Please answer this correctly

Complete question is:

A hospital claims that the proportion, p, of full-term babies born in their hospital that weigh more than 7 pounds is 36%. In a random sample of 170 babies born in this hospital, 56 weighed over 7 pounds. Is there enough evidence to reject the hospital's claim at the level of significance?

Answer:

Yes, there is enough evidence to reject the claim.

Step-by-step explanation:

We are given;

n = 170

x = 56

So, will use one sample proportion test to solve this.

p^ = x/n

p^ = 56/170

p^ = 0.3294

Since the proportion, p, of full-term babies born in their hospital that weigh more than 7 pounds is 36%.

Thus;

Null Hypothesis H0: p ≠ 0.36

Alternative Hypothesis Ha: p = 0.36

Formula for test statistic = (p^ - p)/√(p(1 - p)/n)

This gives;

Test statistic = (0.3294 - 0.36)/√(0.36(1 - 0.36)/170)

Test statistic = -0.8311

From z-table and online z-calculator, the p - value is 0.203.

level of significance is; α = 0.05

Now, Since the p value < α, we reject the null hypothesis .

Thus, the claim is true

Answer:

9.222222222

Step-by-step explanation:

7+21+2+17+3+13+7+4+9 = 83

7+21+2+17+3+13+7+4+9 = 83 83÷9 = 9.222222222

_____________________________

Hey!!

Solution,

Given data=7,21,2,17,3,13,7,4,9

summation FX= 83

N(total no. of items)=9

Now,

Mean=summation FX/N

= 83/9

=9.23

So the answer is 9.23

__________________________

Answer:

12x+40

Step-by-step explanation:

A=l*w

A=20(3/5x+2)

A=4*3x+20*2

A=12x+40

Answer:

[tex] = 12x + 40[/tex]

Step-by-step explanation:

[tex]area = l \times b \\ = 20 \times (\frac{3}{5} x + 2) \\ = \frac{60x}{5} + 40 \\ = 12x + 40[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

The velocity is v(t) = 2*t + a

a) we want to find the average velocity betwen t = 0 and t = 1.

We can do this as:

Average = (v(1) + v(0))/2 = (2*1 + a + 2*0 + a)/2 = 1 + a

b) now we want to find the total distance traveled in the time lapse from t = 0 to t = 4.

For this we can see the integral:

[tex]d = \int\limits^4_0 {2*t + a} \, dt = 4^2 + a*4 - 0^2 - a*0 = 4^2 + a*4 = 16 + a^2[/tex]

Answer:

Step-by-step explanation:

If the profit realized by the company is modelled by the equation

P (x) = −0.5x² + 120x + 2000, marginal profit occurs at dP/dx = 0

dP/dx = -x+120

P'(x) = -x+120

Company's marginal profit at the $100,000 advertising level will be expressed as;

P '(100) = -100+120

P'(100) = 20

Marginal profit at the $100,000 advertising level is $20,000

Company's marginal profit at the $140,000 advertising level will be expressed as;

P '(140) = -140+120

P'(140) = -20

Marginal profit at the $140,000 advertising level is $-20,000

Based on the marginal profit at both advertising level, I will recommend the advertising expenditure when profit between $0 and $119 is made. At any marginal profit from $120 and above, it is not advisable for the company to advertise because they will fall into a negative marginal profit which is invariably a loss.

Answer:

94 more students should be included in the sample.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.99}{2} = 0.005[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.005 = 0.995[/tex], so [tex]z = 2.575[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

How many students we need to sample to be 99% sure that the sample mean x is within 1 semester hour of the population mean?

We need to survey n students.

n is found when M = 1.

We have that [tex]\sigma = 4.7[/tex]

So

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = 2.575*\frac{4.7}{\sqrt{n}}[/tex]

[tex]\sqrt{n} = 2.575*4.7[/tex]

[tex](\sqrt{n})^{2} = (2.575*4.7)^{2}[/tex]

[tex]n = 146.47[/tex]

Rounding up

147 students need to be surveyed.

How many more students should be included...?

53 have already been surveyed

147 - 53 = 94

94 more students should be included in the sample.

Answer:

y = -3/4x-1/4

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b

where m is the slope and b is the y intercept

y = -3/4x +b

We have a point (-5,4)

4 = -3/4 (-5) +b

Changing to a common denominator

16/4 = 15/4 +b

subtracting 15/4 from each side

16/4-15/4 = -15/4 +15/4 +b

1/4 = b

y = -3/4x-1/4

Answer:

book

Step-by-step explanation:

kmgktn

Answer:

16.25%

=0.163 (correct to 3 decimal places)

Step-by-step explanation:

The child dependency ratio of a population is defined as the number of children (Under 15 years) divided by the working-age population (15–64 years old).

[tex]\mathrm{ Child}\;\mathrm{ dependency}\;\mathrm{ ratio}=\dfrac{{\mathrm{ Population}\,\left( \text{Under 15} \right)}}{{\mathrm{ Population}\,\left( {15-64} \right)}}\times 100[/tex]

From the given table:

Population Under 15 years = 2600

Population of the working class (between 15-64) = 16000

Therefore:

[tex]\mathrm{ Child}\;\mathrm{ dependency}\;\mathrm{ ratio}=\dfrac{2600}{16000}\times 100\\\\=16.25\%[/tex]

=0.163 (correct to 3 decimal places)

Answer:

The expected value of profit is -$0.65.

Step-by-step explanation:

The rules of the lottery are as follows:

The probability of winning is, P (W) = 0.001.

Then the probability of losing will be,

P (L) = 1 - P (W)

       = 1 - 0.001

       = 0.999

Let the random variable X represent the amount of profit.

The probability distribution table of the lottery result is as follows:

Result      X        P (X)

Win      +349     0.001

Lose         -1       0.999

The formula to compute the expected value of X is:

[tex]E(X)=\sum X\cdot P(X)[/tex]

Compute the expected value of profit  as follows:

[tex]E(X)=\sum X\cdot P(X)[/tex]

         [tex]=(349\times 0.001)+(-1\times 0.999)\\\\=0.349-0.999\\\\=-0.65[/tex]

Thus, the expected value of profit is -$0.65.

The building height is 32 feet.

Let us consider that building height is x feet.

From attached diagram shown below,

Two triangles are formed.

Apply law of similarity of triangles.

Corresponding sides are in equal proportion.

                  [tex]\frac{x}{24}=\frac{12}{9} \\\\9x=12*24\\\\x=\frac{12*24}{9}=32 feet[/tex]

Learn more:

https://brainly.com/question/14285697

Answer:  A) 3 x 4

Step-by-step explanation:

The dimensions of a matrix are ROWS x COLUMNS.

The given matrix has 3 rows and 4 columns,

therefore the dimensions are: 3 x 4

Answer:

Step-by-step explanation:

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is [tex]\mathbf{P(X>1100n) = 0.158655}[/tex]

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy  is given as :

[tex]f_x(x) = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0[/tex]

Thus, the expected  total claim amount [tex]\mu[/tex] =  1000

The variance of the total claim amount [tex]\sigma ^2 = 1000^2[/tex]

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

[tex]P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})[/tex]

[tex]P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})[/tex]

[tex]P(X>1100n) = P(Z> \dfrac{10*100}{1000})[/tex]

[tex]P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345[/tex]

[tex]\mathbf{P(X>1100n) = 0.158655}[/tex]

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is [tex]\mathbf{P(X>1100n) = 0.158655}[/tex]

Answer: It’s 2

Step-by-step explanation:

look at picture

Answer:

Step-by-step explanation:

Your answer would be 1/2.

Because they are 2 coins and each have a probability of landing on tails.

The probability that both display tails are 1/2.

We have given that,

Two fair coins are flipped at the same time

We have to determine the, what is the probability that both display tails.

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates the impossibility of the event and 1 indicates certainty.

Because they are 2 coins and each has a probability of landing on tails.

To learn more about the probability visit:

https://brainly.com/question/25870256

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Answer: 1/4+3/8+1/2+5/8+7/8

= 21/8

Hope this helps :)))

Answer:

21/8

Step-by-step explanation:

Answer: recantagle

Step-by-step explanation:

Answer:

B.

Step-by-step explanation:

The cottage inside the pen is a shape of a cylinder.

Answer:

Cylinder

As u can see the shape it's like a cylinder

Answer:

Step-by-step explanation:

a) The first derivative helps considering f decreases or increases. Also, when f'(x) = 0, the function gets local max/min depends on how it acts.

The second derivative helps determining the concave up/down.

At x = -5, f"(-5) = -1 <0 That means the function f have concave down. Also, it shows f increases before -5 and decreases after -5.

Hence f'(-5) = 0 shows f gets maximum at -5.

b) At the point where f" =0, the function has a reflecting point and we need more information to determine if f has a local max/min there.

Using concepts of critical points, it is found that:

a) At x = −5, f has a local maximum.

b) At x = 1, f has neither a maximum nor a minimum.

-----------------------

A critical value of a function f(x) is a value of [tex]x^{\ast}[/tex] for which: [tex]f^{\prime}(x^{\ast}) = 0[/tex].

The second derivative test is also applied:

Item a:

At x = −5, f has a local maximum.

Item b:

At x = 1, f has neither a maximum nor a minimum.

A similar problem is given at https://brainly.com/question/16944025

Answer:

1/4 probability of getting a product that isn't divisible by 2.

Step-by-step explanation:

These are all the possible outcomes

1 x 1 = 1    2 x 1 = 2    3 x 1 = 3     4 x 1 = 4     5 x 1 = 5      6 x 1 = 6

1 x 2 = 2   2 x 2 = 4   3 x 2 = 6     4 x 2 = 8    5 x 2 = 10    6 x 2 = 12

1 x 3 = 3  2 x 3 = 6    3 x 3 = 9     4 x 3 = 12   5 x 3 = 15   6 x 3 = 18

1 x 4 = 4   2 x 4 = 8   3 x 4 = 12     4 x 4 = 16   5 x 4 = 20  6 x 4 = 24

1 x 5 = 5   2 x 5 = 10  3 x 5 = 15   4 x 5 = 20  5 x 5 = 25  6 x 5 = 30

1 x 6 =  6   2 x 6 = 12  3 x 6 = 18   4 x 6 = 24   5 x 6 = 30  6 x 6 = 36

All of the outcomes that aren't divisible by 2 are in bold

There are 9 out of 36 possible outcomes that aren't divisible by 2

9/36 = 1/4

Answer:

Step-by-step explanation:

The bottom (or top) of the U is called the vertex, or the turning point. The vertex of a parabola opening upward is also called the minimum point. The vertex of a parabola opening downward is also called the maximum point.

The x-intercepts are called the roots, or the zeros. To find the x-intercepts, set ax^2 + bx + c = 0.

The parabola is symmetric (a mirror image) about a vertical line drawn through its vertex (turning point). This line is called the axis of symmetry.

If possible, please mark brainliest

The quadratic function can be expressed in the form of vertex form and the parabola is symmetric about the line which is passing through focus.

The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2.

The important features for the graph of a quadratic function will be

The parabola is symmetric about the line which is passing through focus.

The quadratic function can be expressed in the form of vertex form.

Let the point (h, k) be the vertex of the parabola and a be the leading coefficient.

Then the equation of the parabola will be given as,

y = a(x - h)² + k

More about the quadratic equation link is given below.

https://brainly.com/question/2263981

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Answer: There is a 0.88% chance of pulling three red marbles in a row.

Step-by-step explanation:

First pull = 4/15 (26.67%)

second pull = 3/14 (21.43%)

Third pull = 2/13 (15.38%)

You need to multiply these three fractions to get the probability of pulling three reds in a row, doing that will get you 4/455 or 0.88%

Answer:

X=22/5

Step-by-step explanation:

By cross multiplication

5/2 =11/x

5x = 2(11)

5x =22

X=22/5

Hope this helps..

Answer:

  0.5 units

Step-by-step explanation:

The dilation factor is ...

  (GZ')/(GZ) = (GZ')/(GZ' +Z'Z) = 1.5/(1.5 +7.5) = 1/6

Side WX is 3 units, so side W'X' is (1/6)(3 units) = 1/2 units

W'X' is 0.5 units.

Answer:

It is .5 on edge

Step-by-step explanation:

I took the test

Answer:

No.

Step-by-step explanation:

A point has no length, height or depth. It only has position.

A line has one dimensional length.

Answer:

Step-by-step explanation:

Hello!

So in the refrigerator factory there are three shifts. Each shift records their quality based on the quantity of defective and working parts assembled.

Using a Chi-Square test of independence you have to test the claim that quality and shifts are independent.

The hypotheses are:

H₀: The variables are independent.

H₁: The variables are not independent.

α: 0.05

[tex]X^2= sum\frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~X_{(r-1)(c-1)}[/tex]

r= total number of rows

c= total number of columns

i= 1, 2 (categories in rows)

j=1, 2, 3 (categories in columns)

To calculate the statistic you have to calculate the expected frequencies for each category:

[tex]E_{ij}= \frac{O_{i.}*O_{.j}}{n}[/tex]

[tex]O_{i.}[/tex] Represents the marginal value of the i-row

[tex]O_{.j}[/tex] Represents the marginal value of the j-column

[tex]E_{11}= \frac{O_{1.}*O_{.1}}{n}= \frac{21*40}{120}= 7[/tex]

[tex]E_{12}= \frac{O_{1.}*O_{.2}}{n}= \frac{21*40}{120}= 7[/tex]

[tex]E_{13}= \frac{O_{1.}*O_{.3}}{n}= \frac{21*40}{120}= 7[/tex]

[tex]E_{21}= \frac{O_{2.}*O_{.1}}{n}= \frac{99*40}{120}= 33[/tex]

[tex]E_{22}= \frac{O_{2.}*O_{.2}}{n}= \frac{99*40}{120}= 33[/tex]

[tex]E_{23}= \frac{O_{2.}*O_{.3}}{n}= \frac{99*40}{120}= 33[/tex]

[tex]X^2_{H_0}= \frac{(7-7)^2}{7} + \frac{(5-7)^2}{7} + \frac{(9-7)^2}{7} + \frac{(33-33)^2}{33} + \frac{(35-33)^2}{33} + \frac{(31-33)^2}{33} = 1.385= 1.34[/tex]

Using the critical value approach, the rejection region for this test is one-tailed to the right, the critical value is:

[tex]X^2_{(c-1)(r-1);1-\alpha }= X^2_{2; 0.95}= 5.991[/tex]

Decision rule:

If [tex]X^2_{H_0}[/tex] ≥ 5.991, reject the null hypothesis.

If [tex]X^2_{H_0}[/tex] < 5.991, do not reject the null hypothesis.

The value of the statistic is less than the critical value, the decision is to not reject the null hypothesis.

At 5% significance level, you can conclude that the shift the pieces were assembled and the quality of said pieces are independent.

I hope this helps!

Answer:

a) 5/9

b) 1/3

Step-by-step explanation:

a) P(Die A or Die B) = P(red and red with Die A) + P(red and red with Die B)

                               = 4/6 × 4/6 +  2/6×2/6

                               = 5/9

b)  P(Die A or Die B) = P(red and red and red with Die A) + P(red and red and red with die B)

                           = 4/6×4/6×4/6 + 2/6×2/6×2/6

                          = 1/3

Answer:

[tex]P(15<X<20)=P(\frac{15-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{20-\mu}{\sigma})=P(\frac{15-17.15}{2.25}<Z<\frac{20-17.15}{2.25})=P(-0.96<z<1.27)[/tex]

And we can find the probability with this difference and using the normal standard table:

[tex]P(-0.96<z<1.27)=P(z<1.27)-P(z<-0.96)= 0.898-0.169 = 0.729[/tex]

Step-by-step explanation:

Let X the random variable that represent the wages, and for this case we know the distribution for X is given by:

[tex]X \sim N(17.15,2.25)[/tex]  

Where [tex]\mu=17.15[/tex] and [tex]\sigma=2.25[/tex]

We want to find this probability:

[tex]P(15<X<20)[/tex]

And we can use the z score formula given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Using this formula we have:

[tex]P(15<X<20)=P(\frac{15-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{20-\mu}{\sigma})=P(\frac{15-17.15}{2.25}<Z<\frac{20-17.15}{2.25})=P(-0.96<z<1.27)[/tex]

And we can find the probability with this difference and using the normal standard table:

[tex]P(-0.96<z<1.27)=P(z<1.27)-P(z<-0.96)= 0.898-0.169 = 0.729[/tex]

Answer:

15

Step-by-step explanation:

Because the two triangles are similar:

[tex]\dfrac{LN}{30}=\dfrac{6}{30-18} \\\\\\\dfrac{LN}{30}=\dfrac{6}{12} \\\\\\LN=30\cdot \dfrac{1}{2}=15[/tex]

Hope this helps!