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The table summarizes results from pedestrian deaths that were caused by automobile accidents.
Pedestrian Deaths
Driver
Intoxicated?
Yes
No
Pedestrian Intoxicated?
Yes
No
51
83
263
592
If two different pedestrian deaths are randomly selected, find the probability that they both involved
pedestrians that were intoxicated.
Report the answer rounded to four decimal place accuracy.

Answer:

b

Explanation:

The outcome 0, 1, 1 has a sample mean of x-bar = (0+1+1)/3 = 2/3 = 0.667

For independent outcomes, the probability of an outcome is the product of the probabilities of each individual event, which in this case would be the probability of getting a 0, the probability of getting a 1, and the probability of getting another 1.

If we assume that the probability of getting a 0, a 1, or a 1 is the same (let's say p) the probability of getting the outcome 0, 1, 1 would be ppp = p^3

So the answer is A. x-bar = 0.667, p = p^3

Note that the question doesn't provide the probability of getting a 0, 1, or 1, so I assumed the probability is the same.

The probability that at least 20 of the novels have fewer than 400 pages is 0.086.

To find this probability, we can use the cumulative distribution function (CDF) of a binomial distribution. The binomial distribution models the number of successful outcomes in a fixed number of independent trials, where each trial has a probability of success.

In this case, the number of trials is 50, the number of successful outcomes is the number of novels with fewer than 400 pages, and the probability of success is 0.3 (30% of the novels have fewer than 400 pages).

The CDF of the binomial distribution gives the probability of having at most a certain number of successful outcomes. To find the probability of having at least 20 successful outcomes, we can subtract the probability of having less than 20 successful outcomes from 1:

[tex]P(X > = 20) = 1 - P(X < 20)[/tex]

Where X is the number of successful outcomes.

Using a binomial calculator, we can find that  [tex]P(X > = 20) = 0.086[/tex]

So the probability that at least 20 of the novels have fewer than 400 pages is 0.086.

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The probability that at least 20 of the novels have fewer than 400 pages is given as follows:

0.0823 = 8.23%.

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The parameters for the binomial distribution are given as follows:

p = 0.3, n = 50.

Hence the mean and the standard deviation for the approximation are given as follows:

Using continuity correction, the probability that at least 20 of the novels have fewer than 400 pages is P(x > 19.5), which is one subtracted by the p-value of Z when X = 19.5, hence:

Z = (19.5 - 15)/3.24

Z = 1.39

Z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823 = 8.23%.

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The principle is that to find the mean of the dataset, one would have to measure the height of all students and then calculate the mean.

The mean of the dataset is not provided, but rather a confidence interval for the mean is given. The confidence interval for the mean is calculated using the sample mean, sample standard deviation, and sample size, and it provides a range of values within which we can be certain the true population mean falls with a certain level of confidence (in this case, 95%).

Therefore, the principle is that to find the mean of the dataset, one would have to measure the height of all students and then calculate the mean. With the sample mean, sample standard deviation, and sample size, one can only calculate the confidence interval of the mean.

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