Please help me with this question!!!

Step-by-step explanation:

The last option 45 and 46

Answer:

its 4-5 not 45-46 \

Step-by-step explanation:

Answer:

It is c he revived 10.21

Step-by-step explanation:

Answer:

Step-by-step explanation:

p(x)=2x^2

q(x)=x-3

(p•q)(x)=2(x-3)^2

2(x^2-6x+9)

2x^2-12x+18

Answer:

C

Step-by-step explanation:

It's of the shape of a cone

Answer:

1/4845

Step-by-step explanation:

The probability of selecting a defective cog first is

1/5

The second cog is

3/19

The third cog is

1/9

And the fourth cog is

1/17

Multiplying these together we get

1/5 * 3/19* 1/9 * 1/17  = 1/4845

The probability of selecting 4 cogs from the 20 produced where all are defective is approximately 0.000206.

Probability is a measure of how likely an event is to occur. Many events are impossible to predict with absolute certainty.

The probability of selecting 4 defective cogs from the 20 produced can be calculated as follows:

P(4 defective cogs) = (Number of ways to select 4 defective cogs) / (Total number of ways to select 4 cogs from 20)

The number of ways to select 4 defective cogs can be found by selecting 4 defective cogs out of the 4 defective cogs produced, and 0 non-defective cogs out of the remaining 20-4=16 non-defective cogs. This can be expressed mathematically as:

Number of ways to select 4 defective cogs = (4 choose 4) * (16 choose 0) = 1

The total number of ways to select 4 cogs from 20 can be found by selecting 4 cogs out of the 20 produced. This can be expressed mathematically as:

Total number of ways to select 4 cogs from 20 = (20 choose 4) = 4845

Therefore, the probability of selecting 4 defective cogs from the 20 produced is:

P(4 defective cogs) = (Number of ways to select 4 defective cogs) / (Total number of ways to select 4 cogs from 20) = 1/4845

Thus, the probability of selecting defective cogs is approximately 0.000206.

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Answer:

A and F

Step-by-step explanation:

First we'll dilate it by a scale factor of 2. After that, we'll translate in 6 units left and 6 units up to map circle J onto circle K

Answer:

1130

Step-by-step explanation:

since radius of the circle was given and the formula of the area is pie r square

Answer:

x = 11

Step-by-step explanation:

You are solving for the solution of the variable given (x). Set each parenthesis equal to 0 and simplify:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Add 11 to both sides:

x - 11 = 0

x - 11 (+11) = 0 (+11)

x = 0 + 11

x = 11

Do the same for the other set:

x - 11 = 0

x - 11 (+11) = 0 (+11)

x = 0 + 11

x = 11

~

Answer:

what are the answers fir this question

Answer:

Answer options are:

a. All integers are natural numbers.

b. All rational numbers are integers.

c. All natural numbers are whole numbers.

d. All rational numbers are natural numbers.

Step-by-step explanation:

Answer is C

Answer:

a

the displacement of the plane is  [tex]- \= w[/tex]

b

The displacement of plane  from Portland to Akron with layover at Houston is  

       [tex]\= v + \= w[/tex]

c

  the vector which defines this displacement is  [tex]\= v + \= w =- 2500 \ km[/tex]

Step-by-step explanation:

From the question we are the

   The displacement from Portland, Oregon to Houston, Texas. is  [tex]\= v[/tex]

    The displacement  from Houston, Texas to Akron, Ohio.  is [tex]\= w[/tex]a

a

   The motion of the plane in question a is in the opposite direction to vector [tex]\= w[/tex]

So the displacement of the plane is  [tex]- \= w[/tex]

b

The motion of Portland to Houston to Akron is in the direction of both vector [tex]\= v[/tex] and  [tex]\= w[/tex]  so

The displacement of plane  from Portland to Akron with layover at Houston is  

       [tex]d = \= v + \= w[/tex]

c

From the question we are told that the plane flies over Portland to get to  Anchorage, Alaska which implies that it is moving in opposite direction to the vector [tex]\= v[/tex]

   Give that distance from Portland to Houston is  [tex]\= v = 3000 km[/tex]

           and the distance from Portland to  Anchorage is [tex]\= w = - 5500[/tex]km

Then the vector which defines this displacement is mathematically represented as

   [tex]\= v + \= w = 3000 -5500[/tex]

    [tex]\= v + \= w =- 2500 \ km[/tex]

Answer:

P = 8000

t = 2

I = p × r × t

400 = 8000 × r/100 × 2

r = 400/160 per year

r = 40/16 = 2.5 %

Answer:

y=2x-4

Step-by-step explanation:

Answer:

range 11

Step-by-step explanation:

The range is the largest number minus the smallest number

The largest number is 12 and the smallest number is 1

12 - 1 = 11

Answer:

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

[tex]C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]   we can conclude that the  function is an increasing function.

Step-by-step explanation:

Given that:

[tex]\dfrac{dC}{dt}= r-kC[/tex]

[tex]\dfrac{dC}{r-kC}= dt[/tex]

By taking integration on both sides ;

[tex]\int\limits\dfrac{dC}{r-kC}= \int\limits \ dt[/tex]

[tex]- \dfrac{1}{k}In (r-kC)= t +D[/tex]

[tex]In(r-kC) = -kt - kD \\ \\ r- kC = e^{-kt - kD} \\ \\ r- kC = e^{-kt} e^{ - kD} \\ \\r- kC = Ae^{-kt} \\ \\ kC = r - Ae^{-kt} \\ \\ C = \dfrac{r}{k} - \dfrac{A}{k}e ^{-kt} \\ \\[/tex]

[tex]C(t) =\frac{ r}{k} - \frac{A}{k}e^{ -kt}[/tex]

where;

A is an integration constant

In order to determine A, we have C(0) = C0

[tex]C(0) =\frac{ r}{k} - \frac{A}{k}e^{0}[/tex]

[tex]C_0 =\frac{r}{k}- \frac{A}{k}[/tex]

[tex]C_{0} =\frac{ r-A}{k}[/tex]

[tex]kC_{0} =r-A[/tex]

[tex]A =r-kC_{0}[/tex]

Thus:

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

b ) Assuming that C0 < r/k, find lim t→[infinity] C(t) and interpret your answer

[tex]C_{0} < \lim_{t \to \infty }C(t)[/tex]

[tex]C_0 < \dfrac{r}{k}[/tex]

[tex]kC_0 <r[/tex]

The equation for C(t) can therefore be re-written as :

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

[tex]C(t) =\dfrac{ r}{k} - \left (+ve \right )e^{ -kt} \\ \\C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]

Thus; we can conclude that the above function is an increasing function.

Answer:

(0,2)

Step-by-step explanation:

2:4 means one part is 2/(2+4)=1/3 of AB and the other part is 2/3 of AB

Add 1/3 of the distance from -2 to 4. (1/3)(4+2)=2. -2+2=0 The x coordinate is 0

Subtract 1/3 of the distance from 6 to -6, (1/3)6+6)=4 6-4=2 The y coordinate is 2

The point is (0,2)

Answer:

Step-by-step explanation:

Given: DE║BC

To prove: [tex]\frac{\text{AD}}{\text{DB}}=\frac{\text{AE}}{\text{EC}}[/tex]

                Statements                           Reasons

1). DE║BC                                   1). Given

2). ∠1 ≅ ∠4, ∠3 ≅ ∠4                2). Corresponding angles theorem

3). ΔADE ~ ΔABC                      3). AA Similarity theorem

4). [tex]\frac{\text{AB}}{\text{AD}}=\frac{\text{AC}}{\text{AE}}[/tex]                                4). Corresponding sides are proportional

5). [tex]\frac{\text{AD+DB}}{\text{AD}}=\frac{\text{AE+EC}}{AE}[/tex]                   5). Segment addition postulate

6). [tex]1+\frac{\text{DB}}{\text{AD}}=1+\frac{\text{EC}}{\text{AE}}[/tex]                   6). [tex]\frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}[/tex]

7). [tex]\frac{\text{DB}}{\text{AD}}=\frac{\text{EC}}{\text{AE}}[/tex]                                7). Subtract 1 from both sides

8). [tex]\frac{\text{AD}}{\text{DB}}=\frac{\text{AE}}{\text{EC}}[/tex]                               8). Take the reciprocal of both sides

Answer:

y=2.4

Step-by-step explanation:

7y-2=2y+10

7y-2y=10+2

5y=12

y=12/5=2.4

Answer:

True

True

Step-by-step explanation:

The unknown parameters are treated as variable and data serve as coefficients. The random variables are value whose outcome depends on some random event. The θ can exist when n ≥ 0. A sample mean is a sequence which has normal distribution and n ≥ 1. The sample average of X-n follows normal distribution for all integer and n is greater or equal to 1.

The given statement is True

The unknown parameters should be considered variable and data represent the coefficients. The random variables refers to the value where  outcome based on some random event. The θ could exist at the time when n ≥ 0. A sample mean represent the sequence that contains normal distribution and n ≥ 1.

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Answer:

360 x 30% = answer

30% = 30/100 = 0.3

360 x 0.3 = 108

108 is the answer

Hope this helps

Step-by-step explanation:

Answer:

108 pages

Step-by-step explanation:

30% of 360=108

360*.30=108

[tex]a^{2} {c}^{2} - {a}^{2} {d}^{2} - {b}^{2} {c}^{2} + {b}^{2} {d}^{2} + 4abc[/tex]

Answer:

2, -1/2

Step-by-step explanation:

2m²-3m-2=0

2m² - 4m + 1m - 2=0

2m(m-2)+(m-2)=0

(2m+1)(m-2)=0

2m+1=0 ⇒ m= -1/2

m-2=0 ⇒ m=2

Answer:

Step-by-step explanation:

_______________________________

Hey!!

Solution,

X+61+42=180[ sum of angle in triangle]

or,X+103=180

or,X=180-103

X=77°

So the value of X is 77°

Hope it helps..

Good luck on your assignment

____________________________

Answer:

around 68 minutes 31 seconds.

Step-by-step explanation:

10km = miles = 6.21x11 = 68.31

Answer:

56%

Step-by-step explanation:

Any number out of 100 is that number's percent.

If it's for say 0.1/100, its 0.1%.

Answer:

  the sum of the prices divided by 7

Step-by-step explanation:

The mean is the sum of the elements of a set, divided by the number of elements in the set. This set has 7 members, so its mean is ...

  the sum of the prices divided by 7

Answer:

A. (I) v = 46.42 m/s; (ii) v = 47.35 m/s; (III) v = 48.09 m/s; (iv) v = 48.26 m/s; (v) v = 58.28 m/s

B. v = 48.28 m/s

Note: the question is missing some values. The full Question is provided below:

If an arrow is shot upward on Mars with a speed of 52 m/s, its height in meters t seconds later is given by y = 52t − 1.86t2. (Round your answers to two decimal places.)

(a) Find the average speed over the given time intervals. (i) [1, 2] m/s (ii) [1, 1.5] m/s (iii) [1, 1.1] m/s (iv) [1, 1.01] m/s (v) [1, 1.001] m/s

(b) Estimate the speed when t = 1. m/s

Step-by-step explanation:

Height, y = 52t - 1.86t²

Velocity = ∆y/∆t = 52 - 1.86 * 2t = 52- 3.72t

A. Average velocity = (v1 + v2)/2

(i) At t = 1, 2

Average velocity = (52 - 3.72*1 + 52 -3.72*2)/2 = 46.42 m/s

(ii) At t = 1,1.5

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.5)/2 = 47.35 m/s

(iii) At t = 1,1.1

Average velocity = (52 - 3.72*1 + 52 -3.72*1.1)/2 = 48.09m/s

(iv) At to = 1, 1.01

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.01)/2 = 48.26 m/s

(iv) At t = (1, 1.001)s

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.001)/2 = 48.28 m/s

B. Speed at t = 1s

Velocity = 52 - 3.72 * 1 = 48.28 m/s

Answer:

-3 =n

Step-by-step explanation:

11(n – 1) + 35 = 3n

Distribute

11n -11 +35 = 3n

Combine like terms

11n +24 = 3n

Subtract 11n from each side

11n +24 -11n = 3n -11n

24 = -8n

Divide each side by -8

24/-8 = -8n/-8

-3 =n

Answer: n=-3

Step-by-step explanation:

11n-11+35=3n

24=-8n

n=-3

Answer:

Camera 2nd has to cover the maximum angle, i.e. [tex]78.70^\circ[/tex].

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle [tex]\triangle ABC[/tex] with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles [tex]\angle A, \angle B, \angle C[/tex]

As per Law of cosine:

[tex]cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}[/tex]

Putting the values of a,b and c to find out angles [tex]\angle A, \angle B, \angle C[/tex].

[tex]cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ[/tex]

[tex]cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ[/tex]

[tex]cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ[/tex]

Camera 2nd has to cover the maximum angle, i.e. [tex]78.70^\circ[/tex].

Answer:

618

Step-by-step explanation:

l x w

34x5

14x27

5x14

618