Patrick is paid
$12 for 3 hours of work
How many hours does she work is she gets payed $1

The box and whiskers plot visually presents the ages of the 12

Reasons:

The five number summary from the box and whiskers plot is presented as follows;

Minimum value = 7.5

Maximum value = 50

Lower quartile, Q₁ = 15

Upper quartile, Q₃ = 40

Median, Q₂ = 32.5

The first quartile is equivalent to the 25th percentile

Therefore, given that the age 15 is equivalent to the first quartile = 25th percentile, the percentage of the 12 people that are older than 15 are;

Percent older than 15 = 100% - 25% = 75%

The correct option is 75%

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Answer:

14=300X

X=14/300

X=.04667 OR 4.67%

Step-by-step explanation:

100*.08+200*.03=(100+200)X

8+6=300X

14=300X

X=14/300

X=.04667 OR 4.67% SOLUTION ANS.

If this process is wrong, let me know

Answer:

60

Step-by-step explanation:

Perimeter = 2l + 2w

57x2 = 114

234 - 114 = 120

120 / 2 = 60

Answer:

7x

Step-by-step explanation:

(5.2 + 6.8)x - (25 ÷ 5)x

12x-(25divied by 5)x

12x-5x

7x

Step-by-step explanation:

$84 $12 use x as your variable then cross multiply and the answer u get is us variable

Answer:

y=10x-2

Step-by-step explanation:

Answer:

a b

They both are a type of currency from different countries in order to purchase things

Step-by-step explanation:

[tex]\displaystyle \sf \red{I=\int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \frac{ \alpha + \beta + \gamma + \theta - \eta}{\alpha + \beta + \gamma + \theta + \eta} \: d \alpha d \beta d \gamma d \theta d \eta}[/tex]

[tex]\displaystyle \sf \red{I=\int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \frac{ \alpha + \beta + \gamma - \theta + \eta}{\alpha + \beta + \gamma + \theta + \eta} \: d \alpha d \beta d \gamma d \theta d \eta}[/tex]

[tex]\displaystyle \sf \red{I=\int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \frac{ \alpha + \beta - \gamma + \theta + \eta}{\alpha + \beta + \gamma + \theta + \eta} \: d \alpha d \beta d \gamma d \theta d \eta}[/tex]

[tex]\displaystyle \sf \red{I=\int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \frac{ \alpha - \beta + \gamma + \theta + \eta}{\alpha + \beta + \gamma + \theta + \eta} \: d \alpha d \beta d \gamma d \theta d \eta}[/tex]

[tex]\displaystyle \sf \red{I=\int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \frac{ - \alpha + \beta + \gamma + \theta + \eta}{\alpha + \beta + \gamma + \theta + \eta} \: d \alpha d \beta d \gamma d \theta d \eta}[/tex]

[tex]\displaystyle \sf \green{5I=\int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \frac{ 3(\alpha + \beta + \gamma + \theta + \eta)}{\alpha + \beta + \gamma + \theta + \eta} \: d \alpha d \beta d \gamma d \theta d \eta}[/tex]

[tex]\displaystyle \sf \pink{5I=3\int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \int^{3}_{1} \: d \alpha d \beta d \gamma d \theta d \eta}

[/tex]

[tex]\large \sf \green{5I=3( {2)}^{5} }[/tex]

[tex]\large \sf \pink{I={ \frac{96}{5} }^{} }[/tex]

Answer:

I = 96/10 = 96:10 is your correct answer.

Answer:

  A.

Step-by-step explanation:

The attached graph has a y-intercept of -1 and a slope of 2, as the equation says it must.

__

The equation is in slope-intercept form, where the coefficient of x is the slope of the line. That is, the ratio of "rise" to "run" is 2: the line rises 2 grid squares for each grid square it runs to the right.

9514 1404 393

Answer:

Step-by-step explanation:

Let s represent the shortest side. Then the longest side is (s+10) and the middle side is (s+(s+10)-19). The perimeter is the sum of the sides.

  s + (2s-9) +(s+10) = 53

  4s +1 = 53

  s = (53 -1)/4 = 13

The side lengths are ...

rhombus opposite sides are equal.

So, CD = 15

Answer:

.............................

Answer:

120

Step-by-step explanation:

The LCM of 24 and 30 is 120. To find the least common multiple (LCM) of 24 and 30, we need to find the multiples of 24 and 30 (multiples of 24 = 24, 48, 72, 96 . . . 120; multiples of 30 = 30, 60, 90, 120) and choose the smallest multiple that is exactly divisible by 24 and 30, i.e., 120.

Answer:

Step-by-step explanation:

(fog)(x) = f[g(x)]

(fog)(x) = f[(4/x - 5)]

(fog)(x) = 1 / ((4/x - 5) - 9)

(fog)(x) = 1 / (4/x - 14)

(gof)(x) = g[f(x)]

(gof)(x) = g[1/(x - 9)]

(gof)(x) = (4/ 1/(x - 9)) - 5

(gof)(x) = (4•(x - 9)/1) - 5

(gof)(x) = (4x - 36) - 5

(gof)(x) = 4x - 41

Answer:

$159.99

Step-by-step explanation:

Step-by-step explanation:

let v is the speed of the wind,

the equation of the speed:

(550 + v ) × 5 = (550 - v) × 6

2750 +5v = 3300 - 6v

11v = 3300 - 2750

11v = 550

v = 550/11

v = 50

therefore, the speed of the wind =

50 mph

Step-by-step explanation:

5(550 + v) = 6(550 - v)

2.750 + 5v = 3.330 - 6v

5v + 6v = 3.300 - 2.750

11v = 550

v = 550 ÷ 11

v = 50mph

Answer:

A. and B.

Step-by-step explanation:

A. $34 - $10= $24 hourly fee divided by 3= $8 per hour.

B. $66 - $12= $54 hourly fee divided by 6= $9 per hour.

C.$92-$8= $84 hourly fee divided by 7= $12 per hour.

D. $52.5-$0= $52.5 hourly fee divided by 3.5= $15 per hour.

E. $112-$2=$110 hourly fee divided by 5.5= $20 per hour.

So Mia and Alex are the cheapest .

Answer:

C (Hypotenuse) = 9.9

Step-by-step explanation:

Given the two sides of a triangle, where a = 7, and b = 7:

We can use the Pythagorean Theorem where it states: c² = a² + b².

Substitute the given values into the Pythagorean Theorem to find the length of the hypotenuse.

c² = a² + b²

c² = 7² + 7²

c² = 49 + 49

c² = 98

[tex]\LARGE\mathsf{\sqrt{c^2}\:=\:\sqrt{98}}[/tex]

c = 9.89 or 9.9

Therefore, the length of the hypotenuse is 9.9, making the given triangle an isoceles triangle with two equal sides.

Its g is increasing

I guess you could just plug in 0, 1 and -1 and graph it.

Answer:

See down

Step-by-step explanation:

Mary served 22 orders, Jose served 16 orders and Aldo served 44 orders:

(Mary) 22 + (Jose) 16 + (Aldo) 44 = 82

Answer:

Both Prince and swallow were alike because both were kind, fully sympathy for the needy and suffering people. Both gave all which was there with them. the swallow gave his own life by carrying out all the errands commanded by the Prince.

Step-by-step explanation:

Answer:

➟ Two triangles are similar then ratio of their corresponding sides are equal.

(Option 3 is correct)

★ Criteria for similarity of two triangles

i.) Their corresponding angles are equal.

ii.) Their corresponding sides are proportional.

∆ABC ~ ∆DEF only if

∠A = ∠D

∠B = ∠E

∠C = ∠F

and

AB/DE

BC/EF

CA/FD

[ Some theorems ]

AAA - similarity

AA - similarity

SSS - similarity

SAS - similarity

Step-by-step explanation:

Answer:

L spedd

Step-by-step explanation:

Answer:

Both of the angles will add up to 180 degrees so let’s make an equation.

5x-5+2x+10=180

First we collect like terms

5x+2x-5+10=180

Add them up

7x+5=180

Move the constant to the right

7x=180-5

7x=175

7x/7=175/7

x=25

So yes it’s true x=25.

Now we find the respective angles,

5x-5

5(25)-5

125-5

120

So angle one is 120 degrees.

2x+10

2(25)+10

50+10

60

So angle two is 60 degrees.

Now to check,

120+60=180

Step-by-step explanation:

Step-by-step explanation:

2×10,000 + 8×1000 + 5×100+6×10+1

QUESTION :-

ANSWER :-

Take Lcm by the denominator ( check the pic )

Now subtract this

[tex] \frac{23}{15} [/tex]

=================================================

[tex] \large\rightarrow \tt 1 \frac{8}{15}[/tex]

=================================================

To solve the problem, let's find the LCM or Latest Common Multiple.

[tex]\tt5 \underline{ | \tt5, \: 3} \\ \tt3 \underline{ \tt |1, \: 3} \\ \: \: \: \: \tt1, \: 1[/tex]

[tex] \rightarrow [/tex] LCM = 5 x 3 = 15

[tex] \\ [/tex]

Since the LCM is already finished let's solve for the both numerator and denominator.

[tex]\rightarrow \: \tt3 \frac{1 \times 3}{5 \times 3} = 3 \frac{3}{15} \\ \\ \rightarrow \: \tt1 \frac{2 \times 5}{3 \times 5} = 1 \frac{10}{15} [/tex]

Since both of the fractions cannot be subtracted from each other, then let's make it to a improper fraction.

[tex] \rightarrow \: \tt3 \frac{3}{15} = 3 \times 15 + 3 = \frac{48}{15} \\ \\ \rightarrow \: \tt1 \frac{10}{15} = 1 \times 15 + 10 = \frac{25}{15} [/tex]

Now its time to subtract.

[tex]\rightarrow \: \tt \frac{48}{15} - \frac{25}{15} = \frac{23}{15} \: \: or \: \: 1 \frac{8}{15} [/tex]

Therefore, the answer is 1 8/15.

=================================================

[tex] \underline{{\sf \: \: \#CarryOnLearning! \: \:}} [/tex]

If there initially 12 grams of the substance, 5.35 grams will remain after 3 hours

The initial amount, a = 12 grams

The amount after 2 hours, y = 7 grams

Time taken, x = 2 hours

First, let us calculate the decay constant, b

The formula for the final value of an exponential decay is:

[tex]y=a(1-b)^x[/tex]

Substitute y = 12, a = 7, and x = 2 into the equation to solve for b

[tex]7=12(1-b)^2\\\\\frac{7}{12} = (1-b)^2\\\\0.583=(1-b)^2\\\\\sqrt{0.583} = 1 - b\\\\0.764=1-b\\\\b=1-0.764\\\\b=0.236[/tex]

The decay constant, b = 0.236

After 3 hours:

Substitute x = 3, a = 12, and b = 0.236 to solve for y

[tex]y=a(1-b)^x\\\\y=12(1-0.236)^3\\\\y = 5.35[/tex]

Therefore, 5.35 grams will remain after 3 hours

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