Part A- Variation in the speed of sound Sound is a longitudinal wave, and its speed depends on the medium through which it propagates. In air, sound travels at 343 m/s. In an experiment, you observo a sound with a frequency of 500 Hz and a wavelength of 6.4 m. What is the speed of sound in this differont medium? Express your answer with the appropriate units. HÅ ? Value Units Submit Request Answer Sounds vary in intensity and loudness across a very wide range, and we use the logarithmic decibel scale to quantify sound. Sort and match the following sounds with their decibel level. Place each sound in the appropriate in for its decibel level. Only one sound may be placed in each bin. Reset Help Operating a lawnmower Your clothing rusting Telephone hold music A whisper across a football field Abrary with people studying -20 dB 10 dB 30 dB 60 dB 90 dB Part D- Calculating the limits of hearing In a large perfectly quiet room, at what maximum distance could you hear a bee with a power output of 1W? Recall that the threshold of hearing is 10-12 W/m² Express your answer with the appropriate units. HA ? T Value Units Submit Request Answer

60 kg m/s is the answer because you gave it and I thought you are telling ruth also you are a big questioner and also you should check with your doctor and go out and go touch the grass.

The change in velocity of an object is given by the equation Δv = F * t / m, where Δv is the change in velocity, F is the force applied, t is the time over which the force is applied, and m is the mass of the object.

In this case, the impulse applied to the block is 24 Ns, and the mass of the block is 6 kg. The time over which the force is applied can be calculated as t = Impulse / Force = 24 Ns / 24 N = 1 s.

Using these values, we can calculate the change in velocity of the block as follows:

Δv = F * t / m = 24 N * 1 s / 6 kg = 4 m/s

So, the velocity of the block after the impulse is applied would be v = v0 + Δv = 8 m/s + 4 m/s = 12 m/s.

Neutron star diameter estimated to be between 10 and 20 kilometers (6 to 12 miles), which is extremely small compared to other astronomical objects.

The diameter of a neutron star can vary depending on its mass, rotation, and other properties. However, it is generally estimated to be between 10 and 20 kilometers (6 to 12 miles), which is extremely small compared to other astronomical objects like planets and stars.

Neutron stars are extremely dense and compact objects that form when a massive star undergoes a supernova explosion and its core collapses. This collapse causes the protons and electrons in the star to merge and form neutrons, which results in a neutron star. Because neutron stars are so small and dense, they have very strong gravitational fields and are surrounded by extremely powerful magnetic fields.

While the exact diameter of a neutron star can be difficult to measure, scientists have used a variety of methods to estimate their size, including observations of their rotation and interactions with other objects in space. Despite their small size, neutron stars are incredibly important in the study of astrophysics and have helped scientists to better understand the nature of matter, gravity, and the universe itself.

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Newton's Law of Universal Gravitation says that every particle in the cosmos attracts every other particle with a force directly equal to the product of their masses and inversely proportional to the square of their distance.

To detect the gravitational force of attraction between any two objects, at least one of them on Earth must have an exceptionally massive mass. We cannot detect such forces because no object on Earth has an enormously big mass.

Newton's universal law of gravitation states that all objects attract each other with a force (i) away from directly proportional to the product of their masses and (ii) gravity proportional to the square of the distance between their centers. When considering objects on the surface of the Earth, the force is (iii) directly proportional to the product of the mass of the object and the (iv) acceleration due to (v) smaller at the Earth's surface. Since the Earth is (vi) larger than any object under consideration, the object is drawn (vii) towards the Earth.

The two items in a room do not move towards one other since the gravitational force of attraction between them is extremely minimal due to their modest masses. According to the universal law of gravity, every object exerts a gravitational force on every other thing. The gravitational force is directly proportional to the product of masses and inversely proportional to the square of their distances, according to the universal law of gravitation.

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Complete Question:

Fill in the blanks with the appropriate option:

Newton's universal law of gravitation states that all objects attract each other with a force (i) _____ proportional to the product of their masses and (ii) ____ proportional to the square of the distance between their centers. When considering objects on the surface of the Earth, the force is (iii) _____ proportional to the product of the mass of the object and the (iv) ____ due to (v) _____ at the Earth's surface. Since the Earth is (vi) ____ than any object under consideration, the object is drawn (vii) ______ the Earth.

Options:

acceleration, away from directly, directly, gravity, inversely, larger, smaller, some, toward.

Answer:

To determine the inclination angle for both cable segments, we can use the law of sines. Let's call the inclination angle "theta."

L/sin(theta) = h/sin(90-theta)

40/sin(theta) = 8/cos(theta)

Cross multiplying and simplifying, we get:

sin(theta) = 8/40 = 1/5

So,

theta = sin^-1(1/5) = 11.31 degrees

Next, we can use the law of cosines to find the tension force T in cable BAC.

T^2 = W^2 + (LBAC)^2 - 2WLBACcos(theta)

T^2 = 200^2 + 50^2 - 2(200)(50)cos(11.31)

T = sqrt(200^2 + 50^2 - 2(200)(50)cos(11.31)) = sqrt(20000 + 2500 - 2000cos(11.31))

T = sqrt(22500 - 2000cos(11.31))

Rounding to the nearest whole number, we get:

T = 150 lb

So, the inclination angle for both cable segments is 11.31 degrees, and the tension force T in cable BAC is 150 lb.

Explanation:

If a 1.5 kg ball has a momentum of 4.5 kg*m/s, the velocity of the ball is  3 m/s.

According to the question, the given quantity is,

Mass of the ball = 1.5 kg

The momentum of the ball =  4.5 kg. m/s

The momentum is defined as the product of the mass of the object and the velocity of the object, so p = mv.

p = momentum of an object

m = mass of an object

v = velocity of an object

According to question the given value outs in the formulae,

p= mv

4.50 = 1.50 × v

v = 4.50/ 1.50

v = 3 m/s.

Therefore, the velocity of the ball is  3 m/s.

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The displacement of the Usain Bolt will be 100 m if ran a straight path. (There is need to specify the shape of the track, did he return to the initial position?)

Displacement is a vector quantity that measures the overall change in position of an object, from its initial position to its final position.

It is defined as the straight-line distance between the initial and final positions, along with the direction from the initial to the final position.

Δx = x₂ - x₁

where;

Δx =  100 m - 0 m

Δx = 100 m

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The coefficient of kinetic friction between the block and the surface 0.245.

Friction is a force that opposes relative motion and manifests itself at the interfaces of bodies as well as inside, as in the case of fluids. Leonardo da Vinci was the first to conceive the idea of friction coefficient.

The characteristics of the surfaces, the environment, surface details, the presence of lubricant, etc. all affect how much friction there is between surfaces.

There are a number of theories on what generates static friction, and like other friction-related ideas, each one holds true in some situations but falls short in others.

Therefore, The coefficient of kinetic friction between the block and the surface 0.245.

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a. The thickness of 1 card (of a deck of 52) = 0.011346 in/card

b. The decks that need to be measured together = 62,500

To calculate the thickness of 1 card, we divide the measured thickness of the deck by the number of cards in the deck:

(a)

0.590 in / 52 cards = 0.011346 in/card

The uncertainty of the measurement is also divided by the number of cards:

±0.005 in / 52 cards

= ±0.000096 in/card

So the thickness of 1 card is 0.011346 in ± 0.000096 in.

b. To reduce the uncertainty to 0.00002 in, we can use the formula:

uncertainty / √n = desired uncertainty

Where,

n is the number of decks measured together.

Rearranging the formula and plugging in the values:

n = (uncertainty / desired uncertainty)²n

= (0.005 in / 0.00002 in)²

n = 62,500

So we need to measure 62,500 decks together to achieve the desired uncertainty of 0.00002 in.

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The distance over which the force was applied would be 10 meters.

The work done on an object is given by the product of the force applied and the distance over which it is applied. Therefore, we can use the formula:

Work = Force x Distance

We know that the force applied is 50 newtons, and the work done is 5.0 x 10^2 joules. We can rearrange the formula to solve for distance:

Distance = Work / Force

Substituting the values we know, we get:

Distance = (5.0 x 10^2 J) / 50 N

Distance = 10 meters

Therefore, the force of 50 newtons was applied over a distance of 10 meters to do 5.0 x 10^2 joules of work on the object.

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Answer: True

Explanation:

Simple machines are devices with few or no moving parts that make work easier by multiplying, reducing, or changing the direction of force

Simple machines can be combined to form complex machines and mechanisms that make many tasks easier to perform. Examples of six types of simple machines include;

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Answer:

Explanation:

a) To find the current in the wire, use the formula:

I = Q / t

Where I is the current, Q is the amount of charge that passes through the wire (2.37 C), and t is the time (5.4 s).

I = 2.37 C / 5.4 s = 0.44 A

So the current in the wire is 0.44 A.

b) To find the cross-sectional area of the wire, use the formula:

A = π * r^2

Where A is the cross-sectional area, r is the radius of the wire (1.0 mm = 0.001 m), and π is Pi (3.14).

A = π * (0.001 m)^2 = 3.14 * 10^-6 m^2

So the cross-sectional area of the wire is 3.14 * 10^-6 m^2.

c) To find the charge of the charge carriers in the wire, use the formula:

Q = n * e

Where Q is the charge, n is the number of charge carriers, and e is the elementary charge (1.60 × 10^-19 C).

The wire has a charge carrier density of 7.5 × 10^26 /3, so the number of charge carriers can be calculated as:

n = (charge carrier density * cross-sectional area of the wire)

n = (7.5 × 10^26 / 3) * (3.14 * 10^-6 m^2)

n = 7.5 × 10^26 * 3.14 * 10^-6 / 3

n = 2.35 × 10^20

So the charge of the charge carriers in the wire is:

Q = n * e = 2.35 × 10^20 * 1.60 × 10^-19 C = 3.72 × 10^-19 C

d) To find the drift speed of the electrons in the wire, use the formula:

v = I / (n * e * A)

Where v is the drift speed, I is the current (0.44 A), n is the number of charge carriers (2.35 × 10^20), e is the elementary charge (1.60 × 10^-19 C), and A is the cross-sectional area of the wire (3.14 * 10^-6 m^2).

v = 0.44 A / (2.35 × 10^20 * 1.60 × 10^-19 C * 3.14 * 10^-6 m^2)

v = 0.44 / (2.35 × 10^20 * 1.60 × 10^-19 * 3.14 * 10^-6)

v = 0.44 / (3.74 × 10^-5)

v = 11766 m/s

So the drift speed of the electrons in this wire is 11766 m/s.

The gravitational potential energies are 300 kJ and 400 kJ respectively

Gravitational potential energy is a form of potential energy that an object possesses due to its position relative to a reference point in a gravitational field. It is defined as the amount of work that must be done to move an object from its current position to a reference point, without changing its speed or direction.

The gravitational potential energy of an object can be calculated using the formula:

For the first case;

Note that the mass of  2500 L is 2500 Kg

With respect to the floor;

2500 Kg * 10 * 12 = 300 kJ

With respect to the basement;

2500 * 10 * 16 = 400 kJ

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Answer: Smaller planets are easier to detect using the transit method.

Explanation:

The transit method is a technique for detecting exoplanets, or planets outside our solar system, by observing the periodic dimming of a star as a planet passes in front of it (transits). The size of the planet affects the amount of light that is blocked, and therefore the magnitude of the dimming.

Smaller planets block less light than larger planets, making it more difficult to detect the transit. However, smaller planets are more numerous, and their transits are more frequent and easier to observe. Additionally, smaller planets are more likely to be located in the habitable zone of their star, where conditions may be suitable for life.

Therefore, smaller planets are easier to detect using the transit method, as they cause a smaller but more frequent dimming of the star, making them easier to detect with current technology. The relative size of the planet does matter in the transit method, as smaller planets are easier to detect.

Answer:

larger planets (correct)

Explanation:

After a workplace incident requiring first aid, is it beneficial to review the first aid response because:

1) The WHS Act and Regulations make it a legal duty.

2) That the initial responder/s were properly trained for the occurrence.

3) Verify the efficacy of the workplace's first aid strategy and risk management procedure.

A review of first aid occurrences may be required by the workplace health and safety (WHS) act and regulations to confirm that correct procedures and protocols were followed and to identify any areas for improvement.

Confirming that the first aider/s had the requisite training for the event is critical to ensuring that the appropriate steps were taken during the incident and that the first aider/s were equipped with the knowledge and abilities to respond correctly.

After an event, review the first aid response to confirm the success of the workplace's first aid strategy and risk management approach. This can aid in identifying areas for development and preparing the workplace for similar situations in the future. The study may involve assessing the availability and accessibility of first aid equipment and supplies, as well as first aid personnel response time.

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The ball needs to go at least  speed is 13 m/s per second to be able to clear the ceiling.

angle should you toss the ball 46.26°.

From the query, we learn that

We are 6.0 metres away from one home wall.

who is 6.0 metres from the wall across from you.

Both the throw and the catch take place one metre above the ground.

Assume that you and your companion are both 6.0 metres from the edge of the roof.

The Newtons equation for the distance is typically expressed numerically as

[tex]s=v*t+\frac{a}{2}*t^{2}\\5=0*t+4.9*t^{2}\\t=1.04[/tex]

Therefore

[tex]2*t = 2.0s[/tex]

Where

[tex]18=V_{x} *2.0\\V_{x} =8.9[/tex]

And

[tex]5=V_{y} *1.04-4.9*1.04^{2}\\V_{y} =9.8[/tex]

Therefore

[tex]V=\sqrt{V_{y}^{2}+V_{x} ^{2} } \\V=\sqrt{(9.8)^{2}+(8.9)^{2}} \\\V=13m/s[/tex]

In order to determine the angle at which you should toss the ball, you must first calculate the distance between you and your friend. This is done by using the Pythagorean Theorem to calculate the hypotenuse of the right triangle formed by the two walls and the distance between you and your friend:

[tex]C = \sqrt (6.0m)^2 + (6.0m)^2 \\ = 8.485m[/tex]

Now you can calculate the angle using trigonometry. Since the triangle is a right triangle, you can use the inverse tangent function to calculate the angle:

tan⁻¹[tex](\frac{6.0m}{8.485m})[/tex] = 46.26°

Therefore, you should toss the ball at an angle of 46.26°.

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Answer:

Explanation:Electric potential of a point charge is V=kQ/r V = k Q / r . Electric potential is a scalar, and electric field is a vector. Addition of voltages as numbers gives the voltage due to a combination of point charges, whereas addition of individual fields as vectors gives the total electric field.

Answer:

In a Newton's ring arrangement, the difference in the square of the diameters of successive rings is equal to four times the wavelength of light divided by the refractive index of the medium between the planoconvex lens and the plane glass plate.

If the wavelength of light is changed to 4.5 x 10-5 cm, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by the refractive index of the medium (which is assumed to be 1 if a liquid of refractive index 1.33 is not introduced).

If a liquid of refractive index 1.33 is introduced between the lens and the plate, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by 1.33.

If the radius of curvature of the convex surface of the plano-convex lens is doubled, then the difference in the square of the diameters of successive rings will remain the same.

The horizontal speed at which the water leaves the hole is[tex]4.09 ms^-1.[/tex]

Speed is the rate of change of the position of an object in a given direction. It is expressed as the distance traveled per unit of time, typically measured in meters per second (m/s). It is also commonly represented by the symbol ‘v’. Speed is a scalar quantity, meaning it has only magnitude, not direction.

The kinetic energy per unit volume at the point of the hole is equal to the density of the water multiplied by one-half the square of the velocity of the water leaving the hole.

Since these two values are constant across a horizontal streamline, we can set up the following equation:

[tex]ρgh = ρ(v^2/2)[/tex]

Solving for v, we get:

[tex]v = √(2gh)[/tex]

Plugging in the values for the height of the water above the hole (h = 0.4 m) and the acceleration due to gravity[tex](g = 9.81 ms^-2)[/tex], we get:

[tex]v = √(2*9.81*0.4) = 4.09 ms^-1[/tex]

Therefore, the horizontal speed at which the water leaves the hole is [tex]4.09 ms^-1.[/tex]

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The time is 5s.

In this problem, the observer is driving through town at

vi​ =16 m/s applies the brakes and begin decelerating with }a=−3.2 m/s²

We calculate the time for the vehicle to stop, and the speed after half the stopping time.

We use the velocity-time equation of the vehicle. When the vehicle stops, the velocity is

vf  ⟹ =vi +at

T = Vf−vi

= 0−16 m/s / −3.2 m/s²

= 5.0 s

What is time?

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The x component of the center mass is 4.64 m.

The x component of the center mass is calculated by applying the following formula as shown below;

X_cm = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3),

where;

X_cm = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3)

X_cm = (7 x 0   + 1 x 5  + 10 x 6) / (7 + 1 + 6)

X_cm = 4.64 m

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The total resistance is 9 ohms + 7 ohms = 16 ohms. Thus, the current is 1.0V/16 ohms = 0.0625 A.

Total resistance is the total opposition that a circuit or device encounters when an electric current is applied to it. It is the sum of all the individual resistances of each component in the circuit. Resistance is measured in ohms and is calculated by dividing voltage by current.

The current through the battery is the same as the current through the entire circuit.
To calculate the current, we can use Ohm's law which states that the current (I) is equal to the voltage (V) divided by the resistance (R).
In this case, the voltage is 1.0V and the resistance is the sum of the three individual resistances.
Since the 21 ohm resistors are in parallel, their total resistance is 7 ohms (1/R = 1/21 + 1/21).
Therefore, the total resistance is 9 ohms + 7 ohms = 16 ohms. Thus, the current is 1.0V/16 ohms = 0.0625 A.

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Answer:

find the average speed in km/h, we need to convert the time from minutes to hours, then divide the total distance by the total time.

First, let's convert the time from minutes to hours:

30 minutes ÷ 60 minutes/hour = 0.5 hours

Next, we can calculate the average speed:

2.4 km ÷ 0.5 hours = 4.8 km/h

So the average speed of the walker for this distance is 4.8 km/h.

The magnitude of vector F⃗ is approximately 34.7.

Describe Magnitude?

Magnitude is a term used in physics to describe the size or quantity of a physical property or phenomenon, such as the strength of a force, the intensity of light or sound, or the size of a vector.

It is a scalar value that expresses the amount or level of a quantity, without specifying its direction or orientation. In the context of vectors, magnitude refers to the length of the vector, which is calculated using the Pythagorean theorem, by taking the square root of the sum of the squares of the vector's components. Magnitude is typically expressed in units that correspond to the physical property being measured, such as meters for length or newtons for force.

To find the magnitude of vector F⃗, we first need to calculate the components of vector F⃗.

F⃗ = A⃗ - 5B⃗

= 6i^ - 3j^ - 5(-4i^ + 4j^) [substituting the given values]

= 6i^ - 3j^ + 20i^ - 20j^

= 26i^ - 23j^

The magnitude of vector F⃗ is given by:

|F⃗| = √(F_x^2 + F_y^2)

= √(26^2 + (-23)^2) [substituting the values of F_x and F_y]

= √(676 + 529)

= √1205

= 34.7 (approx.)

Therefore, the magnitude of vector F⃗ is approximately 34.7.

To find the direction of vector F⃗, we need to calculate the angle that the vector makes with the positive x-axis.

The direction of vector F⃗ can be expressed as:

θ = tan^(-1)(F_y/F_x)

Substituting the values of F_x and F_y:

θ = tan^(-1)(-23/26)

θ ≈ -42.7°

Since the angle is negative, we can express the direction as 360° - 42.7° = 317.3° counterclockwise from the positive x-axis.

Therefore, the direction of vector F⃗ is approximately 317.3° counterclockwise from the positive x-axis.

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The engine weighs four times as much as a freight car. Therefore, the final velocity following connection is 4 km/h.

v′=m1v1+m2v2m1+m2 m1 is the weight of item 1, v1 is indeed the velocity of the object of item 1, m2 is indeed the mass of argument 2, and v2 is the starting velocity of instrument 2 wherein v' is the final speed of a two objects after they travel as one mass after the collision.

The velocity of the special properties in a head-on object with a projectile that is significantly more massive than target the projectile's speed before and after the contact will be roughly equal, and the projectile's speed will practically remain unaltered.

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