Personal values have a direct impact on how people treat personal and
nvironmental health. Explain this statement.

We must take into consideration the balance of atoms and charges in order to balance the half-reaction for the conversion of S2O3 2- to S4O6 2- in acidic solution.

Write the imbalanced half-reaction as the first step.

S2O3 S4O6 2- (aq)

Step 2: Align the atoms, with the exception of hydrogen and oxygen.

2S4O6 2-(aq) = S2O3 2-(aq)

Step 3: Add water (H2O) to balance the oxygen atoms.

2S4O6 2- (aq) + H2O = S2O3 2- (aq)

Step 4: Add hydrogen ions (H+) to balance the hydrogen atoms.

2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq)

Step 5: Add more electrons (e-) to balance the charge.

2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq) + 2e-

The balanced half-reaction in acidic solution is:

S2O3 2- (aq) + 4H+ (aq) + 2e- → 2S4O6 2- (aq) + H2O

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Answer:

The balanced chemical equation is:

3H2O + 2CO2 → 2H2CO3

Explanation:

The molarity of the 180.0 mL chloric acid, HClO₃ solution needed to neutralize the 440.0 mL of 1.75 M strontium hydroxide, Sr(OH)₂ is 8.56 M

We'll begin by writing the balanced equation for the reaction. This is given below:

2HClO₃ + Sr(OH)₂ —> Sr(ClO₃)₂ + 2H₂O

The molarity of the chloric acid, HClO₃ solution necessary can be obtained as follow:

MaVa / MbVb = nA / nB

(Ma × 180) / (1.75 × 440) = 2

Cross multiply

Ma × 180  = 1.75 × 440 × 2

Divide both side by 180

Ma = (1.75 × 440 × 2) / 180

Ma = 8.56 M

Thus, we can conclude that the molarity of the chloric acid, HClO₃ solution is 8.56 M  

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Complete question:

Given that 180.0 mL chloric acid (HCIO3) reacted with 440.0 mL of 1.75 M strontium hydroxide (Sr(OH)2). What is the molarity of HCIO3 necessary to neutralize Sr(OH)?

Wanted: [HCIO3] necessary to neutralize Sr(OH)?

Taking into account the reaction stoichiometry, 14.31 grams of Fe₂O₃ are formed when 10.0g of iron reacts with 20.0g of oxygen.

In first place, the balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 96 grams of O₂ reacts with 223.4 grams of Fe, 20 grams of O₂ reacts with how much mass of Fe?

mass of Fe= (20 grams of O₂ ×223.4 grams of Fe) ÷96 grams of O₂

mass of Fe= 46.54 grams

But 46.54 grams of Fe are not available, 10 grams are available. Since you have less mass than you need to react with 20 grams of O₂, Fe will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 223.4 grams of Fe form 319.7 grams of Fe₂O₃, 10 grams of Fe form how much mass of Fe₂O₃?

mass of Fe₂O₃= (10 grams of Fe×319.7 grams of Fe₂O₃)÷223.4 grams of Fe

mass of Fe₂O₃= 14.31 grams

Finally, 14.31 grams of Fe₂O₃ are formed.

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Answer:

Humans and animals are dependent on plants directly or indirectly for food. Only plants are autotrophs i.e., they are capable of synthesizing their own food. Animals are heterotrophs i.e., they are incapable of synthesizing their own food. They depend on plants and other animals for food. The man also being a heterotroph, gets his food from plants as well as animals.

Considering the ideal gas law, the total pressure at 27.0 °C if the gases are confined in a 2.00 L container is 13.3 atm.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

Where:

P is the gas pressure.

V is the volume that occupies.

T is its temperature.

R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.

n is the number of moles of the gas.

In this case you know:

mass of He= 1 gr

mass of N₂= 14 gr

mass of NO= 10 gr

molar mass of He= 4 gr/mole

molar mass of N₂= 28 gr/mole

molar mass of NO= 30 gr/mole

moles of He= mass of He÷ molar mass of He= 1 gr÷ 4 gr/mole= 0.25 moles

moles of N₂= mass of N₂÷ molar mass of N₂= 14 gr÷ 28 gr/mole= 0.5 moles

moles of NO= mass of NO÷ molar mass of NO= 10 gr÷ 30 gr/mole= 1/3 moles

total moles= moles of He + moles of N₂ + moles of NO= 0.25 moles + 0.5 moles + 1/3 moles= 13/12 moles

V= 2 L

R= 0.082 (atmL)/(molK)

T= 27 °C= 300 K

Replacing in the ideal gas law:

P×2 L = 13/12 moles×0.082 (atmL)/(molK)×300 K

Solving:

P= [13/12 moles×0.082 (atmL)/(molK)×300 K]÷ 2 L

P= 13.3 atm

Finally, the total pressure is 13.3 atm.

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Three changes could be made to a chemical system to shift the equilibrium to increase the yield of NH3 in the reaction [tex]N_{2} (g)[/tex] + [tex]3H_{2} (g)[/tex] → [tex]2NH_{3} (g)[/tex] + Heat are Increase the pressure, Decrease the temperature, and Add a catalyst.

1. Increase the pressure: According to Le Chatelier's principle, increasing the pressure will shift the equilibrium towards the side with fewer moles of gas. In this case, that means increasing the pressure on the left-hand side of the equation, where there are only two moles of gas (one [tex]N_{2}[/tex] and three [tex]H_{2}[/tex]), compared to the two moles of gas on the right-hand side (two [tex]NH_{3}[/tex]). By increasing the pressure, more of the reactants will be forced to react and produce more [tex]NH_{3}[/tex].

2. Decrease the temperature: The forward reaction in this equation is exothermic, meaning that it releases heat. According to Le Chatelier's principle, decreasing the temperature will shift the equilibrium towards the side of the equation that produces heat. In this case, that means shifting towards the products (the right-hand side). By decreasing the temperature, more [tex]NH_{3}[/tex] will be produced.

3. Add a catalyst: Adding a catalyst can increase the rate of the reaction, which can also shift the equilibrium towards the products. In this case, a catalyst like iron can be added to the reaction to increase the rate of [tex]NH_{3}[/tex] production. This will allow more [tex]NH_{3}[/tex] to be produced in the same amount of time, effectively increasing the yield.

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The charges present on the following ionic compounds are Ca²⁺, Mg²⁺, Cs⁺, Sc⁺, Al³⁺, S²⁻, F⁻, O²⁻, Cl⁻.

Ionic compounds are held together by ionic bonds are classed as ionic compounds. Elements can gain or lose electrons in order to attain their nearest noble gas configuration. The formation of ions (either by gaining or losing electrons) for the completion of octet helps them gain stability.

In a reaction between metals and non-metals, metals generally loose electrons to complete their octet while non-metals gain electrons to complete their octet. Metals and non-metals generally react to form ionic compounds.

Ionic compounds include salts, oxides, hydroxides, sulphides, and the majority of inorganic compounds. Ionic solids are held together by the electrostatic attraction between the positive and negative ions.

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Rotating a right triangle around its vertical axis will form a cone. The correct option is B.

The above one is basically the correct statement. When a two-dimensional shape is rotated around an axis, it creates a three-dimensional shape.

Rotating a right triangle around its vertical axis creates a cone because one of the sides of the triangle forms the curved surface of the cone, while the other side becomes the height.

The rotation axis goes through the apex of the triangle and creates a point at the other end of the curved surface.

Rotating a right trapezoid around its vertical axis would result in a frustum (a truncated cone). Rotating a square or rectangle around its vertical axis would form a cylinder, not a sphere.

Thus, the correct option is B.

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Answer:

Crystallization apparatus: (1) laboratory crucible furnace, (2) continuosly changeable transformer, (3) air cooler (“cold key”), (4) movable rings and (5) branched Tamman's test tube (“crystallization test comb”).

There are 64 neutrons in an atom of Q-123 with a charge of -1.

Since the isotope Q-123 has an atomic number of 59, we know that it has 59 protons. The charge of -1 tells us that the atom has one more electron than protons, so it has 60 electrons.

To find the number of neutrons, we need to subtract the atomic number (59) from the mass number (123):

Number of neutrons = Mass number - Atomic number

Number of neutrons = 123 - 59

Number of neutrons = 64

Hence there are 64 neutrons in an atom of Q-123 with a charge of -1. It is important to note that the charge does not affect the number of neutrons in the atom, only the number of electrons. The number of protons and neutrons in the nucleus of an atom determine its identity and chemical properties.

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The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm.

To calculate the pressure exerted by a column of mercury, we can use the formula:

Pressure = density * gravity * height

Given:

Density of mercury = 13.6 g/cm³

Height of the mercury column = 760 mm = 76 cm

Acceleration due to gravity = 9.8 m/s²

First, we need to convert the height of the mercury column from centimeters to meters:

Height = 76 cm * (1 m / 100 cm) = 0.76 m

Now, we can calculate the pressure:

Pressure = 13.6 g/cm³ * 9.8 m/s² * 0.76 m

To ensure consistent units, we need to convert the density from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³):

Density = 13.6 g/cm³ * (1 kg / 1000 g) * (1 cm³ / (1e-6 m³))

Density = 13600 kg/m³

Plugging in the values into the pressure formula:

Pressure = 13600 kg/m³ * 9.8 m/s² * 0.76 m

Pressure = 99992.8 Pa

We can express the pressure in terms of atmospheric pressure:

1 atm = 101325 Pa (approximately)

To compare the pressure with atmospheric pressure, we can convert 99992.8 Pa to atm:

Pressure in atm = 99992.8 Pa / 101325 Pa/atm

Pressure in atm ≈ 0.987 atm

The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm. Since atmospheric pressure near sea level is approximately 1 atm, this calculation supports the claim that atmospheric pressure near sea level is equivalent to the pressure exerted by a column of mercury about 760 mm high.

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