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A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.
1. Calculate the impulse delivered to the ball.
2. What was the change in momentum of the ball?
3. What was the velocity of the ball as it left the tennis racket?
4. What would happen to the ball's velocity if it remained on the tennis racket longer than .05 s?

Answer: 20

Explanation: cause

Explanation:

When two or more atoms link up, they create a molecule. e.g, A molecule of water is made of two atoms of hydrogen (H) and one atom of oxygen (O).

Answer:

See the explanation below,

Explanation:

Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.

[tex]P=m*v[/tex]

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

A)

[tex]P = 10000*0\\P=0[/tex]

B)

[tex]P=100*5\\P=500[kg*m/s][/tex]

C)

[tex]P=1200*15\\P=18000[kg*m/s][/tex]

D)

[tex]P=15*1000\\P=15000[kg*m/s][/tex]

From higher to lower momentum

C,D,B,A

Answer:

Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages. Absolute dating is used to determine a precise age of a fossil by using radiometric dating to measure the decay of isotopes, either within the fossil or more often the rocks associated with it.

Answer:

It begins to increase

Explanation:

As the surfaces move slowly and then increase their relative speeds, the coefficient of kinetic friction begins to increase until it reaches it terminal value in which, it can no longer increase.

Answer:

For two waves of equal amplitude interfering constructively, the resulting amplitude is twice as large as the amplitude of an individual wave. For 100 waves of the same amplitude interfering constructively, the resulting amplitude is 100 times larger than the amplitude of an individual wave.

Answer:

Δp = 620 N.s

Explanation:

       [tex]F = \frac{\Delta p}{\Delta t} (1)[/tex]

       for m= constant, it reduces to F= m*a.

       [tex]\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)[/tex]

Answer: The difficulty comes in the modulation, and in the fact that X-rays can't be transmitted via wires or fiber.

Explanation: Mark me as brainlisti

Answer:

B. Evaporation

Explanation:

Because I am absolutely positive

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Answer:

Explanation:

Let the velocity of firing be u at angle θ

At maximum height velocity will be equal to horizontal component of initial velocity or vcosθ

So , vtop = v cosθ

At height h/2

vertical component of velocity v₂

v₂² = (usinθ)² - 2 g . h/2

v₂² = u²sin²θ - gh

horizontal component of velocity at height h/2 = u cosθ

velocity at height h / 2

= √ ( u²sin²θ - gh + u² cos²θ)

Given

√ ( u²sin²θ - gh + u² cos²θ) = 2 vtop

u²sin²θ - gh + u² cos²θ = 4 v²top = 4 u² cos²θ

u²sin²θ - gh =  3 u² cos²θ

At height h , vertical component of velocity is zero

0 = u²sin²θ - 2gh

gh = u²sin²θ / 2

u²sin²θ - u²sin²θ / 2  =  3 u² cos²θ

u²sin²θ / 2  = 3 u² cos²θ

Tan²θ = 6

Tanθ = 2.45

θ = 68⁰ .  

Answer:

e

Explanation:

Answer:

Explanation:

For a string of length L clamped down on both ends , for fundamental mode of vibration

2 . λ / 4 = L

= λ / 2 = L

λ = 2 L

For other modes , the formula is

n . λ/2 = L where n is an integer .

λ = 2L / n

if n = 6

λ = 2L / 6

= L/3

So wavelength = L/3 is possible .

Answer:

the  ratio of r₂/r₁ is 1.37.

Explanation:

Given;

magnitude of electric field strength at a distance r₁, E₁ = 300 N/C

magnitude of electric field strength at a distance r₂, E₂ = 160 N/C

Electric field strength is given as;

[tex]E = \frac{kQ}{r^2} \\\\E_1r_1^2 = E_2r_2 ^2\\\\\frac{E_1}{E_2} = \frac{r_2^2}{r_1^2} \\\\\frac{E_1}{E_2} =( \frac{r_2}{r_1})^2\\\\\sqrt{\frac{E_1}{E_2} } = \frac{r_2}{r_1}\\\\\frac{r_2}{r_1} = \sqrt{\frac{300}{160} }\\\\\frac{r_2}{r_1} =1.37[/tex]

Therefore, the  ratio of r₂/r₁ is 1.37.

Answer:

the work that must be done to stop the hoop is 2.662 J

Explanation:

Given;

mass of the hoop, m = 110 kg

speed of the center mass, v = 0.22 m/s

The work that must be done to stop the hoop is equal to the change in the kinetic energy of the hoop;

W = ΔK.E

W = ¹/₂mv²

W = ¹/₂ x 110 x 0.22²

W = 2.662 J

Therefore, the work that must be done to stop the hoop is 2.662 J

The amount of work that must be done to stop a hoop of mass 110 kg moving with s speed of 0.220 m/s is 2.662 J

Work can be defined as the ability or the capacity to perform work. Work is also the measure of energy of a body. The S.I unit of work is Joules (J)

Formular for kinetic energy of the hoop is

EK = mv²/2.................... Equation 1

Where EK = Kinetic energy of the hoop, m = mass of the hoop, v = velocity of the hoop.

Given: m = 110kg, v = 0.220 m/s.

Substitute these values into equation 1

EK = 110(0.22)²/2

Ek = 2.662 J.

Therefore, The amount of work that must be done on the hoop to stop it is

Learn more about Work here: https://brainly.com/question/12106685

The common characteristics  of planets do Saturn and Earth share is they both have moon. Saturn have 13 moons and earth have only one moon.

Moons of planets are spatial objects which revolves around a planet and experiences gravitational pull from the planet. Both saturn and earth are planets of solar system.

The earth that is the only planet planet with living things have only one moon which is called moon itself. Earth is entirely different from the composition and nature of all other planets.

Saturn have 13 moons namely, enceladus, janus, mimas etc. Saturn have some rings made of dust and gases which are not found for any other planet. The composition and gaseous matter in saturn is different from that of earth.

To find more on saturn, refer here:

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Answer:

combustion reaction

glucose,oxygen

carbon dioxide,water,energy

8

no. required balanced equation is:

C6H12O6+6O2--->6CO2+6H2O+energy

endothermic as it needs heat in the form of sunlight.

Answer:

The answer is :(B) 1.9 N

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Answer:

a. 0.143 mm b. 77.6 rad/m c. 483.18 rad/s  d. +1

Explanation:

a. ym

Since the amplitude is 0.143 mm, ym = amplitude = 0.143 mm

b. k

We know k = wave number = 2π/λ where λ = wavelength.

Also, λ = v/f where v = speed of wave in string = √(T/μ) where T = tension in string = 19.3 N and μ = mass per unit length = 5.12 g/cm = 5.12 ÷ 1000 kg/(1 ÷ 100 m) = 0.512 kg/m and f = frequency = 76.9 Hz.

So, λ = v/f = √(T/μ)/f

substituting the values of the variables into the equation, we have

λ = √(T/μ)/f

= √(19.6 N/0.512 kg/m)/76.9 Hz

= √(38.28 Nkg/m)/76.9 Hz

= 6.187 m/s ÷ 76.9 Hz

= 0.081 m

= 81 mm

So, k = 2π/λ

= 2π/0.081 m

= 77.6 rad/m

c. ω

ω = angular frequency = 2πf where f = frequency of wave = 76.9 Hz

So, ω = 2πf

= 2π × 76.9 Hz

= 483.18 rad/s

d. The correct choice of sign in front of ω?

Since the wave is travelling in the negative x - direction, the sign in front of ω is positive. That is +1.

Answer:

The work done will be [tex]W=55.27\: J[/tex]

Explanation:

The work equation is given by:

[tex]W=F\cdot x[/tex]

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

[tex]F_{x-direction}=mgsin(28)[/tex]

Therefore, the work done will be:

[tex]W=mgsin(28)*3[/tex]

[tex]W=4*9.81*sin(28)*3[/tex]

[tex]W=55.27\: J[/tex]

I hope it helps you!

Answer:

Gravitation Potential Energy and Elastic Potential Energy

Explanation:

PE=abbreviation for potential energy

PE is a mechanical energy like KE is. There are two types of PE in high school physics (do not talk about other PE's like chemical PE).

Elastic PE is like the stored energy for example in a pole vault competition, the Elastic PE is stored in the pole before the vaulter goes over the desired height. (Energy stored in ELASTIC object ONLY) (commonly on the 11th grade regents springs are used to represent elastic PE)

Gravitational PE can be calculated through the formula PE=mgh although some people substitute the PE with a U. (ENERGY STORED IN OBJECT'S HEIGHT)

Answer: the contents of this container weighs 4905 kg.m/s²

Explanation:

Given that;

volume of a container V = 0.5 m³

we know that standard gravitational acceleration g = 9.81 m/s²

specific volume of liquid filled in the container v = 0.001 m³/kg

now we express the equation for weight of the container.

W = mg

W = (pV)g

W = Vg / ν

so we substitute

W =  (0.5 m³)(9.81 m/s ) / 0.001 m³/kg

W = 4.905 / 0.001

W = 4905 kg.m/s²

Therefore, the contents of this container weighs 4905 kg.m/s²

Answer: C. A stove burner that glows red when it is turned on

Explanation:

I did the quiz

Answer:

0m/s²

Explanation:

The acceleration of the given body whose motion has been described will be zero.

This is because the body moves with a constant velocity.

Acceleration is defined as the rate of change of velocity with time.

Since in this problem, the velocity is not changing per time, then the acceleration would be zero.

A body moving steadily implies that such body is not changing its motion by the virtue of its velocity and even direction.

Answer:

98

Explanation:

Answer:

friction, air resistance

Explanation:

Answer:

The sign of the velocity depends on the coordinate system chosen to define the position. A positive velocity simply means that the object is moving in the positive direction, as defined by the coordinate system, while a negative velocity means the object is traveling in the other direction.

- Hope this helps!

Answer: The more massive one will have larger kinetic energy.

Explanation:

We know that when we drop an object, the acceleration of the object will be equal to the gravitational acceleration.

a(t) = -9.8m/s^2

And to get the velocity, we need to integrate over time, to get:

v(t) = (-9.8m/s^)*t + v0

Where v0 is the initial speed of the object.

You can see that the mass of the object does not affect the velocity of it.

Then when we drop two marbles of different masses from the same height, we know that the final velocity of them will be equal.

Now, we also know that the kinetic energy can be written as:

K = (m/2)*v^2

where m is the mass, and v is the velocity.

Then the kinetic energy of the marble with less mass can be written as:

k = (m/2)*v^2

And the kinetic energy for the more massive one is:

K = (M/2)*v^2

And we know that both of them have the same velocity, and M is larger than m, then we can conclude that the marble with larger mass will have larger kinetic energy.

Answer:

Psychology traces its roots back through recorded history to India, China, the Middle East, and Europe. Buddha and Confucius focused on the powers and origin of ideas. ... The ideas of Bacon and Locke contributed to the development of modern empiricism.

Explanation:

Answer:

We know that the gravitational force F between two masses P and Q, that are separated by a distance R is:

[tex]F = G*\frac{P*Q}{R^2}[/tex]

Where G is the gravitational constant.

a) Mass P is doubled, then we have 2*P instead of P, the new force is:

[tex]F' = G*\frac{(2*P)*Q}{R^2} = 2*(G*\frac{P*Q}{R^2} ) = 2*F[/tex]

b) Now R is doubled, then instead of R, we have 2*R:

[tex]F' = G*\frac{P*Q}{(2*R)^2} = G*\frac{P*Q}{4*R^2} = G*\frac{P*Q}{R^2}*(1/4) = F/4[/tex]

c) Now we replace P by 2*P, and Q by 3*Q

[tex]F' = G*\frac{(2*P)*(3*Q)}{R^2} = 2*3*(G*\frac{P*Q}{R^2} ) = 6*F[/tex]

d) The entire mass of the system is increased by a factor of 4, then both of the individual masses are increased by a factor of 4.

Then we need to replace P by 4*P, and Q by 4*Q.

[tex]F' = G*\frac{(4*P)*(4*Q)}{R^2} = 4*4(G*\frac{P*Q}{R^2} ) = 16*F[/tex]

e) Now we replace R by R/2.

[tex]F' = G*\frac{P*Q}{(R/2)^2} = G*\frac{P*Q}{R^2/4}= 4*G\frac{P*Q}{R^2} = 4*F[/tex]

The strength of the electric field is 1.10×10^4 N/C.

The data is sent to us.

r = d/2 = 0.1/2 = 0.05 m, d = 10 cm = 0.1 m, and z = 17 cm = 0.17 m

Q = 40 nC = 40×10^-9 C

A) in the middle of the two circles

Since the electric fields created by the two rings are directed in opposite directions, there is no electric strength.

B) midway down the left ring

Electric strength is equal to the sum of the electric fields created by the left and right rings.

Electric strength is equal to E leftring + E rightring, which equals 0 plus kQz/(r2 + z2).

Electric strength = k×Q×z/(r^2 + z^2)^

Electric strength = 9×10^9×40×10^-9×0.17/(0.05^2 + 0.17^2)

Electric strength= 1.10×10^4 N/C

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