Please please help me with this i have 40 missing assignments, if you help YOUR AMAZING

Answer:

Step-by-step explanation:

48 out 52 cards are not a 2:

        [tex]P(not 2)=\frac{48}{52} =\frac{12}{13}[/tex]

The solution for x, is x= (3m - b)/2. (Option-d)

To solve for x in the given equation, m=(2x+b)/3, we can start by isolating x on one side of the equation.

First, we can multiply both sides of the equation by 3 to get rid of the denominator:

3m = 2x + b

Next, we can subtract b from both sides of the equation:

3m - b = 2x

Finally, we can divide both sides of the equation by 2:

x = (3m - b)/2

It's important to note that this is a linear equation with one unknown variable, and we can use algebraic methods to solve for the unknown variable. This equation may arise in many fields of study, including physics, engineering, and economics, among others.(Option-d)

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34. I haven't seen Tom since his wedding day.

36. Mary hasn't spoken French in years.

37. I haven't had a good night's sleep in ten weeks.

38. He hasn't paid taxes since 1970.

40. The windows haven't been cleaned for 3 months.

41. It's been years since I took photographs.

The perfect tense is a grammatical construction used to express actions that are completed or have happened before the present moment. It indicates that an action was performed and finished in the past but has relevance or impact on the present.

There are three main forms of the perfect tense: present perfect, past perfect, and future perfect.

1. Present Perfect Tense: This tense is used to describe an action or event that started in the past and has a connection to the present. It emphasizes the result or completion of the action.

2. Past Perfect Tense: This tense is used to describe an action or event that occurred before another action or a specific point in the past. It expresses an action completed before a specified time in the past.

3. Future Perfect Tense: This tense is used to describe an action that will be completed before a specified time or point in the future.

Each form of the perfect tense can be used with different time references to indicate the relationship between the completed action and the present or other points in time.

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<1 and <2 are same-side interior angles. Option D

<1 and <5 are same-side interior angles. Option B

<6 and <8 are corresponding angles. Option C

To determine the angles, we need to know the following;

Now, from the information given, we have that;

1. <1 and <2 are same-side interior angles because they are found on the same side of the transversal

2. We can see that < 1 and <5 are also same-side interior angles because they are two angles found on the exact same side of the transversal

3. Since corresponding angles are angles on matching corners of a transversal, < 6 and < 8 are corresponding angles

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a. The scalar product of vectors A = A₁i + A2₂j + A₃k and B = B₁i + B₂j + B₃k. is A ∙ B = A₁B₁ + A₂B₂ + A₃B₃.

b. The angle between the vectors A = 2i +2j - k and B = 7i + 24k is 97.67°

The scalar product of two vectors a = a₁i + a₂j + a₃k and b = b₁i + b₂j + b₃k is given by

a.b = abcosФ = a₁b₁ + a₂b₂ + a₃b₃ where

6a) Suppose A = A₁i + A2₂j + A₃k and B = B₁i + B₂j + B₃k. Prove that A ∙ B = A₁B₁ + A₂B₂ + A₃B₃.

We proceed as follows

We know that

A ∙ B = (A₁i + A₂j + A₃k). (B₁i + B₂j + B₃k)

= A₁i.(B₁i + B₂j + B₃k) + A₂j.(B₁i + B₂j + B₃k) + A₃k.(B₁i + B₂j + B₃k)

Expanding the brackets, we have

= A₁i.B₁i + A₁i.B₂j + A₁i.B₃k + A₂j.B₁i + A₂j.B₂j + A₂j.B₃k + A₃k.B₁i + A₃k.B₂j + A₃k.B₃k

= A₁B₁i.i + A₁B₂i.j + A₁B₃i.k + A₂B₁j.i + A₂B₂j.j + A₂B₃j.k + A₃B₁k.i + A₃B₂k.j + A₃B₃k.k

We know that

So, we have that

= A₁B₁i.i + A₁B₂i.j + A₁B₃i.k + A₂B₁j.i + A₂B₂j.j + A₂B₃j.k + A₃B₁k.i + A₃B₂k.j + A₃B₃k.k

= A₁B₁(1) + A₁B₂(0) + A₁B₃(0) + A₂B₁(0) + A₂B₂(1) + A₂B₃(0) + A₃B₁(0) + A₃B₂(0) + A₃B₃(1)

= A₁B₁ + 0 + 0 + 0 + A₂B₂ + 0 + 0 + 0 + A₃B₃

= A₁B₁ + A₂B₂ + A₃B₃

So, A ∙ B = A₁B₁ + A₂B₂ + A₃B₃.

6b) To find the angle between the vectors A = 2i +2j - k and B = 7i + 24k, we proceed as follows.

We know that the angle between two vectors is given by

Ф = cos⁻¹[(A.B)/AB​] where

Now, A.B =  (2i +2j - k).(7i + 24k) = (2 × 7 + 2 × 0 + (-1) × 24)

= (14 + 0 - 24)

= -10

Now, the magnitude of a vector C = C₁i + C₂j + C₃k is C = √(C₁² + C₂² + C₃²)

Since vector A = 2i +2j - k its magniude A = √(2² + 2² + (-1)²)

= √(4 + 4 + 1)

= √9

= 3

Also since vector B = 7i + 24k,  its magniude A = √(7² + 0² + 24²)

= √(49 + 0 + 576)

= √625

= 25

So, substituting the values of the variables into the equation, we have that

Ф = cos⁻¹[(A.B)/AB​]

Ф = cos⁻¹[(-10)/(3 × 25)]

Ф = cos⁻¹[(-2)/(3 × 5)]

Ф = cos⁻¹[-2/15]

Ф = -0.13333

Ф = 97.67°

So, the angle betwen the vectors is 97.67°

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The radius of the cylinder is 2.25 feet.

To find the radius of the cylinder, we can use the formula for the volume of a cylinder:

V = πr²h

Given that the volume V is 400 cubic feet and the height h is 25 feet, we can substitute these values into the formula and solve for the radius r.

400 = 3.14 r² x 25

Dividing both sides of the equation by (3.14 * 25) to isolate r^2, we have:

r² = 400 / (3.14 x 25)

r² ≈ 5.08

Taking the square root of both sides to solve for r, we get:

r ≈ √5.08

r ≈ 2.25

Therefore, the radius of the cylinder is 2.25 feet.

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The angle m∠HAT in the line segment is 54 degrees.

When line segment intersect, angle relationships are formed such as

vertical angles, linear angles etc.

Therefore,  the angle ∠HAT can be found using the relationship of the angles as follows:

m∠MAH = 3x + 14

m∠HAT = 2x + 6

Therefore,

m∠MAH + m∠HAT = 90 degrees

3x + 14 + 2x + 6 = 90

5x + 20 = 90

5x = 90 - 20

5x = 70

x = 24

Therefore,

m∠HAT = 2x + 6 = 2(24) + 6 = 48 + 6 = 54 degrees

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Answer:

D is the correct answer

Step-by-step explanation:

Acellus

No, the trapezoids are not similar because their corresponding angles do not have the same measures.

The given trapezoids ABCD and EFGH can be analyzed to determine if they are similar. Similarity in geometric figures implies that their corresponding angles are congruent, and their corresponding sides are proportional.

Let's examine the angles of the trapezoids:

In trapezoid ABCD:

Angle A = 137 degrees

Angle B = 90 degrees

Angle C = 90 degrees

Angle D = 43 degrees

In trapezoid EFGH:

Angle E = 136 degrees

Angle F = 90 degrees

Angle G = 90 degrees

Angle H = 44 degrees

By comparing the angles, we can observe that angles B and F are both right angles (90 degrees) in both trapezoids. Additionally, angles C and G are also right angles (90 degrees) in both trapezoids.

However, angles A and E, as well as angles D and H, do not have the same measures. Angle A measures 137 degrees in trapezoid ABCD, while angle E measures 136 degrees in trapezoid EFGH. Similarly, angle D measures 43 degrees in trapezoid ABCD, while angle H measures 44 degrees in trapezoid EFGH.

Since the corresponding angles in the two trapezoids do not have the same measures, we can conclude that trapezoids ABCD and EFGH are not similar.

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Answer:

To determine the possible degree(s) of a function from the graph alone, you need to examine the behavior of the graph at the extremes (far left and far right) and consider the number of turning points or changes in direction. Here's a step-by-step approach:

Look at the far left side of the graph: Determine the behavior of the graph as it approaches negative infinity. Does the graph approach a specific value, such as a horizontal line (asymptote) or the x-axis? If the graph approaches a horizontal line, it suggests a polynomial function of even degree. If the graph approaches the x-axis, it indicates a polynomial function of odd degree or possibly a function with a root of multiplicity greater than one.

Look at the far right side of the graph: Determine the behavior of the graph as it approaches positive infinity. Similar to step 1, observe if the graph approaches a specific value or a horizontal line. The behavior at the far right side should be consistent with the behavior at the far left side. This can help you identify if the function is even or odd degree.

Examine the number of turning points or changes in direction: Count the number of times the graph changes direction. These points are where the slope of the graph changes from positive to negative or vice versa. The number of turning points can provide an indication of the degree of the polynomial. For example, if there are two turning points, it suggests a polynomial function of degree 3.

Remember that this method provides potential degrees, but it may not definitively determine the exact degree of the function. Additional information or analysis might be required for a more accurate determination.

The relationship in this problem is not proportional, as there are different ratios between the number of people and the number of cars washed.

A proportional relationship is a relationship in which a constant ratio between the output variable and the input variable is present.

The equation that defines the proportional relationship is a linear function with slope k and intercept zero given as follows:

y = kx.

The slope k is the constant of proportionality, representing the increase or decrease in the output variable y when the constant variable x is increased by one.

The ratios between the output and the inputs are given as follows:

Different ratios, hence the relationship is not proportional.

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To express the value 6 × 10^(-10), you can use scientific notation or decimal notation. Here are some valid expressions that equal 6 × 10^(-10):

0.0000000006

6E-10

6 × 10^(-10)

These expressions represent the same value, which is 6 multiplied by 10 raised to the power of -10.

Decimal is a number system used in everyday arithmetic and mathematics. It is also known as the base-10 system because it uses ten digits (0-9) to represent numbers. Each digit's position in a decimal number represents a power of 10.

In a decimal number, the digits to the left of the decimal point represent whole numbers, while the digits to the right of the decimal point represent fractions or parts of a whole. For example, in the decimal number 123.45, the digit "1" represents 100, the digit "2" represents 10, the digit "3" represents 1, the digit "4" represents 0.1, and the digit "5" represents 0.01.

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The simplified form of the rational expression [tex](7x)/(14x^6)[/tex] is [tex]1/(2x^6).[/tex]

To simplify the rational expression [tex](7x)/(14x^6)[/tex], we can begin by simplifying the numerator and denominator separately.

In the numerator, 7x, we can see that both 7 and x have a common factor of 7. So, we can rewrite the numerator as 7 × x = 7x.

In the denominator, [tex]14x^6[/tex], we can see that both 14 and x^6 have a common factor of [tex]2x^6[/tex].

So, we can rewrite the denominator as

[tex]14 \times x^6 = 2 \times 7 \times x^6 = 2 \times 7x^6.[/tex]

Now, we can simplify the rational expression by canceling out the common factors in the numerator and denominator:

[tex](7x)/(14x^6) = (7x)/(2 \times 7x^6) \\= (7x)/(2 \times 7 \times x^6) \\= (cross(7x))/(2 \times cross(7) \times x^6) \\= 1/(2x^6)[/tex]

Therefore, the simplified form of the rational expression[tex](7x)/(14x^6)[/tex] is [tex]1/(2x^6).[/tex]

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In a hypothetical situation, an incorrect dosage calculation due to an error in metric system to Imperial System conversion could lead to potential harm to the patient. To avoid such errors, it is crucial to ensure accurate and precise conversions between the metric and Imperial systems. As a nurse, I will double-check my calculations, use reliable conversion charts or tools, and consult with colleagues or supervisors when in doubt. Additionally, ongoing education and training on dosage calculations and metric system conversions will be important to maintain proficiency and prevent errors in the future.

~~~Harsha~~~

The value of x is 33.4

To determine the value in the green box, we need to know that there are six different trigonometric identities.

These identities are enumerated as;

Using the sine identity, we have;

sin θ = opposite/hypotenuse

We have that;

θ = 64 degrees

Opposite = 30

Hypotenuse  = x

Substitute the values, we have;

sin 64 = 30/x

cross multiply

x = 30/0. 8987 = 33. 4

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Answer: 4 small bags, 3 large bags (equations below in explanation)

Step-by-step explanation:

x=number of small bags

y=number of large bags

x+y=7

4x+10y=52

Subtract them after multiplying the first equation by 4.

4x+4y=28

4x+10y=52

-6x=-24

x=4

x+y=7

4+y=7

y=3

The complete table for the function are

- f(1) - 3 = -5

- f(0) - 3 = -5.5

- f(2) - 3  = -7

- f(6) - 3 = undefined

- f(14) - 3 = -1

- f3(0) - 3 = 2

From the question, we have the following parameters that can be used in our computation:

The function equation and the incomplete table of values

This is given as

g(x) = - f(x) - 3

From the table, the missing values are at all values of x

So, we have

- f(1) - 3 = -2 - 3 = -5

- f(0) - 3 = -2.5 - 3 = -5.5

- f(2) - 3 = -4 - 3 = -7

- f(6) - 3 = undefined

- f(14) - 3 = 2 - 3 = -1

- f3(0) - 3 = 5 - 3 = 2

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The simplification of [tex]\sqrt{3x^2} * \sqrt{4x^2} is 2x^2\sqrt{3.[/tex]

The given expression is [tex]\sqrt{3x^2} * \sqrt{4x^2} .[/tex].

To simplify this expression, we can start by simplifying each square root individually and then multiply the simplified expressions.

[tex]\sqrt{3x^2[/tex] can be written as[tex]\sqrt{3} * \sqrt{x^2[/tex]. Since [tex]x^2[/tex] is a perfect square, its square root is x. Therefore, [tex]\sqrt{3x^2[/tex] simplifies to [tex]x\sqrt{3.[/tex]

Similarly,[tex]\sqrt{4x^2[/tex] can be written as[tex]\sqrt{4} * \sqrt{x^2.[/tex]The square root of 4 is 2, and the square root of[tex]x^2[/tex]is x. Thus, [tex]\sqrt{4x^2[/tex] simplifies to 2x.

Now, we can multiply the simplified expressions:

[tex]x\sqrt{3} * 2x.[/tex]

To multiply these terms, we multiply the coefficients (numbers in front) and the variables separately.

The coefficient of [tex]x\sqrt{3[/tex]is x, and the coefficient of 2x is 2.

Multiplying the coefficients gives us x * 2 = 2x.

The variables in x√3[tex]x\sqrt{3[/tex] are x and √3, and the variables in 2x are x and 1.

Multiplying the variables gives us x * x = x^2, and √3 * 1 = √3.

Therefore, the final simplified expression is [tex]2x^2\sqrt{3.[/tex].

In summary,[tex]\sqrt{3x^2 } * \sqrt{4x^2[/tex] simplifies to [tex]2x^2\sqrt{3.[/tex]

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Answer:approximately $396,849.46 after 30 years with continuous compounding.

Step-by-step explanation:

To calculate the cost of the loan after 30 years with continuous compounding, we can use the formula for continuous compound interest:

A = P * e^(rt)

Where:

A = the total amount after interest

P = the principal amount (loan amount)

e = Euler's number, approximately 2.71828

r = interest rate per period

t = time in years

Given:

Principal amount (loan amount), P = $175,000

Interest rate, r = 3% = 0.03 (as a decimal)

Time, t = 30 years

Using the formula, we can calculate the total amount (A):

A = $175,000 * e^(0.03 * 30)

Now, let's calculate the cost of the loan after 30 years:

A = $175,000 * 2.71828^(0.03 * 30)

Using a calculator or software, we find:

A ≈ $396,849.46

Therefore, the loan will cost approximately $396,849.46 after 30 years with continuous compounding.

The domain and range of the graph above in interval notation include the following:

Domain = [-6, 3]

Range = [-3, 3]

In Mathematics and Geometry, a domain refers to the set of all real numbers (x-values) for which a particular function (equation) is defined.

In Mathematics and Geometry, the horizontal portion of any graph is used to represent all domain values and they are both read and written from smaller to larger numerical values, which simply means from the left of any graph to the right.

By critically observing the graph shown in the image attached above, we can reasonably and logically deduce the following domain and range:

Domain = [-6, 3] or -6 ≤ x < 3.

Range = [-3, 3] or -3 < y < 3

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The  missing parts of the hierarchy of the quadrilaterals is listed below

A four-sided polygon is called a quadrilateral. A polygon having four sides is referred to as a four-sided polygon in general.

A geometric figure with two pairs of parallel sides. The quadrilateral shape known as a trapezoid (or trapezium in certain areas) can be restated in different words.

A quadrilateral having four angles measuring 90 degrees each and having opposite sides parallel is called a parallelogram.

Rhombus shape: This particular four-sided shape is distinguished by having every angle measuring 90 degrees.

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See text below

Hierarchy of a Quadrilateral Assignment

Fill in each of the missing parts of the hierarchy of the

quadrilaterals. Include the properties of each of the figures

Tara will pay £360 for 5 nights if she chooses a hotel with a regular room price of £80 per night that has a 25% off sale on its prices, and the VAT charge of 20% must be added at the end of the transaction.

Tara looked up hotel room prices for her holiday. A hotel had a 25% off sale on its prices. A VAT charge of 20% must be added at the end of the transaction, after any discount. If the regular price of a room is £80 per night, then we have to determine how much Tara will pay for 5 nights.

A 25% discount on £80 is: 25/100 * 80 = £20. So the discounted price of a hotel room is: £80 - £20 = £60.Next, we add VAT of 20% to the discounted price: 20/100 * £60 = £12.

Hence, the final price for one night is: £60 + £12 = £72.Since Tara needs to stay in the hotel for 5 nights, she will pay: £72 * 5 = £360.

Therefore, Tara will pay £360 for 5 nights if she chooses a hotel with a regular room price of £80 per night that has a 25% off sale on its prices, and the VAT charge of 20% must be added at the end of the transaction.

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The possible degrees of a function from it's graph are found with the sum of the multiplicities of each root of the function.

On the definition of a function, the x-intercept is given by the value/values of x for which the function assumes a value of zero.

On the graph, these are the values of x for which the graph of the function crosses or touches the x-axis.

The multiplicity of each root is given as follows:

Hence the degree is found with the sum of the multiplicities of the zeros of the function.

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The exact value of cos(-n/12) is equal to cos(n/12).

The cosine function (or cos function) in a triangle is the ratio of the adjacent side to that of the hypotenuse.

The value of cosine function is periodic with a period of 2π. Therefore, we can use the property cos(x) = cos(x + 2πk) for any integer value of k.

In this case, we have cos(-n/12). To find the exact value, we can use the fact that cos(x) = cos(-x) for any angle x. Therefore, we can rewrite cos(-n/12) as cos(n/12).

So, the exact value of cos(-n/12) is equal to cos(n/12).

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Answer:

approximately 4.2667%

Step-by-step explanation:

To calculate the percentage above the website's estimate that Jerrold set his asking price, we can use the following formula:

Percentage above = ((Asking price - Website estimate) / Website estimate) * 100

Percentage above = (($750,000 - $715,000) / $715,000) * 100

Percentage above ≈ 4.895

Therefore, Jerrold set his asking price approximately 4.895% above the website's estimate.

To calculate the percentage below his asking price that Jerrold sold for, we can use the following formula:

Percentage below = ((Selling price - Asking price) / Asking price) * 100

Percentage below = (($718,000 - $750,000) / $750,000) * 100

Percentage below ≈ -4.2667

Therefore, Jerrold sold his house approximately 4.2667% below his asking price.

Susan uses 500 milliliters of solution b to obtain a resulting mixture with 102 milliliters of pure alcohol.

Let's set up the equation based on the given information.

Let x represent the amount of solution b in milliliters.

Since Susan uses 100 milliliters less of solution a than solution b, the amount of solution a is (x - 100) milliliters.

We know that solution a has a concentration of 13% alcohol, which means that for every 100 milliliters, it contains 13 milliliters of alcohol.

Similarly, solution b has a concentration of 10% alcohol, which means that for every 100 milliliters, it contains 10 milliliters of alcohol.

Given that the resulting mixture has 102 milliliters of pure alcohol, we can set up the equation:

0.13(x - 100) + 0.1x = 102

Simplifying the equation, we have:

0.13x - 13 + 0.1x = 102

0.23x - 13 = 102

0.23x = 115

x = 115 / 0.23

x = 500

Therefore, Susan uses 500 milliliters of solution b to obtain a resulting mixture with 102 milliliters of pure alcohol.

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Answer:

Step-by-step explanation:

-3≤ x = graph 6

-3 > x = graph 3

x≥ 3 = graph 2

x ≤ 3 = graph 4

3 > x = graph 1

x > 3 = graph 5

the closed circles means greater/less than or equal to

the open circle means greater/less than

the direction of the arrow tells you if the number is greater than x or less than x

As you can see below, both expressions result in the same value of 105. This demonstrates the application of the associative law in regrouping terms and maintaining the equivalence of the expression.

The associative law in mathematics states that the grouping of numbers in an addition or multiplication operation does not affect the result. In other words, you can regroup terms within parentheses without changing the value of the expression.

Using the associative law, we can regroup the terms in the expression s + (r + 75) by removing the parentheses and rearranging the terms:

s + (r + 75) = (s + r) + 75

The expression (s + r) + 75 is equivalent to s + (r + 75) because the addition operation is associative.

Let's take an example to illustrate this:

Suppose s = 10 and r = 20.

Using the original expression:

s + (r + 75) = 10 + (20 + 75) = 10 + 95 = 105

Using the expression with regrouped terms:

(s + r) + 75 = (10 + 20) + 75 = 30 + 75 = 105

As you can see, both expressions result in the same value of 105. This demonstrates the application of the associative law in regrouping terms and maintaining the equivalence of the expression.

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Given statement solution is :- The quartile value above which 75% of the data lies is 31.625.

To find the value above which 75% of the data lies, you can determine the third quartile (Q3) of the data set. In this case, the upper quartile (Q3) is given as 30.5.

Since the data is represented on a number line with tick marks every one-half unit, we can divide the range between Q3 and the maximum value (32) into four equal parts. Each part represents 25% of the data.

To find the value that corresponds to 75% of the data lying above, we need to determine the value that is three-fourths of the way between Q3 and the maximum value.

First, calculate the range between Q3 and the maximum value: 32 - 30.5 = 1.5.

Next, divide the range by four to find the size of one-fourth of the range: 1.5 / 4 = 0.375.

Now, multiply the size of one-fourth of the range by three to find the size of three-fourths of the range: 0.375 * 3 = 1.125.

Finally, add the size of three-fourths of the range to Q3 to find the value above which 75% of the data lies: 30.5 + 1.125 = 31.625.

Therefore, the quartile value above which 75% of the data lies is 31.625.

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