Answer:
12.7272
Step-by-step explanation:
subtract 10 on both sides
divide by 11 on both sides 11/11>140/11
Answer:
x=130
Step-by-step explanation:
11x+10>=150
11x>= 150-10
11x>=140
x>=140-11
x>=129
so, because "x" is bigger than 129,
so, x=130
Tres profesores compraron libros: uno de ellos pago $845 por 3 libros de Algebra, 5 libros de Geometría Analítica y 2 libros de Cálculo Diferencial. Otro pago $580 por 2 libros de Geometría Analítica, 4 libros de Algebra y 1 libro de Cálculo Diferencial. El último de ellos pago $605 por un libro de Algebra, 3 libros de Geometría Analítica y 3 de Cálculo Diferencial. ¿Cuál es el costo de cada libro según su tema?
Usando un sistema de ecuaciones, se encuentra que
$96.875 es el costo de un libro de Algebra.$23.125 es el costo de un libro de Geometría Analítica.$146.25 es el costo de un libro de Calculo Diferencial.Para el sistema, hay que:
x es el costo de un libro de Algebra.y es el costo de un libro de Geometría Analítica.z es el costo de un libro de Calculo Diferencial.$845 por 3 libros de Algebra, 5 libros de Geometría Analítica y 2 libros de Cálculo Diferencial, o sea:
[tex]3x + 5y + 3z = 845[/tex]
$580 por 2 libros de Geometría Analítica, 4 libros de Algebra y 1 libro de Cálculo Diferencial, o sea:
[tex]4x + 2y + z = 580[/tex]
$605 por un libro de Algebra, 3 libros de Geometría Analítica y 3 de Cálculo Diferencial, o sea:
[tex]x + 3y + 3z = 605[/tex]
Reemplazando la segunda equación en las otras duas:
[tex]z = 580 - 4x - 2y[/tex]
[tex]3x + 5y + 3z = 845[/tex]
[tex]3x + 5y + 3(580 - 4x - 2y) = 845[/tex]
[tex]-9x - y = -895[/tex]
[tex]9x + y = 895[/tex]
[tex]y = 895 - 9x[/tex]
[tex]x + 3y + 3z = 605[/tex]
[tex]x + 3y + 3(580 - 4x - 2y) = 605[/tex]
[tex]-11x - 3y = -1135[/tex]
[tex]11x + 3y = 1135[/tex]
[tex]y = 895 - 9x[/tex], por eso:
[tex]11x + 3(895 - 9x) = 1135[/tex]
[tex]-16x = -1550[/tex]
[tex]x = \frac{1150}{16}[/tex]
[tex]x = 96.875[/tex]
[tex]y = 895 - 9x = 895 - 9(96.875) = 23.125[/tex]
[tex]z = 580 - 4(96.875) - 2(23.125) = 146.25[/tex]
$96.875 es el costo de un libro de Algebra.$23.125 es el costo de un libro de Geometría Analítica.$146.25 es el costo de un libro de Calculo Diferencial.Un problema similar, que también envuelve un sistema de ecuaciones, es dado en https://brainly.com/question/24646137
f(c)=x²-3x
find f (-8)
Answer:
88Step-by-step explanation:
Given function:
f(x) = x² - 3xFind f(-8):
f(-8) = (-8)² - 3(-8) = 64 + 24 = 88f(-8)
(-8)²-3(-8)64+2488Systems of elimination for
2w-3q=8
3w-7q=7
i guess is by multiplying 3by the first equation and multiply 2by the second equation
A jacket usually sells for $68.00. If the jacket is 40% off, and sales tax is 6%, what is the total price of the jacket, including tax?
Answer:
$ 43.25
Step-by-step explanation:
68 - 40% = 40.8
40.8 + 6% = $ 43.25
The angle measurements in the diagram are represented by the following expressions.
Answer:
114 degrees
Step-by-step explanation:
6x+12=3x+63
-3x -12 -3x -12
3x=51
x=17
6(17) +12 = 114
At a charity fund-raiser, adult tickets were sold for $7 each and children's tickets were sold for $2 each. Write an algebraic expression for the total amount of
money raised from the sale of tickets. How much money was raised if the fundraiser fsold 246 adult tickets and 380 children's tickets?
Let a = the number of adult tickets and let c = the number of child tickets. Then, an algebraic expression for the total money raised from the sale of tickets is
Answer:
x is amount of money
c + a = 646
2c + 7a = x
2(380) + 7(246) = 2486
x = $2486
A line passes through the points (1, 4) and (3 -4). Which is the equation of the line?
Answer:
Step-by-step explanation:
(-4 - 4)/(3 - 1)= -8/2= -4
y - 4 = -4(x - 1)
y - 4 = -4x + 4
y = -4x + 8
answer is option 1
PLEASEEEEE HELP…
In Exploration 3.1.2 you went through a procedure that helped you see how a formula
with n compounds per year relates to the formula for compounding continuously. Select
the appropriate answers to model what you did in the exploration.
Annual growth Rate
A (t) = P(1 + r)
n compounds per year
nt
A () = (1+ a)
a =
[Select]
n
let z = -
7
A (t) = P(1 + [b])"
b = (Select)
let n = ar
Ict
C =
[Select)
A (0) P(1)
110) - P{(x - 2)
+
2
The growth amount is given by the growth rate the duration of the growth
and how the rate is applied to each period.
The correct selections are;
a = n[tex]\displaystyle b = \frac{1}{x}[/tex]c = x·r[tex]\displaystyle \lim_{x \to \infty} \left(1 + \frac{1}{x} \right)^x \to 1[/tex]Reasons:
First part;
The given formula for the annual growth rate is; [tex]A(t) = \mathbf{P \cdot \left(1 + r)^t}[/tex]
[tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{r}{[a]} \right)^{n \cdot t}}[/tex]
Where;
P = The principal
r = The rate per period
n = The number of compounding per period
t = The number of periods
In the above formula, we have that the number of compounding per periods = n
Therefore;
a = nWhich gives the fraction of the interest applied to each period as [tex]\displaystyle \frac{r}{n}[/tex]
Which gives;
[tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{r}{n} \right)^{n \cdot t}}[/tex]
Second part;
When [tex]x = \displaystyle \frac{n}{r}[/tex], we have; [tex]A(t) = \mathbf{P \cdot \left(1 + [b])^{n \cdot t}}[/tex]
[tex]\displaystyle A(t) = P \cdot \left (1 + \frac{r}{n} \right)^{n \cdot t}[/tex]
Therefore;
[tex]\displaystyle b=\frac{r}{n}[/tex]
[tex]\displaystyle \frac{1}{x} = \frac{1}{\left(\frac{n}{r} \right)} =\frac{r}{n}[/tex]
Which gives;
[tex]\displaystyle b=\frac{r}{n} = \mathbf{\frac{1}{x}}[/tex]
[tex]\displaystyle \underline{ b = \frac{1}{x} }[/tex]
Third part;
Where, n = x·r, and [tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{1}{x} \right)^{[c] \cdot t}}[/tex]
We have;
[tex]\displaystyle x= \frac{n}{r}[/tex]
[tex]\displaystyle \frac{1}{x}=\frac{r}{n}[/tex]
[tex]\displaystyle A(t) = P \cdot \left (1 + \frac{1}{x} \right)^{[c] \cdot t} = \mathbf{P \cdot \left (1 + \frac{r}{n} \right)^{[c] \cdot t}}[/tex]
Which gives;
c = n = x·r
c = x·rFourth part;
If x is a really large number, we have; [tex]\displaystyle \mathbf{\left(1 + \frac{1}{x} \right)^x}[/tex]
Where x approaches ∞, we have;
[tex]\displaystyle \frac{1}{\infty}=0[/tex]
Which gives;
[tex]\displaystyle \displaystyle \left(1 + \frac{1}{x} \right)^x= \left(1 + \frac{1}{\infty} \right)^\infty = \displaystyle \left(1 + 0\right)^\infty = 1 ^\infty = 1[/tex]
[tex]\displaystyle \underline{\lim_{x \to \infty} \left(1 + \frac{1}{x} \right)^x \to 1}[/tex]Learn more about growth rate formula here:
https://brainly.com/question/2284816
A sixth grade class has 12 boys and 24 girls.
For every 2 boys, there are 4 girls. Do you agree with this statement? Explain.
Answer:
Yes
Step-by-step explanation:
The best way to solve this question is to use ratios. The first ratio to make is 12:24. This represents how there are 12 boys for 24 girls. Ratios remain equivalent as long as both sides of the ratio are simplified by the same number. So, you can divide both sides by 6. When you divide both sides you get 2:4. Therefore, there are 2 boys for 4 girls.
dividing 0.68÷0.6936
Answer:
0.9804
Step-by-step explanation:
0.68 ÷ 0.6936 = 0.98039215686275
at breakfast yusef drinks 16 ounces of water
Answer:
Step-by-step explanation:
K, but what's the question?
In the figure given, what is the (numerical) value of x?
(5a)
(4a)
Lia has 72 green grapes that are shared equally between 8 of her friends. Darrel adds 41 green grapes to his share. How many grapes does Darrel have in all
Darrel has 50 grapes in all.
Lia has 72 green grapes, and she shares them equally between 8 friends. To find out how many grapes each friend receives, divide the total number of grapes by the number of friends:
Number of grapes each friend receives = 72 / 8 = 9
Now, Darrel adds 41 green grapes to his share, so the total number of grapes he has is:
Total grapes for Darrel = Number of grapes Darrel received initially + Additional grapes added by Darrel
Total grapes for Darrel = 9 + 41 = 50
To know more about grapes:
https://brainly.com/question/22694731
#SPJ2
What number president was john quincy adams.
Answer:
6
Step-by-step explanation:
john quincy adams was the 6th president
Cherries cost $4.35 per pound and onions cost $0.98 per pound. Lacey has $21.45 to spend. How many pounds of cherries can Lacey afford if she
has to buy 3 pounds of onions?
Answer:
Lacey could afford 4.25lb of cherries
Step-by-step explanation:
Cost of onions= 3 lb x 0.98/1=2.94
21.45-2.94=18.48$
1 lb=4.35
18.48 x 1lb of cherries/4.35=4.25lb of cherries.
Hope I helped please mark brainliest it means a lot to my progression and thanks! <3
please this is half my grade!!!
Benjamin has a ladder that is 15 ft long. He wants to lean the ladder against a vertical wall so that the top of the ladder is 13.8 ft above the ground. What is the angle, rounded to the nearest tenth, that the ladder makes with the ground? Show your work
2. What is the length of side YZ to the nearest tenth? Show your work.
side XY is 11 feet, and angle Z is 35 degrees(this is a right triangle)
3. What are the exact measures of the other two sides of the triangle? Use special right triangles ratios and show your work.
Side AC is 14 feet, this is a right triangle, and angle A is 30 degrees
The special right triangle is the right triangle that have acute angle values
that simplify the process of finding its dimensions.
The correct values are;
1. The angle the ladder makes with the ground, is approximately 66.93°
2. The length of YZ is approximately 19.18 ft.
3. CB = 7 ft. and AB = 7·√3 ft.
Reasons:
1. The length of the ladder = 15 ft.
Height of the ladder above the ground, h = 13.8 ft.
Required:
The angle the ladder makes with the ground.
Solution:
The angle the ladder makes with the ground is given by the equation;
[tex]sin(\theta) = \dfrac{Length \ of \ the \ ladder}{Height\ of \ the \ ladder \ above the \ ground} = \dfrac{13.8}{15} = 0.92[/tex]
[tex]\theta = arcsin\left(0.92 \right) \approx 66.93^{\circ}[/tex]
2. The given parameters are;
XY = 11
∠Z = 35°
YZ = Required
In a right triangle, the side facing the acute angle is a leg of the triangle.
Therefore;
XY is the opposite side to ∠Z
[tex]sin(\angle Z) = \dfrac{XY}{YZ}[/tex]
Which gives;
[tex]sin(35^{\circ}) = \dfrac{11}{YZ}[/tex]
[tex]YZ= \dfrac{11}{sin(35^{\circ}) } \approx 19.18[/tex]
YZ ≈ 19.18 ft.
3. AC = 14 ft.
∠A = 30
Required:
The length of the other two sides
Solution:
Where by AC is the hypotenuse side, we have;
CB = AC × sin(∠A)
Therefore;
CB = 14 × sin(30°) = 7
CB = 7 ft.
AB = AC × cos(∠A) = 14 × cos(30°) = 7·√3
Learn more here:
https://brainly.com/question/12237712
1. The angle the ladder makes with the ground, is approximately 66.93°
2. The length of YZ is approximately 19.18 ft.
3. CB = 7 ft. and AB = 7·√3 ft.
Twelve football teams are playing in a league. Each team played each of the other teams exactly once. How many matches were played in the league? *
1 point
a. 72
b. 66
c. 11
d. 132
Each team will play with 11 other teams. Hence each team plays 11 games. Hence a total of 11*12 =132 games but since each game involves two teams divide 132/2 = 66 so B
Part A: A store had a 20% off
Black Friday sale. One item was
originally $75. How much was it on
sale for? Part B: if that same store gave an extra 10% off for using their credit card, what’s the final cost of the item (not including tax)
Answer:
Part A: $60
Part B: $54
Step-by-step explanation:
There are 60 students eating lunch in the cafeteria five-tenths of them brought lunches from home. How many students brought lunches from home?
Answer: 30 Hope this helps please mark brainliest! Thanks!
Step-by-step explanation:
Five tenths=5/10=50%=1/2
So basically it's 30 out of 60 students brought lunch from home.
So the answer is 30!
Which two integers is 129 between?
Answer:
128 130
Step-by-step explanation:
128 129 130
Anyone know how to answer this
Answer:
21
Step-by-step explanation:
The average rate of change of function f(x) from x = a to x = b is
[tex] \dfrac{f(b) - f(a)}{b - a} [/tex]
Here we have
a = -1
b = 2
f(a) = f(-1) = 1
f(b) = f(2) = 64
[tex] \dfrac{f(b) - f(a)}{b - a} = [/tex]
[tex] = \dfrac{f(2) - f(-1)}{2 - (-1)} = [/tex]
[tex] = \dfrac{64 - 1}{2 + 1} [/tex]
[tex] = \dfrac{63}{3} [/tex]
[tex] = 21 [/tex]
four more than the price ,p
there are 16 children and 24 adults what percent are children and what percent are adults
Answer:
60% adult
40% children
Reasoning:
Add the adults and children first.
Then find the ratios of the children and parent percentages.
16:40 children
24:40 adult
16/40=2/5=0.4=40% children
24/40=3/5=0.6=60% adult
Answer:
40% is children and 60% in adults
Step-by-step explanation:
so if you add the two you have 40, 100% of 40 is 40 and 50% is 20, so we know that the children percent is less than 50, if you go through you will find that 40% of 40 is 16 therefor leaving the rest (aka 60%) to be adults
State what additional information is required in order to know that the triangles are congruent for the reason given. If possible, write the triangle congruence statement.
refer to attachment
Answer:
SU ≅ RPΔPQR ≅ ΔUTSStep-by-step explanation:
For SSS congruence, all three pairs of sides must be marked as congruent. That is, there needs to be 3 hash marks on sides SU and RP. (Note the order of the vertices.)
needed: SU ≅ RP
If we label the triangles in order by hash marks, the congruence statement becomes ...
ΔPQR ≅ ΔUTS
A baseball tournament begins with 128 teams. After each round of games, only half of the teams are left. How many teams will be left after three rounds of games?
Answer:
End of round 1:
128 ÷ 2 = 64
End of round 2:
64 ÷ 2 = 32
End of round 3:
32 ÷ 2 = 16
Step-by-step explanation:
Answer: 16
Step-by-step explanation: i think :)
the first term of an AP is 2,and the last term is 59.if the sum of the first terms is 610,Find the common difference
Answer:
d = 3
Step-by-step explanation:
The sum to n terms of an AP is
[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] ( a + l)
where a is the first term and l the last term
Here a = 2, l = 59 and sum = 610 , then
[tex]\frac{n}{2}[/tex] (2 + 59) = 610
[tex]\frac{n}{2}[/tex] × 61 = 610 ( divide both sides by 61 )
[tex]\frac{n}{2}[/tex] = 10 ( multiply both sides by 2 to clear the fraction )
n = 20
Then the sequence has 20 terms with a₂₀ = 59
The nth term of an AP is
[tex]a_{n}[/tex] = a + (n - 1)d
where d is the common difference , then
2 + 19d = 59 ( subtract 2 from both sides )
19d = 57 ( divide both sides by 19 )
d = 3
Guys please help asap i don't want to fail
Consider the sequence shown.
Answer:
The answer is option D
Step-by-step explanation:
f (n)=-2. (-5)^n-1. Jesus loves you
Which inequality is best represented by the following number line?
Answer:
A
Step-by-step explanation:
Answer:
solve:
-3x+10<dividing22
-3x< 12
by a negativie flips sign
x>4
So A is correct because the because its an open circle on number line
ANSWER QUICKLY WILL GIVE BRAINLIEST
Answer:
\sqrt(3)[cos((4\pi )/(45))+isin((4\pi )/(45))]
Step-by-step explanation:
The first one.
How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird
The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000
Let
[tex]\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}[/tex]
Then
[tex]Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\[/tex]
Note that since
[tex]F \cap R=\varnothing[/tex], [tex]Perm(F)\cap Perm(R)\ne \varnothing[/tex]
But since
[tex]B \cap R \ne \varnothing[/tex], [tex]Perm(B)\cap Perm(R)= \varnothing[/tex]
and
[tex]B \cap F \ne \varnothing[/tex] , [tex]Perm(B)\cap Perm(F)= \varnothing[/tex]
Since
[tex]|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\[/tex]
where [tex]|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}[/tex]
and
[tex]|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}[/tex]
What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or
[tex]|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}[/tex]
This link contains another solved problem on permutations:
https://brainly.com/question/7951365
