PLEASE HELP!! what is newton’s second law?

Answer:

Explanation:

open pipe :

In open pipe , wavelength of tone produced =  2L / n where n is integer .

3 lowest tone or highest wavelength  = 2L / 1 , 2L / 2 , 2L / 3

= 2L , L , 2L/3

Closed pipe :

In closed pipe , wavelength of tone produced =  4L / n where n is odd integer

3 lowest tone or highest wavelength  = 4L / 1 , 4L / 3 , 4L / 5

= 4L  , 4L / 3 , 4L / 5

Answer:

Life science is alternatively known as biology, and physical science is subdivided into branches: physics, chemistry, Earth science, and astronomy.

Answer:

A, 1.25m/s^2

Explanation:

use formula v=v0+at to solve for a

a= v-v0/t

Plug in givens

30-15/12 to get 15/12 = 1.25m/s^2

Answer: in cases neither of two equations in the system will contain a variable.

Explanation:

Answer:

See the answers below.

Explanation:

a)

The change in momentum can be calculated by means of the following equation.

[tex]P=m*v[/tex]

where:

P = momentum [kg*m/s]

m = mass = 45 [g] = 0.045 [kg]

v = velocity = 20 [m/s]

[tex]P=20*0.045\\P=0.9[kg*m/s][/tex]

b)

The change in momentum can also be calculated by means of the product of force by the duration time of the impact.

[tex]F*t=P\\F*0.006=0.9\\F=0.9/0.006\\F =150 [N][/tex]

Answer:

1. 75 N

2. 6.8351 N

3. 700 N

Explanation:

1. Determination of the weight of the bowling ball:

Mass (m) = 7.5 kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 7.5 × 10

W = 75 N

2. Determination of the weight of the object.

Mass (m) = 683.51 g

Weight (W) =?

We'll begin by converting 683.51 g to kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

683.51 g = 683.51 g × 1 Kg / 1000 g

683.51 g = 0.68351 Kg

Thus, 683.51 g is equivalent to 0.68351 Kg.

Finally, we shall determine the weight of the object as follow:

Mass (m) = 0.68351 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 0.68351 × 10

W = 6.8351 N

3. Determination of the weight of the KHS student.

Mass (m) = 154 lb

Weight (W) =?

We'll begin by converting 154 lb to Kg. This can be obtained as follow:

2.2 lb = 1 Kg

Therefore,

154 lb = 154 lb × 1 Kg / 2.2 lb

154 lb = 70 kg

Thus, 154 lb is equivalent to 70 kg.

Finally, we shall determine the weight of the KHS student as follow:

Mass (m) = 70 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 70 × 10

W = 700 N

Answer:

300 m/s

Explanation:

Step one:

Given data

Mass of players head m1= 5kg

The initial velocity of players head u1= 3.2m/s

mass of ball m2= 0.5kg

Initial velocity of ball= 5 m/s

Final velocity of player= 2.5 m/s

Required

The velocity of the ball after collision

Step two:

Applying the conservation of momentum formula for elastic collision

m1u1+m2u2= m1v1+m2v2

substitute

5*32+0.5*5= 5*2.5+0.5*v2

160+2.5= 12.5+0.5v2

collect like terms

162.5-12.5= 0.5v2

150= 0.5v2

divide both sides by 0.5

v2= 150/0.5

v2=300 m/s

The new velocity of the ball is 300 m/s

This question is incomplete, the complete question is;

A driver takes 3.5 s to react to a complex situation while driving at a speed of 60 mi/h.

How far does the vehicle travel before the driver initiates a physical response to the situation (i.e., putting his or her foot on the brake)

Answer:

the distance travelled by the vehicle, before the driver initiates a physical response is 308 ft

Explanation:    

Given that;

Reaction time t = 3.5 sec

Speed S = 60 mi/h

we convert mile to foot and hour to seconds

so

Speed S = 60 mi/h =  (60×5280)/(60×60) = 316800/3600 = 88 ft/sec

Now, The distance travelled by vehicle before the driver  initiates physical response is equal to Lag distance. i.e

Lag distance = V × t

we substitute

Lag distance = 88 ft/sec  3.5 sec

Lag distance = 308 ft

Therefore, the distance travelled by the vehicle, before the driver initiates a physical response is 308 ft

This question is incomplete, the complete question is;

The electric force due to a uniform external electric field causes a torque of magnitude 20.0 × 10⁻⁹ N⋅m on an electric dipole oriented at 30° from the direction of the external field. The dipole moment of the dipole is 7.5 × 10⁻¹² C⋅m.

What is the magnitude of the external electric field?

If the two particles that make up the dipole are 2.5 mm apart, what is the magnitude of the charge on each particle?

Answer:

- the magnitude of the external electric field is 5333.3 N/C

- the magnitude of the charge on each particle is 3.0 × 10⁻¹² C  ≈ 3 nC

Explanation:

Given that;

Torque = 20.0 × 10⁻⁹ N⋅m

dipole moment = 7.5 × 10⁻¹²

∅ = 30°

The moment T of restoring couple is;

T = PEsin∅

E = T/Psin∅

we substitute

E = 20.0 × 10⁻⁹ N⋅m / (7.5 × 10⁻¹²) sin(30°)

E = 20.0 × 10⁻⁹ / 3.75 × 10⁻¹²

E =  5333.3 N/C

Therefore, the magnitude of the external electric field is 5333.3 N/C

The dipole moment is given by the expression;

p = ql

q = p / l

given that l = 2.5 mm = 0.0025 m

we substitute

q = 7.5 × 10⁻¹² / 0.0025

q = 3.0 × 10⁻¹² C ≈ 3 nC

Therefore, the magnitude of the charge on each particle is 3.0 × 10⁻¹² C ≈ 3 nC

Answer:

Explanation:

As we know that ,

P=F/A

Where P=12 lb/in²  and A= 0.2 in²

Putt in formula to get F ( weight of body)

F=12*0.2

F=2.4 Ib

Answer:

C

Explanation:

Answer:

the answer to this question is D

Explanation:

hope its helps

have a great day

Answer:

the horizontal velocity while it was falling is 22.1 m/s.

Explanation:

Given;

height of fall, h = 16 m

horizontal distance, x = 40 m

The time to travel 16 m is calculated as;

[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 16}{9.8} } \\\\t = 1.81 \ s[/tex]

The horizontal velocity is calculated as;

[tex]v_x = \frac{X}{t} \\\\v_x = \frac{40}{1.81} \\\\v_x = 22.1 \ m/s[/tex]

Therefore, the horizontal velocity while it was falling is 22.1 m/s.

The horizontal velocity while it was falling is

Horizontal velocity becomes important for objects moving in a horizontal direction. Generally, horizontal velocity is horizontal displacement divided by time, such as mph or m/s.

Therefore, from equation of motion

[tex]Time, t = \sqrt\frac{2h}{g}\\\\t = \sqrt\frac{2*16}{9.8}\\\\t = 1.81sec[/tex]

Therefore, the horizontal velocity, [tex]V_h[/tex]

[tex]V_h = \frac{x}{t}\\\\V_h = \frac{40}{1.81}\\\\V_h = 22.09 or 22.1m/s[/tex]

For more information on horizontal velocity, visit

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250kg

                                        would have momentum that is being caried by the impact of the trow                                                                                                                    

Explanation:

A star is in equilibrium when the pressures inside the star balance out the force of gravity. The pressure is thermal pressure resulting from the fusion reactions taking place in the star's core. A star stays in equilibrium until the supply of hydrogen in the core is depleted.

In a stable star, the gas pressure pushing out from the center is equal with the gravity pulling atoms inward to the center – when these forces are equal, the star is at equilibrium. Once a star reaches equilibrium for the first time, it will start burning (fusing) hydrogen into helium.

Answer: It has enough mass to resist expansion.

Question:

A high ____will have a short wavelength

Answer:

That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength. Light waves have very, very short wavelengths

Explanation:

Hope it help

Explanation:

Wave Is The Answer

HighWave

Answer:

Increasing the force acting on an object will increase its acceleration

Explanation:

The force acting on an object is given by the formula as follows :

F = ma

Where

m is mass and a is acceleration of the object

It can be seen that the force and the acceleration are directly proportional to each other.

It means if we increase the acceleration of the object, the force will increase and vice versa.

Hence, the correct option is (c) "Increasing the force acting on an object will increase its acceleration".

Answer:

i think Increasing the force acting on an object will increase its acceleration

Explanation:

This question is incomplete, the complete question is;

The two 60 cm in diameter cylinders in Figure 13.15, closed at one end, open at the other, are joined to form a single cylinder, then the air inside is removed.

a) How much force does the atmosphere exert on the flat end of each cylinder?

b) Suppose one cylinder is bolted to a sturdy ceiling. How many 81 kg football players would need to hang from the lower cylinder to pull the two cylinders apart ?

Answer:

a) the atmosphere exert a force of 2.9 × 10⁴ N on the flat end of each cylinder

b) 36 football players each of 81 kg are needed to pull the two cylinders apart.

Explanation:

Given that;

diameter of cylinder is 60 cm = 0.6 m

then radius r will be 0.6/2 = 0.3 m

a)

How much force does the atmosphere exert on the flat end of each cylinder;

we know that; F = PA

inside its the flats end that its in question; Area A = πr².

We Know that, Pressure P due to atmosphere is 1.013 × 10⁵ Pa

so, F = 1.013 × 10⁵ Pa × π( 0.3 )²

F = 1.013 × 10⁵ Pa × 0.09π

F =  28641.9 N ≈ 2.9 × 10⁴ N

Therefore, the atmosphere exert a force of 2.9 × 10⁴ N on the flat end of each cylinder.

b) number of players needed to pull the two cylinders apart.

given that; m = 81 kg and g is 9.8 m/s²

n = F / mg

we substitute

n = 28641.9 / (81 × 9.8)

n = 28641.9 / 793.8

n = 36.08 ≈ 36

Therefore, 36 football players each of 81 kg are needed to pull the two cylinders apart.

Answer:

The centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².

Explanation:

The centripetal acceleration is given by:

[tex] a_{c} = \frac{v^{2}}{r} [/tex]

Where:

[tex] v^{2}[/tex]: is the tangential speed = 9.50 m/s

r: is the distance = 6.00 m

Hence, the centripetal acceleration is:

[tex] a_{c} = \frac{v^{2}}{r} = \frac{(9.50 m/s)^{2}}{6.00 m} = 15.04 m/s^{2} [/tex]

Therefore, the centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².

I hope it helps you!

Answer:

10.8n

Explanation:

For this case the centripetal force is given by:

Where,

m: mass of the object

v: tangential speed

r: rope radius

Substituting values in the equation we have:

Then, doing the corresponding calculations:

Answer:

The centripetal force exerted on the rope is:

Answer:

[tex]V_R=5.80mph(-\hat j )[/tex]

Explanation:

From the question we are told that

Speed of man [tex]V_m=3.30mph[/tex]

Speed of wind  [tex]V_w=-2.70mph[/tex]

Generally the Relative wind speed V_R is mathematically given directly as

   [tex]V_R=V_w-V_m[/tex]

   [tex]V_R=-2.7-3.30[/tex]

   [tex]V_R=-5.80mph[/tex]

Therefore the relative wind speed will the person sense

   [tex]V_R=5.80mph(-\hat j )[/tex]

Answer:

The Answer is D

Explanation:

Hope this helps!!!

Answer:

The most likely answer is option C: She lost body mass during the flight due to a decrease in metabolism.

Explanation:

There are different theories regarding this. One of fact is that astronauts drink and eat considerably less than normal during the first day of flight (probably due to sickness before adaptation). It is thought that their bodies adapt to the changes in accelerations they suffer during the trip and in space.

Answer:

Wavelength

Explanation:

Velocity of a wave is given by

[tex]v=f\lambda[/tex]

where

[tex]f[/tex] = Frequency of wave = [tex]f=\dfrac{v}{\lambda}[/tex]

[tex]\lambda[/tex] = Wavelength of wave

We have the relation

[tex]f\propto \dfrac{1}{\lambda}[/tex]

Now, velocity of the wave in a given medium remains constant. So, if the frequency increases the wavelength must decrease in order to keep the velocity of the wave constant. Also if the frequency decreases the the wavelength increases.

Answer:

Heat causes the molecules to move faster, (heat energy is converted to kinetic energy ) which means that the volume of a gas increases more than the volume of a solid or liquid.

Through nuclear fusion, the sun is constantly using up the hydrogen in its core: Every second, the sun fuses around 620 million metric tons of hydrogen into helium. At this stage in the sun's life, its core is about 74% hydrogen.

Answer:

  fr = 245 N,  T = fr

Explanation:

We can solve this exercise using the equilibrium conditions, let's start by creating a reference system

where we call T the drag force of the gorilla, m the mass of the trunk and μ the coefficient of kinetic friction

Y axis  

           N- W =

           N = W = mg

X axis

          T - fr = 0

          T = fr

the expression for the friction force is

          fr = μ N

          fr = μ mg

we substitute

           T = μ m g

When analyzing these expressions we see that when the trunk reaches the maximum speed that the gorilla carries, the friction force is equal to the gorilla's tension

            fr = T

for a specific calculation we must assign values ​​to:

      μ = 0.25

      m = 100 kg

let's calculate

         T = 0.25 100 9.8

         T = 245 N

therefore for this case

         fr = 245 N

Answer:

[tex]Y_A=277.128 \angle 30v[/tex]

[tex]Y_B=277.128 \angle (-150)v[/tex]

[tex]Y_C=277.128 \angle (90)v[/tex]

Explanation:

From the question we are told that

Voltage [tex]V_L_L =480v[/tex]

Generally in a case of Y_connection [tex]V_p_ h[/tex] is mathematical represented as

[tex]V_p_h=\frac{V_l_l}{\sqrt{3}} \angle (\phi-30)v[/tex]

Generally voltage drop across phase A

[tex]Y_A=\frac{408}{\sqrt{3}} \angle -(0-30)[/tex]

[tex]Y_A=277.128 \angle 30v[/tex]

Generally voltage drop across phase B

[tex]Y_B=277.128 \angle (-30-120)[/tex]

[tex]Y_B=277.128 \angle (-150)v[/tex]

Generally voltage drop across phase C

[tex]Y_C=277.128 \angle (-30+120)[/tex]

[tex]Y_C=277.128 \angle (90)v[/tex]