please help question 12​

The percent of Lan's budget that will go towards savings is 35%

The correct option is; 35%

A percentage is a representation of a ratio as a fraction with a denominator of a hundred, 100.

The amount Lan's income is = $1,000

Lan's budget obtained from a similar question on the internet can be presented as follows;

Expense         [tex]{}[/tex]                     Amount ($)

Car Payment [tex]{}[/tex]                     $350

Car Insurance [tex]{}[/tex]                   $100

Fuel [tex]{}[/tex]                                   $120

Cell Phone [tex]{}[/tex]                        $80

Therefore, Lan's total budget is; $350 + $100 + $120 + $80 = $650

The amount Lan's has to save is; $1,000 - $650 = $350

The percentage of his budget he saves is therefore;

Percent savings = $350/($1,000) × 100 = 35%

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We find that the approximation converges to 9.74679419, accurate to eight decimal places. So, the square root of 95, approximated using Newton's method, is 9.74679419.

Newton's method is a way to approximate the roots of a function. In this case, we want to approximate the square root of 95 correct to eight decimal places. To use Newton's method, we start with an initial guess and then apply the following formula repeatedly:
x1 = x0 - f(x0) / f'(x0)
where x0 is our initial guess, f(x) is the function we are trying to find the root of (in this case, f(x) = x^2 - 95), and f'(x) is the derivative of f(x) (which is 2x).
Let's start with an initial guess of 10:
x1 = 10 - (10^2 - 95) / (2 * 10) = 5.75
We can continue this process, plugging in our new guess into the formula each time, until we reach a value that is accurate to eight decimal places. After a few iterations, we get:
x8 = 9.74679434
This is our final answer, correct to eight decimal places.
Using Newton's method, we can approximate the square root of a number, such as 95, to eight decimal places. Newton's method is an iterative process that starts with an initial guess and refines the guess using the formula:
x1 = x0 - f(x0)/f'(x0)
For square root approximation, f(x) = x^2 - a, where a is the number we want to find the square root of (95 in this case), and f'(x) = 2x.
Let's start with an initial guess x0 = 9 (since 9^2 = 81 is close to 95). We can then perform the following iterations:
1. x1 = 9 - (9^2 - 95)/(2*9) ≈ 9.72222222
2. x2 = 9.72222222 - (9.72222222^2 - 95)/(2*9.72222222) ≈ 9.74679424
3. x3 = 9.74679424 - (9.74679424^2 - 95)/(2*9.74679424) ≈ 9.74679419
Continuing this process, we find that the approximation converges to 9.74679419, accurate to eight decimal places. So, the square root of 95, approximated using Newton's method, is 9.74679419.

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The coordinates of the point B of vector is B ( -5 , -3 )

Given data ,

To find the coordinates of the terminal point B, we can start with the initial point of vector AB and add its components.

Initial point of AB: (-9, 8)

x-component of AB: 4

y-component of AB: -11

To find the coordinates of the terminal point B, we add the x-component and y-component to the corresponding coordinates of the initial point.

x-coordinate of B = x-coordinate of initial point + x-component of AB

x = -9 + 4

x = -5

y-coordinate of B = y-coordinate of initial point + y-component of AB

y = 8 + (-11)

y = -3

Hence , the coordinates of the terminal point B are (-5, -3)

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Answer:

C(t) = 10,500(1 + 0.07)^t

Step-by-step explanation:

Answer:

480

Step-by-step explanation:

Using the formula s=n/2(a+l), where a is the first term, l is the last term, n is the number of terms, and s is the sum of the terms, we can substitute the given values and solve for s:

s = 15/2(2 + 30)

s = 15/2(32)

s = 15/64

s = 480

Therefore, the value of s is 480.

Answer:

Step-by-step explanation:

[tex]s = \frac{n}{2}(a+l) \\s = \frac{15}{2} (2+30)\\s = \frac{15}{2} X 32\\s = 15 X 16\\s = 240[/tex]

[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta r^2}{2} ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=8\\ \theta =2.2 \end{cases}\implies A=\cfrac{(2.2)(8)^2}{2}\implies A=70.4~m^2[/tex]

a) The range of the number of cans found is: 8

b) The range of the number of bottles found is: 5

The range of a dataset is basically  the simplest measurement of the difference between values in a data set. To find the range, we will simply subtract the lowest value from the greatest value while ignoring the others.

a) The range of the number of cans found is simply the difference between the highest number of cans found and the lowest number of cans found.

Thus:

Range of number of cans = 10 - 2

Range of number of cans = 8

b) The range of the number of bottles found is simply the difference between the highest number of bottles found and the lowest number of bottles found.

Thus:

Range of number of bottles = 6 - 1

Range of number of bottles = 5

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Answer:

Answer: 1/7 as a decimal is 0.143

1-7-as-a-decimal

Let us understand the division method to write 1/7 as a decimal.

Explanation:

To convert any fraction to its decimal form, we just need to divide the numerator by the denominator.

Here, the fraction is 1/7 which means we need to divide 1 by 7 (1 ÷ 7)

This gives the answer as 0.14285714... which can be rounded off and written as 0.143. So, 1/7 as a decimal is 0.143

Irrespective of the methods used, the answer to 1/7 as a decimal will always remain the same.

The P-value for the hypothesis test H₀: p = 0.9 against H₁: p ≠ 0.9, at α = 0.056, is less than 0.056.

What is hypothesis test?

A hypothesis test is a statistical procedure used to make inferences or draw conclusions about a population based on sample data. It involves formulating two competing hypotheses, the null hypothesis (H₀)

In this hypothesis test, we are interested in determining if the proportion (p) of customers who are satisfied or very satisfied with a corporation's products and services is different from 0.9.

The null hypothesis (H₀) states that the proportion is equal to 0.9, while the alternative hypothesis (H₁) states that the proportion is not equal to 0.9.

To test these hypotheses, we use a binomial proportion test. From the given information, we have a sample of 1000 customers, and 850 of them are satisfied or very satisfied.

Using the sample proportion calculated as 850/1000 = 0.85, we can calculate the test statistic, which follows an approximately standard normal distribution under the null hypothesis.

Since the P-value is less than 0.056, we reject the null hypothesis and conclude that there is evidence to suggest that the proportion of satisfied or very satisfied customers is different from 0.9.

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The equivalent value of the expression is x = 65

Given data ,

The equation is represented by the letter A , where

By substituting the values in the equation, we obtain the value of A as

5x + 1 + 5x - 1 - 650 = 0

Taking the similar terms of the expression:

10x - 650 = 0

Adding 650 to both sides:

10x = 650

Dividing both sides by 10:

x = 65

Hence , the expression is x = 65

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False. For a test of independence, the population that the data has come from does not need to be normally distributed. Independence tests, such as the Chi-square test, assess the relationship between two categorical variables and do not require normality assumptions.

The focus is on the association between variables, not on the distribution of the population.

False. For a test of independence, the assumption of normality is not necessary for the population from which the data has come. Instead, the focus is on the relationship between two categorical variables. The test of independence examines whether there is a statistically significant association between the two variables, and the data is usually presented in a contingency table. This test is commonly used in research studies to determine whether two factors are independent of each other or whether they are related. Therefore, the normality assumption is not relevant in this case, and the test can be performed regardless of the distribution of the population data. In conclusion, a test of independence does not require a normally distributed population.

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Rounding to two decimal places, the relative frequency of male students who are chemistry majors is approximately 0.23.Therefore, the answer is 0.23.

To find the relative frequency of male students who are chemistry majors, we need to divide the number of male chemistry majors by the total number of male students in the sample.

According to the contingency table, there are 35 male chemistry majors.

To calculate the relative frequency, we divide the number of male chemistry majors by the total number of male students:

Relative Frequency = Number of Male Chemistry Majors / Total Number of Male Students

Relative Frequency = 35 / (35 + 34 + 38 + 42)

Relative Frequency ≈ 35 / 149

Relative Frequency ≈ 0.2349.

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Mr. Smith can bake 3/5 of the total number of cupcakes he needs in an hour.

Since Mr. Smith can bake 1/5 of the total number of cupcakes he needs in 1/3 hour, we can say that he can bake 3/5 of the total number of cupcakes he needs in an hour, since 1 hour is 3 times as long as 1/3 hour.

To see why this is true, we can think about it in terms of rates.

If Mr. Smith can bake 1/5 of the cupcakes he needs in 1/3 hour, then he can bake (1/5)/(1/3) = 3/5 of the cupcakes he needs in an hour, since dividing by 1/3 is the same as multiplying by 3.

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Answer:

D. 23% decrease

Step-by-step explanation:

To find the percentage of increase or decrease, we can use the following formula:

Percentage change = ((New value - Old value) / Old value) * 100

Let's calculate the percentage change in the price of the television:

Old value = 398

New value = 306.46

Percentage change = ((306.46 - 398) / 398) * 100

Percentage change = (-91.54 / 398) * 100

Percentage change ≈ -22.98%

The percentage change is approximately -22.98%.

Since the value decreased, the correct answer is:

D. 23% decrease

91.54 decrease

91.54/398 ~ 0.23 ~ %23

the answer must have been D

The shape of the Distribution of total points in Mr. Price's science class, more information about the data is needed, such as the number of observations, the range of values, and the presence of any outliers.

If the data is roughly symmetrical with a peak at the center and tails on either end, then the distribution is said to be normally distributed or bell-shaped. This is the most common shape observed in natural phenomena and social sciences.

If the data has a single peak, but the tails are longer on one side than the other, then the distribution is said to be skewed. If the tail is longer on the left side, the distribution is said to be left-skewed or negatively skewed. If the tail is longer on the right side, the distribution is said to be right-skewed or positively skewed.

If the data has multiple peaks, it is said to be bimodal or multimodal. This can occur when there are two or more distinct groups within the data that have different characteristics.

If the data has no discernible pattern, it is said to be uniform or rectangular. This can occur when there is no underlying pattern in the data or when the data has been artificially manipulated to be evenly distributed.

In order to determine the shape of the distribution of total points in Mr. Price's science class, more information about the data is needed, such as the number of observations, the range of values, and the presence of any outliers.

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Note the full question is :

Which describes the shape of the distribution of total points in Mr. Price's science class? Please help ​

Solving the equation, 1 = 2k - 1 for k, we have that k = 1

An equation is a mathematical expression that shows the relationship between two variables.

Since we have the equation 1 = 2k - 1 and we desire to solve for k, we proceed as follows.

1 = 2k - 1

Now first, we desire to isolate the 2k term by adding 1 to both sides of the equation. so, we have that

1 = 2k - 1

1 + 1 = 2k - 1 + 1

2 = 2k + 0

2 = 2k

Now to isolate k, we divide both sides by 2. so, we have that

2k = 2

2k/2 = 2/2

k = 1

so, k = 1

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Answer:

sin²θ

Step-by-step explanation:

* trig identities are sin²θ + cos²θ = 1, sin²θ = 1 - cos²θ.

tan²θ = sin²θ/cos²θ.

sec²θ = 1/cos²θ.

Now we can begin to work it out.

(sec²θ - 1) / (1 + tan²θ)

Simplify sec and tan

((1/cos²θ) - 1) / (1 + (sin²θ/cos²θ))

now multiply every term by cos²θ

((cos²θ/cos²θ) - cos²θ) / ((cos²θ + sin²θ))

= (1 - cos²θ) / 1

= 1 - cos²θ

= sin²θ

The probability that the point chosen is inside the right triangle outlined is approximately 0.3, or 8.33%, rounded to 2 decimal places.

To find the chance that a factor chosen in the ordinary polygon is likewise in the proper triangle mentioned, we need to examine the areas of the two shapes. The location of the everyday polygon may be determined using the formulation:

Area of everyday polygon = (variety of facets × period of 1 side × apothem)/2

The region of the right triangle can be found using the system:

Area of proper triangle = (base × top)/2

The probability is then given by way of the ratio of the 2 areas:

Probability = Area of proper triangle / Area of normal polygon

However, to apply this formulation, we need to recognize some values that aren't given within the query, inclusive of the range of facets, the duration of one facet, the apothem, and the base and peak of the triangle. Without those values, we can't calculate the exact opportunity. We can most effectively estimate it by looking at the discernment and making a few assumptions.

One possible way to estimate the chance is to anticipate that the everyday polygon is a hexagon (has six aspects) and that the right triangle is 1/2 of one among its facets. Then we will approximate the length of one facet as 1 unit and the apothem as 0.866 units (the use of trigonometry). The base and height of the triangle would then be zero. 5 units and 0.866 units respectively.

Using those values, we are able to estimate the areas as follows:

Area of regular polygon ≈ (6 × 1 × 0.866)/2 ≈ 2.598 devices² Area of right triangle ≈ (0.5 × 0.866)/2 ≈ 0.2165 devices²

Probability ≈ 0.2165 / 2.598 ≈ 0.0.33

Therefore, the opportunity is approximately 0.3, or 8.33%, rounded to 2 decimal places.

Note: This is best an estimate primarily based on a few assumptions and approximations. The actual possibility might also vary depending on the actual values of the parameters worried.

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Answer:

B. (1, -2)

Step-by-step explanation:

In order to for it to be a function, the inputs need to have only one output.

The table shows:

(-1, 2), (0, -4), (1, -2), (1, 5), (2, 0), (3, 2), (4, 9)

If a x-value is repeating it is not a function.

The equation of the circle in standard form is (x - 5)² + (y + 4)² = 36

The center of the circle is the midpoint of the diameter.

Using the midpoint formula, we can find the center as follows:

x-coordinate of center = (x-coordinate of endpoint 1 + x-coordinate of endpoint 2)/2

= (-1 + 11)/2

= 5

y-coordinate of center = (y-coordinate of endpoint 1 + y-coordinate of endpoint 2)/2

= (-4 - 4)/2

= -4

So the center of the circle is (5, -4) and the radius is half the length of the diameter:

radius = distance between endpoints of diameter/2

= √(11 - (-1))² + (-4 - (-4))²]/2

= 6

Therefore, the equation of the circle in standard form is (x - 5)² + (y + 4)² = 36

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The county commissioner should test the hypothesis H0: p<=0.5 (null hypothesis) against the alternative hypothesis Ha: p>0.5.

This means that the commissioner assumes that the proportion of people in her district who favor the spending on a sewer system is equal to or less than 50%, and she wants to see if there is enough evidence to reject this hypothesis in favor of the alternative that the proportion is greater than 50%.

The commissioner needs to conduct a hypothesis test to determine if a majority of the people in her district favor the construction of a sewer system. She should test the null hypothesis H0: p<=0.5 against the alternative hypothesis Ha: p>0.5, where p is the proportion of people in her district who favor the spending on the sewer system.

The commissioner will only vote to appropriate funds if she is convinced that the proportion of people who favor the measure is greater than 50%.

In conclusion, by conducting a hypothesis test, the commissioner can determine whether a majority of the people in her district favor the spending on a sewer system and make an informed decision based on the evidence.

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To find the median of a data set when the number of observations is odd, you follow these steps:

Arrange the data set in ascending order.

Identify the middle observation in the ordered data set.

The value of the middle observation is the median.

For example, let's say you have the following data set with an odd number of observations:

3, 5, 1, 2, 4

To find the median, you would:

Arrange the data set in ascending order: 1, 2, 3, 4, 5

Identify the middle observation, which is 3.

Therefore, the median of this data set is 3.

In summary, when the number of observations in a data set is odd, the median is the middle value when the data is arranged in ascending order.

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If a flag pole that is 15 feet tall casts a shadow that is 22 feet long. at the same time of day, the shadow of a nearby tree is 52.3 feet long then the tree is 35.5 feet tall

To determine the height of the tree, we need to use ratios and proportions. We know that the flagpole is 15 feet tall and casts a shadow of 22 feet. Using these values, we can create a proportion:
15/22 = x/52.3
To solve for x, we can cross-multiply:
15 x 52.3 = 22 x
x = (15 x 52.3)/22
x = 35.5
Therefore, the tree is 35.5 feet tall.
In mathematics, proportions are often used to compare two quantities. In this case, we used the ratio of the height of the flagpole to the length of its shadow to create a proportion and find the height of the nearby tree. It's important to note that this calculation assumes that both the flagpole and tree are standing vertically and that the angle of the sun's rays is constant. Understanding and using proportions is a valuable skill in many areas of math and science, including geometry, physics, and engineering. By using ratios and proportions, we can compare different quantities and make calculations that help us better understand the world around us.

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Answer:

105.6 ft

Step-by-step explanation:

1 acre = 43,560 ft²

2/3(43,560) = 29,040

x = width of the lot

Area = (275 ft)(x) = 29,040 ft²

x = 29040/275 = 105.6 ft

Answer:

[tex]\pi 5[/tex]

Step-by-step explanation:

Use the formula [tex]C=\pi d[/tex].

[tex]C=\pi 5[/tex]

So your answer is [tex]\pi 5[/tex].

Answer:

Cos D = 3/5

Step-by-step explanation:

We know that the sine ratio is sin (angle) = opposite/hypotenuse.  Thus, sin F = 3/5 indicates that

The cosine ratio is cos (angle) = adjacent/hypotenuse.

When D is the reference angle, side MD is the adjacent side and DF is the hypotenuse.

Because MD = 3 units and DF = 5 units, Cos D = 3/5

A. From the stem and leaf plot below, there are about 28,000 cars manufactured before 2000.

B. lower quartile (Q1) is between the 7th and 8th values (1995+1997)/2 = 1996. Upper quartile is  the 23rd and 24th values (2009 + 2010) = 2009.5.

C. The number of cars in the city that were manufactured between 1996 and 2009.5 is 37100.

D. To determine the number of car manufactured in 1996 and 2009.5, first determined the relevant proportions from the sample data. Then, multiply the proportion by the total number of cars in the city to estimate the number of cars manufactured before between 1996 and 2007.5,

A. To find the number of cars manufactured at the given period, we find the number of cars sampled that were created before 2000. From the stem-and-leaf plot, we can see that there are 12 cars manufactured before 2000.

Proportion of cars = 12/30 = 0.4.

Using the proportion, we find the number of cars manufactured before 2000.

70,000 × 0.4.

=28,000

B The  lower quartile (Q1) is the 25th percentile, and the upper quartile (Q3) is the 75th percentile.

= 0.25×(n+1)              

= 0.25×(30+1)

= 7.75 Therefore the lower quartile is between 7th and 8th values.

Q1 = (1995+1997)/2 = 1996.

0.75×(n+1)

= 0.75×(30+1)

= 23.25  Therefore the upper quartile is between 23rd and 24th values.

(2009+2010)/2 = 2009.5

C. There are 16 cars manufactured between 1996 and 2009.5

16/30 = 0.53

= 70,000×0.53

= 37100

The answer provided is based on the stem and leaf plot below

3. Brittney randomly selected 30 cars in a parking lot and determined each car's year of manufacture. She made this stem- and-leaf plot to show the results.

CARS IN PARKING LOT-YEAR OF MANUFACTURE

197 | 1

198 | 26

199 | 345577899

200 | 12455677899

201 | 0011222

Key: 197 |1 = 1971

A There are about 70,000 cars in the city where Brittney lives. According to Brittney's data, about how many of the cars in her city were manufactured before the year 2000?

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The best simulation to model the scenario of randomly selecting widgets and recording them as defective or working is a Bernoulli trial simulation.

A Bernoulli trial simulation is used when there are only two possible outcomes, such as success or failure. In this case, the two outcomes are defective or working widgets. The simulation involves randomly selecting a widget and recording whether it is defective or working. This process is repeated multiple times to generate a sample of widgets. The probability of success, or the proportion of defective widgets, is known and remains constant throughout the simulation. This type of simulation is appropriate for modeling the scenario because it allows for the calculation of the probability of selecting a defective widget and can be used to estimate the proportion of defective widgets in the factory's production.

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The degrees of freedom for a two-sample t-test with equal variances depend on the sample sizes of the two populations being compared.

The degrees of freedom for this scenario, we need to first understand the statistical test that would be used to compare the average errors of the two processes.

In this case, the appropriate test would be a two-sample t-test, assuming equal variances.
The formula for calculating the degrees of freedom for a two-sample t-test with equal variances is as follows:

df = n1 + n2 - 2

where n1 and n2 are the sample sizes of the two populations being compared. In this case, since process A is the first population, we can assume that n1 represents the sample size for process A.

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Figure C is the only angle that falls within the Range of 91 to 179 degrees.

An obtuse angle is an angle that measures between 91 and 179 degrees. Therefore, the correct answer is (c) Figure C. An obtuse angle is larger than a right angle (90 degrees) and smaller than a straight angle (180 degrees).

Figure A is a right angle measuring 90 degrees, which is smaller than an obtuse angle. Figure B is an acute angle measuring less than 90 degrees, which is also smaller than an obtuse angle. Figure D is a straight angle measuring 180 degrees, which is larger than an obtuse angle.

Figure C is the only angle that falls within the range of 91 to 179 degrees, making it the correct answer to the question.

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