please help i need it fast

True. If E=0, at all points of a closed surface that means there is no electric field present. Therefore, electric flux should also be zero.

This leads us to the Gauss's Law, which says that the electrical flux going through a closed surface, is that the sum of all charges Q inside that closed surface, divided by permittivity of free space E₀. If that flux is zero, meaning there is no net charge inside the shape.

The net flux through a closed surface is a quantitative measure of the net charge inside a closed surface. 2. the web electric flux through any closed surface surrounding a net charge 'q' is independent of the shape of the surface.

The flux of an electrical field through a closed surface will be always zero if and only if there is no net charge in the volume enclosed by the surface. the quantity of electric flux is always proportional to the charges inside the surface

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The tall would be 2 x [tex]10^{-6}[/tex] m

Given

Use D1 and D2 to represent the old and new diameters.

D1 =  2 x [tex]10^{-8}[/tex]

D2 = 1cm

To determine how tall you'd be, we need to divide D2 by D1:

Ratio = [tex]\frac{D2}{D1}[/tex]

Substitute values for D2 and D1

Ratio = [tex]\frac{2*10^{-8} }{1cm}[/tex]

Convert cm to m

Ratio = [tex]\frac{2*10^{-8} }{0.01}[/tex]

Convert denominator to exponents

Ratio = [tex]\frac{2*10^{-8} }{10^{-2} }[/tex]

Apply the Law of indices

Ratio = [tex]2*10^{-8} *10^{2}[/tex]

Ratio = [tex]2*10^{-8+2}[/tex]

Ratio = [tex]2*10^{-6}[/tex]

Therefore [tex]2*10^{-6}[/tex]m time falls.

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By the half-life of radioactive, the decay constant is 0.144 /s.

We need to know about the half-life of the radioactive elements to solve this problem. The radioactive element will decay over time and follow the equation

N = No(1/2)^(t/t'')

λ = ln2 / t''

where N is the final quantity, No is the initial quantity, λ is the decaying constant, t is time and t'' is the half-life of a radioactive element.

From the question above, we know that

t = 18.3 s

No = 175 kbq

N = 12.4 kbq

Calculate the half-life

N = No(1/2)^(t/t'')

12.4 = 175(1/2)^(18.3/t'')

(1/2)^(18.3/t'') = 62/875

18.3/t'' = ⁰'⁵log(62/875)

18.3/t'' = 3.82

t'' = 4.79 seconds

Determine the decay constant

λ = ln2 / t''

λ = ln2 / 4.79

λ = 0.144 /s

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The frequency ()of photons to break the O-H bond is 1.1704 ✕ 1015 Hz.

Here, it is given that

The bond energy of O-H per mole=E =467 kJ/mol

Convert the unit of bond energy from kJ to J by using a conversion factor:

1kJ =1000 J

467 kJ/mol = 467 ✕ 103 J /mol

Determine the bond energy for 1 molecule of water (H2O) as:

E = Bond energy per mole / Avogadro’s number (NA)

E = (467 ✕ 103 ) / (6.022 ✕ 1023 )

=  77.55 ✕ 10-20 J

Thereby, the energy required to break 1 molecule of H2O is 77.55 ✕ 10-20 J

Now, determine the frequency in Hz by using a relation:

E=h

Where ‘’ is the frequency of the photon and ‘h’ is the Planck’s constant whose value is 6.626  ✕ 10-34 J/s.

Putting all the values we get,

(77.55 ✕ 10-20 J) = (6.626  ✕ 10-34 J/s) ✕

= (77.55 ✕ 10-20 J) / (6.626  ✕ 10-34 J/s)

= 11.704  ✕ 1014 s-1

= 1.1704 ✕ 1015 s-1

So,  =1.1704 ✕ 1015 Hz

Therefore, the frequency ()of photons to break the O-H bond is 1.1704 ✕ 1015 Hz.

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Answer:

[tex]0.70\; {\rm kg}[/tex].

Explanation:

If an object of mass [tex]m[/tex] is travelling at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of that object would be [tex]p = m\, v[/tex].

In this question, both momentum [tex]p[/tex] and velocity [tex]v[/tex] are given, and mass [tex]m[/tex] needs to be found. Hence, rearrange the equation [tex]p = m\, v[/tex] and solve for [tex]m\![/tex]:

[tex]\begin{aligned} m &= \frac{p}{v} \\ &= \frac{3.22\; {\rm kg \cdot m \cdot s^{-1}}}{4.6\; {\rm m\cdot s^{-1}}} \\ &= 0.70\; {\rm kg}\end{aligned}[/tex].

Therefore, the mass of this ball would be [tex]0.70\; {\rm kg}[/tex].

Option C) Infinite charge has passed through the Circuit

Alternating current, also known as AC, is an intermittent electric charge flow.

It might begin at zero, increase to a maximum, decline to zero, turnabout, reach a maximum in the opposite direction, return to the starting value once more, and repeat this cycle indefinitely.

Both the current we receive from our home power outlets and the current generated by generators or turbines are AC currents. Most electrical appliances, including fans, bulbs, air conditioners, and motors, operate on AC current.

In contrast to direct current (DC), which only travels in one direction and cannot sporadically shift, alternating current (AC) is an electric current that periodically reverses direction.

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A plane traveling north at 200 m/s turns and then travels south at 200 m/s. the change in its velocity is 400 m/s in the south direction.

A particle or object's movement with respect to time is expressed vectorially as velocity.

The meter per second (m/s), usually referred to as speed, is the accepted unit of velocity magnitude.

As an alternative, the velocity magnitude can be expressed in centimeters per second (cm/s).

The rate of something moving in a specific direction is called its velocity. Using an automobile driving north on a highway as an example, or a rocket after it has launched, as an example of speed.

Scalar implies that the velocity vector's absolute value magnitude will always equal the motion's speed.

ΔV = V1 - V2

ΔV = 200 - (-200)

ΔV = 200+200 = 400 m/s

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(a) The change in momentum of the girl is 736.32 Kg-m/s ( Downwards).

(b) The Impulse in the net is 736.32 Kg-m/s.

(c) The Average force on the net is 1635.86 N.

(a) Let us say, the mass of the girl to be M.

The height of the window is 12m.

When the girl jumps out of the window it becomes a case of free fall so we can apply the equations of motion because downward acceleration as constant. The initial velocity U of the girl is zero.

The final velocity of the girl on reaching the ground is V.

V = √2gH

V = √2x9.8x12

V = √235.2

V = 15.33 m/s.

Now, we know that.

Change in momentum (Δp) = M(V-U)

Δp = 48(15.33-0)

Δp = 736.32 Kg-m/s (Downwards).

(b) The impulse on the net will be equal to the change in momentum of the girl i.e. 736.32 Kg-m/s, because the net was initially at rest and the final velocity of the net is same as that of the girl. Impulse is nothing but change in momentum.

(c) From the Impulse-Momentum theorem, We know that,

Average net force (F) = Δp/Δt

Here change in momentum is 736.32 Kg-m/s.

total change in time is 0.45 seconds.

So, the net average force will be,

F = 736.32/0.45

F = 1635.86 N.

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It is false. The period of a pendulum clock increases if you increase the length of the pendulum.

The time period of a pendulum clock is directly proportional to the square root of the length.

The formula of the time period of a simple pendulum is:

                                       T = 2π√(l/g)

According to the formula, time period T is directly proportional to the square root of length and inversely proportional to gravity. The time period will increase if we increase the length of the pendulum clock.

For example, the time period will increase by two times if we increase the length of the pendulum by four times.

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False, the period of a pendulum clock does not decreases if you increase the length of the pendulum. Their variation is directly proportional.

The square root of the length of a simple pendulum determines its period in a direct proportion. In other words, as length grows, so does the amount of time.

The relationship between two values where their ratio equals a constant number is known as a direct proportion or direct variation. In our case, the two values are.

1. Square root of the length of the pendulum

2. Period of a pendulum

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The peak (+ve half) and trough (-ve half) portions of the waveform signal flatten out or are "Clipped-off" when the input amplitude is too high, forcing the output waveform signal to exceed the power supply voltage rails.

Over the whole auditory range of frequencies from 20 Hz to 20 kHz, the majority of contemporary audio amplifiers exhibit the same flat frequency response as seen above. The Bandwidth (BW) of an audio amplifier, which is mostly influenced by the circuit's frequency response, is the range of frequencies it can handle. The power in the high frequency band, from 8 to 24 Hz, divided by the power in the low frequency band, from 3 to 5 Hz, is known as the frequency ratio.

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According to photoelectric effect, the threshold frequency of metal is 1.42 x 10¹⁵ Hz.

We need to know about the photoelectric effect to solve this problem. The photoelectric effect is electron ejected from metal because of light source. The kinetic energy of the ejected electron is

K = h(f - fo)

where K is kinetic energy, h is Max Planck constant (6.6 x 10¯³⁴ Js), f is the frequency of light source and fo is the threshold frequency of the metal.

From the question above, we know that

λ = 200 nm = 200 x 10¯⁹ m

v = 3.4 x 10⁵ m/s

me = 9.1 × 10¯³¹ kg

Find the frequency of light source

f = c / λ

f = 3 x 10⁸ / (200 x 10¯⁹)

f = 1.5 x 10¹⁵ Hz

Find the threshold frequency

K = h(f - fo)

1/2 . me .v² = 6.6 x 10¯³⁴ (1.5 x 10¹⁵ - fo)

1/2 . 9.1 × 10¯³¹ . (3.4 x 10⁵)² = 9.9 x 10¯¹⁹ - 6.6 x 10¯³⁴fo

9.9 x 10¯¹⁹ - 6.6 x 10¯³⁴fo = 5.26 x 10¯²⁰

6.6 x 10¯³⁴fo = 9.37 x 10¯¹⁹

fo = 1.42 x 10¹⁵ Hz

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The current drawn by the load is 9.17 A.

Current can be defined as the rate of flow of electric charge round a circuit.

To calculate the current drawn by the load, we use the formula below.

Formula:

Where:

From the question,

Given:

Susbtitute these values into equation 1

Hence, the current drawn by the load is 9.17 A.

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Answer:

E = - dΦ / dt

(b) would be the correct answer

Through accountability and open disclosure, CMS's core measures lessen the load on providers and enhance patient care in an effective and efficient manner.

Eligible professionals (EP), critical access hospitals, and eligible hospitals offer healthcare services that are measured and tracked by electronic clinical quality measures (eCQMs), which are produced by a provider's electronic health record (EHR). Reporting and tracking eCQMs enables the health care system to deliver timely, patient-centered, effective, safe, efficient, equitable treatment. Health care providers electronically submit eCQMs, which measure high quality treatment using information from EHRs and other health IT systems.

Health care providers follow up with the eCQMs and needs that the CMS quality programme has identified. Regulatory reporting is an efficient instrument that ensures correct, on-demand reporting by gathering reports and submitting data to CMS in accordance with regulatory requirements. Reduced provider workload and expense due to the CMS metric introduced to NQF. It might be challenging to achieve the patient regulatory criteria for meaningful use (eCQMs) reporting. Its primary metrics don't entirely correspond to requirements for high-quality healthcare.

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2Q charge should it have on its plates.

The electric field between plates is the area or space where the plates' charge influences can be seen.

For example, if a charged particle is placed near any charged plate, the plate exerts an electric force to attract or repel the charged particle.

Either positive or negative charges are present in charged particles.

Since electrons are always negatively charged, a negatively charged particle carries more electrons (negative charges) than protons (positive charges).

Therefore, there must be fewer electrons than protons in order for charged particles to be positive.

A plate becomes positively or negatively charged when charged particles are placed on it, and a charged plate generates an electric field all around it.

Gauss's law is shaped by the surface.

Calculating the area of shapes with a defined geometry is simple.

The Gauss's law equation can be written as the surface charge density divided by the medium's electric permittivity in the case of a sphere or rectangular plate.

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Individual characteristics are demonstrated by the unique pattern of bullets fired from every gun model

There are two types of characteristics. They are class characteristics and individual characteristics. Class characteristics helps to place an evidence into a group of objects whereas individual characteristics narrows down the evidence to a particular object.

For example, a type of blood group is a class characteristic because it belongs to a group of humans. But DNA taken from the blood is a individual characteristic because it belongs to only one human on the entire planet.

Therefore, Individual characteristics are demonstrated by the unique pattern of bullets fired from every gun model

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Answer:

rotation is a day and revolution is 365 days

The average velocity of the ball is 1.14 m/s.

Since there is no height given, we can assume that the ball was rolling on a non-inclined surface.

Distance covered by the ball = 18 meters

Time taken by the ball = 15.7 seconds

The velocity of the ball = Distance / Time taken

Velocity= 18/15.7

Velocity= 1.14 m/s

and since there is no initial velocity given, it is the average velocity of the ball.

The distance traveled divided by the time passed is the definition of an object's average speed. Average velocity can be calculated as the displacement divided by the time. Velocity is a vector quantity. The straight line average velocity formulae are invalid for broad scenarios involving non-constant acceleration, hence this definition must be used directly.

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Answer:

They are maintaining tension with an equal force on all sides.

Fez engages in team activities such as running or passing the ball, then muscles maintain tension with an equal force on all sides. Hence, option B is correct.

Exercise is the training of the body to increase fitness and function.

Although the phrases physical activity and exercise are sometimes used synonymously, this article will make a distinction between the two. Physical activity is a broad phrase that refers to any energy expenditure caused by skeletal muscle action. As a result, it encompasses the full range of activity, from deficient resting levels to maximal exertion. Physical activity includes exercise.

Exercise stands apart because it is a systematic activity designed with physical fitness development and maintenance in mind. Physical fitness growth through the body's and its various systems' adaptation to a workout regimen is referred to as physical conditioning.

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The   increase  by a factor of 2 is sufficient to change the applied voltage in a circuit if we  want to increase the power by a factor of 4 by keeping the resistance constant.

Simple formula is:

Voltage (V) = Current (I) X Resistance (R)

Thu if R is constant and V is increased I will reduce

Thus assuming a constant Resistance , increasing the Voltage will reduce the current in the circuit.

Applied voltage :

Voltage applied to a circuit is equal to the sum of the individual voltage drops. The drop across a resistor in a series circuit is directly proportional to the size of the resistor. If the circuit is broken at any point, no current will flow.

What happens when voltage is applied to a resistor?

Therefore, if the voltage is increased, the present will increase provided the resistance of the circuit does not change. Similarly, increasing the resistance of the circuit will lower the present flow if the voltage is not changed

Why is voltage applied?

When a voltage is applied, it's energetically preferable for an electric charge to move towards the point of lowest voltage in the wire; that's a fancy way of saying that a positive electric charge gains energy when going from a point of high voltage to a point of low voltage.

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Quiet inspiration will increase thoracic and lung volume and decrease intrapulmonary pressure.

Boyle's Law is the law that determines the relationship of the pressure of a gas with respect to the volume of the container. Here the pressure of gas exists as inversely proportional to the volume of the particular container.

This is one of the major principles which is important for understanding various processes of events occurring during pulmonary ventilation. If there is an increase in the volume of a container takes place, the pressure will gradually decrease.

Quiet inspiration will result in increasing thoracic as well as lung volume and is likely to decrease intrapulmonary pressure. Since the inspiratory muscles get contract to increase the thoracic cavity volume as this will cause an increased volume of the lungs as well. Then gradually there will be an increase in the volume of the lungs that lowers the intrapulmonary pressure which exists below atmospheric pressure.

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Answer: Block A - 19.3

Block B - 0.64

Block C - 0.70

Block D - 0.917

Block E - 3.53

Explanation: i hope this helps you a little

The molarity of the solution is 0.0293 m. 1.928 g of kno3 are dissolved in 651 ml of water.

The amount of a substance in a solution stated as an amount of substance per unit volume of solution is known as molar concentration, also known as molarity, quantity concentration, or substance concentration. The most common unit used in chemistry to express molarity is the number of moles per liter, represented by the unit sign mol/L or mol/dm3 in SI units. One molar, or 1 M, of a solution is defined as one mol/L.

The use of molar concentration in thermodynamics is typically not applicable because the volumes of most solutions very minimally change with temperature due to thermal expansion.

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The minimum initial velocity u = 58.3°

(v0) min = 9.76 m/s

Coordinate System: The coordinate system will be set so that its origin coincides with the ball’s initial position.

x-Motion: Here (v0) = v0 cos u x0 and x = 6 m Thus,                

 (+)     x = [tex]x_{0}[/tex] + (v0)xt

           6 = 0 + (v0 cos u)t

           t = 6/v0 cos u                                       (1)          

y-Motion: Here (v0)x = v0 sin u, ay = -g = -9.81m/s  and y0 = 0  

   ( A + c B)    y = y0 + (v0)y t +1/2 [tex]a_{y}[/tex][tex]t^{2}[/tex]

                      3 = 0 + v0 (sin u)t + 1/2 (-9.81) [tex]t^{2}[/tex]

                       3 = v0 (sin u)t - 4.905[tex]t^{2}[/tex]               (2)

Substituting Eq. (1) into Eq.(2) yields

        v0 = [tex]\sqrt[2]{\frac{58.86}{sin 2u - cos2 u} }[/tex]                                       (3)

From Eq. (3), we notice that is minimum when is

maximum. This requires [tex]\frac{df(u)}{du}[/tex]

[tex]\frac{df(u)}{du}[/tex] = 2 cos2u + sin2u = 0

tan2u = -2

2u = 116.57°

u = 58.28° = 58.3°

Substituting the result into Eq.(2), we have

(v0)min = [tex]\sqrt[2]{\frac{58.86}{sin 116.57° - cos2 58.28°} }[/tex]

(v0)min =  9.76 m/s

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The beam used is a negatively charged electron beam with a velocity of

v = E / B where E is the electric field and B is a magnetic field.

Now indicates that the electric field and the magnetic field are contracted and that the beam passes without deviating, so the electric and magnetic forces must be balanced

        Fe = Fm

        q * E = q * v * B

        v = E / B

this configuration is called speed selector.

The beam used is a negatively charged electron beam with a velocity of v = E / B.

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Although part of the question is missing the complete question is A depiction of a famous scientific experiment is given. Consider how the beam changes when the magnet is off compared to when the magnet is on. A bell-shaped evacuated glass tube with a narrow end and a wide end is connected to a battery at the narrow end. In the center of the tube there is a negatively charged plate above the tube, a positively charged plate below the tube, and a magnet with the field turned off. A beam originating at the narrow end of the tube travels toward the wide end of the tube. With the magnetic field turned off, the beam path bends toward the positively charged plate and ends at the lower half of the wide end of the tube. A bell-shaped evacuated glass tube with a narrow end and a wide end is connected to a battery at the narrow end. In the center of the tube there is a negatively charged plate above the tube, a positively charged plate below the tube, and a magnet with the field turned n. A beam originating at the narrow end of the tube travels toward the wide end of the tube. With the magnetic field turned on, the beam path travels in a straight path to the center of the wide end of the tube. What type of beam was used in this experiment?

Answer:

UN balanced force to applied on that object

The friction force applied to the block performs nonconservative work

on the system.

The formula of the friction force F = μN

where,

F = friction force

μ = coefficient of friction

N = normal force

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