Please help answer these!

It is polar or non polar is discussed below:

a) Beryllium chloride (BeCl2) is a linear molecule with two chlorine atoms on either side of the beryllium atom. Since the electronegativity of both chlorine and beryllium is similar, the bond between them is nonpolar. Therefore, BeCl2 is a nonpolar molecule. b) Hydrogen sulfide (H2S) is a bent molecule with the two hydrogen atoms and a sulfur atom. The sulfur atom has a higher electronegativity than the hydrogen atom, which leads to a polar covalent bond. Due to the bent shape of the molecule, the polar bonds do not cancel each other out, resulting in an overall polar molecule. c) Sulfur trioxide (SO3) is a trigonal planar molecule with three oxygen atoms surrounding a central sulfur atom. The electronegativity of oxygen is higher than that of sulfur, which creates polar covalent bonds. However, due to the symmetry of the molecule, the polar bonds cancel each other out, resulting in a nonpolar molecule. d) Water (H2O) is a bent molecule with two hydrogen atoms and one oxygen atom. The electronegativity of oxygen is higher than that of hydrogen, resulting in polar covalent bonds. Due to the bent shape of the molecule, the polar bonds do not cancel each other out, resulting in an overall polar molecule.

e) Trichloromethane (CHCl3) is a tetrahedral molecule with one carbon atom and three chlorine atoms. The electronegativity of chlorine is higher than that of carbon, resulting in polar covalent bonds. However, due to the tetrahedral shape of the molecule, the polar bonds do not cancel each other out, resulting in an overall polar molecule.

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The kind of assorted fruits that can be sold in school are Apples

Bananas, Oranges, Grapes, Pineapples, Mangoes, Strawberries, Blueberries, Kiwis, etc.

There are many different types of fruits that can be sold in schools, depending on availability, seasonality, and local preferences.

The following are some examples of assorted fruits that are commonly sold in schools;

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We can compare the solubility product constants (Ksp) values to establish the correct order of the solubilities of the iron compounds in water. The solubility of the substance in water is inversely correlated with the Ksp value.

Fe(OH)3 Ksp = 2.8 x 10(-39) is provided.

4.9 x 10(-17) Fe(OH)2 Ksp

3.5 x 10(-11) FeCO3 Ksp

Fe(OH)3 has the lowest Ksp value (2.8 x 10(-39)), which indicates the lowest solubility among the three compounds, when the Ksp values are compared. Similarly, FeCO3 is more soluble than Fe(OH)3 and has a higher Ksp value (3.5 x 10(-11)). Fe(OH)2 is the most soluble of the three compounds, as indicated by its greatest Ksp value (4.9 x 10(-17)).

As a result, the iron compounds' solubilities in water should be listed in the following order:

FeCO3 Fe(OH)2 Fe(OH)3

Therefore, "The order of solubilities is Fe(OH)3 FeCO3 Fe(OH)2" is the appropriate response.

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Answer:

The answer is C

3+

Explanation:

electron configuration =2,3

oxidation state of boron=3+

According  to the peaks depicted and the chemical formula the molecule is that of ethanol.

Chemical  formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols  of elements. It also makes use of brackets and subscripts.

Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form  is called empirical formula.

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Answer:

false shield volcanoes are the product of gentle effusive eruptions

Answer:

The answer is 223.8g/mol

Explanation:

RMM=1×39.1+1×1×79.9•8(2×1+1×16)

=39.9+79.9•8(2+16)

=119.8•8(18)

=119.8+114

RMM=223.8g/mol

A substance's cooling curve is a graph representing the change in temperature over time as it is allowed to cool. The gradient of the cooling curve is influenced by the heat capacity, thermal conductivity, and ambient temperature of the material. The correct option is A.

The rate of cooling for a sample with a known composition is measured in order to map the phase boundaries on a phase diagram. As the sample (or some piece of it) starts to go through a phase change, the rate of cooling will alter. When the temperature-time curve changes slope, these "breaks" will be visible.

In the cooling curve, the graph never meet with the time axis.

Thus the correct option is A.

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Answer:

y = 2x pv = 13 z = (2/x) 4 = (y/x) h = (9g/5) Inverse variation is represented by the equation y = k/x, where k is a constant.

Art Nouveau is perhaps the first historical artistic movement that comes to mind when thinking about the Neo-Traditional style and japan.

Thus, in order to comprehend Art Nouveau, one must first comprehend the context and symbolism that led to the development of the style.

Japan has cut off communication with the rest of the world by 1603. The floating world was determined to defend and preserve its culture, which was under severe attack from outside powers.

To debate the opening of Japan's heavily guarded gates, forty Japanese officials were dispatched to Europe in 1862, more than 250 years later. Goods from the two countries started to transcend oceans and lands to eagerly awaiting fingertips in order to reduce tensions between the countries and maintain stable Japan.

Thus, Art Nouveau is perhaps the first historical artistic movement that comes to mind when thinking about the Neo-Traditional style and japan.

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The manual aims to provide a detailed guide on the reaction between carbon dioxide (CO2) and water (H2O).

Title: Reaction of Carbon Dioxide and Water: A Comprehensive Manual

Introduction:

The manual aims to provide a detailed guide on the reaction between carbon dioxide (CO2) and water (H2O). This fundamental chemical reaction is of great significance in various fields, including environmental science, chemistry, and biology. Understanding the reaction mechanism, factors influencing the reaction, and its applications is crucial for researchers, students, and professionals in these disciplines.

Content:

Overview of the CO2 and H2O Reaction

Description of the reaction equation and its significance

Discussion on the role of CO2 and H2O in the environment and living organisms

Reaction Mechanism

Step-by-step explanation of the reaction mechanism

Exploration of the chemical bonds involved and energy changes during the reaction

Factors Influencing the Reaction

Temperature and pressure effects on the reaction rate

Catalysts and their role in accelerating the reaction

Concentration and pH considerations

Applications and Implications

Role of CO2 and H2O reaction in photosynthesis and respiration

Environmental impact of CO2 and H2O reaction, including greenhouse gas effects

Industrial applications, such as carbonation processes and carbon capture technologies

Experimental Techniques and Procedures

Laboratory methods for studying the CO2 and H2O reaction

Measurement techniques for analyzing reaction products and rates

Safety precautions and guidelines for conducting experiments

Conclusion:

This comprehensive manual serves as a valuable resource for individuals seeking a deep understanding of the reaction between carbon dioxide and water. By exploring the reaction mechanism, factors influencing the reaction, and its applications, readers can gain insights into the significance of this reaction in various scientific fields and its implications for the environment. The manual provides a foundation for further research and experimentation in this important area of study.

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A polar molecule is considered polar if it has a net dipole moment, meaning that the electron density is not evenly distributed around the molecule. Both H2O2 and NO2 are polar molecules, while N2H2 and CF2 are nonpolar molecules.

H2O2, or hydrogen peroxide, is a polar molecule due to its bent molecular geometry and the polarity of its O-H bonds. NO2, or nitrogen dioxide, is also a polar molecule because of its bent molecular geometry and the polarity of its N-O bonds. N2H2, or diazene, is a nonpolar molecule because its linear molecular geometry and nonpolar N=N bonds result in an even distribution of electron density. Finally, CF2, or difluoro methylene, is a nonpolar molecule due to its linear molecular geometry and the symmetrical distribution of its polar C-F bonds.

In summary, both H2O2 and NO2 are polar molecules, while N2H2 and CF2 are nonpolar molecules. The polarity of a molecule is an important factor in determining its physical and chemical properties, as well as its interactions with other molecules.

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Answer:

In hot water, molecules gain kinetic energy, therefore molecules in hot water have kinetic energy

while molecules of cold water have less or no kinetic energy

We can apply the concept of heat transmission to determine the water's final temperature. The heat acquired by the water offsets the heat lost by the metal.

Given: 200 g for the mass of water (m).

Water's initial temperature (T1) is 50 °C.

(Q) = 8400 J of heat is transferred from metal to water.

Water has a specific heat capacity (C) of 4.18 J/(g°C).

The following formula can be used to determine the heat transferred:

Q = m * C * ΔT

We may calculate the temperature change (T) by rearranging the equations as follows:

ΔT = Q / (m * C)

replacing the specified values:

T is equal to 8400 J / (200. g * 4.18 J/(g°C))

ΔT ≈ 10.048 °C

We multiply the original temperature by the temperature change to obtain the final temperature (T2):

T2 = T1 + T + 10.048 °C T2 = 50 °C + 10.048 °C

T2 ≈ 60.048 °C

As a result, the water's final temperature is around 60.048 °C.

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To inflate the self-inflating balloon to a volume of 2.3 L at a room temperature of 25 °C, approximately 25.7 grams of baking soda (sodium bicarbonate) and 19.7 grams of citric acid would be needed.

To calculate the amount of baking soda and citric acid needed to inflate a self-inflating balloon to a volume of 2.3 L at a room temperature of 25 °C, we need to consider the chemical reaction that occurs inside the balloon.

Self-inflating balloons typically contain a mixture of baking soda (sodium bicarbonate, NaHCO3) and citric acid (C6H8O7) powders. When these powders come into contact with water or moisture, a chemical reaction takes place, producing carbon dioxide gas (CO2) as a byproduct, which inflates the balloon.

The chemical equation for this reaction is:

3NaHCO3 + C6H8O7 → 3CO2 + 3H2O + Na3C6H5O7

From the balanced equation, we can see that 3 moles of sodium bicarbonate react with 1 mole of citric acid to produce 3 moles of carbon dioxide gas.

To calculate the amount of baking soda and citric acid needed, we need to know the molar volume of the gas at the given temperature and pressure. At room temperature and standard atmospheric pressure, the molar volume of an ideal gas is approximately 22.4 liters.

Since we want to inflate the balloon to a volume of 2.3 L, we divide this volume by the molar volume to get the number of moles of carbon dioxide gas required. In this case, it would be:

2.3 L / 22.4 L/mol ≈ 0.103 moles of CO2

Since 3 moles of sodium bicarbonate react with 1 mole of citric acid to produce 3 moles of carbon dioxide gas, we can conclude that we would need 0.103 moles of citric acid.

Similarly, 3 moles of sodium bicarbonate are required to produce 3 moles of carbon dioxide gas, so we would need 0.309 moles of sodium bicarbonate.

To convert moles to grams, we would need the molar mass of each compound. The molar mass of sodium bicarbonate is approximately 84 grams/mol, and the molar mass of citric acid is approximately 192 grams/mol.

Therefore, we would need:

0.309 moles of NaHCO3 x 84 g/mol ≈ 25.7 grams of baking soda (sodium bicarbonate)

0.103 moles of C6H8O7 x 192 g/mol ≈ 19.7 grams of citric acid

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Answer:

85Rb: 72.15%

87Rb: 27.85%

Explanation:

The average atomic mass of an atom is the sum of all [atomic abundance of isotope]*[mass of isotope].

Rubidium has only two isotopes, so let the atomic abundance of 85Rb be x, thus making the atomic abundance of 87Rb equal to 1-x.

[Average atomic mass of Rb] = [Mass of 85Rb]*[atomic abundance of 85Rb] + [Mass of 87Rb]*[atomic abundance of 87Rb]

85.4678 = 84.9117x + 86.9085*(1-x)

85.4678 = 84.9117x + 86.9085 - 86.9085x

85.4678 = 84.9117x + 86.9085 - 86.9085x

-1.4407 = -1.9968x

Atomic abundance of 85Rb = x = 0.7215 = 72.15%

Atomic Abundance of 87Rb = 1 - x = 1 - 0.7215 = 0.2785 = 27.85%

The true statement is [tex][Fe(OH_2)_6]^ 3^+[/tex] has a low-spin [tex]Fe^3^+[/tex] ion in an octahedral geometry. This anion allows for exchange of Tl+ with the [tex]Fe^3^+[/tex] in [tex][Fe(OH_2)_6]^ 3^+[/tex] by releasing [tex]4[Fe(CN)_6][/tex] in the urine.

Octahedral molecular geometry, also called square bipyramidal, describes the shape of compounds with six atoms or groups of atoms or ligands symmetrically arranged around a central atom, defining the vertices of an octahedron.

The mechanism of action of the compound [tex][Fe(OH_2)_6]_4[Fe(CN)_6]_3[/tex] is an involvement of  the exchange of the toxic Tl+ ion with the[tex]Fe^3^+[/tex] ion in [tex][Fe(OH_2)_6]^ 3^+[/tex]

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The mass percent of [tex]KNO_3[/tex] in the solution is approximately 1.91%.

To calculate the mass percent of [tex]KNO_3[/tex] in the solution, we need to divide the mass of [tex]KNO_3[/tex] by the total mass of the solution ([tex]KNO_3[/tex] + [tex]H_2O[/tex]), and then multiply by 100%:

mass percent = (mass of [tex]KNO_3[/tex] / total mass of solution) x 100%

The mass of [tex]KNO_3[/tex]is given as 16.5 g. To find the total mass of the solution, we add the mass of [tex]KNO_3[/tex] to the mass of [tex]H_2O[/tex]:

total mass of solution = mass of [tex]KNO_3[/tex] + mass of[tex]H_2O[/tex]

total mass of solution = 16.5 g + 848 g

total mass of solution = 864.5 g

Now we can calculate the mass percent:

mass percent = (16.5 g / 864.5 g) x 100%

mass percent = 1.91%

Therefore, the mass percent of [tex]KNO_3[/tex] in the solution is approximately 1.91%.

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The volume of 0.205 M K3PO4 solution necessary to completely react with 114 mL of 0.0118 M NiCl2 solution is 0.00437 L or 4.37 mL

The given chemical equation shows that two moles of K3PO4 react with three moles of NiCl2 to form one mole of Ni3(PO4)2 and six moles of KCl. Thus, the stoichiometric ratio of K3PO4 to NiCl2 is 2:3.

To calculate the volume of K3PO4 solution required to completely react with 114 mL of 0.0118 M NiCl2 solution, we need to use the concept of stoichiometry and the equation of concentration, C = n/V, where C is the concentration in moles per liter (M), n is the amount in moles, and V is the volume in liters.

First, we can calculate the amount of NiCl2 in 114 mL of 0.0118 M solution:

n(NiCl2) = C × V = 0.0118 M × 0.114 L = 0.0013452 mol

Next, we can use the stoichiometric ratio to calculate the amount of K3PO4 required:

n(K3PO4) = (2/3) × n(NiCl2) = (2/3) × 0.0013452 mol = 0.0008968 mol

Finally, we can use the equation of concentration to calculate the volume of 0.205 M K3PO4 solution required:

V(K3PO4) = n(K3PO4) / C(K3PO4) = 0.0008968 mol / 0.205 M = 0.00437 L

Therefore, the volume of 0.205 M K3PO4 solution necessary to completely react with 114 mL of 0.0118 M NiCl2 solution is 0.00437 L or 4.37 mL (to three significant figures).

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If more energy is absorbed than what is released during bond breaking and forming, the reaction is endothermic.

When bonds in the reactants are broken in endothermic reactions, greater energy is absorbed than emitted when new bonds are created in the products.

The energy required to break existing bonds in endothermic processes is more than the energy released when new bonds are generated. In an exothermic process, more energy is generated when new bonds are created than is consumed when old ones are broken.

If more energy is absorbed than what is released during bond breaking and forming, the reaction is endothermic.

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We must take into account the compound's dissociation into its corresponding ions and the subsequent hydrolysis of those ions in water in order to determine the pH of a 0.44 M sodium oxalate (Na2C2O4) solution.

Oxalate ions (C2O4-) and sodium ions (Na+) are produced when sodium oxalate breaks down. We concentrate on the hydrolysis of the oxalate ion instead because the sodium ion has neither acidic nor basic characteristics.

The oxalate ion can react with water to form hydroxide ions (OH-) and oxalic acid (H2C2O4). Oxalic acid (H2C2O4) has pKa1 = 1.27 and pKa2 = 4.28 as its pKa values.

Being a salt, sodium oxalate entirely separates into its ions. As a result, we can assume that the concentration of the oxalate ion (C2O4-) is the same as sodium oxalate's initial concentration, which is 0.44 M.

Now that the oxalate ion has been hydrolyzed, we need to figure out the concentration of hydroxide ions (OH-). We must take into account the equilibrium constant (Kw) for water, which is Kw = [H+][OH-] = 1.0 x 10-14, in order to accomplish this.

Since the ratio of oxalate to hydroxide ions in the hydrolysis reaction is 1:1, we can predict that the amount of hydroxide ions that are produced will be x M.

Consequently, we have the following expression for equilibrium:

[C2O4^2-][OH-] = x * x = x^2

Now, we need to calculate x, which represents the concentration of hydroxide ions in the solution. Since the concentration of hydroxide ions is small compared to the initial concentration of sodium oxalate, we can neglect its contribution to the 0.44 M concentration.

Using the approximation, we can simplify the equilibrium expression:

x^2 ≈ 1.0 x 10^-14

Solving for x gives:

x ≈ √(1.0 x 10^-14) ≈ 1.0 x 10^-7 M

Since we have determined the concentration of hydroxide ions (OH-), we can find the concentration of hydrogen ions (H+) using the equation:

[H+][OH-] = 1.0 x 10^-14

[H+] = 1.0 x 10^-14 / [OH-] = 1.0 x 10^-14 / (1.0 x 10^-7) = 1.0 x 10^-7 M

To calculate the pH, we use the equation:

pH = -log[H+]

pH = -log(1.0 x 10^-7) ≈ 7.00

Therefore, the pH of the 0.44 M sodium oxalate solution is approximately 7.00.

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The piece of information that you need to determine whether a molecule is an alkyne or an alkene is D. The type of C-C bonds in the molecule

Alkenes and alkynes can be decribed as the name that is been gotten by  by identifying the longest chain that contains the double or triple bond.

It should be noted that The chain is numbered  so that theminimization of  the numbers assigned to the double or triple bond can be easy however the suffix of the compound  can be “-ene”  when regarding to an alkene or “-yne” when regarding to alkyne.

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The volume of the gas in the tank at 293K and 3.0 atm pressure is 248 L. Hence, option B is correct.

Given:

T1 = 473K

T2 = 293K

P1 = 0.92 atm

P2 = 3.0 atm

The ideal gas law equation is:

PV = nRT

where P is pressure, V is volume, n is the number of moles of gas, R is the universal gas constant, and T is temperature.

n1 = (PV)/(RT)

= (0.92 atm × 500.0 L)/(0.0821 Latm/molK × 473K)

= 10.42 mol

Use the ideal gas law again to find the final volume of the gas in the tank under high pressure:

V2 = (n1 × R × T2)/P2

= (10.42 mol × 0.0821 Latm/molK × 293K)/(3.0 atm)

= 248 L

Therefore, the volume of the gas in the tank at 293K and 3.0 atm pressure is 248 L.

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Answer:

Using the ideal gas law, PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature in Kelvin, we can solve for n:

n = PV/RT

We know that the initial volume is 500.0 L, pressure is 0.92 atm, and temperature is 473K. We can use this information to find the initial number of moles:

n1 = (0.92 atm x 500.0 L)/(0.08206 L atm/mol K x 473K) = 11.80 mol

Next, we can use the ideal gas law again to find the final volume. We know that the final pressure is 3.0 atm and the final temperature is 293K:

V2 = nRT2/P2

V2 = (11.80 mol x 0.08206 L atm/mol K x 293K)/3.0 atm = 95 L

Therefore, the volume of the gas at the lower temperature and higher pressure is approximately 95 L. Answer: 95 L.

The mass percent of [tex]KNO_3[/tex] in the solution is approximately 1.91%.

To calculate the mass percent of [tex]KNO_3[/tex] in the solution, we need to divide the mass of [tex]KNO_3[/tex] by the total mass of the solution ([tex]KNO_3[/tex] + [tex]H_2O[/tex]), and then multiply by 100%:

mass percent = (mass of [tex]KNO_3[/tex] / total mass of solution) x 100%

The mass of [tex]KNO_3[/tex]is given as 16.5 g. To find the total mass of the solution, we add the mass of [tex]KNO_3[/tex] to the mass of [tex]H_2O[/tex]:

total mass of solution = mass of [tex]KNO_3[/tex] + mass of[tex]H_2O[/tex]

total mass of solution = 16.5 g + 848 g

total mass of solution = 864.5 g

Now we can calculate the mass percent:

mass percent = (16.5 g / 864.5 g) x 100%

mass percent = 1.91%

Therefore, the mass percent of [tex]KNO_3[/tex] in the solution is approximately 1.91%.

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The electron configuration for bromine is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁵ (option A).

Electron configuration is the arrangement of electrons in an atom, molecule, or other physical structure like a crystal.

Electron configuration is a summary of where the electrons are around a nucleus.

The symbols used for writing the electron configuration start with the shell number (n) followed by the type of orbital and finally the superscript indicates how many electrons are in the orbital.

According to this question, the electron configuration of bromine with an atomic number of 35 is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁵.

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Approximately 2.0933 ounces of bronze are needed in the preparation of the bronze figure

Bronze statue volume: 225 mL

Bronze has a density of 7.8 g/mL.

The volume is first converted from millilitres to ounces as follows:

Approximately 0.0338 fluid ounces make up 1 mL.

The formula for converting a bronze figure's liquid volume into ounces is (volume in mL) * (0.0338 fluid ounces/mL).

Next, we use density and volume to compute the mass of bronze:

Bronze's density is determined by multiplying its volume in ounces by its mass.

The mass can now be changed from grammes to ounces:

Approximately 0.0353 ounces make up 1 gramme.

Bronze's mass in ounces is equal to its mass in grammes multiplied by 0.0353 ounces per gramme.

Once the calculations are done, we have:

225 mL * 0.0338 fluid ounces/mL = 7.603 fluid ounces is the bronze figure's volume in ounces.

7.603 fluid ounces * 7.8 g/mL 59.2754 grammes is the mass of bronze.

Bronze mass in ounces is equal to 2.0933 ounces, or 59.2754 grammes multiplied by the ounces per gramme.

As a result, the bronze figure requires roughly 2.0933 ounces of bronze to prepare.

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