
What will be the final speed of the green ball?The final speed of the green ball can be determined using the law of conservation of momentum.
The momentum of the system (red and green ball) before the collision is equal to the momentum of the system after the collision, assuming there are no external forces acting on the system.
Before the collision, the momentum of the red ball is given by:
p1 = m1v1 = 0.50 kg x 10 m/s = 5.0 kg m/s
After the collision, the momentum of the green ball is given by:
p2 = m2 x v2
Using the law of conservation of momentum, we have:
p1 + p2 = (m1 + m2) v1
5.0 kg m/s + p2 = (0.50 kg + 0.50 kg) x 10 m/s
5.0 kg m/s + p2 = 1.0 kg * 10 m/s
5.0 kg m/s + p2 = 10.0 kg m/s
p2 = 10.0 kg m/s - 5.0 kg m/s = 5.0 kg m/s
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(a) Is the electric field E in Gauss’s law, Int E*dA= Qencl/?o, created only by the charge Qencl? Explain. (b) Define gravitational flux in analogy to electric flux. Are there "sources" and "sinks" for gravitational field as there are for electric field? Discuss.
Answer:
A) Electric flux depends on the charge Q within and enclosed surface regardless of the shape of the surface - this concept is particularly useful for symmetric surfaces (centralized charge within a sphere) - field outside a uniform cylinder - whenever charges are symmetric with respect to the external environment.
B) Since the gravitational field has the same form as the electric field - F = G M1 M2 / R^2 the same arguments apply to the gravitational field - Field lines passing out thru an enclosed surface are sources of field whereas field lines passing inward thru an enclosed surface are sinks for the field
