Please help on this math question.

Will be marked as BRAINLEST!

hope this sheet helps :)

Answer:

It would bounce at 78 centimeters height

Step-by-step explanation:

Answer:

Why you just copy and paste it

Answer:

0, 25, 12, -5

Step-by-step explanation:

integers are whole numbers - positives and negatives - including zero

Answer:

0712....,.......................

Answer:

x>-4

Step-by-step explanation:

I looked it up. Use Mathpapa it's really helpful and free

A

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

i think because the bottom of the triangles are the denominators and the x is the numerator

Answer:

  .

Step-by-step explanation:

Answer:

the answer is 2223 please mark as brainliest

Answer:

2223

Step-by-step explanation:

its a simple math issue

Answer:

42=3x+15

42-15+3x

27/3 = 9

Step-by-step explanation:

Answer:

$22.5

Step-by-step explanation:

Answer:

5 classes

Step-by-step explanation:

Let x represent the number of aerobics classes

Create an equation that sets the member and nonmember prices equal to each other, then solve for x:

4x + 10 = 6x

10 = 2x

5 = x

So, after 5 aerobics classes, the costs will be the same.

Answer: Steep. Its 50% steep.

This question is incomplete, the complete question is;

Determine if the described set is a subspace. Assume a, b, and c are real numbers.

The subset of R³ consisting of vectors of the form [tex]\left[\begin{array}{ccc}a\\b\\c\end{array}\right][/tex] , where abc = 0

Answer:

Therefore; The set is not a subspace

Step-by-step explanation:

Given the data the question;

the subset R³;

S = {  [tex]\left[\begin{array}{ccc}a\\b\\c\end{array}\right][/tex] , where abc = 0 }

we know that a subset of R³ is a subspace if it stratifies the following properties;

Looking at the properties, we can say that it is not a subspace

As;

         u = [tex]\left[\begin{array}{ccc}1\\1\\0\end{array}\right][/tex] ∈ S       and v = [tex]\left[\begin{array}{ccc}0\\1\\1\end{array}\right][/tex]  ∈ S

As    1×1×0=0                          0×1×1=0

But   u+v = [tex]\left[\begin{array}{ccc}1+0\\1+1\\0+1\end{array}\right] =[/tex] [tex]\left[\begin{array}{ccc}1\\2\\1\end{array}\right][/tex]  ∉  S     as 1×2×1 ≠ 0

Hence, it is not closed under addition.

Therefore; The set is not a subspace

Answer: -1

Step-by-step explanation:

[tex]\bigg (-1\dfrac{1}{2} \bigg) \cdot \dfrac{2}{3} =-\dfrac{3}{2} \cdot \dfrac{2}{3} =-1[/tex]

Answer:

f(x) = x^2+ 3x

f(A + 4)=(A+4)²+3(A+4)=A²+8A+16+3A+12

=A²+11A+28

Answer:

cool

Step-by-step explanation:

Answer:

account 2 years ago. The simple interest rate is 2.9% The interest that you eamed in those 2 years is $17.40. Which of the following is/are true? = 2.996 r=17-40 D= 300.

Answer:

0.2406 = 24.06% probability that exactly two of the selected major customers accept the plan

Step-by-step explanation:

The customers are chosen without replacement, which means that we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

50 major customers, 15 would accept the plan.

This means that [tex]N = 50, k = 15[/tex]

The utility selects 10 major customers randomly (without replacement) to contact and promote the plan.

This means that [tex]n = 10[/tex]

a. What is the probability that exactly two of the selected major customers accept the plan

This is P(X = 2).

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 2) = h(2,50,10,15) = \frac{C_{15,2}*C_{35,8}}{C_{50,10}} = 0.2406[/tex]

0.2406 = 24.06% probability that exactly two of the selected major customers accept the plan

Answer:

Constant is 6 and the variable is a

Answer:

0

Step-by-step explanation:

2 - c(4) is -2. -2 + a(2) is 0.

Hope it helps!

Answer:

The second one

210 lbs

Step-by-step explanation:

The difference between 7 and 4 is 3

90/3 = 30

30 times 7 = 210

Answer:

Second Diagram

Step-by-step explanation:

Answer:

the domain for both graphs is infinity

Step-by-step explanation:

both graphs are absolute value graphs, which means there is an infinite amount of possible x values in positive and negative directions.

edit: actually, if there are no arrows of the ends of the graphs, then what i just said is not true. a possible answer if that's the case may be both graphs have domains that include negatives

Answer:

3

Step-by-step explanation:

Answer:

The answer is 18

Step-by-step explanation:

All you have to do is look at the length the left side of the triangle and see what you have to divide the larger number by to get the smaller number.

Then you have to divide the number on the bottom by the number that you had to divide the larger number by the side by.

6/? = 3

6/2 = 3

36/2 =18

Answer:

A' is (-1,-1) B' becomes (-1,-4) C' becomes (-3,-1)

Step-by-step explanation:

To take a shortcut, reflecting a figure across both axes is the same as rotating a figure 180 degrees about the orgin using formula x,y goes to -x,-y but to explain it. Use formula (x,y) goes to (x,-y) to reflect it across x-axis then use formula (x,y) goes to (-x,y) to reflect it across y-axis. A' becomes -1,-1. B' becomes -1,-4 . C' becomes (-3,-1)

Answer:

(a) [tex]P(x\le 3) = 0.75[/tex]

(b) [tex]P(x\le 3) = 0.75[/tex]

(b) is the same as (a)

(c) [tex]P(x \ge 5) = 0.10[/tex]

(d) [tex]P(x = 1\ or\ 2) = 0.55[/tex]

(e) [tex]P(x > 2) = 0.45[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}[/tex]

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

[tex]\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}[/tex]

This probability is calculated as:

[tex]P(x\le 3) = P(1) + P(2) + P(3)[/tex]

This gives:

[tex]P(x\le 3) = 0.30 + 0.25 + 0.20[/tex]

[tex]P(x\le 3) = 0.75[/tex]

Solving (b): Probability of at most 3 CDs

Here, we consider:

[tex]\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}[/tex]

This probability is calculated as:

[tex]P(x\le 3) = P(1) + P(2) + P(3)[/tex]

This gives:

[tex]P(x\le 3) = 0.30 + 0.25 + 0.20[/tex]

[tex]P(x\le 3) = 0.75[/tex]

(b) is the same as (a)

Solving (c): Probability of 5 or more CDs

Here, we consider:

[tex]\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}[/tex]

This probability is calculated as:

[tex]P(x \ge 5) = P(5) + P(6\ or\ more)[/tex]

This gives:

[tex]P(x\ge 5) = 0.05 + 0.05[/tex]

[tex]P(x \ge 5) = 0.10[/tex]

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

[tex]\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}[/tex]

This probability is calculated as:

[tex]P(x = 1\ or\ 2) = P(1) + P(2)[/tex]

This gives:

[tex]P(x = 1\ or\ 2) = 0.30 + 0.25[/tex]

[tex]P(x = 1\ or\ 2) = 0.55[/tex]

Solving (e): Probability of more than 2 CDs

Here, we consider:

[tex]\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}[/tex]

This probability is calculated as:

[tex]P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)[/tex]

This gives:

[tex]P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05[/tex]

[tex]P(x > 2) = 0.45[/tex]

Answer:

44

Step-by-step explanation:

Answer:(1) reduce border conflicts with Canada

(2) increase acceptance of minorities within the

United States

(3) encourage Germany and the Soviet Union to

resolve their differences

(4) improve relations with Latin America

Step-by-step explanation:

think its B good luck