please help
(a) Is it safe to place the plant box on a window ledge that can support a maximum weight of 2400 grams? Explain why or why not.
(b) Would the density of the soil change if the plant box was only half full? Explain.

Answer:

Step-by-step explanation:

Ray can be defined as a part of a line that has a fixed starting point but no end point.

The starting point is B and on its way to infinity, it passes through point A.

Correct sign is

[tex]\huge\boxed{\overrightarrow{BA}}[/tex]

Answer:

is A

Step-by-step explanation:

Negative 2.5, 1 and three-fourths, 50 percent, 1.5

Pls Mark Brainliest

Answer:

The first choice on edge / A

Step-by-step explanation:

don't come at me if its wrong

Answer:

it should be 319

Step-by-step explanation:

Answer:

639 is the answers for the question

Step-by-step explanation:

please mark me as brainlest

Answer:

19

Step-by-step explanation:

tan35=x/20

20tan35=x

x=14.0041507641942

x+5=19.0041507641942

Nearest foot is 19

i

Step-by-step explanation:

i

Answer:

Option

Step-by-step explanation: The way tell what the answer is are the similar lines. The single yellow line helps indicate that it's a similar angle.

Answer:

0riginal price = 4900

Step-by-step explanation:

294 = 6%

294/6 = 49 49 = 1%

49 x 100 = 4900

0riginal price = 4900

Answer:

RSP, ZXY

SRP, XZY

RPS, ZYX

Step-by-step explanation:

Obviously, the numbers match each other.

ex. R = 41, Z = 41

Those two have the ability to pair in the same order

The value of the expression for the given values is 1294139

From the question, we are to rewrite the expression

(11j⁻³k²) (j³k⁴)

This can be rewritten as

11 × j⁻³ × k² × j³ × k⁴

11 × j⁻³ × j³ × k² × k⁴

11 × j⁻³⁺³ × k²⁺⁴

11 × j⁰× k⁶

= 11 × 1 × k⁶

= 11k⁶

Now we are to evaluate the expression for when j = -8 and k  = 7

The expression is

= 11 × k⁶

= 11 × 7⁶

= 1294139

Hence, the value of the expression for the given values is 1294139

Here is the complete question:

Use the properties of exponents to rewrite this expression. Then evaluate the rewritten expression for the given values to

complete the statement.

(11j⁻³k²) (j³k⁴)

When j = -8 and k = 7

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Answer:

539

Step-by-step explanation:

Answer:

Step-by-step explanation:

Assuming you are looking for x

2.8 + 32x + 1 = 16.6

32x = 16.6 - 2.8 - 1

32x = 12.8

x = 12.8 : 32

x = 0.4

-----------------------

check

2.8 + 32 * 0.4 + 1 = 16.6

2.8 + 12.8 + 1 = 16.6

16.6 = 16.6

the answer is good

We make use of the row percentage for comparisons

From the question, we have:

The data represented by the independent variable is always used to make comparison

Since this variable is on the rows, then the row percentage would be used for comparisons

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The error happens in the last line.

The relevant log rule is ln(A) - ln(B) = ln(A/B)

The issue is that the 0 isn't ln(0), so that 0 cannot be thrown into the natural log like that.

What we can do is this set of steps

ln(3x) - 0

ln(3x) - ln(1)

ln(3x/1) ... applying the log rule mentioned

ln(3x)

But these steps are a needlessly overcomplicating things. We can simply go from ln(3x)-0 to ln(3x) in one step. Subtracting off zero doesn't change ln(3x) at all.

--------------------------

Let's continue the steps to solve for x.

ln(x^2) = ln(3x)

x^2 = 3x

x^2-3x = 0

x(x-3) = 0

x = 0 or x-3 = 0

x = 0 or x = 3

Those are the two possible solutions.

However, x = 0 isn't valid because it's not in the domain of ln(x^2). In other words, ln(0) isn't defined. The domain of y = ln(x) is x > 0

This means that x = 3 is the only solution.

Answer:

A

Step-by-step explanation:

(4x² + 2x - 3) + (3x² + 6)

= 4x² + 3x² + 2x - 3 + 6

= 7x² + 2x + 3

Answer :

A and E .

Step-by-step explanation:

Step-by-step explanation:

Let, the given point of the equation of the line are (3,-1) and (0,3) i.e

(x1,y1)=(3,-1) and (x2,y2) = (0,3)

Now,

The slope of the line (m1) = y2-y1 ÷ x2-x1

= 3-(-1) ÷ 0-3

= 3+1 ÷ -3

= 4/-3

since, the lines are parallel i.e.

m1 = m2

or, m2 = -4/3

Again,

The required equation of the line passing through the point (-3,2)=(x1,y2) is

y-y1 = m2(x-x1)

or, y-2 = -4/3 ( x +3)

or, 3(y-2) = -4(x+3)

or, 3y-6 = -4x - 12

or, 4x+3y = -12+6

Therefore, 4x+3y = -6 is the right answer.

The cost of book case be $ 11.6.

A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form

                                       Ax + B = 0.

Here, let the cost of book case be $ x

       and the cost of pencil case be $ y

Now, Helen purchased 3 books and 2 pencils in $ 74.

         3x + 2y = 74    .......(i)

Cost of pencil case $ 8 less than the book.

          y - 8 = x      ............(ii)

put the value of x in equation (i), we get

    3(y - 8) + 2y = 74

    3y - 24 + 2y = 74

    5y = 74 + 24

     5y = 98

      y = 98/5

      y = $ 19.6

put the value of y in equation (ii), we get

   x = y -8

   x = 19.6 - 8

   x = $ 11.6

Thus, the cost of book case be $ 11.6.

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[tex]-3(x^{2} +5x+10)[/tex] is the standard form of the given expression

The given expression is:

[tex]=-3(x+3)^{2} -3+3x\\\\=-3*(x^{2} +2*3*x+3^{2} )-3+3x\\\\=-3x^{2} -3*6x-3*9-3+3x\\\\=-3x^{2} -18x-27-3+3x\\\\=-3x^{2} -15x-30\\\\=-3(x^{2} +5x+10)[/tex]

This is the standard form of the given expression.

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Answer: £20 doubling at the end of each year for 5 years

From the question, Stephen would want to select one option which gives the highest amount of profit. I mean, even if you were to select one, you would obviously try calculating all the 4 choices to see which one makes you earn the most money. Now let's conduct the workout and see which one will earn us the most £ in 5 years:

Option 1:
[tex](500*\frac{5}{100} ) + 500 ---- > 1yr\\= 25 + 500 \\ = 525\\\\(525*\frac{5}{100} ) + 525 ----- > 2yrs\\= 26.25 + 525\\= 551.25\\\\(551.25 * \frac{5}{100}) + 551.25 - - - > 3yrs\\ = 27.563 + 551.25\\= 578.813\\\\(578.813 * \frac{5}{100}) + 578.813 - - > 4 yrs\\ = 28.941 + 578.813\\ = 607.754 \\\\(607.754 * \frac{5}{100}) + 607.754 - - > 5 yrs\\ = 30.388 + 607.754\\ = 638.142 \\[/tex]

ans: £ 638.142

Option 2:

[tex]1 year = 12 months\\5 years : 5*12 = 60 months\\\\10*60 = 600[/tex]

ans: £ 600

Option 3:

[tex](550*\frac{3}{100}) + 550 - - - - > 1yr\\= 16.5 + 550\\= 566.5 \\\\(566.5 * \frac{3}{100}) + 566.5 - - - > 2 yrs\\ = 16.995 + 566.5\\= 583.495\\\\(583.495 * \frac{3}{100}) + 583.495 - - > 3 yrs\\ =17.505 + 583.495\\= 601\\\\(601 * \frac{3}{100}) + 601 - - - - - - > 4 yrs\\= 18.03 + 601\\= 619.03\\\\( 619.03* \frac{3}{100}) + 619.03 - - - - > 5 yrs\\= 18.571 + 619.03\\= 637.601[/tex]

ans: £ 637.601

Option 4:

[tex]20*2= 40 - - - - > 1yr\\40 * 2= 80 - - -- > 2 yrs\\80*2 = 160 - - - > 3 yrs\\160*2 = 320 - - - > 4 yrs\\320*2= 640 - - - > 5yrs[/tex]

ans: £ 640

Out of all the calculated answers, you can see that option 4 has the highest amount. So that's it. By the way, I might do some incorrections in some calculations because I am not good at long maths, but yes i hope I did it all right!

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   hope it helped
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Using the Poisson distribution, it is found that:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

In this problem, the mean is of [tex]\mu = 16[/tex], hence the probability of 15 patients in a day is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 15) = \frac{e^{-16}16^{15}}{(15)!} = 0.0992[/tex]

Hence the mean number of days in a month (30 days) with 15 patients visiting is given by:

M = 30 x 0.0992 = 2.976.

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Answer: By adding 2 to y and subtracting x by 3.

Step-by-step explanation: Let’s use the equation y = x since it’s simple. In order to translate an equation anywhere to the right, you have to subtract x by a unit. Since it’s 3 units, the equation is now y = x - 3. To translate an equation down, you have to add a unit to y. Since the questions asks for two units, add 2 to y. The equation should now be y + 2 = x - 3.

The relationship between the average rates is that ; The average rate of return trip is twice the average rate of front trip.

From the complete question seen online, we can say that;

Time taken on front trip = t

Time taken on return trip = 1/2 × t = t/2

Relationship between speed(Rate) and time is;

Rate ∝ 1/time

This means that Rate is inversely proportional to time.

Thus, for the front trip, the rate is; r = 1/t

For return trip, the rate is; R = 1/(t÷2)

R = 1 × 2/t

R = 2/t

Rate of front trip = 1/t

Rate of return trip = 2/t

Thus, we can say that the average rate of return trip is twice the average rate of front trip.

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Answer:

The first one (x=1 and y=1/2)

Step-by-step explanation:

The first table is the only one that has a constant rate of change.  The x value increases by 1, and the y value increase by 1/2.

Hope this helped :)

Answer:

The first one where x increases by 1 and y increases by 1/2.

Step-by-step explanation:

To find the equation, 1/2=1+b

Solve for b

1/2-1=-0.5

B=-0.5

Now, solve for x

1/2=x-0.5

As you can already see in the table, x increase by 1, so no need to even solve.

The equation would be y=1x-0.5 (I’ll post the graph in the picture to prove it is linear.

A linear equation is an equation of a straight line, which means that the degree of a linear equation must be 0 or 1 for each of its variables. In this case, the degree of variable yy is 1 and the degree of variable x is 1.

Answer:

range of f is [0,3]

Step-by-step explanation:

The "square root" symbol, [tex]\sqrt{\text{ \quad }}[/tex], is a function.  As a result, it only has a single output because functions must only have a single output for each input.

Thinking about it graphically, if the square root function did give both a positive and a negative result, the function "f" would not pass the vertical line test and it would not be a function.

When solving an equation like [tex]x^2=25[/tex], to solve, we must apply the square root property.  The square root property says that to find both solutions, one must look at both the positive and the negative of the square root.  So, to solve:

[tex]x^2=25[/tex]

Apply square root property...

[tex]\sqrt{x^2} = \pm \sqrt{25}[/tex]

[tex]x=\sqrt{25}[/tex]  or  [tex]x=-\sqrt{25}[/tex]

[tex]x=5[/tex]  or  [tex]x=-5[/tex]

In this case, because the square root function itself only outputs non-negative results (so, including zero, as you already identified), the range will only be [0,3].

Step-by-step explanation:

Hi There! Let me help you :)

[tex] = 8.8.8.8.8.8.8[/tex]

[tex] = ( \text{there \: are \: 7 \:numbers \: eight })[/tex]

[tex] \: [/tex]

So we can rewrite the above equation to be like this.

[tex] = 8.8.8.8.8.8.8[/tex]

[tex] = 8.(1 + 1 + 1 + 1 + 1 + 1 +1)[/tex]

[tex] = 8.7[/tex]

Answer:102

Step-by-step explanation:

34 x 3 = 102

Answer:

102

Step-by-step explanation:

Since Jack has 34 toy cars and Mike has 3 times more than Jack's toys, we should multiply 34 with 3 to get the answer.

34 * 3 = 102

So, this means that Mike has 102 toy cars.\

Hope this helps :)

Answer:

Round of 969.991

970

Rules of round off

1) If the digit is odd no. the no. will increase to 1

2) if it is even the no. will be same.

Answer:

[tex] \sqrt{30} [/tex]

Step-by-step explanation:

altitude rule

10 / x = x / 3

x^2 = 30

x = sqrt(30)

Answer:

its 3.348 - crown pls

Step-by-step explanation:

easiest way of doing this is multiplying the total by the known number then put that number on top. After that divide and check if its right