Please Help if pQ = 6n QR=3 and PR=27 find n and PQ

Answer: x^29

Step-by-step explanation:

x^11 * x^18=

x^(11+18)=x^29

Answer:

= x²⁹

Step-by-step explanation:

x¹¹ · x¹⁸

= x¹¹ ⁺ ¹⁸

= x²⁹

Answer:

Step-by-step explanation:

I think you meant

-0.4 - x = -6(x - 3.1) + 6x

-0.4 - x = -6x + 6x + 18.6

-0.4 - x = 18.6

       -x = 18.6 + 0.4

       -x/-1 = 19/-1

           x = -19

check

-0.4 - (-19) = -6(-19 - 3.1) + 6(-19)

           18.6 = -6(-22.1) + (-114)

           18.6 = 132.6 - 114

           18.6 = 18.6

Answer:

15

Step-by-step explanation:

9 seeds in 3 packets is a 3:1 ratio which means that there are 3 seeds per packet. With 5 packets you simply multiply 5 by 3

The unknown angles when line BD bisect the angle ABC is as follows:\

An angle bisector divides and angle into 2 equal angles.

Therefore, line BD bisect angle ABC.

Hence,

let's find m∠ABD

if m∠ABD = 6x + 4

m∠DBC =  8x - 4

Therefore,

m∠ABD  = m∠DBC

6x + 4 = 8x - 4

6x - 8x = -4 - 4

-2x = -8

x = -8 / -2

x = 4

Therefore,

m∠ABD = 6x + 4 = 6(4) + 4  = 24 + 4 = 28°

let's find m∠ABC

If m∠ABD = 5y - 3

m∠DBC = 3y + 15

Hence,

m∠ABD = m∠DBC

5y - 3 = 3y + 15

5y - 3y = 15 + 3

2y = 18

y = 18 / 2

y = 9

Therefore,

m∠ABC = m∠ABD +  m∠DBC

m∠ABC = 5(9) - 3 + 3(9) + 15

m∠ABC = 45 - 3 + 27 + 15

m∠ABC = 84°

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Approximately 17 ribbons of ¾ yards can make from a 12 ½ yards of ribbon

Given,

The length of ribbon Mary had with her = 12 ( ½ ) yards

Length of single piece of ribbon = ¾ yard

We have to find the number of pieces of ribbon made by Mary:

Then,

Number of pieces of ribbon = (Total length of ribbon / Length of single piece of ribbon)

Number of pieces of ribbon = (12 ( ½ ) / ¾ ) = (25/2) / ¾  = (25 x 2) / 3 = 50/3 = 16.66 ≈ 17

Approximately 17 ribbons of ¾ yards can make from a 12 ½ yards of ribbon.

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Answer:

1600

Step-by-step explanation:

1600

Answer:

1600

Step-by-step explanation:

The value of the expression 6 - 1/4 - 2(1/1) as a mixed number is 2( 3/4 ).

Fraction: A number that is stated as a quotient in mathematics, when the numerator and denominator are divided. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. A suitable fraction has a numerator that is less than its denominator.

Consider the expression,

6 - 1/4 - 2(1/1)

Let x = 6 - 1/4 - 2(1/1)

First solving the mixed fraction,

x = 6 - 1/4 - 2(1/1)

x = 6 - 1/4 - ( (2 ×1 + 1) / 1 )

x = 6 - 1/4 - ( 2 +1 / 1)

x = 6 - 1/4 - 3

x = 3 - 1/4

x = ( 12 - 1)/4

x = 11/ 4

x = 2( 3 /4 )

The value of 6 - 1/4 - 2(1/1) as a mixed fraction is 2( 3/4 ).

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Answer/Step-by-step explanation:

1)

   3              ?

|-------|-----------------------|

G      H                         I

|<---------------------------->|

              14

3 + ? = 14

-3          -3

? = 11

HI = 11

2)

    9              ?

|---------|---------------------|

E         F                      G

|<---------------------------->|

               21

9 + ? = 21

-9         -9

? = 12

FG = 12

3) Find RS

Q----------------R-----S-----------------T

|<----------------------------------------->|

                      19

|<---------------------->|

              10

                     |<----------------------->|

                                  10

QS = 10

QR = 9

RT = 10

ST = 9

RS = 1

4) Find SV

                             7

S-----------------T-------------U--------V

                     |<---------------------->|

                                   8

|<--------------------------------->|

                   12

SU = 12

TV = 8

TU = 7

UV = 1

ST = 5

SV = 13

5) Solve for x

       2x + 29            4

M--------------------L---------K

  |<---------------------------->|

             x + 22

2x + 29 + 4 = x + 22

2x + 33 = x + 22

-x            -x

x + 33 = 22

  -33      -33

x = -11

6) Solve for x

  2x + 14      x + 11

J-------------I-------------H

 |<------------------------>|

              10

2x + 14 + x + 11 = 10

3x + 25 = 10

     -25     -25

3x = -15

÷3     ÷3

x = -5

I hope this helps!

The 10th term of an arithmetic sequence is found to be a₁₀ = 115.

In Arithmetic Progression, the difference between two mathematical orders is a constant quantity (AP). Arithmetic Sequence is another name for it.

We'd come across a few specific terms in AP that had been labeled as:

As shown below, the AP can also be viewed in analysed in terms of common differences.

Now, as per the given question;

Let the 9th term be 'a₉' = 132.

The 11th term be 'a₁₁' = 98.

The 10th term be 'a₁₀'.

The AP must have contain equal common difference. So,

d = a₁₀ - a₉

d = a₁₀ - 132

And, also

d = a₁₁ - a₁₀

d = 98 - a₁₀

Since, a₁₀ - a₉ = a₁₁ - a₁₀ for forming an AP.

Equate the common difference.

a₁₀ - 132 = 98 - a₁₀

Bring the variable part on single side.

2a₁₀ = 98 + 132

2a₁₀ = 230

a₁₀ = 115.

Therefore, the value of the 10 th term is estimated as a₁₀ = 115.

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Answer:

b=100 c=80

Step-by-step explanation:

The elevation of -10 feet is farther from the surface level of the ocean than an elevation of -8 feet.

Here, we are given two elevation levels from the surface of the ocean.

One elevation is of -10 feet and another one is of -8 feet.

An elevation of -10 feet implies that the distance from the surface level is 10 feet.

On the other hand an elevation of of -8 feet implies that the distance from surface level is 8 feet.

Thus, by comparing the distances, we can see that elevation of -10 feet is farther from the surface level of the ocean than an elevation of -8 feet. To be more precise, it is 2(10-2) feet farther than an elevation of -8 feet.

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Answer:

8

Step-by-step explanation

we must find the total of the students to do that we look at when she grouped them in 7, 4 are left out so we multiple 4 miltiplied by 7 and we get 28, there are 4 left out so we add them. now we have a total of 32 students. 32 divided by 4 is 8

[tex] \bf \implies \frac{ - 1}{2} [/tex]

[tex] \bf \longrightarrow({ - 2}^{3})( {3}^{0})({4}^{ - 2} )[/tex]

[tex] \bf \longrightarrow( - 8)(1)( \frac{1}{16}) [/tex]

[tex] \bf \longrightarrow( - 8)( \frac{1}{16})[/tex]

[tex] \bf \longrightarrow \frac{ \cancel{- 8}}{ \cancel{16}} \frac{ \cancel{ - 4}}{ \cancel{8}} \frac{ \cancel{ - 2}}{ \cancel{4}} \frac{ - 1}{2} [/tex]

[tex] \bf \longrightarrow \frac{ - 1}{2} [/tex]

Answer:

About 22 mangoes.

Step-by-step explanation:

If we need to find the number of mangoes in a bag, and we have the total mass of the bag, and the average mass of a mango...

Total mass / Average mass = Number of mangoes

56kg / 13/5 kg = n

We can divide the fraction by flipping it and multiplying...

[tex]\frac{56}{1} /\frac{13}{5} = \frac{56}{1} *\frac{5}{13} \\\\56*5 / 13 \\\\280 / 13 = 21.54[/tex]

Because there are probably only whole mangoes in the bag, 21.5 is rounded up to 22 mangoes.

If a precise answer is necessary than stick with 21.54

Answer:

show a picture

Step-by-step explanation:

No, the given sequence is not geometric.

A geometric progression, sometimes referred to as a geometric sequence in mathematics, is a series of non-zero numbers where each term following the first is obtained by multiplying the preceding one by a constant, non-zero value known as the common ratio.

Given: 1, 5, 9, 13, ....

Here, we can see that: [tex]\frac{5}{1}\neq \frac{9}{5}\neq \frac{13}{9}[/tex] and so on.

Hence, it is not a geometric sequence, since it does not follow the definition of a geometric progression, that the ratio of each adjacent term to the previous term should be equal.

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Answer:

Terms: 17xy, 4, 3x

Coefficients: 17, 3

Variables: x, y

Constants 4, 3

Answer:

-3x+y=14

Step-by-step explanation:

add the x and -4x which gives you -3x

add the -y and 2y which is y

then -14 and 28 add up to 14

The solution of the given system of equations is (4,0)

We can use 3 methods to solve a system of equations:

- graphical method

- elimination method

- substitution method.

The given system of equation is:

-2x + 8y = -8  ....... (1)

5x - 8y = 20  ........(2)

Notice that in the both equations the coefficients of y are -8 and 8, hence if we add those coefficients, they will be cancelled out.

Therefore, we will choose elimination method.

Add equation (1) and equation (2)

-2x + 8y = -8

5x - 8y = 20   +

3x        = 12

 x        = 12/3 = 4

Substitute x = 4 into equation (1):

-2x + 8y = -8

-2.(4) + 8y = -8

-8 + 8y = -8

Add 8 to both sides:

-8 + 8y +8 = -8 + 8

8y = 0

y = 0

Thus, the solution is (4,0)

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There are 20 markers with no tops and 46 markers with tops in the box.

So, there are 66 markers in the box.

Markers with tops:

Therefore, there are 20 markers with no tops and 46 markers with tops in the box.

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The correct question is given below;
There are 66 markers in the box. 20 markersdon't have tops. How many more markers have tops?

Answer:

remember angles on a straight ine add up to 180

∣∣−175∣∣=175 Write an absolute value equation that has -17 and 5

1.) 0.66666666666

2.) 3

3.) 5.2

4.) 0.875

5.) 11.875

6.) 1.10526315789

7.) 0.92

8.) 1.4

9.) 1.27272727273

10.) 12.44

11.) 11.36

Here ya go!

The equation of the circle (x + 6)^2 + y^2 = 121 has a radius of 11 and a center located at (-6 , 0).

The standard form of the equation of  circle is given by

(x - h)^2 + (y - k)^2 = r^2

where (h , k) is the location of the center and r is the radius of the circle.

On the other hand, the general form of the equation of  circle is given by

x^2 + y^2 + Dx + Ey + F = 0

where D = -2h, E = -2k, and F = h^2 + k^2 -r^2.

If the equation of the circle, (x + 6)^2 + y^2 = 121, is in standard form, then

h = -6

k = 0

r = 11

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Answer:

18

Step-by-step explanation:

The total weight of the two animals is 5.9×10⁴ lbs.

In order to solve the question easily, firstly lets write the weight of each animal in standard form.

Weight of first animal = 5.36×10⁴

Weight of first animal = 53,600

Weight of first animal = 6.2×10⁴

Weight of first animal = 62,000

Now, the total weight of animals will be calculated by summing the two values.

Total weight = 53,600 + 62,000

Performing addition of total weight of animals

Total weight = 1,15,600 lbs

Writing the total weight in scientific notation -

Total weight = 1.15×10⁵ lbs

On rounding off, we get -

Total weight = 1.2×10⁵ lbs

Hence, the total weight of the two animals is 1.2×10⁵ lbs.

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