Please help. I’ll mark you as brainliest if correct!

Answer: 30

Step-by-step explanation:

Q1: 120

Q3: 150

To find the interquartile range, subtract Q1 from Q3, which is 150-120. Therefore, the interquartile range  of the kitten's weight, is 30

Answer: 30 grams

Step-by-step explanation:

The interquartile range is the range within the boxed areaa. You subtract the minimum value from the maximum value.

150 - 120 = 30

Answer:55

Step-by-step explanation:

55x1=55

Answer:

10 and 2

Step-by-step explanation

Nitesh is currently 10 and Ravi is currently 2

(2 times 5 is 10)

in 2 years Nitesh will be 12 and Ravi will be 4

(4 times 3 is 12)

Answer:

is this supposed to be a question?

Answer:

yah so

Step-by-step explanation:

Answer:

y = -x + 2

Step-by-step explanation:

The slope intercept form equation of this line can be written like this :

y = my + p ; where m is the slope and p is the y intercept.

[tex]m = \frac{-1-4}{3-(-2)} = \frac{-5}{5} =-1[/tex]

then the equation becomes y = -x + p

(-2,4) is a point of the line means 4 = -(-2) + p

then p = 4 - 2 = 2

finally, y = -x + 2

Answer:  b) 1/3

Step-by-step explanation:

The numbers LESS THAN 3:  1, 2

[tex]\dfrac{\text{Quantity of numbers less than 3}}{Total\ number}\quad =\dfrac{2}{6}\quad \rightarrow \large\boxed{\dfrac{1}{3}}[/tex]

Answer:

$9215.24

Step-by-step explanation:

Total Number of Computers=15

Number of New=11

Number of Refurbished Computers=4

[tex]P(NN)=\frac{11}{15} \times \frac{10}{14} = \frac{11}{21}\\P(NR)=\frac{11}{15} \times \frac{4}{14} = \frac{22}{105}\\P(RN)=\frac{4}{15} \times \frac{11}{14} = \frac{22}{105}\\P(RR)=\frac{4}{15} \times \frac{3}{14} = \frac{2}{35}[/tex]

The probability of one new and one refurbished =P(NR)+P(RN)

[tex]=\frac{22}{105}+ \frac{22}{105}\\=\frac{44}{105}[/tex]

Let X be the amount of profit earned on the purchase. The probability distribution of X is given as:

[tex]\left|\begin{array}{c|c|c|c|c}$Profit(X)& NN=\$10000 &NR=\$9600& RR=-\$800\\$P(X)&\dfrac{11}{21}&\dfrac{44}{105}&\dfrac{2}{35}\end{array}\right|[/tex]

(b) Expected Profit

[tex]\text{Expected Profit}=\sum X_iP(X_i)\\=(10000 \times \dfrac{11}{21}) +(9600 \times \dfrac{44}{105}) + (-800 \times \dfrac{2}{35})\\=\$9215.24[/tex]

The average profit of the store on the order is $9215.24.

Answer:

The probability that X and Y are both positive and that their sum is less or equal to 1 0.64.

Step-by-step explanation:

It is provided that the random variables X and Y follows a standard normal distribution.

That is, [tex]X,Y\sim N(0, 1)[/tex]

It is also provided that the variables X and Y are statistically independent of each other.

Compute the probability that X and Y are both positive and that their sum is less or equal to 1 as follows:

The mean and standard deviation of X + Y are:

[tex]E(X+Y)=E(X)+E(Y)=0+0=0\\\\SD(X+Y)=\sqrt{V(X)+V(Y)+2Cov(X,Y)}=\sqrt{1+1+0}=\sqrt{2}[/tex]

The probability is:

[tex]P(X+Y\leq 1)=P(X+Y<1-0.50)\ [\text{Apply continuity correction}]\\[/tex]

                       [tex]=P(X+Y<0.50)\\\\=P(\frac{(X+Y)-E(X+Y)}{SD(X+Y)}<\frac{0.50-0}{\sqrt{2}})\\\\=P(Z<0.354)\\\\=0.63683\\\\\approx 0.64[/tex]

*Use the z-table.

Thus, the probability that X and Y are both positive and that their sum is less or equal to 1 0.64.

Answer:

(a) The correct option is (A).

(b) The correct option is (B).

Step-by-step explanation:

Nam collected the data for the distance traveled by all the cars in his car lot.

(a)

A histogram is a bar graph representing the distribution of a random variable. The height of the bars of the histogram represents the frequency for a specific interval.

If Nam wants to know how many vehicles had driven more than 200,000 km, the histogram would be the best display of this data. This is because the histogram shows the frequency for various interval values.

The correct option is (A).

(b)

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

So, if Nam wants to find whether the median distance was approximately 140,000 km, a box plot would be a better choice. This is because the box plot represents the median of the data by a line within the box.

The correct option is (B).

Answer: For the first one is A second one is B

Step-by-step explanation: I took the khan test. UwU♡

Answer:

The more extreme height was the case for the shortest living man at that time (12.1017 standard deviation units below the population's mean) compare with the tallest living man (at that time) that was 9.3374 standard deviation units above the population's mean.

Step-by-step explanation:

To answer this question, we need to use standardized values, and we can obtain them using the formula:

[tex] \\ z = \frac{x - \mu}{\sigma}[/tex] [1]  

Where

A z-score "tells us" the distance from [tex] \\ \mu[/tex] in standard deviation units, and a positive value indicates that the raw score is above the mean and a negative that the raw score is below the mean.

In a normal distribution, the more extreme values are those with bigger z-scores, above and below the mean. We also need to remember that the normal distribution is symmetrical.

Heights of men at that time had:

Let us see the z-score for each case:

Case 1: The tallest living man at that time

The tallest man had a height of 252 cm.

Using [1], we have (without using units):

[tex] \\ z = \frac{x - \mu}{\sigma}[/tex]

[tex] \\ z = \frac{252 - 176.74}{8.06}[/tex]

[tex] \\ z = \frac{75.26}{8.06}[/tex]

[tex] \\ z = 9.3374[/tex]  

That is, the tallest living man was 9.3374 standard deviation units above the population's mean.

Case 2: The shortest living man at that time

The shortest man had a height of 79.2 cm.

Following the same procedure as before, we have:

[tex] \\ z = \frac{x - \mu}{\sigma}[/tex]

[tex] \\ z = \frac{79.2 - 176.74}{8.06}[/tex]

[tex] \\ z = \frac{-97.54}{8.06}[/tex]

[tex] \\ z = -12.1017[/tex]

That is, the shortest living man was 12.1017 standard deviation units below the population's mean (because of the negative value for the standardized value.)

The normal distribution is symmetrical (as we previously told). The height for the shortest man was at the other extreme of the normal distribution in [tex] \\ 12.1017 - 9.3374 = 2.7643[/tex] standard deviation units more than the tallest man.

Then, the more extreme height was the case for the shortest living man (12.1017 standard deviation units below the population's mean) compare with the tallest man that was 9.3374 standard deviation units above the population's mean.

Answer:

b. non-directional

Step-by-step explanation:

A directional hypothesis can be described as a hypothesis which predicts the direction of impact, either positive or negative, of one variable, especially independent variable, on the other variable which is known as an independent variable. For example, the hypothesis "age reduces memory performance" is a directional hypothesis. The reason is that "reduces" show the direction that age has a negative effect on memory performance.

On the other hand, non-directional hypothesis can be described as a hypothesis that does not predict the direction of impact but only states the relationship between two variables. For example, the research hypothesis is in the question that "age is related to memory performance" is non-directional hypothesis. This because the word "related" in the hypothesis only indicate that there is a relationship between the two variables, not the direction of effect of one variable on the other.

Answer:

The probability that the proportion of vegetarians in a sample of 471 Americans would be greater than 8% is P=0.776.

Step-by-step explanation:

We have to calculate a probability that a sample of n=471 has a proportion greater than 8%, given that the population proportion is 9%.

First, we have to calculate the parameters of the sampling distribution of the proportions:

[tex]\hat{p}=p=0.09\\\\\\\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.09\cdot 0.91}{471}}=0.0132[/tex]

Now, we can calculate the probability using the z-score:

[tex]z=\dfrac{p-\hat{p}}{\sigma_{\hat{p}}}=\dfrac{0.08-0.09}{0.0132}=\dfrac{-0.01}{0.0132}=-0.7576[/tex]

Then, the probability is:

[tex]P(p>0.08)=P(z>-0.7576)=0.776[/tex]

Answer:

a) The 99% confidence interval for the mean number of steps taken on a typical workday for all people working in New York City who wear an activity tracker is (9,009, 10,585).

We are 95% confident that the mean number of steps taken on a typical workday for all people working in New York City who wear an activity tracker is within 9,009 and 10,585 steps.

b) No, we can not use the confidence interval to estimate the probability of individual values. It can onlybe used to make inference about the population mean.

Step-by-step explanation:

a) We have to calculate a 99% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=9,797.

Ths sample standard deviation is s=2,313.

The sample size is N=61.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2313}{\sqrt{61}}=\dfrac{2313}{7.81}=296.15[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=61-1=60[/tex]

The t-value for a 99% confidence interval and 61 degrees of freedom is t=2.66.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=2.66 \cdot 296.15=787.84[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 9797-787.84=9009\\\\UL=M+t \cdot s_M = 9797+787.84=10585[/tex]

The 99% confidence interval for the mean number of steps taken on a typical workday for all people working in New York City who wear an activity tracker is (9,009, 10,585).

b) The value of 8,500 steps is outside the confidence interval, but this means that it is an unusual value for the mean number of steps for all people in New York City who wear an activity tracker.

We can not use the confidence interval to estimate the probability of individual values.

The activity tracking devices.

The activity tracker re those devices such as watches and a bands that tells you about your physical activity such as skipping, running, and walking. They simply count the steps and tell you about the daily goals and targets. They are quite effective for monitoring blood pressure and more.

Thus answer is 9,009, 10,585 workers,  9,009, and 10,585 steps and population mean.

Learn more about the trackers are electronic.

brainly.com/question/17434350.

Answer:

Step-by-step explanation:

5

Answer:

Option (2).

Step-by-step explanation:

In the figure attached,

A, C and B are the points lying on a straight line.

2 lines EC and DC have been drawn by extending the lines from C to E and D respectively.

Ray CE is the angle bisector of ∠ACD.

That means CE divides ∠ACD in two equal parts.

m∠ACE = m∠DCE

Since m∠ACD = m∠ACE + m∠DCE

                        = 2(m∠ACE)

          m∠ACE = [tex]\frac{1}{2}(\angle ACD)[/tex]

Therefore, option (2) will be the answer.

Answer:

b

Step-by-step explanation:

took test

Answer:

  total cost = 8x^2 +17280/x

Step-by-step explanation:

Let x represent the base length. Then the area of the base is x^2, and the height is h = 720/x^2.

The area of the four sides is ...

  (4x)(h) = (4x)(720/x^2) = 2880/x

The cost of the base is ...

  base cost = 8x^2

And the cost of the sides is ...

  side cost = 6(2880)/x = 17280/x

The total cost of the box is ...

  total cost = base cost + side cost

  total cost = 8x^2 +17280/x

_____

Comment on the cost function

You will find this function has a minimum at x=∛1080 ≈ 10.260 in. The total cost is about $2526.35, and the box is 2/3 times as tall as wide. That aspect ratio makes any pair of opposite sides cost the same as the base, the generic solution to a cost optimization problem of this sort.

Answer: choice B

Step-by-step explanation:

The graph of y=-3x^n is the reflection of the graph of y=3x^n about the x-axis.

Answer: B

Step-by-step explanation:

Answer:

0.902 = 90.2% probability that the flight would leave on time when it is not raining

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Not raining

Event B: Flight leaving on time.

The probability that it will rain is  0.18.

This means that there is a 1 - 0.18 = 0.82 probability of not raining. So [tex]P(A) = 0.82[/tex]

The probability that it  will not rain and the flight will leave on time is 0.74.

This means that [tex]P(A \cap B) = 0.74[/tex]

What is the probability that the  flight would leave on time when it is not raining?

[tex]P(B|A) = \frac{0.74}{0.82} = 0.902[/tex]

0.902 = 90.2% probability that the flight would leave on time when it is not raining

Answer:

x  ≥  -2

Step-by-step explanation:

Divide both sides of the inequality by 2.

2x       ≥   - 4

2x / 2  ≥   -4 / 2

x          ≥   -2

Answer:

the answer is the arrow going to the right because its not a negative number and a closed circle

Step-by-step explanation:

so that means that 2x is at LEASt more than -4 opposed to this sign> wich just means greater than

because when you work with variables you usually cannot find the exact amount especially when you are rounding so you know that its biigger than no less than or at least -4

Answer:

The probability of getting the same colour twice is approximately 34%.

Step-by-step explanation:

The probability of getting each color is:

Then, we can calculate the probability of getting the color red twice as:

[tex]P(x_1=R;x_2=R)=P(x=R)^2=(3/11)^2=9/121[/tex]

We have to repeat this for the color blue and green:

[tex]P(x_1=B;x_2=B)=P(x=B)^2=(4/11)^2=16/121\\\\P(x_1=G;x_2=G)=P(x=G)^2=(4/11)^2=16/121[/tex]

Then, the probability of getting the same color twice in two spins can be calculated as:

[tex]P=P(x_1=R;x_2=R)+P(x_1=B;x_2=B)+P(x_1=G;x_2=G)=\\\\P=9/121+16/121+16/121\\\\P=41/121\approx0.34[/tex]

Answer:

5

Step-by-step explanation:

a minus times by another minus makes a positive, so it is basically 1 x 5

Answer:

5

Step-by-step explanation:

Since the you are multiplying 2 minuses together they will cancel each other out to form a positive number. However if you have an example like this

-6 × 7

Then the answer will be -42 because there is only one negative

Answer:

if you go around a track one time thats 400 meters but if you go around 4 times thats 1600 meters, you dont need to use 3.14 pi for this " no offense", i do track and field myself and i do the short distance, which is 100 meters and 200 meter but for for long distance runners they go around the track 4- 8 times so it is 1600 meters is ur answer. and when u go around 8 times, thats 3200 meters.

Step-by-step explanation:

Answer: [tex]y=\frac{3}{2} x - 3[/tex]

Step-by-step explanation:

Looking at the  graph we could locate the y intercept at point (0,-3)  and we can locate another point (4,3) which also passes through the line.  So using these coordinates we already know the the y-intercept as -3 but we need to find the slope to write it in slope intercept form.

To find the slope, we will need to find the difference in the y values and divide it by the difference in the x values.

(0,-3)

(4,3)

-3 - 3 = -6

0-4 =  -4  

-6 /-4 =  3/2   so now we know that the slope is 3 over 2  

so we could write the equation as   y = 3/2x -3  

Answer: Thank you (nermay7)

Step-by-step explanation: They are correct!!!!!!!

Answer:

D

Step-by-step explanation:

y = sqrt(25x-75)+3

y = sqrt(25(x-3))+3

y = sqrt 5(x-3)+3

transformations:

vertically stretched by a factor of 5

right 3 units

up 3 units

D is the best answer

Answer:

see below

Step-by-step explanation:

To find the x intercept set y =0 and solve for x

6x+5y = -30

6x = -30

Divide by 6

x = -30/6 = -5

The x intercept is (-5,0)

To find the y intercept set x =0 and solve for y

6x+5y = -30

5y = -30

Divide by 5

y = -30/5 = -6

The y intercept is (0,-6)

To find the x-intercept set y =0. Solve for x.

6x+5y=-30

6x+5(0)=-30

6x+0=-30

6x=-30

x=-30/6

x=-5

The x-intercept is at (-5, 0)

To find the y-intercept set x =0. Solve for y.

6x+5y=-30

6(0)+5y=-30

0+5y=-30

5y=-30

y=-30/5

y=-6

The y-intercept is at (0, -6)

Answer:

  (0, ∞)

Step-by-step explanation:

A good place to start is by visualizing what the graph looks like on a number line.

For x > 0, it is an open circle at x=0, and shading to the right extending to infinity.

__

So, the left end of the interval is 0, but 0 is not included in the interval.

The right end of the interval is infinity, but there is no such number, so "infinity" is not included in the interval.

"Not included" means you use round brackets ( ) for the corresponding end of the interval. ("Included" would mean you use square brackets [ ].)

So, the interval 0 < x < ∞ is written in interval notation as ...

  (0, ∞)

Answer:

91.92% of pregnancies last beyond 246 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 267, \sigma = 15[/tex]

What percentage of pregnancies last beyond 246 days?

We have to find 1 subtracted by the pvalue of Z when X = 246. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{246 - 267}{15}[/tex]

[tex]Z = -1.4[/tex]

[tex]Z = -1.4[/tex] has a pvalue of 0.0808

1 - 0.0808 = 0.9192

91.92% of pregnancies last beyond 246 days

Answer:

1, -4

Step-by-step explanation:

Let  x^-1 = 1/x = y

1. Root 1

2. Root 2